Answers
The sum is ...
(2+1-3)x³ +(-4+6+2)x² +(6-8-4)x +(-3+12-7)
= 0x³ +4x² -6x +2
The sum is 4x² -6x +2
_____
* The process is easier because there are no "carry" operations from one column to another as there may be when adding multi-digit numbers.
Related Questions
A car rental costs $50 for the first day. Additional days cost $35 per day, unless the car is rented for 7 days or more, in which case there is a 10% discount on the daily rate. Identify the expression which represents the cost of renting a car if the car has been rented for more than a week.
A.) 45+35x
B.) 45+31.5x
C.) 50+35x
D.) 50+31.5x
Answers
Answer:
Option D [tex]\$50+\$31.5x[/tex]
Step-by-step explanation:
Let
x------> the number of days
y----> the cost of renting a car
we know that
For [tex]x<7\ days[/tex]
[tex]y=\$50+\$35x[/tex]
For [tex]x\geq 7\ days[/tex]
The rate is equal to
[tex]0.90*\$35=\$31.5[/tex]
so
[tex]y=\$50+\$31.5x[/tex]
In this problem. the car has been rented for more than a week
therefore
[tex]x> 7\ days[/tex]
The cost of renting a car is equal to
[tex]y=\$50+\$31.5x[/tex]
The sum of the squares of two numbers is 18. the product of the two numbers is 9. find the numbers.
Answers
Answer:
x=3 y=3
Step-by-step explanation:
The sum of the squares of two numbers is 18, and the product of those two numbers is 9, you just need to create an equation:
So the sum of the squares is 18, the first number will be represented as X and the second as Y:
[tex]x^{2}+ y^{2} =18[/tex]
And the other one is that the product of the two numbers is 9:
[tex]xy=9[/tex]
We have a system of equations here, we clear X from the first one:
[tex]x=\frac{9}{y}[/tex]
And instert that value of x in the first one:
[tex]x^{2}+ y^{2} =18\\(\frac{9}{y} )^{2}+ y^{2} =18\\81=y^2(18-y^2)\\y^4-18y^2+81=0\\(y^2-9)(y^2-9)=0\\Y^2-9=0\\y^2=9\\y=3[/tex]
By solving this equation we get that the first number is 3.
The second number is solved by inserting the value of Y into one of the equations, in this case we will use the second:
[tex]xy=9\\x=\frac{9}{y} \\x=\frac{9}{3} \\x=3[/tex]
So we get that x and y are both 3.
Please please help i don’t understand this.
Answers
a(n) = a1*r^(n-1)
Where
a(n) = nth term
a1 = first term
r = common ratio
n = 0,1,2,3,4,5, ... n
To establish which graphs agree with this formula, each graph should be tested separately as follows:
Graph A:
a2 = 9
Then
9 = a1*(1/3)^(2-1) =1/3a1 => a1 = 3*9 = 27
Sequence:
a1 = 27
a2 = 9
a3 = 27*(1/3)^(3-1) = 3
a4 = 27*(1/3)^(4-1) = 1
These are the same values shown and thus this graph corresponds to geometric sequence.
Graph B:
a1 = 12
a2 = 12*(1/3)^(2-1) = 4
a3 = 12*(1/3)(3-1) = 4/3
a4 = 12*(1/3)^(4-1) = 4/9
These are the values shown by the graph and thus it corresponds with geometric sequence.
Graph C:
a1 = 3+3/2 = 9/2
a2 = (9/2)*(1/3)^1 = 3/2
a3 = (9/2)*(1/3)^2 = 1/2
a4 = (9/2)*(1/3)^3 = 1/6
a0 = (9/2)*(1/3)^-1 = 13.5 (this is not the case as the graph shows a0 = 12)
Therefore, this graph does not correspond to geometric sequence.
