How do the values of δg∘ calculated this way compare to those calculated from δh∘ and δs∘? how do the values of calculated this way compare to those calculated from and ? all of the values are compararable. some of the values are compararable. none of the values are compararable?

Answer:

83000 m/s

Explanation:

Using

F = Bqv....................... Equation 1

Where F = Force experienced by the charge, B = magnetic field q = charge of the particle, v = speed of the particle.

make v the subject of the equation

v = F/Bq.................... Equation 2

Given: q = 5.2×10⁻¹⁹ Coulombs, F = 9.5×10⁻¹⁵ Newtons, B = 2.2×10⁻¹ Tesla

Substitute into equation 2

v = 9.5×10⁻¹⁵ /(5.2×10⁻¹⁹×2.2×10⁻¹)

v = 8.3×10⁴ m/s

v = 83000 m/s

Answer:

a) 1.1mm

b) 2.513kg/ms^2

Explanation:

You can use the formula for the calculation of the wavelength of a wave

f=1.40MHz=1.40*10^{6}Hz

1 )

[tex]\lambda=\frac{v}{f}=\frac{1540m/s}{1.40*10^{6}Hz}=1.1*10^{-3}m=1.1mm[/tex]

2)

The Young modulus can be computed by using the expression:

[tex]v=\sqrt{\frac{Y}{\rho}}\\\\Y=v^2\rho[/tex]

where Y is the Young modulus and p is the density of the material. Here, you have considered that the prostate gland can be taken as a vibrating membrane or string.

By replacing you obtain:

[tex]Y=(1540m/s)^2(1060kg/m^3)=2.513*10^9kg/ms^2[/tex]

hence, the Young modulus of the prostate glande is 2.513kg/ms^2

Answer:

1) 1.1 x [tex]10^{-3}[/tex] m

2)2.51 x[tex]10^{9}[/tex]Pa

Explanation:

Given:

Speed of sound in prostate 'V'= 1540m/s

frequency 'f'  = 1.40 MHz = 1.40 x [tex]10^{6}[/tex]Hz

density of prostate'ρ' = 1060 kg/m3

1) As we know that the relationship of the speed of sound, its frequency, and wavelength is the same as for all waves

V= fλ

λ= V/f => 1540/1.40 x [tex]10^{6}[/tex]

λ= 1.1 x [tex]10^{-3}[/tex] m

Thus, the wavelength of the sonogram ultrasound is 1.1 x [tex]10^{-3}[/tex] m

2)The speed of sound in a solid the depends on the Young's modulus of the medium and the density

V=√Y/ρ.

V² = Y/ρ

Y= V² x ρ=> 1540² x 1060

Y= 2.51 x[tex]10^{9}[/tex]Pa

Thus, Young's modulus for the prostate gland is 2.51 x[tex]10^{9}[/tex]Pa

Answer: 11.5 Hz, 29.83 m

Explanation:

Given

Linear density of the cable, μ = 0.2 kg/m

Tensión in the cables, T = 500 N

Wavelength of the wave, = 4.5 Waves

Distance between the poles, L = 20 m

Temperature of, t = 20° C

Speed of sound, v = 343 m/s

λ = length / number of waves =

λ = 20 / 4.5

λ = 4.44 m

Frequency of a standing wave is the same as frequency of a hum. Calculated using the formula

F = n/2L * √(T/μ)

F = 1/λ * √(T/μ)

F = 1/4.44 * √(500/0.2)

F = 0.23 * √2500

F = 0.23 * 50

F = 11.5 Hz

Wavelength of the hum,

λ = v/f

λ = 343 / 11.5

λ = 29.83 m

The wavelength of the hum produced by the cable is approximately 4.44 meters, and the frequency is approximately 11.26 Hz, calculated using the known linear density, tension, and distance between poles.

