Answers
Total number of numerals to be used = 6
We are to find the number of different codes that can be formed and those can be found by permutations.
We have to find the permutations of 10 numerals taken 6 at a time. So we are to find 10P6.
10P6 = 151200
So, 151200 different codes can be formed.
So the answer to this question is option A
Related Questions
hey can you please help me posted picture of question
Answers
D. (-3x+6i)(x+2i)
It is impotant to know that if you want to verify that the option D. (-3x+6i)(x+2i) is the correct answer, you can apply the distributive property to (-3x+6i)(x+2i).
Therefore, when you apply the distributive property, you obtain that the result is:
-3x²-12
Which is correct
Therefore, you can be sure that the correct answer is the option D. (-3x+6i)(x+2i).
Find the surface area of the part of the surface z = x y that lies within the cylinder
Answers
A surface area, r radius, and h height
A=2πr²+2πrh
xy should be like a rectangle so x is r and y is h
A=2πx²+2πxy
Use the word BULLDOG to answer the question. If the letters of this word are written on paper and then cut into squares with one letter per square, what is the probability of selecting a C or a Z?
Answers
A right angle has a league of 13 cm in the hypotenuse of 21 cm what is the length of the other leg
Answers
One leg is 13cm long, hypotenuse is 21cm long. Let the other leg be x cm. So, we can write:
[tex]21^{2} =13^{2} + x^{2} \\ \\ 272= x^{2} \\ \\ x= \sqrt{272} \\ \\ x=16.49 [/tex]
Rounding of to nearest hundredth, the length of other leg of the Triangle is 16.49
Given: a = 13; c = 21
Required: b - other leg
Solution:
c^2 = a^2 + b^2
21^2 = 13^2 + b^2
441 = 169 + b^2
b^2 = 272
√b = 16.49
b = 16.49 cm
Hey can you please help me out posted picture
Answers
Number of people who speak Spanish:
Spanish = 8 + 4 = 12
Number of people who speak Chinese:
Chinese = 5 + 6 = 11
Number of people who speak both languages:
Both = 3 + 2 = 5
Adding we have:
12 + 11 + 5 = 28
Answer:
28
option A
Find the absolute maximum of f(x,y) = e^(-x^2-y^2)(x^2+2y^2) on x^2 + y^2 < 2
Answers
Notice that converting to polar coordinates, setting
[tex]x=r\cos\theta[/tex]
[tex]y=r\sin\theta[/tex]
[tex]\implies r^2=x^2+y^2[/tex]
allows us to consider [tex]f(x,y)[/tex] as a function of one variable; let's call it [tex]F(r)[/tex], where
[tex]f(x,y)\equiv F(r)=re^{-r}[/tex]
Then
[tex]F'(r)=e^{-r}(1-r)=0\implies r=1[/tex]
We have [tex]F'(r)>0[/tex] for [tex]r<1[/tex], and [tex]F'(r)<0[/tex] for [tex]r>1[/tex], which means [tex]F[/tex] is increasing, then decreasing as [tex]r[/tex] exceeds 1. This suggests that extrema occur for [tex]f(x,y)[/tex] wherever [tex]r^2=x^2+y^2=1[/tex], i.e. along the intersection of the cylinder [tex]x^2+y^2=1[/tex] and [tex]f(x,y)[/tex].
Computing the second derivative of [tex]F(r)[/tex] and setting equal to 0 gives
[tex]F''(r)=-e^{-r}(2-r)=0\implies r=2[/tex]
as a possible point of inflection. We have [tex]F''(r)<0[/tex] for [tex]r<2[/tex], and namely when [tex]r=1[/tex], which means [tex]F(r)[/tex] is concave downward around this point. This confirms that [tex]r=1[/tex] is a site of a maximum. Along this path, we have a maximum value of [tex]F(1)=e^{-1}\approx0.368[/tex].
Next, to check for possible extrema along the border, we can parameterize [tex]f(x,y)[/tex] by [tex]x=\sqrt2\cos t[/tex] and [tex]y=\sqrt2\sin t[/tex], so that
[tex]x^2+y^2=(\sqrt2\cos t)^2+(\sqrt2\sin t)^2=2[/tex]
and we can think of [tex]f(x,y)[/tex] as a function a single variable, [tex]F(t)[/tex], where
[tex]F(t)=2e^{-2}\approx0.271[/tex]
In other words, [tex]f(x,y)[/tex] is constant along its boundary [tex]x^2+y^2=2[/tex], and this is smaller than the maximum we found before.
