How many milliliters of 5.50 m hcl(aq) are required to react with 9.55 g of zn(s)?

Answers

Answer 1

Final answer:

To react with 9.55 g of Zn(s), you will need 53.1 mL of a 5.50 M HCl(aq) solution.

Explanation:

To determine the volume of 5.50 M HCl(aq) required to react with 9.55 g of Zn(s), we need to use the balanced chemical equation:

Zn(s) + 2 HCl(aq) → ZnCl2 (aq) + H2(g)

From the equation, we can see that 1 mole of Zn reacts with 2 moles of HCl. First, we need to calculate the moles of Zn using its molar mass and mass given:

Moles of Zn = mass / molar mass = 9.55 g / 65.38 g/mol = 0.146 moles

Since the stoichiometric ratio between HCl and Zn is 2:1, the moles of HCl needed will be double:

Moles of HCl = 2 × moles of Zn = 2 × 0.146 mol = 0.292 mol

Finally, to calculate the volume of HCl, we need to use its molarity:

Volume of HCl = moles of HCl / molarity = 0.292 mol / 5.50 M = 0.0531 L = 53.1 mL


Related Questions

What happens if you cool the crystallization solution in a container of ice that is too big?

Answers

Crystallization is a physical change from liquid form to solid form. It is the opposite of melting. This is done by creating a supersaturated solution. You add more solute exceeding its capacity and heat so that all will dissolve. Then, when you cool it down with an aid of the ice, solid crystals will eventually form. The bigger the container the ice, the faster is the rate of crystallization and the bigger the solid crystals would be.

A certain ore is 37.3% nickel by mass how many kilograms of this ore would you need to dig up to have 10.0g of nickel

Answers

If the grade of the ore is 37.3% nickel, then the unknown quantity to get 10 grams of nickel is 0.373 x = 10 grams or x = 10/0.373=26.8 grams or 0.0268 kg needed to dig up to recover the 10 grams of nickel. At this grade of ore, 1 kilogram would yield 373 grams of nickel. 

insulin is a protein that is used by the body to regulate both carbohydrate and fat metabolism. a bottle contains 475 mL of insulin at a concentration of 30.o mg/mL what is the total mass in the bottle?

Answers

Given: Insulin bottle = 475 mL, Concentration = 30.0 mg/mL We are ask to find the total mass in the bottle.  The formula that we will be using is 475(x) * 30(x) = 1 (x)30(mg/mL)*475(mL) cancel the unit mL= (300*475)mg = 14250 mg

Why does calcium chloride weigh more when exposed to air?

Answers

Calcium chloride is hygroscopic so it absorbs water when it is exposed to air and this leads to an increase in weight.

What is the probability that four 13c isotopes will be adjacent to each other in benzene? g?

Answers

Final answer:

The probability of four 13C isotopes being adjacent to each other in a benzene molecule, given their natural molar abundance of roughly 1%, is extremely low at 1x10⁻⁸, due to the need for this specific arrangement to occur consecutively.

Explanation:

The question asks about the probability of four 13C isotopes being adjacent to each other in a benzene molecule. Given that the natural molar abundance of 13C is roughly 1%, the probability of any given carbon atom in benzene being 13C is 0.01. Since benzene has a ring structure with 6 carbon atoms, the probability of any specific sequence of four carbon atoms being all 13C can be calculated using the multiplication rule of probability.

To find the probability of four 13C isotopes in a row, we raise the single-event probability (0.01) to the fourth power because we need this event to happen four times consecutively for four specific carbon atoms:

Probability = 0.01⁴ = 0.00000001 or 1x10⁻⁸

This calculation shows that the probability is extremely low, reflecting the rare occurrence of such an event due to the low natural abundance of 13C.

Calculate the mass (in g) of 2.1 x 1024 atoms of W.

