How is a pure substance different from a mixture? A. Pure substances cannot be seperated by physical means.B. A pure substance is heterogeneous.C. A mixture is made of ine substance.D. Mixtures cannot be seperated by physical means.

Answer:

Density

Explanation:

Density is not unique only to water. All liquids have density. Liquids have density either higher or lower than that of water. All liquids have mass and they occupy the volume of the container in which they are kept. Density is the ratio of mass to volume.  

Density = mass/ volume.  

As all liquids have mass and volume they also have density.  

Well it depends, if you add heat to ice it will melt, if you add heat to water it will  evaporate.

Hope it helps!

Why hello there, Lithommie

Your question: can someone explain to me what happens when thermal energy is added to a state of matter?

My answer:

Very good question

lets take a look at what happens when thermal energy is added to a state of matter.

In this case lets look at a football game, at the beginning of the game the players represent the state SOLID the scores 0-0 and the heat is on. Remember the players are solid and when they are melting into a liquid by the end of the game and the players are mixing through the field and collapsing with one another and by the end of the game they become liquid.

Do you understand more clearfully? If you add heat to ice( the solid ) it melts and becomes water( The liquid )

IMPORTANT: If my answer helped please mark me as brainliest thank you and have the best day ever!

Hey there!:

The 1s, 2s and 2p subshells are completely filled (a maximum of two electrons go into the 1s subshell and a maximum of two electrons go into the 2s subshell.  The 2p subshell includes 3 orbitals, with 2 electrons maximum per orbital).  The 3s subshell has only one of a maximum of two electrons.

Hope that helps!

The question involves calculating the enthalpy of reaction (ΔH) for the conversion of SiCl4 and H2O to SiO2 and HCl, focusing on the energy changes associated with bond breaking and formation during this chemical reaction.

The question refers to the enthalpy of reaction for the process in which silicon tetrachloride (SiCl4) reacts with water (H2O) to produce silicon dioxide (SiO2) and hydrochloric acid gas (HCl). This reaction can be represented as:

SiCl4(l) + 2H2O(l) → SiO2(s) + 4HCl(g)

To understand the enthalpy change (ΔH) of this reaction, one needs to consider the bond energies involved in breaking and forming chemical bonds during the reaction. The process of calculating ΔH for a reaction involves understanding the energy required to break bonds in the reactants and the energy released by forming bonds in the products.

Silicon tetrachloride is a covalent tetrahedral molecule that engages in reactions leading to the formation of silicon dioxide and hydrochloric acid gas when exposed to water. This type of reaction is exothermic if the energy released in forming the products' bonds is greater than the energy required to break the reactants' bonds. Calculating the exact ΔH would require specific values of bond energies, which are not provided here.

The enthalpy of reaction for SiCl₄(l) + 2H₂O(l) → SiO₂(s) + 4HCl(g) is calculated to be -66 kJ.

This involves using the enthalpies of formation for each compound. The result indicates an exothermic reaction.

To determine the enthalpy of reaction for the given chemical equation, we need to use the known enthalpies of formation for each compound involved:

The enthalpy of the reaction (ΔHrxn) is calculated using the formula:

ΔHrxn = ΣΔHf(products) - ΣΔHf(reactants)

Assuming standard enthalpy of formation (ΔHf) values as follows:

The enthalpy of the reaction would be calculated as:

ΔHrxn = [(-910) + 4(-92)] - [(-640) + 2(-286)] kJ

That simplifies to:

ΔHrxn = (-910 - 368) - (-640 - 572) kJ = -1278 + 1212 kJ = -66 kJ

Thus, the enthalpy of the reaction is -66 kJ.

The appearance of small pieces of ice instead of ice cubes in the freezer can happen through a process called sublimation, in which ice transitions directly into a gaseous state, additionally influenced by thermal equilibrium as per the second law of thermodynamics.

Finding small pieces of ice instead of ice cubes in the freezer could be due to a process called sublimation, in which solids transition directly into the gaseous state, bypassing the liquid state. This is a common phenomenon for snow and ice at temperatures below the melting point of water. It's a slow process that can be accelerated by reduced atmospheric pressure in the freezer or sporadic variations in the temperature of the freezer. The varying conditions inside the freezer could cause ice cubes to break down into smaller pieces of ice.

