Answers
Answer:
Total moment of inertia when arms are extended: 1.613 [tex]kg\,m^2[/tex]
Explanation:
This second part of the problem could be a pretty complex one, but if they expect you to do a simple calculation, which is what I imagine, the idea is just adding another moment of inertia to the first one due to the arms extended laterally and use the moment of inertia for such as depicted in the image I am attaching.
In that image:
L is the length from one end to the other of the extended arms (each 0.75m from the center of the body) which gives 1.5 meters.
m is the mass of both arms. That is: twice 5% of the mass of the person: which mathematically can be written as: 2 * 0.05 * 56.5 = 5.65 kg
Therefore this moment of inertia to be added can be obtained using the formula shown in the image:
[tex]I_z=\frac{1}{12} \,m\,L^2\\\\I_z=\frac{5.65\,*\,1.5^2}{12} \\I_z=1.05937\,kg\,m^2[/tex]
Now, one needs to add this to the previous moment that you calculated, resulting in:
0.554 + 1.059 = 1.613 [tex]kg\,m^2[/tex]
Related Questions
A 23.7 kg kid slides down a
frictionless water slide at 47.2°.
What is her acceleration?
(Unit = m/s2)
Answers
Answer:
[tex]\text { The acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}[/tex]
Explanation:
Mass of the kid 23.7 kg.
[tex]\text { The kid is accelerating down at an angle is } 47.2^{\circ} .[/tex]
[tex]^{\prime \prime} \mathrm{g}^{\prime \prime} \text { acceleration due to gravity is } 9.8 \mathrm{m} / \mathrm{s}^{2}[/tex]
We need to find the acceleration of the kid,
We know that, Parallel force acted on the kid at an angle is
F = m × g × sinθ (F = ma)
m × a = m × g × sinθ
Now, substitute the given values in the above formula to find acceleration of the kid,
[tex]23.7 \times a=23.7 \times 9.8 \times \sin 47.2^{\circ}[/tex]
23.7 × a = 232.26 × 0.733
23.7 × a = 170.24
[tex]a=\frac{170.24}{23.7}[/tex]
[tex]a=7.18 \mathrm{m} / \mathrm{s}^{2}[/tex]
[tex]\text { Therefore, acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}[/tex]
An external torque is applied to a flywheel which is a solid cylinder of mass m = 100 kg and radius
R = 1.2 m with a magnitude τ = 450 N · m. What is the angular acceleration of the flywheel?
Answers
The angular acceleration is [tex]6.25 rad/s^2[/tex]
Explanation:
To solve this problem we can use the equivalent of Newton's second law for rotational motions:
[tex]\tau = I \alpha[/tex] (1)
where
[tex]\tau[/tex] is the torque acting on the body
I is the moment of inertia of the body
[tex]\alpha[/tex] is the angular acceleration
In this problem we have:
[tex]\tau = 450 Nm[/tex] is the torque
The moment of inertia of a solid cylinder about its axis is
[tex]I=\frac{1}{2}MR^2[/tex]
where
M = 100 kg is the mass
R = 1.2 m is the radius
Substituting,
[tex]I=\frac{1}{2}(100)(1.2)^2=72 kg m^2[/tex]
And solving eq.(1) for [tex]\alpha[/tex], we find the angular acceleration:
[tex]\alpha = \frac{\tau}{I}=\frac{450}{72}=6.25 rad/s^2[/tex]
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the volume of ice block is 2400cm^3 and its density is 0.9 g/cm^3. how much part of it remains above the surface of water when it is kept in water?
Answers
Answer:
240 cm³
Explanation:
Weight = Buoyancy
mg = ρVg
m = ρV
(0.9 g/cm³ × 2400 cm³) = (1 g/cm³) V
V = 2160 cm³
The submerged volume is 2160 cm³, so the volume above the surface is 240 cm³.
A 513 g ball strikes a wall at 12.1 m/s and
rebounds at 13.1 m/s. The ball is in contact
with the wall for 0.045 s.
What is the magnitude of the average force
acting on the ball during the collision?
Answer in units of N.
