How do you combine like terms of #-10+7x+24-2x#?

The correct answer is:

16√13.

Explanation:

The perimeter of a figure is found by adding together the lengths of all of the sides. The side lengths of this garden are: √13, √13, 7√13 and 7√13. This is because opposite sides in a rectangle are congruent.

Adding these together we have:

√13+√13+7√13+7√13 = (1+1+7+7)√13 = 16√13

Answer:

  29

Step-by-step explanation:

The perimeter is the sum of the side lengths:

  4 + 12 + 13 = 29

The perimeter of the triangle is 29. (It is not a right triangle.)

___

A right triangle with side lengths 12 and 13 will have a short side of 5. Its perimeter is 30.

Answer:

B,5/8+5r=8

Step-by-step explanation:

We have been given that Vivian's insurance company pays for 80% of her foot surgery, after she pays a $500 deductible. We have been given that her surgery costs $9600 and we need to find how much will Vivian have to pay for her surgery.

Since we know that the insurance company will pay any amount after Vivian has paid $500. Therefore, the remaining amount after Vivian pays $500 as deductibles will be $9600 - $500 = $9100.

Now we know that Vivian's insurance company will pay 80% of this amount, therefore, Vivian will have to pay the 20% of $9100 in addition to the $500 she already paid.

20% of $9100 is [tex]9100\cdot \frac{20}{100} = \$1820[/tex]

Therefore, the total amount that Vivian pays for surgery is $500 + $1820 = $2320.

Therefore, the first choice given is the right answer.

By using the area of the ring we will see that the radius of the inner circle is 3cm.

I assume that we have some kind of ring. To get the area of the ring, we need to take the area of the circle defined by the outer radius of the ring, and subtract the area defined by the circle with the inner radius of the ring.

Remember that the area of a circle of radius R is:

A = pi*R^2

We know that:

The radius of the outer circle is 5cm, so its area is:

A = pi*(5cm)^2 = pi*25cm^2

And the area of the ring is pi*16 cm^2

Then the area of the inner circle should be such that:

pi*25cm^2 - A' = pi*16cm^2

Then, solving for A'

A' = pi*25cm^2 - pi*16cm^2 = pi*9cm^2 = pi*(3cm)^2

So the radius of the inner circle is 3cm.

If you want to learn more about circles, you can read:

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Quadratic relations and comic sections unit test part 1

11. a. (0, +/- 6)

Answer:

a statement that your prediction was less than or greater than the actual count

a statement about how you would change your estimation process

Step-by-step explanation:

Choose any of these two.. There both correct btw

The statements that is true about your prediction of the total pennies on rows 1-4 are statement (b) and (d).

A predictive function is one of mathematical function that helps us to know about future events based on past events. There are many types of functions that can be classified as predictive functions.

The prediction was off by greater than 1,000,000 of the actual total. After seeing the result for rows 1-4, you would indeed change your prediction for the total because it indicates a significant deviation.

Complete question

Check every statement that is true about your prediction of the total pennies on rows 1-4.

a) Your prediction was off by less than or equal to 1,000,000 of the actual total.

b) Your prediction was off by greater than 1,000,000 of the actual total.

c) After seeing the result for rows 1-4, you would change your prediction for the total.

d After seeing the results for rows 1-4, you would not change your prediction for the total.

Answer:

To find the zeros of a quadratic function, use the quadratic equation, [tex]x=\frac{-b \pm \sqrt{b^2-4ac} }{2a}[/tex]. We find that the eqautions with zeros at 1 and 4 are b) x² -5x + 4 and d) -2x² + 10x - 8.

Step-by-step explanation:

a) x² + x + 4 --

[tex]x = \frac{-1 \pm \sqrt{1^2-4*1*4} }{2*1}\\x=\frac{-1 \pm \sqrt{1-16}}{2}[/tex]

Because the discriminant (the value inside the square root) is negative, this equation does not have real zeros, so it is not the answer.

b) x² - 5x + 4 --

[tex]x = \frac{5 \pm \sqrt{(-5)^2-4*1*4}}{2*1} \\x=\frac{5 \pm \sqrt{25-16}}{2} \\x = \frac{5 \pm 3}{2}[/tex]

Now, we calculate the two zeros by adding and subtracting the 3.

