Help Please!! An object is dropped from a height h meters. From the time the object is h/2 meters above the ground, it takes 1 second until the object strikes the ground. From what height was the object dropped?

                Option-A " The intermolecular forces holding the caffeine molecules together are weaker than the ionic bonds in CuCl₂ ".

                         There are two types of interactions among the atoms and molecules. One are known as intramolecular forces while the other are known as intermolecular forces.

Examples of Intramolecular forces are ionic bonds and covalent bonds e.t.c. while examples of intermolecular forces are hydrogen bond interactions, dipole-dipole interactions e.t.c.

Remember that intramolecular forces ar far more greater in strength than the intermolecular forces. Hence, in given statement the interactions between Caffeine molecules are intermolecular forces while, that between Cu and Cl ions in CuCl₂ are intramolecular forces.

Final answer:

The lower melting point of caffeine compared to copper (II) chloride is due to the weaker intermolecular forces in caffeine as opposed to the stronger ionic bonds in CuCl2.

Explanation:

The most important reason caffeine (C8H10N4O2) has a lower melting point than copper (II) chloride (CuCl2) is that the intermolecular forces holding the caffeine molecules together are weaker than the ionic bonds in CuCl2. Option A correctly identifies that caffeine, being a covalent molecular compound, is held together by intermolecular forces which are generally less strong than the ionic bonds found in ionic compounds like CuCl2.

This is due to the fact that ionic bonds result from the electrostatic attraction between ions of opposite charge, which is a significantly stronger force than that of the intermolecular forces present in molecular compounds like caffeine.

As we know that sphere roll without slipping so there is no loss of energy in this case

so here we can say that total energy is conserved

Initial Kinetic energy + initial potential energy = final kinetic energy + final potential energy

[tex]\frac{1}{2}mv_i^2 + mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2+ mgh'[/tex]

as we know that ball start from rest

[tex]v_i = 0[/tex]

height of the ball initially is given as

[tex]h = Lsin\theta[/tex]

[tex]h = 1200sin53 = 960 cm[/tex]

also we know that

[tex]I = \frac{2}{5}mR^2[/tex]

also for pure rolling

[tex]v = r\omega[/tex]

also we know that

[tex]480 = m*9.8 [/tex]

[tex]m = 49 kg[/tex]

now plug in all data in above equation

[tex]480*9.60 + 0 = \frac{1}{2}*49*(0.40*\omega)^2 + \frac{1}{2}*\frac{2}{5}*49*(0.40)^2\omega^2 + 0[/tex]

[tex]4608 = 3.92\omega^2 + 1.568\omega^2[/tex]

[tex]\omega^2 = 839.65[/tex]

[tex]\omega = 29 rad/s[/tex]

So speed at the bottom of the inclined plane will be 29 rad/s

Of the following given choices;

The answer is; gravitational.

When the delivery man pushes the doorbell, he is utilizing mechanical energy. This energy is later converted to electrical energy that travels through a circuit to the inside of the house. An actuator then converts the electrical energy to sound that is heard inside the house.

Answer:

55 miles per hour

Explanation:

Given

Distance d = 55 miles

t_o =1.00 pm

t_f = 2.00 pm

Solution

Duration of the trip

[tex]\Delta t = t_f - t_o\\\\\Delta t = 2.00 pm - 1.00 pm\\\\\Delta t = 1 hour[/tex]

Average velocity

[tex]v = \frac{d}{\Delta t} \\\\v = \frac{55}{1} \\\\v = 55 mph[/tex]

Answer:

C. 6.14 m

Explanation:

The maximum horizontal distance travelled by a projectile is given by:

[tex]d=\frac{v^2}{g}sin (2\theta)[/tex]

where

v is the initial velocity

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

[tex]\theta[/tex] is the angle of launch

From the equation, we see that the maximum range is achieved when the projectile is fired at [tex]\theta=45^{\circ}[/tex].

