Answer:
Codominance
Explanation:
Codominance occurs when two heterozygous allele for a trait is expressed equally in the an organism's phenotype with neither allele being dominant or recessive. In codominance, none of the allele hides the expression of the other allele. So when two alleles are crossed, the offspring carries a combination of the parents phenotype without anyone masking the other.
From the question, the type of genetic pattern of the leopard geckos display is codominance.
Darius is observing a family of geese, which includes a male goose, female goose, and several goslings. When a dog approaches the geese, the male goose hisses at the dog and flaps its wings threateningly.
Is the behavior of the male goose an example of an adaptation?
A. Yes, because the behavior is inherited and helps the goose and its offspring survive.
B. Yes, because the behavior is a response to another animal.
C. No, because adaptations are body structures, not behaviors.
D. Maybe, depending on whether or not the dog attacks the geese.
Answer:
A. Yes, its an inherited behaviour that helps the goose and its offspring to survive.
Explanation:
Adaptation could be a trait with a functional role in an individual or animal that is maintained and has also evolved as a result of natural selection.
The male goose hissing and wing flapping is an adaptive trait of scaring away predators.
Answer:
Yes
Explanation:
which of the following is a scientific question
Explanation: whats the following ?
Answer: What are the options?
Explanation:
What are some similarities between nerves and hormones?
Answer:
The biggest difference between the two is that the nervous system uses electrical impulses to send signals through neurons, whereas the hormonal system uses chemical messengers transported into blood plasma to target cells. While endocrine system is slow, nervous impulse is immediate/rapid. Hormones are transported chemically through blood, nervous impulses are transported electrochemically through nerve fibres. Hormones affect different organs of the body and has a widespread effect, while nervous impulses afeect only a particular part of the body. Hormonal effect is long lasting whereas nervous effect is short lived. Hormones can bring about a metabolic change but nervous impulse impulses cannot bring about a metabolic change.
Big Bend National Park in Texas is mostly Chihuahuan desert, where rainfall averages about 10 inches per year. Yet, it is not uncommon when hiking in this bone-dry desert to encounter mosses and ferns. One such plant is called "flower of stone." It is not a flowering plant, nor does it produce seeds. Under arid conditions, its leaflike structures curl up. However, when it rains, it unfurls its leaves, which form a bright green rosette on the desert floor. Consequently, it is sometimes called the "resurrection plant." At first glance, it could be a fern, a true moss, or a spike moss.
What feature of both true mosses and ferns makes it MOST surprising that they can survive for many generations in dry deserts?
A. lack of cuticle
B. a gametophyte generation that is dominant
C. flagellated sperm
D. lack of true roots
Answer: Option C
Explanation:
There is no similarity seen in the ferns and mosses but biologically they have similarities. Both the plants are very primitive in nature and reproduce via sexual reproduction.
They cohabit with each other in moist and shady places. They produce motile sperm which swim through water ad reaches the egg. This is reason they are found in damp places.
Their ability of producing flagellated sperm makes them successful for their survival and called as resurrent plant. They have the ability to survive complete desiccation and grow as soon as they get favorable condition. They also have alternation of generation which also helps in its survival.
The most surprising feature of mosses and ferns that enables them to survive in deserts is their flagellated sperm, which requires water for fertilization. However, certain adaptations, like those seen in the resurrection plant, allow these plants to thrive in such conditions.
Explanation:The feature of both true mosses and ferns that makes it most surprising that they can survive for many generations in dry deserts is their flagellated sperm. Both mosses and ferns have flagellated sperm that requires water to reach the eggs for fertilization, which seems at odds with a desert environment where water is scarce.
However, many desert plants have adaptations to make the most of the limited water available. For example, the resurrection plant (or 'flower of stone') mentioned unfurls its leaves to collect rainfall when available and curls up to conserve water when conditions are arid.
These adaptations allow the plant to take advantage of the infrequent rainfalls in the desert and ensure the survival of these plants in this extreme environment.
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In man, assume that spotted skin (S) is dominant over non-spotted skin (s) and that wooly hair (W) is dominant over non-wooly hair (w). Cross a marriage between a heterozygous spotted, non-wooly man with a heterozygous wooly-haired, non-spotted woman. Give genotypic and phenotypic ratios of offspring.