[tex]x = \frac{5+3}{2} \\x= \frac{8}{2} = 4\\\\x= \frac{5-3}{2} \\x= \frac{2}{2}=1[/tex]

The zeros of this function are 1 and 4, so it is included in our answer.

c) x² + 3x - 4 --

[tex]x = \frac{-3 \pm \sqrt{3^2-4*1*-4}}{2*1} \\x = \frac{-3 \pm \sqrt{9+16}}{2} \\x= \frac{-3 \pm 5}{2}\\\\x=\frac{-3+5}{2}=1\\x=\frac{-3-5}{2} = -4[/tex]

The zeros of this function are -4 and 1, so it is not the answer.

d) -2x² + 10x - 8 --

[tex]x = \frac{-10 \pm \sqrt{10^2-4*(-2)*(-8)} }{2*(-2)} \\x=\frac{-10 \pm \sqrt{100-64} }{-4} \\x = \frac{-10 \pm 6}{-4} \\\\x=\frac{-10 + 6}{-4} =1\\x = \frac{-10-6}{-4} =4[/tex]

The zeros of this function are 1 and 4, so it is included in our answer.

Answer: just add 8 + 8 and you will get 16

Your answer is the last option, -148°F

The formula to convert temperatures from Celcius to Farenheit is:
(C° x 9/5) + 32 or (C° x 1.8) + 32

So to solve, plug in -100°C and follow the order of operations (PEMDAS).

(-100 x 1.8) + 32
(-180) + 32
-148

-100°C is equal to -148°F

The freezing point of the antifreeze solution in Fahrenheit is -148 °F, calculated using the formula for converting Celsius to Fahrenheit.

To convert a temperature from the Celsius scale to the Fahrenheit scale, you can use the following formula: F = (C  imes 9/5) + 32, where F represents the Fahrenheit temperature, and C represents the Celsius temperature.

In this case, we are given the freezing point of an antifreeze solution, which is -100 °C. Applying the formula, we get F = (-100 x 9/5) + 32. This calculation gives us F = (-180) + 32, which simplifies to F = -148 °F.

So, the freezing point of the antifreeze solution on the Fahrenheit scale is -148 °F.

The exact value of the arc length of the curve is 149.4 units

How to determine the exact arc length of the curve

From the question, we have the following parameters that can be used in our computation:

[tex]y = \dfrac35x^\frac53 - \dfrac34x^\frac13 + 8[/tex]

Also, we have the interval to be

-1 ≤ x ≤ 27

This means that the x valus are

x = -1 to x = 27

The arc length of the curve can be calculated using

[tex]\text{Length} = \int\limits^a_b {\sqrt{1 + ((dy)/(dx))^2}} \, dx[/tex]

Recall that

[tex]y = \dfrac35x^\frac53 - \dfrac34x^\frac13 + 8[/tex]

So, we have

[tex]\dfrac{dy}{dy} = x^\frac{2}{3}-\dfrac{1}{4x^\frac{2}{3}}[/tex]

This means that

[tex]\text{Length} = \int\limits^{27}_{-1} {\sqrt{1 + (x^\frac{2}{3}-\dfrac{1}{4x^\frac{2}{3}})^2}} \, dx[/tex]

Using a graphing tool, we have the integrand to be

[tex]\text{Length} = \dfrac{12x^\frac{5}{3}+15\sqrt[3]{x}}{20}|\limits^{27}_{-1}[/tex]

Expand and evaluate

[tex]\text{Length} = 149.4[/tex]

Hence, the exact arc length of the curve is 149.4 units

Answer:

The solutions are B. -4 and C. -5

Step-by-step explanation:

For a quadratic equation of the form [tex]ax^2+bx+c=0[/tex] the solutions are

[tex]x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

For [tex]\mathrm{}\quad a=3,\:b=27,\:c=60:\quad x_{1,\:2}=\frac{-27\pm \sqrt{27^2-4\cdot \:3\cdot \:60}}{2\cdot \:3}[/tex]

[tex]x_1=\frac{-27+\sqrt{27^2-4\cdot \:3\cdot \:60}}{2\cdot \:3}\\\\x_1=\frac{-27+\sqrt{9}}{2\cdot \:3}\\\\x_1=\frac{-27+3}{2\cdot \:3}\\\\x_1=\frac{-24}{6} = -4[/tex]

[tex]x_2=\frac{-27-\sqrt{27^2-4\cdot \:3\cdot \:60}}{2\cdot \:3}\\\\x_2=\frac{-27-\sqrt{9}}{2\cdot \:3}\\\\x_2=\frac{-27-3}{2\cdot \:3}\\\\x_2=-\frac{30}{6} = -5[/tex]

The probability that a strawberry dessert contains whipped topping is approximately 69.2%

We are given that the probability a dessert contains strawberries (P(S)) is 26%, or 0.26, and the probability that a dessert contains both strawberries and whipped topping (P(S and W)) is 18%, or 0.18.

To find the probability that a randomly chosen strawberry dessert contains whipped topping (P(W|S)), we use the conditional probability formula:

[tex]P(W|S) = \frac{P(S and W)}{P(S)}[/tex]

Substituting the given values, we get:

[tex]P(W|S) = \frac{0.18}{0.26} \approx 0.6923[/tex]

Rounding to the nearest tenth of a percent we get the probability that a randomly chosen strawberry dessert contains whipped topping to be 69.2%.