Answers

Set up your units to algebraically cancel out the original unit, and end up with the units of the answer in the final numerator. We'll first convert to moles by using Avogadro's number, then the atomic mass of tungsten (W) from the periodic table, since the mass, in grams, of one mole of any element is the atomic mass number:
2.1x10∧24 atoms W x (1 mole/6.022x10∧23 atoms) x (183.84g/1 mole) = 641.089 grams
Since your given number has only two significant figures (2.1), your answer should also only express in 2 sig figs: 6.4x10∧2 grams

The mass of [tex]\( 2.1 \times 10^{24} \)[/tex] atoms of tungsten (W) is [tex]641.03 \text{ g}} \)[/tex].

To calculate the mass of [tex]\( 2.1 \times 10^{24} \)[/tex] atoms of tungsten (W), we'll follow these steps:

1. Find the molar mass of tungsten (W):

The molar mass of tungsten (W) is approximately [tex]\( 183.84 \)[/tex] g/mol.

2. Convert atoms to moles:

Use Avogadro's number to convert the number of atoms to moles:

[tex]\[ \text{Number of moles} = \frac{\text{Number of atoms}}{\text{Avogadro's number}} \][/tex]

Avogadro's number is [tex]\( 6.022 \times 10^{23} \)[/tex] atoms/mol.

[tex]\[ \text{Number of moles} = \frac{2.1 \times 10^{24}}{6.022 \times 10^{23}} \]\[ \text{Number of moles} = 3.487 \text{ moles} \][/tex]

3. Calculate the mass:

Now, multiply the number of moles by the molar mass to find the mass in grams:

[tex]\[ \text{Mass} = \text{Number of moles} \times \text{Molar mass} \]\[ \text{Mass} = 3.487 \text{ moles} \times 183.84 \text{ g/mol} \]\[ \text{Mass} = 641.03 \text{ g} \][/tex]

Therefore, the mass of [tex]\( 2.1 \times 10^{24} \)[/tex] atoms of tungsten (W) is [tex]641.03 \text{ g}} \)[/tex].

The sphere is the layer of the earth that contains a mixture of gases

Answers

Omoze layer I know this

No... I believe that the part of Earth that contains mixtures of gases is the atmosphere, along with its layers.

Which statement describes a chemical property of oxygen

Answers

Oxygen can combine with a metal to produce a compound
Oxygen gas can be compressed.

The iupac name for ch3–ch2–c ≡ c–ch3 is ________

Answers

The IUPAC name of the compound ch3–ch2–c ≡ c–ch3 is PEN-2-YNE or 2-PENTYNE.

Attached below is a diagram that fully explains how the name was given and derived.

Final answer:

The IUPAC name for CH3–CH2–C ≡ C–CH3 is 3-hexyne.

Explanation:

The IUPAC name for CH3–CH2–C ≡ C–CH3 is 3-hexyne.

In this compound, the longest carbon chain contains six carbons, so it is called a hexyne. The triple bond is between the third and fourth carbon, so the name includes the prefix 3-

The reaction between elemental phosphorus p4(s) and o2(g) to make p4o10(s):

Answers

The reaction between elemental phosphorus p4(s) and o2(g) is a synthesis type of reaction where two elements combine together to form a compound. Balancing the equation, we get P4(s) + 5 O2(g) = P4O10(s). Here the number of oxygen molecules are balanced on either side by adding 5 molecules of O2 on the product side.

Write the balanced molecular equation for the neutralization reaction between h2so4 and koh in aqueous solution. phases are optional.

Answers

Final answer:

The balanced molecular equation for the neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) is H2SO4(aq) + 2KOH(aq) → K2SO4(aq) + 2H2O(l). This showcases a typical neutralization reaction, where an acid reacts with a base to produce salt and water.

Explanation:

The neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) results in the formation of water (H2O) and potassium sulfate (K2SO4). The reaction's balanced molecular equation is:

H2SO4(aq) + 2KOH(aq) → K2SO4(aq) + 2H2O(l)

This equation is a clear representation of a neutralization reaction where an acid reacts with a base to produce salt and water. In this specific instance, the acid is H2SO4, the base is KOH, the salt is K2SO4, and, of course, the water is H2O.

