Answer:
The procedure by which soil, land, or rock get slowly worn away by the natural elements like wind or water is known as erosion. The landforms refer to the natural characteristics found on the surface of the Earth that exhibit different shape and origin. The landforms can be destroyed and created by erosion.
The landforms created by the process of erosion are known as fluvial erosion landforms. With the passing of water across the land, the sediments and other kinds of natural debris also get carried with it. With time, the gathering of the debris and sediments generate deposits that ultimately turn into a landform. Some of the examples of fluvial erosion landforms comprise flood plains, sandbars, and levees.
Which of the following gases will have the highest velocity at a given temperature? (3 points)
A .Ne
B. O2
C .He
D. Cl2
Answer:
Option-(C)-Helium, He is the most lightest among the given four elements. As the molecular mass of helium,He is about 4.002602 u. It is considered the second most lightest element inside the periodic table after the hydrogen,H atom which is the lightest of all.
Explanation:
Velocity dependence upon the molecular weight of the element:The molecular weight of the different elements gives them the very specific features including the ability to travel fast in a given space. While the helium,He is considered one of the lightest elements in the universe so, it has a greater velocity among the four options.
For example:A person with less weight will run much faster as compared to a person having more weight.
Consider a certain type of nucleus that has a half-life of 32 min. calculate the percent of original sample of nuclides remaining after 1.9 hours have passed
To calculate the percent of nuclides remaining after 1.9 hours, given a half-life of 32 minutes, we find that about 3.56 half-lives have passed and approximately 9.09% of the original sample remains.
Explanation:The question concerns the calculation of the remaining nuclides in a sample after a period of time, given the half-life of the substance. If the half-life of a certain type of nucleus is 32 minutes, we first need to calculate how many half-lives are in 1.9 hours. Since there are 60 minutes in an hour, 1.9 hours equals 114 minutes. Dividing 114 minutes by the half-life of 32 minutes gives us approximately 3.56 half-lives.
After each half-life, the amount of a radioactive material will halve. To find the remaining percent, we use the formula:
Percent Remaining = (1/2)number of half-lives passedTherefore, for 3.56 half-lives passed, the calculation is as follows:
Percent Remaining = (1/2)3.56Punching this into a calculator, we find that about 9.09% of the original sample remains after 1.9 hours have passed.
What is the change in atomic mass when an atom emits an alpha particle? A. decreases by 2 B. decreases by 1 C. decreases by 4 D. remains the same
Write a balanced equation to show the reaction of gaseous ethane,c2h6 with gaseous oxygen to form carbon monoxide gas,co, and water vapor
Answer: The balanced chemical equation is written below.
Explanation:
Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.
If supply of oxygen gas is limited, it is known as incomplete combustion and carbon monoxide gas is also produced as a product.
The chemical equation for this reaction of ethene and oxygen gas follows:
[tex]2C_2H_6+5O_2\rightarrow 4CO+6H_2O[/tex]
By Stoichiometry of the reaction:
2 moles of ethene gas reacts with 5 moles of oxygen gas to produce 4 moles of carbon monoxide gas and 6 moles of water vapor.
Hence, the balanced chemical equation is written above.
How does the atmospheric pressure at altitudes below sea level compare
What is the consequence of deforestation?
Answer:
The consequence of deforestation is discussed below.
Explanation:
One of the outcomes of deforestation is a waste of biodiversity. Deforestation also improves greenhouse gas discharges, disturbs the water series, improves soil erosion and reduces the physical attraction of a region.deforestation causes the Decline of nutrients in the clay that are obtained from the categorization of tree petals.Iodine-131 decays with a half-life of 8.02
d. in a sample initially containing 5.00 mg of 131i, what mass remains after 6.01 d
The question is about the decay of radioactive isotope Iodine-131 over time, using the concept of half-life. It's calculated that after 6.01 days, approximately 3.18mg of the initial 5.00mg of Iodine-131 remains.
Explanation:The question is about the decay of the Iodine-131 isotope, a nuclear physics concept, using the half-life theory. The half-life is the time it takes for half of a radioactive substance to decay. In this case, the half-life of Iodine-131 is 8.02 days. After 6.01 days, the question asks how much of an initial 5.00 mg sample remains.