Another contributing factor could be the thermal equilibrium dictated by the second law of thermodynamics. This law predicts that after heat transfers energy from the warmer freezer air to the colder ice, the components will eventually reach a thermal equilibrium. The continual transfer of energy could cause the ice cubes to reduce in size over time.

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Answer: The correct answer is Option C.

Explanation:

Oxidation reaction are the reactions in which an element or compound looses electrons and the element that looses electrons is known as oxidized species. The oxidation state of the species is increased for these kind of reactions.

[tex]X\rightarrow X^{n+}+ne^-[/tex]

Reduction reaction are the reactions in which an element or compound gains electrons and the element that gains electrons is known as reduced species. The oxidation state of the species gets reduced for these kind of reactions.

[tex]X^{n+}+ne^-\rightarrow X[/tex]

For the given chemical reaction:

[tex]4Li+2CoO\rightarrow 2Co+2Li_2O[/tex]

On reactant side:

Oxidation state of lithium = 0

Oxidation state of cobalt = +2

Oxidation state of oxygen = -2

On product side:

Oxidation state of lithium = +1

Oxidation state of cobalt = 0

Oxidation state of oxygen = -2

As, oxidation state of lithium is increasing, it is loosing electrons and thus it is undergoing oxidation reaction and the oxidation state of cobalt in reducing, it is gaining electrons and thus it is undergoing reduction reaction .

Hence, the correct answer is Option C.

Answer:

C. Li

Explanation:

There are four sublevels s, p, d ,f   2 in the s

2.57 kilograms = 2570 grams

i think this is standard form but i don't know 100%

Remember that there are 1000 grams in 1 kilogram.

Multiply 1000 grams with 2.570 kilograms

1000 x 2.570 = 2570

2570 grams are in 1 kilogram

hope this helps

Using the formula as frequency = speed of light/ wavelength of light

f = c/λ

Where c = [tex]3.0 X 10^{8}[/tex] m/s and λ = [tex]5.4 X 10^{-4}[/tex] m

Substituting in above formula we get,

∴ f = [tex]\frac{3.0 X 10^{8}m/s}{5.4 X10^{-4}m}[/tex]

∴f = 5.55 X [tex]10^{13}[/tex] Hz

Answer:

55x 1013x i think im not too sure

Explanation:

c group A is the correct answer

Answer:

The answer is D "in the middle"

Explanation:

I did the test and got 100%

Have a great day! :)

There are 60 seconds in a minute. There are 60 minutes in an hour. There are 24 hours a day. There is 86400 seconds per day (24 hours). There are 168 hours per week (7 days). There are 720 hours in 30 days. 86,400 seconds divided by 60 seconds is 1440 seconds. 1440 seconds times 30 days is 43,200 minutes.

That gives us the answer.. 43,200 minutes are in 30 days.

131400 hope it helps.

               Adding 15 g of Flubber with 85 g of inert solvent will result in the formation of 15 % solution.

              W/V %  =  15 %

              Weight of Flubber  =  ?

              Weight of Solution  =  ?

              Let's suppose we are going to prepare a 100 mL solution. The using following formula we can calsulate the amount of Flubber required.

              W / W %  =  (Weight of Flubber ÷ Weight of Solution) × 100

Putting values,

              15 %  =  (Weight of Flubber ÷ 100 g) × 100

Solving for Weight of flubber,

              Weight of Flubber  =  (15 × 100 g) ÷ 100

              Weight of Flubber  =  15 g

Hence, taking 15 g of Flubber and adding it to 85 g of solvent will result in the formation of 15% Flubber solution.

Final answer:

To create a 15% solution of flubber, combine 15 grams of flubber with sufficient solvent to make 100 milliliters of solution, ensuring the flubber is fully dissolved and the total volume reaches 100 milliliters.

Explanation:

How to Make a 15% Solution of Flubber

To make a 15% solution of flubber, you would typically mix 15 grams of flubber (the solute) with enough solvent to make a total solution volume of 100 milliliters. The steps to creating this solution are as follows:

Weigh 15 grams of flubber using a scale.

Transfer the flubber into a container, such as a beaker.

