Gravitational potential energy is the energy something contains due to its ________ the Earth.
A. weight on
B. velocity on
C. position above
D. attraction towards

Answers

Answer 1
i believe this answer will be A

Related Questions

Why might someone choose to use U-238 over C-14 to determine the age of a specimen?

Answers

Carbon 14 and and Uranium 238 are not used together to determine fossil ages, because of the huge differences in the half lives of C -14 and U -238 that cannot be used together. C -14 can only be used to date fossils of a very recent age. U -238 can only be used to date volcanic rocks of a very old age. 
I hope I helped you :) 

The half life of C-14 is 5700 years and that of U-238 is 4.5 billion years. So U-238 can be used to determine the age of ancient objects. U-238 is used to date the age of the Earth. U-238 is found in volcanic rocks but not in fossils. Fossils contain C-14 only. C-14 is used to date fossils of recent age.

If a sample of a certain solution is determined to have a [h3o+][h3o+] concentration of 4.91×10−44.91×10−4 moles/liter, what is its ph? round off your answer to one decimal place.

Answers

pH scale is used to determine how acidic , basic or neutral a solution is. It can be calculated using the following equation 
pH = -log [H₃O⁺]
hydronium ion concentration has already been given 
[H₃O⁺] = 4.91 x 10⁻⁴ M
pH = -log[4.91 x 10⁻⁴ M]
pH = 3.3
the pH of medium is 3.3

The energy stored in the motion or vibration of molecules in a substance is a definition for
A. heat.
B. work.
C. radioactivity.
D. electromagnetism.

Answers

the answer is A.

A: heat

plz give me brainliest <3

HEEELLLPPP PPLEEAASSEE
Which statement best describes a battery?
Identical cells are arranged in the same orientation to increase the energy output.
Identical cells are arranged in opposite orientations to reverse the half reactions.
Different cells are arranged in the same orientation to increase the energy output.
Different cells are arranged in opposite orientations to reverse the half reactions.

Answers

OXIDATION UNIT TEST

1. Which statement best explains why magnesium and chlorine combine in a 1:2 ratio?

A. Magnesium has two valence electrons, and chlorine can accept one electron in its outer shell

2. Hydrogen and nitrogen combine to form ammonia. When nitrogen and hydrogen bond, nitrogen pulls the electrons from hydrogen toward itself. Which statement about the reactants is correct?

C. Hydrogen is oxidized, and nitrogen is reduced.

3. C3H8 + 5O2 → 3CO2 + 4H2O + energy

Which type of reaction is shown?

C. combustion

4. Which phrase best defines a redox reaction?

D. a reaction in which electrons are transferred between different atoms

5. Which statement describes the process of oxidation?

D. Oxidation results in a loss of electrons, so the oxidation number increases.

6. Which chemical equation represents a redox reaction?

D. Fe2O3(s) + 2Al(s) → Al2O3(s) + 2Fe(l)

7. Which statement correctly describes the oxidation number of the manganese atom (Mn) in MnI2 and MnO2?

A. Manganese has an oxidation number of +2 in MnI2 and +4 in MnO2.

8. Br2(l) + 2NaI(aq) → I2(s) + 2NaBr(aq)

Which elements are oxidized and reduced in the reaction?

D. Iodine (I) is oxidized, and bromine (Br) is reduced.

9. Which action occurs at an electrode of a galvanic cell?

D. electron transfer

10. Which statement best compares a battery and a galvanic cell?

A. A battery’s source of power is a galvanic cell in which a redox reaction produces electrical energy.

11. Zn + 2H+ → Zn2+ + H2

2Al + 3Cu2+ → 2Al3+ + 3Cu

Which elements are oxidized?

A. zinc (Zn) and aluminum (Al)

12. 2Cr(s) + 3Cu2+(aq) → 2Cr3+(aq) + 3Cu(s)

Which half reaction occurs at the cathode?

B. 3Cu2+(aq) + 6e– → 3Cu(s)

13. Written

14. Written

15. Written

I hope this helps!

A battery can be described as identical cells arranged in the same orientation to increase energy output. Therefore, option (A) is correct.