Graph D:
a1 = 4
a2 = 4*(1/3)^1 = 4/3
a3 = 4*(1/3)^2 = 4/9
a4 = 4*(1/3)^3 = 4/27
a0 = 12
This graph seems to agree with values of geometric sequence and thus corresponds to geometric sequence.
Therefore, graphs A, B, and D corresponds with geometric sequence.
Solve for y.
a.10
b.12
c.15
d.18
Answers
Angle ABD=90°
3x°=90°
3x=90
Solving for x:
3x/3=90/3
x=30
Angle CBD=90°
(2x+3y)°=90°
2x+3y=90
x=30
2(30)+3y=90
60+3y=90
Solving for y:
60+3y-60=90-60
3y=30
3y/3=30/3
y=10
Answer: Option a. 10
At the candy store, a chocolate bar costs c dollars and a vanilla bar costs 2 dollars more than a chocolate bar. Jamie buys a chocolate bar and three vanilla bars, and Kevin buys five chocolate bars. How much money, in total, do Jamie and Kevin spend at the candy store in terms of c?
Answers
Jamie: c + 3(c + 2)
Kevin: 5c
c + 3(c + 2) + 5c; Simplify
c + 3c + 6 + 5c; combine like terms
9c + 6 represents the amount they would spend.
A laterally loaded single pile is shown below. use the elastic pile solutions (based on the winkler's model) to calculate the displacement and rotation at pile head ????. assume free headed condition. pile length ???? = 30 ft; young's modulus ???????? = 3 × 10 6 psi; ????ℎ = 30 lb/in3 ; and the eccentricity ???? = 60 in.
Answers
The hypotenuse of an isosceles right triangle is 14 sqrt 2. How long is each leg of the triangle?
Answers
Hope this helps!
Answer:
14
Step-by-step explanation:
Let the legs of the triangle each have length $x$ (they are equal because it is an isosceles right triangle). Then
x^2 + x^2 = (14√2)^2 = 14^2 × (√2)^2 = 14^2 × 2, so x^2 = 14^2. Given that x must be positive, we have x = 14. So, the value of each leg is 14
(Hope this helped you!)
QF Q6.) Find the following function for b.
Answers
5(2x - 2)² - 3
First, you do FOIL method of the binomial:
5(4x² - 8x + 4) - 3
Now distribute the 5:
20x² - 40x + 20 - 3
And combine like terms:
20x² - 40x + 17
=g(2x-2)
=5(2x-2)^2-3
=5(4x^2-8x+4)-3
=20x^2-40x+17
Calculator Problem You downloaded a video game to your computer. You have a 60 -minute free trial of the game. It take 5 minutes to set up the game and 7minutes to play each level. You want to find out how many levels you can play for free. Let ll l l represent the number of levels played. Write an inequality to determine the number of levels you can play in 60 minutes.
Answers
S = setup = 5 minutes.
L = Levels = x
T = Time / L = 7 minutes / Level.
Formula
S + x * T ≤ 60 minutes
Substitute and solve.
5 + 7*x ≤ 60 Subtract 5 from both sides.
7x ≤ 60 - 5
7x ≤ 55 minutes Estimated, the answer is almost x = 8 but not quite. Divide by 7
x ≤ 55/7
x ≤ 7 . He almost makes it through the 8th game but not quite
x ≤ 7 Answer.
The inequality 5 + 7l ≤ 60 represents the scenario where a student has a 60-minute free trial of a game that requires 5 minutes to set up and 7 minutes to play each level, where 'l' denotes the number of levels the student can play.
Explanation:The subject of this question is about setting up an inequality to represent a scenario. The student has a 60-minute free trial of a game and it takes 5 minutes to set up the game and another 7 minutes to play each level. Let's denote 'l' as the number of levels the student can play. The total time spent both setting and playing the game cannot exceed 60 minutes. Therefore, the inequality to determine the maximum number of levels the student can play would be: 5 + 7l ≤ 60.
