HELP IF YOU'RE GOOD AT GEOMETRY AND I WILL MARK BRAINLIEST AND DO NOT ANSWER FOR FREE POINTS OR I WILL REPORT YOU
△ABC∼△DEF , △ABC has a height of 6 meters, and △DEF has a height of 10 meters.

What is the ratio of the area of △ABC to the area of △DEF ?

Enter your answer, in simplest form, in the boxes.


:

Answers

Answer 1
height of ABC = h = 6m
height of DEF = H = 10m
Since they are similar, their bases must be in the same proportion: base of ABC = b = 6/10B = 3/5B
Since a = 1/2 bh = 1/2 (3/5B)(6) = 9/5B
A = 1/2 BH = 1/2 (B)(10) = 5B
So ratio of a:A = 9/5B:5B = 9/5:25/5 = 9:25
Answer 2

Final answer:

The ratio of the areas of two similar triangles with heights of 6 and 10 meters is 9/25.

Explanation:

To find the ratio of the areas of two similar triangles, △ABC and △DEF, with heights 6 meters and 10 meters respectively, we use the knowledge that the areas of similar triangles are proportional to the squares of the corresponding linear dimensions, such as their heights. For these triangles, the ratio of their heights is 6/10 or 3/5. Thus, the ratio of their areas is (3/5)2 or 9/25.


Related Questions

Rosen 15 how many solutions are there to the equation x1 x2 x3 x4 x5

Answers

The number of answers always corresponds to the highest number of exponents.

Therefore, if x⁵ is the highest exponent, then there are 5 possible answers.

However, it is important to note that not all of these have real answers for each one. In some cases, an x⁵ equation will have a number of real answers and a number of imaginary answers. Nevertheless, they will always add to 5. 

Simone is buying 10 bracelets for her friends. Each bracelet costs $8. Simone is also buying a necklace for her mother for $18. She believes that her total will be $98. Which expression could be used to estimate the reasonableness of Simone’s total? 8 × $8 + $10 8 × $8 + $18 10 × $8 + $20 10 × $10 + $10

Answers

C. 10 x $8 + $20 
that is $100 so I'm assuming the extra $2 is because of taxes
(8 x 10)+18
=98  which mean simone is right

Eighty percent of the dogs have completed obedience classes. How many of the dogs have completed obedience classes? Five dogs of different breeds 4 dogs 3 dogs 2 dogs 1 dog

Answers

let
x--------> number of dogs that completed the obedience class

we know that
total number of dogs=5
Eighty percent of the dogs have completed obedience classes
so
x=0.80*5------> x=4

the answer is
4 dogs have completed obedience classes
Answer:
4 dogs have completed the obedience classes

Explanation:
We are given that 80% of the dogs completed the obedience classes and that the total number of dogs who attended the class was 5

This means that 80% of the 5 dogs have completed the class

Therefore:
number of dogs that completed the class = 80% * 5
= 0.8 * 5
= 4 dogs

Hope this helps :)

A. 11 cm^3
B. 14 cm^3
C. 15 cm^3
D. 25 cm^3

Answers

Lets get started :)

We need to find the radius of the larger cylinder

V = [tex] \pi [/tex]r²h
960 = [tex] \pi [/tex]r²(16)
[tex] \frac{960}{16} = \pi r^2[/tex]
60 = [tex] \pi r^2[/tex]
[tex] \frac{60}{ \pi } = r^2 [/tex]
r = [tex] \sqrt{ \frac{60}{ \pi } } [/tex]
r ≈ 4.27 cm

The ratio of the bigger cylinder to smaller is:
16 : 4

Therefore, the big cylinder is 4 times bigger than the small cylinder

[tex] \frac{4.37}{4} [/tex] = r
r = 1.09 cm (radius of small cyclinder)

V (small cylinder) = [tex] \pi [/tex](1.09)²(4)
                             = 15 cm³

Your answer will be C. 15 cm³

the volume of a cylinder= height * base area
while the base area = [tex] \pi r^{2}[/tex]
since the two cylinders are similar then the ratio between the two radii= the ratio between the two heights =16/4 =4
then the volume of the large cylinder with respect to the smaller dimensions= [tex] \pi * (4r)^{2} *(4*4)=(\pi r^{2} *4)*4*16[/tex]
but [tex] the volume of the smaller one = \pi r^{2} *4[/tex]
then the volume of the large cylinder = the volume of the smaller cylinder*4*16=960
then the smaller's volume= [tex] \frac{960}{4*16}=15[/tex]