Answer:
Total four genotypes and its frequency
SsWw – 4/16
ssWw- 4/16
Ssww - 4/16
ssww - 4/16
Phenotype –
SsWw – Heterozygous Spotted skin and heterozygous wooled hair
ssWw - Homozygous non-spotted skin and heterozygous wooled hair
Ssww - Heterozygous Spotted skin and Homozygous non -wooled hair
ssww - Homozygous non-spotted skin and Homozygous non -wooled hair
Explanation:
Given -
Allele for spotted skin is "S"
Allele for non-spotted skin is "s"
Allele for Wooly hair is "W"
Allele for non-wooly hair is "w"
Allele "S" is dominant over "s"
And Allele "W" is dominant over "w"
Cross is carried out between heterozygous spotted, non-wooly man and heterozygous wooly-haired, non-spotted woman
Genotype of heterozygous spotted, non-wooly man - Ssww
Genotype of heterozygous wooly-haired, non-spotted woman - ssWw
Ssww * ssWw
Sw Sw sw sw
sW SsWw SsWw ssWw ssWw
sw Ssww Ssww ssww ssww
sW SsWw SsWw ssWw ssWw
sw Ssww Ssww ssww ssww
Total four genotypes and its frequency
SsWw – 4/16
ssWw- 4/16
Ssww - 4/16
ssww - 4/16
Phenotype –
SsWw – Heterozygous Spotted skin and heterozygous wooled hair
ssWw - Homozygous non-spotted skin and heterozygous wooled hair
Ssww - Heterozygous Spotted skin and Homozygous non -wooled hair
ssww - Homozygous non-spotted skin and Homozygous non -wooled hair
The branch of science which deals with the gene and inheritance is called genetics.
The correct answer is 1:2:1 and 3:1
The cross between two characters is called a dihybrid cross.
According to the question, the parent's genes are Ss and Ww.
The gamete formed during the gametogenesis is S and s for one parent and W and w for another.
This gamete and fused with any of the gametes to increase the variation.
After the cross the result is
SW, Sw, sW, and sw.
Hence the genotype ratio is 1:1:1:1 but the phenotype ratio is spotted skin: nonspotted skin is 2:2.
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The cycling of carbon between the living and non-living parts of the Earth system is an important result of which of the following processes?
A: Plants and animals exchanging gases with the atmosphere
B: Condensation of water vapor leading to cloud formation
C: Herbivores digesting plant materials to get nutrients
D: Methane entering the atmosphere from volcanic activity
The carbon cycling between the living and non-living components of the Earth's system is primarily due to the exchange of gases between plants and animals and the atmosphere. During photosynthesis, plants absorb carbon dioxide and convert it into glucose. The animals that consume these plants then respire, releasing the carbon back into the atmosphere.
Explanation:The cycling of carbon between the living and non-living parts of the Earth system is largely the result of plants and animals exchanging gases with the atmosphere. This process is a part of the carbon cycle, where plants absorb carbon dioxide from the atmosphere during photosynthesis and convert it into glucose. These plants are then consumed by animals, which in turn respire, releasing the carbon back into the atmosphere in the form of carbon dioxide. Thus, choice 'A' is the correct one.
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Which statement is true of mitosis?
A) mitosis plays a vital role in sexual reproduction
B) mitosis plays a vital role in an organisms growth
C) During the process of mitosis, new organisms are created
D) during the process of mitosis, haploid cells are created
Answer:Mitosis plays a vital role in an organism's growth.
Explanation:During reproduction, new organisms are created. Sometimes, the new organisms are created asexually through processes like binary fission, budding, or fragmentation. In other cases, new organisms are created sexually when a sperm cell fertilizes an egg cell.
Growth is different from reproduction. When an organism grows, it creates more of its own cells through the process of mitosis. No new organisms are created during growth, however.
Drag the missing word into place
When classifying living things,
is the largest division.
domain
class
kingdom
Answer:
Domain is the largest division. See the attachment for more help!
