Help me with 1 and 2 please

Answer:  The required co-ordinates of the point are (9, 0).

Step-by-step explanation:  We are given to find the co-ordinates of the point that is [tex]\dfrac{3}{5}[/tex] of the way from A(-9,3) to B(21, -2).

Let K be the required point. Then, we mus have

[tex]AK:AB=3:5\\\\\Rightarrow \dfrac{AK}{AK+BK}=\dfrac{3}{5}\\\\\\\Rightarrow 5AK=3AK+3BK\\\\\Rightarrow 2AK=3BK\\\\\Rightarrow AK:BK=3:2.[/tex]

We know that

the co-ordinates of a point that divides the line joining the points (a, b) and (c, d) in the ratio m : n are given by

[tex]\left(\dfrac{mc+na}{m+n},\dfrac{md+nb}{2}\right).[/tex]

For the given division, m : n = 3 : 2.

Therefore, the co-ordinates of the point K are

[tex]\left(\dfrac{3\times21+2\times(-9)}{3+2},\dfrac{3\times(-2)+2\times3}{3+2}\right)\\\\\\=\left(\dfrac{63-18}{5},\dfrac{-6+6}{5}\right)\\\\=\left(\dfrac{45}{5},\dfrac{0}{5}\right)\\\\=(9,0).[/tex]

Thus, the required co-ordinates of the point are (9, 0).

Building and solving an equation, it is found that the coordinates are: (9,0).

C is 3/5 of the way from A to B, thus:

[tex]C - A = \frac{3}{5}(B - A)[/tex]

This is used to find both the x-coordinate and the y-coordinate of C.

First, the x-coordinate, considering [tex]C = x, A = -9, B = 21[/tex].

[tex]C - A = \frac{3}{5}(B - A)[/tex]

[tex]x + 9 = \frac{3}{5}(21 + 9)[/tex]

[tex]x = 18 - 9[/tex]

[tex]x = 9[/tex]

Then, the y-coordinate, considering [tex]C = y, A = 3, B = -2[/tex].

[tex]C - A = \frac{3}{5}(B - A)[/tex]

[tex]y - 3 = \frac{3}{5}(-2 - 3)[/tex]

[tex]y = -3 + 3[/tex]

[tex]y = 0[/tex]

Thus, the coordinates are (9,0).

A similar problem is given at https://brainly.com/question/24352869

Answer:

(2,0) was already given so (-1,0) is the other one.

Step-by-step explanation:

So we are asked to use the quadratic formula.

To find the x-intercepts (if they exist) is use:

[tex]\text{ If } y=ax^2+bx+c \text{ then the } x-\text{intercepts are } (\frac{-b \pm \sqrt{b^2-4ac}}{2a},0)[/tex].

Let's start:

Compare the following equations to determine the values for [tex]a,b, \text{ and }c [/tex]:

[tex]y=ax^2+bx+c[/tex]

[tex]y=4x^2-4x-8[/tex]

So

[tex]a=4[/tex]

[tex]b=-4[/tex]

[tex]c=-8[/tex]

We are now ready to enter into our formula:

[tex]x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]

[tex]x=\frac{4 \pm \sqrt{(-4)^2-4(4)(-8)}}{2(4)}[/tex]

[tex]x=\frac{4 \pm \sqrt{16+16(8)}}{8}[/tex]

[tex]x=\frac{4 \pm \sqrt{16(1+8)}}{8}[/tex]

[tex]x=\frac{4 \pm \sqrt{16}\sqrt{1+8}}{8}[/tex]

[tex]x=\frac{4 \pm 4\sqrt{9}}{8}[/tex]

[tex]x=\frac{ 4 \pm 4(3)}{8}[/tex]

[tex]x=\frac{4 \pm 12}{8}[/tex]

[tex]x=\frac{4(1\pm 3)}{8}[/tex]

[tex]x=\frac{1(1\pm 3)}{2}[/tex]

[tex]x=\frac{1 \pm 3}{2}[/tex]

[tex]x=\frac{1+3}{2} \text{ or } \frac{1-3}{2}[/tex]

[tex]x=\frac{4}{2} \text{ or } \frac{-2}{2}[/tex]

[tex]x=2 \text{ or } -1[/tex]

So the x-intercepts are (2,0) and (-1,0).

(2,0) was already given so (-1,0) is the other one.

