graph of this ellipse
x^2 + y^2 =1
_ _
4 16
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Related Questions
hey can you please help me posted picture of question
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The solutions are 3 and -3
Explanation:
To get the solution, we will need to isolate the x on one side of the equation as follows:
10x² - 56 = 88 - 6x²
10x² - 56 + 56 = 88 - 6x² + 56
10x² = 144 - 6x²
10x² + 6x² = 144 - 6x² + 6x²
16x² = 144
x² = 144/16
x² = 9
x = ±√9
either x = +√9 = 3
or x = -√9 = -3
Hope this helps :)
Design amanda wants to make this design of circles inside an equilateral triangle.
a. what is the radius of the large circle to the nearest hundredth of an inch?
b. what are the radii of the smaller circles to the nearest hundredth of an inc
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the answer in the attached figure
Answer:
Using theorem
AE=8.66
Thus radius of large circle is one third of equilateral triangle altitude.
Radius of larger circle=2.9 inch
And radius of inner circle will be 0.96 inch
What is the first step in solving ln(x − 1) = ln6 − lnx for x?
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Answer:
[tex]ln(x - 1) = ln(\frac{6}{x})[/tex]
Step-by-step explanation:
[tex]ln(x - 1) = ln6 - lnx[/tex]
To solve for x we need to simplify the ln
To simplify logarithmic function we use log property
[tex]ln(a) - ln(b) = ln(\frac{a}{b})[/tex]
we apply the same property on the right hand side of the given equation
[tex]ln(x - 1) = ln6 - lnx[/tex]
[tex]ln(6) - ln(x) = ln(\frac{6}{x})[/tex]
[tex]ln(x - 1) = ln(\frac{6}{x})[/tex]
This is the first step in solving the given equation
Please Help!
Khalid has a game board as shown below, which is a square with 20-cm sides. The area of the largest circle is 320 square centimeters.
What is the probability of scoring 1, 3, or 5 points with one randomly thrown dart?
A. 1/2
B. 5/8
C. 3/4
D. 4/5
Answers
Answer:
Option D. 4/5
Step-by-step explanation:
we know that
The probability of scoring 1, 3, or 5 points with one randomly thrown dart is equal to divide the area of the largest circle by the area of the square game board
step 1
Find the area of the square game board
[tex]A=b^{2}[/tex]
we have
[tex]b=20\ cm[/tex]
substitute
[tex]A=20^{2}[/tex]
[tex]A=400\ cm^{2}[/tex]
step 2
Find the probability
[tex]P=320/400[/tex]
[tex]P=0.8=8/10=4/5[/tex]
Runners in a long distance race start out going 5 kilometers south and then head west for the remainder of the race. The finish line is 13 kilometers from the starting line. How far did the runners travel?
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5 km +12 km = 17 km
_____
By the Pythagorean theorem, ...
(straight-line distance)² = (distance south)² +(distance west)²
In km, this is
13² = 5² +(distance west)²
169 -25 = (distance west)²
√144 = 12 = distance west
Construct a 90% confidence interval for the population mean, µ. assume the population has a normal distribution. a sample of 15 randomly selected math majors has a grade point average of 2.86 with a standard deviation of 0.78. round to the nearest hundredth
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The 90% confidence interval for the population mean [tex]\( \mu \)[/tex] is approximately (2.50, 3.21) .
To construct a 90% confidence interval for the population mean [tex]\( \mu \)[/tex], we can use the formula:
[tex]\[ \text{Confidence Interval} = \bar{x} \pm \left( \text{Critical Value} \times \frac{s}{\sqrt{n}} \right) \][/tex]
where:
- [tex]\( \bar{x} \)[/tex] is the sample mean,
- s is the sample standard deviation,
- n is the sample size, and
- the critical value corresponds to the desired confidence level and degrees of freedom.
Given:
- Sample mean [tex]\( \bar{x} = 2.86 \),[/tex]
- Sample standard deviation s=0.78
- Sample size n=15
- Confidence level = 90%.
First, we need to find the critical value corresponding to a 90% confidence level and 14 degrees of freedom (since ( n - 1 = 15 - 1 = 14 )). We can find this value using a t-distribution table or a statistical calculator. For a 90% confidence level and 14 degrees of freedom, the critical value is approximately 1.7613.
