Answer:
1 yard
Step-by-step explanation:
Simplify the expression 13+(x+8)
Answer:x+21
Step-by-step explanation:
EXAMPLE 4 Find the moments of inertia Ix, Iy, and I0 of a homogeneous disk D with density rho(x, y) = rho, center the origin, and radius a. SOLUTION The boundary of D is the circle x2 + y2 = a2 and in polar coordinates D is described by 0 ≤ θ ≤ 2π, 0 ≤ r ≤ a. Let's compute I0 first: I0 = D (x2 + y2)rho dA = rho 2π 0 a 0 r2 r dr dθ = rho 2π 0 dθ a 0 r3 dr = 2πrho a 0 = . Instead of computing Ix and Iy directly, we use the facts that Ix + Iy = I0 and Ix = Iy (from the symmetry of the problem). Thus Ix = Iy = I0 2 = .
The moments of inertia are [tex]\( I_x = I_y = \frac{\pi \rho a^4}{4} \)[/tex] and [tex]\( I_0 = \frac{\pi \rho a^4}{2} \).[/tex]
Example 4 involves finding the moments of inertia [tex]\( I_x \)[/tex], [tex]\( I_y \)[/tex], and [tex]\( I_0 \)[/tex] of a homogeneous disk [tex]\( D \)[/tex] with density [tex]\( \rho(x, y) = \rho \)[/tex], centered at the origin, and radius [tex]\( a \)[/tex].
To compute [tex]\( I_0 \)[/tex], we integrate [tex]\( (x^2 + y^2) \rho \)[/tex] over the disk [tex]\( D \)[/tex] using polar coordinates. The bounds for [tex]\( \theta \)[/tex] are [tex]\( 0 \)[/tex] to [tex]\( 2\pi \)[/tex], and for [tex]\( r \)[/tex] are [tex]\( 0 \)[/tex] to [tex]\( a \).[/tex]
[tex]\[ I_0 = \int \int_D (x^2 + y^2) \rho \, dA = \rho \int_0^{2\pi} \int_0^a r^3 \, dr \, d\theta = \frac{2\pi \rho a^4}{4} = \frac{\pi \rho a^4}{2} \][/tex]
Since the disk is symmetric about both the x-axis and y-axis, [tex]\( I_x = I_y = \frac{I_0}{2} = \frac{\pi \rho a^4}{4} \).[/tex]
The answer is [tex]\( I_0 = \frac{1}{2} \rho a^4 \pi \).[/tex]
To find the moments of inertia[tex]\( I_x \) and \( I_y \) of a homogeneous disk \( D \) with density \( \rho(x, y) = \rho \),[/tex] centered at the origin, and radius \( a \), we use the following formulas:
[tex]\[ I_x = \int \int_D y^2 \rho(x, y) \, dA \]\[ I_y = \int \int_D x^2 \rho(x, y) \, dA \]where \( dA \) represents the differential area element in polar coordinates.[/tex]
For a disk, we use polar coordinates [tex]\( (r, \theta) \), where \( r \) represents the radius and \( \theta \)[/tex] represents the angle.
The density [tex]\( \rho \)[/tex] is constant, so it can be pulled out of the integrals.
We integrate over the disk, which has a radius [tex]\( a \), and \( \theta \) ranging from \( 0 \) to \( 2\pi \).[/tex]
[tex]Let's calculate \( I_x \):\[ I_x = \int_0^{2\pi} \int_0^a (r \sin \theta)^2 \rho \cdot r \, dr \, d\theta \]\[ = \rho \int_0^{2\pi} \int_0^a r^3 \sin^2 \theta \, dr \, d\theta \]\[ = \rho \int_0^{2\pi} \left[ \frac{1}{4} r^4 \sin^2 \theta \right]_0^a \, d\theta \]\[ = \rho \int_0^{2\pi} \frac{1}{4} a^4 \sin^2 \theta \, d\theta \]\[ = \rho \cdot \frac{1}{4} a^4 \int_0^{2\pi} \sin^2 \theta \, d\theta \]\[ = \rho \cdot \frac{1}{4} a^4 \cdot \pi \][/tex]
Using the trigonometric identity [tex]\( \sin^2 \theta = \frac{1 - \cos(2\theta)}{2} \) and integrating from \( 0 \) to \( 2\pi \), the integral of \( \sin^2 \theta \) over one period is \( \pi \), and thus, the integral over \( 2\pi \) periods is \( 2\pi \).[/tex]
[tex]So, \( I_x = \rho \cdot \frac{1}{4} a^4 \cdot \pi \).Similarly, for \( I_y \), the integral will be:\[ I_y = \rho \int_0^{2\pi} \int_0^a (r \cos \theta)^2 \rho \cdot r \, dr \, d\theta \]\[ = \rho \int_0^{2\pi} \int_0^a r^3 \cos^2 \theta \, dr \, d\theta \]\[ = \rho \cdot \frac{1}{4} a^4 \cdot \pi \]Thus, \( I_y = \rho \cdot \frac{1}{4} a^4 \cdot \pi \), which is the same as \( I_x \).[/tex]
Now, for the moment of inertia \( I_0 \) about the origin:
[tex]\[ I_0 = I_x + I_y = 2 \rho \cdot \frac{1}{4} a^4 \cdot \pi \][/tex]
So, [tex]\( I_0 = \frac{1}{2} \rho a^4 \pi \).[/tex]
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I get HOW to make a box and whisker plot. What I don't get is WHY you would want to make one. From a practical point of view, what can it teach you?