The student is asking about the properties of a standing wave created when the wind blows across a cable hung between two poles. Given the linear density (µ) of 0.2 kg/m, the tension in the cable (500 N), and the distance between poles (20 meters), we are to find the frequency and wavelength of the hum produced by the cable.

Firstly, we can calculate the wavelength (λ) of the wave using the information that 4.5 wavelengths fit between the two poles that are 20 meters apart:

λ = 20 meters / 4.5 wavelengths = 4.44 meters (approx)

Next, we can find the speed (v) of the wave on the cable using the formula:

v = sqrt(T / µ)

Plugging in the given values, we get:

v = sqrt(500 N / 0.2 kg/m) = sqrt(2500 m2/s2)

v = 50 m/s

Now, using the wave speed (v) and the wavelength (λ), we can calculate the frequency (f) of the wave using the formula:

f = v / λ

f = 50 m/s / 4.44 m = 11.26 Hz (approx)

Therefore, the wavelength is approximately 4.44 meters, and the frequency of the hum is approximately 11.26 Hz.

Answer:

I'm sorry, I don't think there is any answer to give seeing as no question has been asked

Answer:

No question

Explanation: Sorry

Answer:

Multiplying the mass of any student by a factor of 4.5 gives the kinetic energy of the student.

Explanation:

because

Answer: the question was asked to think about how to multiply a mass speech student by a factor to include the student. Kinetic energy, are there any common factors that appeal to them? The table shows mass energy and constant velocity. Let's calculate a constant factor, multiply it by mass, get the energy and see if we can do it. It's very easy. You can do it just in case. Only kinetic energy divided by mass can be produced. That is, the first is 100 and 21.5 divided by 27. Now you have the next 4.5. This is one. Then it is 162 divided by 36. This is 4.5. January 3, 202

Divide 5 by 45 to get 4.5. And hopefully you can see the patterns that are appearing here. In the fourth one, 243 divided by 54 gives 4.5. The fifth 288 divided by 64. Since it is 4.5, you can guess what it will be like. And finally, in the sixth case, it's 3 to 8.5 divided by 73. This is also equivalent to 4. Well, this common factor 4.5 was found.

Kinetic energy is a form of energy that an object or particle has due to its movement. When work is done on an object by applying a net force that transfers energy, the object accelerates, thereby gaining kinetic energy. In physics, the kinetic energy of an object is the energy that the object has due to its motion.

This is defined as the work required to accelerate an object of a given mass from a stationary state to a specified velocity. After the body gains this energy during acceleration, the body retains this kinetic energy unless the velocity changes.

All moving objects use kinetic energy. Examples of kinetic energy are walkers, thrown baseball, bread crumbs falling from a table, and charged particles in an electric field.

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Answer:

It was made possible by the new methods of making steel

Explanation:

The Bessemer process was the first inexpensive industrial process for the mass production of steel from molten pig iron prior to the development of the open hearth furnace. The key principle used was the removal of impurities from the iron by process of oxidation with air being blown through the molten iron. The oxidation also enhances the temperature of the iron mass and keeps it molten. So with the presence of this, building of skyscraper was made possible.

Skyscrapers in the 1800s were made possible by the invention of steel girders and elevators, along with the high prices of real estate in city centers.

The construction of skyscrapers in the 1800s was made possible by several key advancements. One important development was the invention of steel girders that could support the weight of tall buildings. These girders allowed for the construction of buildings beyond the previous limit of 10 to 12 stories.

Another crucial factor was the invention of elevators, both passenger and freight elevators. The introduction of elevators made it feasible for people and goods to reach higher floors easily, making taller buildings more practical.

Additionally, the price of real estate in city centers played a significant role. As the cost of land increased, developers turned to building upwards to maximize space and value. These advancements in construction technology and the need for efficient use of space contributed to the rise of skyscrapers in the 1800s.

Answer:

The correct option is;

The voltages become negative instead of positive and keep the same magnitudes

Explanation:

Here we have that there is a change in direction from positive to negative with the direction pointing to opposite of the initial direction whereby the field strength does not change due to the reversal of the. Therefore the voltage becomes negative instead of negative while keeping the the magnitude.