Answers
The average force on the ball is 287.3 N.
Explanation:
The impulse exerted on an object, which is equal to the product between the force exerted and the duration of the collision, is equal to the change in momentum of the object.
If we apply this to the ball, we can write:
[tex]F \Delta t = m(v-u)[/tex]
where
F is the force exerted on the ball
[tex]\Delta t = 0.045 s[/tex] is the duration of the collision
m = 513 g = 0.513 kg is the mass of the ball
u = 12.1 m/s is the initial velocity of the ball
v = -13.1 m/s is the final velocity (negative since the ball rebounds in the opposite direction)
And solving for F, we find:
[tex]F=\frac{m(v-u)}{\Delta t}=\frac{(0.513)(-13.1-12.1)}{0.045}=-287.3 N[/tex]
So, the magnitude of the average force is 287.3 N.
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differentiate between a cation and an anion.
Answers
Answer:
The positively charged ions are called cations and negatively charged ions are called anions.
Explanation:
When an atom releases an electron to form the nearest rare gas configuration, it forms a positive ion. Similarly, an atom receives an electron to form the nearest electronic configuration, it forms negative ions. The positive ions have an affinity towards the negative electrode and moves towards it. So it is called cations. The negative charge ions have an affinity towards the positive electrode and moves towards it. So, it is called anions. Hence, the positively charged ions are called cations and negatively charged ions are called anions.There are two objects with initial charge. Object A has 3 positive and 3 negative charges. Object B has 5 positive and 3 negative charges.
When the objects interact, which option indicates a possible net charge for each object?
Object A: +1 Object B: +1
Object A: +8 Object B: +6
Object A: –2 Object B: +2
Object A: +5 Object B: +3
Answers
Answer:
first option
Explanation:
we know the total amount of charges should be constant so
3 + (-3) + 5 + (-3) = 2
1 + 1 = 2 true
6 + 8 = 14 false
2 + (-2) = 0 false
5 + 3 = 8 false
Object A: +1 Object B: +1 indicates a possible net charge for each object.
ConceptCharge is the intrinsic property of protons and electrons. Charge is denoted by Q Positive charge are known as protonsNegative charge are known as electrons.Neutral charge are known as neutrons.How to solve the problem?The problem can be solved by following steps.
Object A has 3 positive and 3 negative charges (given)Object B has 5 positive and 3 negative charges (given)We need to indicate a possible net charge for each objectLet us , calculate the total charge
3+(-3)+5-3
=2
Hence, the net charge of Object A will be +1 and the net charge of Object B will be +1
Why other options are incorrect?Object A: +8 Object B: +6 is incorrect because the net charge is 8+6 =14
Object A: –2 Object B: +2 is incorrect because the net charge is -2+2=0
Object A: +5 Object B: +3 is incorrect because the net charge is 5+3=8
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SELECT TWO
The two methods used for determining mass are:
1 measuring directly on a scale
2 measuring directly on a balance
3 calculated by measurements of w and g
Answers
Question:
The two methods used for determining mass are: measuring directly on a scale measuring directly on a balance measuring directly by displacement of water calculated by measurements of w and g
Answer:
The two methods used for determining mass are measuring directly on a balance and measuring directly by displacement of water.
Explanation:
Mass is the actual content of the body, and when it is under some gravity, it becomes weight. But, mass cannot be calculated using any scale. It can be determined by using balance, as well as by a weight machine.
But, what is true here is that the mass of a body cannot be measured directly. It should be directly measured using water displacement. Because the displaced amount of water is equal to the volume of the objects.
If the airman had a mass of 80 kg, find the magnitude of the air drag acting on him when he reached terminal velocity of 54 m/s.
Answers
The magnitude of the air drag is 784 N
Explanation:
When the airman is falling down, there are two forces acting on him:
- The force of gravity, downward, of magnitude
[tex]F=mg[/tex]
where
m = 80 kg is the mass of the airman
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
- The air drag, upward, of magnitude [tex]F_D[/tex], whose value is proportional to the speed of the airman
At the beginning of the fall, the speed is zero, so the air drag is also zero and therefore the airman starts accelerating due to the presence of the force of gravity, which is unbalanced. However, as the airman falls down, he gains speed, so the magnitude of the air drag increases up to a point where it becomes equal to the magnitude of the force of gravity. When this occurs, the airman no longer accelerates and continues its motion at constant velocity, which is called terminal velocity.