Answer:
I'd say go to Wikipedia and look it up. It is something that cannot be summarized into just a few words.
Step-by-step explanation:
Find the savings plan balance after 18 months with an APR of 2% and monthly payments of $200.
The balance is $ 1
(Do not round until the final answer. Then round to the nearest cent as needed.)
Answer:
$800 [((1.005)18 - 1)/.005]
$800 x [(1.0939 - 1)/.005]
$800 x (0.0939/0.005)
$800 x 18.785
~ $15,028
The savings plan is 15,028.
Step-by-step explanation:
The savings plan balance on the account after 18 months is $3651.46.
What is the balance after 18 months?Basically, the savings plan balance means the total amount of money saved and accumulated in a designated account or investment over a period of time.
The savings plan balance will be found using annuity formula [tex]P * [(1 + r)^n - 1] / r[/tex]
Data:
P = Monthly payment = $200r = Monthly interest rate = 0.02 / 12 = 0.00166667n = Number of months = 18The plan balance will be:
= 200 * [(1 + 0.00166667)^18 - 1] / 0.00166667
= 200 * 18.2572814188
= 3651.45628376
= 3651.46.
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abby is making a maze for her pet mouse the diameter of the maze is 24 what is the circumference
Answer:
75.36
Step-by-step explanation:
To find the diameter, take the radius and multiply it by two, or use the diameter, and then multiply by pi. The formula, in this case, would be pi x 24. I hope this helps. I used 3.14, the shorter version, but a more precise answer would be 75.3982236862, or 75.4 rounded.
Which value of x makes x-16=32true?
Answer:
48
Step-by-step explanation:
32+16=48
48-16=32
Answer:
48
Step-by-step explanation:
add 32 and 16 to get 48
orange jelly beans is 82 and that exam scores have an approximately symmetric distribution. She gives orange jelly beans to 25 randomly selected students and finds that these students had a sample mean score of 87 with a sample standard deviation of 10. She wants to have 95% confidence in her result. 27. Conduct a hypothesis test using the confidence interval approach. Write your answer on paper and upload a photo or scan, or else put your answer in an electronic file and upload the file. In order to earn full credit your answer must include all of the following: A statement of the confidence interval in a complete sentence using the appropriate statistical symbol. Include two decimal points in your numbers. The statistical criterion you use to determine whether to reject or fail to reject the hypothesis. The result of your test in statistical terms
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 82
For the alternative hypothesis,
µ ≠ 82
This is a 2 tailed test
Since the sample mean and sample standard deviation is given, the t test would be used to determine the test statistic. The formula is
t = (x - µ)/(s/√n)
Where
x = sample mean = 87
µ = population mean = 82
s = samples standard deviation = 10
n = 25
t = (87 - 82)/(10/√25) = 2.5
α = 1 - Confidence level
α = 1 - 0.95 = 0.05
Since α = 0.05, the critical value is determined from the t distribution table.
For the left, α/2 = 0.05/2 = 0.025
For the right of 0.025 = 1 - 0.025 = 0.975
To determine the t score from the t distribution table, we would find the degree of freedom, df and look for the corresponding α value.
df = n - 1 = 25 - 1 = 24
t score = critical value = ±2.064
In order to reject the null hypothesis, the test statistic must be smaller than - 2.5 or greater than 2.5
Since - 2.064 > - 2.5 and 2.064 < 2.5, we would fail to reject the null hypothesis.