Now, let's calculate the confidence interval:
[tex]\[ \text{Confidence Interval} = 2.86 \pm \left( 1.7613 \times \frac{0.78}{\sqrt{15}} \right) \]\[ \text{Confidence Interval} = 2.86 \pm \left( 1.7613 \times \frac{0.78}{\sqrt{15}} \right) \]\[ \text{Confidence Interval} = 2.86 \pm \left( 1.7613 \times \frac{0.78}{3.87298} \right) \]\[ \text{Confidence Interval} = 2.86 \pm \left( 1.7613 \times 0.20172 \right) \]\[ \text{Confidence Interval} = 2.86 \pm 0.35587 \][/tex]
Lower Limit:
[tex]\[ 2.86 - 0.35587 \approx 2.5041 \][/tex]
Upper Limit:
[tex]\[ 2.86 + 0.35587 \approx 3.2141 \][/tex]
Solve the equation: Sin2x - Sinx = 0
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(search the net for proof if you wish)
So the original equation becomes
2sinxcosx-sinx=0
The two terms both have sinx that can be taken out to get:
sinx(2cosx-1)=0
This is true if sinx=0 or 2cosx-1=0 , rewritten: cosx=1/2
sinx=0 than x=2kπ
cosx=1/2 than x=π/3+2kπ
where k is an integer
the square in this figure has a side length of 14 inches. the radius of the quarter circle is 7 inches. what is the estimate area
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The area of the shaded region is 42.14 square inches.
How the area of the shaded region is determined:
We are given a square with side lengths of 14 inches, and each corner of the square has a quarter circle with a radius of 7 inches. We need to find the area of the shaded region, which is the area of the square minus the area of the quarter circles.
To calculate the area of the figure, we need to consider both the square and the quarter circles.
1. Calculate the area of the square:
The square has a side length of 14 inches.
Area of the square = [tex]side^2[/tex] = [tex]14^2[/tex] = 196 square inches
2. Calculate the area of the quarter circles:
The quarter circle has a radius of 7 inches.
The area of a full circle is given by:
Area of the circle = [tex]\pi r^2[/tex]
Area of the quarter circle = 4/4 x [tex]\pi r^2[/tex]
= 1 x 3.14 x [tex]7^2[/tex]
= 153.86 square inches
Therefore, the area of the shaded region = Area of the square - Area of the quarter circles:
= 196 - 153.86
= 42.14 square inches
Complete Question:
The square in the figure has a side length of 14 inches. The radius of the each quarter circle is 7 inches. What is the area of the shaded region?
what is 12.81 repeated rounded to the nearest hundredth
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Let me know if you have any further questions.
:)
Use parametric equations of the ellipse, ???? 2 16 + ???? 2 9 = 1, to find the area that it encloses in the first quadrant.
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For the data set below, calculate the standard deviation to the nearest hundredth decimal place. 27 38 47 42 33 56 37 57 38 52
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Final answer:
The standard deviation of the given data set is 10.03, and the value that is one standard deviation below the mean is 32.67. Calculations involve finding the mean, computing squared deviations, calculating the sum of squared deviations, finding the variance, and taking the square root of the variance.
Explanation:
The mean is calculated as: (27 + 38 + 47 + 42 + 33 + 56 + 37 + 57 + 38 + 52) ÷ 10 = 427 ÷ 10 = 42.7.
Now we calculate each deviation from the mean, square it, and sum them:
(27 - 42.7)² = 246.49
(38 - 42.7)² = 22.09
(47 - 42.7)² = 18.49
(42 - 42.7)² = 0.49
(33 - 42.7)² = 94.09
(56 - 42.7)² = 176.89
(37 - 42.7)² = 32.49
(57 - 42.7)² = 204.49
(38 - 42.7)² = 22.09
(52 - 42.7)² = 86.49
A sum of squared deviations = 904.61.
The variance is 904.61 ÷ (10-1) = 100.51.
The standard deviation is the square root of the variance,
which is √100.51 equal to approximately 10.03.
To find the value that is one standard deviation below the mean, we subtract one standard deviation from the mean: 42.7 - 10.03 = 32.67.
Therefore, the standard deviation to the nearest hundredth is 10.03, and the value that is one standard deviation below the mean is approximately 32.67.
Two friends bring hamburger meat to your cookout. One brings 2.7 pounds, and the other brings 3.54 pounds. How much hamburger meat do they bring?
