How does a hydronium ion molecule form?
A) Evaporation.
B) Two water molecules bonded.
C) A water molecule gained an hydrogen ion from another water molecule.
D) A hydrogen molecule bonded with an OH- molecule.
E) A water molecule split in half

Answer:

Hello My friend! The balanced reaction its: 2Al(s) + 3CuSO4(aq) –> Al2(SO4)3(aq) + 3Cu(s)

Explanation:

In this case an oxidation reaction involving the metallic aluminum occurred;

Al (s) -> Al3 + (aq) + 3e–

and reduction reaction involving copper;

2e– + Cu2 + (aq) -> Cu (s)

Answer:

2Al(s) + 3CuSO4(aq) → Al2(SO4)3(aq) + 3Cu(s)  

Single replacement reaction

Explanation:

From the picture above the reaction is between aluminium and copper(ii) tetraoxosulphate .

The chemical reaction can be represented with a chemical equation as follows:

Al(s) + CuSO4(aq) → Al2(SO4)3(aq) + Cu(s).

In a chemical reaction we have the reactant side and the product side. The reactant side is at the left hand side while the product is at the right hand side.

The number of atom of element should be equal in number on both sides for the chemical equation to be balanced .

2Al(s) + 3CuSO4(aq) → Al2(SO4)3(aq) + 3Cu(s)  

The equation is balanced now as we have 2 atoms of aluminium on the reactant and product sides., 3 atoms of copper on both sides, 3 atoms of S and 12 atoms  of O on both sides.

The reaction type is a single replacement reaction. The more reactive aluminium displaced copper from it compound.  

Answer: There is no solution for the required amount of butanoic acid.

Explanation:

We are given:

Mass of butanoic acid needed = 60.00 grams

36.9 % w/w butanoic acid solution

This means that 36.9 grams of butanoic acid is present in 100 grams of solution

Applying unitary method:

If 36.9 grams of butanoic acid is present in 100 grams of solution

So, 60.00 grams of butanoic acid will be present in = [tex]\frac{100}{36.9}\times 60.00=162.6g[/tex]

As, the given amount of solution is less than the required amount.

Hence, there is no solution for the required amount of butanoic acid.

Final answer:

To obtain 60.00 g of butanoic acid from a 36.9% w/w solution, 162.6 g of the solution is needed. The student has only 120 g available, which is insufficient.

Explanation:

To determine how much of the 36.9% w/w butanoic acid solution is needed to obtain 60.00 g of butanoic acid, we use the percentage concentration to set up a calculation. The 36.9% w/w solution means that for every 100 g of solution, there are 36.9 g of butanoic acid. Therefore, to find the mass of the solution needed for 60.00 g of butanoic acid, we can use the equation:

Mass of solution = (Mass of butanoic acid)/(Percentage of butanoic acid by mass) × 100

This yields:

Mass of solution = (60.00 g)/(0.369) × 100 = 162.6 g

Since the student has 120 g of the solution available, which is less than the 162.6 g required, there is not enough solution to obtain 60.00 g of butanoic acid.

364667 milligrams of calcium carbonate will be in the Tums tablets that contains 64.25 mL of a 0.1555 M HCl solution.

The mass of a substance can be calculated using the following formula:

molarity = no of moles ÷ volume

no of moles = 64.25 × 0.1555 = 9.99moles

no of moles = mass/molar mass

Molar mass of HCl = 36.5g/mol

mass = 36.5 × 9.99 = 364.7g

Therefore, 364667 milligrams of calcium carbonate will be in the Tums tablets that contains 64.25 mL of a 0.1555 M HCl solution.

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The Tums tablet contains 500 milligrams of calcium carbonate, calculated by using stoichiometry based on the volume and molarity of HCl solution needed to neutralize it.