Confidence interval is written in the form,
(Sample mean - margin of error, sample mean + margin of error)
Margin of error = z × s/√n
Where
s = sample standard deviation
z = t score
Margin of error = 2.064 × 10/√25
= 4.13
Confidence interval = 87 ± 4.13
the lower limit of this confidence interval is
87 - 4.13 = 82.87
the upper limit of this confidence interval is
87 + 4.13 = 91.13
Five samples of a ferrous-type substance are to be used to determine if there is a difference between a laboratory chemical analysis and an X-ray fluorescence analysis of the iron content. Each sample was split into two sub-samples and the two types of analysis were applied. Following are the coded data showing the iron content analysis:
Sample
Analysis 1 2 3 4 5
X-rays 2.0 2.0 2.3 2.1 2.4
Chemical 2.2 1.9 2.5 2.3 2.4
Assuming that the populations are normal, test at the 0.05 level of significance whether the two methods of analysis give, on the average, the same result.
Step-by-step explanation:
Step 1
From the given information,
number of ferrous-type substance, n = 5
Let [tex]\mu_1[/tex] and [tex]\mu_2[/tex] are the true population average for laboratory chemical and X-ray flourescence analysis
Level of significance, [tex]\alpha = 0.05[/tex]
state the null and alternative hypotheses
[tex]H_0 : \mu_1 - \mu_2 = 0\\\\H_1 : \mu_1 - \mu_2 \neq 0[/tex]
Attached are steps 2 to 7 of the remaining solution
Yes, the two methods of analysis give, on average, the same result and this can be determined by using the given data.
Given :
Five samples of a ferrous-type substance are to be used.Each sample was split into two sub-samples and the two types of analysis were applied.0.05 level of significance.The mean of the first sample is:
[tex]\bar{X_1} = \dfrac{\sum X_1}{n_1}[/tex]
[tex]\bar{X_1} = \dfrac{ 10.8}{5}=2.16[/tex]
Now, the standard deviation of the first sample is:
[tex]S_1 =\sqrt{\dfrac{\sum(X_1-\bar{X_1})^2}{n_1-1}}[/tex]
[tex]S_1 =\sqrt{\dfrac{0.132}{4}}=0.182[/tex]
The mean of the second sample is:
[tex]\bar{X_2} = \dfrac{\sum X_2}{n_2}[/tex]
[tex]\bar{X_2} = \dfrac{ 11.3}{5}=2.26[/tex]
Now, the standard deviation of the second sample is:
[tex]S_2 =\sqrt{\dfrac{\sum(X_2-\bar{X_2})^2}{n_2-1}}[/tex]
[tex]S_2 =\sqrt{\dfrac{0.212}{4}}=0.230[/tex]
Now, the hypothesis test is given below:
Null Hypothesis -- [tex]H_0:\mu_1=\mu_2[/tex]
Alternative Hypothesis -- [tex]H_a:\mu_1\neq \mu_2[/tex]
The degree of freedom is calculated as:
[tex]df=n_1+n_2-2\\df=8[/tex]
Now, the formula of the test statistics is given below:
[tex]t = \dfrac{(\bar{X_1}-\bar{X_2})-(\mu_1-\mu_2)}{\sqrt{\dfrac{S^2_1}{n_1}+\dfrac{S^2_2}{n_2}} }[/tex]
[tex]t = \dfrac{2.16-2.26}{\sqrt{\dfrac{(0.182)^2}{5}+\dfrac{(0.230)^2}{5}} }[/tex]
[tex]t = -0.76238688[/tex]
Now, according to the t-value, the p-value is 0.46771. Therefore, the null hypothesis is not rejected.
So, yes the two methods of analysis give, on average, the same result.
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finding the size of angle x on a straight line. 2 of the angles are 29 degree and 82 degrees
Answer:
x = 111°
Step-by-step explanation:
We know that angles in a triangle add up to 180°
Step 1: Find angle supplementary to x
82 + 29 + x = 180
111 + x = 180
x = 69°
Step 2: Find angle x
Both the angles are supplementary, meaning they add up to 180°.
x + 69 = 180
x = 111°
Answer:
Easy = 111 degrees
Step-by-step explanation:
Find the percentage of people in the sample who prefer blue.
There is no sample given, please provide us with an attachment for your answer.
In a study conducted to examine the quality of fish after 7 days in ice storage, ten raw fish of the same kind and approximately the same size were caught and prepared for ice storage. The fish were placed in ice storage at different times after being caught. A measure of fish quality was given to each fish after 7 days in ice storage. Review the accompanying sample data and scatterplot, where "Time" is the number of hours after being caught that the fish was placed in ice storage and "Fish Quality" is the measure given to each fish after 7 days in ice storage (higher numbers mean better quality). Is it appropriate to use the correlation coefficient to describe the strength of the relationship between "Time" and "Fish Quality"?
