Graph f(x)=−0.5x+3. Use the line tool and select two points to graph the line.

Answer:

the answer is D and A hope this helps

B and D

under a counterclockwise rotation about the origin of 270°

a point (x, y ) → (y, - x )

A(5, 4 ) → A'(4, - 5 )

B(6, 9 ) → B'(9, - 6 )

C(2, 8 ) → C'(8, - 2 )

These points correspond to the coordinates in the diagram → B

under a counterclockwise rotation about the origin of 90°

a point (x, y ) → (- y, x )

A(- 1, 2 ) → A'(- 2, - 1 )

B(-1, 5 ) → B'(- 5, - 1 )

C(- 3, 5 ) → C'(- 5, - 3 )

D(- 3, 2 ) → D'(- 2, - 3 )

These points correspond to the coordinates in the diagram → D

You must get two equation to find point of intersections

Answer:

x = (2,0)

y = (0,4)

Step-by-step explanation:

Solve For x:

Lets take y as 0 so the equation is 0 = -2x + 4, and if we simplify the expression we get x = 4/2 which s x = 2 so the answer for x is (2,0)

Solve for y:

Lets take x as 0 so the equation is y = -2 · 0 + 4 which simplyfied to y = 4, so the answer for y is (0,4)

Answer:

m=-3/8, n=12

Step-by-step explanation:

Answer: m=-3/8, n=12

Step-by-step explanation: Got it right on TTM

D. John Felton kills the Duke of Beckingham

Here is some proof: https://en.wikipedia.org/wiki/John_Felton_(assassin)

Answer:

d

Step-by-step explanation:

Given:  sin theta = 2/5.  This tells us that the lengths of the opp side and the hyp are 2 and 5 respectively.  The adj side is found using the Pyth. Thm.:  5^2-2^2= 25-4 = 21, so that the adj side is sqrt(21).

The double angle formula for the sine is sin 2theta = 2 sin theta *cos theta.

In this particular problem, the sine of 2theta is 2*(2/5)*[sqrt(21) / 5], or:

                                                                              (4/25)*sqrt(21).

Answer:

The value of [tex]\sin^2 \theta=\frac{4}{25}[/tex]                                                                            

Step-by-step explanation:

Given : [tex]\sin \thet=\frac{2}{5}[/tex] and  [tex]0<\theta<90[/tex]

To find : The value of [tex]\sin^2\theta[/tex] ?

Solution :

We have given the value of [tex]\sin \thet=\frac{2}{5}[/tex] and  [tex]0<\theta<90[/tex]

To find [tex]\sin^2\theta[/tex] we just have to square [tex]\sin\theta[/tex]

[tex]\sin \theta=\frac{2}{5}[/tex]

Squaring both sides,

[tex](\sin \theta)^2=(\frac{2}{5})^2[/tex]

[tex]\sin^2 \theta=\frac{4}{25}[/tex]

Therefore, The value of [tex]\sin^2 \theta=\frac{4}{25}[/tex]

64%. You would divide 16 from 25 because you're trying to find the amount of garbage that was plastic.

Hope this helped! :)

To answer this, divide 1000 cm by 16:

1000 cm

------------------ = 66 2/3 cm per piece

  16 pieces

(b)

using the 'laws of exponents '

[tex]a^{m}[/tex] × [tex]a^{n}[/tex] = [tex]a^{(m+n)}[/tex]

[tex]\frac{a^{m} }{a^{n} }[/tex] = [tex]a^{(m-n)}[/tex]

2² × [tex]\frac{2}{2^{4} }[/tex] = [tex]\frac{2^{3} }{2^{4} }[/tex] = [tex]2^{(3-4)}[/tex] = [tex]2^{-1}[/tex]

The answer is 70494.

Answer:

Make use of your knowledge of the maximum and minimum of the cosine function. Then scale and translate according to the way that function is scaled and translated to make f(x).

Step-by-step explanation:

f(x) is the cosine function, multplied by 4 and with 9 added to the result.

The minimum of the cosine function is -1. Multiplying that by 4 gives -4, and adding 9 gives 5.

The maximum of the cosine function is +1. Multiplying that by 4 gives +4, and adding 9 gives 13.

The minimum and maximum of f(x) are 5 and 13, respectively.

Max and Min:

Max = 13

Min = 5

COS Standard Period

[tex]2\pi[/tex]

COS Period with a multiplier of 2 on x

[tex]\pi[/tex]

COS Period with a multiplier of 2 on x and a Phase Shift

Answer to period

[tex]\frac{5}{4}\pi[/tex]

Step-By-Step Explanation:

Please view the image I have provided.