The question involves calculating the mass of calcium carbonate in a Tums tablet based on the volume and molarity of HCl used to neutralize it. We know that it takes 64.25 mL of a 0.1555 M HCl solution to fully neutralize the tablet. Using the stoichiometry of the reaction between calcium carbonate and hydrochloric acid:

CaCO3(s) + 2HCl(aq) → CaCl2(s) + CO2(g) + H2O(l)

We can determine the number of moles of HCl reacted:

mole HCl = (0.06425 L) * (0.1555 M) = 0.009993 mol HCl

Since it takes 2 moles of HCl to react with 1 mole of CaCO3, we can find the moles of CaCO3:

mole CaCO3 = 0.009993 mol HCl / 2 = 0.0049965 mol

The molar mass of calcium carbonate (CaCO3) is approximately 100.09 g/mol. We can now find the mass:

mass CaCO3 = 0.0049965 mol * 100.09 g/mol = 0.500 g or 500 mg

The Tums tablet contains 500 milligrams of calcium carbonate.

To prepare 1.00 L of 0.120 M HNO3 by mixing with water, you would need approximately 0.992 kg of the concentrated solution.

To prepare 1.00 L of 0.120 M HNO3, we can start by calculating the number of moles of HNO3 needed, using the given concentration and volume. We can then use the density of the concentrated solution to calculate the mass of the concentrated solution required. Finally, we can use the percentage of HNO3 in the concentrated solution to determine the mass of HNO3 needed.

Step 1: Calculate the number of moles of HNO3 needed:

moles HNO3 = concentration x volume = 0.120 M x 1.00 L = 0.120 moles HNO3

Step 2: Calculate the mass of the concentrated solution needed:

mass concentrated solution = volume x density = 1.00 L x 1.41 g/mL = 1.41 kg

Step 3: Calculate the mass of HNO3 needed:

mass HNO3 = mass concentrated solution x percentage HNO3 = 1.41 kg x 70.3% = 0.992 kg

Therefore, you would need approximately 0.992 kg of the concentrated solution to prepare 1.00 L of 0.120 M HNO3 by mixing it with water.

Hydrogen bonds between water molecules must break for water to change from solid to liquid to gas.

In order for water to change from solid to liquid to gas, the hydrogen bonds between water molecules must break. These hydrogen bonds are weaker than covalent or ionic bonds and are constantly forming and breaking in liquid water. When the heat is increased, the higher kinetic energy of the water molecules causes the hydrogen bonds to break completely, allowing water molecules to escape into the air as gas. On the other hand, when water is cooled and freezes, the water molecules form a crystalline structure maintained by hydrogen bonding, making ice less dense than liquid water.

Answer:

In carbon containing compounds, carbon usually forms four bonds, nitrogen usually forms three bonds, oxygen usually forms two bonds, and hydrogen only forms one bond.

Explanation:

In organic compounds in which carbon is present, the number of bonds formed depend on the number of electrons available for each chemical element. In the case of Carbon, it is 4. Nitrogen is 3. Oxygen is 2. Hydrogen is 1. In other types of compounds, it is possible to see different types of bonds.

Answer:

a) 0.65

b) 0.342 atm

Explanation:

a) First, we need to know the molar mass of the compounds. By periodic table, the molar mass of the elements are:

C = 12 g/mol; Cl = 35.5 g/mol; H = 1 g/mol. So:

CCl4 = 12 + 4x35.5 = 154 g/mol

CHCl3 = 12 + 1 + 3x35.5 = 119.5 g/mol

They both have the same mass, so we can choose the basis of calculus as 100 g (you can choose any other basis, the result will be the same because the fraction will be the same!)

