How many ml of 2.50 M NaOH solution are required to make a 525 mL of 0.150 M?

Answer:

All helium atoms have two protons, and no other elements have atoms with two protons. In the case of helium, the atomic number is 2. The atomic number of an element is usually written in front of and slightly below the element's symbol, like in the Figure below for helium.

Answer:

The goal is to remove both heavy solids and floating oils

Explanation:

Primary treatment consists of temporarily holding the sewage in a quiescent basin where heavy solids can settle to the bottom while oil, grease and lighter solids float to the surface. The settled and floating materials are removed and the remaining liquid may be discharged.

Answer : The correct option is, (C) C to Fe

Explanation :

The given chemical reaction is:

[tex]2Fe_2O_3+3C\rightarrow 4Fe+3CO_2[/tex]

By the stiochiometry we can say that, 2 moles of [tex]Fe_2O_3[/tex] react with 3 moles of C to gives 4 moles of Fe and 3 moles of [tex]CO_2[/tex].

From the balanced chemical reaction we conclude that,

As, 3 moles of C produces 4 moles of Fe

So, 1 mole of C produces [tex]\frac{4}{3}[/tex] moles of Fe

That means, the moles of ratio of C to Fe is 4 : 3

Therefore, the correct option is (C) C to Fe

Covalent network solids often have the highest melting points. These solids are characterized by a network of covalent bonds that extend throughout the material, creating a very stable and strong structure.

Materials with high melting points typically have strong intermolecular forces. In the case of covalent network solids, such as diamond (pure carbon) or silicon carbide, each atom is bonded to several others in a lattice structure, creating an incredibly strong bond throughout the entire structure. This extensive network of strong bonds requires a large amount of energy to break apart, thus resulting in very high melting points. Molecular solids, where molecules are held together by weaker forces such as van der Waals forces, generally have much lower melting points because these intermolecular forces are much easier to overcome. Ionic solids also have high melting points, but not typically as high as covalent network solids, due to the nature of ionic bonds which are strong, but localized between individual pairs of ions rather than throughout the entire structure.

Answer:

Explanation:

Chlorite anion, ClO₂⁻ has one atom of chlorine and two atoms of oxygen.

Chlorine atom has 7 valence electrons (group 17 of the periodic table) and oxygen has 6 valence electrons (group 16 of the periodic table).

Thus, in total the anion has 7 + 6×2 electrons, plus an additional electron indicated by the negative charge of the anion: 7 + 12 + 1 = 20 valence electrons, that must be distributed among the three atoms.

Being chlorine the most electronegative atom, you place it in the center. surrounded by the two oxygen atoms.

Thus, so far:

             O Cl  O (pending to place the valence electrons.

You can put two electrons between each chlorine and oxygen atoms to form the bonds:

     O : Cl : O

Also, complete the octets:

 . .      . .    . .

: O  :  Cl :  O :

 . .     . .     . .

That structure works because:

But you need to calculate the formal charges on each atom:

For chlorine:

For each oxygen:

The total charge of the anion is +1 -1 - 1 = -1.

And the complete structure with the charge is:

   . .      . .    . .

[ : O  :  Cl :  O : ] ⁻

   . .      . .     . .

The square bracketts comprise the entire anion and the negative charge is for the entire structure.

In this structure, the central atom (Cl) is surrounded by two bonding and two unshared pairs of electrons. (this is the answer to the question).

There is another structure which minimizes the formal charge, which will be preferred. It is by making a double bond between chlorine and one of the oxygen atoms, by moving two of the atoms beside one chlorine.

That structure is:

 . .      . .    . .

: O  :  Cl ::  O

 . .     . .     . .

There you have 20 valence electrons and complete octets too, but the formal charges are:

Chlorine:

The oxygen on the left is equal to the previous structure, thus - 1 forma charge.

The oxygen on the right:

Hence, this las structure minimizes the formal charges and is preferred.

This is:

 . .      . .    . .