First, we need to determine how many half-lives have passed during the 6.01 days. We can calculate this by dividing the overall time elapsed by the half-life of the isotope (6.01 / 8.02). This gives us approximately 0.75 half-lives.
Now, for each half-life, the substance will halve in quantity. So, we can calculate the remaining mass by multiplying the initial mass by (0.5) raised to the power of the number of half-lives (0.75). So, (5.00 mg) * (0.5)^0.75 = 3.18 mg.
So, after 6.01 days, approximately 3.18 mg of the original Iodine-131 remains.
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To calculate the remaining mass of iodine-131 after 6.01 days with a half-life of 8.02 days, use the decay formula. For an initial 5.00 mg sample, approximately 2.58 mg of iodine-131 would remain after 6.01 days.
Iodine-131 decays with a half-life of 8.02 days. To calculate the mass remaining after 6.01 days, we use the formula: Final mass = Initial mass x (1/2)^(time elapsed/half-life).
Given an initial mass of 5.00 mg of 131I and a decay time of 6.01 days, the mass remaining can be calculated as follows:
Final mass = 5.00 mg x (1/2)^(6.01/8.02)Final mass = 5.00 mg x (1/2)^(0.7494)Final mass = 5.00 mg x 0.5158 = 2.58 mgWhat is the noble gas configuration for silicon? [Ne] 3s2 3p1 [Ar] 4s1 [Kr] 5s1 [Ne] 3s2 3p2
Answer: The noble gas notation for silicon atom is [tex][Ne]3s^23p^2[/tex]
Explanation:
Noble gas notation is defined as the notation in which the configuration of an atom is written in terms of previous noble gas.
Silicon is the 14th element of the periodic table having 14 electrons.
The nearest noble gas to this element is neon.
So, the noble gas notation for silicon atom = [tex][Ne]3s^23p^2[/tex]
A) how many hydrogen atoms are in an acyclic alkane with 15 carbon atoms?
Choose all the answers that apply. The sun: heats the earth evenly;can acclerate the water cycle;is closer to the earth during the summer;is the perfect distance from earth;causes surface waves
Answer:
Heats the earth evenly;can acclerate the water cycle;is the perfect distance from earth.Explanation:
Radiation is the most important process of heat propagation, because it is through it that the heat of the sun reaches the earth. Without this process there would be no life on earth. While conduction and convection occur only in material media, radiation also occurs in a vacuum, so it is possible for the sun to heat the earth evenly.
The heat radiated by the sun heats the water of rivers, lakes, seas and oceans occurring the phenomenon of evaporation during the water cycle. At this point, the liquid state of water changes to its gaseous state as it moves from the earth's surface to the atmosphere. For this reason we can say that the sun can accelerate the water cycle.
Although the Earth's orbit around the Sun is an ellipse, not a circle, the distance from Earth to the Sun varies by only 3%, with the Earth being closest to the Sun from January 4-7 each year, depending on leap year. But it's easy to remember that the northern hemisphere of the earth is also closer to the sun in January and it's winter there, while it's summer in the southern hemisphere. So we cannot say that the earth is closer to the sun in summer, but between January 4th and 7th.
Living conditions on earth are a puzzle to astronomy. A little closer to the sun - and we'd be a greenhouse and toxic high-pressure gas plant like Venus. A little farther - and the gases would escape, the water would freeze, there would be at most microbes, as on Mars. The earth is the perfect distance to house water, oxygen, carbon and complex life forms.
Surface Waves are seismic waves that propagate to the Earth's surface and result from interference between P waves and S waves (called volumetric waves). It is to the surface waves that are due to the great destruction caused by the earthquakes. The sun does not interfere with the creation of these waves, which is a factor caused by the movement of the earth and other geological terms.
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Explain how a change in thermal energy causes matter to change From one state to another.Give two examples
When potassium-40 undergoes decay by electron capture the product is?
Identify the three ingredients used in a blast furnace to make pig iron.
The three ingredients used in a blast furnace to make pig iron are roasted ore, coke, and limestone.