The number of moles is :

n = mass/molar mass

nCCl4 = 100/154 = 0.649 mol

nCHCl3 = 100/119.5 = 0.837 mol

So, the total number of moles is nt =  nCCl4 + nCHCl3 = 1.486

Then, the molar fractions in the solution will be:

xCHCl3 = nCHCl3/nt = 0.837/1.486 = 0.56

xCCl4 = 1 - 0.56 = 0.44

By Dalton's Law

Pt = PCCl4*xCCl4 + PCHCl3*xCHCl3

Where Pt is the total pressure of the vapor, and PCCl4 and PCHCl3 are the vapor pressure of the compounds. So:

Pt = 0.44*0.354 + 0.56*0.526 = 0.451 atm

The molar fraction of the vapor will be:

yCHCl3 = (xCHCl3*PCHCl3)/Pt

yCHCl3 = (0.56*0.526)/0.451 = 0.65

b) When the vapor is condensed, the molar fraction of the vapor phase will be the molar fraction of the solution, so xCHCl3 = 0.65

P = molar fraction x vapor pressure

P = 0.65 x 0.526

P = 0.342 atm

The mole fraction of CHCl₃ in the vapor above the solution is equal to 0.65.

Given the following data:

Vapor pressure of CCl₄ = 0.354 atm.

Vapor pressure of CHCl₃ = 0.526 atm.

Scientific data:

Molar mass of CCl₄ = 154 g/mol.

Molar mass of CHCl₃ = 119.5 g/mol.

Next, we would determine the number of moles for each compound:

Note: Assume a mass of 100 grams.

Mathematically, the number of moles contained in a chemical compound is given by this formula:

[tex]Number \;of \;moles = \frac {mass}{molar\;mass}\\\\Number \;of \;moles = \frac {100}{154}[/tex]

Number of moles of CCl₄ = 0.649 mol.

For CHCl₃:

[tex]Number \;of \;moles = \frac {mass}{molar\;mass}\\\\Number \;of \;moles = \frac {100}{119.5}[/tex]

Number of moles of CHCl₃ = 0.837 mol.

The total number of moles = 0.649 + 0.837 = 1.486 mol.

For the mole fraction of CCl₄, we have:

[tex]M_f = \frac{0.649}{1.486} \\\\[/tex]

Mole fraction = 0.44.

For CHCl₃, we have:

Mole fraction = 1 - 0.44 = 0.56.

Next, we would determine the total pressure of the two compounds by applying Dalton's law:

Total pressure = 0.56 × 0.526 + 0.44 × 0.354

Total pressure = 0.451 atm.

Now, we can determine the mole fraction of CHCl₃ in the vapor above the solution:

[tex]Mole \;fraction = \frac{0.56 \times 0.526}{0.451}[/tex]

Mole fraction = 0.65.

Vp = molar fraction × vapor pressure

Vp = 0.65 × 0.526

Vp = 0.342 atm.

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Answer:

The concentration of the standard NaOH solution is 0.094 moles/L.

Explanation:

In the titration, the equivalence point is defined as the point where the moles of NaOH (the titrant) and KHP (the analyte) are equal:

     moles of NaOH = moles of KHP

[tex][NaOH]xV_{NaOH} = moles of KHP[/tex]

[tex][NaOH] = \frac{moles of KHP}{V_{NaOH}}[/tex]

The [tex]V_{NaOH}[/tex] is 40.82mL = 0.04082L and the moles of KHP are

[tex]0.7816g / 204.2212\frac{g}{mol} = 3.827x10^{-3} moles[/tex]

Replacing at the first equation:

[tex][NaOH] = \frac{3.827x10^{-3}moles}{0.04082L} = 0.094 moles/L[/tex]

Answer:

The answer is letter b.

Explanation:

a. Acids and bases cannot mix together. This is wrong, in fact there is a reaction called neutralization in which the reactants are an acid and a base.

b. Acids and bases will neutralize each other. This is true, when acids and bases react, the products are a salt and water and the reaction is called neutralization reaction.

c. Acids, but not bases, can change the pH of a solution. It's false, both acids and bases change the pH of a solution.

d. Acids donate hydroxide ions (OH–); bases donate hydrogen ions (H+). It's wrong, acids donate H+ and bases donate OH-.

The correct statement here is  Acids and bases will neutralize each other.

