how many moles of 18L of NH3 at 30 celcius and 912 mmHg? how many grams?

Let's assume that both He and N₂ have ideal gas behavior.

Then we can use ideal gas law,
     PV = nRT
Where, P is the pressure of gas, V is the volume, n is moles of gas, R is universal gas constant and T is the temperature in Kelvin.

The P and V are same for the both gases.
R is a constant.

The only variables are n and T.

Let's say temperature of He is T₁ and temperature of N₂ is T₂.

n = m/M where n is moles, m is mass and M is molar mass.

Molar mass of He is 4 g/mol and molar mass of N₂ is 28 g/mol

Since mass (m) of both gases are same,
 moles of He = m/4
 moles of N₂ = m/28

Let's apply the ideal gas equation for both gases.
For He gas,
 PV = (m/4)RT₁              (1)

For N₂ gas,
 PV = (m/28)RT₂            (2)

(1) = (2)
(m/4)RT₁ = (m/28)RT₂ 
        T₁/4 = T₂/28
        T₁    = T₂/7
        7T₁  = T₂

Hence, the temperature of N₂ gas is higher by 7 times than the temperature of He gas.

Given the same mass and pressure, the temperature of the helium would be the same as the temperature of nitrogen. This is due to the ideal gas law, which connects the variables of pressure, volume, temperature, and the number of moles of a gas.

The temperature of the helium would be the same as the temperature of nitrogen, given that the quantities (in terms of mass) are the same and they are at the same pressure. This follows from the ideal gas law which states that pressure is directly proportional to temperature and the number of moles of the gas, and inversely proportional to volume. Considering this in context, helium and nitrogen have different molar masses. For a given mass, there will be more moles of helium (which has a lower molar mass) than of nitrogen (which has a higher molar mass). Therefore, if the mass, volume, and pressure are held constant, the temperature for equal masses of the two gases will also be constant. More moles of gas does not mean a higher temperature, contrary to what one might intuitively think.

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Answer : The number of moles of carbon sulfide produced are, 1.18 moles.

Explanation : Given,

Moles of carbon = 5.9 moles

The balanced chemical reaction is:

[tex]5C+2SO_2\rightarrow CS_2+4CO[/tex]

From the balanced chemical reaction we conclude that,

As, 5 moles of carbon react to give 1 mole of carbon sulfide

So, 5.9 moles of carbon react to give [tex]\frac{5.9}{5}=1.18[/tex] mole of carbon sulfide

Thus, the number of moles of carbon sulfide produced are, 1.18 moles.

The net ionic equation for the reaction between aqueous sulfuric acid and aqueous sodium hydroxide is h+ (aq) + oh- (aq) → h2o (l). Here, the sodium ions are spectator ions and are thus not included in the net ionic equation.

The question asks about the net ionic equation for the reaction between aqueous sulfuric acid and aqueous sodium hydroxide. Remember, a net ionic equation includes only those components that undergo a change. Spectator ions are not included. In this case, the correct answer is (d) h+ (aq) + oh- (aq) → h2o (l). This equation represents the essential acid-base reaction that occurs. The sodium ion is a spectator ion in this reaction. Hence, it is not included in the net ionic equation.

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Answer:

c. Some unstable materials decay radioactively into other unstable materials.

Explanation:

got it correct on edg

Monomers are generally small molecules that make up a long polymeric chain. The monomer for lipids is triglycerides.

A triglyceride is an ester consisting of three fatty acids and glycerol. Triglycerides are the main components of human body fat.

Lipids are made up of long chains of triglycerides.

Thus, the correct option is B.

For more details regarding triglycerides, visit:

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Approximately 200.6 grams of Aluminum will be produced from the electrolysis of molten AlCl3 for 3.25 hours with an electrical current of 15.0 A, as determined through application of Faraday's law of electrolysis.

In order to determine the number of grams of aluminum produced from electrolysis of molten AlCl3, we need to use Faraday's law of electrolysis.

Faraday's law states that the amount of substance produced at an electrode during electrolysis is directly proportional to the number of moles of electrons (or amount of electrical charge) transferred at that electrode. The charge Q in coulombs (C) can be calculated using the formula Q = It, where I is the current in amperes (A) and t is the time in seconds.

For this scenario, we know that the current I is 15.0 A and the time t is 3.25 hours, which needs to be converted to seconds for the equation to work properly (3.25 hr × 3600 s/hr = 11700 s). Hence, Q = 15.0 A × 11700 s = 175500 C.

The quantity of a substance produced in an electrolytic cell is given by the equation  m = Q × M / F × n, where M is the molar mass of the substance, F is Faraday's constant (~96485 C/mol), and n is the number of electrons transferred per formula unit of the substance. In this case, M = 26.98 g/mol for Al, n = 3 for Al3+, so m = 175500 C × 26.98 g/mol / (96485 C/mol × 3) = 200.6 g

Therefore, approximately 200.6 g of Aluminum will be produced from the electrolysis of AlCl3 in 3.25 hours with an electrical current of 15.0 A.

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Answer:

1.67m

Explanation:

Factors affecting the rate of a chemical reaction in the context of a specific reaction equation.

The factors that affect the rate of the reaction Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g) include:

Catalyst: Adding a catalyst can increase the rate of the reaction.

Surface area: Grinding the zinc solid into a fine powder increases its surface area, enhancing the reaction rate.

Concentration and Temperature: Increasing the concentration of HCl or raising the temperature can also speed up the reaction.

You need 1000 milliliters of a 1.0 M AgNO3 solution to provide 169.9 g of pure AgNO₃.

Step 1: Calculate the moles of AgNO₃ needed. To do this, use the given molar mass of AgNO₃, which is 169.87 g/mol.

