how many isosceles triangles appear in this figure?

How Many Isosceles Triangles Appear In This Figure?

Answers

Answer 1
Though it looks like BE ≅ CE ≅ AD and BA ≅ BX ≅ DX, these congruencies are not indicated either on the drawing or in the problem statement. Thus they cannot be relied upon.

There is exactly 1 isosceles triangle in the figure.

Related Questions

Lena runs 2/3 mile each day she wants to know how many miles she has to run before she has has run a whole number

Answers

3 days and she will have run 2 miles 
It will take her 3 days for two miles

PLEASE HELP QUICK!!!!

11PTS AND BRAINLIEST AVAILABLE TO CORRECT ANSWER

Answers

Your answer would be B

For a machine, the output force is 20 N, and the output distance is 4 m. Which must be true about the work input? A. It equals 80 J. B. It must be greater than 80 J. C. It must be less than 80 J.

Answers

Work = Force*Displacement
Work = (20 N)*(4 m)
Work = (20*4) Nm
Work = 80 J

So 80 joules of work is the output. Ideally we'd expect 80 J to be the input but that's not the case. There will always be things like heat loss, leading to some level of inefficiency. So if we input some amount of work, say 100 J, then it might drop to 80 J of actual output work after the wasted energy is accounted for.

In short, you have to put more work in than the work you want out. This is why the answer is choice B) It must be greater than 80 J

write an equation of the line that is parallel to the line y = -x + 4 and passes through the points 0, 10.

Please help me!

Answers

Line parallel to y = -x+4 will have the same gradient.
Gradient = -1
Equation of line: y = -x + c
Point : (0,10) replace in the above equation
y = -x + c
10 = -0 + c
c = 10
Equation is: y = -x + 10


Hope it helped!

People who reach retirement age will have accidents and health issues. True False

Answers

The answer is True...

Answer:

Its FALSE on odyssey

A machine packs at a constant rate of 2/3 of a box every 1/2 minuet. What’s is the number of boxes per minute that’s the machine packs?

Answers

For this case what we can do is the following rule of three:
 2/3 of a box ------> 1/2 minutes
 x of a box ---------> 1 minute
 Clearing x we have:
 x = (1 / (1/2)) * (2/3)
 Rewriting:
 x = 2 * (2/3)
 x = 4/3
 Answer:
 the number of boxes per minute that the machine packs is:
 x = 4/3

Find the slope of the line that passes through the points (2 , 0) and (2 , 4).

Answers

[tex]\text {Slope = } \dfrac{Y_2-Y_1}{X_2-X_1} [/tex]

[tex]\text {Slope = } \dfrac{4-0}{2-2} = \dfrac{4}{0} = \infty[/tex]

The graph is a vertical line , x = 2

The slope of the line passing through the given points (2, 0) and (2, 4) is (undefined).

Given the following data:

Points on the x-axis = (2, 2)Points on the y-axis = (0, 4)

To find the slope of the line passing through the given points (2, 0) and (2, 4):

The slope of a straight line.

Mathematically, the slope of a line is given by the following formula;

[tex]Slope. \;m = \frac{Change \; in \; y \;axis}{Change \; in \; x \;axis} \\\\Slope. \;m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Substituting the points into the formula, we have;

[tex]Slope, \;m = \frac{4 - 0}{2 - 2}\\\\Slope, \;m = \frac{4}{0}[/tex]

Slope, m  = (undefined).

Note: A mathematical expression is considered to be undefined when its denominator is zero (0).

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Voluntary sampling is one type of sampling method that is not probability based. This means that
a)each member of a population is equally likely to be chosen for the survey.
b)the results of the survey cannot reliably be extended and generalized.
c)the likelihood of a member of the population volunteering to be surveyed is not probable.
d)the results of the survey are not mathematically probable.

Answers

Answer:

b)the results of the survey cannot reliably be extended and generalized.

Step-by-step explanation:

Voluntary sampling is a type of convenience sample; it is convenient for the researcher to perform.  

However, voluntary sampling can lead to bias; usually only people who feel strongly one way or the other about the survey will volunteer to be members of a sample.

Since there is a possibility of bias, the results of the survey cannot reliably be extended and generalized.

The correct statement is,

b) the results of the survey cannot reliably be extended and generalized.

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Since, We know that;

Voluntary sampling is a type of convenience sample and it is convenient for the researcher to perform.  

However, voluntary sampling can lead to bias; usually only people who feel strongly one way or the other about the survey will volunteer to be members of a sample.

Now, Since there is a possibility of bias,

Hence, the results of the survey cannot reliably be extended and generalized.