It is appropriate to use the correlation coefficient to describe the strength of the relationship between "Time" and "Fish Quality" in this study. The correlation coefficient measures the strength and direction of the linear relationship between two variables.
Explanation:It is appropriate to use the correlation coefficient to describe the strength of the relationship between "Time" and "Fish Quality" in this study. The correlation coefficient measures the strength and direction of the linear relationship between two variables. In this case, "Time" and "Fish Quality" are both continuous variables, and a scatterplot can be used to visually represent their relationship.
In the scatterplot, if the data points form a clear pattern or trend, it suggests a strong relationship between the variables. The correlation coefficient quantifies this relationship, ranging from -1 (perfect negative relationship) to 1 (perfect positive relationship), with 0 indicating no linear relationship. By calculating the correlation coefficient, we can determine the strength and direction of the relationship between "Time" and "Fish Quality" in the study.
Keywords: correlation coefficient, relationship, variables, scatterplot, strength, direction, linear, continuous
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Which expression is equivalent to:
16(w+q)
A. (m + 16) (w + 16) B.16w + 169
C. 16w +9
D. W + 169
The equivalent expression to 16(w+q) is 16w + 16q, but none of the given options A, B, C, or D are correct as they do not accurately represent this distribution. The closest option would be C (16w + 9), though it is still incorrect because it has 9 instead of 16q.
Explanation:The question asks which expression is equivalent to 16(w+q). The correct way to distribute a constant over a sum inside parentheses is to multiply each term inside the parentheses by that constant. So, 16 must be multiplied by both w and q.
Therefore, the equivalent expression is 16w + 16q. Looking at the provided options:
A. (m + 16) (w + 16) includes additional terms and multiplication not present in the original expression.B. 16w + 169 includes the term 169, which is not correct since no such number results from multiplying 16 by q.C. 16w + 16q is correct, but as given in the option just as 16w + 9 it is incorrect because it has 9 instead of 16q.D. w + 169 does not multiply w by 16 and includes the incorrect number 169.Since none of the given options are exactly 16w + 16q, no available option is a correct equivalent expression to 16(w+q).
Many investors and financial analysts believe the Dow Jones Industrial Average (DJIA) provides a good barometer of the overall stock market. On January 31, 2006, 9 of the 30 stocks making up the DJIA increased in price (The Wall Street Journal, February 1, 2006). On the basis of this fact, a financial analyst claims we can assume that 30% of the stocks traded on the New York Stock Exchange (NYSE) went up the same day.
1. Formulate null and alternative hypotheses to test the analyst's claim.
H0: p
Ha: p
2. A sample of 50 stocks traded on the NYSE that day showed that 24 went up. What is your point estimate of the population proportion of stocks that went up (to 2 decimals)?
3. Conduct your hypothesis test using = .01 as the level of significance.
Calculate the value of the test statistic (to 2 decimals).
What is the p-value (to 4 decimals)?
Can you conclude that the proportion of stocks going up is not .30?
Answer:
1) H0: p=0.3
Ha: p≠0.3
2) 0.48
3)•2.78
•0.0054. So, we reject H0.
• No, we cannot conclude
•
Step-by-step explanation:
1) To formulate the null and alternative hypothesis:
• Null hypothesis:
[tex] H_0: p=0.3 [/tex]
•Alternative hypothesis:
Ha: p≠0.3
2) Point estimate of the population proportion stocks that went up:
Since sample is 50 stocks and 24 went up, we have phat as:
[tex]phat = \frac{24}{50} = 0.48[/tex]
3) • Hypothesis test using 0.01 as level of significance:
Test statistic =
[tex] Z = \frac{phat-p}{\sqrt{\frac{p*(1-p)}{n}}}[/tex]
[tex] = \frac{0.48-0.3}{\sqrt{\frac{0.3*0.7}{50}}}[/tex]
= 2.78
•Using standard normal table
P value =
2*(P>2.78) = 0.0054
• The p value (0.0054) is less than level of significance (0.01), we reject null hypothesis H0.
• No, we cannot conclude that the proportion of stocks going up is not .30
Sam parents agreed to let him buy a new video game systemic he paid for half of it. His parents gave him the $170 for their portion. If Sam has saved $109.85 so far, how much more does he need before heading to the store?