Answer:

D

Step-by-step explanation:

Formula

Volume = pi*r^2*h

Givens

r = x

h = 3x

Volume= 242

Solution

242 = pi * x^2 * 3x

242 = 3.14 * 3x^3                    Divide by pi

242/3.14 = 3.14 * 3x^3 / 3.14   Do the division

77 = 3x^3                                 Divide by 3

77/3 = 3x^3 /3

25.69 = x^3                              Take the cube root of both sides.

2.95  = x

The height of the cylinder is 3 times that of the radius of the circle (x)

The answer is 8.85. I suppose the closest answer is 8.

Answer:

  AC = 26

Step-by-step explanation:

AD = DC . . . . . .these segments are marked congruent

8x-1 = 6x+9 . . . substitute the given expressions

2x = 10 . . . . . add 1-6x

x = 5

__

AC = 2·AB = 2(3x-2) = 2(3·5-2) . . . . substitute into expression for AB

AC = 26

Your answer is the third option, x = -2 and x=6

We can see this because the solutions of x^2/2 - 8 = 2x - 2 are going to be where the lines y = x^2/2 - 8 and y = 2x - 2, because this is where the two equations are equal to each other.

Therefore, we can just look on the graph at where the two lines intersect, and see that it happens when x = -2 and x = 6.

I hope this helps!

Answer:

x=-2 and x=6

Step-by-step explanation:

The solution to a graph would be where the two lines intersect. When you look at the graph you plot where they connect

(-2, -6), (6, 10)

The x value is the very first variable in an ordered pair. Therefore, the solution to this graph would be x=-2 and x=6.

Answer:

[tex]f(x)=2(x-2)^{3}(x+2)^{2}[/tex]

Step-by-step explanation:

we know that

2 is a zero of multiplicity 3 of the polynomial

so

we have that

x=2  is a solution of the polynomial

A factor of the polynomial is

[tex](x-2)^{3}[/tex] ----> is elevated to the cube because is a multiplicity 3

and the other solution is x=-2

since the polynomial  is fifth degree, x=-2 must have a multiplicity 2

so

the other factor of the polynomial is  

[tex](x+2)^{2}[/tex] ----> is squared because is a multiplicity 2

therefore

The polynomial is equal to multiply the factors by the leading coefficient

so

[tex]f(x)=2(x-2)^{3}(x+2)^{2}[/tex]

The polynomial function based on the given properties: zeros at 2 (with multiplicity 3) and -2 (with multiplicity 1), leading coefficient of 2, is f(x) = 2(x - 2)³(x + 2).

To construct a polynomial with given zeros and multiplicities, we need to set up a product of binomial factors based on the zeros, with each binomial factor raised to the power of its respective multiplicity. The resulting polynomial is the given function f(x).

For the given properties, the roots are 2 and -2. The root 2 has multiplicity 3 and the root -2 has multiplicity 1. Also, the leading coefficient is 2. So, we can set up the polynomial function as follows:

f(x) = 2(x - 2)3(x + 2)

This represents a fifth degree polynomial function that has the zeros and multiplicities listed, with the leading coefficient of 2.

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Answer:

[tex]\large\boxed{3^\frac{2}{3}}[/tex]

Step-by-step explanation:

[tex]Use\\\\\sqrt[n]{a^m}=a^\frac{m}{n}\\\\(a^n)^m=a^{nm}\\\\a^n\cdot a^m=a^{n+m}\\\\\bigg(\sqrt[4]{9^{15}}\cdot\sqrt{3^3}\bigg)^\frac{2}{27}=\bigg(\sqrt[4]{(3^2)^{15}}\cdot3^\frac{3}{2}\bigg)^\frac{2}{27}=\bigg(\sqrt[4]{3^{2\cdot15}}\cdot3^{\frac{3}{2}}\bigg)^\frac{2}{27}\\\\=\bigg(3^{\frac{30}{4}}\cdot3^\frac{3}{2}\bigg)^\frac{2}{27}=\bigg(3^{\frac{15}{2}}\cdot3^\frac{3}{2}\bigg)^\frac{2}{27}=\bigg(3^{\frac{15}{2}+\frac{3}{2}}\bigg)^\frac{2}{27}[/tex]

[tex]=\bigg(3^{\frac{18}{2}}\bigg)^\frac{2}{27}=\bigg(3^9\bigg)^\frac{2}{27}=3^{9\cdot\frac{2}{27}}=3^\frac{2}{3}[/tex]

Answer:

This is an obtuse, isosceles triangle.