What is a battery?

Batteries are used in various electronic devices as a source of power. A battery can be described as an electronic device that is needed for storing chemical energy and transforming it into an electrical one.

The battery is an important device that helps electronic devices to work seamlessly and stores chemical energy, It provides electrical energy to many devices to work.

An electrochemical cell helps in the functioning of the battery. A battery may consist of only one or many electrochemical cells. The chemical reaction occurring inside the cell produces electrons at one electrode. These electrons start moving and produce electricity.

The identical cells in a battery are arranged in the same orientation to increase the energy output.

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How many hydroxide ions are needed to completely neutralize 1.0 liter of 0.50 m hcl?

Answers

The  number of hydroxide ions that are needed to completely neutralize 1.0 liter  of  0.50M HCl  is  calculated as below

find the  moles of H^+ used  from HCl
moles = molarity  x  volume
  = 0.50 x 1  =0.50  moles of  H^+  used

write ionic equation  for reaction

that is H ^+  + OH^-  = H2O

by  use of  mole  ratio between H^+ to OH^-  which  is 1:1 the moles of OH^- used = 0.50 x1/1 = 0.50  moles

By  use of Avogadro  law  constant

1  mole =  6.02 x10^23 ions
what about 0.5  moles

= 0.5 moles/ 1 moles  x 6.02  x10^23  = 3.01 x10^23 ions of OH^-

To neutralize 1.0 liter of 0.50 M HCl, you need 3.011 × 10²³ of hydroxide (OH⁻) ions.

To determine how many hydroxide ions are needed to completely neutralize 1.0 liter of 0.50 M HCl, follow a simple stoichiometry process:

The balanced chemical equation for the neutralization reaction is:

        HCl + OH⁻ → H₂O + Cl⁻

Given:

Volume of HCl solution = 1.0 literMolarity of HCl solution = 0.50 M

First, calculate the moles of HCl in the solution:

Moles of HCl = Molarity × Volume = 0.50M × 1.0L = 0.50moles

Since each mole of HCl provides one mole of H⁺ ions, there are 0.50 moles of H⁺ ions.

To completely neutralize these H⁺ ions, we need an equal number of OH⁻ ions:

Moles of OH⁻ needed = 0.50 moles

Since 1 mole of any substance contains Avogadro's number of entities (ions, molecules, etc.), which is approximately 6.022 x 10²³ entities per mole, we can convert moles of OH⁻ to number of ions:

Number of OH⁻ ions = 0.50moles x 6.022 x 10²³ ions/mole = 3.011 x 10²³

Which must be the same when comparing 1 mol of oxygen, O2, with 1 mol of carbon monoxide has, CO?

Answers

Answer: 1 mol of oxygen, O₂, and 1 mol of CO will have the same number of molecules, and the same number of atoms.

Justification:


Althought the question is too open, other answers may arise, the most remarkable similarity between the two compounds is that both are diatomic.

That means that both molecules oxygen, O₂, and carbon monoxide, CO have two atoms.

So, 1 mol of oxygen, O₂, and 1 mol of CO will have the same number of molecules, and the same number of atoms.


You must remember that 1 mol means a specific number. It is Avogadro's number, which is 6.022 × 10 ²³.

So 1 mol of CO and 1 mol of O₂ are the same number of representative particles: 6.022 ×10²³ molecules eac, and two times that number of atoms each (since each molecule has two atoms).

What will be the effect on the amount of gas produced if the experiment is repeated using 0.35g of k?

Answers

Hello there, I believe you are practicing for the AP Chemistry exam. If you are, so am I :) 

Anyways, the answer is that some gas will be produced but less than the amount of gas produced by Li.

To understand this, we first need to look at the number of moles we have of each substance. For 0.35 grams of Li, we have an estimated value (I am estimating because the multiple choice of the exam is non calculator) of 0.05 moles. For K however, we have an estimated value of 0.01 moles used.