That is there is a electric field reversal or a change electric field direction.

Answer:

When we change the distance, the universal attraction force increases, so that the system is free to reach a new equilibrium, the linear speed of the earth must rise to the calculated value.

v = √ (G M / r)

Explanation:

For this exercise it is asked that if you maintain the linear speed of the Earth and bring it closer to the sun that would pass.

We pass the distance from Ro = 1.49 10¹¹ m to r = 0.736 10¹¹ m shortens, we write Newton's second law

             F = m a

where the force is the universal force of attraction

            F = G mM / r²

acceleration is central

            a = v² / r

           G m M / r² = m v² / r

            v = √ (G M / r)

When we change the distance, the universal attraction force increases, so that the system is free to reach a new equilibrium, the linear speed of the earth must rise to the calculated value.

We can compare this value with that of the normal orbit

           v₀ = √ (GM / R₀)

            v / v₀ =√ (Ro / r)

           v² r = v₀² R₀

 either of these two expressions gives the relations gives the change in velocity with the radius of the orbit

Answer:At the top of the page is a transvers wave

C= crest

B= wavelingth

D= trough

A= amplatud

The next wave is a longitudinal wave

Answer:

The tropic of Capricorn

Explanation:

This line runs 23.5 degrees south of the equator.

Answer:

yeah

Explanation:

electric fields help the charged particles interact

and isn't magnetic field the same as electric field.

Answer:

The arc measure is 20°.

Answer:160

Explanation:edg

Answer:

1. 60 W

2. 24 W

3. 0.83 A

4. 25200 J

Explanation:

1. What we are simply asked to look for is Electrical Power. It is the rate electrical energy is being transferred.

It is given as:

[tex]P = IV[/tex]

where I = current and V = voltage.

Therefore, Power is:

P = 0.50 * 120 = 60 W

2. Power, as given in the formula above is:

P = 2.0 * 12

P = 24.0 W

3. According to the formula of Power, current is given as:

[tex]I[/tex] = [tex]\frac{P}{V}[/tex]

Power is 100 W and voltage is 120 V, therefore, current is:

[tex]I = \frac{100}{120} \\\\\\I = 0.83 A[/tex]

4. Recall that power is the time rate of transfer of electrical energy. Mathematically:

[tex]P = \frac{E}{t}[/tex]

where t = time

This means that Electrical energy is:

[tex]E = Pt[/tex]

Recall that Power is:

[tex]P = IV[/tex]

Therefore, Electrical energy is:

[tex]E = IVt[/tex]

[tex]E = 210 * 12 * 10\\\\\\E = 25200 J[/tex]

1. At "60 W" the bulb convert electric energy to light

2. Power used by lamp will be "24.0 W".

3. The current flow will be "0.83 A".

4. The electric energy delivered to the motor will be "25200 J".

According to the question,

1. Current, I = 0.50 A

  Voltage, V = 120 V

We know,

→ Power (P) = Current (I) × Voltage (V)

                     = 0.50 × 120

                     = 60 W

2. Current, I = 2.0 A

  Voltage, V = 12.0 V

then,

→ P = 2.0 × 12

       = 24.0 W

3. Power, P = 100 W

  Voltage, V = 120 V

We know,

→ Current, I = [tex]\frac{P}{V}[/tex]

                    = [tex]\frac{100}{120}[/tex]

                    = 0.83 A

4. Current, I = 210 A

Potential difference, V = 12.0  

We know,

→ E = Pt

    P = IV

or,

The electrical energy be:

→ E = IVt

       = 210 × 12 × 10

       = 25200 J

Thus the above answer is correct.

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Answer:

a. scattering of lower frequencies by larger particles in the air.

b. light's longer path through the air at sunset.