Therefore, at terminal velocity, the air drag is equal to the force of gravity on the airman (the weight), so we can write:
[tex]F_D = mg = (80)(9.8)=784 N[/tex]
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The resistivity of glass is higher than that of wood. True False
Answers
Answer:True
Explanation:
Answer:true
Explanation:because the glass material is template and the wood is natural for SAE convention and normalitation have in chard that glass is more resistive than the wood
Three forces act on an object. If the object is moving to the right in translational equilibrium, which of the following must be true?
Answers
If an object is moving to the right in translational equilibrium, it means the sum of all the forces acting on the object is zero indicating a state of balanced forces. Translational equilibrium indicates the body is moving in a straight line at a constant speed or at rest. Equilibrium does not mean the absence of forces, but the balance of forces.
Explanation:When an object is moving to the right in translational equilibrium, it means it is in a state of steady motion, either at rest or moving at a constant velocity, with no acceleration. This equilibrium occurs when the sum of all the forces acting on the object is zero, indicating the forces are balanced. If we consider three forces acting on the object: F1, F2, and F3, for it to be in translational equilibrium, the vector sum of the three forces must be zero. This can be represented mathematically as: F1 + F2 + F3 = 0. If any of the forces change its magnitude or direction, it would disrupt the equilibrium status.
Translational equilibrium stands for a body moving in a straight line at a constant speed or being at rest, while rotational equilibrium refers to objects rotating at a constant rotation or being steady.
An important point to remember is that an equilibrium state does not necessarily mean the absence of forces but signifies that forces are equally balanced.
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Voltage differences cause charge to flow where
Answers
Voltage differences create an electric field that pushes free charges through a conductor, resulting in an electric current. This occurrence is explained by Ohm's Law, which states that current is directly proportional to the voltage applied to a conductor. Conventional current flows from the positive to the negative terminal although electrons, the actual charge carriers in metals, move in the opposite direction.
Explanation:Voltage differences are what drive an electric current in a conductor. When a voltage source such as a battery or a generator is connected to a conductor, it applies a potential difference that creates an electric field. This electric field exerts a force on free charges, causing them to move and create an electric current. In a material like a metal wire, the current is carried by the movement of electrons, which are negative charges moving from the negative terminal to the positive terminal. When discussing current flow, we often refer to the term "conventional current," which flows from the positive terminal to the negative terminal, even though the actual charge carriers (electrons) move in the opposite direction. This stems from historical convention initiated by Benjamin Franklin.
According to Ohm's Law, the current that flows through a substance is directly proportional to the voltage applied to it, which means that a higher voltage will generally result in a larger current, assuming the resistance of the material does not change. If charges accumulate at certain points, reducing the voltage there, the electric field will adjust to push the current toward areas with higher voltage. In static conditions, excess charges collect along the surface of a conductor until static equilibrium is reached.
What is the most likely effect on the life of a plant if a student cuts it’s flowers?
A. The plant can’t absorb more water.
B.The plant can’t produce food
C.The plant cannot support it’s self.
D.The plant cannot reproduce.
Please explain why you picked that answer. Ty
Answers
Answer:
D
Explanation:
The reproduction parts of the plant are in the flower and around it so this would eliminate the plants ablity to reproduce.
The reason a plant has a flower is for reproduction. The attractive smell and color of the flower attract pollinators. These pollinators eat nectar from the flower and get covered in pollen. They then transport the pollen to other flowers were the pollen is used by the other plant to produce seeds. The seeds are the way that the plant reproduces. Option A) doesn’t make sense because absorbing water is done by the roots. Option B) doesn’t make sense because that is done in the plants leaves. And C) doesn’t make sense because the plant supports itself using the stem. So the answer must be D)
A student sitting in a merry-go-round has an acceleration of 3.6 m/s2. If the tangential velocity of the student is 2.5 m/s, what is the distance of the student from the center of the merry-go-round?