Now look at the two equations: 2K +3H2O ---> 2H2 + 2K(OH)
                                                  2Li +3H2o ---> 2H2 +2Li(OH)
In the question, it specifies that H2 gas is produced as a product. Because both equations produce H2 in a 2:2  ratio (or a simplified ratio of 1:1), 0.05 moles of H2 will be produced for the Li equation, while 0.01 moles of H2 will be produced for the K equation. Therefore, the Li produces more moles of gas than K. 

I hope that makes sense. Happy studying :)

The effect on the amount of gas produced if the experiment is repeated using 0.35g of potassium is that less amount of hydrogen gas is produced.

What is the stoichiometry?

Stoichiometry of any reaction gives idea about the amount of species present and before the completion of the reaction.

Chemical reaction with repect to Lithium (Li) and Potassium (K) will be represented as:

2K + 3H₂O → 2H₂ + 2KOH

2Li + 3H₂O → 2H₂ + 2LiOH

From the stoichiometry of the reaction it is clear that 2 moles of K & Li produces 2 moles of hydrogen gas.

Moles will be calculated as:

n = W/M, where

W = given mass = 0.35g

M = molar mass

Moles of 0.35g Li = 0.35 / 6.9 = 0.0507 moles

Moles of 0.35g K = 0.35 / 39 = 0.0089 moles

From the moles of both elements it is clear that lithium will produce more gas.

Hence on replacing lithium with potassium, less gas will be produced.

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"what is the concentration of positive charge and mass in rutherford's atomic model called?"

Answers

The concentration of positive charge and mass in Rutherford's atomic model is called the nucleus. Rutherford's experiments involving the use of alpha particle beams directed onto thin metal foils demonstrated the existence of the nucleus. The nucleus of an atom contains positively charge particles called protons and other uncharged particles called neutrons. According to this model most volume of an atom is made up of an empty space. 

Calculate h3o+ in an aqueous solution that is 0.10M NaNO2 and 0.055M HNO2

Answers

Answer is: concentration of hydronium ions is 8.13·10⁻⁴ M.
c(HNO₂) = 0.055 M.
c(NaNO₂) = 0.10 M.
Ka(HNO₂) = 4.5·10⁻⁴.
This is buffer solution, so use Henderson–Hasselbalch equation: 
pH = pKa + log(c(NaNO₂) ÷ c(HNO₂)).
pH = -log(4.5·10⁻⁴) + log(0.055 M ÷ 0.10 M).
pH = 3.35 - 0.26.
pH = 3.09.
[H₃O⁺] = 10∧(-3.09).
[H₃O⁺] = 8.13·10⁻⁴ M.

A gas is contained in a thick walled balloon. when the pressure changes from 417 mm hg to 576 mm hg, the volume changes from ____ L to 4.78 L and the temperature changes from 497 K to 386 K

Answers

Initial volume is 8.5. Could I get best answer??

Answer: 8.5

Explanation:

What is the waste product bilirubin produced from? globin chains of hemoglobin iron found in hemoglobin molecules heme molecules lacking iron heme molecules with iron?

Answers

The waste product bilirubin is produced from the heme molecules lacking iron. Bilirubin is a highly insoluble antioxidant that is produced by the metabolism of heme. It is a brownish yellow pigment of bile, secreted by the liver in vertebrates, which gives to solid waste products (feces) their characteristic color. It is produced in bone marrow cells and in the liver as the end product of red blood cell breakdown.

Heme molecules deficient in iron produce the waste product bilirubin. Heme molecules are broken down into bilirubin during the breakdown of red blood cells.

Bilirubin is a waste product formed by iron-deficient heme molecules. The heme molecules are metabolised and transformed into bilirubin as red blood cells degrade. This bilirubin is then taken to the liver and processed further before being eliminated from the body via bile. Bilirubin is a yellowish pigment produced by the body during the breakdown of red blood cells. It is a byproduct of the heme metabolism. When red blood cells reach the end of their useful life, they undergo a process known as hemolysis. Heme molecules within red blood cells are transformed into bilirubin during this process.

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Iron, an important component of the steel used in the construction of buildings, bridges, and railroads, combines with oxygen to form fe2o3, which we recognize as rust. at room temperature, iron

Answers

I don't understand, what you want?