In a particular recessive genetic disorder, you find the allele frequency for this recessive allele in a population is 0.02. Assuming the population is in Hardy-Weinberg Equilibrium over the last generation, which of the following are possible statements about this population? Select all that apply. Select one or more: a. This genetic disorder could display severe and potentially fatal health complications only in individuals above 50 years of age. b. Most of the recessive alleles are found in heterozygous individuals. c. Any individuals in this population that are homozygous recessive are sterile. d. The population under investigation could have been formed by a founder event several hundred years ago.
Final answer:
In a recessively inherited disorder with a given allele frequency and an assumption of Hardy-Weinberg Equilibrium, complications appearing late in life, a higher presence of alleles in heterozygous individuals, and the possibility of a founder event are plausible statements. However, sterility in homozygous recessive individuals cannot be concluded without specific disorder information.
Explanation:
When considering the statements regarding a population with a recessive genetic disorder allele frequency of 0.02 and assuming Hardy-Weinberg Equilibrium (HWE), we can evaluate the given options:
a. This genetic disorder could display severe and potentially fatal health complications only in individuals above 50 years of age: This is possible since some disorders may have late onset or become symptomatic later in life.b. Most of the recessive alleles are found in heterozygous individuals: This is true given the low frequency of the allele (q), suggesting that homozygous individuals (q²) will be rare, making heterozygous carriers (2pq) more common in the population.c. Any individuals in this population that are homozygous recessive are sterile: This cannot necessarily be concluded from the allele frequency and the assumptions of HWE, as sterility would be a specific trait of the disorder, not a given for all recessive genetic disorders.d. The population under investigation could have been formed by a founder event several hundred years ago: This is possible as the founder effect is a form of genetic drift which can cause rare alleles to become prevalent in a population descended from a small ancestral group.Therefore, the correct statements that apply, based on the information provided and HWE, are a, b, and possibly d, but not c since it requires additional specific information about the genetic disorder.
The population could have late-onset severe complications, most recessive alleles are in heterozygotes, fertility depends on the disorder, and a founder event may explain allele frequencies.
a. This genetic disorder could display severe and potentially fatal health complications only in individuals above 50 years of age.
This statement is plausible as certain genetic disorders may manifest symptoms later in life, and the age of onset can vary. If the disorder in question has a late onset, individuals above 50 years may be more prone to severe health complications associated with the recessive allele.
b. Most of the recessive alleles are found in heterozygous individuals.
This statement is accurate based on the principles of Hardy-Weinberg Equilibrium. In a population in equilibrium, the frequency of homozygous recessive individuals is q^2, where q is the frequency of the recessive allele. The frequency of heterozygous individuals is 2pq, where p is the frequency of the dominant allele. If q is small (as indicated by the allele frequency of 0.02), then 2pq is much larger than q^2.
c. Any individuals in this population that are homozygous recessive are sterile.
This statement is not necessarily true. The fertility or sterility of homozygous recessive individuals depends on the specific genetic disorder. Some recessive genetic disorders may impact fertility, but it is not a general rule for all recessive alleles.
d. The population under investigation could have been formed by a founder event several hundred years ago.
This statement is plausible. A founder event, where a small group establishes a new population, can lead to a deviation from the allele frequencies in the larger source population. Over time, genetic drift in the smaller population can result in different allele frequencies, consistent with the observed frequency of the recessive allele in this scenario.
The poly(A) sequence that is added to RNA during processing: helps prevent rapid breakdown of the messenger RNA. is needed for ribosomes to attach to messenger RNA. aids in the accuracy of translation of the messenger RNA into protein. helps prevent formation of complex three-dimensional structures in the messenger RNA.
Answer:
Option A, helps prevent rapid breakdown of the messenger RNA
Explanation:
The poly-A tail is a chain of adenine nucleotides which when get attached to the messenger RNA during RNA processing enhances the stability of the molecule and therefore prevents it from breaking down. This is required because after the transcription of gene in a eukaryotic cell, newly formed RNA molecule undergoes several modifications. It also helps is preventing the new RNA from enzymatic degradation in the cytoplasm and translation.