Step-by-step explanation:

The largest angle is greater than 90 degrees (obtuse), and two sides are equal as you can tell by two equal angles (isosceles).

The given triangle can be classified as isosceles and acute triangle.

A triangle is a two dimensional figure which consist of three vertices, three edges and three angles.

Sum of the interior angles of a triangle is 180 degrees.

Given is a triangle.

The three angles of the triangle are 41°, 41° and 98°.

That is, two angles of the triangle are equal. So the sides opposite these two angles are also equal.

So this is an isosceles triangle.

Obtuse triangle has one of the angles greater than 90°.

Acute triangle has all the angles less than 90°.

Here all the angles are less than 90°.

So it is acute.

Hence the given triangle is acute and isosceles triangle.

Learn more about Triangles here :

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Answer:

4 ropes.

Step-by-step explanation:

There are 100 cms in a meter.

So 10 meters = 10* 100

= 1000 cms.

1000 / 210 = 4  ropes with  160 cms remaining.

Answer:

25,5 miles

Step-by-step explanation:

4.25 inch on map

4.25/0.5 = 8,5

8,5 * 3 = 25,5 miles

Final answer:

To find the actual distance between two towns on a map, set up a proportion using the given scale. By solving the proportion, you can determine the real distance between the towns.

Explanation:

To find the actual distance between the two towns, we can set up a proportion using the given scale:

Answer:

[tex]y+1=\dfrac{1}{3}(x+2)[/tex] - point-slope form

[tex]f(x)=\dfrac{1}{3}x-\dfrac{1}{3}[/tex] - function notation

Step-by-step explanation:

The point-slope form of an equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

m - slope

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

From the graph we have the points (-2, -1) and (1, 0).

Substitute:

[tex]m=\dfrac{0-(-1)}{1-(-2)}=\dfrac{1}{3}[/tex]

[tex]y-(-1)=\dfrac{1}{3}(x-(-2))[/tex]

[tex]y+1=\dfrac{1}{3}(x+2)[/tex] - point-slope form

[tex]y+1=\dfrac{1}{3}(x+2)[/tex]          use the distributive property

[tex]y+1=\dfrac{1}{3}x+\dfrac{2}{3}[/tex]           subtract 1 = 3/3 from both sides

[tex]y=\dfrac{1}{3}x-\dfrac{1}{3}[/tex]

Answer:

1. 3rd option

2. 2nd option

Step-by-step explanation:

Answer:

see explanation

Step-by-step explanation:

Using the exact values of the trigonometric ratios

sin60° = [tex]\frac{\sqrt{3} }{2}[/tex], cos60° = [tex]\frac{1}{2}[/tex]

sin45° = cos45° = [tex]\frac{1}{\sqrt{2} }[/tex]

Using the sine ratio on the right triangle on the left

sin60° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{a}{4\sqrt{3} }[/tex] = [tex]\frac{\sqrt{3} }{2}[/tex]

Cross- multiply

2a = 4[tex]\sqrt{3}[/tex] × [tex]\sqrt{3}[/tex] = 12 ( divide both sides by 2 )

a = 6

Using the cosine ratio on the same right triangle

cos60° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{c}{4\sqrt{3} }[/tex] = [tex]\frac{1}{2}[/tex]

Cross- multiply

2c = 4[tex]\sqrt{3}[/tex] ( divide both sides by 2 )

c = 2[tex]\sqrt{3}[/tex]

------------------------------------------------------------------------------------------

Using the sine/cosine ratios on the right triangle on the right

sin45° = [tex]\frac{a}{b}[/tex] = [tex]\frac{6}{b}[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex]

Cross- multiply

b = 6[tex]\sqrt{2}[/tex]

cos45° = [tex]\frac{d}{b}[/tex] = [tex]\frac{d}{6\sqrt{2} }[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex]

Cross- multiply

[tex]\sqrt{2}[/tex] d = 6[tex]\sqrt{2}[/tex] ( divide both sides by [tex]\sqrt{2}[/tex] )

d = 6

------------------------------------------------------------------------------------------------

a = 6, b = 6[tex]\sqrt{2}[/tex], c = 2[tex]\sqrt{3}[/tex], d = 6

Answer: 3

Step-by-step explanation: I jus got it right on a pex

Answer: Choice C

x represents time and x is positive; y value is 45 times more than the x value

==================================

Explanation:

The inequality y > 45x is the same as y > 45*x

We have y greater than 45*x meaning that y is 45 times more than the x value.