Moles = mass / molar mass

Moles of AgNO₃ = 169.9 g / 169.87 g/mol = 1.000 mol

Step 2: Determine the volume of the 1.0 M AgNO₃ solution required to obtain 1.000 mol of AgNO₃.

Molarity (M) = moles of solute / liters of solution

Rearranging the formula to solve for volume (liters):

Volume (L) = moles of solute / Molarity

Volume (L) = 1.000 mol / 1.0 M = 1.000 liters

Since the question asks for the volume in milliliters:

Volume (mL) = Volume (L) * 1000

Volume (mL) = 1.000 L * 1000 = 1000 mL

Therefore, you need 1000 milliliters of a 1.0 M AgNO₃ solution to provide 169.9 g of pure AgNO₃.

Answer: D: By decreasing the activation energy

Explanation: A catalyst is a substance which increases the rate of a reaction by taking the reaction through a different path which involves lower activation energy and thus more molecules can cross the energy barrier and convert to products.

Activation energy is the extra energy that must be supplied to reactants in order to cross the energy barrier and thus convert to products.

The catalyst itself does not take part in the chemical reaction and is regenerated as such at the end.

Answer: Latent Heat of Vaporization

Using Gay-Lussac's Law, we calculate that when the temperature of a gas increases from 320 K to 450 K, the pressure of the gas will increase from 1.5 atm to 2.1 atm, assuming the volume and the amount of gas remain constant.

To answer the question, we need to use the concept in physics called Gay-Lussac's Law. This law states that the pressure of a given amount of gas held at a constant volume is directly proportional to the Kelvin temperature. It's also important to remember that when we're dealing with gases, temperatures have to be in Kelvin for our calculations to work.

Given that, we know that the initial pressure (P1) is 1.5 atm, the initial temperature (T1) is 320K, and the final temperature (T2) is 450K. We want to find the final pressure (P2). According to Gay-Lussac's law, this can be calculated using the following equation: P1/T1 = P2/T2.

Thus, P2 = P1 * T2 / T1 = 1.5 atm * 450K / 320K = 2.1 atm.

So, the gas pressure will be 2.1 atm when the temperature increases from 320 K to 450 K, assuming that the volume and the amount of gas remain constant.

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ANSWER: C temperature of the gas

Answer:

(C) The temperature of gas

Explanation:

It's correct for Plato

Answer:

the options are

2, 3, 1

1, 3, 2

4, 3, 2

3, 2, 3

when balancing equation the masses should be balanced. In other words the same number of atoms of the same element should be on either side of the equation

the balanced equation for the oxidation of aluminium is as follows

4Al + 3O₂ ---> 2Al₂O₃

coefficients are the numbers in front of the respective compounds.

the coefficients in the correct sequence are 4,3 and 2

answer is 4, 3, 2

Final answer:

A dilute solution has a relatively small amount of solute compared to the solvent. Qualitative terms like 'dilute' and 'concentrated' describe the concentration of solutes in a solution, but for precise measurements, a quantitative expression of concentration is necessary.

Explanation:

A solution with a relatively low amount of solute is referred to as a dilute solution. This term contrasts with a concentrated solution, which contains a larger quantity of solute. In a dilute solution, the solute is present in a lower concentration compared to the solvent, which is the substance present in a higher concentration.

When discussing the concentration of solutions, it is essential to express it quantitatively for precision. However, qualitative descriptors such as 'dilute' and 'concentrated' are commonly used. The meaning of these terms can vary depending on several factors, such as the nature of the solute and solvent, as well as the context in which they are used.

For example, a solution containing 1 gram of salt in 1 liter of water is more dilute than a solution containing 10 grams of salt in the same amount of water. The latter would be considered more concentrated. Both terms are relative and describe the amount of solute dissolved in a solvent without precisely quantifying the concentration.

Final answer:

Aluminum hydroxide can be safely ingested in small amounts as it's used in antacids, while sodium hydroxide, calcium hydroxide, and ammonia have various uses but are not safe to ingest in their industrial forms.

Explanation:

The student is asking about which bases can be safely ingested. Among the options given, aluminum hydroxide is a compound that can be ingested safely in small amounts, as it is often used in antacids to combat excess stomach acid. Sodium hydroxide, commonly found in drain cleaner, and calcium hydroxide, though it is used in food processing, must be consumed in very limited amounts because of their high reactivity and potential for causing harm. Ammonia is a weak base and is used in cleaning products; it should not be ingested due to its toxicity. It is important to note that while some bases can be ingested in medicinal or food-grade forms, their industrial counterparts used in cleaning and other products can be harmful and should not be ingested.

Saturated hydrocarbons, such as alkanes, are utilized in combustion processes for producing heat due to their single carbon-to-carbon bonds.

Saturated hydrocarbons, also known as alkanes, involve the direct use of hydrocarbons with only single carbon-to-carbon bonds. An example of an activity that most likely involves the direct use of saturated hydrocarbons is combustion processes for producing heat. These hydrocarbons are composed entirely of single bonds and are saturated with hydrogen.

Answer: iron (III) chloride is the excess reactant in the reaction.

Explanation:

i just did the assignment

Explanation:

According to the mole concept, there are [tex]6.022 \times 10^{23}[/tex] atoms or molecules present in 1 mole.

As, it is given that mass of ethyne is 84.3 g. Hence, calculate its number of moles as follows.

          No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]

                                 = [tex]\frac{84.3 g}{26.04 g/mol}[/tex]

                                 = 3.24 mol

Therefore, calculate number of ethyne molecules as follows.

                 [tex]3.24 mol \times 6.022 \times 10^{23}[/tex] atoms

                    = [tex]19.51 \times 10^{23}[/tex] atoms

Thus, we can conclude that there are [tex]19.51 \times 10^{23}[/tex] atoms in 84.3 grams of ethyne.