The dart in the problem has an initial velocity of

v = 7.76 m/s

Substituting into the formula, we find the maximum horizontal distance:

[tex]d=\frac{7.76^2}{9.8}sin (2\cdot 45^{\circ}) = 6.14 m[/tex]

When you are on a swing, and at the lowest point of your motion, is your apparent weight greater than to your true weight.

In general, an object's apparent weight is equal to its mass multiplied by the vector difference between gravitational acceleration and the object's acceleration.

According to this definition, apparent weight is a vector that can act in any direction, not just vertically.

The weight of an object is how gravity pulls on it, but apparent weight is a measure of downward force. Weight, on the other hand, is a measure of the force exerted by gravity.

We can pretend you're in a uniform circular motion at the bottom of the swing trajectory, so the net force points toward the center of the circle.

As a result, the swing must exert a greater force on you than the earth does in the opposite direction. As a result, your apparent weight is greater than your true weight.

Thus, the true weight will be less than the apparent weight.

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Answer:

acceleration = 0.12 m/s^2  

Explanation:

Using Second Law of Motion,

F = m*a

μ = f/Fn

Fn = m*g – 90*sin(30)

Fn = (20)*(9.81) – 90*sin(30)

Fn = 151.2 N

f = μ*Fn

f = (0.5)*(151.2)

f = 75.6 N

F = 90cos(30) – 75.6

F = 2.34 N

a = F/m

a = 2.34/20  

a = 0.12 m/s^2  

Answer:

It's option d - Negative acceleration

Explanation:

Mathematically position X , velocity V and acceleration A are:

[tex] \frac{dX}{dt} = V [/tex] and [tex] \frac{dV}{dt} = A [/tex]

Where X, V, A are vectors and [tex] \frac{d(a)}{dt} = b [/tex]  indicates the derivate a of a time is equal to b.

So, this show that acceleration is a rate respect of time of velocity ⇒ When acceleration is positive, velocity increments, when acceleration is negative, velocity decrements.

The above explanation correspond to the motion map shown, getting demonstrated that the answer is D - Negative acceleration

The answer is:

Let say the basket ball is tossed upwards with initial speed "v"

now when it moves up in the air its speed will decrease due to acceleration of gravity in opposite direction

So here we can say that its final speed at the top position will be zero

here it will take t = 2.5 s to reach the top

now we can use equation of kinematics

[tex]v_f = v_i + at[/tex]

[tex]0 = v + (-9.8)*2.5[/tex]

now we have

[tex]v = 9.8 * 2.5[/tex]

[tex]v = 24.5 m/s[/tex]

so the ball is tossed up initially with speed 24.5 m/s

Answer:

Mass of the gold bar is 90.71 gram.

Explanation:

Given:

volume = 4.7 [tex]cm^{3}[/tex]

density = 19.3 [tex]\frac{g}{cm^{3}}[/tex]

To find:

mass = ?

Formula used:

density = [tex]\frac{mass}{volume}[/tex]

Solution:

density is given by,

density = [tex]\frac{mass}{volume}[/tex]

mass = volume × density

mass = 4.7 × 19.3

mass = 90.71 g

Mass of the gold bar is 90.71 gram.

1. Meter Rule  

Meter rule is used to measure the small length or distance between any two points.

2. Measuring Tape

It is also use to measure length and distance in meters and centimeters.

3. Vernier calipers.

It can be use to measure small diameter or radius of objects up-to 10th part of a millimeter.

4. Micrometer screw gauge.

It is also use to measure diameter or radius unto 100th part of a millimeter.

5.Beam balance

It is use to measure mass upto 10th part of a gram.

6. Physical balance

it is use to measure mass upto 100th part of a gram.

7.Electronic balance

It is use to measure mass upto 100th part of a gram.

8. Stop watch.

It is use to measure time upto 10th and 100th part of a second.

9.Measuring cylinder

It is use to measure volume of a small object.

10. Hydrometer

It is use to measure density of liquids.

11. Barometer.

It is use to measure the atmospheric pressure.

12. Thermometer

It is use to measure temperature.