A substance that is not soluble in a polar solvent is

Answers

I believe its a Nonpolar substance.

calculate the pressure in atm, if 0.00825 moles occupies 174 mL at -15 celcius.

Answers

Answer is: the pressure is 1.12 atm.
n(O₂) = 0.00825 mol, amount of substance.
V = 174 mL ÷ 1000 mL/L = 0.174 L, volume of gas.

T = 15°C = 288.15 K; temperature.
R = 0.08206 L·atm/mol·K, universal gas constant.
Ideal gas law: p·V = n·R·T.
p = n·R·T / V.
p = 0.00825 mol · 0.08206 L·atm/mol·K · 288.15 K / 0.174 L.
p = 1.12 atm.


The pressure is calculated using the Ideal Gas Law. Given the moles, volume in liters, and temperature in Kelvin, the pressure is approximately 0.100 atm. This calculation involves converting units and applying the gas constant.

To calculate the pressure in atmospheres (atm) given the number of moles, volume, and temperature, we need to use the Ideal Gas Law formula:

PV = nRT

Here:

P is the pressure in atm.V is the volume in liters. Since the given volume is in milliliters (174 mL), we need to convert it to liters:

        174 mL × 0.001 L/mL = 0.174 L.

n is the number of moles, which is 0.00825 moles.R is the ideal gas constant, which is 0.0821 (L atm)/(K mol).T is the temperature in Kelvin. We need to convert the temperature from Celsius to Kelvin:

        T = -15 °C + 273 = 258 K.

Now, we substitute the known values into the Ideal Gas Law equation:

P × 0.174 L = 0.00825 moles × 0.0821 (L atm)/(K mol) × 258 K

Simplify and solve for P:

P = (0.00825 moles × 0.0821 × 258) / 0.174

P ≈ 0.100 atm

When bismuth-212 undergoes alpha decay, it becomes which of the following?


A asatine-208 + an alpha particle
B lead-210 + an alpha particle
C polonium-210 + and alpha particle
D thallium-208 + and alpha particle

Answers

Answer is: D thallium-208 + and alpha particle.
Nuclear reaction: ²¹²Bi → ²⁰⁸Tl + α (alpha particle).
Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.

What mass of KBr is present in 25 mL of a 0.85 M solution of potassium chloride?

Answers

Answer : The correct answer for mass of KBr = 2.53 g

Given :

Molarity of KBr solution = 0.85 M

Volume of KBr solution = 25 mL

Converting volume from mL to L ( 1 L = 1000 mL )

[tex] Volume of solution = 25 mL * \frac{1 L }{1000mL} [/tex]

Volume of solution = 0.025 L

Mass of KBr = ?

Mass of KBr can be calculated using following steps :

1) To find mole of Kbr :

Mole of KBr can be calculated using molarity .

Molarity : It is defined as mole of solute present in volume of solution in Liter .

It uses unit as M or [tex] \frac{mol}{L} [/tex]

It can be expressed as :

[tex] Molarity = \frac{mol of solute (mol)}{volume of solution (L)} [/tex]

Plugging value of molarity and volume

[tex] 0.85 \frac{mol}{L} = \frac{mol of Kbr}{0.025 L} [/tex]

Multiplying both side by 0.025 L

[tex] 0.85 \frac{mol}{L} * 0.025 L = \frac{mole of KBr}{0.025 L} * 0.025 L [/tex]

Mole of KBr = 0.02125

2) To find mass of Kbr :

Mass of Kbr can be calculated using mole . Mole can be expressed as :

[tex] Mole (mol) = \frac{mass (g) }{molar mass \frac{g}{mol} } [/tex]

Mole of Kbr = 0.02125 mol

Molar mass of KBr = 119.00 [tex] \frac{g}{mol} [/tex]

Plugging values in mole formula

[tex] 0.02125 mol = \frac{mass (g)}{119.00 \frac{g}{mol}} [/tex]

Multiplying both side by 119.00 [tex] \frac{g}{mol} [/tex]

[tex] 0.02125 mol * 119.00 \frac{g}{mol} = \frac{mass (g)}{119.00 \frac{g}{mol}} * 119.00\frac{g}{mol} [/tex]

Mass of KBr = 2.53 g


Final answer:

To find the new volume of a diluted 0.885 M KBr solution after dilution to 0.500 M, use the formula (M1×V1) / M2, resulting in a new volume of 266.85 mL.

