In which form do many minerals occur naturally on the Earth’s surface? rocks plants streams water
Answer:
rocks
Explanation:
Question 15 How many grams of NaCl are required to make 500.0 mL of a 1.500 M solution? 58.40 g 175.3 g 14.60 g 43.83 g
How many moles are there in a 2.00 kg bottle of water?
What is the approximate bond angle around the central carbon atom in acrolein?
All three carbon atom has [tex]{\mathbf{s}}{{\mathbf{p}}^{\mathbf{2}}}[/tex] hybridization and therefore bond angle of all central atoms is approximately equal to [tex]\boxed{{\mathbf{120^\circ }}}[/tex].
Further Explanation:
Prediction of hybridization:
The hybridization can be determined by calculating the number of hybrid orbitals (X) which is formed by the atom. The formula to calculate the number of hybrid orbitals (X) as follows:
Steric number (X) = [(Number of atoms bonded to the central atom) + (Number of lone pairs on the central atom)]
Generally, the least electronegative atom is considered as the central atom. Calculate hybridization as follows:
1. If the value of X is 2 then it means two hybrid orbitals are to be formed and thus the hybridization is sp.
2. If the value of X is 3 then it means three hybrid orbitals are to be formed and thus the hybridization is [tex]s{p^2}[/tex].
3. If the value of X is 4 then it means four hybrid orbitals are to be formed and thus the hybridization is[tex]s{p^3}[/tex].
4. If the value of X is 5 then it means five hybrid orbitals are to be formed and thus the hybridization is [tex]s{p^3}d[/tex].
5. If the value of X is 6 then it means six hybrid orbitals are to be formed and thus the hybridization is [tex]s{p^3}{d^2}[/tex].
For carbon atom 1 (refer to the image attached):
Substitute 3 for a number of atoms bonded to the carbon atom and 0 for a number of lone pair on the central atom in equation (1) to find out the steric number.
[tex]\begin{aligned}{\text{Steric number}}&=3 + 0\\&=3\\\end{aligned}[/tex]
The steric number of carbon atom 1 is 3 thus the hybridization of carbon atom 1 in acrolein is [tex]{\mathbf{s}}{{\mathbf{p}}^{\mathbf{2}}}[/tex].
For carbon atom 2 (refer to the image attached):
Substitute 3 for a number of atoms bonded to the carbon atom and 0 for a number of lone pair on the central atom in equation (1) to find out the steric number.
[tex]\begin{aligned}{\text{Steric number}}&=3 + 0\\&=3\ \end{aligned}[/tex]
The steric number of carbon atom 2 is 3 thus the hybridization of carbon atom 2 in acrolein is [tex]{\mathbf{s}}{{\mathbf{p}}^{\mathbf{2}}}[/tex].
For carbon atom 3 (refer to the image attached):
Substitute 3 for a number of atoms bonded to the carbon atom and 0 for a number of lone pair on the central atom in equation (1) to find out the steric number.
[tex]\begin{aligned}{\text{Steric number}}&=3 + 0\\&=3\\\end{aligned}[/tex]
The steric number of carbon atom 3 is 3 thus the hybridization of carbon atom 3 in acrolein is [tex]{\mathbf{s}}{{\mathbf{p}}^{\mathbf{2}}}[/tex].
Since all three carbon atom has [tex]{\mathbf{s}}{{\mathbf{p}}^{\mathbf{2}}}[/tex] hybridization and therefore, bond angle of all central atoms is approximately equal to [tex]{\mathbf{120^\circ }}[/tex].
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Covalent bonding and molecular structure
Keywords: hybridization, acrolein, geometry, sp2, steric number, 3, p orbital, s orbital, Lewis structure, hybridization of acrolein, central atom, carbon, hydrogen, oxygen, shape, double bond.
G: draw the monosaccharide present in dna. draw the sugar in its β-furanose form.
Answer:
Deoxyribose.
Explanation:
Hello,
On the attached picture, you will find the β-furanose structure of the deoxyribose which is the monosaccharide present in the DNA (deoxyribonucleic acid).
Deoxyribose is a sugar derived from ribose by replacement of a hydroxyl group by hydrogen. In addition, it is the five-carbon sugar molecule that helps form the phosphate backbone of DNA molecules
Best regards.