Answers
They bought 6.24 pounds of hamburger meat
Explanation:
We are given that:
The first friend brought 2.7 pounds of hamburger meat
The second friend brought 3.54 pounds of hamburger meat
The total amount of hamburger meat they both brought would be simply the summation of what they brought individually.
This means that:
Total amount brought = 2.7 + 3.54
Total amount brought = 6.24 pounds of hamburger meat
Hope this helps :)
The scatter plot shows the relationship between the number of car accidents in a month and the number of drivers attending a program on distracted driving. The equation represents the linear model for this data. y=−0.0067x+17 What does the number -0.0067 in the equation mean in this context? There were 0.67 accidents per month. The number of accidents was reduced by 0.67 per month for every additional 100 drivers in the program. The number of accidents was reduced by 0.67 per month for every additional driver in the program. The number of accidents increased by 0.67 per month for every additional 100 drivers in the program. The number of accidents was reduced by 0.67 per month every month.
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Answer:
the answer is A
PLZ HELP ASAP FEATURES OF A CIRCLE FROM ITS EXPANDED EQUATION
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[tex] x^{2} +y^{2} +14x-10y+65=0 \\ \\ x^{2} +2(x)(7)+ y^{2}-2(y)(5)=-65 \\ \\ x^{2} +2(x)(7)+ (7)^{2}+ [y^{2}-2(y)(5)+ (5)^{2}]=-65+(7)^{2}+(5)^{2} \\ \\ (x+7)^{2}+(y-5)^{2}=9 [/tex]
The above equation is in standard form.
The center of the circle is (-7, 5) and its radius is 3.
What is the value of x in the following equation 1/5x=5^8
A)-8 B) 8 C)40 D)-40
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What is the value of x in the following equation (1/5)^x=5^8
Applying logarithms both members
log(1/5)^x=log(5^8)
x*log(1/5)=8*log(5)
x=8*log(5)/log(1/5)
we know that
log (1/5)----> log (1)-log (5)----> 0-log (5)-----> -log (5)
so
x=8*log(5)/-log (5)------> x=-8
the answer is
-8
A rectangular page is to contain 95 square inches of print. the margins on each side are 1 inch. find the dimensions of the page such that the least amount of paper is used.
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Let the dimensions for the Print Region be M,N
Additional Margin is summed up to get :
New Dimensions of the Page = (M + 2)(N)
[ 2 inches - 1 inch on either side ]
Hence, the Area = [ MN + 2N ] = [ 95 + 2N ]
Note that 'N' has to be a factor of 95
=> Least Possible Area is achieved when N = 5
=> Dimensions of the Page = { 21 inches x 5 inches ]
Two planes are flying in opposite directions, away from each other, one with the speed of 800 km per hour and the other with the speed of 840 km per hour. How much farther from each other are the planes getting every hour?
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The "Let's Roll" game uses a number cube with the numbers 2,4,6,8,10, and 12. There are prizes for rolling any number less than 6. How likely is it to roll a number less than 6?
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The probability of rolling a number less than 6 in the 'Let's Roll' game is 1/3.
Explanation:To find the probability of rolling a number less than 6 in the 'Let's Roll' game, we need to count the number of favorable outcomes (numbers less than 6) and divide it by the total number of possible outcomes (numbers on the number cube). In this case, the favorable outcomes are 2, 4, and the total number of outcomes is 6.
Therefore, the probability of rolling a number less than 6 is 2/6 or 1/3.
Therefore the probability of getting a number less than 6 will be 33.3%
Probability is defined as the ratio of the
number of favorable outcomes to the total
number of outcomes in other words the
probability is the number that shows the
happening of the event.
Sample space we have = [ 2,4,6,8,10,12 ] = 6
Desirable outcome will be = [2,4] = 2
Probability = 2 / 6
Probability = 1/3
Probability = 0.33 = 33%
Therefore the probability of getting a number less than 6 will be 33.3%
One method of slowing the growth of an insect population without using pesticides is to introduce into the population a number of sterile males that mate with fertile females but produce no offspring. let p represent the number of female insects in a population and s the number of sterile males introduced each generation. let r be the per capita rate of production of females by females, provided their chosen mate is not sterile. then the female population is related to time t by t = p + s p[(r − 1)p − s] dp. suppose an insect population with 10,000 females grows at a rate of r = 1.2 and 400 sterile males are added. evaluate the integral to give an equation relating the female population to time. (note that the resulting equation can't be solved explicitly for p. remember to use absolute values where appropriate.)