Explanation:

Sun light has to travel several distances through the earth's atmosphere during Sun set and Sun rise. This light gets scattered by air molecules present and the shorter wave length blue gets upwards and red comes down. That is why the sun light appears red in our eyes.

Answer:

Constructive interference occurs

Explanation

This is because at the point they both occupy the same region of space at the same time, there is a superposition of the waves causing them to add up. Since their amplitudes are equal and positive, they are in phase. and thus there is increase the resultant amplitude..This increase in amplitude is due to constructive interference.

Two wave pulses with equal positive amplitudes moving in opposite directions on a string will result in constructive interference where their displacements add up leading to an increased amplitude at the point of overlap. This is a momentary or transient event.

When two wave pulses with equal positive amplitudes meet each other on a string, moving in opposite directions, what we experience is constructive interference. This happens because the displacement of the two waves at every point adds up. Essentially, they combine to produce a wave of increased amplitude. In this case, the resultant wave would have an amplitude that's twice that of the individual wave pulses. Please note: this phenomenon happens only at the instant when both waves overlap and not any time before or after that. In other words, it's a transient or temporary phenomenon, not a permanent one, causing a momentary increase in the height of the wave at the point of intersection.

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Answer:

C after the hurricane of 1900s

Explanation:

They didn’t remove 8 feet of soil they put 8 feet of soil

Answer:

The new separation is [tex]\bf{(d/\sqrt{3})}[/tex].

Explanation:

The expression of the force between two spheres is given by

[tex]F = k\dfrac{q_{A}q_{B}}{d^{2}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)[/tex]

where, [tex]q_{A}[/tex] is the charge on sphere A, [tex]q_{B}[/tex] is the charge on sphere B, [tex]k[/tex] is constant and [tex]d[/tex] i the separation between two spheres.

The new value of charge on sphere B is [tex]q_{B}^{n} = \dfrac{q_{A}}{3}[/tex]. Consider the new separation between the spheres be [tex]d'[/tex]. Under the new configuration the force between the spheres is given by

[tex]F = k \dfrac{q_{A}(q_{A}/3)}{d'^{2}}~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)[/tex]

Equating equation (1) and equation (2), we have

[tex]~~~~&& \dfrac{1}{d'^{2}} = \dfrac{1}{3d^{2}}\\&or,& d' = \dfrac{d}{\sqrt{3}}[/tex]

So, the new separation is [tex](d/\sqrt{3})[/tex].

A stationary charge does not experience a force in a magnetic field. A moving charge experiences a force perpendicular to both its velocity and the magnetic field. A ferromagnetic object is attracted to a magnet regardless of its movement.

The magnetic force between a bar magnet and different charged materials can be understood in respect to the properties of the magnetic field, and these forces can range from attractive to repulsive depending on the orientation of the objects in the field and the type of materials involved. For a stationary charge, magnetic forces do not act on it because the magnetic force on a charged particle is always perpendicular to the direction of its motion. Hence, a stationary charged particle does not experience a force.

In the case of a moving charge, a magnetic field exerts force on it. This force is perpendicular to both the velocity of the charge and to the magnetic field, and is dependent on the magnitude of the charge, its speed, and the magnetic field. For example, if you place a moving charge in a magnetic field, the charge will experience a force that's oriented at right angles to both its direction of movement and the field itself. Ferromagnetic objects like iron or nickel will experience attraction to the magnet irrespective of their movement. It is the property of the ferromagnetic material to align its domains in the direction of the external magnetic field (from the bar magnet), thus the entire object acts like a small magnet and feels an attraction.

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Answer:

Pressure exerted by statue = [tex]15 kN/m^{2}[/tex]

Explanation:

Weight of the statue (F)= 3600 N

Area of the base of statue(A) = Length of the base x Width of the base

                                              =0.6 m x 0.4 m =0.24 m

Pressure is defined as  force per unit area.