Add a solvent, usually water, to the beaker.

Stir the mixture until the flubber is completely dissolved.

Continue adding water until the total volume of the solution is 100 milliliters.

Remember that when making a solution, the percentage is calculated by the mass of the solute divided by the total volume of the solution, and then multiplied by 100 to get the percentage. Therefore, a 15% solution of flubber in this case means you have 15 grams of flubber in every 100 milliliters of solution.

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Ionic bonds are formed by the differences in the electronegativities of the elements. Yes, sodium, and fluorine will form ionic bonds. Thus, option A is correct.

Ionic bonds are the category of chemical bonds that are formed by the complete transfer of the electron from one atom to another resulting in the formation of the cation and the anion. This sharing occurs through the difference in electronegativity.

If the electronegativity difference is more than 1.5 to 1.7 then, the electron sharing occurs by the virtue of the valence shell.

Given,

Electronegativity of fluorine (F) = 3.98

Electronegativity of sodium (Na) = 0.93

The differences are calculated as:

= Electronegativity of fluorine - Electronegativity of sodium

= 3.98 - 0.93

= 3.05

As 3.05 > 1.7 it will form the ionic bond.

Therefore, yes sodium and fluorine form an ionic bond.

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Final answer:

The difference in electronegativity between Na and F is large enough to predict the formation of an ionic bond. Sodium, being a metal, donates an electron to fluorine, a nonmetal, resulting in the creation of oppositely charged ions that attract each other.

Explanation:

When predicting whether a pair of elements will form an ionic bond, the key factor to consider is the electronegativity difference between the two elements. Ionic bonds generally form when one element (typically a metal) transfers one or more valence electrons to another element (typically a nonmetal), resulting in the formation of ions that are oppositely charged and attract each other due to electrostatic forces. In the case of sodium (Na) and fluorine (F), the electronegativity difference is indeed large enough to favor the formation of an ionic bond.

Electronegativity differences greater than approximately 1.7 tend to lead to ionic bonding. Sodium (Na), a metal, has a much lower electronegativity compared to fluorine (F), which is a highly electronegative nonmetal. The difference in electronegativity between Na and F is roughly 3.0, which is significantly greater than the threshold value for ionic bonding, indicating that Na and F will form an ionic bond.

Answer:

Na₂S + FeBr₂ → 2NaBr + FeS(s)

MgSO₄ + CaCl₂ → MgCl₂ + CaSO₄(s)

AgNO₃ + NaCl → AgCl(s) + NaNO₃

Explanation:

You must recall the pertinent solubility rules:

Na₂S + FeBr₂ → 2NaBr + FeS(s)

NaBr is soluble (Rule 1). FeS is insoluble (Rule 5), so a precipitate forms.

MgSO₄ + CaCl₂ → MgCl₂ + CaSO₄(s)

MgSO₄ is soluble (Rule 3). CaSO₄ is insoluble (Rule 4), so a precipitate forms.

AgNO₃ + NaCl → AgCl(s) + NaNO₃

NaNO₃ is soluble (Rule 1). AgCl is insoluble (Rule 3) so a precipitate forms.

LiOH + NH₄I → LiI + NH₄OH and 2NaCl + K₂S → Na₂S + 2KCl

All products are soluble (Rule 1), so these are not precipitation reactions.

HEY I GOT YO ANSWER

THE ANSWERS ARE A B AND DA LAST ONE

The measurement 6.4x10^3 g could be written as 6.4 kg in kilograms and as 6.4x10^6 mg in milligrams, considering the unit conversions.

The measurement 6.4x10^3 g can be expressed in other units. The use of scientific notation, such as 6.4x10^3, helps us write very large or very small numbers in a more manageable way. This notation means that you are multiplying 6.4 by 10 raised to the power of 3, or in other words, adding three more zeros to 6.4, which results in 6400.

To convert it to kilograms, we need to remember that 1 kilogram is equal to 1000 grams. So, we can divide the number of grams by 1000 to get the measurement in kilograms. Hence, 6.4x10^3 g = 6.4 kg. Similarly, we can convert it to milligrams, remembering that 1 gram equals 1000 milligrams, which results in 6.4x10^3 g = 6.4x10^6 mg.