Explanation:In a blast furnace, the three ingredients used to make pig iron are:
Roasted Ore: The iron ore is heated in air to remove water and convert sulfides into oxides.Coke: This is a fuel made by heating coal in the absence of air. It provides the high temperature required for the reduction reactions.Limestone: Impure calcium carbonate (CaCO3) is added to remove impurities and form s_lag.The combination of these three ingredients undergoes various reactions in different temperature zones of the blast furnace, resulting in the production of molten iron and s_lag.
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When atoms of two or more different elements bond, their properties ___________.
A. are the same as the largest atom in the compound
B. change
C. combine
D. None of these
When atoms of two or more different elements bond, their properties change.
What is the difference between molecules and compounds?When two or more atoms of the same element chemically combine, a molecule is created.
Examples: O₂, O₃, H₂
A compound is a type of molecule in which the atom types that make up the molecule differ from one another.
Examples: NaCl, H₂O
Properties of compound:Only chemical breakdown can separate compounds.Different atoms of elements are present in a defined ratio.Learn more about molecules and compounds here:
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The process by which complex compounds are decomposed by living systems is called
fermentation
distillation
oxidation
reduction
What is the rate of a reaction if the value of k is 0.01, [A] is 2 M, and [B] is 3 M? Rate = k[A]3[B]2
Our good friend and pseudo scientist, homer simpson, attempts to analyze 300 mg of an unknown compound containing only c and h by burning it in excess oxygen. 540 mg of h2o is produced. you may assume that all the hydrogen in the compound ended up as water.
You adjust the temperature so that a sound wave travels more quickly through the air. You increase the temperature from 30°C to 36°C. What's the velocity of the sound wave at this new temperature? A. 335.6 m/s B. 352.6 m/s C. 344.0 m/s D. 350.0 m/s
It is found that doubling the concentration of a quadruples the reaction rate and tripling the concentration of b triples the reaction rate. what is the overall order of the reaction?
The reaction is second order with respect to reactant A and first order with respect to reactant B, giving an overall reaction order of 3.
To determine the overall order of a reaction, we need to find the individual orders with respect to each reactant.
1. Doubling the concentration of reactant A increases the reaction rate by a factor of four. This indicates that the reaction is second order with respect to A, because 2² = 4.
2. Tripling the concentration of reactant B increases the reaction rate by a factor of three. This means the reaction is first order with respect to B, because 3¹ = 3.
Therefore, the overall order of the reaction is the sum of the orders with respect to each reactant:
Order with respect to A: 2Order with respect to B: 1The overall order = 2 + 1 = 3.
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What method could you use to seperate oil from water? Remember that the both must still remain, they just have to be seperated.
The equilibrium concentrations were found to be [br2] = 2.2 × 10−3 m, [cl2] = 3.0 × 10−2 m, and [brcl] = 1.5 × 10−2 m. write the equilibrium expression, and calculate the equilibrium constant for this reaction at this temperature.
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 7.80 moles of magnesium perchlorate, Mg(ClO4)2.
In 7.80 moles of magnesium perchlorate (Mg(ClO4)2), there are approximately 7.80 moles of magnesium atoms, 15.60 moles of chlorine atoms, and 31.20 moles of oxygen atoms.
Magnesium perchlorate (Mg(ClO4)2) consists of one magnesium (Mg) atom, two chlorine (Cl) atoms, and eight oxygen (O) atoms per formula unit. To calculate the number of moles of each element in 7.80 moles of magnesium perchlorate, you can use the mole ratios from the chemical formula.
First, you have 7.80 moles of the entire compound. Since there is one magnesium atom in each formula unit, there are also 7.80 moles of magnesium atoms. Similarly, as there are two chlorine atoms in each formula unit, you have 2 * 7.80 = 15.60 moles of chlorine atoms. Lastly, since there are eight oxygen atoms in each formula unit, there are 8 * 7.80 = 62.40 moles of oxygen atoms. So, in 7.80 moles of magnesium perchlorate, you have approximately 7.80 moles of magnesium atoms, 15.60 moles of chlorine atoms, and 31.20 moles of oxygen atoms.
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) what is the mass percent of a solution prepared by dissolving 18.9 grams of an unknown solid into 39.5 grams of water?