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Final answer:

The balanced molecular equation for the neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) is H2SO4 (aq) + 2KOH(aq) → K2SO4 (aq) + 2H2O(l). This reaction is a classic example of a neutralization reaction, where an acid reacts with a base to form salt and water.

Explanation:

The neutralization reaction between H2SO4 (sulfuric acid) and KOH (potassium hydroxide) in aqueous solution can be represented as follows:

H2SO4 (aq) + 2KOH(aq) → K2SO4 (aq) + 2H2O(l)

This resulting equation is balanced, meaning the number of atoms of each element is the same on both sides of the equation. In this case, a base (KOH) and an acid (H2SO4) react to form a salt (K2SO4) and water, which is characteristic of a neutralization reaction.

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The Atomic Mass of Al is 26.98154 g/mol. Is it possible to have 5.0 × 10^-25 g of Al? Explain.

Answers

If a mole of aluminum weighs 26.98 grams, that means 1 atom of aluminum weighs = (26.98 g/mole) / (6.023 x 10^23 atoms/mole) = 4.479 x 10^-23 grams,

so, it is not possible because 1 atom weighs that much we calculated which is almost 100 times more than the amount you mentioned

It is theoretically possible to have 5.0 × 10⁻²⁵ g of Al, but this is realistically impossible because it is smaller than the mass of a single aluminum atom.

The question asks if it's possible to have 5.0 × 10⁻²⁵ g of aluminum (Al), given that the atomic mass of Al is 26.98154 g/mol. One mole of Al has a mass in grams that is numerically equivalent to its atomic mass. Since the mass of 1 mol of Al is 26.98 g, having a sample of 5.0 × 10⁻²⁵ g is theoretically possible but practically not feasible since this mass represents far less than a single atom of Al. The smallest practical amount of Al one can have is the mass of one atom, which is much more than 5.0 × 10⁻²⁵ g. Hence, 5.0×10⁻²⁵ g of Al is not a meaningful physical quantity because it is significantly less than the mass of one atom, and one cannot have a fraction of an atom.

what is the molarity of sucrose if 150.0 g is dissolved in 250.0 mL of solution

Answers

Sucrose has the following formula: C12H22O11

From the periodic table:
mass of carbon = 12 grams
mass of hydrogen = 1 gram
mass of oxygen = 16 grams

molar mass of sucrose = 12(12) + 22(1) + 11(16) = 342 grams

number of moles = mass / molar mass = 150 / 342 = 0.4385 moles
250 ml = 0.25 liters

molarity can be calculated as follows:
molarity = number of moles of solute / liters of solvent
molarity = 0.4382 / 0.25 = 1.75 M

Why are covalent bonds between hydrogen and nitrogen or oxygen polar? see section 2.1 ( page 57) ?

Answers

Polar molecules exhibit an unequal balance of charges between the individual elements of the compound. This is brought about by the large difference in their electronegativities. The H atom has the least amount of electronegativity. Then, it is a known periodic trend, that as you go downwards in a group, electronegativity decreases, and increase as you go from left to right. Thus, you can deduce that the most electronegative elements are found in the upper right corner which includes O, N and F atoms. Any bond created between Hydrogen and any of O, N and F atoms is a polar bond.

which statement describes a homogeneous mixture

Answers

A homogeneous mixtureis a mixture that is uniform and consistent throughout. A homogeneous mixture can also be called a solution.

90 nitroglycerin (c3h5n3o9) is a powerful explosive. its decomposition may be represented by this reaction generates a large amount of heat and many gaseous products. it is the sudden formation of these gases, together with their rapid expansion, that produces the explosion. (a) what is the maximum amount of o2 in grams that can be obtained from 2.00 × 102 g of nitroglycerin? (b) calculate the percent yield in this reaction if the amount of o2 generated is found to be 6.55 g.