Hence, option A is correct
The poly(A) tail is added to mRNA to protect it from degradation, assist in its export from the nucleus, and support the initiation of translation. It does not directly influence the accuracy of translation or prevent the mRNA from forming complex structures.
The Function of the Poly(A) Tail in mRNA Processing
The poly(A) tail is a critical feature of messenger RNA (mRNA) in eukaryotic cells. Following the completion of transcription, the 3' end of pre-mRNA is processed to form a mature mRNA molecule. This processing includes the polyadenylation mechanism, where an enzyme known as poly(A) polymerase adds about 200 adenosine monophosphates to the mRNA creating a poly(A) tail. This sequence, traditionally located at the 3' end of the mRNA, serves several essential functions. It protects the mRNA from enzymatic degradation in the cytoplasm, aids in the export of mRNA from the nucleus, and is involved in the initiation of translation.
The addition of the poly(A) tail ensures the stability of the mRNA molecule by safeguarding it against rapid breakdown and thus prolongs its half-life, which is essential for producing proteins. Additionally, the poly(A) tail aids in the recognition and binding of proteins that are essential for exporting the processed mRNA to the cytoplasm. Here, ribosomes can attach and initiate translation, synthesizing the corresponding protein based on the mRNA sequence. The poly(A) tail does not, however, have a direct role in aiding the accuracy of translation or in preventing the formation of complex three-dimensional structures within the mRNA. Its primary role is in mRNA stability and facilitating protein synthesis
What genetic mutation is sickle cell anemia caused by?
"Sickle-cell anemia is caused by a point mutation in the β-globin chain of hemoglobin."
More can be found on the wikipedia page about point mutation if you want more information about the specifics.
Starch is a polymer of glucose molecules in plants with a role analogous to that of glycogen in animals. Starch synthesis requires ADP‑glucose generated by ADP‑glucose pyrophosphorylase. The biochemical mechanism of ADP‑glucose pyrophosphorylase catalysis is similar to that of UDP‑glucose pyrophosphorylase. What is the driving force for the ADP‑glucose pyrophosphorylase reaction?
a. production of ADP‑glucose
b. hydrolysis of ADP‑glucose
c. production of pyrophosphate
d. hydrolysis of pyrophosphate
The driving force for the ADP-glucose pyrophosphorylase reaction is hydrolysis of pyrophosphate.
Explanation:The driving force for the ADP‑glucose pyrophosphorylase reaction is d. hydrolysis of pyrophosphate.
Here's why:
The reaction is:
ATP + glucose-1-phosphate + pyrophosphate <=> ADP-glucose + phosphate
The hydrolysis of pyrophosphate (PPi) into two inorganic phosphates releases a significant amount of free energy (approximately -30 kJ/mol). This free energy release drives the reaction forward, even though the difference in free energy between ADP-glucose and ATP is small.
The production of ADP-glucose (a readily usable sugar precursor) is important for starch synthesis, but it is the hydrolysis of PPi that provides the necessary energy for the reaction to occur.
Therefore, option d is the correct answer.The driving force for the ADP‑glucose pyrophosphorylase reaction is production of ADP-glucose.
Explain the characteristics scientists use when observing organisms and placing them in the six kingdoms.
Answer:
Classification of organisms is done while considering many factors such as:
Cell type- whether the organism is prokaryotic or eukaryotic
Cell structure- This includes both the presence and composition of the cell wall
Body type- whether the organism is multicellular or unicellular
Mode of nutrition- the method through which the organism achieves its nutritional requirement, by consuming other organisms (heterotroph) or making its own food (autotroph)
The color operon codes for structural genes that convert pigment A to pigment C. The operon is regulated by a gene called Paint. In wild type cells, the operon is transcribed in the presence of pigment A, but not in the absence of A. In Paint- mutants, the operon is constitutively transcribed. Is this operon inducible or repressible? Group of answer choices Inducible, because wild type transcription occurs in the presence of pigment A. Repressible, because wild type transcription is repressed in the presence of A. It cannot be determined because the number of structural genes is unknown. Inducible, because the operator in Paint- mutants can still bind to pigment A. Repressible, because Paint- transcription only occurs in the presence of pigment A.