Note:

Always remember to check the magnitude of the units you are converting to ensure accuracy.

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Answer:

condense

Explanation:

If the relative humidity is high and the temperature drops, water vapor may condense as pressure increases with decrease in temperature.

Pressure is defined as the force applied on an object perpendicular to it's surface per unit area over which it is distributed.Gauge pressure is a pressure which is related with the ambient pressure.

There are various units by which pressure is expressed most of which are derived units which are obtained from unit of force divided by unit of area . The SI unit of pressure is pascal .

It is a scalar quantity which is related to the vector area element with a normal force acting on it.It is distributed over solid boundaries and across arbitary sections of fluid normal to the boundaries at every point.

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Answer:- Molarity = 0.121M and normality = 0.121N.

Solution:- KHP that is potassium hydrogen phthalate reacts with sodium hydroxide as:

[tex]NaOH+KHP\rightarrow NaKP+H_2O[/tex]

From this equation, they react in 1:1 mol ratio. Grams of KHP are given so we could convert them to moles and the moles of NaOH would also be equal since the mol ratio is 1:1. Molar mass of KHP is 204.2 gram per mol.

[tex]1.24gKHP(\frac{1mol}{204.2g})(\frac{1molNaOH}{1molKHP})[/tex]

= 0.00607 mol NaOH

Volume of NaOH solution is 50.0 mL that is 0.0500 L. Molarity is moles of solute per liter of solution. So, let's divide the moles by the liters to get the molarity.

[tex]molarity=\frac{0.00607mol}{0.0500L}[/tex]

= 0.121 M

The molarity of NaOH solution is 0.121 M.

Normality is the grams equivalent per liter of solution.

For a base, normality = molarity* acidity

acidity means how many hydroxide ions would be given out from the base. It could also be calculated on dividing the molecular weight of the compound by it's equivalent weight.

Acidity of NaOH is 1 as it has only one OH present in it.

So, normality = 0.121(1) = 0.121 N

The answer is

[tex]\[ \boxed{\text{Molarity} \approx 0.1214 \text{ M}} \] \[ \boxed{\text{Normality} \approx 0.1214 \text{ N}} \][/tex]

To determine the molarity and normality of the NaOH solution, we need to perform a titration calculation. The reaction between NaOH and KHP (potassium hydrogen phthalate) is a neutralization reaction, and the balanced equation is:

[tex]\[ \text{NaOH} + \text{KHC}_8\text{H}_4\text{O}_4 \rightarrow \text{KNaC}_8\text{H}_4\text{O}_4 + \text{H}_2\text{O} \][/tex]

From the equation, we can see that the molar ratio between NaOH and KHP is 1:1.

First, we calculate the moles of KHP that reacted with the NaOH solution:

The molar mass of KHP [tex](\( \text{KHC}_8\text{H}_4\text{O}_4 \))[/tex]is:

[tex]\[ 39.10 (\text{K}) + 1.01 (\text{H}) + 12 \times 12.01 (\text{C}) + 4 \times 16.00 (\text{O}) + 1.01 (\text{H}) = 204.22 \text{ g/mol} \][/tex]

Now, we calculate the moles of KHP:

[tex]\[ \text{moles of KHP} = \frac{\text{mass of KHP}}{\text{molar mass of KHP}} = \frac{1.24 \text{ g}}{204.22 \text{ g/mol}} \approx 0.00607 \text{ mol} \][/tex]

Since the molar ratio between NaOH and KHP is 1:1, the moles of NaOH used in the reaction are also approximately 0.00607 mol.

Now, we can calculate the molarity of the NaOH solution:

[tex]\[ \text{Molarity} = \frac{\text{moles of solute}}{\text{liters of solution}} \][/tex]

Given that 50.0 ml of NaOH solution was used, we convert milliliters to liters:

[tex]\[ 50.0 \text{ ml} = 0.0500 \text{ L} \][/tex]

Then, the molarity (M) is:

[tex]\[ M = \frac{0.00607 \text{ mol}}{0.0500 \text{ L}} \approx 0.1214 \text{ M} \][/tex]

To find the normality (N) of the NaOH solution, we need to consider that normality is the measure of the concentration of a solution in terms of the number of gram equivalents of solute per liter of solution. For NaOH, which is a strong base, the gram equivalent weight is the same as its molar mass because it provides one mole of [tex]OH^-[/tex] ions per mole of NaOH.