Answers

The reaction for the decomposition of nitroglycerin is:

4 C₃H₅N₃O₉ (l) → 6 N₂ (g) + 12 CO₂ (g) + 10 H₂O (g) + O₂ (g)

a.) The molar mass of C₃H₅N₃O₉ is 227 g/mol. Let's compute for the number of moles nitroglycerin.

Moles of nitroglycerin = 200 g * 1 mol/227 g = 0.881 mol
Moles O₂ produced = 0.881 mol nitroglycerin(1 mol O₂/4 mol nitroglycerin) = 0.22 mol O₂

The molar mass of O₂ is 32 g/mol. So, the corresponding mass would be:
Mass O₂ produced = 0.22 mol O₂(32 g/mol) = 7.048 g O₂

b.) The percent yield is equal to the actual yield divided by the theoretical yield. The amount calculated in part a is the theoretical yield, while the given in part b is the actual yield.

Percent yield = (6.55 g/7.048 g)*100 = 92.93%
Final answer:

The maximum amount of O2 that can be obtained from 227 g of nitroglycerin is 907 grams. The percent yield of O2 in this reaction is 0.72%.

Explanation:

Nitroglycerin decomposes according to the following reaction:

2 C3H5N3O9 → 3 N2 + 5 H2O + 7 CO + 7 C

To determine the maximum amount of O2 that can be obtained from a given amount of nitroglycerin, we need to calculate the molar mass of nitroglycerin and find the stoichiometric ratio between O2 and nitroglycerin. The molar mass of nitroglycerin is approximately 227 g/mol. From the balanced equation, we can see that 2 moles of nitroglycerin produce 7 moles of O2. Therefore, if we have 227 grams of nitroglycerin, we can calculate the amount of O2 produced as follows:

(227 g nitroglycerin) * (7 moles O2 / 2 moles nitroglycerin) * (32 g O2 / 1 mole O2) = 907 g O2

So, the maximum amount of O2 that can be obtained from 227 g of nitroglycerin is 907 grams.

To calculate the percent yield, we compare the actual yield (6.55 g) to the theoretical yield (907 g) and calculate the percentage:

Percent Yield = (Actual Yield / Theoretical Yield) * 100%

Percent Yield = (6.55 g / 907 g) * 100% = 0.72%

The word hydrolysis has two roots, hydro and lysis. describe how this term relates to the chemical reaction illustrated in model 2

Answers

The root words in this item are hydro- are lysis-. Hydro pertains to water and lysis is the disintegration of a cell or a compound. The word hydrolysis is the disintegration or the breaking of the compound because or due to its reaction with water. This usually brings about changes in pH of a solution. 

How many gold atoms are in an 0.333 ounce, 18 k gold bracelet? (18 k gold is 75% gold by mass.)?

Answers

0.333 ounce * 0.75 * 28.35 grams/ounce = 7.080 grams gold 7.080 grams Au / 196.967g/mol Au = 0.0359 mol Au 0.0359 mol Au * (6.023 * 10^23) atoms/mol = 2.24 * 10^22 Atoms Au
Final answer:

An 18 karat gold bracelet weighing 0.333 ounces contains approximately 2.16 × 10^22 atoms of gold. This calculation is based on converting the weight to grams, accounting for the 75% gold content of the bracelet, and using Avogadro's number.

Explanation:

To calculate how many gold atoms are in an 0.333 ounce, 18 k (karat) gold bracelet, we must first convert the mass of the bracelet into grams since the mass of gold is typically measured in grams. We know that 18 karat gold is comprised of 75% gold by mass. Once the mass of pure gold is identified, we can use Avogadro's number to determine the amount of atoms in that mass.

First, 0.333 ounces is approximately 9.43 grams (1 ounce = 28.3495 grams). Since the bracelet is 18k gold or 75% gold, the mass of pure gold would be 75% of 9.43 grams, which equals approximately 7.0725 grams of gold.