Answer:
32.4%
Explanation:
Step 1: Given data
Mass of the solute = 18.9 g
Mass of the solvent = 39.5 g
Mass of the solution = Mass of the solute + Mass of the solvent = 58.4 g
Step 2: Calculate the mass percent of the solute in the solution
We use the following expression.
[tex]\% m/m =\frac{mass\ of\ the\ solute}{mass\ of\ the\ solution} \times 100\%=\frac{18.9g}{58.4g} \times 100\% =32.4\%[/tex]
The molecular mass of methyl ethanoate is 75.1 amu . calculate the molecular mass of propanoic acid, an isomer of methyl ethanoate. express your answer with the appropriate units.
Final answer:
The molecular mass of propanoic acid, an isomer of methyl ethanoate, is 74.09 amu, calculated by the sum of atomic masses of carbon, hydrogen, and oxygen in its molecular formula, C3H6O2.
Explanation:
To calculate the molecular mass of propanoic acid, an isomer of methyl ethanoate, we need to first understand that isomers are compounds with the same molecular formula but different structures, and hence, the same molecular mass. Propanoic acid's molecular formula is C3H6O2. Using the atomic masses of carbon (12.01 amu), hydrogen (1.01 amu), and oxygen (16.00 amu), we calculate the molecular mass as follows:
(3 × 12.01 amu) + (6 × 1.01 amu) + (2 × 16.00 amu) = 36.03 amu + 6.06 amu + 32.00 amu = 74.09 amu
Therefore, the molecular mass of propanoic acid is 74.09 amu.
Compound j is optically active and has the molecular formula c6h10 and has a four carbon ring. on catalytic hydrogenation, j is converted to k (c6h12) and k is optically inactive. propose structures for j and k. (draw a three-dimensional formula for each using dashes and wedges around chiral centers.) j (draw one of the enantiomers):
Compound J, with the formula C6H10, could be a cyclobutane with two methyl groups creating a chiral center, which becomes a non-chiral cyclohexane (C6H12) upon hydrogenation.
Explanation:The student's question is related to the identification of the structures of an optically active compound with the molecular formula C6H10, and its hydrogenated form C6H12.
Compound J must be a cycloalkane with a four-carbon ring to fit the given molecular formula and to be optically active, it should contain at least one chiral center. Given that hydrogenation leads to an optically inactive compound (K), it suggests that compound J had one or more chiral centers which become quenched upon hydrogenation.
One possible structure for J could be a cyclobutane ring with two methyl groups bonded to adjacent carbon atoms, creating a chiral center at one of those carbons. Upon hydrogenation, the double bonds are saturated, resulting in a compound with all single bonds, thus removing any chirality and creating an optically inactive compound (K).
The proposed structure for J could be represented as follows (for one of the enantiomers):
Cyclobutane ring with a chiral center (drawn using dashes and wedges).Two methyl groups (-CH3) attached to adjacent carbons.And for compound K, after hydrogenation:
Cyclohexane (since the addition of H2 would give us C6H12, which is the formula for cyclohexane).No chiral centers as all carbons are in the plane of symmetry.Does the structure below exhibit geometric isomerism? ch3 tally1 ch3― c ―ch═ch―ch3 tally1 ch3
The ______________of matter depends upon how close the individual particles are together. A) identity B) mass C) state D) temperature
Answer:
State
Explanation:
The state of matter depends on the closeness of the particles. Gases have particles that are very far apart and solids are close together. This is determined by the strength of attraction of these particles to one another.
Anthracene is a yellow, crystalline solid found in coal tar. complete this structure for anthracene, c14h10, by adding bonds and hydrogen atoms as necessary.what type of hybrid orbitals are utilized by carbon in anthracene?how many σ bonds and π bonds are there in an anthracene molecule? how many valence electrons occupy σ-bond orbitals and how many occupy π -bond orbitals?
Anthracene is a polycyclic aromatic hydrocarbon with chemical formula C₁₄H₁₀. The number of fused rings in Anthracene are three in number. This compound is colorful and is used in the formation of different dyes due to its property of deloclization of pi electrons. All the carbon atoms in Anthracene are sp² hybridized with a trigonal planar structure hence, the Anthracene is planar in nature.