[tex]Hence,\ pressure\ by\ statue= \frac{Force(F)}{Area(A)}=\frac{3600}{0.24} = 15000\ N/m^{2}[/tex]

Pressure exerted by statue = 15000 [tex]N/m^{2} = 15 kN/m^{2}[/tex]

The pressure exerted by the deer statue on the ground is approximately 15000 Pa.

Pressure is a measure of the force exerted per unit area. In physics, it is defined as the force acting perpendicular to the surface of an object divided by the area over which the force is applied.

To calculate pressure (P), we use the formula [tex]\(P = \frac{force}{area}\).[/tex] The force exerted by the statue is its weight, which is the gravitational force acting on it, given by [tex]\(F = mg\)[/tex], where (m) is the mass and (g) is the acceleration due to gravity (approximately 9.8 m/s²).

Given the weight of the statue [tex]\(3600 \, N\),[/tex] we find the mass using [tex]\(F = mg\)[/tex], rearranging to [tex]\(m = \frac{F}{g}\)[/tex], which gives [tex]\(m \approx \frac{3600 \, N}{9.8 \, m/s^2} \approx 367.35 \, kg\)[/tex].

Now, we find the area (\(A\)) of the base of the statue:[tex]\(A = \text{length} \times \text{width} = 0.60 \, m \times 0.40 \, m = 0.24 \, m^2\).[/tex]

Finally, we use the pressure formula [tex](P = \frac{F}{A}\): \(P \approx \frac{3600 \, N}{0.24 \, m^2} \approx 15000 \, Pa\).[/tex]

Answer:

Explanation:

Given

Original volume V1=30cm^3 converting to L

=30/1000=0.03L

Constant pressure P= 648 tors

Converting to atm; 648 tors*1atm/760 torr=0.853 atm

Work=984J= 984**1L/101.33=9.7L.atm

Note before

W= -P(Vfinal-Vinitial)

-9.7/0.853+0.03L=11.68L

Answer:

Final expanded volume 11.43 L

Explanation:

The picture attached shows the solution

Answer:

The new angular velocity of the two stones = 160.064 rad/s

Explanation:

This is a case of conservation of angular momentum.

For initial case:

Mass = 50 kg

Radius = 0.75 m

Angular velocity N = 30 rev/s

We must convert to rad/s w

w = 2¶N = 2 x 3.142 x 30 = 188.52 rad/s

Moment of inertia I = m x r^2

I = 50 x 0.75^2 = 28.125 kgm2

Angular momentum = I x w

= 28.125 x 188.52 = 5302.125 kgm2-rad/s

For second case smaller stone has

m = 20 kg

Radius = 0.5 m

I = m x r^2 = 20 x 0.5^2 = 5 kgm2

Therefore,

Total moment of inertia of new system is

I = 28.125 + 5 = 33.125 kgm2

Final angular momentum = I x Wf

Where Wf = final angular speed of the system.

= 33.125 x Wf = 33.125Wf

Equating the two angular moment, we have,

5302.125 = 33.125Wf

Wf = 5302.125/33.125 = 160.064 rad/s

Answer:

[tex]\dot n = 25.471\,\frac{rev}{s}[/tex]

Explanation:

The situation is described reasonably by the Principle of Angular Conservation:

[tex]\frac{1}{2}\cdot (50\,kg)\cdot (0.75\,m)^{2}\cdot \left(30\,\frac{rev}{s} \right) = \frac{1}{2}\cdot \left[(50\,kg)\cdot (0.75\,m)^{2}+ (20\,kg)\cdot (0.5\,m)^{2} \right] \cdot \dot n[/tex]

The final angular velocity is:

[tex]\dot n = 25.471\,\frac{rev}{s}[/tex]

Answer:

All particles made of quarks are called hadrons.

All particles madeup of two or more quarks held together by a force  are called ; ( C ) Hadrons

Hadrons are subatomic particles which are made of two or more quarks which are held firmly by a force similar to electric force. An example of Hadron is Baryon which contains three quarks which are held closely together.