We know from the periodic table that the atomic mass of gold (Au) is approximately 197 g/mol, which means that 1 mole of gold has a mass of about 197 grams. Using this, we can determine the number of moles of gold in our bracelet:

7.0725 grams Au × (1 mole Au / 197 grams Au) = 0.0359 moles Au

Avogadro's number tells us that 1 mole of any substance contains approximately 6.022 × 1023 atoms. So:

0.0359 moles Au × (6.022 × 1023 atoms/mole) = approximately 2.16 × 1022 atoms of gold.

Therefore, an 18 karat gold bracelet weighing 0.333 ounces, which corresponds to 75% gold by mass, contains approximately 2.16 × 1022 atoms of gold.

Joseph Priestly discovered and described the chemical properties of oxygen. What type of chemist would he be considered today

Answers

The answer is inorganic chemist.

Answer : Inorganic Chemist.

Explanation : When Joseph Priestly discovered and described the chemical properties of oxygen, then he would be considered as inorganic chemist.

As the physical and chemical properties of elements are studied under the branch of inorganic chemistry, therefore he would be considered as an inorganic chemist.

If your lawn is 21.0 ft wide and 20.0 ft long, and each square foot of lawn accumulates 1350 new snow flakes every minute. How much snow (in kilograms) accumulates on your lawn per hour? Assume an average snow flake has a mass of 1.60 mg.

Answers

Let us start with the total area of the lawn. Area= width x length, ie, 21 x 20 = 420 sq. ft.   Snow flakes per square foot per minute = 1350  So Snow flakes for 420 sq.feet per minute = 420 x 1350 = 567000.   Snow flakes for 1 hour = 567000 x 60 = 34020000 (60 minutes)  Weight of 34020000 snow flakes = 34020000 x 1.60 = 54432000mg.  To convert it into kilograms, divide this number by 1000000 (1 kilogram = 1000000 milligrams)  Thus 54432000/1000000 = 54.432 kilograms or 54 kilograms and 432 grams.

What is the common difference between successive terms in the sequence? 9, 2.5,-4, -10.5,-17,

Answers

6.5 is subtracted from each number.
9 - 6.5 = 2.5
2.5 - 6.5 = -4
-4 - 6.5 = -10.5
-10.5 - 6.5 = -17
or you could think of adding -6.5 to everything if that is easier for you to picture. 

Answer:

-6.5

Explanation:

What is the name of an isotope with 23 protons and 25 neutrons?

Answers

I believe it's Vanadium.
Vanadium but I'm not sure what the charge is. it should be neutral. I hope this helps!

Question 25 for each chemical reaction in the table below, decide whether the highlighted reactant is a brønsted-lowry acid, a brønsted-lowry base, or neither.

Answers

According to the Bronsted-Lowry definitions, an acid is any substance that donates hydrogen ions; whereas, a base is any substance that accepts hydrogen ions. 

In the first reaction, water is acting as an acid because it donates a hydrogen ions.

In the second reaction, water is acting as a base because it accepts a hydrogen ion.

In the third reaction, water is again donating a hydrogen ion so it is the acid.

In the fourth reaction, water is acting as a base by accepting the hydrogen ion from the ammonium ion.
Final answer:

In the table, the highlighted reactants NH3 and Ag2CO3 are Brønsted-Lowry bases, whereas the reactant in the electrolysis of a solution of strontium chloride reaction cannot be determined without more information.

Explanation:

In the table, we have the following reactions:

a) NH3 + HC104
b) Ag2CO3 + HNO3
c) electrolysis of a solution of strontium chloride

From the information given, we can determine the type of reactant for each reaction.

a) NH3 is a weak base and HC104 is a strong acid, so NH3 is a Brønsted-Lowry base.
b) Ag2CO3 is a weak base and HNO3 is a strong acid, so Ag2CO3 is a Brønsted-Lowry base.
c) In this reaction, the type of reactant is not specified, so we cannot determine if it is a Brønsted-Lowry acid or base.

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What would likely happen if a hot saturated solution were filtered by vacuum filtration using a büchner funnel? (hint: the mixture will cool as it comes in contact with the büchner funnel.)?