1. A sine function has the following key features:
Frequency = 16π
Amplitude = 2
Midline: y = 3
y-intercept: (0, 3)
The function is not a reflection of its parent function over the x-axis.
Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

2. A sine function has the following key features:
Period = 12
Amplitude = 4
Midline: y = 1
y-intercept: (0, 1)
The function is not a reflection of its parent function over the x-axis.
Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

3. A sine function has the following key features:
Period = 4π
Amplitude = 2
Midline: y = 3
y-intercept: (0, 3)
The function is a reflection of its parent function over the x-axis.
Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

4. picture

5. picture

Answers

Problem 1

See the attached image (figure 1)

16pi seems like a typo. I'm going to assume that it's a fraction and it is 1/(6pi)
f = 1/(6pi) = frequency
T = 1/f = 1/(1/(6pi)) = 6pi
Amplitude = 2
a = 2
b = 2pi/T = 2pi/(6pi) = 1/3
Midline: y = 3
d = 3

The function is
y = a*sin(bx-c)+d
y = 2*sin(1/3*x-0)+3
y = 2*sin(x/3)+3

===============================================

Problem 2

See the attached image (figure 2) 

T = 12 is the period
a = 4 is the amplitude
b = 2pi/T = 2pi/12 = pi/6
y = 1 is the midline so d = 1
The y intercept is (0,1) which is the midline, which indicates no phase shifts have occurred so c = 0

The function is
y = a*sin(bx-c)+d
y = 4*sin((pi/6)x-0)+1
y = 4*sin((pi/6)x)+1

===============================================

Problem 3

See the attached image (figure 3)

Period = 4pi
T = 4pi
b = 2pi/T = 2pi/(4pi) = 1/2 = 0.5
Amplitude = 2
a = 2
Midline: y = 3
d = 3
y-intercept: (0,3)
The function is a reflection of its parent function over the x-axis, so 'a' is negative meaning a = -2 instead of a = 2

The function is
y = a*sin(bx-c)+d
y = -2*sin(0.5x-0)+3
y = -2*sin(0.5x)+3

===============================================

Problem 4

See the attached image (figure 4)

a = 10 which is half of the distance between the highest and lowest points
T = 8 is the period
b = 2pi/T = 2pi/8 = pi/4
c = -pi/2 is the phase shift since its really a cosine graph
d = 0 is the midline

The function is
y = a*sin(bx-c)+d
y = 10*sin((pi/4)*x+(-pi/2))+0
y = 10*sin((pi/4)*x+pi/2)

===============================================

Problem 5

See the attached image (figure 5)

a = 2 is the amplitude since it bobs up and down this distance from the midline
T = 8 seconds is the period (double that of the time it takes for it to go from the highest to the lowest point)
b = 2pi/T = 2pi/8 = pi/4
c = 0 is the phase shift as the buoy starts at normal depth of 20 meters
d = 20 is the midline

The function is
y = a*sin(bx-c)+d
y = 2*sin((pi/4)x-0)+20
y = 2*sin((pi/4)x)+20

===============================================

Answer:

1. Picture Below

2.  Ordered Pair : (0,1) (3,5) (6,1) - Function: f(x)=4sin(pi/6x)+1

3. Ordered Pair : (0,3) (3.14,5) (6.27,3) - Function: f(x)= 2sin(1/2x)+3

4.  I have no idea.

5. Plot the first point at (0, 20) and the second point at (2, 22)

Step-by-step explanation:

The height of a tree was 4.8m .After one year the height of the tree was increased by 12.5%.find its new height

Answers

The new height of the tree after it has increased by 12.5% is 5.4 meters

To find the new height of the tree after it has increased by 12.5%, we start by calculating the increase in height using the following equation

Increase = 12.5% of the original height

The original height is given as 4.8m. So, the formula can be expressed as follows

Increase = 12.5% * 4.8

Increase = 0.125 * 4.8

Increase = 0.6 meters

Add the increase to the original height

New height = Original height + Increase

The above equation can then be expressed as follows

New height = 4.8 + 0.6

New height = 5.4 meters

The owners want to hire a contractor to build a porch along side the parlor. The parlor is rectangular with width Of 32 feet and length of 50 feet. The porch will have the same width that on each side of the house. See design plans.