The equilibrium constant kc for the reaction hf(aq) + h2o(l) h3o+(aq) +f-(aq) is 3.5 x 10-4. what is the equilibrium concentration of h3o+ if the initial concentration of hf is 1.0 m?
The equilibrium concentration of H3O+ for the given reaction with an equilibrium constant of 3.5 x 10^-4 and initial HF concentration of 1.0 M is calculated to be 1.9 x 10^-2 M.
Explanation:The equation for the given reaction is HF(aq) + H2O(l) => H3O+(aq) + F-(aq). Given the equilibrium constant (Kc) is 3.5 x 10^-4 and the initial concentration of HF is 1.0 M, we can use the assumption that the change in concentration is small enough to ignore (less than 5% of the initial concentration).
The equilibrium concentrations of the species are therefore: [H3O+] = x M, [F-] = x M, and [HF] = 1.0 - x M. Concluding, we can substitute these concentrations into the expression for the equilibrium constant: Kc = 3.5 x 10^-4 = [H3O+][F-] / [HF] => 3.5 x 10^-4 = (x)(x) / (1.0 - x). However, 1.0 - x is approximately 1.0. Hence, we can solve for x and conclude that [H3O+] = x = sqrt(3.5 x 10^-4) = 1.9 x 10^-2 M. Equilibrium concentration of H3O+ is 1.9 x 10^-2 M.
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If 12.1 kilograms of al2o3(s), 60.4 kilograms of naoh(l), and 60.4 kilograms of hf(g) react completely, how many kilograms of cryolite will be produced?
Without the complete chemical equations for the synthesis of cryolite, it's not possible to calculate the mass of cryolite produced from the reactants Al2O3, NaOH, and HF.
Explanation:To determine the mass of cryolite that will be produced, we need to look at the stoichiometry of the reactions involved. However, the given information does not provide a complete chemical equation for the reaction of Al2O3, NaOH, and HF to form cryolite, so we can't perform a straightforward stoichiometric calculation. Instead, we know from the provided context that aluminum oxide reacts with cryolite in the Hall-Heroult process, suggesting that cryolite acts as a solvent for Al2O3 during aluminum extraction.
In the industrial production of aluminum, cryolite serves as a solvent and does not get consumed in the process. Therefore, we cannot calculate the amount of cryolite produced without the specific chemical equations for its synthesis. One would typically start with a known amount of aluminum oxide and cryolite for the electrolysis process rather than producing cryolite during the reaction. Since we cannot calculate the mass of cryolite produced with incomplete information, we would need the actual synthesis reaction of cryolite to proceed.
When michelle's blood was tested, the chloride level was 0.45 g/dl.
a. what is this value in milliequivalents per liter?
The value in milliequivalents per liter 127 mEq/L when michelle's blood was tested, the chloride level was 0.45 g/dl.
Milliequivalent:
A milliequivalent is a unit of measurement often used for electrolytes and it tells us the chemical activity of the species relative to 1 mg of hydrogen.
The formula,
[tex]\rm \bold {mEq/L = \frac{ (mg/L)}{MW} }[/tex]
0.45 g/dL x 10 dL/1L = 4.5 g/L
Put the value,
Given here,
Chloride level = 0.45 g/dl = 4500 mg/L
The atomic weight of chloride (35.5 g/mol) to solve for the mEq/L:
[tex]\rm \bold { mEqL = \frac{ (4500 mg/L)}{35.5 g/mol)} }[/tex]= 127 mEq/L
Hence, we can conclude that the value in milliequivalents per liter 127 mEq/L when michelle's blood was tested, the chloride level was 0.45 g/dl.
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The table below shows the set of traits in four different beetle populations.
Traits in Population
Population
Traits
1
Brown-colored beetles, pesticide-resistant gene present
2
Green-colored beetles, pesticide-resistant gene absent
3
Green and brown–colored beetles, pesticide-resistant gene absent
4
Green and brown–colored beetles, pesticide-resistant gene present
Which population of beetles is most likely to become extinct when the existing conditions change?
The most likely species of beetles to become extinct when existing conditions change is the Green-colored beetles, pesticide-resistant gene absent; option 3.
What is favorable traits?Favorable traits are those traits possessed by organisms which enables them to survive or gives them an advantage to adapt to their environment.
An example of a favorable trait is pesticide-resistance or being disease-resistant.
Therefore, the most likely species of beetles to become extinct when existing conditions change is the Green-colored beetles, pesticide-resistant gene absent.