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Answer:

(a) 0.459 Jg⁻¹°C⁻¹

(b) 22 Jmol⁻¹°C⁻¹

(c) 0.72 moles

Explanation:

(a) The specific heat capacity can be calculated using the following equation:

Q = mcΔt, where Q is the heat energy, m is the mass, c is the specific heat capacity, and Δt is the temperature change from initial to final.

Rearranging the equation to solve for c gives:

c = Q / (mΔt) = (312J) / ((34.0g)(44.0°C - 24°C) = 0.459 Jg⁻¹°C⁻¹

(b) To find the molar specific heat, grams in the above result must be converted to moles using the mass per mole:

(0.459 Jg⁻¹°C⁻¹)(47g/mol) = 22 Jmol⁻¹°C⁻¹

(c) The numer of moles present are found by converting grams to moles using the mas per mole:

(34.0g)(mol/47g) = 0.72 moles

Answer:

number 2 your welcome good luck

Final answer:

Ionization in human cells due to high-energy particles or electromagnetic waves from radioactive nuclides can lead to unstable atoms, free electrons, and reactive free radicals, causing serious disruptions in cell functions and health.

Explanation:

The consequences of ionization in human cells can lead to various forms of radiation damage, which is highly concerning due to the critical functions that cells play in an organism's health. When high-energy particles such as alpha and beta particles, or electromagnetic waves emitted by radioactive nuclides, encounter living cells, they have the potential to cause significant disruption. These disruptions include:

The damage caused by ionizing radiation includes both somatic and genetic impacts, with the former affecting the individual's own body cells and the latter having potential consequences for future generations. Cells that reproduce rapidly, such as those found in bone marrow and the gastrointestinal tract, are often most susceptible to this type of damage.

Answer:

The correct option is c) exothermic, negative.

Explanation:

Reactions that releases heat to the surroundings are called exothermic, and are characterized by negative entalpy (ΔH) values.

A chemical reaction that releases heat to the surroundings is said to be exothermic and has a negative H at constant pressure.

This is the type of reaction which involves the release or loss of heat to the surrounding.

Since heat is lost, exothermic reaction has a negative enthalpy thereby making option C the most appropriate choice.

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Answer:

The vapor pressure of X at [tex]- 89^{\circ}[/tex] = 0.12 atm

Given:

[tex]\Delta H_{v} = 16.0 kJ mol[/tex]

Normal boiling point, T = [tex]- 43^{\circ}C = 230 K[/tex]

T' = [tex]- 89^{\circ}C = 184 K[/tex]

Solution:

At boiling point, vapor pressure  = atmospheric pressure

Thus at T, P = 1 atm

Now, to calculate vapor pressure, P' at T' = 184 K, we use:

[tex]log_{10}\frac{P'}{P} = \frac{\Delta H_{v}}{R2.303}\frac{T' - T}{T'T}[/tex]

where

R = Rydberg's constant = 8.314 J/mol.K

Putting the values in the above formula:

[tex]log_{10}\frac{P'}{1} = \frac{16.0\times 1000}{8.314\times 2.303}\frac{184 - 230}{184\times 230}[/tex]

[tex]log_{10}{P'}= - 0.9083[/tex]

[tex]P'= 10^{- 0.9083} = 0.12 atm[/tex]

Vapor pressure of Substance X at -89°C is calculated by using the Clausius-Clapeyron equation along with the given enthalpy of vaporization and the normal boiling point. The equation is rearranged to a linear form to solve for the vapor pressure.

To calculate the vapor pressure of Substance X at -89°C using the enthalpy of vaporization and normal boiling point, we use the Clausius-Clapeyron equation. This equation is: P = Ae¯^Hvap/RT, where AHvap is the enthalpy of vaporization for the substance, R is the gas constant, and A is a constant whose value depends on the substance. Temperature T must be in Kelvin for this equation. In this case, the enthalpy of vaporization of Substance X is 16.0kJ mol and its normal boiling point is −43.°C.