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Two or more lines on a graph together is known as a

Answers

Two or more lines on a graph together is known as a system of equations.

A bag of marbles contains 5 red, 10 blue, 3 yellow and 7 green marbles. lisa chooses one marble at random from the bag. what is the probability of not choosing a red marble?

Answers

20/25=4/5 or 80%

There are 20 non-red marbles and there are 25 total marbles

10 POINTS + BRAINLIEST ANSWER

A box contains 30 pieces of chocolate, distributed as shown in the table below. Each piece is made of either white chocolate or dark chocolate, and each piece contains either cream filling or no filling. If one piece is selected at random, what is the probability that the piece is either white chocolate with cream filling or dark chocolate with no filling? (10 POINTS + BRAINLIEST ANSWER)

A. 8/30

B. 12/30

C. 20/30

D. 22/30

Answers

It’s A 5+3= 8
8/30
I need 20 characters

The probability of selecting a chocolate at random that is either white chocolate with cream filling or dark chocolate with no filling is [tex]\frac{8}{30}[/tex].

What is probability?

Probability is the chance of happening an event or incident.

Given, the box contains 30 chocolates.

The number of chocolates that are white chocolate with cream filling is 5.

Therefore, the probability of selecting a chocolate at random that is white chocolate with cream filling is [tex]= \frac{5}{30}[/tex].

The number of chocolates that are dark chocolate with no filling is 3.

Therefore, the probability of selecting a chocolate at random that is dark chocolate with no filling is [tex]= \frac{3}{30}[/tex].

Now, the probability of selecting a chocolate at random that is either white chocolate with cream filling or dark chocolate with no filling is

[tex]= \frac{5}{30} + \frac{3}{30} \\= \frac{8}{30}[/tex]

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how do graphs of y=1/x and y=5/(x+6) compare? I know the second graph shifts to left by 6 units but does it move down and how many units?

Answers

By multiplying the first function with number 5, the graph will stretch by the order of five, meaning that in the second graph every value of the x will correspond to the 5 times bigger value of y than in the first case. Due to the +6 component, the second graph shifts to the left by 6 units.

Answer:

y = 5/x +6 makes your raises your graph 6 units higher.

Step-by-step explanation:

check my work please will give medals if you tell if this is right or not!!!
Let f(x)=x+5 and g(x)=x^2. find (g o f) (4)
A. 9 <--- my answer
B. 81
C. 20
D. 1
2. police can estimate the speed of a vehicle before the brakes are applied using the formula 0.75d=s^2/30.25, where s is the speed in miles per hour and d is the length of the vehicle's skid marks. what was the approximate speed of a vehicle that left skid marks measuring 140 feet?
A. about 10 miles per hour <-- my answer
B. about 75 miles per hour
C. about 15 miles per hour
D. about 56 miles per hour,

Answers

Since f(x)=(x+5) and g(x)=x^2, (g circle f)(x) means g(f(x)) which is composition. This tells us to substitute f(x) into g wherever there is an x. Here we want g(f(4)). First substitute 4 into f. THat is f(4)=4+5=9. THe we want g(f(4))=g(9). SUbstitute 9 into g which would be 9^2=81. The answer is 81. If .75d=s^2/30.25 and we know d is the length of the skid mark which here is 140, we substitute 140 in for d. 0.75*140=s^2/30.25 Multiply both sides by 30.25. s^2=105*30.25=3176.25 Take the square root of both sides and we get +/- sqrt 3176.25 But we only want the positive answer since we are talking speed. So s=56.358 which is about 56 miles per hour.
1. The answer is letter B. 81
Since f(x)=(x+5) and g(x)=x^2, 
First substitute 4 into f which is
 f(4)=4+5=9.
then g(f(4))=g(9). 
 9^2=81

2.The answer is D. about 56 miles per hour
75d=s^2/30.25
given: d= 140
so 0.75*140=s^2/30.25
 s^2=105*30.25=3176.25 
= +/- sqrt 3176.25 
 s=56.358
=56 miles per hour.

What is the reciprocal of 4 3/7? Please help!

Answers

The reciprocal of the mixed number 4 3/7 is 7/31. To find the reciprocal of a mixed number, you change it into an improper fraction, then you flip it so that the original numerator is the denominator and the original denominator is the numerator.
I hope this helped! :-)

The reciprocal of number 4 3/7 is 7/31.

What is a fraction?

In such a fraction, the value that appears above the horizontal line is referred to as the numerator.

It represents the number of pieces removed from the whole. The denominator of a fraction is the numerical value that comes before the brings together various.