So to recap, the maximum value of [tex]f(x,y)[/tex] is [tex]\dfrac1e\approx0.368[/tex], which is attained along the surface above the circle [tex]x^2+y^2=1[/tex] in the [tex]x-y[/tex] plane.
2.
Find the amount of the annuity.
Amount of Each Deposit: $295
Deposited: Quarterly
Rate per Year: 10%
Number of Years: 6
Type of Annuity: Due
$9,671.28
$9,542.97
$10,076.54
$9,781.54
Answers
where
[tex]FV[/tex] is the future value [tex]P[/tex] is the periodic payment [tex]r[/tex] is the interest rate in decimal form [tex]n[/tex] is the number of times the interest is compounded per year [tex]k[/tex] is the number of payments per year [tex]t[/tex] is the number of years
We know for our problem that [tex]P=295[/tex] and [tex]t=6[/tex]. To convert the interest rate to decimal for, we are going to divide the rate by 100%:
[tex]r= \frac{10}{100} [/tex]
[tex]r=0.1[/tex]
Since the payment is made quarterly, it is made 4 times per year; therefore, [tex]k=4[/tex].
Since the type of the annuity is due, payments are made at the beginning of each period, and we know that we have 4 periods, so [tex]n=4[/tex].
Lets replace those values in our formula:
[tex]FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ][/tex]
[tex]FV=(1+ \frac{0.1}{4} )*295[ \frac{(1+ \frac{0.1}{4} )^{(4)(6)} -1}{ \frac{0.1}{4} } ] [/tex]
[tex]FV=9781.54[/tex]
We can conclude that the amount of the annuity after 10 years is $9,781.54
Write an expression that represents the difference of 32 and N multiplied by 10
Answers
32-n
we multiply it by 10:
10(32-n)
If you want it to be distributed:
320 - 10n
The price C, in dollars per share, of a high-tech stock has fluctuated over a twelve-year period according to the equation C= 14 +12x – x2, where x is in years. The price C, in dollars per share, of a second high-tech stock has shown a steady increase during the same time period according to the relationship C = 2x + 30. For what values are the two stock prices the same?
Answers
C = 14 + 12x - x2
C = 2x + 30
Equating the equations we have:
14 + 12x - x2 = 2x + 30
Rewriting we have:
-x2 + 10x - 16 = 0
Solving the polynomial we have:
x1 = 2
x2 = 8
Answer:
the two stock prices are the same for:
x1 = 2
x2 = 8
The values for which the two stock prices are the same are approximately x ≈ -1.405 and x ≈ 11.405.
Explanation:To find the values for which the two stock prices are the same, we need to set the equations for the prices equal to each other and solve for x.
Equation for the first stock: C = 14 + 12x - x^2
Equation for the second stock: C = 2x + 30
Setting the two equations equal: 14 + 12x - x^2 = 2x + 30
Rearranging the equation and combining like terms: x^2 - 10x - 16 = 0
Using the quadratic formula to solve for x: x = (-b ± sqrt(b^2 - 4ac))/(2a)
Plugging in the values: x = (-(-10) ± sqrt((-10)^2 - 4(1)(-16)))/(2(1))
Simplifying: x = (10 ± sqrt(100 + 64))/2
Calculating: x = (10 ± sqrt(164))/2
Approximate values: x ≈ (10 ± 12.81)/2
Therefore, the two stock prices are the same for x ≈ -1.405 and x ≈ 11.405.
50 POINTS...Which equation would best help solve the following problem? Tania releases a javelin 1.6 meters above the ground with an initial vertical velocity of 25 meters per second. How long will it take the javelin to hit the ground?
Answers
[tex]x''(t)=-9.8[/tex]
Integrating once with respect to [tex]t[/tex], we get
[tex]x'(t)=-9.8t+C_1[/tex]
where [tex]x'(t)[/tex] is the velocity of the javelin. We're told that [tex]x'(0)=25[/tex], so
[tex]25=-9.8\cdot0+C_1\implies C_1=25[/tex]
Integrating again with respect to [tex]x[/tex] to get
[tex]x(t)=-4.9t^2+25t+C_2[/tex]
and we know the javelin was initially thrown 1.6 meters above the ground, or [tex]x(0)=1.6[/tex], so we get
[tex]1.6=-4.9\cdot0^2+25\cdot0+C_2\implies C_2=1.6[/tex]
So the javelin's position at any time [tex]t[/tex] is given by
[tex]x(t)=-4.9t^2+25t+1.6[/tex]
It will hit ground when [tex]x(t)=0[/tex]. Solve this however you want; you'll find that this will happen at about [tex]t=5.165[/tex] seconds after the javelin has been thrown.