This equation can be rearranged into logarithmic form to obtain a linear equation: Hvap + lnA = RT. If we know the vapor pressure at one temperature (T₁, P₁) and want to find the vapor pressure at another temperature (T₂), we can use these values to find A and subsequently calculate the vapor pressure at T₂.

Keep in mind that the normal boiling point is the temperature at which the vapor pressure equals atmospheric pressure at sea level, so this allows us to know one vapor pressure-temperature value.

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Answer:

What is your question?

High School Chemistry 10+5 pts

Water molecules are _____polar_______ because the hydrogen atoms are positively charged on one end and the oxygen atoms are negatively charged on one end. Molecules that are _____nonpolar_______ share electrons equally. Sodium chloride (NaCl) is an example of a ______polar______ molecule because it is soluble in water. Molecules that are _____nonpolar_______ are insoluble in water. It is ______false______ that most molecules formed with nonpolar bonds dissolve easily in water.

Answer:

C. is a covalent bond between the carboxyl carbon of one amino acid and the amino nitrogen of a second amino acid.

A peptide bond  is a covalent bond between the carboxyl carbon of one amino acid and the amino nitrogen of a second amino acid. Therefore, the  correct option is option C.

A peptide bond, also known as a eupeptide bond, is a chemical connection produced by attaching one amino acid's carboxyl group towards the substituent of the other.

A peptide bond is a form of covalent chemical link that is amide in nature. A peptide bond  is a covalent bond between the carboxyl carbon of one amino acid and the amino nitrogen of a second amino acid.

Therefore, a peptide bond  is a covalent bond between the carboxyl carbon of one amino acid and the amino nitrogen of a second amino acid. The correct option is option C among all the given options.

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Answer:

D is the best choice. Those percentages, are giving you the information about how concentrated are the solutions.  As 0.015 is so concentrated, this solution will damage the structures more quickly

Explanation:

Answer:

The answer is D. 0.015%

Explanation:

That is the concentration of the Sulfuric Acid solution given in mass per mass percentage (w/w%), it means that the solution has 0.015 grams of Sulfuric Acid per 100 grams of solution. If it is compared with C answer, it has 0.005 grams more. Considering the reaction:

[tex]H_{2} SO_{4} + CaCO_{3}[/tex] ⇒ [tex]CaSO_{4} + CO_{2} + H_{2}O[/tex]

The more [tex]H_{2} SO_{4}[/tex] (Sulfuric Acid) is present, the more [tex]CaCO_{3}[/tex] (Limestone) is consumed.

Answer:

The correct answer to your question is the second option

Explanation:

The amount of energy from the products  This option is not correct because in a chemical reaction the energy given off or absorved is written at the end of the reaction, it is not a coefficient.

The ratios of the number of moles of each substance that react and that are produced  This option is correct, coefficients tell the number of moles of each substance in a reaction.

The physical states of the compounds reacting  Physical states are written next to the molecule and using parenthesis.  Incorrect

The elements involved in the reaction Incorrect because elements are written with symbols not with coefficients.

Final answer:

The coefficients in a balanced chemical equation represent the molar ratios of reactants and products in a chemical reaction, which are essential for stoichiometric calculations and ensure adherence to the Law of Conservation of Mass.

Explanation:

The coefficients in a balanced chemical equation tell us the ratios of the number of moles of each substance that react and that are produced during the chemical reaction. These coefficients indicate the relative amounts of reactants and products in a reaction and are used in stoichiometry to determine the quantities of one substance that will react with or produce a given amount of another substance.

Stoichiometry is the study of the numerical relationships between the reactants and the products in balanced chemical reactions. The coefficients in a balanced chemical equation also respect the Law of Conservation of Mass, ensuring that the number of atoms of each element is equal on both the reactant and product sides of the equation. These ratios are referred to as stoichiometric factors and are critical in performing quantitative chemical calculations.