To explain this further, the '5' is the time spent setting up the game and '7l' is the total time spent playing the levels. As we want to find out the maximum number of levels that can be played within a constraint of 60 minutes, thus we use the less than or equal to symbol ('≤').
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The formula to convert Fahrenheit to Celsius is C=5/9(F-32). Convert 18 degrees C to Fahrenheit. Round to the nearest degree.
Answers
Answer:
Temperature in celcius scale to the nearest degree = 64
Step-by-step explanation:
Temperature in celcius scale = 18° C
We have the formula
[tex]C=\frac{5}{9}(F-32)[/tex]
Substituting value in celcius scale.
[tex]18=\frac{5}{9}(F-32)\\\\F=64.4^OC[/tex]
Temperature in celcius scale to the nearest degree = 64
Enrique earns 101010 points for each question that he answers correctly on a geography test. Write an equation for the number of points, yyy Enrique scores on the test when he answers xxx questions correctly.
Answers
[tex]y = 101010 \times x[/tex]
In the question it must be 10 instead of 101010, y instead of yyy and x instead of xxx.
Since, Enrique earns 10 points for each question that he answers correctly on a geography test.
We have to write an equation for the number of points, 'y' Enrique scores on the test when he answers 'x' questions correctly.
So, Number of points scored = Points scored for one question [tex] \times [/tex] Number of questions answered correctly.
So, Number of points scored = [tex] 10 \times x [/tex]
[tex] y=10 \times x [/tex]
y = 10x is the required equation.
a coin is tossed , then a number 1-10 is chosen at random.what is the probability of getting heads then a number less than 4?
Answers
The probability of tossing a coin and getting heads is 50%, or 0.5, and the probability of selecting a number less than four from 1-10 is 40%, or 0.4.
The overall probability can then be expressed as:
0.5 x 0.4 = 0.2 or 20%
There is a twenty percent chance that a heads would be tossed and a number less than four selected.
Julia has 3 hand bags in her closet in how many ways can the bags be arranged
Answers
There are 6 ways the bags can be arranged.
Explanation:The number of ways the bags can be arranged is equal to the number of permutations of the bags. In this case, Julia has 3 handbags in her closet, so we need to find the number of permutations of 3 objects taken from a set of 3. The formula for permutations is nPr = n! / (n-r)!, where n is the total number of objects and r is the number of objects being selected.
Plugging in the values, we get 3P3 = 3! / (3-3)! = 3! / 0! = 3 x 2 x 1 / 1 = 6.
Therefore, there are 6 ways the bags can be arranged.
The number of ways to arrange 3 handbags is 6.
The arrangement of objects where the order matters is a permutation problem. To find the number of permutations of n distinct objects, one uses the factorial of n, denoted as n!. The factorial of a non-negative integer n is the product of all positive integers less than or equal to n.
In this case, Julia has 3 handbags, so n = 3. We want to find the number of permutations of these 3 handbags, which is given by 3!.
Calculating 3!:
3! = 3 × 2 × 1 = 6
Therefore, there are 6 different ways to arrange the 3 handbags in Julia's closet.
7.
Find the amount of the payment for the sinking fund.
Amount Needed: $58,000
Years Until Needed: 2
Interest Rate: 6%
Interest Compounded: Semiannually
$13,863.74
$8,620.68
$28,155.52
$13,258.22
Answers
Substituting,
SFF = (0.06/2)/{(1+0.06/2)^2*2 -1} = 0.239
PMT = A*SFF = 58,000*0.239 = $13,863.57 ---- The closest answer is $13,863.74
If i know a real root of f(x) = x3 -6x2 + 11x – 6 is neither 1, even, or negative, a good guess would be?
Answers
A good guess for the real root of the polynomial [tex]f(x) = x^3 - 6x^2 + 11x - 6[/tex] that is neither 1, even, nor negative, would be a positive odd integer such as 3 or 5, considering the constraints and the Rational Root Theorem.