Explanation:

The subject of this question is determining the new volume of a diluted potassium bromide (KBr) solution in chemistry. When a 0.885 M solution of KBr with an initial volume of 76.5 mL is diluted to a concentration of 0.500 M, we can use the concept of molarity (M), which is defined as moles of solute per liter of solution, to find the new volume.

To find the new volume (V2) after dilution, we can apply the formula M1×V1 = M2×V2, where M1 and V1 are the initial molarity and volume, and M2 is the final molarity. By rearranging the formula, V2 = (M1×V1) / M2. Substituting the given values, we get V2 = (0.885 moles/L × 76.5 mL) / 0.500 moles/L = 133.425 mL / 0.500 = 266.85 mL. Thus, the new volume is 266.85 mL.

Compared to the nucleus 5626Fe, what is the radius of the nucleus 112 48Cd?

Answers

Answer is: nucleus of Cd is 1.26 times greater.
The Nuclear radius formula or radius of nucleus formula: R = R₀ · ∛A.
R is nuclear radius.
R₀ is empirical constant, R₀ = 1.2 10⁻¹⁵ m.
A is number of nucleon.
R(Fe) = 1.2·10⁻¹⁵ m · ∛56.
R(Fe) = 4.59·10⁻¹⁵ m.
R(Cd) = 1.2·10⁻¹⁵ m · ∛112.
R(Cd) = 5.78·10⁻¹⁵ m.
R(Cd) / R(Fe) = 5.78·10⁻¹⁵ m / 4.59·10⁻¹⁵ m.
R(Cd) / R(Fe) = 1.26.

How many kj of heat are needed to completely vaporize 1.30 moles of h2o? the heat of vaporization for water at the boiling point is 40.6 kj/mole?

Answers

The Kj of heat that  are needed to completely vaporize 1.30  moles of H2O  if  the heat of vaporization  for water is 40.6 Kj/mole  is calculated as  below

Q(heat) = moles x heat  of vaporization)

=1.30 mol  x40.6 kj/mol= 52.78 Kj  is needed

Explanation:

Heat of vaporization is defined as the amount of heat required to change one mole of a liquid into vapor state without any change in the temperature.

It is known that for 1 mole of water, latent heat of vaporization is 40.6 kJ/mol.

Therefore, heat of vaporization for 1.30 moles will be calculated as follows.

              [tex]1.30 moles \times 40.6 kJ/mol[/tex]

               = 52.78 kJ

Thus, we can conclude that the 52.78 kJ of heat are needed to completely vaporize 1.30 moles of [tex]H_{2}O[/tex].

Object A has 604 J of kinetic energy and 285 J of gravitational potential energy. Object B has 481 J of kinetic energy and 300 J of gravitational potential energy. Which object has more mechanical energy? Object A has more mechanical energy. Object B has more mechanical energy. They have the same amount of mechanical energy. There is not enough information to know.

Answers

Mechanical energy can be defined as the sum of kinetic energy and the gravitational potential energy. 

Object A has kinetic energy as 604 J and gravitational potential energy as 285 J.
Hence, mechanical energy of A = 604 J + 285 J
                                                   = 889 J

Object B has kinetic energy as 481 J and gravitational potential energy as 300 J.
Hence, mechanical energy of A = 481 J + 300 J
                                                   = 781J

Hence, object A has more mechanical energy than B.


Answer:

Object A has more mechanical energy.

Explanation:

Object A has more mechanical energy.

What is the new mass/volume (m/v)% of a koh solution that is prepared by diluting 110 ml of a 6% (m/v) koh solution to 330 ml?