Answers
Answer:
The distance of the student from the center of the merry-go-round is, r = 1.74 m
Explanation:
Given,
The acceleration of the student in merry go round, a = 3.6 m/s²
The tangential velocity of the student is, v = 2.5 m/s
The acceleration of the merry go round is given by the formula,
a = v² / r
Therefore,
r = v² / a
= 2.5² / 3.6
= 1.74 m
Hence, the distance of the student from the center of the merry-go-round is, r = 1.74 m
Predict using Boyle's law, what will happen to a balloon that an ocean diver takes to a pressure of 202 kPa.
Answers
The volume of the balloon will halve
Explanation:
Boyle's law states that for an ideal gas kept at constant temperature, the pressure of the gas is proportional to its volume. Mathematically,
[tex]pV=const.[/tex]
where
p is the gas pressure
V is the volume
The equation can also be rewritten as
[tex]p_1 V_1 = p_2 V_2[/tex]
And if we apply it to the gas inside the balloon in this problem (assuming its temperature is constant), we have:
[tex]p_1 = 101 kPa[/tex] is the initial pressure at sea level (the atmospheric pressure)
[tex]V_1[/tex] is the initial volume
[tex]p_2 = 202 kPa[/tex] is the final pressure
[tex]V_2[/tex] is the final volume
Substituting into the equation, we find:
[tex]V_2 = \frac{p_1 V_1}{p_2}=\frac{(101)V_1}{202}=\frac{V_1}{2}[/tex]
Which means that the volume of the balloon will halve.
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Two snowmobiles, Frosty and Snowflake, of equal masses suffer a rear-end collision. Just Before the collision, Frosty's velocity is 25 m/s east and Snowflake's velocity is 10 m/s in the same firection. Just after the collision, Frosty is moving 13m/s towards the east.
A. What is Snow flakes velocity immediately after the collision?
B. Was this an elastic collision? Justify your answer by calculation.
Please. I am sooo lost..
Answers
Answer:
A. 22 [tex]ms^{-1}[/tex]
B. NO
Explanation:
A.
During a collision , the net external force on the system is zero .
hence , the total momentum of the system can be CONSERVED .
let the mass of frosty and snowflake be m ;
initial velocity of frosty be [tex]v_{F_{i} }[/tex] = 25 [tex]ms^{-1}[/tex] final velocity of frosty be [tex]v_{F_{f} }[/tex] = 13 [tex]ms^{-1}[/tex]initial velocity of snowflake be [tex]v_{S_{i} }[/tex] = 10 [tex]ms^{-1}[/tex]final velocity of snowflake be [tex]v_{S_{f} }[/tex] = x [tex]ms^{-1}[/tex]therefore from principle of conservation of momentum ,
[tex]m*v_{F_{i} } + m*v_{S_{i} } = m*v_{F_{f} } + m*v_{S_{f} }[/tex]
so ,
[tex]m*25 + m*10 =m*13 +m*x[/tex]
[tex]x = 25+10-13 = 22 ms^{-1}[/tex]
answer for A. 22 [tex]ms^{-1}[/tex]
B.
The collision is NOT ELASTIC.
this is because if it had been elastic , the coefficient of restitution should have been 1 but it isnot i.e
[tex]e =\frac{ v_{F_{f} } - v_{S_{f} } }{ v_{S_{i} } - v_{F_{i} } } \\=\frac{13-22}{10-25} \\=\frac{9}{15} = \frac{3}{5} = 0.6[/tex] ≠ 1
thus it's an inelastic collision.