13. Ammeter

It is used to measure amount of electric current in circuit.

14.Photometer.

It is use to measure intensity of light.

15. Protector,.

It can be use to measure angle.

16. Lactometer.

It can be use to measure specific gravity of milk.

If both nuggets have the same mass and different densities then it can be concluded that the volume with the highest density is smaller.

For, so to speak, density is a relation of how much mass is there in a given volume. So the more the mass and the smaller the volume, the greater the density.

To verify this, let us calculate the volumes of iron pyrite and gold pyrite.

For the iron pyrite nugget:

density = mass / volume

volume = mass / density

volume = 50/5

volume = 10cm3

For the gold nugget:

volume = mass / density

volume = 50 / 19.3

volume = 2.59cm3

Therefore it is found that the nugget with the highest density (gold) is the one with the lowest volume.

Answer:

Velocity of the eagle = 7.08 m/s

Explanation:

  We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

  Vertical motion of fish:

      Initial velocity = 0 m/s , acceleration = acceleration due to gravity = [tex]9.8m/s^2[/tex], displacement = 6.1 m we need to find time.

     [tex]6.1= 0*t+\frac{1}{2} *9.8*t^2\\ \\ 4.9t^2=6.1\\ \\ t=1.116 seconds[/tex]

 Horizontal motion of fish:

      Acceleration = acceleration due to gravity = [tex]0m/s^2[/tex], displacement = 7.9 m , time = 1.116 seconds we need to find Initial velocity (u).

      [tex]7.9= u*1.116+\frac{1}{2} *0*1.116^2\\ \\ u=7.08m/s[/tex]

    So, velocity of the eagle = 7.08 m/s

Answer:

7.1

Explanation:

did endgenuity, said it's correct

(explanation above is correct, also)

Einstein's energy mass equivalence relation say that if the whole given mass is converted to energy then it would be

[tex]E = mc^2[/tex]

where

m = mass in kg

c = speed of light in m/s

this is the origination of quantum physics and by this formula we can relate the dual nature of light and particle

So correct relation above will be

[tex]E = mc^2[/tex]

the answer is B i just took it

Here it is given that speed of migrating Robin is 12 m/s relative to air

so we can say that

[tex]\vec v_{ra} = 12 m/s[/tex] North

so it will be

Let North direction is along Y axis and East direction is along X axis

[tex]\vec v_{ra} = 12\hat j[/tex]

also it is given that speed of air is 6.7 m/s relative to ground

[tex]\vec v_a = 6.7 \hat i[/tex]

now as we know by the concept of relative motion

[tex]\vec v_{ab} = \vec v_a - \vec v_b[/tex]

[tex]\vec v_{ra} = \vec v_r  - \vec v_a[/tex]

now by rearranging the terms

[tex]\vec v_r = \vec v_{ra} + \vec v_a[/tex]

[tex]\vec v_r = 12 \hat j + 6.7 \hat i[/tex]

now we need to find the speed of Robin which means we need to find the magnitude of its velocity which we found above

So here we will say

[tex]v_r = \sqrt{12^2 + 6.7^2}[/tex]

[tex]v_r = 13.7 m/s[/tex]

so the net speed of Robin with respect to ground will be 13.7 m/s

7.  First write down all the known variables while separating the values for each direction:

x-direction:

vix = 20m/s

vfx = 20m/s

x = 39.2m

y-direction:

viy = 0m/s

ay = -9.8m/s^2

y = ?

Based on the knowns, the first step is to calculate the time of flight from the x-direction as it will be the same as value for the y-direction.  Find the correct kinematic equation to do so:

x = (1/2)(vix+vfx)t

(39.2) = (1/2)(20+20)t

1.96s = t

Now that we have the time of flight, we can use the kinematic equation that will relate the known variables in the y-direction:

y = viy*t + (1/2)ay*t^2

y = (0)(1.96) + (1/2)(-9.8)(1.96)^2

y = -18.82m  (Value is negative because gravity constant was negative.  It is the height reference that from the top of the building down, which is why it is negative.  The sign can be ignored for this question.)