Answer:
Inducible, because wild type transcription occurs in the presence of pigment A.
Explanation:
In the question, we were given that color operon codes for structural genes that convert pigment A to pigment C and is regulated by a gene called Paint. Since transcription occurs in the presence of pigment A then it means pigment A induces the transcription. This makes it Inducible, because wild type transcription occurs in the presence of pigment A.
The color operon, which is turned on in the presence of pigment A and constantly expressed in a Paint- mutant, is an example of an inducible operon.
Explanation:The color operon codes for structural genes that convert pigment A to pigment C is an example of an inducible operon. In wild type cells, the operon is transcribed in the presence of pigment A, indicating that the operon is induced when A is present. In Paint- mutants where the operon is constantly being expressed, regardless of the presence or absence of pigment A, this further suggests the operon is inducible since it can be turned on in the absence of a repressor.
Inducible operons are often associated with metabolic pathways where the end product is not constantly required (in contrast with repressible operons, which are typically associated with biosynthetic pathways that produce substances necessary for growth). In the case of this color operon, pigment A serves as the inducer, similar to how lactose acts as the inducer in the lactose (lac) operon.
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How can rain and hail fall from the same cumulonimbus cloud?
When clouds get so full of water droplets that they can not hold any more, the water falls back to the ground as rain but sometimes water droplets freeze and fall to the ground as snow, sleet, or hail.
2. The mRNA for a well-known secretory protein is isolated and placed in a test tube in the presence of all the substances required for in vitro protein synthesis. The sequence of the protein produced in vitro is then compared to the sequence of the secretory protein purified from the extracellular fluid. The sequences of the two proteins are not the same. What do you predict is the difference between the two proteins and why do you see this difference
Answer:
Post-transnational adjustment is a significant character of secretory protein which happens during translocation of protein through the endoplasmic reticulum and Golgi bodies. These proteins have some sign arrangement for this translocation and these successions are cut in the wake of moving toward the particular area of the cell.
If there should arise an occurrence of in vitro amalgamation of the above protein, the protein basically interpreted from the RNA and no cutting of the sign grouping and another succession which are cut in any case during translocation happens. Because of this succession of protein varies from the in vivo protein.
The difference in the protein sequences can be due to post-transcriptional and post-translational modifications in the cell, such as splicing, alternative gene splicing, and glycosylation.
Explanation:The difference between the proteins produced in vitro and purified from the extracellular fluid is likely due to post-transcriptional and post-translational modifications that occur in the cell but not in the test tube. For the protein made in the test tube, the sequence reflects the exact sequence of the mRNA. However, inside the cell, mRNA undergoes various modifications like splicing, addition of a 5' methylguanosine cap, and a 3' poly A tail.
Additionally, the sequence difference could also be attributed to alternative gene splicing, a mechanism that allows a single gene to code for multiple proteins by varying the sequence of exons enclosed within the mRNA. The sequences of these proteins will thus differ due to varying exon combinations. Another factor that could contribute to the sequence differences is post-translational modifications to the protein, such as glycosylation within the Golgi apparatus.
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Although the direct reduction of CoQ to CoQH2 is thermodynamically possible, this reaction is not a direct part of the electron transport chain via complexes I, III, and IV. Instead NADH reduces an FMN cofactor in complex I and the reduced FMNH2 kick-starts electron transport in the membrane.
Why is this electron handoff from NADH to FMN, as opposed to direct reduction of CoQ by NADH, a critical component of the electron transport chain?