Answer:

1. Identify the SI unit(s) that would be most appropriate for measuring each of the following:

A) the length of a new pencil (cm)

B) the width of your classroom (m)

C) the length of your arm (cm)

D) the diameter of pencil lead (mm)

2. Identify the SI unit(s) that would be most appropriate for massing each of the following:

A) a person (kg)

B) a banana ( g)

C) your daily vitamin tablet (mg)

D) a pencil (g)

3. Identify the SI unit(s) that would be most appropriate for measuring each of the following:

A) a glass of milk  (mL)

B) the amount of water required to fill a glass of water (mL)

(C) a dose of cough syrup (mL)

(D) a truckload of sand  (m³)

4. Rank the measurements within each set from largest to smallest:

(A) 1.2m, 750cm, 0.005km, 65dm, and 2000mm

65 dm, 750 cm, 0.005km, 2000 mm; 1.2 m

B) 450mg, 3.8cg, 0.27dg, 0.50g, and 0.00047kg

0.27 dg, 0.50 g, 0.0047 kg, 450 mg, 3.8 cg

c.) 2.5L, 22cL, 13dL, 870mL, and 175cm3

13dL, 2.5L, 870 mL, 22cL, 0.175 L

Explanation:

The International System of Units is inherited from the old decimal metric system. One of the main characteristics is that the units are based on physical phenomena. The units of the S.I. they are the reference for the indications of the measuring instruments, and are found by means of calibrations. The International System of Units has seven basic units, called fundamental units. By combining the basic units the other units are obtained, called units derived from the International System.

1) The SI Units for Length are; The length of a new pencil: cm (centimeters), The width of your classroom: dam (decameters), The length of your arm: m (meters), The diameter of pencil lead: μm (micrometers). 2) The SI Units for Mass: A person: kg (kilograms), A banana: g (grams), Your daily vitamin tablet: mg, A pencil: g . 3) SI Units for Volume: A glass of milk: L, The amount of water required to fill a glass of water: mL (milliliters), A dose of cough syrup: mL, A truckload of sand: m3 (cubic meters). 4) Measurements of Length:1.2 m 65 dm (decimeter) 750 cm (centimeter) 2000 mm (millimeter) 0.005 km, Measurements of Mass: 0.00047 kg 0.27 dg 0.50 g (gram) 3.8 cg 450 mg (milligram), Measurements of Volume: 2.5 L 13 dL , 22 cL (centiliter) 870 mL (milliliter) 175 cm³ (cubic centimeter).

1) The SI units for measuring each of the given quantities are;

The length of a new pencil: cm (centimeters)

Centimeters are a suitable SI unit for measuring the length of a new pencil. Centimeters are a commonly used unit for relatively small measurements, and they are well-suited for measuring objects like pencils, which are typically a few tens of centimeters in length.

The width of your classroom: dam (decameters)

Decameters (dam) are not commonly used for measurements like the width of a classroom.

The length of your arm: m (meters)

Meters are a suitable unit for measuring the length of larger objects like body parts. The length of an arm is typically measured in meters because it is a relatively substantial length compared to centimeters or millimeters.

The diameter of pencil lead: μm (micrometers)

Micrometers (μm) are the most appropriate unit for measuring the diameter of pencil lead.

2) Identify the appropriate SI unit for measuring mass:

Mass of a person: kg (kilograms)

Kilograms are the most appropriate SI unit for measuring the mass of a person. Kilograms are a standard unit of mass and are used for measuring larger objects, including humans.

Mass of a banana: g (grams)

Grams are a suitable SI unit for measuring the mass of smaller objects like a banana. Bananas typically have masses that fall within the gram range.

Mass of your daily vitamin tablet: mg (milligrams)

Milligrams are the most appropriate SI unit for measuring the mass of a small object like a daily vitamin tablet.