The real root of the cubic equation [tex]f(x) = x^3 - 6x^2 + 11x - 6[/tex] that is neither 1, even, nor negative would most likely be a positive odd number (since all positive even numbers are, by default, also excluded). Considering the smallest odd numbers greater than 1 are 3 and 5, and given that we're working with integers, a good guess for the real root would be either 3 or 5. However, one can apply the Rational Root Theorem which states that any rational root, expressed in its lowest form p/q, must have p as a factor of the constant term and q as a factor of the leading coefficient. In this case, the possible rational roots could be
divisors of 6 (constant term) over divisors of 1 (leading coefficient), which gives us only divisors of 6 itself
since the leading coefficient is 1. Among those divisors, the ones that fit the criteria of being neither 1, even, nor negative, would be 3 or positive odd integers.
A jar of peanut butter and a jar of jam cost $10.20 in total. the jar of peanut butter costs $10.00 more than the jar of jam. how much does the jar of jam cost
Answers
Ples help me find slant assemtotes
this one is different because it isn't a rational function
find the slant assemtotes of [tex](y+1)^2=4xy[/tex]
the equation can be rewritten using the quadratic formula as [tex]y=2x-1 \pm \sqrt{x^2-x}[/tex]
ples find slant assemtotes and show all work
thx
Answers
[tex]\displaystyle\lim_{x\to\pm\infty}(f(x)-p(x))=0[/tex]
[tex](y+1)^2=4xy\implies y(x)=2x-1\pm2\sqrt{x^2-x}[/tex]
Since this equation defines a hyperbola, we expect the asymptotes to be lines of the form [tex]p(x)=ax+b[/tex].
Ignore the negative root (we don't need it). If [tex]y=2x-1+2\sqrt{x^2-x}[/tex], then we want to find constants [tex]a,b[/tex] such that
[tex]\displaystyle\lim_{x\to\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0[/tex]
We have
[tex]\sqrt{x^2-x}=\sqrt{x^2}\sqrt{1-\dfrac1x}[/tex]
[tex]\sqrt{x^2-x}=|x|\sqrt{1-\dfrac1x}[/tex]
[tex]\sqrt{x^2-x}=x\sqrt{1-\dfrac1x}[/tex]
since [tex]x\to\infty[/tex] forces us to have [tex]x>0[/tex]. And as [tex]x\to\infty[/tex], the [tex]\dfrac1x[/tex] term is "negligible", so really [tex]\sqrt{x^2-x}\approx x[/tex]. We can then treat the limand like
[tex]2x-1+2x-ax-b=(4-a)x-(b+1)[/tex]
which tells us that we would choose [tex]a=4[/tex]. You might be tempted to think [tex]b=-1[/tex], but that won't be right, and that has to do with how we wrote off the "negligible" term. To find the actual value of [tex]b[/tex], we have to solve for it in the following limit.
[tex]\displaystyle\lim_{x\to\infty}(2x-1+2\sqrt{x^2-x}-4x-b)=0[/tex]
[tex]\displaystyle\lim_{x\to\infty}(\sqrt{x^2-x}-x)=\frac{b+1}2[/tex]
We write
[tex](\sqrt{x^2-x}-x)\cdot\dfrac{\sqrt{x^2-x}+x}{\sqrt{x^2-x}+x}=\dfrac{(x^2-x)-x^2}{\sqrt{x^2-x}+x}=-\dfrac x{x\sqrt{1-\frac1x}+x}=-\dfrac1{\sqrt{1-\frac1x}+1}[/tex]
Now as [tex]x\to\infty[/tex], we see this expression approaching [tex]-\dfrac12[/tex], so that
[tex]-\dfrac12=\dfrac{b+1}2\implies b=-2[/tex]
So one asymptote of the hyperbola is the line [tex]y=4x-2[/tex].
The other asymptote is obtained similarly by examining the limit as [tex]x\to-\infty[/tex].