Answer:
60.15
Step-by-step explanation:
if he needs to pay 170 and he has 109.85
170-109.85=60.15
so he needs 60 dollars and 15 cents to reach his goal
cuantas unidades mide el lado QR? cual es la distancia entre los puntos P y R
Answer:
Part A) [tex]QR=2\sqrt{5}\ units[/tex]
Part B) [tex]PR=2\sqrt{13}\ units[/tex]
Step-by-step explanation:
The complete question in English is
Observe the isosceles PQRS trapeze in the Cartesian plane.
A) How long is the QR side?
B) What is the distance between points P and R?
The picture of the question in the attached figure
we know that
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
Part A) How long is the QR side?
we have the coordinates
Q(7,6) and R(9,2)
substitute in the formula
[tex]d=\sqrt{(2-6)^{2}+(9-7)^{2}}[/tex]
[tex]d=\sqrt{(-4)^{2}+(2)^{2}}[/tex]
[tex]d_Q_R=\sqrt{20}\ units[/tex]
simplify
[tex]d_Q_R=2\sqrt{5}\ units[/tex]
Part B) What is the distance between points P and R?
we have the coordinates
P(3,6) and R(9,2)
substitute in the formula
[tex]d=\sqrt{(2-6)^{2}+(9-3)^{2}}[/tex]
[tex]d=\sqrt{(-4)^{2}+(6)^{2}}[/tex]
[tex]d_P_R=\sqrt{52}\ units[/tex]
simplify
[tex]d_P_R=2\sqrt{13}\ units[/tex]
A waiter served 12 customers at lunch. Then he worked the dinner shift and served 5 new customers per hour. Write an equation that represents the number of customers the waiter served over lunch and dinner. Identify the x and y variables and explain the meaning of the slope and y-intercept.
The question is asking to find an equation of how many customers the waiter served.
Given: 12 customers at lunch; 5 per hour for dinner
Find: number of customers served at lunch AND dinner
We use variables for this, x and y. A general equation is usually y=ax+b, where y is the solution, x is the variable, and a and b are numbers.
Knowing this information, since it is already given that 12 customers were served, the equation turns into y=ax+12
Additionally, since we don't know how many hours she worked, we can use that as a variable. y=5x+12
x=how many hours the waiter worked at dinner
y=overall hours the waiter worked at both lunch and dinner
slope=5, means customers are going up 5 every hour
y-intercept=12, the given/starting point on the y-axis
a box of cookies contain 12 chocolate chip cookies, 6 peanut butter cookies, and 6 sugar cookies, what is the probability of selecting a sugar cookie?
Answer:
The answer of this question is 1/4
Step-by-step explanation:
Total no of cookies=12+6+6=24
No.sugar cookies=6
Probability= Possible outcomes/total no of outcomes
= 6/24
= 1/4
6(2x-5y)-2(x+9y) simplified
Answer:
10x-48y
Step-by-step explanation:
What's the answer to 1/2(x+4)^2-5+=3.
Answer:
x = 0
Step-by-step explanation:
To solve this equation you would need to get x by itself on one side
1/2 (x+4)^2 - 5 = 3
1.) add 5 to both sides
1/2 (x+4)^2 = 8
2.) divide each side by 1/2
(x+4)^2 = 16
3.) find the square root of both sides
(x+4) = 4
4.) subtract 4 from both sides
x = 0
The app "Photomath" is a great way to solve problems like these and it gives a step by step explanation that might be easier to understand than mine :)
Segments ~ Clementine is a kind of mandarin introduced into Florida by the United States Department of Agriculture in 1909. Historically, on average, clementine have 10.25 segments. A fruit lover bought 100 clementine and found that there were 10.66 mean number of segments with a standard deviation of 2.0712. The fruit lover wonders if the actual mean number of segments is more than the historic value and wants to carry out a hypothesis test. What are the null and alternative hypothesis? Question 2 options: Null hypothesis Alternative hypothesis 1. μ = 10.25 2. x⎯⎯ = 10.66 3. μ > 10.25 4. x⎯⎯ > 10.66 5. μ > 10.66 6. x⎯⎯> 10.25 7. μ ≠ 10.25 8. x⎯⎯ ≠ 10.66
Answer:
Step-by-step explanation:
The null hypothesis is the hypothesis that is assumed to be true. It is an expression that is the opposite of what the researcher predicts.
The alternative hypothesis is what the researcher expects or predicts. It is the statement that is believed to be true if the null hypothesis is rejected.
From the given situation,
Historically, on average, clementine have 10.25 segments. This is the null hypothesis.