: O  :  Cl ::  O

 . .     . .     . .  

But you must add the negative charge which belongs to the complete anion:

      . .      . .     . .

[     : O  :  Cl ::  O  ] ⁻

      . .     . .      . .

The square brackets comprise the entire anion and the negative charge is for it.

Hence, in this other structue the central atom, chlorine, is surrounded by six bonding electrons and four nonbonding electrons.

Answer:

The air pressure is significantly less than 1 atm, so the boiling point of water is much lower than at sea level.

Explanation:

This has to do with Gay Lussac's Law (a.k.a pressure law) which in essence means that when pressure goes up, temperature goes up and when pressure decreases, temperature decreases. This is why when the air pressure is signifcantly less than 1 atm (the pressure at sea level), the boiling point of water is much lower than at sea level.

The best explanation for the scenerio is :  High in the mountains , the air pressure is significantly less than 1 atm, so the boiling point if water is much lower than at sea level.

The higher you go above sea level the lower the air pressure and this will significantly affect the temperature at which certain liquids ( water ) will boil. therefore the boiling point of water will be  much lower than at sea level.

In this scenerio the application of Gay Lussac's law comes in

Gay Lussac's law states that the pressure of gas is directly proportional to its temperature at constant volume

Hence we can conclude that The best explanation for the scenerio is :  High in the mountains , the air pressure is significantly less than 1 atm, so the boiling point if water is much lower than at sea level.

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Answer:

0.178 moles of oxygen gas molecules were collected.

Explanation:

Pressure at which oxygen gas collected = p= 1.00 atm

Vapor pressure of the water [tex]p'=34.5 Torr=\frac{34.5}{760} atm=0.0454 atm[/tex]

Pressure of the oxygen gas = P

p = p' + P

[tex]1.00 atm =0.0454 atm+P[/tex]

P = 1.00 atm -  0.0454 atm = 0.9546 atm

Volume of the oxygen gas = V = 4.56 L

Moles of oxygen gas = n

Temperature at which gas collected = T = [tex]25^oC=273+25=298 K[/tex]

[tex]PV=nRT[/tex] (ideal gas)

[tex]n=\frac{PV}{RT}=\frac{0.9546 atm\times 4.56 L}{0.0821 atm L/mol K\times 298 K}=0.178 mol[/tex]

0.178 moles of oxygen gas molecules were collected.

Answer: The moles of nickel (II) chloride were present in the solution are 0.925

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n}{V_s}[/tex]

where,

Molarity = 0.925

n= moles of solute  = 0.2

[tex]V_s[/tex] = volume of solution in L = 1.0 L

Now put all the given values in the formula of molarity, we get

[tex]0.925=\frac{moles}{1.0L}[/tex]

[tex]moles=0.925\times 1.0=0.925[/tex]

Therefore, the moles of nickel (II) chloride were present in the solution are 0.925

Explanation:

A non-renewable energy source (also called a finite source) is a natural resource that cannot be readily replaced by natural means at a quick pace enough to keep up with consumption.

An example is a carbon-based fossil fuel.

Answer:

C. An energy source that cannot be reused or replaced

Explanation:

non-renewable = cannot be renewed

Answer: nuclear

Explanation:

Nuclear energy resource causes the most safety concerns. Therefore, option C is correct.

Nuclear energy is the energy contained within an atom's nucleus, or core. Nuclear energy can be used to generate electricity, but it must be liberated from the atom first.

Nuclear power is a zero-emission source of clean energy. Fission, the process of splitting uranium atoms to produce energy, is used to generate power. The heat produced by fission is used to generate steam, which spins a turbine to generate electricity without emitting the harmful byproducts that fossil fuels do.

Coal, oil, and gas are by far the most significant contributors to global climate change, accounting for more than 75% of global greenhouse gas emissions and nearly 90% of total carbon dioxide emissions.

Thus, option C is correct.