Yes. You can solve in the usual way.

Take the square root:

... x-7 = ±√0 = 0

Add 7:

... x = 7

_____

There is one distinct real solution (with multiplicity 2).

(1) it is (C) the commutative property of multiplication: a*b = b*a, so 2*(-6/7) = (-6/7)*2

(2) it is (D) the commutative property of addition: a+b=b+a, so 5*4+3=3+5*4

commutate = "swap around"

When you write expressions like this, you need to pay attention to the Order of Operations. As this is written, the only factor in the denominator is the one immediately after the division symbol: 7. This simplifies to

... (35/7)·x^(3+2)·y^(5+4) = 5x^5y^9

_____

We suspect you might intend ...

... (35x^3y^5)/(7x^2y^4) = (35/7)x^(3-2)y^(5-4) = 5xy

y = -x² + 9

the x-intercepts are x = - 3 and x = 3 hence the factors are

(x + 3 ) and (x - 3 )

polynomial is the product of its factors

y = a(x - 3 )(x + 3) ← ( a is a multiplier )

from the end behaviour the parabola opens down and is a maximum and so the value of a is negative

y = -(x - 3)(x+3) = - (x² - 9 ) = - x² + 9

The polynomial function with the given features is f(x) = -(x + 3)(x - 3), which is a quadratic function with the required y-intercept, x-intercepts, and end behavior.

The question involves finding a polynomial function given certain characteristics: a y-intercept of (0, 9), x-intercepts at (-3, 0) and (3, 0), a degree of 2, and specific end behavior.

Since the degree is 2, we are dealing with a quadratic function.

The x-intercepts tell us that the factors of the polynomial are (x + 3) and (x - 3).

The y-intercept indicates that when x is 0, the function equals 9.

The end behavior suggests that the leading coefficient is -1 because as x goes to infinity or negative infinity, f(x) goes to negative infinity.

Considering all the information, the function can be expressed as:

f(x) = -(x + 3)(x - 3)

To verify, expanding the factors gives:

f(x) = -(x^2 - 9)

f(x) = -x^2 + 9

This function has the required y-intercept of 9, x-intercepts of -3 and 3, and the correct end behavior.

Answer:

no solution

Step-by-step explanation:

To put the first equation into standard form, with the coefficients mutually prime, divide it by 5:

... x - y = 4

To put the second equation into standard form, with the coefficients mutually prime and the leading coefficient positive, divide by -2:

... x - y = 2

These are inconsistent equations, hence have no solution.

Answer:

a

Step-by-step explanation:

Let x represent the number of half-gallons purchased by the store. Then x-13 is the number sold, and 2.80x is the store's cost. The revenue is 4.06(x-13) and the difference between that and cost is the profit.

... 4.06(x -13) -2.80x = 63.14

... 1.26x - 52.78 = 63.14 . .  . . eliminate parentheses, collect terms

... 1.26x = 115.92 . . . . . . . . . . add 52.78

... x = 115.92/1.26 = 92 . . . . . divide by the coefficient of x

The store purchased 92 half-gallons of milk.

Answer: First option. x-intercept is -5; y-intercept is -7/4

Solution:

1) To find the x-intercept we replace y by 0, and solve for x:

-(7/5)x-4y=7

-(7/5)x-4(0)=7

-(7/5)x-0=7

-(7/5)x=7

Multiplying both sides of the equation by -(5/7)

-( 5/7)[-(7/5)]x=-(5/7)(7)

x=-(5*7)/7

x=-35/7

x=-5

The x-intercept is -5

2) To find the y-intercept we replace x by 0, and solve for y:

-(7/5)x-4y=7

-(7/5)(0)-4y=7

-0-4y=7

-4y=7

Dividing both sides of the equation by -4:

-4y/(-4)=7/(-4)

y=-(7/4)

The y-intercept is -(7/4)

Angles 1 and 2 involve lines a, b, and d. If d is the transversal, then the only pair left out of those three lines is a and b.

_____

Angles 1 and 2 are between lines a and b (interior), and either side of line d (alternate), so meet the requirements to be called alternate interior angles.

Answer:

ITS A AND B

Step-by-step explanation:

2*53/25 = 4.24

4 is not enough to maintain the required ratio, so there must be 5 chaperones, minimum.