Answers

Final answer:

A hot saturated solution, when filtered using a Büchner funnel, may result in the precipitation of the solute as the solution cools down. This is due to the decreased solubility at cooler temperatures.

Explanation:

If a hot saturated solution was filtered using vacuum filtration with a Büchner funnel, some of the solutes could precipitate out of the solution as it cools down. This is because the solubility of most solutes decreases as the temperature decreases. Thus, as the hot solution comes in contact with the cooler Büchner funnel and cools down, the solute's ability to remain dissolved lessens, leading to the precipitation of the solute. The precipitate could end up on the filter in the Büchner funnel, potentially clogging it and affecting the filtration process.

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Vacuum filtration with a Büchner funnel for a hot saturated solution will cause rapid cooling, leading to crystal formation on the filter paper or in the stem, thus clogging the setup.

A crystal formation occurs on the filter paper or in the stem and as a result the setup is clogged.

A hot filtration is essential for filtering solutions that crystallize upon cooling. Vacuum filtration using a Büchner funnel would cause the mixture to cool rapidly. Consequently, crystals would form on the filter paper or in the stem, clogging the setup and reducing yield.

To avoid this, ensure the funnel is pre-warmed and maintain a hot temperature during the filtration process.

Calculate the number of moles of calcium ions present in a 50.00 mL water sample that has a hardness of 75.0 ppm (hardness due to CaCO3)

Answers

hardness = 75ppm = 75 mg / L

volume = 50 mL =  0.05 L

So, applying hardness formula:

Hardness = mass / volume

so, mass =  hardness x volume = 75 x 0.05 =  3.75 mg = 0.00375 g

So, moles of CaCO3 = moles of Ca2+ ions = mass / molar mass of CaCO3 =  0.00375 / 100.06  =  0.00003747751 moles 

The number of moles of calcium ions present in a 50.00 mL water sample with hardness of 75.0 ppmis [tex]\boxed{0.00003747{\text{ mol}}}[/tex].

Further Explanation:

The hardness of water is calculated with the use of following formula:

[tex]{\text{Hardness}} = \dfrac{{{\text{Mass}}}}{{{\text{Volume}}}}[/tex]                                                                      …… (1)

Since hardness in given problem occurs due to presence of [tex]{\text{CaC}}{{\text{O}}_{\text{3}}}[/tex], the above formula involves mass of [tex]{\text{CaC}}{{\text{O}}_{\text{3}}}[/tex] and volume of [tex]{\text{CaC}}{{\text{O}}_{\text{3}}}[/tex].

Rearrange equation (1) to calculate mass.

[tex]{\text{Mass}} = \left( {{\text{Hardness}}} \right)\left( {{\text{Volume}}} \right)[/tex]                                                       …… (2)

In case of water, 1 ppm is approximately equivalent to 1 mg/L. Therefore hardness becomes 75.0 mg/L.

Volume is given in mL. It is to be converted into L. The conversion factor for this is,

[tex]1{\text{ mL}} = {10^{ - 3}}{\text{ L}}[/tex]  

Therefore volume of water sample can be calculated as follows:

[tex]\begin{aligned}{\text{Volume of water sample}} &= \left( {50.00{\text{ mL}}} \right)\left( {\frac{{{{10}^{ - 3}}{\text{ L}}}}{{1{\text{ mL}}}}} \right) \\&= 0.05{\text{ L}} \\\end{aligned}[/tex]  

Substitute 75.0 mg/L for hardness and 0.05 L for volume in equation (2) to calculate mass of [tex]{\text{CaC}}{{\text{O}}_3}[/tex].