The fruit lover wonders if the actual mean number of segments is more than the historic value. This is the alternative hypothesis.
Therefore, the correct null and alternative hypotheses are
H0: μ = 10.25 and HA: μ > 10.25
The null hypothesis for the test is that the population mean number of clementines segments is equal to the historic value (μ = 10.25). The alternative hypothesis is that the population mean number of clementines segments is greater than the historic value (μ > 10.25). The test will determine whether to accept or reject the null hypothesis.
Explanation:In conducting a hypothesis test, the null hypothesis is the statement that is assumed to be true, whereas the alternative hypothesis is what the test is attempting to prove. In this instance, if we are questioning whether the actual mean number of segments in a clementine is more than the historic value, we set our null and alternative hypothesis as follows:
Null Hypothesis (H0): μ = 10.25Alternative Hypothesis (Ha): μ > 10.25In this context, μ represents the population mean number of segments, whilst '10.25' is the historical mean number of segments. The test will determine if there is strong enough evidence to reject the null hypothesis in favour of the alternative hypothesis, hence proving that the mean number of segments is indeed greater than 10.25.
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The decreasing function M represents the mass of a sample of a radioactive element at time t. The rate of change of the sample’s mass is proportional to the mass of the sample. Which of the following differential equations could be used to model the relationship between the mass of the sample and the rate of change of the sample’s mass, where k is a constant?A)dM =kt dtb) d - = KM dtc)DMd)dᎷ .
Answer:
[tex](B) \dfrac{dM}{dt} = kM[/tex]
Step-by-step explanation:
Given the mass M(a decreasing function) of a sample of a radioactive element at time t.
The rate of change of the sample’s mass [tex]\dfrac{dM}{dt}[/tex], is proportional to the mass, M of the sample.
This is written as:
[tex]\dfrac{dM}{dt} \propto M[/tex]
Introducing the decay constant k,
[tex]\dfrac{dM}{dt} = kM[/tex]
This is the equation which model the relationship between the mass of the sample and the rate of change of the sample’s mass.
The other options are therefore invalid.
[tex](A)\dfrac{dM}{dt} = kt (C)\dfrac{dM}{dt} = \dfrac{k}{t} (D)\dfrac{dM}{dt} = \dfrac{k}{M}[/tex]
The correct differential equation is [tex]\(\frac{dM}{dt} = kM\)[/tex], option B) indicating the rate of change of mass is proportional to the mass.
1. Understanding the Problem Statement:
- The mass [tex]\(M\)[/tex]of a sample of a radioactive element is a decreasing function of time [tex]\(t\).[/tex]
- The rate of change of the sample's mass is proportional to the mass of the sample itself.
2. Translating the Statement into a Mathematical Form:
- When a quantity is said to change at a rate proportional to its current value, we can express this mathematically as:
[tex]\[ \frac{dM}{dt} \propto M \][/tex]
- This means the rate of change of [tex]\(M\)[/tex] with respect to time [tex]\(t\)[/tex] is proportional to [tex]\(M\).[/tex]
3. Introducing a Proportionality Constant:
- To express this proportionality as an equation, we introduce a constant of proportionality [tex]\(k\):[/tex]
[tex]\[ \frac{dM}{dt} = kM \][/tex]
- Here, [tex]\(k\)[/tex] is a constant that determines the rate at which [tex]\(M\)[/tex] changes with respect to [tex]\(t\).[/tex]
4. Evaluating Given Differential Equations:
- We need to find which of the provided differential equations matches the relationship [tex]\(\frac{dM}{dt} = kM\).[/tex]
The given differential equations are:
[tex]\[ \begin{aligned} & \frac{dM}{d} = kt \\ & \frac{dM}{dt} = kM \\ & \frac{dM}{d} = \frac{A}{2} \\ & \frac{dM}{d} = \frac{k}{M} \end{aligned} \][/tex]
5. Matching with the Correct Equation:
- Comparing each option with [tex]\(\frac{dM}{dt} = kM\):[/tex]
[tex]- \(\frac{dM}{d} = kt\)[/tex] does not match since it suggests the rate of change depends on [tex]\(t\), not \(M\).[/tex]
[tex]- \(\frac{dM}{dt} = kM\)[/tex] matches our derived equation perfectly.
[tex]- \(\frac{dM}{d} = \frac{A}{2}\)[/tex] suggests a constant rate of change, which does not depend on [tex]\(M\).[/tex]
[tex]- \(\frac{dM}{d} = \frac{k}{M}\)[/tex] suggests an inverse relationship, which is incorrect.