Mass of a pencil: g (grams)

Grams are suitable for measuring the mass of objects like pencils. Pencils are relatively light and fall within the range of grams.

3) SI unit for measuring each of the given quantities;

A glass of milk: L (liters); Liters are a suitable SI unit for measuring the volume of liquids like a glass of milk.

The amount of water required to fill a glass of water: mL (milliliters); Milliliters are the most appropriate SI unit for measuring smaller quantities of liquids like the amount of water needed to fill a glass.

A dose of cough syrup: mL (milliliters); Similar to the previous case, milliliters are the most suitable SI unit for measuring the volume of a dose of cough syrup.

A truckload of sand: m³ (cubic meters); Cubic meters are the most appropriate SI unit for measuring large volumes, such as a truckload of sand.

4) The measurements in each set from largest to smallest:

In set A, the measurements are given in various units of length. To rank them from largest to smallest, we simply convert all measurements to the same unit (for example, millimeters) and then compare their numerical values. Larger numerical values represent larger measurements.

In set B, the measurements are given in various units of mass. Similar to set A, we can convert all measurements to the same unit (for example, milligrams) and then rank them based on their numerical values. Larger numerical values represent larger masses.

In set C, the measurements are given in various units of volume. Liters and milliliters are common units for volume, and cubic centimeters (cm³) are also used for measuring volume. In this case, we can directly compare the values since they are all volume measurements.

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Answer:

The answer t your question is below:

Explanation:

When a salt is mixed with water, it will form ions, these ions are soluble in water.

Example:    Ca(NO3)2    ⇒    Ca⁺²     +    2 NO₃⁻¹

Both Ca⁺² and NO₃⁻¹ are soluble in water.

Then the answer to your question is:

Soluble because all Ca+2 compounds are soluble in water

Soluble because all NO3−1 compounds are soluble in water

Ca(NO3)2 is soluble in water because all nitrate compounds are soluble in water regardless of the cation they are paired with.

When the compound Ca(NO3)2 is mixed with water, the Ca(NO3)2 is soluble because all NO3−1 compounds are soluble in water. This is generally based on the solubility rules of ionic compounds in water where all nitrates (NO3-) are soluble, regardless of the cation they are paired with. Thus, in spite of the solubility trends of calcium (Ca+2), the nitrate (NO3-) ion dictates the solubility of this compound in water, making it soluble.

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Answer:

6 is B, 7 is A

Explanation:

Answer:

The answer to your question is: letter A

Explanation:

A. Gas particles are in constant motion. This statement is true because this theory says that Gases are composed of a large number of particles that behave like hard, spherical objects in a state of constant, random motion.

B. Gas particles attract each other. This statement is false because this theory says that there is no force of attraction between gas particles or between the particles and the walls of the container.

C. Gas particles lose their energy during collisions. This statement is false, this theory says that none of the energy of a gas particle is lost when it collides with another particle or with the walls of the container.

D. Gas particles stick to the walls of their container. This statement is false, the theory says that there is no force of attraction between gas particles or between the particles and the walls of the container.

Answer:

27.216 mg/h.

Explanation:

First you need to convert 100 lb to kg, and there are 45.36 kg, she will receive 10 mcg/kg/min so if you multiply it by 45.36 kg, she will receive 453.6 mcg/min, so in one hour (60 minutes) she will receive 27216 mcg/h, 1000 mcg are 1 mg, so she will receive 27.216 mg/h.

Hey!

---------------------------------------------------------------

Mass of the alloy:

m = 8.48 g/cm^3 * 125.5 cm^3 = 954 grams

954 * 0.37 = 352.98 grams

---------------------------------------------------------------

Mass of the copper:

954 - 352.98 = 601.02 grams

---------------------------------------------------------------

Copper Molar Mass: 63.55 g/mol

Zinc Molar Mass: 65.38 g/mol

---------------------------------------------------------------

Moles in copper: 352.98 / 65.38 = 5.40 moles!