Answers

we can use the dilution formula where we make diluted solutions from more concentrated solutions
c1v1 = c2v2 
c1 is concentration and v2 is volume of the concentrated solution
c2 is concentration and v2 is volume of the diluted solution to be prepared 
in this case we have been given m/v % which we can use as the concentrations
substituting the values in the equation 
6% x 110 mL = C x 330 mL 
C = 2%

the new m/v % of the diluted solution prepared is 2% (m/v) 

Le Châtelier's principle tells us that chemical _____ will adjust in an attempt to remove a stressor.
a. formulas
b. equations
c. equilibrium
d. concentrations

Answers

Le Châtelier's principle tells us that chemical c. equilibrium will adjust in an attempt to remove a stressor.

Which reaction may be described as an acid-base neutralization reaction? 1. be(oh)2 + h2so4 → beso4 + 2 h2o 2. ba(oh)2 + 2 licl → bacl2 + 2 lioh 3. naoh + h2o → h3o + + nao− 4. hno2 + h2o → h3o + + no− 2?

Answers

 The reaction that describe an acid an acid- base neutralization reaction is

Be(OH)2 + H2SO4 = BeSO4 +2 H2O

Neutralization reaction involve an acid  and a base reaction whereby the acid  neutralization the base. for the reaction above Be(OH)2 is  the base while H2SO4 is the acid  thus H2SO4  neutralizes  Be(OH)2 to form BeSO4 and H2O

Assume that the rate law for a generic chemical reaction is rate = [a][b]3 . what is the reaction order in a, the reaction order in b, and the overall reaction order?

Answers

If the reaction is
     X + Y → Products

Then the rate is
     R = k[X]ᵃ [Y]ᵇ

Where,
R = the rate of the reaction (mol L⁻¹ s⁻¹)
k = rate constant
[X] and [Y] = concentrations of the reactants (mol L⁻¹)
a = order of the reaction with respect to X
b = order of the reaction with respect to Y
overall reaction order, n = a + b

according to the given rate expression,
rate = [a][b]³

order of the reaction with respect to 'a' is 1
order of the reaction with respect to 'b' is 3

Overall reaction order = 1 + 3
                                       = 4

The order of reaction in a is 1 while the order of reaction in b is 3.

What is order of reaction?

The rate law is obtained from the reaction equation or from experiment. We can determine the order of reaction by summing up the exponents in the rate law as shown in the equation of the rate law.

Now, we have;  rate = k[a][b]3, the order of reaction in a is 1 while the order of reaction in b is 3.

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Which quantity or quantities must always be the same on both sides of a chemical equation? (a) the number of atoms of each kind (b) the number of molecules of each kind (c) the number of moles of each kind of molecule (d) the sum of the masses of all substances involved?

Answers

Explanation:

An equation that contains same number of atoms on both reactant and product side is known as a balanced chemical equation.

Also, mass of substances involved and formed in a chemical reaction will be equal.

For example, [tex]2K + Cl_{2} \rightarrow 2KCl[/tex]

Number of K atoms on both reactant and product side are 2.

Number of Cl atoms on both reactant and product side are 2.

Therefore, this equation is balanced.

Also, mass of K = 39.09 g/mol, mass of Cl = 35.45 g/mol.

Sum of reactant molecules = [tex](2 \times 39.09 g/mol) + (2 \times 35.45 g/mol)[/tex]

                                             = 149.08 g/mol

Sum of product molecules = [tex]2 \times (39.09 g/mol + 35.45 g/mol)[/tex]

                                             = 149.08 g/mol

Therefore, masses of atoms involved is same on both reactant and product side.

Thus, we can conclude quantity or quantities that must always be the same on both sides of a chemical equation are as follows.

the number of atoms of each kind.the sum of the masses of all substances involved.

The quantities which must always be the same on both sides of a chemical equation is:

(a) the number of atoms of each kind.

(d) the sum of the masses of all substances involved.

A chemical reaction refers to a chemical process that involves the rearrangement or transformation of the ionic, atomic or molecular structure of a chemical element through the breakdown and formation of chemical bonds in order to produce a new compound.

A chemical equation is typically used to denote or represent a chemical reaction between two or more chemical elements.

A balanced chemical equation is one in which the number of atoms on the reactant (left) side is equal to the number of atoms on the product (right) side.