Answers
To be clear, the given relation between
time and female population is an integral:
[tex]t = \int { \frac{P+S}{P[(r - 1)P - S]} } \,
dP [/tex]
[tex]t = \int { \frac{P+400}{P[(1.2 - 1)P - 400]} } \, dP [/tex]
= [tex] \int { \frac{P+400}{P(0.2P - 400)} } \, dP [/tex]
In order to evaluate this integral, we need to write this rational function in a simpler way:
[tex]\frac{P+400}{P(0.2P - 400)} = \frac{A}{P} + \frac{B}{(0.2P - 400)} [/tex]
where we need to evaluate A and B. In order to do so, let's calculate the LCD:
[tex]\frac{P+400}{P(0.2P - 400)} = \frac{A(0.2P - 400)}{P(0.2P - 400)} + \frac{BP}{P(0.2P - 400)} [/tex]
the denominators cancel out and we get:
P + 400 = 0.2AP - 400A + BP
= P(0.2A + B) - 400A
The two sides must be equal to each other, bringing the system:
[tex] \left \{ {{0.2A + B = 1} \atop {-400A = 400}} \right. [/tex]
Which can be easily solved:
[tex] \left \{ {{B=1.2} \atop {A=-1}} \right. [/tex]
Therefore, our integral can be written as:
[tex]t = \int { \frac{P+400}{P(0.2P - 400)} } \, dP = \int {( \frac{-1}{P} + \frac{1.2}{0.2P-400} )} \, dP [/tex]
= [tex]- \int { \frac{1}{P} \, dP + 1.2\int { \frac{1}{0.2P-400} } \, dP[/tex]
= [tex]- \int { \frac{1}{P} \, dP + 6\int { \frac{0.2}{0.2P-400} } \, dP[/tex]
= - ln |P| + 6 ln |0.2P - 400| + C
Now, let’s evaluate C by considering that at t = 0 P = 10000:
0 = - ln |10000| + 6 ln |0.2(10000) - 400| + C
C = ln |10000| - 6 ln |1600|
C = ln (10⁴) - 6 ln (2⁶·5²)
C = 4 ln (10) - 36 ln (2) - 12 ln (5)
Therefore, the equation relating female population with time requested is:
t = - ln |P| + 6 ln |0.2P - 400| + 4 ln (10) - 36 ln (2) - 12 ln (5)
Joey got a 25% raise on his salary. if his original salary was 1,200, how much was it after the raise was implemented?
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a dress was reduced from $100 to $85. express the discount as a % of the original price
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$15/$100 = 15/100 = 15%
_____
It can be helpful to think of "%" as another way to write "/100".
Find the 15th term of the arithmetic sequence.
a+1, 2a+1, 3a+1
a. a+15
b. 15a+15
c. 15a + 1
d. 14a+14
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The coefficient of "a" in the given sequence is the term number (1, 2, 3, ...) and the constant remains constant at 1. Thus the 15th term can be expected to be ...
c. 15a + 1
c. 15a + 1
Solve the equation <(a-5)-5=3
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a - 5 - 5 = 3
Calculate the difference between -5 and 5.
a - 10 = 3
Now move the constant to the right side of the equation and change its sign.
a = 3 + 10
Add the numbers on the right side together to get your final answer.
a = 13
Let me know if you have any further questions.
:)
estimate the difference between 9,030 and 738
Answers
9,030 ⇒ 9,000
738 ⇒ 700
9,000 - 700 = 8,300
simplify 3.2-5.1n-3n+5
Answers
-8.1n+8.2
3.2+5= 8.2
-5.1n-3n= -8.1n
Now you combine the two and get an answer of -8.1n-8.2
An eagle can fly at a speed of 50 mph and a starling can fly at 78 mph. How far will the starling fly in the time it takes the eagle to fly 125 miles?
PLZ HELP ASAP!!!!!!
20 POINTS!
Answers
1.
50*x=125
x=2.5
2.