The molar mass of NaOH is:

[tex]\[ 23.00 (\text{Na}) + 16.00 (\text{O}) + 1.01 (\text{H}) = 40.01 \text{ g/mol} \][/tex]

Since the gram equivalent weight of NaOH is the same as its molar mass, the normality is equal to the molarity:

[tex]\[ N = M \approx 0.1214 \text{ N} \][/tex]

Therefore, the molarity and normality of the NaOH solution are both approximately 0.1214.

Final answer:

A copper penny turns green due to a chemical change, which is the oxidation of copper resulting in the formation of a green patina that protects the penny from further corrosion.

Explanation:

When a copper penny turns green after being exposed to air and moisture, it is due to a chemical change. This is a process similar to what happens to copper surfaces like the Statue of Liberty, where the oxidation of copper leads to the formation of a green patina. The chemical reaction for the oxidation can be represented by the equation 2 Cu(s) + O₂(g) → CuO(s), where copper (Cu) reacts with oxygen (O₂) to form copper oxide (CuO). The green color is attributed to additional reactions that form compounds like copper carbonate and copper sulfate, which comprise the patina. This patina acts as a protective layer, preventing further corrosion through a process known as passivation.

Answer: High energy and Low wavelength.

Explanation: We are given an electromagnetic wave having high energy, so by using Planck's equation:

[tex]E=h\nu[/tex]

where, E = energy

h = Planck's constant

[tex]\nu[/tex] = frequency

here, Energy and frequency follow direct relation and hence high frequency means high energy.

and [tex]\nu=\frac{c}{\lambda}[/tex]

[tex]\nu[/tex] = Frequency

c = speed of light

[tex]\lambda[/tex] = wavelength

Here, the frequency is inversely related to the wavelength, hence high frequency means low frequency.

[tex]\boxed{2172.1{\text{ kg}}}[/tex] of sodium carbonate must be added to neutralize [tex]2.01 \times {10^3}{\text{ kg}}[/tex] of sulfuric acid solution.

Further Explanation:

Stoichiometry:

Theamountof species present in the reaction is determined with the help of stoichiometryby the relationship between reactants and products. It is used to determine the moles of a chemical species when moles of other chemical species present in the reaction is given.

Balanced chemical reaction between sodium carbonate and sulphuric acid is as follows:

 [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} + {{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} \to {\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} + {{\text{H}}_{\text{2}}}{\text{O}} + {\text{C}}{{\text{O}}_{\text{2}}}[/tex]

According to stoichiometry of reaction, one mole of [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex] reacts with one mole of [tex]{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}[/tex] to produce one mole of [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}[/tex], one mole of  [tex]{{\text{H}}_{\text{2}}}{\text{O}}[/tex] and one mole of [tex]{\text{C}}{{\text{O}}_{\text{2}}}[/tex]. So stoichiometric ratio between [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex] and [tex]{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}[/tex] is 1:1.

The formula to calculate number of moles of [tex]{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}[/tex] is as follows:

[tex]{\text{Moles of }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} = \dfrac{{{\text{Mass of }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}}}{{{\text{Molar mass of }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}}}[/tex]                                             …… (1)

Substitute [tex]2.01 \times {10^3}{\text{ kg}}[/tex] for mass of [tex]{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}[/tex] and 98.079 g/mol for molar mass of [tex]{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}[/tex] in equation (1).

[tex]\begin{aligned}{\text{Moles of }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} &= \left( {\frac{{2.01 \times {{10}^3}{\text{ kg}}}}{{{\text{98}}{\text{.079 g/mol}}}}} \right)\left( {\frac{{{{10}^3}{\text{ g}}}}{{1{\text{ kg}}}}} \right)\\&= 20493.7{\text{ mol}}\\\end{aligned}[/tex]  

Since one mole of [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex] reacts with one mole of [tex]{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}[/tex], 20493.7 moles of [tex]{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}[/tex] reacts with 20493.7 moles of [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex].