Answer:
This electron handoff from NADH to FMN, as opposed to direct reduction of CoQ by NADH, a critical component of the electron transport chain is important for Signaling Transduction and Metabolomics
Explanation:
The NADH-CoQ reductase reaction is catalyzed by Complex I. In this course of activity, following events takes place-
a) FNM (NADH dehydrogenase flavoprotein) is reduced by the NADH to FMNH2 through following reactions –
NADH+H++E-FMN↔NAD++E-FMNH2
b) In the next phase coenzyme Q receives electron from FMNH2 through the the iron–sulfur centers of the NADH-CoQ reductase
c) The iron atom undergoes oxidation–reduction cycles to conserve mitochondrial protein as lataxin and hence transport protons from the matrix to the intermembranal space thereby Signaling Transduction and Metabolomics
"Nitrous acid causes all possible transitions (A<-- -->G, C<-- -->T). If a protein has an alanine at position 65, what amino acid(s) would be likely to replace alanine as a result of nitrous acid mutagenesis?a. isoleucine
b. "valine, threonine"
c. threonine
d. "isoleucine, threonine, valine"
e. leucine
Answer:
Due to nitrous acid causes all possible transitions "isoleucine, threonine, valine" is the amino acid that would most likely to replace.
A child's pituitary gland does not release enough hormones. What is the most
likely cause of this?
A. The child has no ovaries.
B. The child has no adrenal hormones.
C. The child's blood glucose level is too high.
D. The child's hypothalamus is not working correctly.
Answer: im not sure but i think its b
Explanation:
A child's pituitary gland does not release enough hormones, the most
likely cause of this - D. The child's hypothalamus is not working correctly.
Hypothalamic dysfunction is a problem with a part of the brain called the hypothalamus. The hypothalamus helps control the pituitary gland and regulates many body processes with help of hormones.
The following changes would take place due if the hypothalamus is not working correctly -
If the hypothalamus is not working correctly which leads to many issues such as blurred vision and weight loss.The hypothalamus dysfunction regulates the pituitary gland that releases many essential hormones such as growth hormones which cause poor intellectual and body growth.homeostasis will also be affected.Thus, The correct choice is - D.
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what are the two reasons for the change in the population of the giraffes?
Answer:
Explanation:
Giraffe numbers plummeted by a staggering 40% in the last three decades, and less than 100,000 remain today. Habitat loss through expanding agriculture, human-wildlife conflict, civil unrest, and poaching for their meat, pelts, and tails, are among the reasons for the decline.
Final answer:
The giraffe population changed primarily due to overproduction of offspring and differential survival and reproduction, where longer-necked giraffes had a survival advantage and passed this trait to their progeny.
Explanation:
The two main reasons for the change in giraffe populations can be attributed to natural selection mechanisms. First is the overproduction of offspring: Giraffes produced more young than the available food sources could support, which led to a struggle for existence where only some could survive. Second is differential survival and reproduction: Giraffes with longer necks could reach food sources higher up in trees, which gave them a survival advantage, leading to greater reproductive success and passing on of the long-neck trait to their offspring. Over time, this caused a shift in the population towards giraffes with ever longer necks, illustrating the principle that chance variations can significantly impact a species' survival if environmental conditions change.
Irene and William are having their first child. Irene knows her blood type is A, but William does not know his blood type. However, William knows that his mother and father were B. Their first child is a boy named Gregory. Gregory has type O blood. Of course, Irene and William do not understand how this happened. You could explain this to them using which of the following choices?
a. B only
b. either B or O
c. O only
d. either AB or
e. A only
Answer:
Option C
So, for them to be able to produce an O type (genotype OO) child (Gregory), Both Irene and William have one copy each of O trait to be able to give birth to Gregory.
Explanation:
If Irene's bloodtype is A, her genotype could be either AO or AA. Since Williams does not know his bloodtype but knows his parents were both B which could be BO or BB. It is safe to assume that Williams could be a BO if is parents were BO and BB for him to produce a child with O type with Irene.
So, for them to be able to produce an O type (genotype OO) child, each has one copy each of O trait to give birth to Gregory.
What is the function of a motor neuron?
O
A. Connects parts of the brain
O
B. Controls muscles
O
C. Connects spinal cord to brain
O
D. Connects other neurons
Answer: Controls Muscles
Explanation:
Apez
Answer:
Controls Muscles
Explanation:
A.P.E.X.
Explain the characteristics scientist use when observing organisms and placing them in the six kingdoms.
Answer:
Mobility- When an organisms is able to physically move from place to place.
Cell Type- Having a nucleus and organelles or Not having them.
Cell Type - Prokaryotic. ...
Cell Type- Eukaryotic. ...
Cell Structure- Cell Wall. ...