Lana is trying to find an equation for a line that passes through (5, 2) and is parallel to 3x + 2y = 15. explain the steps that lana could take to determine the equation.
Answers
3x + 2y = 15
Step 1:
Rewrite given equation:
2y = 15 - 3x
y = 15/2 - (3/2) x
Step 2:
Parallel lines have the same slope:
y = mx + b
m = -3 / 2
y = (- 3/2) x + b
Step 3:
Find b, for this we evaluate the point (5, 2) in the equation:
2 = (- 3/2) (5) + b
2 = (- 15/2) + b
2 + 15/2 = b
19/2
Step 4:
The parallel line is:
y = (- 3/2) x + 19/2
the following shows the correlation between the length of a person's handspan and how many jolly ranchers they can pick up with one hand.
Which of the following does the data suggest?
a. strong positive
b. strong negative
c. no relation
d.weak negative
( please help)
Answers
Answer:
a. strong positive is the answer.
Step-by-step explanation:
The following shows the correlation between the length of a person's hand span and how many jolly ranchers they can pick up with one hand.
There is a strong positive correlation between the two things. We can see the scatter plot moving up as the hand span increases, the number of jolly ranchers they can pick up also increases.
The quantity demanded each month of the walter serkin recording of beethoven's moonlight sonata, manufactured by phonola media, is related to the price per compact disc. the equation p = −0.00054x + 9 (0 ≤ x ≤ 12,000) where p denotes the unit price in dollars and x is the number of discs demanded, relates the demand to the price. the total monthly cost (in dollars) for pressing and packaging x copies of this classical recording is given by c(x) = 600 + 2x − 0.00002x2 (0 ≤ x ≤ 20,000)
Answers
the Profit function is: P(x) = xp(x) - C(x) = -0.00041 x2 + 4x - 600
Attention: don't get confuse by the big P of the profit with the small p of the price To calculate the maximum profit, we need to find the derivative of P(x) then set it to 0 then find x: dP(x)/dx = -0.00082 x + 4 = 0 , so x = 4/0.00082 = 4,878 copies each month.
To find the equilibrium price and quantity, we set the demand to be equal to the supply, solve for x, and substitute the value back into the demand equation to find the equilibrium price.
Explanation:The given equation is:
p = -0.00054x + 9, where p is the unit price in dollars and x is the number of discs demanded.
The total monthly cost for pressing and packaging x copies is given by:
c(x) = 600 + 2x - 0.00002x^2
To find the equilibrium price and quantity, we need to find the point where the demand equals the supply. In this case, the demand is represented by the equation p = -0.00054x + 9 and the supply is represented by the equation c(x) = 600 + 2x - 0.00002x^2.
To solve for the equilibrium price and quantity, we set the demand equals the supply:
-0.00054x + 9 = 600 + 2x - 0.00002x^2
This equation can be solved by rearranging and solving for x:
0.00002x^2 + 2.00054x - 591 = 0
Using the quadratic formula, we can find the values of x that satisfy this equation:
x = (-2.00054 ± sqrt(2.00054^2 - 4*0.00002*(-591))) / (2*0.00002)
After calculating, we find two possible values for x, which are approximately x_1 = 13727.927 and x_2 = -0.036. However, since the quantity demanded cannot be negative, we discard the negative value.
The equilibrium quantity is approximately 13728.
To find the equilibrium price, we substitute the value of x into the demand equation:
p = -0.00054(13728) + 9
p is approximately equal to $1.53.