_____

Presumably, the guidelines contain additional information regarding whether the number of chaperones can be odd. Sometimes, two are required so that one can be taking care of a student while the other handles the remaining students (or calls for emergency aid). In that case, the minimum for 53 students may be 6 chaperones.

Answer:

The answers would be

1. C

2. B

3. A

Step-by-step explanation:

The term product refers to multiplication. So in question 1, when we see the term quotient, we are looking to multiply.

The term quotient refers to division. So in questions 2 and 3, when we see this term, we look to divide.

Answer:

C. [tex]6n[/tex]

B. [tex]\frac{6}{(x+y)}[/tex]

A. [tex]\frac{Z}{3}[/tex]

Step-by-step explanation:

1. This expression refers to the product operation between real numbers, therefore the correct algebraic form is [tex]6n[/tex]

2. This expression refers to the operation division between real numbers, therefore the correct algebraic form is [tex]\frac{6}{(x+y)}[/tex]

3. This expression refers to the operation division between real numbers, therefore the correct algebraic form is [tex]\frac{Z}{3}[/tex]

C) p ≤ 78

I got 78 by subtracting 118 by 40. Since we know the maximum is 118 we can't get any higher than 78 so it has to be equal or less than.  

Answer:

C) p ≤ 78

Step-by-step explanation:

so we know the plane has a maximum capacity of 118

and 40 have already been loaded.

118-40= 78

we know it cannot have greater than 78 but it can equal 78

there fore passengers are less than or equal to 78

also shown like this p ≤ 78 or option C

f^-1 is found by reading the table from right to left, so find the f(x) number in the right hand column and f^-1 would be the number in the left hand column.

When f(x) = 3, x = 2

f^-1(3) would be 2

When f(x) = 8, x = 7

f^-1(8) = 7

As per the given value of the function , value of [tex]f^{-1}(3) = 2[/tex] and [tex]f^{-1}(8) = 7[/tex].

" Function is defined as the for each input value there is one and only one output."

According to the question,

From the given table value of function [tex]f(x)[/tex]defined for [tex]x[/tex]

Consider,

[tex]f(x) = y\\\\\implies x = f^{-1}(y)[/tex]

Value of required function we get,

[tex]y= 3\\\\\implies f^{-1}(3)= 2[/tex]

[tex]y= 8\\\\\implies f^{-1}(8)= 7[/tex]

Hence, as per the given value of the function , value of [tex]f^{-1}(3) = 2[/tex] and [tex]f^{-1}(8) = 7[/tex].

Learn more about function here

https://brainly.com/question/12431044

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| u + v | = 2

u + v = - 4i + 1j + 4i + 1j = 2j

the magnitude of a vector ai + bj is

| ai + bj | = √(a² + b² )

for u + v = 0 + 2j

| u + v | = √(0² + 2² ) = √4 = 2

If each item Kathy puts in the box weighs 2 kg, then the weight of p items will be 2p kilograms. Since the box weighs 1 kg, the total weight in kilograms will be ...

... 2p + 1

Kathy wants that value to be less than or equal to 10 kg, so her inequality will be

... 2p + 1 ≤ 10 . . . . . corresponds to selection D

Answer

d = 2

Step-by-step explanation:

d divided by 12 is the same as d/12?

d/12 = 1/6

cross multiply and get 12 = 6d.

6(2) = 12.

Divide 12 by 2 and you get 2/12 which simplifies to 1/6.

Hope I helped. ^-^

d = 2

given [tex]\frac{d}{12}[/tex] = [tex]\frac{1}{6}[/tex]

multiply both sides by 12

d = 12 × [tex]\frac{1}{6}[/tex] = 2

A 81.2 is the answer

Hello!

Answer:⇒⇒⇒⇒⇒⇒⇒⇒A. 81.2

Step-by-step explanation:

[tex]6(2.6+12.1)[/tex]

Add the numbers.

[tex]2.6+12.1=14.7[/tex]

[tex]6*14.7[/tex]

Multiply the numbers.

[tex]6*14.7=88.2[/tex]

[tex]=88.2[/tex]

[tex]88.2-7[/tex]

Subtract the numbers.

[tex]88.2-7=81.2[/tex]

[tex]=81.2[/tex]

Hope this helps!

Thank you for posting your question at here on brainly.

-Charlie

6

24% = [tex]\frac{24}{100}[/tex]

multiply 25 by this fraction

25 × [tex]\frac{24}{100}[/tex] = [tex]\frac{25(24)}{100}[/tex] = 6