Answers
Answer 1
11. Ionic compounds that dissolve in water conduct electricity because they break into ions that move freely.
12. Solid metals are good conductors of heat and electricity.
13. Molecular compounds that dissolve in water do not conduct electricity because no charged particles are present.
14. Because the electrons in a molecule of hydrogen fluoride (HF) are more strongly pulled toward the fluorine atom, the molecule is polar.
15. A metal crystal consists of positively charged metal ions embedded in a "sea" of freely moving valence electrons.
16. The properties of solid metals can be explained by the structure of and the bonding among the metal atoms. = True
17. Orderly crystal shapes, high melting points, and electrical conductivity, when dissolved in water, are properties of ionic compounds. = True
18. When electrons are transferred between two atoms, a covalent bond is formed. = False (When electrons are shared between two atoms, a covalent bond is formed.)
19. A low melting point is one property of molecular compounds. = True
20. A nonpolar bond is formed when two atoms share electrons unequally. = False (a polar bond is formed)
12. Solid metals are good conductors of heat and electricity.
13. Molecular compounds that dissolve in water do not conduct electricity because no charged particles are present.
14. Because the electrons in a molecule of hydrogen fluoride (HF) are more strongly pulled toward the fluorine atom, the molecule is polar.
15. A metal crystal consists of positively charged metal ions embedded in a "sea" of freely moving valence electrons.
16. The properties of solid metals can be explained by the structure of and the bonding among the metal atoms. = True
17. Orderly crystal shapes, high melting points, and electrical conductivity, when dissolved in water, are properties of ionic compounds. = True
18. When electrons are transferred between two atoms, a covalent bond is formed. = False (When electrons are shared between two atoms, a covalent bond is formed.)
19. A low melting point is one property of molecular compounds. = True
20. A nonpolar bond is formed when two atoms share electrons unequally. = False (a polar bond is formed)
Related Questions
1. Aqueous solutions of chromium(III) iodide and sodium hydroxide react to give a chromium(III) hydroxide precipitate and aqueous sodium iodide.
2. Aqueous solutions of iron(II) sulfate and barium nitrate react to give a barium sulfate precipitate and aqueous iron(II) nitrate.
Express your answer as a chemical equation. Identify all of the phases in your answer. Enter noreaction if there is no reaction.
Answers
1- The original equation of the reaction is :
CrI3 + NaOH → Cr(OH)3 + NaI
but this is not a balanced equation so we have to balance it :
-first, we have 3 I atoms on the left side and 1 I atom on the right side
so to makes the no.of atoms on both sides equal we put 3NaI instead of NaI
CrI3 + NaOH → Cr(OH)3 + 3NaI
- then no.of Na atoms on the left side is 1 and on the right side is 3 so, we put 3NaOH instead of NaOH
CrI3 + 3NaOH → Cr(OH)3 + 3NaI
now we have :
Cr atoms = 1 on both sides
I atoms = 3 on both sides
Na atoms = 3 on both sides
O&H atoms = 3 on both sides
So the final balanced equation of our reaction is:
CrI3(aq) + 3NaOH(aq) → Cr(OH)3(s) + 3NaI(aq)
2 - the chemical equation of the second reaction is :
FeSO4 + Ba(NO3)2 → BaSO4 + Fe(NO3)2
let's see if it is the balanced equation or not?
we have:
no of Fe atom on both sides = 1
no of (SO4) atom on both sides are equal
no of Ba atom on both sides = 1
no of (NO3) group on both sides= 2
so this is our balanced equation, so the final equation for this reaction is:
FeSO4(aq) + Ba(NO3)2(aq) →BaSO4(s) + Fe(NO3)2(aq)
CrI3 + NaOH → Cr(OH)3 + NaI
but this is not a balanced equation so we have to balance it :
-first, we have 3 I atoms on the left side and 1 I atom on the right side
so to makes the no.of atoms on both sides equal we put 3NaI instead of NaI
CrI3 + NaOH → Cr(OH)3 + 3NaI
- then no.of Na atoms on the left side is 1 and on the right side is 3 so, we put 3NaOH instead of NaOH
CrI3 + 3NaOH → Cr(OH)3 + 3NaI
now we have :
Cr atoms = 1 on both sides
I atoms = 3 on both sides
Na atoms = 3 on both sides
O&H atoms = 3 on both sides
So the final balanced equation of our reaction is:
CrI3(aq) + 3NaOH(aq) → Cr(OH)3(s) + 3NaI(aq)
2 - the chemical equation of the second reaction is :
FeSO4 + Ba(NO3)2 → BaSO4 + Fe(NO3)2
let's see if it is the balanced equation or not?
we have:
no of Fe atom on both sides = 1
no of (SO4) atom on both sides are equal
no of Ba atom on both sides = 1
no of (NO3) group on both sides= 2
so this is our balanced equation, so the final equation for this reaction is:
FeSO4(aq) + Ba(NO3)2(aq) →BaSO4(s) + Fe(NO3)2(aq)
Final answer:
For reaction 1, the balanced equation is CrI3(aq) + 3NaOH(aq) → Cr(OH)3(s) + 3NaI(aq). For reaction 2, it is FeSO4(aq) + Ba(NO3)2(aq) → BaSO4(s) + Fe(NO3)2(aq). The products Cr(OH)3(s) and BaSO4(s) form precipitates in their reactions.
Explanation:Based on your questions, we can establish the following balanced chemical equations:
The synthesis of chromium(III) hydroxide from chromium(III) iodide and sodium hydroxide:CrI3(aq) + 3NaOH(aq) → Cr(OH)3(s) + 3NaI(aq).The synthesis of barium sulfate from iron(II) sulfate and barium nitrate:FeSO4(aq) + Ba(NO3)2(aq) → BaSO4(s) + Fe(NO3)2(aq).This shows the precipitation reactions that can occur between certain metallic ions in solution. The precipitates are the insoluble products - chromium(III) hydroxide and barium sulfate, respectively.
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