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If r = -6, s = -2, v = 10, and w = 3; then vs(r - s) ÷ 2 + rw =
Answers
= (10)(-2)[-6 - (-2)] ÷ 2 + (-6)(3)
= -20(-4) ÷ 2 -18
= 80 ÷ 2 - 18
= 40 - 18
= 22
What are the missing pieces to the steps? –27 = 4x2 – 24x –27 = 4(x2 – 6x) –27 + = 4(x2 – 6x + 9) 9 = 4(x – 3)2 = (x – 3)2 ± = x – 3 = x
Answers
Answer:
We can find out the missing pieces by the below explanation,
Here, the given equation,
[tex]-27 = 4x^2 - 24x[/tex]
Step 1 :
[tex]-27=4(x^2-6x)[/tex]
Step 2 :
[tex]-27+36=4(x^2-6x+9)[/tex]
Step 3 :
[tex]9=4(x-3)^2[/tex]
Step 4 :
[tex]\frac{9}{4}=(x-3)^2[/tex]
Step 5 :
[tex]\pm \frac{3}{2}=x-3[/tex]
Step 6 :
[tex]x=3\pm \frac{3}{2}[/tex]
What is the Least common denominator for -3/x -6/8x^2
Answers
The Least Common Denominator is 8x^2 for the fractions as written.
_____
You can reduce the second fraction to -3/(4x^2), which would make the Least Common Denominator be 4x^2.
Question part points submissions used use the gram-schmidt process to find an orthogonal basis for the column space of the matrix. (use the gram-schmidt process found here to calculate your answer. let xi be the ith column of the matrix.) 0 1 1 1 0 1 1 1 0
Answers
What is the sum of the first 35 terms in the series 7 + 9 + 11 + ...?
a.
29
c.
1645
b.
1399
d.
1435
Answers
Hope this helps :)
an = a1 + (n - 1)d
a1 = first number in the series
d = difference between successive number
n = number of terms
a35 = 7 + (35 - 1)2
a35 = 7 + (34)2
a35 = 7 + 68 = 75.
Therefore, the 35th term is 75.
To find the sum of the first 35 numbers, use the formula:
Sn = n(a1 + an) / 2
Sn = 35(7 + 75) / 2
Sn = 2870 / 2 = 1,435.
Therefore, the sum of the first 35th term is 1,435.
The correct answer is D.
Determine the mean ,median,modes ,IQR,and rage for the data 3,8,6,6,4,6,9,9,12
Answers
Add all the numbers:
3 + 8 + 6 + 6 +4 + 6 + 9 + 9 + 12 = 63
There are 9 numbers.
63 / 9 = 7
Mean = 7
Median:
Order all the numbers:
3, 4, 6, 6, 6, 8, 9, 9, 12
The median is 6.
Mode:
The number that appears the most is 6.
The mode is 6.
Inter-Quartile Range :
Median of 2nd part = 9
Median of 1st part = 5
Subtract:
9 - 5 = 4
The IQR is 4.
Range:
The highest number is 12. The lowest is 3
Subtract:
12 - 3 = 9
The range is 9.
Hope this helped☺☺
3+8+6+6+4+6+9+9+12
=63
63/9
=7 is your mean
Median=The middle number in a set of ordered numbers
first place all the numbers from least to greatest
3,4,6,6,6,8,9,9,12
The middle number of this set is 6 so 6 is your median
Mode is the most numbers repeated so if no numbers are repeated there is no mode
6 is repeated 3 times so 6 is your mode
Range: greatest number minus least number
12-3
=9 is your range
IQR=since the median is 6 we would split it and then minus it
so 3,4,6,6,6,8,9,9,12
It would be 9-5
=4is your IQR I am pretty sure that is correct!
^o^
Find the horizontal or oblique asymptote of f(x) = negative 3 x squared plus 7 x plus 1, all over x minus 2
Answers
Finding the horizontal and oblique asymptote of
f(x)= (-3x^2+7x+1)/(x-2)
Solution:
For Horizontal Asymptote:
Line y=L is a horizontal asymptote of the function y=f(x), if either limx→∞f(x)=Llimx→∞f(x)=L or limx→−∞f(x)=Llimx→−∞f(x)=L, and LL is finite.
Calulate limits:
limx→∞(1x−2(−3x2+7x+1))=−∞
limx→−∞(1x−2(−3x2+7x+1))=∞
Thus, there are no horizontal asymptotes.
For Oblique Asymptote:
Do polynomial long division (−3x2+7x+1)/(x-2)=−3x+1+3/(x−2)
The rational term approaches 0 as the variable approaches infinity.
Thus, the slant asymptote is y=−3x+1y=−3x+1.
When 415 junior college students were surveyed, 150 said they have a passport. constructa 95% confidence interval for the proportion of junior college students that have apassport. round to the nearest thousandth?