Answers

Hello there!

a) Basically, you are adding the length of porch to the original length of the parlor.
Let's say that the newly added porch is x.

(50 + x)(32 + x)
1600 + 50x + 32x + x²
x² + 82x + 1600

b) Just make the polynomial x² + 82x + 1600 equal to 2320.
x² + 82x + 1600 = 2320

subtract 2320 on both sides to make the polynomial equal to 0.
x² + 82x - 720 = 0

factor this
(x - 8)(x + 90) = 0
(x - 8) =0       (x + 90) = 0
       x = 8                 x = - 90
                            (-90ft doesn't make sense. So don't mind about this.)

So the porch should be 8ft.


Hope this helped!


Final answer:

The width of the porch will be 32 feet, the same as the parlor. However, to calculate the amount of building materials needed, additional specifics are required such as the porch's length, location of posts, and number of boards.

Explanation:

To answer the question related to designing a porch that matches the width of the parlor, we first understand that the parlor is of a rectangular shape with a width of 32 feet. Considering that the porch will have the same width, it means the porch will also have a width of 32 feet.

From this point, specifics such as the desired length of the porch, location of posts, number of boards or rails, and other related factors would come into play in the calculating of building materials needed for the construction. There may also be the need to consider factors like the ratio of width to length in the design, akin to the mathematical relation mentioned in the statement 'X = Y x 2 + 1'.

So, while we know the width of the porch because it matches the parlor, the exact amount of materials that will be required would depend on further specifics of the porch design, similar to the steps in a stoichiometry problem in chemistry where one calculates the amount of reactants or products in a chemical reaction based on known ratios.

Learn more about Porch Construction here:

https://brainly.com/question/31213522

#SPJ2

You are standing 40 feet away from a building that is 115 feet tall. What is the angle from the ground to the top of the building to the nearest degree?

Answers

whats the answer? i got 0.348??

A knife is 3 times the cost of the spoon 9 spoons and 12 knives costs £82.80 work out the cost of 1 knife

Answers

5.52

Hope this helped!

The cost of spoon is £1.84 and therefore the cost of one knife is £5.52.

Given :

A knife is 3 times the cost of the spoon.9 spoons and 12 knives costs £82.80.

Solution :

This question is solve by creating a linear equation and linear equations are nothing but yet another subset of "equations". Linear calculations that requires more than one variable can be done with the help of linear equations.The standard form of a linear equation in one variable is ax + b = 0.

Now let x be the cost of spoon. Than the cost knife is 3x. It is given that 9 spoons and 12 knives costs £82.80.

[tex]9x + 12\times(3x)= 82.80[/tex]

[tex]9x + 36x = 82.80[/tex]

[tex]45x =82.80[/tex]

[tex]x = 1.84[/tex]

Therefore the cost of 1 knife = [tex]1.84\times 3 = 5.52[/tex].

For more information, refer the link given below

https://brainly.com/question/2263981

How do I solve #21???? Please don't just give me the answer.... tell me how u got it... thanks!

Answers

Since X and Y are on the same vertical line, the distance between them is the difference of their y-coordinates: 6 - 3 = 3.

Since Y and Z are on the same horizontal line, the distance between them is the difference of their x-coordinates: 6 - 1 = 5.

The segment XZ is the hypotenuse of a right triangle with sides 3 and 5, so its length is
.. XZ = √(3^2 +5^2) = √34

XY = 3
YZ = 5
XZ = √34 ≈ 5.83095

Y= v^2/2a solve for v

Answers

Solve for v:
Y = (a v^2)/2

Y = (a v^2)/2 is equivalent to (a v^2)/2 = Y:
(a v^2)/2 = Y

Divide both sides by a/2:
v^2 = (2 Y)/a

Take the square root of both sides:

Answer:  v = sqrt(2) sqrt(Y/a) or v = -sqrt(2) sqrt(Y/a)

Final answer:

To solve for v in the equation y = v²/2a, multiply both sides by 2a and then take the square root of both sides which gives v = √(2ay).