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A Gas OCCUPIES 525ML AT A PRESSURE OF 85.0 kPa WHAT WOULD THE VOLUME OF THE GAS BE AT THE PRESSURE OF 65.0 kPa
Boyle's law of ideal gas: This law states that the volume of a gas is inversely proportional to its pressure at a constant temperature. Acc to this law we can write the relation of pressure and volume as:
[tex] PV=Constant [/tex]
That means:
[tex] P_{1}V_{1}=P_{2}V_{2} [/tex]
From that equation we can calculate Volume of gas at a certain pressure:
P₁=Initial pressure
V₁=Initial volume
P₂=Final pressure
V₂= Final volume
Here P₁, initial pressure is given as 85.0 kPa
V₁, initial volume is given as 525 mL
P₂, final pressure is 65.0 kPa
[tex] P_{1}V_{1}=P_{2}V_{2} [/tex]
so,
V_{2}=85\times 525\div 65
=686 mL
Volume of gas will be 686 mL.
What is the equilibrium constant expression for dissolving calcium carbonate in water?
Because amines are basic, they can often accept a proton. draw the protonated structure of n-propylamine
N-Propylamine, being an amine, is basic because the nitrogen atom can accept a proton. Upon acceptance, it forms a protonated structure, C3H9NH+, where nitrogen is bonded to three carbons and the extra hydrogen atom from the accepted proton. This ability of amine's nitrogen atom to accept proton underlines many chemical behaviours of amines.
Explanation:N-Propylamine is a type of amine which contains three carbons (forming a propyl group) attached to a nitrogen atom. Being an amine, it is considered basic as a nitrogen atom in an amine has a lone pair of electrons and can readily accept a proton. When it does accept a proton (H+), it forms a positively charged ion due to the addition of that extra proton.
The protonated form of n-propylamine would have the formula C3H9NH+. In this structure, nitrogen is bonded to the three carbon atoms and also holding onto an additional hydrogen atom, obtained from the accepted proton, making it positively charged.
This basicity of amine's nitrogen atom plays an important role in its chemistry. Amines are found in many compounds essential for life, such as amino acids, hormones, neurotransmitters, and DNA, mainly due to their proton accepting ability.
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In looking at the bolded atoms in the answer choices, which pair consists of molecules having the same geometry? view available hint(s) in looking at the atoms in the answer choices, which pair consists of molecules having the same geometry? ch2o and ch3oh ch2ccl2 and ch2ch2 pcl3 and bf3 co2 and so2
The pair of molecules with the same geometry are CH2CCl2 and CH2CH2 as their central atom (carbon) has the same number of bonding sites.
Explanation:In molecular geometry, we can look for similarities by examining the central atom and its bonding. In the case of the molecules CH2CCl2 and CH2CH2, both contain a carbon atom as their central atom with the same number of bonding sites. In CH2CCl2, the carbon atom is connected to four atoms: two hydrogen and two chlorine. Similarly, in CH2CH2, the carbon atom is attached to three atoms: two hydrogen and one carbon. Therefore, the given two compounds have the same molecular geometry which is tetrahedral.
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Oxides of virtually every element are known. bromine, for example, forms several oxides when treated with ozone. suppose you allow 1.250 g of bromine, br2, to react with ozone, o3, and obtain 1.876 g of brxoy. what is the empirical formula of the product?
Answer:
[tex]Br_2O_5[/tex]
Explanation:
Hello,
Considering the given information, the undergoing chemical reaction is:
[tex]Br_2+O_3-->Br_xO_y[/tex]
Thus, we consider the formed grams of [tex]Br_xO_y[/tex] because the grams of bromine are equal before and after the chemical reaction (mass can't be neither created nor destroyed), thus, the bromine grams into the [tex]Br_xO_y[/tex] are 1.250g and the oxygen grams that come from the ozone are:
[tex]m_O=1.876gBr_xO_y-1.250gO=0.626gO[/tex]
Now, we compute the moles for each one of them as:
[tex]n_{Br}=1.250gBr_2*\frac{1molBr_2}{160gBr_2}*\frac{2molBr}{1molBr_2}=0.0156molBr.\\ n_O=0.626gO*\frac{1molO}{16gO}=0.039molO[/tex]
Now, we divide by the bromine's moles to find the littlest whole-number that allows us to identify the empirical formula as shown below:
[tex]Br=\frac{0.0156}{0.0156}=1;O=\frac{0.039}{0.0156} =2.5[/tex]
Finally, by multiplying by two to find the littlest whole-number, one gets:
[tex]Br_2O_5[/tex]
Best regards.