Given the mixed number

4 3/7 = (7×4 + 3)/7

⇒ 31/7

Now reciprocal is nothing but an interchange of numerator and denominator.

So

Reciprocal of 31/7 → 7/31

Hence "The reciprocal of number 4 3/7 is 7/31".

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20 POINTS!! EASY QUESTION! WILL MARK BRAINLIEST!! READ THE INFO! THEN FILL IN THE BLANKS!

The cost for a single class session for each dance class is below.

Clodagh’s Dance = $6.00
New Steps = $7.50
Stepping High = $6.50


The class hours are below.

Clodagh’s Dance = 3:00pm - 4:00pm
New Steps = 4:00pm - 5:30pm
Stepping High = 9:00am - 10:15am


How would these answers change if you were to write the unit rate in cost per hour?
Fill in the blanks!

Dance Classes | Total Hours for Each Payment | Cost Per Hour
| |
Clodagh’s Dance | $6.00 | $6.00
New Steps | $7.50 | _____
Stepping High | $6.50 | _____

Answers

To find the unit rate in cost per hour, you will write the amount of money over the total time for each class. Then divide the cost by the time to find the unit rate.


New Steps: $7.50/1.5 hours = $5 per hour


Stepping High: $6.50/1.25 hours = $5.20 per hour

Answer:

To find the unit rate in cost per hour, you will write the amount of money over the total time for each class. Then divide the cost by the time to find the unit rate.

New Steps: $7.50/1.5 hours = $5 per hour

Stepping High: $6.50/1.25 hours = $5.20 per hour

darren has 3/4 of a gallon of soil.he needs to plant 5 small plants.if he splits the soil evenly between the plants.how much soil will each plant get?

Answers

3/4 divides by 5

3/4 x 1/5 = 3/20 of a gallon

Which group of measurements could be the side lengths of a right triangle?
A.
57 in, 86 in, 95 in
B.
47 in, 76 in, 95 in
C.
57 in, 76 in, 95 in
D.
57 in, 76 in, 105 in

Answers

In right angled triangles, according to Pythagoras' theorem, squared of the hypotenuse is equal to the sum of the squares of the other 2 sides of the triangle.
if the hypotenuse is H and other 2 sides are A and B, then equation is as follows;
H² = A² + B²

1. A - 57 in. B - 86 in.
H² = A² + B²
H² = 57² + 86²
H² = 3249 + 7396
H  = √10645
    = 103.17 in.
third side given is not 103 in therefore this is not a right angled triangle 

2. A - 47 in. B - 76 in.
H² = A² + B²
H² = 47² + 76²
     = 2209 + 5776
H   = √7985
H = 89.3 in.
third side given is 95 in. therefore this is not a right angled triangle.

3. A- 57 in. + B - 76 in.
H² = A² + B²
H² = 57² + 76²
     = 3249 + 5776
H = √9025
H = 95 in.
third side given is 95 in. therefore this is a right angled triangle.

4. A - 57 in. B - 76 in.
As calculated in the third equation with the same side lengths of A and B, hypotenuse should be 95 in. however the third side length given is 105 in. so this is not a right angle triangle 

Jared is a boxer. He can box in the Heavyweight class if his mass is at least 100 \text{ kg}100 kg100, space, k, g by the end of the month. Write an inequality that is true only for masses (m)(m)left parenthesis, m, right parenthesis at which Jared can box in the Heavyweight class.

Answers

 the answer would be m≥100 hope this helps

Answer:

Inequality for the given condition for the weight (m) ≥ 100 (greater than or equal to)

Explanation:

let suppose weight of Jared is "m" according to the given question.

His weight should be atleast (greater than or equal to ) 100 kilogram in order to box is heavy weight class.

So, our inequality equation for the above condition is :

m is greater than or equal to 100

m ≥ 100   That's the final answer.

I hope it will help you.

On a hot, sunny day, a random selection of people in a small town were given a photo of a skating rink in a big city and asked the following question: "Do you think our town should look into building an outdoor skating rink?" Which of the following might be a problem with the survey?

Select one:
a. Timing
b. Privacy
c. Bias
d. Cost

Answers

It can't be timing or cost since it is only a few people , i chose bias because a few people is actually 7 - 8 people 

Please help ASAP!!!! 52 points and will give brainliest for RIGHT answer!

Answers

i have made sure and the correct answer is d

5. (10.01 MC) If sin θ = 1 over 4 and tan θ > 0, what is the value of cos θ? (1 point)

Answers

To find the value of cos θ when sin θ = 1/4 and tan θ > 0, use the Pythagorean identity. As the angle is in the first quadrant, cos θ is positive and equals the square root of 15/16 or √15/4.