A 15 kg object starts for rest and is pushed across a frictionless surface e with a force of 30 N for 4 seconds
Calculate the final momentum
Answers
The final momentum is 120 kg m/s
Explanation:
According to the impuls theorem, the impulse exerted on an object (the product of force applied and time interval) is equal to its change in momentum. Mathematically:
[tex]F \Delta t = \Delta p = p_f - p_i[/tex]
where
F is the average force on the object
[tex]\Delta t[/tex] is the time interval during which the force is applied
[tex]p_f[/tex] is the final momentum
[tex]p_i[/tex] is the initial momentum
In this problem:
F = 30 N is the force applied
[tex]\Delta t = 4 s[/tex] is the time interval
[tex]p_i = 0[/tex] is the initial momentum, since the object starts from rest
Solving for [tex]p_f[/tex], we find the final momentum:
[tex]p_f = F\Delta t=(30)(4)=120 kg m/s[/tex]
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What is a watt a unit of?
power
distance
time
light
Answers
Answer:
I think the answer is A) Power
Explanation:
Answer:
The answer A. Power
Explanation:
Add the vector 12.0 cm at 45 degrees from the x axis to the vector 8.5 cm 105 degrees from the x axis.
Answers
Answer:
Magnitude 17.85 cm
Angle: 69.36 degrees
Explanation:
Analytical sum of vectors
We have the vector 1 with magnitude 12 cm and angle 45 degrees. We'll find its cartesian components by using
[tex]v1_x=12cos45^o=8.49\ cm[/tex]
[tex]v1_y=12sin45^o=8.49\ cm[/tex]
Now we find the components of v2
[tex]v2_x=8.5cos105^o=-2.2\ cm[/tex]
[tex]v2_y=8.5sin105^o=8.21\ cm[/tex]
To add both vectors, we add their components separately
[tex]\vec{v3}=\vec{v2}+\vec{v1}[/tex]
[tex]v3_x=v1_x+v2_x=8.49\ cm-2.2\ cm=6.29\ cm[/tex]
[tex]v3_y=v1_y+v2_y=8.49\ cm+8.21\ cm=16.7\ cm[/tex]
Magnitude of [tex]\vec{v3}[/tex]:
[tex]\left \| \vec{v3} \right \|=\sqrt{v3_x^2+v3_y^2}[/tex]
[tex]\left \| \vec{v3} \right \|=\sqrt{(6.29)^2+(16.7)^2}[/tex]
[tex]\left \| \vec{v3} \right \|=17.85\ cm[/tex]
Angle of [tex]\vec{v3}[/tex]:
[tex]\theta_3=atan\left ( \frac{16.7}{6.29} \right )=69.36^o[/tex]
Amaya ran around 3 times around a 1 mile track in 45 minutes, what was her average velocity for the trip?
Answers
Since Amaya ran around a 1 mile track 3 times we can multiply this to find the total distance she traveled (displacement).
3 x 1 = 3 miles traveled.
-----------
Formula: [tex]V_a_v_g~=~\frac{displacement}{change~in~time}[/tex]
-----------
In this question the variables are classified as:
Displacement = 3 miles
Change in Time = 45 minutes
-----------
Now, fill in the expression to solve.
[tex]V_a_v_g~=~\frac{45}{3}\\V_a_v_g~=~15~[/tex]
-----------
Amayas average velocity is 15 minutes per mile.
______
Best Regards,
Wolfyy :)
Average Velocity = (displacement) / (time)
Displacement = distance and direction between the start-point and end-point, no matter what happens in between.
Amaya ran around the track, so she ended in the same place she started. The distance between her start-point and end-point was zero. So . . .
Average Velocity = zero.
= = = = = = = = = =
Average Speed = (distance covered) / (time to cover the distance)
Amaya's distance = (1 mile/track) x (3 tracks) = 3 miles
Time to cover the distance = (3/4 hour)
Average speed = (3 miles) / (3/4 hour)
Average speed = (3 ÷ 3/4) mi/hr
Average speed = (3 x 4/3) mi/hr
Average speed = 4 miles per hour
What does the addition of two vectors give you?
A. A scalar
B. The direction of the vector.
C. A resultant vector
D. The magnitude of the vector
Apex answers needed
Answers
Answer: A resultant vector
Explanation: Addition of two vectors can not be a scalar because vectors have a magnitude and a direction. so that they are explained by means of these two chacteristics. If addition is different from zero it will give a vector.
Look at the graph.
Which is the formula to calculate the slope of this line?