6. Conclusion:
- The differential equation that models the relationship between the mass of the sample and the rate of change of the mass is:
[tex]\[ \frac{dM}{dt} = kM \][/tex]option B)
Complete Question:
Identify the level of measurement of the data, and explain what is wrong with the given calculation. In a survey, the hair colors of respondents are identified as 100 for brown hair comma 200 for blond hair comma 300 for black hair comma and 400 for anything else. The average (mean) is calculated for 604 respondents and the result is 256.1 .
Answer:
This type of data are not measurement of anything , so it is not feasible to calculate their average(Mean)
Step-by-step explanation:T
The data are at the level of measurement that are Nominal
In level of nominal measurement, letters, numeric and alpha-numeric, words, symbols are used to classify data in the example stated.
Now we recall that,
Brown hair = 100,
Blond hair = 200,
Black hair = 300
Anything else = 400
Thus, 100, 200, 300, 400 are used as code numbers for hair colors and does not have any importance to their values numerically.
There is no arithmetic solutions such as average, total which cannot be solved using these numbers.
Therefore the average mean calculated is not feasible
Answer:
The level of measurement of the date is: nominal level of measurement.
Such data are not counts or measures of anything, so it makes no sense to compute their average (mean)
Step-by-step explanation:
The given data are at the nominal level of measurement. Nominal data is not measurable and cannot be ordered as well. It is qualitative in nature and not quantitative. For example this nominal data type can be measured of categorized as yes or no, high or low, mild, moderate or severe, male or female etc. So there is no point of calculating average of such qualitative data and nominal level of measurement deals with qualitative variables.
Suppose you deposit $500 in a bank account that pays 8% annual simple
interest. Find the interest earned after 3 years.
Answer:
120
Step-by-step explanation:
I=prt . Where: P = Principal Amount; I = Interest Amount; r = Rate of Interest per year in decimal and time t should be in the same time units such as months or years.
I=500(.08)(3)
Answer:
8% of 500 is 40, For the first year is 540. 8% of 540 is 43.20 dollars. 8% of 583.2 is 46.656. So the total is 630 by rounding but the actual amount is 629.956. The interest is 129.956
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You wish to determine the effectiveness of taking Omega-3 tablets to lower a person’s cholesterol. To determine this, you collect data on the cholesterol level of 50 individuals before and after a 6-week course of Omega-3 tablets. Which test would determine if this treatment was effective? a. Two-Sample t-test for means b. Two-Sample z-test for means c. Matched-Pairs t-test d. Two-Sample z-test for proportions
Answer:
Option C - Matched-Pairs t-test
Step-by-step explanation:
Looking at the options given,
-Two-Sample t-test for means is used to test the difference (d0) between two population means. A common application is to determine whether the means are equal. This can't apply to the question as it determine if this treatment was effective.
- Two-Sample z-test for means is used to test the null hypothesis that there is no difference between the means of two independent populations. This doesn't determine if this treatment was effective
-Matched-Pairs t-test is used to test whether there is a significant mean difference between two sets of paired data. This will be sufficient to determine if this treatment was effective
-Two-Sample z-test for proportions is used when we want to know whether two populations or groups (e.g., males and females; theists and atheists) differ significantly on some single (categorical) characteristic - for example, whether they are vegetarians. This can't be used to determine if this treatment was effective
The only correct option is Matched-Pairs t-test
To evaluate the effectiveness of Omega-3 tablets for lowering cholesterol, a Matched-Pairs t-test should be used, as it compares the cholesterol levels before and after treatment in the same individuals.
Explanation:To determine the effectiveness of taking Omega-3 tablets to lower a person's cholesterol, one should use a statistical hypothesis test that compares two related samples. In this case, the comparison is between cholesterol levels before and after the 6-week course. Since the same individuals are tested twice, the appropriate test is the Matched-Pairs t-test (also known as the paired sample t-test or dependent sample t-test). This test is utilized when you have two sets of related data and want to assess if their means differ. The differences between each pair will follow a normal distribution if certain conditions are met, which is assumed in a matched-pairs t-test.
Learn more about Matched-Pairs t-test here:https://brainly.com/question/15365572
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Calculate social security taxes
Answer:
there is no any number to caculate social security tax.
Step-by-step explanation:
Social Security taxes are calculated using a deduction rate of 6.2% and 1.45% for Medicare from an employee's gross annual income. Employers also contribute matching amounts. However, the economic impact of employers' contributions often invariably impact employees indirectly.