The formula to calculate mass of [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex] is as follows:

[tex]{\text{Mass of N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} = \left( {{\text{Moles of N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}} \right)\left( {{\text{Molar mass of N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}} \right)[/tex]                …… (2)

Substitute 20493.7 mol for moles of [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex] and 105.9888 g/mol for molar mass of [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex] in equation (2).

[tex]\begin{aligned}{\text{Mass of N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} &= \left( {{\text{20493}}{\text{.7 mol}}} \right)\left( {{\text{105}}{\text{.9888 g/mol}}} \right)\left( {\frac{{{{10}^{ - 3}}{\text{ kg}}}}{{1{\text{ g}}}}} \right)\\&= 2172.1{\text{ kg}}\\\end{aligned}[/tex]  

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole concept

Keywords: stoichiometry, Na2CO3, H2SO4, Na2SO4, CO2, H2O, balanced chemical reaction, 1:1, one mole, stoichiometric ratio, 2172.1 kg.

To neutralize the sulfuric acid spill, you need to use sodium carbonate (Na2CO3). For every 2 moles of sulfuric acid, you need 2 moles of sodium carbonate. Therefore, to neutralize 2.01 x 10³ kg of sulfuric acid solution, you would need an equal mass of sodium carbonate.

To neutralize the sulfuric acid spill, you need to use sodium carbonate (Na2CO3). The balanced equation for the reaction between sulfuric acid and sodium carbonate is:

2 NaHCO3(aq) + H2SO4(aq) → Na2SO4(aq) + 2 CO2(g) + 2 H2O(l)

From the equation, you can see that for every 2 moles of sulfuric acid, you need 2 moles of sodium carbonate. Therefore, to neutralize 2.01 x 10³ kg of sulfuric acid solution, you would need an equal mass of sodium carbonate. So, you would need 2.01 x 10³ kg of sodium carbonate.

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Answer:

d

Explanation:

Yes, electron N or electron P have a transition that covered a greater energy difference.

Answer : Electron P has greater energy difference than the Electron N.

Explanation :  

Wavelength range of violet light = 400 - 500 nm

Wavelength range of orange light = 600 - 700 nm

The Planck's equation is,

[tex]E=\frac{h\times c}{\lambda}[/tex]

where,

E = energy of light

c = speed of light

[tex]\lambda[/tex] = wavelength of light

According to the Planck's equation, wavelength and energy follow inverse relation. As the wavelength increases, energy decreases.

From the given spectrum, the wavelength of violet light is less. We conclude that When electron P gives violet light on transition it means that energy difference between the energy level was high.

From the given spectrum, the wavelength of orange light is more. We conclude that When electron N  gives orange light on transition it means that energy difference between the energy level was low.

So, Electron P which gives violet light on transition has greater energy difference than the Electron N.

use baby oil...it helps get the oil paint off.  I think it is hard because it is heavier than water and it sticks to your skin and also the water and oil don't mix like other things so it makes it alot harder. use baby oil and wash.

Which of these measurements is expressed as three significant figures?  

C. 4.20 g

Lead has a higher density

The correct answer is 'Replicable results and empirical data'.

For science to be reliable, the scientific method must be replicable and the data must be empirical.

When scientists publish their work they write enough data so that scientists all over the world can replicate their experiment and get same results.

Also the scientific method is based on empirical data which is based on direct observation of the world and is contrary to hypothesis that do not rely on facts.

Answer:

There are 3 sig figs

Explanation:

Sig figs are the amount of figures counting from the left side of the number until you reach the first zero. Starting from the left, I counted one, three, and six. That's 3 numbers, and therefore, that's how we got our answer. The only exception is when there is a decimal. Then all the numbers before the decimal, despite whether or not they're zeros, are sig figs.

Answer:

3 significant figures

Explanation:

The significant figure is such that every number after it is zero. As such, when a number is given to be rounded to a x significant numbers, the count starts from the left with the first number on the left being the first significant number and others following through i.e the next being the second significant number.

However, to round off to x significant number, we consider the number in the x+1 position. If the number is up to 5, it will be rounded ( as well as every other numbers to the right) to zero but 1 will be added to the number in the x position.

Given the theory, 136,000 ml has 3 significant figures.