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Answer:

hydrogen

Explanation:

Answer:

M = 16.8 M

Explanation:

Data: HNO3

moles = 12.6 moles

solution volume = 0.75 L

Molarity is represented by the letter M and is defined as the amount of solute expressed in moles per liter of solution.

[tex]M=\frac{moles}{solution volume}[/tex]

The data is replaced in the given equation:

[tex]M=\frac{12.6 mol}{0.75L}=16.8\frac{mol}{L}[/tex]

Answer:

The correct answer is 16.8 M

Explanation:

The molarity (M) of a solution is the number of moles of solute in 1 liter of solution. The HNO₃ solution contains 12.6 moles of solute (in this case the solute is HNO₃) in 0.75 liters. In order to find the molarity, we have to divide the number of moles into the volume in liters as follows:

M = 12.6 moles/0.75 L = 16.8 moles/L = 16.8 M

Answer:

a) 13.2 moles [tex]2H_{2}O[/tex]

b) 79.33 grams of [tex]2H_{2}O[/tex]

Explanation:

First, we'll need to balance the equation

[tex]H_{2(g)} + O_{2(g)}[/tex] → [tex]H_{2}O_{(g)}[/tex]

There are 2 (O) on the left and only one on the right, so we'll add a 2 coefficient to the right.

[tex]H_{2(g)} + O_{2(g)}[/tex] → [tex]2H_{2}O_{(g)}[/tex]

Now there are 4 (H) on the right and only 2 on the left, so we'll add a 2 coefficient to the ([tex]H_{2}[/tex]) on the left.

[tex]2H_{2(g)} + O_{2(g)}[/tex] → [tex]2H_{2}O_{(g)}[/tex]

The equation is now balanced.

a) This can be solved with a simple mole ratio.

4.6 moles [tex]O_{2}[/tex] × [tex]\frac{2 moles H_{2}O}{1 mole O_{2}}[/tex] = 13.2 moles [tex]2H_{2}O[/tex]

b) This problem is solved the same way!

2.2 moles [tex]H_{2}[/tex] × [tex]\frac{2 moles H_{2}O}{2 moles H_{2}}[/tex] = 2.2 moles [tex]2H_{2}O[/tex]

However, this problem wants the mass of [tex]2H_{2}O[/tex], not the moles.

The molecular weight of [tex]2H_{2}O[/tex] is the weight of 4 (H) molecules and 2 (O) molecules (found on the periodic table). So,

4(1.008) + 2(15.999) = 36.03 g/mol

2.2 moles [tex]2H_{2}O[/tex] × [tex]\frac{36.03 g}{1 mol}[/tex] = 79.33 grams of [tex]2H_{2}O[/tex]

Answer:

Eukaryote vote me brainleist

Explanation:

Answer:

If the volume of the container is decreased by a factor of 2 the pressure is is increased by the same factor to 1664 torr.

Explanation:

Here we have Boyle's law which states that, at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure

V ∝ 1/P or V₁·P₁ = V₂·P₂

Where:

V₁ = Initial volume

V₂ = Final volume = V₁/2

P₁ = Initial pressure = 832 torr

P₂ = Final pressure  = Required

From V₁·P₁ = V₂·P₂ we have,

P₂ = V₁·P₁/V₂ = V₁·P₁/(V₁/2)

P₂  = 2·V₁·P₁/V₁ = 2·P₁ = 2× 832 torr = 1664 torr

Answer:

The pressure will increase by a factor of 2 and is now 1664 torr

Explanation:

The question says for us to assume that temperature is constant. Now, since we are given pressure and volumw, we will use Boyle's law which is a law stating that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature i.e V ∝ 1/P

Thus, PV = K

Where K is a constant.

So,

P₁•V₁ = P₂•V₂ = k

Where:

P₁ = Initial pressure

V₁ = Initial volume

P₂ = Final pressure

V₂ = Final volume = V₁/2

From the question, P₁ = 832 torr ; we are told that volume is decreased by 2,thus, V₂ = V₁/2

Now, we want to find out what will happen to the pressure P₂.