Explanation:

The question requires us to solve the equation y = v²/2a for the velocity v. To isolate v, we multiply both sides of the equation by 2a, then take the square root of both sides.

Multiply both sides of the equation by 2a: 2ay = v²Take the square root of both sides to solve for v: v = √(2ay)

This mathematical process makes v the subject of the equation based on the given formula from kinematics. It's important to note that v will have two values, one positive and one negative, since taking the square root of a number yields both a positive and negative result.

PLEASE HELP ASAP!! WILL GIVE BRAINLIEST

Answers

I believe that it is D, so sorry if it's wrong, I haven't done this in a while.
i think  you should have studied because it's real easy 


And it's obvious  that it's d  

If the public debt of the United States in 2002 was $6,228,235,965,597.16 and the budget deficit in 2003 was $554,995,097,146.46, what was the public debt in 2003?

A. $11,778,186,937,061.76
B. $5,673,240,868,450.70
C. $5,549,950,971,464.60
D. $6,783,231,062,743.62

Answers

the answer is D
i am taking the test as well

Based on the public debt in 2002 and the budget deficit incurred in 2003, the public debt in 2003 was D. $6,783,231,062,743.62.

The budget deficit refers to the amount that the government had to borrow in order to fund the budget of the country.

To find the public debt in 2003 therefore, you need to add the debt of the previous year to the deficit of the current year.

= 2002 Public debt + Budget deficit

= 6,228,235,965,597.16 + 554,995,097,146.46

= $6,783,231,062,743.62

In conclusion, the public debt in 2003 was $6,783,231,062,743.62.

Find out more at https://brainly.com/question/3638352.

What is the measure of
A. Cannot be determined
B. 74
C. 16
D. 32

Answers

The answer would be D. 32

Why? The triangle in the problem is an isosceles triangle. That means the two legs of the triangle are equal and the angle opposite to the equal legs are also equal. 

Therefore, angle C is also 74°. 

The sum of the interior angles of a triangle is equal to 180°.
Thus, 
      180° = ∡A + ∡B + ∡C
      180° = 74° + ∡B + 74°
      180° = 148° + ∡B
        ∡B = 180° - 148°
        ∡B = 32°

Three brothers have ages that are consecutive even integers. the product of the first and third boys' ages is 20 more than wice the second boy's age. find the age of each of the three boys.

Answers

Let the first brother = x 
second brother = x + 2
third brother = x + 4

The product of the first and third boys' ages is 20 more than twice the second boy's age:

x(x+4) = 2(x+2) + 20
x² + 4x = 2x + 4 + 20
x² + 4x - 2x - 24 = 0
x² + 2x - 24 = 0
(x - 4)(x + 6) = 0
x = 4 or -6 (rejected, age cannot be negative)

First brother = 4
Second brother = 4 + 2 = 6
Third brother = 4 + 4 = 8

The three boys are 4, 6, and 8 years old. 

Three brothers have ages that are consecutive even integers. The product of the first and third boys' ages is 20 more than twice the second boy's age. Find the age of each of the three boys.
Let x be the age of the first boy, snce they are consecutive even integers, they will be 2 way from each other.
1st boy= x
2nd boy= x+2
3rd boy = x+4
"product means the answer to a multiplication problem;
x(x+4)=20+2(x+2)
x%5E2+4x=20+2x+4
x%5E2+4x-2x=20+4
x%5E2+2x=24
x%5E2+2x-24=0


(x+6)(x-4)=0
x+6=0
x=-6
x-4=0
x=4
SInce we know they are even integers, the answerhas to be;
x=4
so the first boys age = 4
2nd boy= 4+2=6
3rd boy= 4+4=8

Hope this helps you

The table shows different geologic time periods: Period Number of Years Ago Jurassic 2.08 ⋅ 108 Silurian 4.38 ⋅ 108 Tertiary 6.64 ⋅ 107 Triassic 2.45 ⋅ 108

Order the time periods from oldest to youngest. (4 points)

1. Tertiary, Jurassic, Triassic, Silurian
2.Jurassic, Triassic, Silurian, Tertiary
3.Silurian, Triassic, Jurassic, Tertiary
4.Triassic, Silurian, Jurassic, Tertiary

Answers

I think it is C, or #3 Hope this helps pls mark brainliest if correct

Select all of the potential solution(s) of the equation 2log5x=log54.