If sin θ = 1/4 and tan θ > 0, we need to determine the value of cos θ. When the sine of an angle is positive and the tangent is positive, we know the angle must be in the first quadrant, where all trigonometric functions are positive. To find cos θ, we utilize the Pythagorean identity sin2 θ + cos2 θ = 1. Rewriting this identity for cos θ, we get cos2 θ = 1 - sin2 θ.

Substituting the given value of sin θ, we have:

cos2 θ = 1 - (1/4)2
cos2 θ = 1 - 1/16
cos2 θ = 15/16

Since θ is in the first quadrant, and cos θ is positive, the value of cos θ is the positive square root of 15/16:

cos θ = √(15/16)
cos θ = √15/4 or approximately 0.9682

Find the slope of the line that contains the points named. C(3, 8), D(-2, 5) -3/5 3/5 5/3

Answers

the slope formula is y2-y1/x2-x1 so if you plug in the numbers you get 3/5. the slope is 3/5

Answer: [tex]\dfrac{3}{5}[/tex]

Step-by-step explanation:

The slope of a line passing through two points X(a,b) and Y(c,d) is given by :-

[tex]m=\dfrac{d-b}{c-a}[/tex]

Given points : C(3, 8) and  D(-2, 5)

Then , the  slope of a line passing through two points C(3, 8) and  D(-2, 5) is given by :-

[tex]m=\dfrac{5-8}{-2-3}=\dfrac{-3}{-5}=\dfrac{3}{5}[/tex]

Hence, the  slope of the line that contains the points C(3, 8) and  D(-2, 5) is [tex]\dfrac{3}{5}[/tex]

.

find the solution of this system of equations shown on the graph.

Answers

answer is (0,3)

hope it helps

A job applicant estimates that his chance of passing a qualifying examination is 2/3, and his chance of being appointed if he does pass is 1/4. What is the probability that he will receive the job?

Answers

so, basically 2
2 * 1
- -
3 * 4
so 2 /12
1/6 when simplified
Answer:

Hence, the probability that he will receive job is:

                                   1/6

Step-by-step explanation:

It is given that:

chance of passing a qualifying examination is 2/3=P

and chance of being appointed if he does pass is 1/4=P'

Now, we are asked to find the probability that he will receive the job.

We are asked to find the probability that he will receive the job.

The probability is calculated as:

Probability that he qualify exam×Probability that he is being appointed.

=P×P'

=(2/3)×(1/4)

=1/6

Solve the system of equations

1.8x-0.5y=-6.4
0.6x+2.1y=2.4

_______________________

x= ??

y= ??

Answers

Solve the following system:
{1.8 x - 0.5 y = -6.4
{0.6 x + 2.1 y = 2.4

In the first equation, look to solve for x:
{1.8 x - 0.5 y = -6.4
{0.6 x + 2.1 y = 2.4

1.8 x - 0.5 y = (9 x)/5 - y/2 and -6.4 = -32/5:
{(9 x)/5 - y/2 = -32/5


Add y/2 to both sides:
{(9 x)/5 = 1/10 (5 y - 64)
{0.6 x + 2.1 y = 2.4

Multiply both sides by 5/9:
{x = 1/18 (5 y - 64)
{0.6 x + 2.1 y = 2.4

Substitute x = 1/18 (5 y - 64) into the second equation:
{x = 1/18 (5 y - 64)
{2.1 y + 0.0333333 (5 y - 64) = 2.4

2.1 y + 0.0333333 (5 y - 64) = 2.1 y + (0.166667 y - 2.13333) = 2.26667 y - 2.13333:
{x = 1/18 (5 y - 64)
2.26667 y - 2.13333 = 2.4

In the second equation, look to solve for y:
{x = 1/18 (5 y - 64)
{2.26667 y - 2.13333 = 2.4

2.26667 y - 2.13333 = (34 y)/15 - 32/15 and 2.4 = 12/5:
(34 y)/15 - 32/15 = 12/5

Add 32/15 to both sides:
{x = 1/18 (5 y - 64)
{(34 y)/15 = 68/15

Multiply both sides by 15/34:
{x = 1/18 (5 y - 64)
y = 2


Substitute y = 2 into the first equation:

Answer: {x = -3, y = 2

The population P(t) of a species satisfies the logistic differential equation dP/dt= P(2-(P/5000)) where the initial population 3,000 and t is the time in years. What is the lim t>infinity P(t)?

Answers

A logistic differential equation can be written as follows:
[tex] \frac{dP}{dt} = rP[1- \frac{P}{K}] [/tex]

where r = growth parameter and K = carrying parameter.