8.  First write down all the known variables while separating the values for each direction:

x-direction:

x = 12m

vfx = 0m/s

vix = ?

y-direction:

y1 = 1.2m

y2 = 0.6m

viy = 0m/s;

ay = -9.8m/s^2

First find time in the y-direction as it would be the same value for the x-direction.

(y2 - y1) = viy*t + (1/2)ay*t^2

(-0.6) = (0)t + (1/2)(-9.8)t^2

t = 0.35s

Now that we have the time of flight, we can use the kinematic equation that will relate the known variables in the x-direction:

x = (1/2)(vix+vfx)t

(12) = (1/2)(vix+(0))(0.35)

68.6m/s = vix

a)

F = net braking force acting on jetliner = - 7.25 x 10⁵ N    (the negative sign indicates that the braking force acts to slow down the motion.)

m = mass of the jetliner =  3.50 x 10⁵ N

a = acceleration of the jetliner

acceleration of the jetliner is given as

a = F/m

a = (- 7.25 x 10⁵)/(3.50 x 10⁵)

a = - 2.1 m/s²

t = time interval = 10 s

v₀ = initial velocity of jetliner = 75 m/s

v = final velocity after time "t" = ?

Using the kinematics equation

v = v₀ + at

v = 75 + (- 2.1) (10)

v = 54 m/s

b)

x  = distance traveled in time "t"

using the kinematics equation

x = v₀ t + (0.5) at²

inserting the values

x = (75) (10) + (0.5) (- 2.1) (10)²

x = 645 m

This Physics question relates to Newton's second law of motion and the principles of linear motion. By utilizing the given data and appropriate formulas, we can find the final speed of the plane after 10 seconds and the distance traveled during this time.

This question is related to Newton's second law of motion which states that force is equal to mass times acceleration. Given the mass (m) of the airplane as 3.50*10^5 kg, the braking force (F) as 7.25*10^5N and the initial speed (u) as 75.0 m/s, we can find acceleration (a) by using the formula: F=ma, thus a=F/m. The negative sign indicates that the plane is slowing down.

(a) To find the final speed (v) of the airplane after 10.0 sec, you use the formula v = u + at. Here, t is 10.0 sec. Substituting the values, we determine the final speed.

(b) The distance travelled can be found using the formula: s = ut + 0.5at^2. We know all the values so we can substitute them in to find the distance. Thus, by substitifying we get the distance traveled during this time period.

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Answer:

B. Water and sugar.

Explanation:

In the given options water and sugar would be the poor conductor of electricity. Other given options such as water and salt, water and Hcl and water and NaOH are better conductor of electricity because Hcl ,NaOH, salt (Nacl) can break into their ionic form whereas water and sugar will not.

Answer: B Water and Sugar

Explanation: I checked and I had the question

Hello!

To answer this question we need to understand what Newton's Second and Third Laws of Motion are!

Second Law- States the accerlation of an object is dependent on two variables, the net force acting upon the object and the mass of the object.

Third Law- States that for ever action, there is an eual and opposite reaction.

The second law is important to our everyday life, because when you try to push something, it's easier for us to push it with a lighter mass. For example pushing an empty box is easier than pushing a full one. Same principal goes for a lot things in our daily life.

The third law is important to our everyday life, because action-reaction pairs affect everything in our life. One of the best examples of this can be see in human body movements!

Hope this helps you with your question.

The correct answer is average speed.

Since we are referring to distance expressed over time taken we are referring to average speed.

If it is displacement expressed over time taken, then we get the average velocity.

Also the velocity expressed over time will give us average acceleration.

Note that distance is a scalar quantity so it goes with another scalar quantity which is speed.

The displacement which is also a vector quantity will go with velocity which is also a vector quantity.

The correct option is B. Which is average speed.