[tex]\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0[/tex]
[tex]\displaystyle\lim_{x\to-\infty}(2x-2x\sqrt{1-\frac1x}-ax-(b+1))=0[/tex]
Reduce the "negligible" term to get
[tex]\displaystyle\lim_{x\to-\infty}(-ax-(b+1))=0[/tex]
Now we take [tex]a=0[/tex], and again we're careful to not pick [tex]b=-1[/tex].
[tex]\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-b)=0[/tex]
[tex]\displaystyle\lim_{x\to-\infty}(x+\sqrt{x^2-x})=\frac{b+1}2[/tex]
[tex](x+\sqrt{x^2-x})\cdot\dfrac{x-\sqrt{x^2-x}}{x-\sqrt{x^2-x}}=\dfrac{x^2-(x^2-x)}{x-\sqrt{x^2-x}}=\dfrac x{x-(-x)\sqrt{1-\frac1x}}=\dfrac1{1+\sqrt{1-\frac1x}}[/tex]
This time the limit is [tex]\dfrac12[/tex], so
[tex]\dfrac12=\dfrac{b+1}2\implies b=0[/tex]
which means the other asymptote is the line [tex]y=0[/tex].
which means the other asymptote is the line .
If ∆XYZ = ∆KLM, then < Y = Please help due today
Answers
∠X = ∠K
∠Y = ∠L
∠Z = ∠M
So ∠Y = ∠L
I hope this helps!
Jorge owes his father $60. After raking the lawn for the month, he has paid him $12, $8, and $9. How much money does Jorge still has owes his father?
Answers
60 - 29= 31
Jorge owes his father $31
k+1=3k-1 please show me the correct steps to solve this problem
Answers
-2k + 1 = -1 |-1
-2k = -2 |:(-2)
k = 1
Hey can you please help me posted picture of question
Answers
A compound event is one in which there is more than one possible outcome. It is also defined as a probabilistic event with two or more favorable outcomes. For example, when you throw a die (singular for dice), it is called a simple event. On the other hand, when you throw a dice, it is known as a compound event.
Emi computes the mean and variance for the population data set 87, 46, 90, 78, and 89. She finds the mean is 78. Her steps for finding the variance are shown below. What is the first error she made in computing the variance? Emi failed to find the difference of 89 - 78 correctly. Emi divided by N - 1 instead of N. Emi evaluated (46 - 78)2 as -(32)2. Emi forgot to take the square root of -135.6.
Answers
The first error Emi made was dividing by N - 1 instead of N when computing the population variance.
The first error in computing the variance is Emi divided by N - 1 instead of N. In Emi's calculations for the data set, which includes the numbers 87, 46, 90, 78, and 89, the correct method should be to divide by N, because she is dealing with a population data set, not a sample.
For the population variance, we divide the sum of squared differences from the mean by the total number of data points in the population, which is N. However, Emi incorrectly divided by N - 1, which would only be correct if she were calculating the sample variance to estimate the population variance based on a subset of the population data.
The probability that a student correctly answers on the first try (the event
a.is p(a) = 0.2. if the student answers incorrectly on the first try, the student is allowed a second try to correctly answer the question (the event b). the probability that the student answers correctly on the second try given that he answered incorrectly on the first try is 0.5. find the probability that the student answers the question on the first or second try.