Answers

x= -2 and x= 2 are the answers

Given :[tex] 2log_{5} x^{2} =log_{5} 2^{2} [/tex]

To solve for x we use the logarithm rule for powers.

The log rule for powers states:

[tex] mlog_{a}n =log_{a} n^{m} [/tex]

We apply this rule to the left side of the equation.

[tex] log_{5} x^{2} =log_{5} 4

Both sides have log with same base so it can be eliminated.

Eliminating log from both sides we have:

[tex] x^{2} =4

To solve for x we take root of both sides

x=2,-2.

if 7(t-4)-2t=4(t-3), what is the value of t?

Answers

7(t-4)-2t=4(t-3)
multiply 7 and 4 by all in parentheses
(7*t) + (7*-4) - 2t= (4*t) + (4*-3)
7t -28 - 2t= 4t - 12
combine like factors
5t - 28= 4t - 12
add 28 to both sides
5t= 4t + 16
subtract 4t from both sides
t= 16

CHECK:
7(t-4)-2t=4(t-3)
7(16-4) - 2(16)= 4(16-3)
7(12) - 32= 4(13)
84 - 32= 52
52= 52

ANSWER: t= 16

Hope this helps! :)
7 (t-4)-2t= 4 (t-3)= t = 16

Find the average rate of change of the function over the given interval. f(x) = 3x − 2; [0, 5]

Answers

To find the avarage rate of change, we first need to find our y-coordinates.
This brings us to our first step: filling in the x-coordinates (of the domain) in the formula.

f(0) = 3*0 - 2 = -2
f(5) = 3*5 - 2 = 15- 2 = 13

We now have found the following coordinates
(0,-2) and (5,13).

To find the avarage rate of change we need to use the following formula:
rate of change = Δy / Δx
With Δ representing the change of coordinates. Filling in this formula, gives us:
rate of change = [tex] \frac{13 - -2}{5 - 0} = \frac{15}{5} = 3 [/tex]

So our answer: the average rate of change on the interval (domain) [0,5] is 3.

Final answer:

The average rate of change of the function over the given interval is 3.

Explanation:

To find the average rate of change of the function over the given interval, we need to calculate the change in the function values and divide it by the change in the input values.

Step 1: Calculate the function values for the two endpoints of the interval.

f(0) = 3(0) - 2 = -2

f(5) = 3(5) - 2 = 13

Step 2: Calculate the change in the function values.

Change in function values = f(5) - f(0) = 13 - (-2) = 15

Step 3: Calculate the change in the input values.

Change in input values = 5 - 0 = 5

Step 4: Divide the change in function values by the change in input values.

Average rate of change = (Change in function values) / (Change in input values) = 15 / 5 = 3

The measure of angle x is 25 more than 4 times the measure of its complement. find the measure of x. x= degrees

Answers

x = 25 +4*(90 -x) . . . . . x is 25 more than 4 times its complement
x = 385 -4x . . . . . . . . . eliminate parentheses
5x = 385 . . . . . . . . . . . .add 4x
x = 77 . . . . . . . . . . . . . . divide by 5

The measue of angle x is 77°.

.please help me thank you you will be given brainley

Answers

The answer is FT.

Hope this helps!

o valor da expressão a=1,67 . 10 + 3,95 . 10

Answers

a = 1.67. 10 + 3.95. 10
 First we rewrite the expression:
 a = (1.67 * 10) + (3.95 * 10)
 We multiply each member of the parenthesis by 10:
 a = 16.7 + 39.5
 We add both values:
 a = 56.2
 Answer:
 
We note that the value of the expression for a is:
 
a = 56.2

Find the measure of “rst”

Answers

its over 90 degrees but i cannot tell you the exact measurement

Answer: it is 110 bcs each section in 10° and there are 11 sections

What is the domain of the given function? {(3, –2), (6, 1), (–1, 4), (5, 9), (–4, 0)}




{x | x = –4, –1, 3, 5, 6} {y | y = –2, 0, 1, 4, 9} {x | x = –4, –2, –1, 0, 1, 3, 4, 5, 6, 9} {y | y = –4, –2, –1, 0, 1, 3, 4, 5, 6, 9}