As an example, if x = 2, then 45*x = 45*2 = 90 meaning that y must be larger than 90 if you picked x = 2. In this scenario, x = 2 means that if you traveled for 2 hours then you must have gone more than 90 miles in total distance.

The feline expanded in weight compared with the canine's underlying weight which is steady with the data given.

The allocation of weights to the important variables that produce the calculation's optimum is referred to as a direct consequence.

Let c be the feline's unique weight. Let c* be the feline's new weight.

Let d be the canine's unique weight. The d* be the canine's new weight.

The equation is given as,

c = 1.2 c

d = .9 d

c = d

The other equation is given as,

p = (d - c)/d = 1 - c/d

We know that the given condition,

c = d = 0.9 d

Then the equation is written as,

p = 1 - 0.9d/d

p = 1 - 0.9

p = 0.1 or 10%.

Hence, toward the beginning, the rate contrast compared with the canine was,

q = (d - c)/d = 1 - 0.75 = 0.25 or 25%.

That is, the feline weighed not exactly like the canine toward the beginning. Since p < q, the feline expanded in weight compared with the canine's underlying weight — which is steady with the data given.

More about the solution of the equation link is given below.

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D) two parabolas one facing down with a vertex at 0, 3 and one facing up with a vertex at 0, negative 3

First of all, let's rewrite the equations in a mathematical language:

[tex]y=\frac{3}{4}x^2-3[/tex]

Since the leading coefficient, the number that accompanies [tex]x^2[/tex] is positive, that is, its value is 3/4, then the parabola opens upward. On the other hand, the vertex can be found as:

[tex](h,k)=\left(-\frac{b}{2a},f\left(-\frac{b}{2a}\right)\right) \\ \\ a=3/4 \\ b=0 \\ c=-3 \\ \\ h=-\frac{0}{2(3/4)}=0 \\ \\ k=f(0)=\frac{3}{4}(0)^2-3=-3 \\ \\ \\ \boxed{Vertex \rightarrow (h,k)=0,-3}[/tex]

[tex]y=-\frac{3}{4}x^2+3[/tex]

Since the leading coefficient is negative, that is, its value is -3/4, then the parabola opens downward. Similarly the vertex can be found as:

[tex](h,k)=\left(-\frac{b}{2a},f\left(-\frac{b}{2a}\right)\right) \\ \\ a=-3/4 \\ b=0 \\ c=3 \\ \\ h=-\frac{0}{2(-3/4)}=0 \\ \\ k=f(0)=-\frac{3}{4}(0)^2+3=3 \\ \\ \\ \boxed{Vertex \rightarrow (h,k)=0,3}[/tex]

Both graph are shown below and you can see that the conclusion of our problem is correct.

5)

[tex]\bf \begin{array}{|cc|cccc|ll} \cline{1-6} sodas&x&\underline{24}&28&\underline{32}&36\\ \cline{1-6} cost&y&\underline{18}&21&\underline{24}&27\\ \cline{1-6} \end{array}~\hspace{9em} (\stackrel{x_1}{24}~,~\stackrel{y_1}{18})\qquad (\stackrel{x_2}{32}~,~\stackrel{y_2}{24}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{24-18}{32-24}\implies \cfrac{6}{8}\implies \cfrac{3}{4}[/tex]

6)

[tex]\bf \begin{array}{|cc|cc|ll} \cline{1-4} year&x&0&12\\ \cline{1-4} \$&y&720&1080\\ \cline{1-4} \end{array}~\hspace{10em} (\stackrel{x_1}{0}~,~\stackrel{y_1}{720})\qquad (\stackrel{x_2}{12}~,~\stackrel{y_2}{1080}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1080-720}{12-0}\implies \cfrac{360}{12}\implies \cfrac{30}{1}\implies 30[/tex]

7)

slope as you should already know is rise/run, or how much something moves in relation something else, namely how much the y-axis go up as the x-axis moves sideways, one moves, the other follows, but the increments will be different, sometimes the same, but usually different.

the y-intercept means, when the graph of the equation touches or intercepts the y-axis, and when that happens x = 0, or the horizontal distance is at bay.

for the slope on  6), 30 or 30/1 means, for every 1 year(x) passed, the worth(y) increased by 30, or jumped by 30 units, so as the x-axis moved 1, the y-axis moved 30.  After 12 years 30 * 12 = 360, and we add the initial 720 and we end up with 1080.

the y-intercept, well, as aforementioned is when x = 0, is year 0.