a.0.90
b.0.40
c.0.10
d.0.70
e.0.60
Answers
We're given that [tex]P(A)=0.2[/tex] and [tex]P(B\mid A^C)=0.5[/tex]. From the first probability, we know that [tex]P(A^C)=1-0.2=0.8[/tex]. By definition of conditional probability,
[tex]\mathbb P(B\mid A^C)=\dfrac{\mathbb P(B\cap A^C)}{\mathbb P(A^C)}[/tex]
[tex]\implies\mathbb P(B\cap A^C)=0.5\cdot0.8=0.4[/tex]
We're interested in the probability of either [tex]A[/tex] or [tex]B[/tex] occurring, i.e. [tex]\mathbb P(A\cup B)[/tex]. Apply the inclusion-exclusion principle, which says
[tex]\mathbb P(A\cup B)=\mathbb P(A)+\mathbb P(B)-\mathbb P(A\cap B)[/tex]
We know the probability of intersection is 0, and we know [tex]\mathbb P(A)[/tex]. Meanwhile, by the law of total probability, we have
[tex]\mathbb P(B)=\mathbb P(B\cap A)+\mathbb P(B\cap A^C)=\mathbb P(B\cap A^C)[/tex]
so we end up with
[tex]\mathbb P(A\cup B)=0.2+0.4=0.6[/tex]
The probability that the student answers the question on the first or second try is 0.60.
Given
P(A) = 0.2
[tex]\rm P(B|A^c)=0.5[/tex].
What is conditional probability?The conditional probability of an event is when the probability of one event depends on the probability of occurrence of the other event.
When two events are mutually exclusive.
Then,
[tex]\rm P(A\cap B)=0[/tex]
The first probability is;
[tex]\rm P(A^C)=1-0.2=0.8[/tex]
Therefore,
The probability that the student answers the question on the first or second try is;
[tex]\rm P(A\cup B)= P(A) +P(B)-P(A \cap B)\\\\ P(A\cup B)= P(A) +P(B|A^C) \times P(A^C)-P(A \cap B)\\\\ P(A\cup B)= 0.2+0.5 \times 0.8 -0\\\\P(A\cup B)=0.2+0.40\\\\ P(A\cup B)=0.60[/tex]
Hence, the probability that the student answers the question on the first or second try is 0.60.
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PLZ HELP ASAP WRITE STANDERED EQAUTION OF A CIRCLE
Answers
(x-xo) ^ 2 + (y-yo) ^ 2 = r ^ 2
Where,
(xo, yo): coordinate of the center of the circle
r: radius of the circle.
Substituting values we have:
(x-9.2) ^ 2 + (y + 7.4) ^ 2 = (5/3) ^ 2
Rewriting:
(x-9.2) ^ 2 + (y + 7.4) ^ 2 = 25/9
Answer:
The equation of the circle is:
(x-9.2) ^ 2 + (y + 7.4) ^ 2 = 25/9
C(9.2, -7.4)
r^2 = (x-h)^2 + (y-k)^2
(5/3)^2 = (x - 9.2)^2 + (y + 7.4)^2
HELP PLEASE
Determine the missing statements and reasons for the following proof.
Answers
Reason 3: Congruent supplements theorem
Statements:
Statement 4: Angle 1 is congruent with angle 2
Answer: Option D:
Reason 3: Congruent supplements theorem.
Statement 4: Angle 1 is congruent with angle 2
In a mathematical proof, missing statements and reasons are usually concluded from the given statements and the relevant geometric postulates or theorems. They could include establishing the congruency of angles or declaring the parallelism of lines.
Explanation:Without the concrete steps of the proof or the reasoning proposed, it is difficult to provide the exact missing statements and reasons. However, in a general mathematical proof, common reasons used include 'definition of congruent angles', 'definition of parallel lines', 'alternate interior angles theorem', etc.
For instance, if we have a proof that involves stating two angles are congruent, the missing statement might be 'Angle A is congruent to Angle B', and the missing reason could be 'Definition of Congruent Angles' or 'Angle Bisector Theorem', if an angle bisector comes into the picture.
Another missing statement might be 'Segment AB is parallel to Segment CD', with the reason being 'Corresponding Angles Postulate', or 'Alternate Interior Angles Theorem', if the proof involves parallel lines.
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while watching a football game, Lin Chow decided to list yardage agained as positive integers and yardage lost as negative integers. after this plays, Lin recorded 14, -7, and 9. what was the net gain or lost?
Answers
hat is the sum of the geometric series in which a1 = 3, r = 4, and an = 49,152?