Answers

the domain is all the x values that makes the graph work so its -4,-1,3,5,6
What is the domain of the given function?
{(3, –2), (6, 1), (–1, 4), (5, 9), (–4, 0)}
The domain is formed by the values of x, the first value of the ordered pairs (x,y), in this case 3, 6, -1, 5, and -4. Ordering the values:
Domain of the function={x | x = –4, –1, 3, 5, 6}
Answer: First option {x | x = –4, –1, 3, 5, 6}

The volumes of two similar solids are 53cm³ and 1113cm³. Which is the ratio of the corresponding sides?
A. 7
B. 21
C. √21
D. ³√21

Answers

Cube Root 1113 = 10.36
Cube Root 53 = 3.76

The ratio is 10.36/3.76 = 2.76
Cube Root (21) = 2.76 to 3 places. 

D <<<<<<<answer.

There is another way to do this (much better I think).
1113/53 = 21

A solid has 3 dimensions. Each dimension of the big solid will be k times bigger than the little one.

Therefore the volumes are related by a factor of cube root(large one ) to small one = cube root (21)

Which of the following is equal to (2x/3 - 7) + 7

A. (2x - 7) + 21

B. 2x - 21/3

C. 3x/2

D. 2x/3

@texaschic101

Answers

Which of the following is equal to: (2x/3 - 7) + 7
The order of the mathematical operations is PEMDAS.
Therefor the first step you will take is to solve the operation inside the parenthesis.
(2x/3 - 7) =(2x/3 - 7)* 3/3 = 2x/3 - 21/3 = (2x - 21)/3
While adding or subtracting fractions, dont forget to check that each term have the same denominator.

Then the operation outside the parenthesis,

(2x - 21)/3 + 7 = (2x-21)/3 + 7 * 3/3 = (2x - 21)/3 + 21/3 =

(2x - 21 + 21) / 3 = 2x/3

The final answer is D. 2x/3

The correct answer is D. The number 7 is subtracted from the first term, 2x/3, but then an equal sum is added, and the two effectively cancel each other out. This means that the value of the first expression is essentially 2x/3, which is option D.

I need help ASAP. I don't understand how to solve this



3. Your fixed expenses are $1,500.45/month. Your emergency fund has 4 month’s worth of coverage. You invest half in a savings account with an interest rate of 3.15% APR and the other half in a 45­ day CD with an interest rate of 4.65% APR. How much is your total interest in 45 days?

4. If you had invested only 1 month’s worth of the emergency fund in the saving account at a 3.15% APR and the remainder in the 45­ day CD at a 4.65% APR, what is the difference in the interest earned in 45 days when compared with question #3?

Answers

There are several ways to work these. The most straightforward is to simply slog through the numbers.

3. Your emergency fund is 4 times your expenses so is
.. emergency fund = 4*(1500.45) = 6001.80
Half that amount is 3000.90.
The interest earned at 3.15% for 45 days on 3000.90 is
.. I = Prt = 3000.90*.0315*(45/365) = 11.65

The interest earned at 4.65% for 45 days on 3000.90 is
.. I = Prt = 3000.90*.0465*(45/365) = 17.20

Your total interest in 45 days is $11.65 +17.20 = $28.85


4. The calculation is the same, only the amounts are different.
The interest earned at 3.15% for 45 days on 1500.45 is
.. I = Prt = 1500.45*.0315*(45/365) = 5.83
The interest earned at 4.65% for 45 days on 4501.35 is
.. I = Prt = 4501.35*.0465*(45/365) = 25.81
The total interest earned in this scenario is $5.83 +25.81 = $31.64

This is $31.64 -28.85 = $2.79 more than the interest earned in question 3.


_____
You could work this using weighted average interest rates.
3. The rate earned is (3.15 +4.65)/2 = 3.90% for 45 days, or 0.480822% of the 6001.80 balance, about $28.86

4. The rate earned is (3.15 +3*4.65)/4 = 4.275% for 45 days, or 0.527055% of the balance. The difference is 0.046233% of the balance, or $2.77.

Note the pennies difference from the numbers above. The differences are due to the way the numbers round off when there are two accounts. The numbers above would better match what you would see at your bank.