Cell Structure- No Cell Walls. ...
Body Type- Unicellular. ...
Body Type- Multicellular.
Explanation:
Answer:
the simple answer
Explanation:
cell type – prokaryotic or eukaryotic
cell structure – cell wall
nutrition – autotrophic or heterotrophic
body type – unicellular or multicellular
n mice, an allele for apricot (a) eyes is recessive to an allele for brown (A) eyes. At an independently assorting locus, an allele for tan (t) coat color is recessive to an allele for black (T) coat color. A mouse that is homozygous for brown eyes and black coat color is crossed with a mouse having apricot eyes and a tan coat. The resulting F1 are intercrossed to produce the F2. What is the probability of an F2 mouse having a black coat and apricot eyes?
Answer:
The probability of an F2 mouse having a black coat and apricot eyes is 3/16
Explanation:
Allele for apricot eyes (aa) is inherited in the recessive condition. Brown eyes can either be AA or Aa.
Allele for tan colour (tt) is inherited in the recessive condition. Black colour can either be TT or Tt.
Parents AATT x aatt
F1 AaTt
AaTt x AaTt
A-T- = 9
A-tt = 3
aaT- = 3
aatt = 1
the probability of an F2 mouse having a black coat and apricot eyes is 3/16
Do you think humans belong in a food chain why or why not ? Help please due at 12
Answer:
I think he is
Explanation:
Because humans get their food from animals and plants therefore they are at the top of food chain and we conceder them as primary consumers.
Which of the following statements about membrane-enclosed organelles is TRUE? Other than the nucleus, most organelles are small and thus, in a typical cell, only about 10% of a cell’s volume is occupied by membrane-enclosed organelles; the other 90% of the cell volume is the cytosol. The nucleus is the only organelle that is surrounded by a double membrane. In a typical cell, the area of the endoplasmic reticulum membrane far exceeds the area of plasma membrane. The nucleus is the only organelle that contains DNA.
Answer:
The correct answer is: "In a typical cell, the area of the endoplasmic reticulum membrane far exceeds the area of plasma membrane".
Explanation:
The endoplasmic reticulum (ER) is a membranous organelle that is in charge of the synthesis and transport of certain molecules. This organelle is composed of a folded lipidic bilayer that branches into interconnected tubules enclosing the lumen. This lumen occupies about 10% of the cell total volume.
More than half of the total membrane of eukaryotic cells is found in the ER. The ER´s membrane size also exceeds the total size of the plasmatic membrane.
The membrane of the endoplasmatic reticulum allows the selection of molecules that need to be transported from the cytoplasm to the organelle´s lumen. It is also a connection channel between the nucleus and the cytoplasm.
Answer:
The third option is the correct answer: In a typical cell, the area of the endoplasmic reticulum membrane far exceeds the area of plasma membrane.
Explanation:
Eucaryotic cells contain intracellular membranes that enclose nearly half the cell's total volume in separate intracellular compartments called organelles.
Membrane-enclosed organelles are those that are bound by a phospholipid bilayer (the membrane), thereby allowing the organelles within the cell to control what goes in or out of it using a semi-permeable membrane.
The main types of membrane-enclosed organelles present in all eucaryotic cells are the endoplasmic reticulum, Golgi apparatus, nucleus, mitochondria, lysosomes, endosomes, and peroxisomes.
The ER encompasses approximately half of the total membrane area of an animal cell, thus, the area of the endoplasmic reticulum membrane far exceeds the area of plasma membrane.
Which growth model would you expect to see in a stable population
Stage 4 of the age structure diagrams is likely to represent a population in decline, as it follows the stages of rapid growth, slow growth, and stable population respectively. Declining populations typically show fewer young individuals and an aging overall population.
Explanation:The age structure diagrams described in stages 1 through 3 indicate different patterns of population growth: stage 1 shows rapid growth, stage 2 shows slow growth, and stage 3 shows a stable population. In stable populations, the logistic growth model is a more realistic representation of population dynamics than exponential growth. This is because the logistic growth model accounts for resource limitations that impact reproductive growth as population size increases.