A. mass minus volume
B. volume minus mass
C. mass divided by volume
D. volume divided by mass
Answers
Answer: C. Mass divided by volume
Explanation:
The slope of a line is equal to the rise over run meaning y over x. Mass is the y value and volume is the x value.
A block is pulled across a flat surface at a constant speed using a force of 50 newtons at an angle of 60 degrees above the horizontal. The magnitude of the friction force acting on the block is:
Answers
The magnitude of the friction force is 25 N
Explanation:
To solve this problem, we just have to analyze the forces acting on the block along the horizontal direction. We have:
The horizontal component of the pulling force, [tex]F cos \theta[/tex], where F = 50 N is the magnitude and [tex]\theta=60^{\circ}[/tex] is the angle between the direction of the force and the horizontal; this force acts in the forward directionThe force of friction, [tex]F_f[/tex], acting in the backward directionAccording to Newton's second law, the net force acting on the block in the horizontal direction must be equal to the product between the mass of the block and its acceleration:
[tex]\sum F_x = ma_x[/tex]
where
m is the mass of the block
[tex]a_x[/tex] is the horizontal acceleration
However, the block is moving at constant speed, so the acceleration is zero:
[tex]a_x = 0[/tex]
So the equation becomes
[tex]\sum F_x = 0[/tex] (1)
The net force here is given by
[tex]\sum F_x = F cos \theta - F_f[/tex] (2)
And so, by combining (1) and (2), we find the magnitude of the friction force:
[tex]F cos \theta - F_f = 0\\F_f = F cos \theta = (50)(cos 60^{\circ})=25 N[/tex]
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What is the period of oscillation of a mass 40kg on a spring with constant k=10N/m?
Answers
The period of oscillation of the system is 12.56 s
Explanation:
The period of oscillation of a spring-mass system is given by
[tex]T=2\pi \sqrt{\frac{m}{k}}[/tex]
where
m is the mass attached to the spring
k is the spring constant
For the system in this problem, we have
m = 40 kg
k = 10 N/m
Substituting into the equation, we find
[tex]T=2\pi \sqrt{\frac{40}{10}}=12.56 s[/tex]
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a steeper incline plane will require _____ Force
Answers
Answer:
wind
Explanation:
A steeper incline plane will require more force to move an object up. This is because the component of the gravitational force acting parallel to the incline increases with the steepness, necessitating a greater force to oppose it. The force required to move objects up an incline plane, therefore, increases with the steepness of the incline.
Explanation:When analyzing an object at rest on an inclined plane, the force of gravity acting on the object is divided into two crucial components - a force acting perpendicular to the plane and a force acting parallel to the plane. The perpendicular force of weight is typically equal in magnitude, but opposite in direction to the normal force. However, the force that impacts the effort needed to move an object up an incline directly is the component of force acting parallel to the plane.
As the slope of an incline plane gets steeper, this parallel component of the gravitational force increases, and it requires more force to oppose this component and move the object up the incline. Therefore, a steeper incline plane will require more force to move an object up.
In simpler terms, think of it as pushing a cart up a steep hill versus a gentle slope - the steeper hill requires more effort, or force, to push the cart up.
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Investigators are working on a case where they need to know whether a watch will stop when it is dropped. In order to have a verified or reliable answer to this question, what should they do?
Call the manufacturer to ask whether it will stop under these circumstances
Drop a similar watch multiple times and record the results
Consult with more senior forensic scientists for their experiences
Take the watch apart and test the mechanism to see what causes failure
Answers
In order to have a verified or reliable answer to this question, they should take the watch apart and test the mechanism to see what causes failure.
Answer: Option D
Explanation:
For dropping a similar watch to record results, we need to buy another one. So, it becomes expensive. And, calling the manufacturer will give accurate results, but no knowledge. It is like getting multiple choices by luck.
Consulting senior faculty won’t result in any progress, because they may not have conducted these. So, one should rip off the watch, and study the mechanism, and its limitations. The testing of mechanism gives the actual results.
Answer: B) Drop a similar watch multiple times and record the results.