Let's make P₂ the subject;

P₁•V₁ = P₂•V₂

Thus, P₂ = (P₁•V₁)/V₂

Plugging in the relevant values to obtain ;

P₂  = (P₁•2V₁)/V₁

V₁ will cancel out and we have;

P₂  = 2P₁

Now, we are given that P₁ = 832 torr, Thus,

P₂ = 2P₁ = 2× 832 torr = 1664 torr

The rate of effusion of gas B is 728.32 m/s

Explanation:

Given:

Mass of A, m₁ = 46 g/mol

Rate of effusion of A, R₁ = 515 m/s

Mass of B, m₂ = 92 g/mol

Rate of effusion of B, R₂ = ?

We know:

[tex]\frac{R_1}{R_2} = \sqrt{\frac{M_2}{M_1} }[/tex]

Substituting the value we get:

[tex]\frac{515}{R_2} = \sqrt{\frac{92}{46} } \\\\\frac{515}{R_2} = \sqrt{2} \\\\R_2 = \frac{515}{\sqrt{2} } \\\\R_2 = 728.32 m/s[/tex]

Therefore, the rate of effusion of gas B is 728.32 m/s

Answer:

I think b if not then c hopefully this helps

To calculate the pH of a 0.107 M NaHA solution, where HA is part of a diprotic acid with given Ka values, HA^-− dissociates in water according to its first ionization step. The pH is determined using the Ka1 value and is calculated to be approximately 1.80.

To calculate the pH for a 0.107 M solution of NaHA, where HA is a diprotic acid (H2A), given Ka1 = 2.3× 10–4 and Ka2 = 3.0× 10–12, we first need to consider what happens when NaHA dissolves in water.

NaHA will dissociate to form NA+ and HA−. Since the concentration of NaHA is relatively high and Ka1 is significantly greater than Ka2, we can assume that the HA− will primarily dissociate according to the first ionization step, while the second ionization can be neglected in this approximation.

The ionization can be represented as:
HA−(aq) + H2O(l) → A2−(aq) + H3O+(aq).

Writing the expression for Ka1 we have:
Ka1 = [H3O+][A2−]/[HA−].
Assuming that [H3O+] = [A2−], we can simplify this to:
Ka1 = [H3O+]^2/[HA−].

Rearranging and solving for [H3O+], we get:
[H3O+] = √(Ka1 × [HA−]). Substituting the given values in:
[H3O+] = √(2.3× 10–4 × 0.107) = √(2.461× 10–4) ≈ 1.57× 10–2.

Using the formula for pH, pH = -log[H3O+], we find:
pH = -log(1.57× 10–2) ≈ 1.80.

Thus, the pH of the 0.107 M NaHA solution is approximately 1.80.

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The pH of a 0.107 M solution of NaHA, derived from the diprotic acid H₂A, is calculated to be approximately 6.24.

To calculate the pH of a 0.107 M solution of NaHA, a salt derived from the diprotic acid H₂A, we will consider that NaHA will primarily exist as HA⁻ in the solution. This involves both the first and second ionization constants of the diprotic acid.

Given:

Step-by-step calculation:

Ka₂ = [H⁺][A²⁻] / [HA⁻]

Assume the initial concentration of HA⁻ is approximately equal to the initial concentration of NaHA (0.107 M) as the dissociation is minimal. Let the change in concentration be 'x.'

Hence:

Ka₂ = 3.0 × 10⁻¹² = (x)(x) / (0.107 - x) ≈ x² / 0.107

Solving for 'x':

x = [H⁺] = √(Ka₂ × 0.107) = √(3.0 × 10⁻¹² × 0.107) ≈ 5.7 × 10⁻⁷ M

pH = -log[H⁺] = -log(5.7 × 10⁻⁷) ≈ 6.24

Therefore, the pH of a 0.107 M solution of NaHA is approximately 6.24

Answer : The final pressure of the gas is, [tex]2.47\times 10^3mmHg[/tex]

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

[tex]P\propto \frac{1}{V}[/tex]

or,

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1[/tex] = initial pressure = 545 mmHg

[tex]P_2[/tex] = final pressure = ?