The total interest earned in 45 days when the emergency fund is evenly split between a savings account and a CD is approximately $29.17. If 1 month's worth of emergency funds were in the savings account and the rest in a CD, the total interest would be approximately $38.05. The difference between the two scenarios is approximately $8.88.

Calculating Interest for Emergency Funds in Savings and CDs

To answer the student's question about the interest earned in 45 days on the emergency fund invested half in a savings account and half in a 45-day CD, as well as the comparison with an alternative investment scenario, we need to perform several calculations using the given interest rates and time periods.

Answer to Question 3

Firstly, the student's fixed expenses are $1,500.45/month, so for a 4-month emergency fund coverage, the total amount saved would be $1,500.45 x 4 = $6,001.80.

Half of this amount goes into the savings account and the other half into the CD, so each gets $3,000.90.

The interest in the savings account with an APR of 3.15% for 45 days (1.5 months) would be calculated using the formula for simple interest: Interest = Principal x Rate x Time.

So the interest earned on the savings account would be: $3,000.90 x (3.15% per year / 12 months) x 1.5 months ≈ $11.85.

The interest in the 45-day CD with an APR of 4.65% would be calculated similarly: $3,000.90 x (4.65% per year / 12 months) x 1.5 months ≈ $17.32.

Therefore, the total interest earned in 45 days would be approximately $11.85 + $17.32 = $29.17.

Answer to Question 4

If only 1 month's worth of emergency fund ($1,500.45) was invested in the savings account and the remainder in the CD, the interest from the savings account would not change, but the interest from the CD would, as it would be calculated on a larger principal of $4,501.35.

The new interest for the CD investment would be $4,501.35 x (4.65% per year / 12 months) x 1.5 months ≈ $26.20.

So the new total interest would be $11.85 (from savings) + $26.20 (from CD) = $38.05.

The difference in interest between the two scenarios would be $38.05 - $29.17 = $8.88.

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Answers

8 < 2b OR 2b + 15 < 5

8 < 2b
2b > 8
b > 8 ÷ 2
b > 4

2b + 15 < 5
2b < 5 - 15
2b < -10 
b < -10 ÷ 2
b < -5

Ans: b > 4 or b < - 5 (Answer A)

What is the probability that a point chosen at random in the rectangle is also in the blue triangle

Answers

Answer:

The probability that a point chosen at random in the rectangle is also in the blue triangle is:

1/2

Step-by-step explanation:

We are given a figure

We have to find the probability that a point chosen at random in the rectangle is also in the blue triangle.

Area of rectangle= 4×5 sq. in.

                            = 20 sq. in.

The area of blue triangle=[tex]\dfrac{1}{2}\times 4\times 5[/tex]

                                         = 10 sq. in.

P(that a point chosen at random in the rectangle is also in the blue triangle)

 = area of blue triangle/whole area of the rectangle

= 10/20

= 1/2

Answer: the answer is 1/2

Step-by-step explanation:

The table shows the percentage of students in each of three grade levels who list soccer as their favorite sport. Soccer Sophomores (35%) 50%
Juniors (33%) 45%
Seniors (32%) 30%
Total (100%) (0.5)(0.35) + (0.45)(0.33) + (0.32)(0.3) = 0.4195 or about 42%
Find the probability that the student is a junior, given that soccer is the favorite sport listed.
P(junior | soccer) = ???%

Answers

The answer should be roughly 35.4%. 

You can obtain this answer by looking at the percentage of each subgrouping. For instance, 33% of the class in juniors and 45% of them list soccer as their favorites. Thus showing that 14.85% of the entire school is made up of juniors that enjoy soccer. 

If you do the totaling for all soccer lovers, you get a total of 41.95% of the school. By dividing the two numbers you get the answer above. 

The probability that the student is a junior, given that soccer is the favorite sport listed is 0.354.

How to calculate the probability?

The percentage of student on Junior level who like soccer will be:

= 33% × 45%

= 0.1485

The total percentage of students who like soccer is 42%. Therefore, probability that the student is a junior, given that soccer is the favorite sport listed will be:

= 0.1485/0.42

= 0.354

Learn more about probability on:

https://brainly.com/question/24756209

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