Answer:

Top:

The rate change is 4.

Bottom:

The rate change is 3.

Step-by-step explanation:

24+4= 28     28+4=32  (and)  32+4=36

18+3=21  21+3=24    (and)  24+3=27

I will get back to you on the rest>

Hope this helped tho! :3

Answer:

B+

Step-by-step explanation:

Grades earned in five subjects are;

A,C+,A-,B- and B+

Remaining subject is biology

Total number of subjects will be=6

3.2 gpa as a percentile =86

For her to maintain 3.2 gpa total sum of percentile in the 6 subjects should be at least

6×86=516

Emily total sum of subjects in percentile is 93+77+90+80+87=427

Find the difference , 516-427=89

89 is grade B+

Emily should earn a grade of B+ to keep her 3.2 gpa

Answer:

45ml of pure water to obtain 135ml of the desired 30% solution

Step-by-step explanation:

45% of 90 = 40.5

So, 40.5ml of alcohol in 90ml

We want 30% and therefore need a ratio of 3:7

40.5÷3=13.5

so one part of our ratio is 13.5

we then times this by 7

13.5 x 7 = 94.5

so, 94.5ml of water

to work out how much we already have, we should do 90ml- 40.5ml = 49.5ml

and then 94.5- 49.5 = 45ml

We need 45ml of water and the total mo of the desired solution will be 90+45=135ml

To dilute a 45% alcohol solution to a 30% alcohol solution by adding pure water, you will need to add 45 mL of pure water to the initial 90 mL to achieve a total volume of 135 mL with the desired 30% alcohol concentration.

To dilute a 45% alcohol solution to a 30% alcohol solution using pure water, we can use the concept of concentration dilution in chemistry. This involves calculating the amount of diluent (in this case, water) to add to an existing solution to achieve a desired concentration.

Let's denote the amount of pure water to add as x mL. The initial volume of the alcohol solution is 90 mL with a 45% concentration, meaning it contains 40.5 mL of pure alcohol. Since adding water doesn't change the amount of alcohol, the final mixture's alcohol volume remains at 40.5 mL.

To find the final volume of the solution and the amount of water needed, we use the formula for the final concentration: Final Concentration = (Volume of Solute) / (Final Volume of Solution). Substituting the given and desired values gives us 30% = 40.5 mL / (90 mL + x).

Rearranging and solving for x gives: x = (40.5 / 0.3) - 90 = 135 - 90 = 45 mL. Therefore, 45 mL of pure water must be added to the original solution to get a 30% alcohol solution.

In conclusion, adding 45 mL of pure water to the 90 mL of 45% alcohol mixture yields a total volume of 135 mL of the desired 30% solution.

Answer:

Option 1

Step-by-step explanation:

Tri means 3. An expression which has 3 terms and the terms are separated by plus or minus:

c^2+c+6

Thus option 1 is correct....

For this case we have that by definition, a trinomial is an algebraic expression formed by the sum or difference of three terms or monomials.

Example:

[tex]ax ^ 2y + cx + dy[/tex]

Thus, the correct option is option 1.

[tex]c ^ 2 + c + 6[/tex]

Three terms are observed.

Answer:

Option 1

Answer:

1) The profit of the company dropped by -15% compared to last year.

2) The temperature of Alaska was -5 degrees yesterday.

3) John had 1,000$ dollars deposited in the bank, and then made a poor investment, causing him to owe the bank 5,000$, making his account -4,000$

Step-by-step explanation:

With each scenario you have to try to find a new way to express a negative number which is primarily through loss. In which ways can you unique express loss of a value below zero in real world is the question, and you can do so with examples like money and temperature.

Answer:

John F. Kennedy

Answer:

[tex]\large\boxed{4x^4\sqrt[3]{2x^2}}[/tex]

Step-by-step explanation:

[tex]\sqrt[3]{2x^5}\cdot\sqrt[3]{64x^9}\qquad\text{use}\ \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\\\\=\sqrt[3]{2}\cdot\sqrt[3]{64}\cdot\sqrt[3]{x^5x^9}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt[3]2\cdot4\cdot\sqrt[3]{x^2x^3x^9}\\\\=4\sqrt[3]2\cdot\sqrt[3]{x^2x^{12}}\\\\=4\sqrt[3]2\cdot\sqrt[3]{x^2x^{4\cdot3}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=4\sqrt[3]2\cdot\sqrt{x^2(x^4)^3}\\\\=4\sqrt[3]2\cdot\sqrt[3]{x^2}\cdot\sqrt[3]{(x^4)^3}\qquad\text{use}\ \sqrt[n]{a^n}=a\\\\=4\sqrt[3]{2x^2}\cdot x^4\\\\=4x^4\sqrt[3]{2x^2}[/tex]

Answer: it's c to put it simply

Step-by-step explanation:

Answer:

I think that the answer is A.