[tex]V_1[/tex] = initial volume = 775 mL

[tex]V_2[/tex] = second volume = 171 mL

Now put all the given values in the above equation, we get:

[tex]545mmHg\times 775mL=P_2\times 171mL[/tex]

[tex]P_2=2470.03mmHg=2.47\times 10^3mmHg[/tex]

Therefore, the final pressure of the gas is, [tex]2.47\times 10^3mmHg[/tex]

Answer:

1,3,6

Explanation:

Answer:

1,3,6

Explanation:

Answer:

178.98 sq. feet

Explanation:

The path and the garden has been shown in the figure below. The green area is the garden and the area in brown is the path.

It has been given that,

Radius of garden = 8 feet

So, the area of garden = 3.14 × 8 × 8 = 200.96 sq. feet

The total radius of the land including garden and path = 8 + 3 = 11 feet

So, the total are of land including garden and path = 3.14 × 11 × 11 = 379.94 sq. feet

So, the area of path = Total area of the land - area of garden

Area of path = 379.94 - 200.96 = 178.98 sq. feet

Answer:

c 178.98 ft

Explanation:

Answer:

2037 L

Explanation:

Step 1:

The balanced equation for the reaction involving the burning of propane. This is given below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Step 2:

Determination of the number of mole in 1kg of propane (C3H8).

Mass of C3H8 = 1kg = 1000g

Molar Mass of C3H8 = (3x12) + (8x1) = 36 + 8 = 44g/mol

Number of mole = Mass/Molar Mass

Number of mole of C3H8 = 1000/44

Number of mole of C3H8 = 22.73 moles

Step 3:

Determination of the number of mole of water produced by burning 1 kg of propane (C3H8). This is illustrated below:

From the balanced equation above,

1 mole of C3H8 boiled 4 moles of H2O.

Therefore, 22.73 moles of C3H8 will produce = 22.73 x 4 = 90.92 moles of H2O.

Step 4:

Determination of the volume of H2O. This is illustrated below:

1 mole of a gas occupy 22.4L.

Therefore, 90.92 moles of H2O will occupy = 90.92 x 22.4 = 2037 L.

Therefore, 2037 L of water is boiled by burning 1kg of propane (C3H8)

Answer:

0.2 mol

Explanation:

Use the given values to find the molar mass.  The molar mass is 40 g/mol.

23 + 16 + 1 = 40

Using the molar mass, convert grams to moles.

(8 g)/(40 g/mol) = 0.2 mol

You have 0.2 mol of sodium hydroxide.

Answer:

After 2 half-lives there will be 25% of the original isotope, and 75% of the decay product. After 3 half-lives there will be 12.5% of the original isotope, and 87.5% of the decay product. After 4 half-lives there will be 6.25% of the original isotope, and 93.75% of the decay product.

Explanation:

Answer:

1,000 -  2,000

Explanation:

Just look at the bar graph. The bar ends at about 1,500 which is between 1,000 - 2,000. That is the only valid answer for this problem.

The frequency of individuals with doctorates who work in the field of physical science is 0-1,000.

Physical science is a branch of natural science that studies non-living systems and the fundamental principles governing the physical world. It encompasses physics and chemistry, exploring the properties and behavior of matter and energy. Physics delves into the nature of space, time, motion, and force, addressing phenomena from the smallest particles to the vastness of the cosmos.

Chemistry, on the other hand, focuses on the composition, structure, properties, and changes of matter. Together, these disciplines provide a comprehensive understanding of the physical universe, forming the basis for technological advancements and contributing to our comprehension of the fundamental laws that govern the natural world.

Answer: 1.1g of copper

Explanation: We begin by writing the balanced reaction equation.