Write a balanced chemical equation for the synthesis of ammonia from hydrogen and nitrogen gas
A solution with a ph of 4 has _________ the concentration of h+ present compared to a solution with a ph of 5.
If a copper acetate hydrate, Cux(C2H3O2)y zH2O compound is found to contain 31.82% Copper, 59.14% acetate, and the remainder is water. What is the empirical formula of this compound
How many bromine atoms are present in 39.0 g of ch2br2?
If the temperature of air in gabor's lungs is 37∘c (98.6∘f), and the volume is 6l, how many moles of air n must be released by the time he reaches the surface? let the molar gas constant be given by r = 8.31 jmol⋅k.
To find the number of moles of air released by the time Gabor reaches the surface, we can use the ideal gas law equation PV = nRT. Given the temperature and volume of air in Gabor's lungs, we can calculate the number of moles using the molar gas constant. Approximately 1.945 moles of air must be released by the time Gabor reaches the surface.
Explanation:To find the number of moles of air released by the time Gabor reaches the surface, we need to use the ideal gas law equation, PV = nRT. Given that the temperature in Gabor's lungs is 37°C (98.6°F) and the volume is 6L, we can calculate the number of moles. The molar gas constant (R) is given as 8.31 J/mol⋅K.
First, we need to convert the temperature to Kelvin by adding 273 to the Celsius value:
T = 37°C + 273 = 310K
Now, we can rearrange the ideal gas law equation to solve for moles (n):
n = PV / RT
Plugging in the given values:
n = (1atm * 6L) / (8.31 J/mol⋅K * 310K)
Simplifying the equation:
n = 1.945 moles
Therefore, approximately 1.945 moles of air must be released by the time Gabor reaches the surface.
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Calculate the percent water in iron ii sulfate heptahydrate
If kc = 0.143 at 25°c for this reaction, predict the direction in which the system will shift if the initial concentrations of c6h12 and mcp are 0.400 m and 0.300 m, respectively. the system
The direction of a chemical reaction in equilibrium can be predicted by comparing the reaction quotient (Qc or Qp) and equilibrium constant (Kc or Kp). If Q > K, the reaction will shift left, towards reactants. If Q < K, it will shift right, towards products.
Explanation:The question refers to the concept of chemical equilibrium in the field of chemistry, specifically the direction in which a chemical reaction will proceed given the certain initial conditions. In a chemical equilibrium, the reaction may move in the forward direction (towards products) or in the reverse direction (towards reactants) depending on the relationship between Qc (reaction quotient) and Kc (equilibrium constant).
In this particular case, Kc, the equilibrium constant, is given as 0.143 at 25°c. The initial concentrations of C6H12 and MCP are 0.400M and 0.300M respectively. The reaction quotient Qc, would be calculated using these concentrations. If Qc > Kc, the system is not at equilibrium and will shift to the left (towards reactants) to reach equilibrium. If Qc < Kc, the system will shift to the right (towards products) to reach equilibrium.
A similar principle applies to reactions involving gases, where the equilibrium can be defined in terms of partial pressures (Kp) or in terms of molar concentrations (Kc), and corresponding quotients Qp and Qc. Like in the earlier case, if Qp > Kp, the system will shift left, and if Qp < Kp, the system will shift right.
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Ammonia, nh3, is a weak base with a kb value of 1.8×10−5. part a what is the ph of a 0.440 m ammonia solution? express your answer numerically to two decimal places. view available hint(s)
Answer is: pH of ammonia solution is 11,43.
Chemical reaction of ammonia in water: NH₃ + H₂O → NH₄⁺ + OH⁻.
Kb(NH₃) = 1,8·10⁻⁵.
c₀(NH₃) = 0,44 M = 0,44 mol/L.
c(NH₄⁺) = c(OH⁻) = x.
c(NH₃) = 0,44 mol/L - x.
Kb = c(NH₄⁺) · c(OH⁻) / c(NH₃).