Hint: an = a1(r)n − 1, where a1 is the first term and r is the common ratio.
Sn = −65,535
Sn = 16,383
Sn = 13,120
Sn = 65,535
Answers
To find the sum of the geometric series, we use the formula: Sn = a1 * (r^n - 1) / (r - 1). Substituting the given values and solving, we find that the sum is 16,383.
Explanation:To find the sum of a geometric series, we can use the formula Sn = a1 * (r^n - 1) / (r - 1), where Sn is the sum of the series, a1 is the first term, r is the common ratio, and n is the number of terms.
In this case, a1 = 3, r = 4, and an = 49,152. We can use the formula to find n, which is the exponent.
49,152 = 3 * (4^n - 1) / (4 - 1)
49,152 = 3 * (4^n - 1) / 3
16,384 = 4^n - 1
4^n = 16,385
n = log4(16,385)
n ≈ 7
Now, we can substitute the values into the formula for Sn.
Sn = 3 * (4^7 - 1) / (4 - 1)
Sn = 3 * (16,384 - 1) / 3
Sn = 3 * 16,383 / 3
Sn = 16,383
Therefore, the sum of the geometric series is 16,383. So the correct answer is Sn = 16,383.
The correct answer is [tex]\( S_n = 65,535 \)[/tex].
To find the sum of a geometric series, you can use the formula:
[tex]\[ S_n = a_1 \frac{(r^n - 1)}{r - 1} \][/tex]
Where:
- [tex]\( S_n \)[/tex] is the sum of the series,
- [tex]\( a_1 \)[/tex] is the first term,
- [tex]\( r \)[/tex] is the common ratio,
- [tex]\( n \)[/tex] is the number of terms.
Given [tex]\( a_1 = 3 \), \( r = 4 \), and \( a_n = 49,152 \)[/tex], we need to find [tex]\( n \)[/tex]. The formula for the [tex]\( n^{th} \)[/tex] term in a geometric series is [tex]\( a_n = a_1 \times r^{(n-1)} \)[/tex]. In this case, [tex]\( 49,152 = 3 \times 4^{(n-1)} \)[/tex]
Let's solve for n:
[tex]\[ 4^{(n-1)} = \frac{49,152}{3} \][/tex]
[tex]\[ 4^{(n-1)} = 16,384 \][/tex]
[tex]\[ n-1 = \log_4(16,384) \][/tex]
[tex]\[ n-1 = 7 \][/tex]
[tex]\[ n = 8 \][/tex]
Now that we have [tex]\( n = 8 \)[/tex], we can use it in the sum formula:
[tex]\[ S_n = 3 \frac{(4^8 - 1)}{4 - 1} \][/tex]
[tex]\[ S_n = 3 \frac{(65,536 - 1)}{3} \][/tex]
[tex]\[ S_n = 3 \frac{65,535}{3} \][/tex]
[tex]\[ S_n = 65,535 \][/tex]
Therefore, the correct answer is [tex]\( S_n = 65,535 \)[/tex].
What is the domain of the function g(x) = 52x? x > 0 x < 0 all real numbers all positive real numbers
Answers
The domain: all real numbers.
Answer: all real numbers
Step-by-step explanation:
The given function is : [tex]g(x) = 52x[/tex], which is polynomial function with degree one.
The domain of a function is the set of all values for x for which the function must be defined.We know that the domain of a polynomial is the entire set of real numbers because for any real number r the polynomial function exists.
Therefore, the domain of the given function [tex]g(x) = 52x[/tex] is the set of real numbers.
K+1=3k-1 what us the answer
Answers
2k = 2
Divide by 2:
k = 1
If you want to check your work:
1 + 1 = 3 - 1
2 = 2
Conduct a chi-squared test of independence on the data presented in data set
d. assume equal probabilities of fe for each cell and make sure to report all relevant statistics, including the value of χ2 obtained, the critical value and your decision as to whether to reject the null hypothesis .