Answer:

No options is correct.    

Step-by-step explanation:

Given : The product of -4 and 3.

To find : Which expression could be used to determine the product ?

Solution :

The product of -4 and 3 is [tex]-4\times 3=-12[/tex]

To know which expression we solve each options and get whose result is same as ours,

A) [tex](-4)(3)\times (-4)(\frac{1}{4})[/tex]

Solve,

[tex](-4)(3)\times (-4)(\frac{1}{4})= -12\times -1=12[/tex]

B) [tex](-4)(3)+(-4)(\frac{1}{4})[/tex]

Solve,

[tex](-4)(3)+(-4)(\frac{1}{4})= -12+(-1)=-13[/tex]

C) [tex](3)(-4)\times (3)(\frac{1}{4})[/tex]

Solve,

[tex](3)(-4)\times (3)(\frac{1}{4})=-12\times\frac{3}{4}=-9[/tex]

D) [tex](3)(-4)+(3)(\frac{1}{4})[/tex]

Solve,

[tex](3)(-4)+(3)(\frac{1}{4})=-12+\frac{3}{4}=-11.25[/tex]

From the given options, No options will get the product.

if EF ≅ WV and JK is intersecting both at a right-angle, the distances OK = JP and likewise PG = GO, namely

[tex]\bf 2(4x-3)-8=4+2x\implies 8x-6-8=4+2x\implies 8x-14=4+2x \\\\\\ 6x-14=4\implies 6x=18\implies x=\cfrac{18}{6}\implies x=3[/tex]

Answer:

I think the answer is d

Step-by-step explanation:

since the graph is a lot bigger than the females, but the box thing is in about the same spot as the females ( you know what i mean), but i'm not 100% sure, but i think its the safest answer

Answer:

6

Step-by-step explanation:

You can see how f(x) is now f(8), this implies you have to replace any x's you see with an 8.

So f(8) = 2(8-5) = 2(3) = 6

Answer:

the cost of rib eye steak dinner = $22.47

the cost of grilled salmon dinners= $10.57 .....

Step-by-step explanation:

Let x be the rib eye steak dinner.

Let y be the grilled salmon dinner.

According to the first given statement:

12x+27y= $554.98    (equation 1)

According to the second statement:

26x+9y=$584.36      ( equation 2)

Lets take a look at the 1st equation:

12x+27y= $554.98

12x=$554.98- 27y

x=$554.98- 27y/12

Now substitute the value of x in 2nd equation:

26x+9y=$584.36

26($554.98- 27y/12)+9y=$584.36

26(554.98- 27y)+9y=584.36*12

14429.48-702y=7012.32

-702y=7012.32-14429.48

-702y= -7417.16

y= 7417.16/702

y=$10.57

Now substitute the value of y in equation 1:

12x+27y= $554.98

12x+27(10.57)=554.98

12x+285.39 = 554.98

Move the constant to the R.H.S

12x=554.98-285.39

12x=269.59

Divide both the terms by 12

12x/12=269.59/12

x=$22.47

Thus the cost of rib eye steak dinner = $22.47

the cost of grilled salmon dinners= $10.57 .....

Answer:

75 yd^2.

Step-by-step explanation:

If the width = x yards, the length will be 3x yards.

The perimeter = 2 * length + 2 * width

= 2* 3x + 2*x = 40

6x + 2x = 40

8x = 40

x = 5

So the width is 5 and the length is 15 yards.

The area = 5 * 15 = 75 yd^2.

Answer:

75

Step-by-step explanation:

x=breadth

3x=length

perimeter=2(x+3x)=8x

40=8x

x=5

length=15

breadth=5

area=15*5=75

Answer:

x = -3 or x = 2

Step-by-step explanation:

It is given a quadratic equation,

(x + 3)(x - 2) = 0

To find the solution of given equation

Let  (x + 3)(x - 2) 0

⇒ either (x + 3) = 0 or (x - 2) = 0

If (x + 3) = 0 then  x = -3

If (x - 2) = 0 then x = 2

Therefore the solution of given equation are

x = -3 or x = 2