Considering the provided descriptions, stage 4 in an age structure diagram would typically represent a population that is either declining or contracting. This is inferred from the fact that stable populations have nearly equal numbers across age groups, while declining populations would show fewer younger individuals and potentially a bulging at older age groups, indicating that less offspring are being produced and the overall population is aging.
In Drosophila melanogaster, round eyes (rai+) are dominant to raisin eyes (rai). Round eyes are found in wild-type flies, while raisin eyes are the result of a mutant allele. If a heterozygous parent is crossed with a homozygous recessive parent, then what are the correct genotypic ratios for the F1 progeny?
A. 4:0, round eyes
B. 3:1, raisin eyes:round eyes
C. 1:1, round eyes:raisin eyes
D. 4:0, raisin eyes
Answer:
The correct genotypic ratios for the F1 progeny is 1 round eyes : 1 raisin eyes (Option c)
Explanation:
Available data:
round eyes (rai+) are dominant to raisin eyes (rai)round eyes are found in wild-type flies, raisin eyes are the result of a mutant alleleCross: A heterozygous parent (rai+ rai) is crossed with a homozygous recessive parent (rai rai)
Parental) rai+ rai x rai rai
Gametes) rai+ rai rai rai
Punnet square) rai+ rai
rai rai+ rai rai rai
rai rai+ rai rai rai
F1) Progeny genotype: 2/4= 1/2 rai+ rai, round-eyed individuals
2/4=1/2 rai rai, raisin-eyed individuals
The correct genotypic ratios for the F1 progeny is 1 round eyes : 1 raisin eyes
The correct response to the cross between a heterozygous (rai+/rai) and a homozygous recessive (rai/rai) parent is a 1:1 genotypic ratio in the F1 generation. Therefore, about half the offspring should have round eyes and the other half should show the raisin eyes trait. The correct answer is option C. 1:1, round eyes:raisin eyes.
Explanation:In the scenario you provided, a heterozygous parent for the eye trait (rai+/rai) is crossed with a homozygous recessive parent (rai/rai). In a typical single-factor cross of this type involving one heterozygous and one homozygous recessive parent, the expected genotypic ratio in the F1 generation is 1:1. That means, out of every two offspring, around one should have round eyes (rai+) and one should have raisin eyes (rai).
So, the correct answer is C. 1:1, round eyes:raisin eyes. This illustrates how dominant and recessive traits work in Mendelian genetics to influence the appearance and prevalence of particular traits in offspring.
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In an alternate version of the universe, the earth rotates around its axis at the same speed with which it revolves around the sun (ie. 365 of our days for one rotation/r). Think about what this means for the time period of day and night in "alter-Earth". What would be the approximate value of the period of the rhythm that would evolve in most species in this world?
a. 365 days
b. 182.5 days
c. 730 days
d. There will be no rhythms based on the light cycle
Answer:
The Correct option is A "365 days"
Explanation:
Earth pivots on its hub once every 24 hrs and species have developed to organize their exercises dependent on these day-night cycles showing endogenously rehashing circadian rhythms.
Then again, in an adjust earth, every revolution on its hub takes 365 days. This time-span is same as the time it takes to rotate around the sun (365 days).
The time-frame of every day and night in this adjust earth will be 182.5 days. The estimated estimation of the time of the beat that would develop in many species in this modify earth will be 365 days.
Name the three structures of seed plants, and explain
their functions.
Answer:
The three principal organs of seed plants are roots, stems, and leaves. These organs perform functions such as the transport of nutrients, protection, and coordination of plant activities. Roots: absorb water and dissolved nutrients.
Explanation:
The three main structures of the seed plants are the roots, stem, and leaves. The different structures perform different functions in the plant.
What are seed plants?A seed plant is also called as the spermatophyte, or a phanogam. The spermatophyte is any plant which produces seeds, hence the alternative name for the plant is seed plant. Spermatophytes are a subset of the embryophytes or the land plants.
Three main structures of seed plant are the roots, stems, and the leaves. The roots are responsible for absorbing water and other minerals from the soil. The stem is the structure which provides strength to the plant body, and the leaves are responsible for performing photosynthesis and transpiration of water.
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