[tex]\begin{aligned}{\text{Mass of CaC}}{{\text{O}}_{\text{3}}} &= \left( {75.0{\text{ mg/L}}} \right)\left( {0.05{\text{ L}}} \right) \\&= 3.75{\text{ mg}} \\\end{aligned}[/tex]  

Mass of [tex]{\text{CaC}}{{\text{O}}_3}[/tex] is to be converted from mg to g. The conversion factor for this is,

[tex]1{\text{ mg}} = {10^{ - 3}}{\text{ g}}[/tex]  

Therefore mass of [tex]{\text{CaC}}{{\text{O}}_3}[/tex] can be calculated as follows:

 [tex]\begin{aligned}{\text{Mass of CaC}}{{\text{O}}_{\text{3}}} &= \left( {3.75{\text{ mg}}} \right)\left( {\frac{{{{10}^{ - 3}}{\text{ g}}}}{{1{\text{ mg}}}}} \right) \\&= 0.00375{\text{ g}} \\\end{aligned}[/tex]

The formula to calculate moles of [tex]{\text{CaC}}{{\text{O}}_3}[/tex] is as follows:

[tex]{\text{Moles of CaC}}{{\text{O}}_{\text{3}}} = \dfrac{{{\text{Mass of CaC}}{{\text{O}}_{\text{3}}}}}{{{\text{Molar mass of CaC}}{{\text{O}}_{\text{3}}}}}[/tex]                                                    …… (3)

Substitute 0.00375 g for mass of [tex]{\text{CaC}}{{\text{O}}_{\text{3}}}[/tex] and 100.08 g/mol for molar mass of    [tex]{\text{CaC}}{{\text{O}}_{\text{3}}}[/tex] in equation (3).

[tex]\begin{aligned}{\text{Moles of CaC}}{{\text{O}}_{\text{3}}} &= \frac{{{\text{0}}{\text{.00375 g}}}}{{{\text{100}}{\text{.08 g/mol}}}} \\&= 0.00003747{\text{ mol}} \\\end{aligned}[/tex]  

Therefore number of calcium ions present in the given water sample is 0.00003747 mol.

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Calculate the moles of chlorine in 8 moles of carbon tetrachloride: https://brainly.com/question/3064603 Calculate the moles of ions in the solution: https://brainly.com/question/5950133

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole concept

Keywords: CaCO3, mass, volume, hardness, molar mass, moles, mass of CaCO3, 3.75 mg, 0.00375 g, 75.0 ppm, 50.00 mL, 0.00003747 mol

Which of the solutions have greatest osmotic pressure 30% sucrose 60% sucrose or 30% magnesium sulfate?

Answers

Osmotic pressure is the minimum amount of pressure a solution must exert in order to prevent from crossing a barrier by osmosis. Solute molecules have difficulty crossing semipermeable membranes, so the more solutes that are in a solution, the higher the osmotic pressure will be. Between 30% sucrose and 60% sucrose, 60% sucrose will have a greater osmotic pressure than 30% because it has a higher percentage of solutes. However, since sucrose has a higher potential to cross semipermeable membranes and is more absorbable than magnesium sulfate, magnesium sulfate would have a higher osmotic pressure than 60% sucrose even though 60% sucrose has higher molecules.

Final answer:

The solution with the greatest osmotic pressure depends on the total concentration of solute particles. While a 60% sucrose solution has a high concentration, the dissociation of magnesium sulfate in a 30% solution increases its total solute particle concentration, potentially giving it a higher osmotic pressure when considering its van 't Hoff factor.

Explanation:

The question asks which of the solutions has the greatest osmotic pressure: 30% sucrose, 60% sucrose, or 30% magnesium sulfate. Osmotic pressure is directly proportional to the concentration of solute particles in a solution. While a higher percentage indicates a more concentrated solution, the key factor in determining osmotic pressure is the number of solute particles in solution, not just the concentration of the solution itself.

Sucrose is a non-electrolyte and does not dissociate in water, meaning a 30% or 60% sucrose solution will provide a straightforward concentration of molecules. Magnesium sulfate, on the other hand, is an electrolyte and will dissociate into magnesium and sulfate ions, effectively increasing the number of solute particles in the solution.