2.5 * 78 = 195 miles
Answer:
195 miles
Step-by-step explanation:
50*x=125
x=2.5
2.5*78=195miles
Help with this one please
Answers
A=G^2/H; H=G^2/A
The explanation is shown below:
1. To solve the exercise shown in the figure attached, you must apply the proccedure shown below:
2. You have the following equation to calculate G:
G=√AH
3. Now, to find the formula to calculate A, you must clear the A, as below:
G^2=(√AH)^2
G^2=AH
A=G^2/H
4. Then, you must apply the same proccedure to find the formula for calculate H, as following:
G^2=(√AH)^2
G^2=AH
H=G^2/A
Rewriting;
G=sqrt(AH)
//square both sides//
G^2=[sqrt(AH)]^2
G^2=AH
A=G^2/H
G=sqrt(AH)
//square both sides//
G^2=[sqrt(AH)]^2
G^2=AH
H=G^2/A
Thus, the answer is the first option which has A=G^2/H and H=G^2/A
The Root-Mean Square-Arithmetic Mean-Geometric Mean-Harmonic Mean Inequality (RMS-AM-GM-HM), is an inequality of the root-mean square, arithmetic mean, geometric mean, and harmonic mean of a set of positive real numbers that says:
with equality if and only if . This inequality can be expanded to the power mean inequality.
As a consequence we can have the following inequality: If are positive reals, then with equality if and only if ; which follows directly by cross multiplication from the AM-HM inequality.This is extremely useful in problem solving.
What are some uses for the distance formula? Finding the perimeter of polygons. Finding the area of rectangles. Finding the equation of a circle. Finding the midpoint of segments. Finding how much gas you will need on a trip.
Answers
-Finding the perimeter of polygons
-finding the area of rectangles
The Distance Formula is used widely in mathematics to calculate the distance between two points, which includes finding the perimeter of polygons, the equation of a circle and the midpoint of segments.
Explanation:The Distance Formula is a valuable tool in mathematics that has a wide range of practical uses and applications. It is primarily used to calculate the distance between two specific points on a coordinate plane. Some uses include the following:
Finding the perimeter of polygons: Distance Formula can be used to calculate the length of each side of the polygon, and then by summing these lengths, we get the perimeter. Finding the equation of a circle: By using Distance Formula, we can establish the radius of the circle - the distance from the center of the circle to any point on the circle. Finding the midpoint of segments: Distance Formula helps to identify the exact middle point between two defined points.
However, usage of the Distance Formula to determine the amount of gas needed for a trip would be incorrect as it requires additional factors like the fuel efficiency of your vehicle and the nature of your trip.
Learn more about Distance Formula here:https://brainly.com/question/11231122
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A patient is given a 50 mg dose of medicine the medicines effectiveness decreases every hour at a constant rate of 40% what is the exponential decay function that models this scenario how much medicine will be left in the patient's system after two hours
Answers
[tex]y = a(1 - r)^{x} \\ y = 50(1 - .40) ^{x} [/tex]
x= hours past
[tex]y = 50(1 - .40)^{2} \\ y = 18[/tex]
after 2 hours, there are 18 mg of medicine left
Answer:
[tex]A=50(0.6)^x[/tex]
18 mg of medicine will be left in the patient's system after two hours.
Step-by-step explanation:
Given,
The initial quantity of the medicine, P = 50 mg,
Also, it decreases every hour at a constant rate of 40%
That is, r = 40 %,
Thus, the quantity of the medicine after x hours,
[tex]A=P(1-\frac{r}{100})^r[/tex]
[tex]=50(1-\frac{40}{100})^x[/tex]
[tex]=50(1-0.4)^x[/tex]
[tex]=50(0.6)^x[/tex]
Which is the required exponential decay function that models this scenario.
The quantity of the medicine after 2 hours,
[tex]A=50(0.6)^2=18\text{ mg}[/tex]
1. Clyde has the chance to buy a piece of old Pennsylvania Dutch pottery that he thinks he can resell for $500. If Clyde needs a 125% markup on cost, what price should he pay?
2. Orchard Supply sells lawn fertilizer at a price of $12.50 per bag. If the markup is 25% of cost, find the cost.
Answers
2.25*cost = 500
cost = 500/2.25 = 222.22
Clyde should pay $222.22 or less for the pottery.
2. cost +0.25*cost = $12.50
1.25*cost = $12.50
cost = $12.50/1.25 = $10.00
The cost to Orchard Supply of a bag of fertilizer is $10.00.