Moles in zinc: 601.02 / 63.55 = 9.46 moles!

---------------------------------------------------------------

Atoms in copper = 10^24 * 3.25 atoms

Atoms in zinc = 10^24 * 5.70

I used the Avogadro's Number.

---------------------------------------------------------------

Hope This Helped! Good Luck!

Answer:

The answer to your question is:

a) 31.75 cm

b) 0.475 miles

c) 2.44 yards

d) 11496.04 inches

Explanation:

Convert

a)           12.5 in to cm

         1 in ------------------- 2.54 cm

       12.5 in ----------------    x

            x = 12.5(2.54)/1 = 31.75/ = 31.75 cm

b)          2513 ft to miles

           1 mile -------------- 5280 ft

           x miles ------------ 2513 ft

        x = 2513(1)/5280 = 0.475 miles

c) 2.23 m to yards

              1 m -------------   1,094 yards

            2.23 m ----------     x

       x= 2.23x1.094/1 = 2.44 yards

d)  292 m to inches

            1 m ---------------- 39.37 inches

          292 m -------------     x

    x = 292 x 39.37/1 = 11496.04 inches

Answer:

The answer to your question is letter B

Explanation:

Activated complex is an intermediate process between the reactants and the products which has a higher energy than both (reactants and products).

In the graph we can see that the higher point is letter B, that is the one of the activated complex. The energy that must be supply to the systed to proceed is called activated energy.

Answer:

Is removed from the atmosphere by photosynthesis.

Explanation:

The carbon dioxide (CO2) is presented in the atmosphere and its cycle began with it's incoming by respiration, combustion of fuels and decomposition. The autotrophs, which realize photosynthesis, use CO2 as fuel to produce their food with Sun rays.

The CO2 comprises about 0.3% of the atmospheric gases, and in the past few years, its input is being higher than its removal of the atmosphere, which is aggravating the greenhouse effect. Besides, the atmosphere of Venus has higher levels of CO2.

Answer:

9742.37 J/mol

Explanation:

We follow the expression for Gibbs free energy:

[tex]\Delta G=\Delta G^{o}+RTlnQ[/tex]

First we calculate Q with the following expression for the reaction:

[tex]aA+bB \rightleftharpoons cC+dD[/tex]

[tex]Q=\frac{P_{C}^{c}P_{D}^{d}}{P_{A}^{a}P_{B}^{b}}[/tex]

Therefore, Q=0.0196

Now we continue with the first equation, and as we are on equilibrium, we know that the Gibbs free energy is zero, therefore:

[tex]0=\Delta G^{o}+RTlnQ\\\\\Delta G^{o}=-RTlnQ\\\\R=8.314J/molK\\\\T=298 K\\\\\Delta G^{o}=+9742.37J/mol[/tex]

The standard change in Gibbs free energy of the given reaction at 25°C can be calculated by first determining the equilibrium constant, K, based on the given partial pressures of the substances and then applying the formula ΔG° = -RT ln K, where R is the ideal gas constant and T is the temperature in Kelvin.

To calculate the standard change in Gibbs free energy of the reaction at 25 °C, we need to take into account the partial pressures of all the substances in the reaction. In this case, the equilibrium constant (K) can be determined as K=(PC*PD^2)/(PA^3*PB^2). After calculating K, we can use the relation for Gibbs free energy change: ΔG° = -RT ln K, with R being the ideal gas constant (8.314 J/(K*mol)) and T being the temperature in Kelvin (273K for 25°C).

Remember that in this context, the equation ΔG = ΔG° + RT ln Q where Q represents the ratio of the initial concentrations of products and reactants. In equilibrium, Q equals K, and ΔG equals to 0, simplifying our calculation.

We can substitute the calculated value of K into the equation to find the standard change in Gibbs free energy. Note that a negative value of ΔG° indicates a spontaneous reaction while a positive value indicates a nonspontaneous reaction at room temperature.

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