Explanation:
In order to have a verified or reliable answer to this question, investigators must drop a similar watch multiple times and record the results. By doing this and repeatedly getting the same result(s), they are able to determine that their answer is in fact true.
*** I would also like to note that I got this question right on a test. Cheers!
Questions to consider:
1. If the skater has a mass of 60 kg, what is her gravitational potential energy at the top of the 4 m high
half-pipe?
Answers
Answer: 2352 J
Explanation:
A body's gravitational potential energy [tex]U[/tex] depends on its position and is mathematically expressed as follows:
[tex]U=mgh[/tex]
Where:
[tex]m=60 kg[/tex] is the mass of the skater
[tex]g=9.8 m/s^{2}[/tex] is the acceleration due gravity
[tex]h=4 m[/tex] is the skater's current height
Solving:
[tex]U=(60 kg)(9.8 m/s^{2})(4 m)[/tex]
[tex]U=2352 J[/tex]
Object A and Object B are 100 meters apart. If Object A gains some
mass, how does that affect the gravitational force between the two objects?
O A) It increases.
OB) It decreases.
OC) It remains the same.
Answers
The gravitational force between the two objects A) It increases.
Explanation:
The gravitational force between two objects is given by:
[tex]F=G\frac{m_1 m_2}{r^2}[/tex] (1)
where
G is the gravitational constant
[tex]m_1, m_2[/tex] are the masses of the two objects
r is the separation between the objects
In this problem, object A and object B are initially at a distance of
r = 100 m
And at that distance, the force between them is
F
Later, object A gains some mass. We notice from eq.(1) that the gravitational force is directly proportional to the mass: therefore, if the mass of either of the two objects increases, then the gravitational force between them also increases. Therefore, the new force will be larger than the original force:
F' > F
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wave is traveling at 60 cm/second and has a wavelength of 15 cm, what is the frequency?
Answers
The frequency of the wave is 4 Hz
Explanation:
The relationship between wave, frequency and speed of a wave is given by the equation:
[tex]v=f \lambda[/tex]
where
v is the speed of the wave
f is the frequency
[tex]\lambda[/tex] is the wavelength
For the wave in this problem, we have:
[tex]v=60 cm/s[/tex] is the speed
[tex]\lambda=15 cm[/tex] is the wavelength
Solving the equation for f, we find its frequency:
[tex]f=\frac{v}{\lambda}=\frac{60 cm/s}{15 s}=4 s^{-1} = 4 Hz[/tex]
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A 388 Hz tuning fork is resonating in a closed tube on a warm day when the speed of sound is 346 m/s. What is the length of the closed tube?
A. 0.89m
B. 1.12 m
C. 0.28m
d. 0.22m
Please help!
Answers
Answer:
A
Explanation:
because u are subtracting if this is from flvs that is what i did and it was right
Answer:
A 0.89m
Explanation:
V= fλ
λ= V/f
λ=346/358
λ=0.89m
Describe three machines that humans have designed and explain how the mechanical advantage is used.
Answers
Answer:
A windmill. Windmills are used to harness the wind through the motion of the windmills wheels spinning. Usually, windmills are used to grind grain or pump water but now with a more modern version called the wind turbine, we can use the wind to generate energy.
Explanation:
this is one example you could use remember to change it up! :)
Three examples of machines that humans have designed are the lever, pulley, and wheel and axle. They all take advantage of mechanical advantage to reduce the input force needed by spreading the force over a greater distance.
Explanation:The first machine we can consider is the lever. A lever is a simple machine that provides a mechanical advantage by increasing the distance over which an input force is applied, hence, reducing the input force needed to accomplish the same amount of work. Consider a seesaw; when one side is pushed down with a certain force, the other side goes up.
Another machine is the pulley. It reduces the effort required to lift an object by spreading the work over a longer length of rope. For example, a pulley system used in construction cranes makes it easier to lift heavy loads.
The third machine is the wheel and axle. It gives a mechanical advantage by allowing the user to exert force over a greater distance. An example of this is the use of wheel and axles in bicycles; pedaling covers a long distance but requires less force.
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