Therefore, even though the sucrose solution at 60% is more concentrated than the 30% magnesium sulfate solution, the dissociation of magnesium sulfate into ions means that the 30% magnesium sulfate solution may actually have a greater total concentration of solute particles, leading to a higher osmotic pressure. However, to accurately determine which solution has the highest osmotic pressure, one must consider the molar concentration of particles (ions for magnesium sulfate and molecules for sucrose) and the van 't Hoff factor (i), which accounts for the dissociation of ions in solution.

Na→Na++− Express your answer as a particle or a chemical formula.

Answers

Final answer:

The process of Na→Na++ represents a sodium atom (Na) losing an electron to become a positively charged sodium cation (Na+). This can be a part of a reaction such as 2NaCl(aq) + 2H2O(l) -> 2NaOH(aq) + H2(g) + Cl2(g). The net ionic equation for this reaction is 2H2O(l) -> H2(g) + Cl2(g).

Explanation:

The chemical formula Na→Na++ indicates a sodium atom losing an electron to become a sodium cation with a positive charge. This is a part of a redox reaction that might occur in a chemical formula such as when sodium chloride (NaCl) reacts with water (H2O) to produce sodium hydroxide (NaOH), hydrogen gas (H2), and chlorine gas (Cl2).

The balanced molecular equation would be: 2NaCl(aq) + 2H2O(l) -> 2NaOH(aq) + H2(g) + Cl2(g)

The complete ionic equation would be: 2Na+(aq) + 2Cl−(aq) + 2H2O(l) -> 2Na+(aq) + 2OH−(aq) + H2(g) + Cl2(g)

The net ionic equation, which only focuses on the species that actually change and react, would thus be: 2H2O(l) -> H2(g) + Cl2(g)

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Cellulose, chitin, and peptidoglycan function as structural molecules and withstand pulling and pushing forces well. which structural feature is most directly responsible? see section 5.3 ( page 114) .

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formation of carbs monosaccarides polymerize to form polymers called polysaccharides, joined by glycosidic linkages carbs perform a wide variety of functions ex: structure, basis for other molecules, cell identity, storing chemical energy How do monosaccharide monomers vary? location of carbonyl group (aldose is at end, ketose in middle) number or carbons present (tri,pent, hex), spatial arrangement, linear vs ringed Polysaccharides also known as complex carbs, polymers of monosaccharide monomers simplest polysaccharide is disaccharide (2 monosaccharide monomers) glycosidic linkage a covalent bond that results after a condensation reaction between two hydroxyl groups (OH) location and geometry of these bonds vary widely Starch : plant storage polysaccharide glycogen : animal storage cellulose : plant cell walls chitin : fungi cell walls, animal exoskeletons, some algae peptidoglycan : bacterial cell walls

Provide a general comparison of the empty space in a solid with that in a liquid as well as

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Assuming that the space within the solid or liquid is vacuum, it is not matter because there is no mass inside. However, there is a volume. The volume inside a solid would have regular straight sides because atoms of a solid is compactly arranged. For liquids, the space could be irregular curves and paths because the atoms in a liquid are free-flowing.

Answer : There is large empty space between the molecule in a gaseous state as compared to the solid and liquid state.

Explanation :

Solid state : In this state, the molecules are arranged in regular and repeating pattern. The molecules are closely packed that means they are fixed and vibrate in place but they can not move from one place to another.  In the solid, there is no empty space present between the molecules.

Liquid state : In this state, the molecules are present in random and irregular pattern. The molecules are closely packed but they can move from one place to another.  In the liquid, there is a some empty space present between the molecules.

Gaseous state : In this state, the molecules are present in irregular pattern. The molecules are not closely packed and they can move freely from one place to another and spread out. In the gaseous, there is large empty space present between the molecules.

On an activity series chlorine is more active than bromine. what is a balanced chemical equation for the reaction between chlorine gas and aqueous sodium bromide?

Answers

Since chlorine is more active than bromine, it will displace the bromine and combine with the sodium in a single-replacement reaction:

Cl2(g) + 2NaBr(aq) ↔ Br2(g) + 2NaCl(aq)
This is the balanced chemical equation

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