So we have : Cu(s) + 2AgNO3 (aq) ------> Cu(NO3)2 (aq) + 2Ag (s)

Molar mass of AgNO3 = 107.87 + 14.01 + 3(16.0) = 169.88g/mol, for 2 moles we then have 2 x 169.88 =339.76g.

Atomic mass of Copper = 64g approximately

From the equation the following deductions can be made:

339.76g of AgNO3 reacts with 64g of copper

5.65g of AgNO3 would react with 64/ 339.76 x 5.65 =1.062 approx 1.1g of copper.

Answer:

we need 1.06g of Cu to react with 5.65g of AgNO₃

Explanation:

C u +2 AgNO₃ = Cu(NO₃ )₂ + 2 Ag

the mole ratio between Copper and silver nitrate is 1:2  meaning we need  2 moles of silver nitrate for every mole of copper that takes part in the reaction.

the molar mass of Cu  is 63.55

the molar mass of AgNO₃ is 107.8682+ 14 + (16x3) = 107.8682+ 14 + 48=  169.87682≈169.88g

for every 63.55 g of Cu reaction with  2(169.88g of AgNO₃)= 339.736g of AgNO₃

if x grams of Cu react with 5.65 grams of AgNO₃

63.55g= 339.736g

x = 5.65g

cross multiply

339.736x = 5.65 x 63.55 = 359.0575

x = 359.0575/339.736 = 1.05687210069≈1.06

we need 1.06g of Cu to react with 5.65g of AgNO₃

Answer: 4M

Explanation:

Answer:

2.4 litters of water are required.

Explanation:

Given data:

Mass of LiF = 19.6 g

Molarity of solution = 0.320 M

Volume of water used = ?

Solution:

Number of moles = mass/molar mass

Number of moles = 19.6 g/ 26 g/mol

Number of moles = 0.75 mol

Volume required:

Molarity = number of moles/ volume in L

Now we will put the values in above given formula.

0.320 M = 0.75 mol /  volume in L

Volume in L = 0.75 mol  /0.320 M

     M = mol/L

Volume in L = 2.4 L

2.36 liters of water is needed to dissolve 19.6 grams of LiF to create a 0.320 M solution.

To determine the volume of water needed to create a 0.320 M solution of LiF, we can use the formula:

[tex]\[ C = \frac{n}{V} \][/tex]

where [tex]C[/tex] is the concentration in moles per liter, [tex]n[/tex] is the number of moles of the solute, and [tex]V[/tex] is the volume of the solution in liters. We can rearrange this formula to solve for [tex]\( V \):[/tex]

[tex]\[ V = \frac{n}{C} \][/tex]

First, we need to calculate the number of moles of LiF:

[tex]\[ n = \frac{\text{mass of LiF}}{\text{molar mass of LiF}} \][/tex]

The molar mass of LiF is approximately 25.94 g/mol (6.94 g/mol for Li and 19 g/mol for F). Now we can calculate the number of moles of LiF:

[tex]\[ n = \frac{19.6 \text{ g}}{25.94 \text{ g/mol}} \][/tex]

[tex]\[ n \approx 0.755 \text{ mol} \][/tex]

Now that we have the number of moles, we can use the concentration to find the volume:

[tex]\[ V = \frac{0.755 \text{ mol}}{0.320 \text{ M}} \][/tex]

[tex]\[ V \approx 2.36 \text{ L} \][/tex]

Answer:

Option D. 1.40x10^5g

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 particles. This equally means that 1mole of Cl2 contains 6.02x10^23 particles.

1 mole of Cl2 =2 x 35.5 = 71g.

Now, If 71g of Cl2 contains 6.02x10^23 particles,

Then Xg of Cl2 will contain 1.19x10^27 particles i.e

Xg of Cl2 = (71x1.19x10^27)/(6.02x10^23)

Xg of Cl2 = 1.40x10^5g

Therefore, 1.40x10^5g of Cl2 contain 1.19x10^27 particles