0,000018 = x² / (0,4 mol/L - x).
x² + 0,000018x - 0,0000072 = 0.
solve quadratic equation: x = c(OH⁻) = 2,67·10⁻³ mol/L.To find the pH of a 0.440 M ammonia solution, we apply the base ionization constant expression for ammonia, make approximations for simplification due to small Kb, solve for the concentration of OH-, calculate pOH, and then find pH by subtracting pOH from 14.
Explanation:The pH of the ammonia solution can be found by first calculating the concentration of hydroxide ion, [OH-], that results from NH3 acting as a Bronsted base. To do this, you set up the base ionization constant expression for ammonia: Kb = [NH4+][OH-] / [NH3]. Since initial concentration of ammonia is 0.440 M and we assume x mol/L ionizes, at equilibrium we have [NH4+] = x, [OH-] = x, and [NH3] = 0.440 - x. Since Kb for ammonia is so small and x is very small compared to 0.440, we can approximate [NH3] as 0.440 to simplify the equation. Solving Kb = x^2 / 0.440 for x gives the concentration of OH-. Then use the relationship between OH- concentration and pOH to find pOH first (pOH=-log[OH-]). Finally, using the relationship pH + pOH = 14 at 25 degrees Celsius, we can find pH.
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if a copper acetate hydrate, Cux(C2H3O2)y zH2O compound is found to contain 31.82% Copper, 59.14% acetate,and the remainder is water. What is the empirical formula of this compound ?
A 225 g sample of french fries supplies 460 kilocalories of energy. 65% of those calories come from fat, which supplies 9 kilocalories of energy per gram. How many grams of fat are in the french fries?
Answer:
33 g
Explanation:
A 225 g sample of french fries supplies 460 kilocalories of energy. 65% (0.65) of those calories come from fat. The kilocalories coming from fat are:
460 kcal × 0.65 = 299 kcal
9 kilocalories of energy are supplied per gram of fat. The grams of fat that supply 299 kcal are:
299 kcal × (1 g fat/ 9 kcal) = 33 g
A chlorine ion (Cl-) would most likely bond with _____.
Cl-
Mg
K+
O
Answer:
The chlorine ion (CI-) would presumably bond with the electrolyte K+
Explanation:
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Ephedrine, a central nervous system stimulant, is used in nasalsprays as a decongestant. this compound is a weak organic base: {\rm{c}}_{10} {\rm{h}}_{15} {\rm{on(}}aq{\rm{)}} + {\rm{h}}_2 {\rm{o}}(l{\rm{)}} \overrightarrow{\leftarrow} {\rm{c}}_{10} {\rm{h}}_{15} {\rm{onh}}^ + (aq) + {\rm{oh}}^ - (aq) a 0.035 {\rm m} solution of ephedrine has a{\rm ph} of 11.33. what is the equilibrium concentration of{\rm{c}}_{10} {\rm{h}}_{15} {\rm{on}}, {\rm{c}}_{10} {\rm{h}}_{15} {\rm{onh}}^ +, and oh-.
Ephedrine, a central nervous system stimulant, is used in nasal sprays as a decongestant. This compound is a weak organic base:
C10H15ON (aq) + H2O (l) -> C10H15ONH+ (aq) + OH- (aq)
A 0.035 M solution of ephedrine has a pH of 11.33.
a) What are the equilibrium concentrations of C10H15ON, C10H15ONH+, and OH-?
b) Calculate Kb for ephedrine.
c(C₁₀H₁₅NO) = 0,035 M.
pH = 11,33.
pOH = 14 - 11,33 = 2,67.
[OH⁻] =
10∧(-2,67) = 0,00213 M.
[OH⁻] =
[C₁₀H₁₅NOH⁺] = 0,00213 M.
[C₁₀H₁₅NO] = 0,035 M - 0,00213 M = 0,03287 M.
Kb = [OH⁻] ·
[C₁₀H₁₅NOH⁺] / [C₁₀H₁₅NO].
Kb = (0,00213 M)² / 0,03287 M = 1,38·10⁻⁴.