Number of Sigma Bonds:
There are 26 sigma bonds (colored in Blue) in Anthracene among which 10 sigma bonds are between carbon and hydrogen atoms while the remaining are between the carbon atoms.
Number of Pi-Bonds:
There are 7 pi bonds in Anthracene (colored in red). All pi bonds are present between carbon and carbon atoms.
Number of Electrons in Sigma Bonds:
As one sigma bond is formed by 2 electrons hence, 26 sigma bonds will be formed by 52 electrons.
Number of Electrons in Pi Bonds:
As one pi bond is formed by the side wise overlap of two p orbitals hence one pi bond is formed by two electrons so, 7 pi bonds will be formed by 14 electrons.
The hybrid orbital that is utilized by the carbon in anthracene is [tex]\boxed{{\text{s}}{{\text{p}}^2}}[/tex] .
The anthracene molecule contains [tex]\boxed{{\mathbf{26}}{\text{ }}{\mathbf{sigma}}}[/tex] bonds and [tex]\boxed{{\mathbf{7}}{\text{ }}{\mathbf{\pi }}}[/tex] bonds.
The number of valence electrons in sigma orbital is [tex]\boxed{{\mathbf{52}}}[/tex] and pi-orbitals is [tex]\boxed{{\mathbf{14}}}[/tex] .
Further explanation:
The anthracene is a crystalline compound and it is yellow in color. It contains three fused rings of benzene thus it is a polyaromatic compound.it has a molecular formula [tex]{{\text{C}}_{{\text{14}}}}{{\text{H}}_{{\text{10}}}}[/tex].
Prediction of hybridization:
The hybridization can be determined by calculating the number of hybrid orbitals (X) which is to be formed by the atom. The formula to calculate the number of hybrid orbitals (X) as follows:
[tex]\boxed{{\text{X}}={\text{Number of bond pair}}+{\text{Number of lone pair}}}[/tex]
Here X is a steric number.
When X is 2 then hybridization is sp.
When X is 3 then hybridization is [tex]{\text{s}}{{\text{p}}^2}[/tex].
When X is 4 then hybridization is [tex]{\text{s}}{{\text{p}}^3}[/tex] .
The structure of anthracene is attached in the image.
Since all carbon atom in anthracene contains three bond pairs and no lone pair thus, the hybridization can be calculated as follows:
[tex]\begin{aligned}{\text{X}}&={\text{Number of bond pair}}+{\text{Number of lone pair}}\\&=3+0\\&=3\\\end{aligned}[/tex]
The value of X is 3, therefore, the hybridization of each carbon in anthracene is [tex]{\text{s}}{{\text{p}}^2}[/tex]
The structure of anthracene contains 26 sigma bond and 7 pi bonds. (refer to the image attached).
The number of valance electron in sigma orbital is twice of the number of sigma bond present in the molecule because every sigma bond contains 2 electrons.
[tex]{\text{Valence electron in sigma orbital}} = 2\left({{\text{sigma bond}}}\right)[/tex]
In anthracene, number of sigma bond is 26, therefore,
[tex]\begin{aligned}{\text{Valence electron in sigma orbital}}&=2\left({{\text{sigma bond}}}\right)\\&=2\left({{\text{26}}}\right)\\&=52\\\end{aligned}[/tex]
The number of valance electron present in pi-orbital is twice of the number of pi bond present in the molecule because every pi-bond contains 2 electrons.
[tex]\begin{aligned}\text{Valence electron in }\pi\text{-orbital}&=2(\pi\text{-bond})\end{aligned}[/tex]
In anthracene, number of pi bond is 7, therefore,
[tex]\begin{aligned}\text{Valence electron in }\pi\text{-orbital}&=2(\pi\text{-bond})\\&=2(7)\\&=14\end{aligned}[/tex]
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Answer details:
Grade: Senior school
Subject: Chemistry
Chapter: Covalent bonding
Keywords: Anthracene, yellow crystalline, coal tar, structure of anthracene, C14H10, hybrid orbitals.
In which set are the substances arranged in order of decreasing solubility in water? (a) (c) al(oh)3 > mg(oh)2 > naoh cac03 > nahc03 > na2c03 (b) (d) bas04 > cas04 > mgs04 agcl > agbr > agl?