Answer and explanation;

According to twin studies attitudes may be genetically based, research has supported that Identical twins are more likely to share similar attitudes. Attitudes change as the result of behavior and not the other way around

Genetic factors may influence general dispositions and condition-ability that may influence formation of more specific attitudes. Controlled twin studies in US and Sweden reveal that identical twins share more similar attitudes than fraternal twins.

The average atomic mass of an element is the mass found on the periodic table under the element symbol.  It is called the average atomic mass because it is actually a calculated sum of the masses of the element's isotopes (same element with different number of neutrons), each multiplied by their natural abundances.

The average atomic mess of an element is the sum of masses of its isotopes, each multiplied by its natural abundance .

gravitational potential energy is given as

[tex]PE = mgH[/tex]

here given that

m = 75 kg

g = 9.8

H = 100 m

now plug in all value above

[tex]PE = 75 * 9.8* 100[/tex]

[tex]PE = 73500 J[/tex]

now for kinetic energy we can use

[tex]K = \frac{1}{2}mv^2[/tex]

here we have

m = 75 kg

v = 60 m/s

now we have

[tex]K = \frac{1}{2}*75*60^2[/tex]

[tex]K = 135000 J[/tex]

now for mechanical energy we have

[tex]ME = KE + PE[/tex]

so now we will add above to energy to find mechanical energy

[tex]ME = 73500 + 135000 [/tex]

[tex]ME = 208500 J[/tex]

 Vi =0  ( as car starts from rest )

Acceleration= a = 5m/s²

t =12sec

Vf =Vi + at

Vf= 0 + (5m/s²) (12s)

Vf=60 m/s

Seagull is at height 11 m

it drops a shell from rest

so here we know that

acceleration of shell is due to free fall = -9.81 m/s^2

displacement = - 11 m

initial speed = 0

now we will use kinematics equation here in order to find the final speed

[tex]v_f^2 = vi^2 + 2as[/tex]

now plug in all values in it

[tex]v_f^2 = 0 + 2*(-9.81)*(-11)[/tex]

[tex]v_f^2 = 215.82[/tex]

[tex]v_f = 14.7 m/s[/tex]

so here the speed by which shell will strike with the rocks is 14.7 m/s

Final answer:

The velocity of a shell dropped from rest at a height of 11m when it hits the ground is approximately 14.69 m/s. This is calculated using the kinematic equation for uniformly accelerated motion, considering gravity as the acceleration.

Explanation:

The question refers to the velocity of a shell dropped by a seagull from a specific height until it hits the ground. To solve this, we can use the equations of motion under gravity. Specifically, we can use the following equation, which comes from the kinematic equations for uniformly accelerated motion:

v² = u² + 2as

v represents the final velocity

u is the initial velocity (which is 0 in this case, since the shell is dropped from rest)

a is the acceleration due to gravity (approximately 9.81 m/s² on Earth)

s is the distance the object has fallen, in this case, 11 meters

Plugging the numbers into the equation gives us:

v² = 0⁻ + 2*9.81*11

v² = 215.82

v = √(215.82)

v = 14.69 m/s (to two decimal places)

Therefore, the velocity of the shell when it hits the rocks will be approximately 14.69 m/s.

I should assume the answer would be C, to determine the affects of sunlight on plant growth. In the above paragraph, everything else in the experiment was the same, and the only variable was the amount of sunlight reaching each plant. Hope this helped!

This procedure will demonstrate the effect of sunlight on plant growth.  If that wasn't the purpose that James had in mind, then he picked the wrong experiment.

Angle made by the light ray with the surface of mirror is given as

[tex]\theta_i = 90 - 20 = 70 [/tex]degree

now as we know as per law of reflection that

angle of incidence = angle of reflection

So here we can say that

[tex]\theta_i = \theta_r[/tex]

[tex]\theta_r = 70 degree[/tex]

now the total angle that reflected ray will rotate with respect to incident ray is known as angle of deviation

[tex]\delta =180 - \theta_i - \theta_r[/tex]

[tex]\delta = 180 - 70 - 70 = 40 degree[/tex]

so here reflected light will deviate by total angle of 40 degree fron its incident ray.