Explanation:To calculate social security taxes, you need to consider a standard deduction rate of 6.2% for the Social Security and 1.45% from Medicare. These deductions are generally taken directly out of the employee's gross annual income. Employers also contribute matching percentages. However, it is important to note that in reality, the burden of the employer's contribution may in effect fall on the employee as it can result in lower wages. For instance, for those considered as independent contractors or members of the 'gig economy' receiving a 1099 tax statement, the individual must pay both the employer and employee portion of the social security and Medicare taxes.
Learn more about Social Security Taxes here:https://brainly.com/question/29032156
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Suppose that f (400 )equals3000 and f prime (400 )equals10. Estimate each of the following. (a) f (401 )(b) f (400.5 )(c) f (399 )(d) f (398 )(e) f (399.75 )
Answer:
a) [tex]f(401) = 3010[/tex], b) [tex]f(400.5) = 3005[/tex], c) [tex]f(399) = 2990[/tex], d) [tex]f(398) = 2980[/tex], e) [tex]f(399.75) = 2997.5[/tex]
Step-by-step explanation:
The estimation of each value can be found by the following value:
[tex]f(x + \Delta x) = f(x) + f'(x)\cdot \Delta x[/tex]
a) [tex]f(401) = 3000 + 10\cdot (401-400)[/tex]
[tex]f(401) = 3010[/tex]
b) [tex]f(400.5) = 3000 + 10\cdot (400.5 - 400)[/tex]
[tex]f(400.5) = 3005[/tex]
c) [tex]f(399) = 3000 + 10\cdot (399 - 400)[/tex]
[tex]f(399) = 2990[/tex]
d) [tex]f(398) = 3000 + 10\cdot (398-400)[/tex]
[tex]f(398) = 2980[/tex]
e) [tex]f(399.75) = 3000 + 10\cdot (399.75-400)[/tex]
[tex]f(399.75) = 2997.5[/tex]
in 2010 an enormous sinkhole suddenly appeared in the middle of a guatemalan neighborhood and swallowed a three story building above it. the sinkhole has an estimated depth of about 100 feet/ how much material is needed to fill the sinkhole? determine what information is needed to answer the question. do you think your estimate is more likely to be too high or too low
Answer:
Step-by-step explanation:
Given that :
The enormous sinkhole that appeared in the middle of Guatemalan neighborhood in the year 2010 swallowed a three story building above it and the sinkhole has an estimated depth of about 100 feet
How much material is needed to fill the sinkhole?
Then , the material needed to fill the sinkhole will be dependent on the volume of the sinkhole.
Determine what information is needed to answer the question.
The information that is needed to answer this question are:
the base area of the sinkhole will be required; &
the height should also be known
if the base area is determined then we can proceed to determine how much material is needed to be calculated.
Do you think your estimate is more likely to be too high or too low
No, the estimate is not likely to be too high or too low rather the estimate of the material required will be almost equal to the volume of the sinkhole, but that does not implies that it will be exactly the same since the sinkhole is not uniform and regular in shape.
On a recent Saturday, a total of 1086 people visited a local library. Of these people, 269 were under age 10, 466 were aged 10–18, 185 were aged 19–30, and the rest were more than 30 years old. One person is sampled at random. What is the probability that the person is more than 30 years old?
Answer:
The probability that the person is more than 30 years old is 0.153
Step-by-step explanation:
We can obtain the probability that the person sampled is more than 30 years old by dividing the amount of peope with more than 30 years old with the total amount of people that visited the library that Saturday, in other owrds, 1086.
The number of people with more than 30 years old can be obtained by substracting from 1086 (the total amount) the total amount of people with 30 years or less.
There are 269 (under 10) + 466 (between 10 and 18) + 185 (between 19 and 30) = 920 people under 30 years old. Therefore, the total amount of people with more than 30 years old is 1086-920 = 166, and the probability that a person selected is from that group is 166/1086 = 0.153
David's gasoline station offers 4 cents off per gallon if the customer pays in cash and does not use a credit card. Past evidence indicates that 40% of all customers pay in cash. During a one-hour period, 15 customers buy gasoline at this station.
(a) What is the probability that more than 8 and less than 12 customers pay in cash?
Answer:
0.09312
Step-by-step explanation:
15C9×0.4⁹×0.6⁶ + 15C10×0.4¹⁰×0.6⁵ × 15C11×0.4¹¹×0.6⁴
0.09311963893
Show a number line to the inequality x-1>2
Answer:
see below
Step-by-step explanation:
x-1>2
Add 1 to each side
x-1+1>2+1
x >3
There would be an open circle at 3 and a line to the right