In order to write you equation in this form, you have to regroup 2:
[tex] \frac{dP}{dt} = 2P[1- \frac{P}{10000}] [/tex]

Therefore, in you case r = 2 and K = 10000

To solve the logistic differential equation you need to solve:

[tex] \int { \frac{1}{[P(1- \frac{P}{K})] } } \, dP = \int {r} \, dt [/tex]

The soution will be:

P(t) = [tex] \frac{P(0)K}{P(0)+(K-P(0)) e^{-rt} } [/tex]

where P(0) is the initial population.

In your case, you'll have:

P(t) = [tex] \frac{3E7}{3E3+7E3 e^{-2t} } [/tex]

Now you have to calculate the limit of P(t).
We know that
[tex] \lim_{t \to \infty} e^{-2t} -\ \textgreater \ 0 [/tex]

hence,

[tex] \lim_{t \to \infty} P(t) = \lim_{t \to \infty} \frac{3E7}{3E3+0} = 10^{4} [/tex]




Final answer:

The lim t>infinity P(t) is 5,000, which is the carrying capacity of the species.

Explanation:

The logistic differential equation dP/dt = P(2-(P/5000)) models the population growth of a species. To find the lim t>infinity P(t), we need to find the stable population when t becomes very large. In this equation, the population growth rate is initially exponential, but as the population approaches its carrying capacity (Q), the growth rate slows down and levels off to zero.

Solving the differential equation, we find that the equation represents logistic growth. The solution to the equation is P(t) = Q / (1 + (Q/Po)e^(-rt)), where Po is the initial population, Q is the carrying capacity, and r is the growth rate.

In this case, the initial population is given as 3,000. To find the carrying capacity (Q), we set dP/dt = 0 and solve for P. Substituting the values into the equation, we find Q = 5,000.

As t becomes very large, e^(-rt) approaches 0, and the equation simplifies to P(t) = Q. Therefore, the lim t>infinity P(t) is 5,000, which is the carrying capacity of the species.

longer
congruent
shorter
proportional

Answers

Shorter. Because of the way the arches work. the pink dot is the center.

WILL MARK AS BRAINLIEST
Complete the general form of the equation of a sinusoidal function having an amplitude of 1, a period of [tex]\frac{ \pi }{2} [/tex], and a vertical shift up 3 units.
y=__________

Answers

The general form for a sine function is: y = a sin(b[x + c]) + d
The amplitude is given by a, so a = 1.
The period is given by 2*pi/b, so 2*pi/b = pi/2, and b = 4.
The variable c gives the horizontal shift, of which there is none, so c = 0.
Finally, the vertical shift of 3 units means that d = 3.
So the equation is:
y = sin(4x) + 3

Answer:

y = sin(4x) + 3

Step-by-step explanation:

The trinket store is open for 14 hours per day. They sell an average of 5 trinkets per hour. The back storeroom currently has 560 trinkets in it

Answers

Q1)
write the equation that estimates the number of trinkets T that will be in the storeroom after H hours
Initially the number of trinkets available = 560
every hour they sell an average of 5 trinkets 
therefore in H hours, number of trinkets that will be sold = 5 trinkets/hr * H hrs
number of trinkets sold in H hours = 5H
the remaining number of trinkets = T
T = number of trinkets initially available - number of trinkets sold 

T = 560 -5H

Q2) 
How many days will it take to run out of trinkets 
number of trinkets sold per hour - 5 
number of hours the shop is open for - 14 hours / day
during one day number of trinkets sold - 5 trinkets/hr x 14 hrs/ day
                                                              = 70 trinkets per day
there are 560 trinkets available 
and if 70 trinkets are sold per day 
number of days it takes to sell 560 trinkets 
days = 560 trinkets / 70 trinkets/day 
         = 8 days 

the third response is correct - 1) T = 560 -5H
                                                2) 8 days

The storage container below is in the shape of a rectangular prism with a height of 6 feet and a length that is 2 feet more than its width. recall that the formula for the volume of a rectangular prism is v = l · w · h, where l is the length, w is the width, and h is the height. write the equation that represents the volume of the storage container in terms of its width.

Answers

Let
l ------------------> is the length
w -----------------> is the width
h ----------------- > is the height
we know that
h=6 ft
l=2+w
[the volume of the storage ]=[l]*[w]*[h]------> [2+w]*[w]*[6]
[the volume of the storage ]=[l]*[w]*[h]------> 6*[2w+w²]-----> 6w²+12w

the answer is
V=[6w²+12w] ft²


Answer:

V = 6w² + 12w

Step-by-step explanation:

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