Hence we can conclude that All particles made of quarks are called Hadrons

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Answer:  

The minimum temperature of hot reservoir is 586K or 313°C

Explanation:

The Carnot cycle is defined as ideal reversible process thermodynamic process which has four successive step. During the expansion and compression of  the substance it can done upto desired point and then reversed up.

Here the energy is used from the hot reservoir to do work and deposited into the cold reservoir. As is it reversible the efficiency of the carnot cycle is the theoretical maximum of the heat engine.

The efficiency of carnot cycle is

η = 1 - [tex]\frac{Tc}{Th}[/tex]    eq 1

Where Tc is the temperature of cold reservoir = 20° = 20°+273K = 293K

           Th is the temperature of hot reservoir.

            η  is the efficency 50% = 0.5

The minimum temperature of the reservoir is related to the maximum efficiency,

Substituting values in eqn 1

0.05 = 1-[tex]\frac{293}{Th}[/tex]

Th = [tex]\frac{293}{1 - 0.5}[/tex] =586 K

The minimum temperature of hot reservoir is 586K.

ie 586K-273 = 313°C

Final answer:

The minimum hot-reservoir temperature required for a heat engine to have 50% efficiency with a cold reservoir at 20°C is 313.15°C.

Explanation:

To determine the minimum hot-reservoir temperature for a heat engine with 50% efficiency where the cold reservoir is at 20°C, we can use the efficiency formula for a Carnot engine: efficiency (e) = 1 - (Tc/Th), where Tc is the cold reservoir temperature and Th is the hot reservoir temperature, both in kelvins. Rearranging the formula to solve for Th gives: Th = Tc / (1 - e).

First, convert the cold reservoir temperature from Celsius to Kelvin: Tc = 20°C + 273.15 = 293.15 K. Now, plug in the efficiency value: Th = 293.15 K / (1 - 0.50) = 293.15 K / 0.50 = 586.3 K. Convert this back to Celsius to get the minimum hot-reservoir temperature required: Th - 273.15 = 586.3 K - 273.15 = 313.15°C.

Therefore, the minimum hot-reservoir temperature required for the proposed heat engine to reach 50% efficiency is 313.15°C.

Answer:

Gravity at a distance of 4R will be reduced to 1/16 th.

Explanation:

Given:

At the surface of the moon, the acceleration due to the gravity of the moon is x.

We have to find the gravity a t a distance of 4 times from the center of the moon.

Let the radius of the moon be "R".

And

The value of acceleration due to gravity is [tex]g_m[/tex] .

Formula:

⇒ [tex]g_m=\frac{GM}{R^2}[/tex]   ...where M is the mass of the moon.

Now

Gravity of the moon at the its surface:

⇒ [tex]g_m=\frac{GM}{R^2}[/tex]    ...equation (i)

Gravity of the moon at a distance of  [tex]4R[/tex]:

⇒ [tex]g_m_1=\frac{GM}{(4R)^2}[/tex]

⇒ [tex]g_m_1=\frac{GM}{16R^2}[/tex]   ...equation (ii)

Dividing equation (i) with (ii) to find the relationship between the two.

⇒ [tex]\frac{g_m_1}{g_m} =\frac{GM}{16R^2}\times \frac{R^2}{GM}[/tex]

⇒ [tex]\frac{g_m_1}{g_m} =\frac{1}{16}[/tex]

⇒ [tex]g_m_1 =g_m(\frac{1}{16})[/tex]

⇒ [tex]g_m_1 =x(\frac{1}{16})[/tex]    ...as gm=x at the surface.

So,

We can say that the gravity at a distance of 4R will be reduced to 1/16 th.

Answer: The acceleration due to gravity on the surface of the moon is 1.620 m/s2. 2) The radius of the Earth is 6.38 x 106 m.