This ultimately implies that, both the charge on each atom and sum of the masses of the chemical substances in a chemical equation are properly balanced.

Additionally, all chemical equations must be in accordance with the Law of Conservation of Mass because mass can neither be created nor destroyed.

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In alpha and beta decay the parent element and the daughter element can be

Answers

In alpha and beta decay the parent element and the daughter element will be different isotope and not the same. 
This is because as alpha particles comes out; the new element will have two less in atomic number; that is the atomic number will reduce by two and the mass number will reduce by four. While in a beta particle decay, the new element will have one higher in atomic number; that is the atomic number will increase by one. 

A 5.00 L sample of helium at STP expands to 20.0 L. What is the new pressure on the gas?

Answers

Answer is: the new pressure on the gas is 0.25 atm or 25.33 kPa.
Boyle's Law: the pressure volume law - volume of a given amount of gas held  varies inversely with the applied pressure when the temperature and mass are constant.
p₁V₁ = p₂V₂.
1 atm · 5.00 L = p₂ · 20.0 L.
p₂ = 1 atm · 5 L ÷ 20.0 L.
p₂ = 0.25 atm, but same amount of helium.

What volume of O2(
g. at 810. mmHg pressure is required to react completely with a 4.50g sample of C(s) at 48°C? 2 C(s) + O2(
g. → 2 CO(
g.

Answers

Answer is: volume of oxygen is 4.63 liters.
Balanced chemical reaction: 2C + O₂ → 2CO.
m(C) = 4.50 g.
n(C) = m(C) ÷ M(C).
n(C) = 4.50 g ÷ 12 g/mol.
n(C) = 0.375 mol.
From chemical reaction: n(C) : n(O₂) = 2 : 1.
n(O₂) = 0.1875 mol.
T = 48°C = 321.15 K.
p = 810 mmHg ÷ 760 mmHg/atm= 1.066 atm.
R = 0.08206 L·atm/mol·K.
Ideal gas law: p·V = n·R·T.
V(O₂) = n·R·T / p.
V(O₂) = 0.1875 mol · 0.08206 L·atm/mol·K · 321.15 K / 1.066 atm.
V(O₂) = 4.63 L.

Which energy changes are associated with a liquid boiling?



A. Energy is released, and potential energy decreases.
B. Energy is absorbed, and potential energy increases.
C. Energy is released, and kinetic energy decreases.
D. Energy is absorbed, and kinetic energy increases.

Answers

When a liquid boils, energy is absorbed, and potential energy increases.

The energy changes associated with a liquid boiling are:

Energy is absorbed, and potential energy increases.

Boiling involves supplying energy to break intermolecular forces and convert the liquid into a gas, leading to an increase in potential energy.

During boiling, energy is absorbed to convert the liquid into gas, increasing the potential energy of the molecules. The temperature remains constant as energy is used for the phase change. The correct answer is B.

A liquid changes phases from a liquid to a gas as it boils. This process is associated with the absorption of energy. Specifically, energy in the form of heat is absorbed by the liquid to overcome the intermolecular forces that hold the molecules together. The molecules' potential energy rises as a result.

Kinetic energy does not increase significantly during the boiling process. Instead, the absorbed energy converts to potential energy, allowing molecules to move from the liquid phase to the gas phase. This is why the temperature of the liquid remains constant at its boiling point; all additional energy is used for the phase change rather than increasing the temperature.

An example of this can be seen when water boils. When you heat water on a stove, the temperature rises until it reaches [tex]100^{\circ}C[/tex] ([tex]212^{\circ}F[/tex]). At this boiling point, the water does not get hotter. Instead, the energy absorbed continues to be used to convert the water from liquid to vapor, indicating that the energy is going into increasing the potential energy.

Sulfuric acid reacts with aluminum hydroxide by double replacement.
a. if 30.0 g of sulfuric acid reacts with 25.0 g of aluminum hydroxide, identify the limiting reactant.
b. determine the mass of excess reactant remaining.
c. determine the mass of each product formed. assume 100% yield.