Answers
The 95% confident interval will be estimated as follows:
sample proportion: 150/415=0.362
ME=1.96*[0.362*0.638/415]=0.0011
thus
95% CI
0.362-0.0011<p<0.362+0.0011
Answer:
[tex]0.362-0.045<p<0.362+0.045[/tex]
Step-by-step explanation:
It is given that When 415 junior college students were surveyed, 150 said they have a passport, then sample proportion will be:
Sample proportion=[tex]\frac{150}{415}=0.362[/tex]
Then, [tex]ME=1.96\sqrt{\frac{0.362{\times}0.638}{415}}[/tex]
=[tex]1.96\sqrt{\frac{0.230}{415}[/tex]
=[tex]1.96(0.023)[/tex]
=[tex]0.045[/tex]
Therefore, at 95% confidence interval, the proportion of junior college students that have a passport is:
[tex]0.362-0.045<p<0.362+0.045[/tex]
Costs for standard veterinary services at a local animal hospital follow a normal distribution with a mean of $88 and a standard deviation of $24. what is the probability that one bill for veterinary services costs between $42 and $133?
Answers
P(42<x<133)
z=(x-μ)/σ
where:
μ-mean
σ-standard deviation
thus
when x=42:
z=(42-88)/24=-1.92
thus
P(x<42)=0.0281
when x=133
x=(133-88)/24=1.875
thus
P(x<133)=0.9699
Thus
P(42<x<133)
=0.9699-0.0281
=0.9418
Answer: 0.9418
There is a 94.25% probability that a bill for veterinary services costs between $42 and $133 in this local animal hospital, based on calculating Z-scores for $42 and $133 and finding the difference between probabilities.
Explanation:The question pertains to the concepts of statistics, specifically the normal distribution which often appear in situations describing natural phenomena and social behavior. To solve this, we need to calculate the Z-scores for both values given and then look those Z-scores up in a standard normal distribution table, or use a calculator or software that can do this.
A Z-score is a statistical measurement that describes a value's relationship to the mean of a group of values. It's measured in terms of standard deviations from the mean.
If X is a random variable from a normal distribution with mean (µ) and standard deviation (σ), the Z-score is calculated by the formula Z = (X - µ)/σ.
For X =$42, Z1 = ($42 - $88)/$24 = -1.92 and for X=$133, Z2=($133-$88)/$24 = 1.88.
The probability that one bill for veterinary services costs between $42 and $133 equals the probability for Z values falling between -1.92 and 1.88. Refer to the standard normal distribution table or a calculator for the corresponding probabilities. The probability for Z1 equals approximately 0.0274, probability for Z2 equals approximately 0.9699. The required probability is then P(Z1
So, "there's a 94.25% chance that a bill for veterinary services costs between $42 and $133 in this local animal hospital".
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4.
Find the present value of the annuity.
Amount Per Payment: $4,725
Payment at End of Each: 6 months
Number of Years: 15
Interest Rate: 10%
Compounded: Semiannually
$72,634.83
$35,938.73
$32,242.03
$68,951.03
Answers
where
[tex]PV[/tex] is the present value
[tex]P[/tex] is the periodic payment
[tex]r[/tex] is the interest rate in decimal form
[tex]n[/tex] is the number of times the interest is compounded per year
[tex]k[/tex] is the number of payments per year
[tex]t[/tex] is the number of years
We know from our problem that [tex]P=4725[/tex] and [tex]t=15[/tex]. To convert the interest rate to decimal form, we are going to divide it by 100%:
[tex]r= \frac{10}{100} [/tex]
[tex]r=0.1[/tex]
Since the interest is compounded semiannually, it is compounded 2 times per year; therefore, [tex]n=2[/tex]. Similarly, since the payment is made at the end of each 6 months, it is made 2 times per year; therefore, [tex]k=2[/tex].
Lest replace the values in our formula:
[tex]PV=P[ \frac{1-(1+ \frac{r}{n})^{-kt} }{ \frac{r}{n} } ][/tex]
[tex]PV=4725[ \frac{1-(1+ \frac{0.1}{2})^{-(2)(15)} }{ \frac{0.1}{2} } ][/tex]
[tex]PV=72634.83[/tex]
We can conclude that the correct answer is $72,634.83
Hugo is a veterinarian. He knows the following information about his 41 patrons: 20 patrons in total do not have a dog. 17 patrons in total have a cat. 7 patrons have neither a dog nor a cat. Can you help Hugo organize the results into a two-way frequency table?