│FV│ = │VD│

Being D the directrix. Given that the focus F is on the y-axis and the directrix is parallel to the x-axis, then the vertex V will also be on this axis, so h = 0.

As │FV│ = │VD│, then:

[tex]k = \frac{6-2}{2}[/tex], that is the middle point of the segment FD, so:

V(0,2)

Now │FV│= │p│= │2-(-2)│=4

Given that the vertex and focus are below the directrix, then the parabola open down, therefore: [tex]p\ \textless \ 0[/tex]

Lastly, the equation is:

[tex]x^{2} = -4(4)(y-2) = -16y+32[/tex]
[tex]y = -\frac{ x^{2} }{16} + 2[/tex]

The equation of a parabola with a focus at (0,-2) and a directrix of y=6 is x^2 = -16(y - 2).

To find the equation of a parabola with a focus at (0,-2) and a directrix of y=6, you need to use the standard form of the equation of a parabola that opens upwards or downwards. The general form of this type of parabola is  (x - h)^2 = 4p(y - k), where (h,k) is the vertex of the parabola, and p is the distance from the vertex to the focus (if the parabola opens upwards or downward) or to the directrix (if the parabola opens sideway).

Given that the focus is at (0,-2) and the directrix is at y=6, the vertex of the parabola will be located midway between them. The distance between the focus and directrix is 8 units, so the vertex will be 4 units from each, which puts the vertex at (0, 2). Therefore, h=0 and k=2.

Since the focus is below the directrix, our parabola opens downward, and the value of p is negative. The distance p is half the distance between the focus and directrix, so p=-4. Plugging these values into the general form, we get (x - 0)^2 = 4(-4)(y - 2), which simplifies to x^2 = -16(y - 2).

This is the equation that represents the desired parabola.

The previous population of the city was 35000.

Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.

Assume the previous population to be [x].

Then, we can write -

x + 26% of x = 44100

x + 26x/100 = 44100

x + 13x/50 = 44100

(50x + 13x)/50 = 44100

63x = 44100 x 50

63x = 2205000

x = 35000

Therefore, the previous population of the city was 35000.

To solve more questions on percentage increase, visit the link below-

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The previous population of the city was 35,000 before experiencing a 26% increase to the current population of 44,100.

To calculate the previous population of a city that has experienced a 26% increase to its current population of 44,100, we need to reverse the percentage increase. The formula for this is:

Previous population = Current population / (1 + Percentage increase)

In this case, the percentage increase is 26%, or 0.26 in decimal form. The calculation is:

Previous population = 44,100 / (1 + 0.26) = 44,100 / 1.26

This gives us:

Previous population = 35,000 (rounded to the nearest whole number)

Hence, the previous population of the city was approximately 35,000 before the 26% increase to the current 44,100.

1. B. Counterclockwise

2. C. (30,401)

3. A. t=2(x-3)

4. C. She should have taken both the positive and negative square root

5. C. y=x^2+8x-25/8

6. D. Hyperbola

7. A. Graph A

The graph of the function (f(x) = -14x - 2) is attached below and the two points from which line passes are (-0.143,0) and (0,-2).

Given :

Equation  --  f(x) = -14x - 2

The following steps can be used in order to sketch the graph of the given function:

Step 1 - Write the given function.

f(x) = -14x - 2

Step 2 - Now, evaluate the x-intercept of the above function.

0 = -14x - 2

x = -1/7

Step 3 - Now, determine the y-intercept of the given function.

f(x) = -2

Step 4 - Now, graph the equation of a line that passes through the points (-1/7,0) and (0,-2).

The graph of the function is attached below.

For more information, refer to the link given below:

https://brainly.com/question/14375099

Answer:

D) 40 miles

Step-by-step explanation:

First we must find the distance between the mall and the house.  The figure formed is a right triangle.  The length of the side from the mall to the house forms the hypotenuse of the triangle.  We can use the Pythagorean theorem to find the length:

a² + b² = c²

The two legs of the triangle, a and b, are 15 and 8:

15² + 8² = c²

225 + 64 = c²

289 = c²

Take the square root of each side:

√289 = √(c²)

17 = c

This makes the total distance

15+8+17= 40 miles

Hey! Pretty easy once you get the hang of these problems.

So you start off with the Pythagorean Theorem. Which is : a^2 + b^2 = c^2

Then just fill it in :

15^2 + 8^2 = c^2

225 + 64 = c2

289 = c^2

17 = c

And last :

15 + 8 + 17 = 40 MILES

hoped this helped!! :))