Answers

a. 
The balanced equation for the reaction between sulfuric acid and aluminium hydroxide is,
                        3H₂SO₄     +   2Al(OH)₃ → Al₂(SO₄)₃ +   6H₂O

mass of H₂SO₄  =        30.0 g             
Molar mass of H₂SO₄  =   98 g/mol
moles of H₂SO₄ = 30.0 g /98g /mol = 0.306 mol

mass of Al(OH)₃            =         25.0 g            
Molar mass of Al(OH)₃  =   78 g/mol
moles of Al(OH)₃           = 25.0 g/ 78 g/mol = 0.321 mol

Stoichiometric ratio between H₂SO₄  and Al(OH)₃ is 3 : 2

Hence reacted moles of H₂SO₄ = 0.306 mol
            reacted moles of Al(OH)₃ = 0.306 mol x (2 / 3) = 0.204 mol

Hence the limiting reactant is H₂SO₄ 

b.
According to the above calculation, the excess reactant is Al(OH)₃. 

The reacted moles of Al(OH)₃ = 0.306 mol x (2 / 3) = 0.204 mol

The added moles of Al(OH)₃ = 0.321 mol

Hence the remaining Al(OH)₃ moles = added moles - reacted moles
                                                          = 0.321 mol - 0.204 mol
                                                          = 0.117 mol

Molar mass of Al(OH)₃  =   78 g/mol
Remaining mass of Al(OH)₃ = number of moles x molar mass
                                             = 0.117 mol x 78 g/mol
                                             = 9.126 g

c. 

The products formed from the reaction between aluminium hydroxide and sulfuric acid are Al₂(SO₄)₃ and H₂O

The limiting reactant is H₂SO₄ 

The stoichiometric ratio between H₂SO₄  and Al₂(SO₄)₃ is 3 : 1
Reacted moles of H₂SO₄ = 0.306 mol
Hence the moles of Al₂(SO₄)₃ formed = 0.306 mol / 3
                                                             = 0.102 mol
Molar mass of Al₂(SO₄)₃  = 342 g/mol
Mass of Al₂(SO₄)₃  formed = 0.102 mol x 342 g/mol
                                           = 34.884 g

The stoichiometric ratio between H₂SO₄  and H₂O is 3 : 6
Reacted moles of H₂SO₄ = 0.306 mol
Hence the moles of H₂O formed = 0.306 mol x (6 / 3)
                                                    = 0.612 mol
Molar mass of H₂O  = 18 g/mol
Mass of H₂O  formed = 0.612 mol x 18 g/mol
                                   = 11.016 g


Final answer:

The limiting reactant is sulfuric acid. The mass of excess reactant remaining is 13.075 g. The mass of aluminum sulfate formed is 104.738 g and the mass of water formed is 5.562 g.

Explanation:

The question is about a chemical reaction where sulfuric acid reacts with aluminum hydroxide by double displacement to produce aluminum sulfate and water.

To identify the limiting reactant, we need to know the moles of sulfuric acid and aluminum hydroxide. Using the molecular weights (98.09 g/mol for sulfuric acid and 78.0 g/mol for aluminum hydroxide), we find that we have 0.306 moles of sulfuric acid and 0.32 moles of aluminum hydroxide. The reaction ratio from the balanced chemical equation is 1:2, implying we need twice as many moles of sulfuric acid as aluminum hydroxide. Therefore, sulfuric acid is the limiting reactant.Using the stoichiometry of the reaction, we find out that all the sulfuric acid is consumed, leaving excess aluminum hydroxide. The mass of excess reactant remaining is calculated by subtracting the mass of aluminum hydroxide consumed from the initial mass of aluminum hydroxide. Aluminum hydroxide consumed is (0.306 moles / 2) * 78.0 g/mol = 11.925 g. So, the mass of excess reactant remaining is 25.0 g (initial) - 11.925 g(consumed) = 13.075 gIn terms of mass of each product formed, we get aluminum sulfate and water. The mass of aluminum sulfate formed is the moles of limiting reactant times the molar mass of the product, i.e., 0.306 moles * 342.15 g/mol = 104.738 g. The mass of water formed is also calculated similarly, giving 5.562 g.

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