Answer:

75 m

Explanation:

wavelength = frequency/ speed = 75 m

Complete Question in order

See the first image attached

Answer and Explanation:

The three images attached discussed the solution to this question

second Image                                                                                      

Third Image                                                                                          

and Fourth Image

If the images are not clear enough right-click on it and open in a new tab

Answer:

The ray passes through a focal point of the lens only if the lens is a converging lens.

Explanation:

By the principles of geometric optics, we know that all rays parallel to the principal axis of converging lens, change its direction to a point situated in the axis of the lens. This last point is know as the focal point.

Hence, the only truth choice is:

The ray passes through a focal point of the lens only if the lens is a converging lens.

I attached an image to illustrate this situation

HOPE THIS HELPS!!

Answer:

[tex]\frac{1}{12}ML^2[/tex]

Explanation:

The moments of the whole object is the sum of the moments of the 2 segments of rod at their ends of which length is L/2 and mass M/2:

[tex]I = 2I_{end} = 2\frac{1}{3}\frac{M}{2}\left(\frac{L}{2}\right)^2[/tex]

[tex]I = \frac{1}{3}M\frac{L^2}{4}[/tex]

[tex]I = \frac{1}{12}ML^2[/tex]

Answer:

The human eye and brain together translate light into color. Light receptors within the eye transmit messages to the brain, which produces the familiar sensations of color. ... Rather, the surface of an object reflects some colors and absorbs all the others. We perceive only the reflected colors.

Explanation:

Final answer:

The eye and brain work together to perceive color. Light enters the eye and is detected by cones in the retina, which send signals to the brain. The brain processes these signals and combines information from different cones to create the perception of color.

Explanation:

The eye and brain work together to give you perception of color through a complex process. When light enters the eye, it is detected by special cells called cones in the retina. These cones are sensitive to different wavelengths of light and send signals to the brain. The brain then processes these signals and combines the information from different cones to create the perception of color.

For example, if you see a red object, the red cones in your eye will be activated and send signals to the brain. The brain then interprets these signals as the color red. Similarly, the green cones are activated by green light and the blue cones by blue light. By combining the information from all three types of cones, the brain is able to perceive a wide range of colors.

Answer:

The gravitational force between proton and an electron is [tex]4.06 \times 10^{-47}[/tex] N

Explanation:

Given:

Mass of proton [tex]m_{1} = 1.67 \times 10^{-27}[/tex] kg

Mass of electron [tex]m_{2} = 9.11 \times 10^{-31}[/tex] kg

Separation between electron and proton [tex]r = 5 \times 10^{-11}[/tex] m

According to the gravitational law,

   [tex]F = \frac{Gm_{1} m_{2} }{r^{2} }[/tex]

Where [tex]G = 6.674 \times 10^{-11}[/tex] = gravitational constant.

   [tex]F = \frac{6.674 \times 10^{-11} \times 1.67 \times 10^{-27} \times 9.11 \times 10^{-31} }{(5 \times 10^{-11} )^{2} }[/tex]

   [tex]F = 4.06 \times 10^{-47}[/tex] N

Therefore, the gravitational force between proton and an electron is [tex]4.06 \times 10^{-47}[/tex] N

The gravitational force between a proton and an electron is 40 * 10⁻⁴⁸ N

Newton's law of gravitation is given by:

F = Gm₁m₂/r²

Where F is the force, m₁, m₂ are masses, r is the distance between the two masses and G is the gravitational constant = 6.67 * 10⁻¹¹ Nm²/kg²

Given that:

m₁ = 1.67 * 10⁻²⁷ kg, m₂ = 9.11 * 10⁻³¹ kg, r = 5 * 10⁻¹¹ m, hence:

F = 6.67 * 10⁻¹¹ Nm²/kg² * 1.67 * 10⁻²⁷ kg * 9.11 * 10⁻³¹ kg/ (5 * 10⁻¹¹ m)²

F = 40 * 10⁻⁴⁸ N

The gravitational force between a proton and an electron is 40 * 10⁻⁴⁸ N

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