The gas phase decomposition of phosphine at 120 °C PH3(g) 1/4 P4(g) + 3/2 H2(g) is first order in PH3 with a rate constant of 1.80×10-2 s-1. If the initial concentration of PH3 is 3.16×10-2 M, the concentration of PH3 will be M after 99 s have passed
Answer:
5.32*10⁻³M
Explanation:
Given:
Rate constant of the First order reaction, k = 1.80*10-2 s-1
Initial concentration of PH3, [A]₀ = 3.16*10-2 M
Reaction time, t = 99 s
Formula:
For a first order reaction:
[tex][A] = [A]_{0} e^{-kt}[/tex]
where [A] and [A]₀ are concentration of reactant at time t and t = 0
k = rate constant
For the given reaction"
[tex][A] = 3.16*10^{-2} e^{-1.80*10^{-2} *99} = 5.32*10^{-3} M[/tex]
In the Beer-Lambert Law equation, what does the “b” represent?
Concentration
Absorption
y-intercept
Buoyancy
Thickness of solution
In the Beer-Lambert Law equation, “b” represents[tex]\boxed{{\text{thickness of solution}}}[/tex].
Further explanation:
Spectrophotometry is a method that is applied for measurement of absorbance of light in terms of intensity of light when light is allowed to pass through the solution sample. Spectrophotometer is the equipment or instrument that is employed for this purpose.
Beer-Lambert’s Law:
This law describes the relationship of absorbance with concentration and path length of solution. According to this law, absorbance of any solution is directly related to its concentration and optical path length. The expression for Lambert-Beer’s law is as follows:
[tex]{\text{A}} = {{\varepsilon bc}}[/tex] …... (1)
Where,
A is absorbance of species.
[tex]{{\varepsilon }}[/tex] is molar absorptivity of species.
b is optical path length or thickness of solution.
c is concentration of species.
If graph is plotted between absorption and concentration of solution, a straight line or linear graph is observed. But this linearity is lost at extremely high concentrations. This non-linearity can be due to several factors. Some of these include use of non-monochromatic radiations, scattering of light, phosphorescence or fluorescence of sample.
According to equation (1),“b” represents the thickness of the solution.
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Grade: Senior School
Subject: Chemistry
Chapter: Beer-Lambert Law
Keywords: absorbance, Beer-lambert’s law, concentration, path length, solution, directly related, thickness of solution, molar absorptivity, A, b, c, spectrophotometry, spectrophotometer.
match the correct properties and characteristics of each type of rock?
Sedimentary rocks are formed from the deposition of materials on Earth's surface or in bodies of water, often in easily weathered layers. Igneous rocks originate from cooled magma and can have various surface characteristics. Metamorphic rocks result from the transformation of existing rocks and are characterized by hard layers formed under high temperature and pressure.
Matching properties and characteristics to each type of rock:
A) cooled magma
Igneous rocks are formed from the cooling and solidification of molten magma. This process can occur beneath the Earth's surface (intrusive) or at the surface (extrusive), giving rise to different textures within igneous rocks.
B) deposition of material on Earth's surface or in bodies of water
Sedimentary rocks are the result of the accumulation and compression of sediments, which can include minerals, organic materials, and even the remains of plants and animals. These sediments often accumulate in bodies of water or on Earth's surface, and over time, they become compacted and cemented into rock.
C) arises from the transformation of existing rocks
Metamorphic rocks are formed through the alteration of pre-existing rocks. This alteration typically occurs due to changes in temperature, pressure, or mineral composition. Metamorphism can result in the development of new minerals and textures within the rock.
D) made of layers that are weathered relatively easily
Sedimentary rocks often exhibit a layered or stratified structure. These layers, called bedding planes, can be prone to weathering and erosion because they are composed of smaller particles, making them susceptible to mechanical and chemical breakdown.
E) made of hard layers formed under high temperature and pressure
Metamorphic rocks, as a result of their formation from existing rocks undergoing high temperatures and pressures, tend to be harder and more resistant to weathering than sedimentary rocks. They often have a foliated texture with aligned minerals.
F) has a shiny surface throughout
Igneous rocks can exhibit a variety of surface characteristics, including a shiny appearance, but this attribute is not exclusive to them. The luster or shine of an igneous rock can vary based on its mineral composition, texture, and the presence of glassy or metallic minerals.
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The question probable may be:
Match the correct properties and characteristics to each type of rock.
sedimentary
igneous
metamorphic
A)) cooled magma
B))
deposition of material
on Earth’s surface or
in bodies of water
C))arises from
transformation
of existing rocks
D))made of layers that are
weathered relatively
easily
E))made of hard layers
formed under high
temperature
and pressure
F))has a shiny surface
throughout
What is the chemical symbol for element 2