Answers
Answer:
4,17,13,7
Step-by-step explanation:
i got it right :)
To assist Hugo in organizing patron pet ownership into a two-way frequency table, calculations were made to determine the number of patrons with both a dog and a cat, leading to a complete frequency table illustrating pet ownership among 41 patrons.
Explanation:Hugo, the veterinarian, is attempting to organize patron pet ownership information into a two-way frequency table. First, let's establish the total number of patrons which is 41. Since 20 patrons do not have a dog, it implies that 41 - 20 = 21 patrons have a dog. Of the 41 patrons, we know that 17 have a cat. Also, 7 patrons have neither a dog nor a cat. To create the two-way frequency table, we need to figure out how many patrons have both a dog and a cat.
To find the number of patrons with both pets, we add the number of patrons without pets to those with dogs and then subtract from the total number of patrons, which gives us 41 - 20 + 7 = 28. However, since this number includes all dog owners, we need to subtract those who only have dogs and no cats, which gives us 28 - (41 - 17) = 28 - 24 = 4 patrons with both a dog and a cat.
With these calculations, we can now fill out the two-way frequency table:
Patron\PetDogNo DogTotalCat41317No Cat17724Total212041
Note: The sum of the numbers for dog owners and non-dog owners must equal the total number of patrons, and the same applies for cat ownership.
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one more question please help me!!!
Answers
b = (35/10)*6 mm = 21 mm
The ratio in parentheses is the ratio of corresponding sides in the respective rectangles, so is the scale factor. The unknown dimension is that scale factor applied to the corresponding known dimension.
what are the common factors of 24 and 48
Answers
Factors are the numbers that can be multiplied with another number, to equal the product stated. Common factors are the factors that both stated products have.
Factors of 24: 1, 2, 3, 4, 6, 8, 12, and 24.
Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48.
Finding all the shared factors, will give you a final answer of 1, 2, 3, 4, 6, 8, 12, and 24.
I hope this helps!
Determine whether quantities vary directly or inversely and find the constant of variation.
A teacher grades 25 students essays in 4 hours. Assuming he grades at the same speed, how long will it take him to grade 35 essays?
Answers
The time take him to grade 35 essays is, 5.6 hours.
What is Proportional?Any relationship that is always in the same ratio and quantity which vary directly with each other is called the proportional.
Given that;
A teacher grades 25 students essays in 4 hours.
And, To find the time take him to grade 35 essays.
Now, Let us assume that,
Time take him to grade 35 essays is, x
Hence, We get;
25 / 4 = 35 / x
Solve for x;
x = 35 × 4 / 25
x = 5.6 hours
Thus, the time take him to grade 35 essays is, 5.6 hours.
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At the deli Jennifer bought roasted turkey and provolone cheese. The turkey costs $6.35 per pound and the cheese costs $4.75 per pound. In total, she bought 3 pounds and the price was $17.13 How many pounds of each did she buy?
Answers
Let the amounts of Turkey Jennifer bought be [tex] T [/tex] pounds and that of Cheese be [tex] C [/tex] pounds.
From the given information,
[tex] 6.35T+4.75C=17.13\\
T+C=3 [/tex]
Solving the above two equations together,
[tex] 6.35T+4.75(3-T)=17.13\\
(6.35-4.75)T+4.75*3=17.13\\
1.6T=2.88\\
T=\frac{2.88}{1.6}\\
T=1.8
[/tex]
Thus, Jennifer bought [tex] 1.8\;pounds [/tex] of Turkey and [tex] 3-1.8=1.2\;pounds [/tex] of Cheese.
Hey can you please help me out posted picture
Answers
For each language we have:
Number of people who speak Spanish:
Spanish = 8 + 4 = 12
Number of people who speak Chinese:
Chinese = 5 + 6 = 11
Number of people who speak both languages:
Both = 3 + 2 = 5
Adding we have:
12 + 11 + 5 = 28
Answer:
28
option A
Number of employees who speak only Chinese = 6
Number of employees who speak Spanish and Russian = 4
Number of employees who speak Spanish and Chinese = 3
Number of employees who speak all three languages = 2
Number of employees who speak Chinese and Russian = 5
The number of employees who speak Spanish or Chinese or both will be the sum of all above values. The sum is = 28
Thus the correct answer is option A
If rain is falling at a rate of ¼ inch per hour, how much rain would you expect after 6 hours
Answers
6 hours = 1/4 x 6 = 6/4 = 1 1/2 inches
Answer: 1 1/2 inches