How many moles of oxygen atoms do 1.5 moles of co2 contain?

Answers

Answer 1

1 molecule CO2 has 2 atoms O.
1 mole CO2 has 2 moles O,
1.5 mole CO2 has 2*1.5 mole O=3.0 mole O

Answer 2

Final answer:

1.5 moles of carbon dioxide (CO2) contain 3 moles of oxygen atoms because each CO2 molecule is composed of two oxygen atoms.

Explanation:

The question 'How many moles of oxygen atoms do 1.5 moles of CO2 contain?' involves understanding the composition of a carbon dioxide (CO2) molecule.

Each molecule of CO2 consists of one carbon atom and two oxygen atoms. Therefore, for every mole of CO2, there are two moles of oxygen atoms. To find the number of moles of oxygen atoms in 1.5 moles of CO2, we simply need to multiply 1.5 moles by 2 (the number of oxygen atoms per mole of CO2).

1.5 moles CO2 x 2 moles O per mole CO2 = 3 moles O

Thus, 1.5 moles of CO2 contain 3 moles of oxygen atoms.

Related Questions

A gas occupies 2240.0 l at 373 k. what are the volumes at standard temperature answers

Answers

Answer is: the volumes at standard temperature is 1639.46 L.
V₁(gas) = 2240.0 L.
T₁(gas) = 373 K.
T₂(gas) = 273 K, standard temperature.
V₂(gas) = ?
Charles' Law: The Temperature-Volume Law - the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature:
V₁/T₁ = V₂/T₂.
2240 L/373 K = V₂/273 K.
V₂ = 1639.46 L.

The ratios of volumes of the gaseous reactants and products in a chemical reaction at constant temperature and pressure can be determined from the

Answers

The ratios of volumes of the gaseous reactants and products in a chemical reaction at constant temperature and pressure can be determined from the ratios of the mole (or coefficients) of the gaseous reactants and products.

When 2 mol of solid magnesium mg combines with 1 mole of oxygen gas 2 mol of solid magnesium oxide is formed and 1204 kj of heat is released write the thermochemical equation for the combustion reaction?

Answers

In a combustion reaction, element or molecule reaction with oxygen to form corresponding oxide.

In present case, 2 mol of solid magnesium mg combines with 1 mole of oxygen gas 2 mol of solid magnesium oxide is formed and 1204 kj of heat is released. The balanced thermochemical equation for the combustion reaction is

2Mg + O2 → 2 MgO + 1204 kJ

here, 1204 kJ is the energy liberated by the system during the reaction. Liberation of energy suggest the it is an exothermic reaction and the resultant product formed is thermodynamically more stable than reactant.

The thermochemical equation for the combustion reaction of magnesium with oxygen is:

[tex]\[ 2 \text{Mg}(s) + \text{O}_2(g) \rightarrow 2 \text{MgO}(s) \quad \Delta H = -1204 \text{ kJ} \][/tex]

The given reaction is the combustion of magnesium (Mg) with oxygen (O2) to form magnesium oxide (MgO). According to the stoichiometry provided in the question, 2 moles of solid magnesium react with 1 mole of oxygen gas to produce 2 moles of solid magnesium oxide. Along with the formation of products, 1204 kJ of heat is released, indicating that the reaction is exothermic.

In a thermochemical equation, the reactants are written on the left side, and the products are written on the right side, separated by an arrow that points towards the products. The coefficients in the equation (the numbers in front of the chemical formulas) represent the moles of each substance involved in the reaction. In this case, the coefficients are 2 for magnesium, 1 for oxygen, and 2 for magnesium oxide, as given in the question.

The enthalpy change [tex](\(\Delta H\))[/tex] for the reaction is included at the end of the equation to indicate the amount of heat absorbed or released during the reaction. Since the reaction releases heat, the enthalpy change is negative, and it is equal to -1204 kJ for the given reaction. This negative sign indicates that the system releases energy to the surroundings.

Therefore, the complete thermochemical equation, which includes the stoichiometric coefficients and the enthalpy change, is written as:

[tex]\[ 2 \text{Mg}(s) + \text{O}_2(g) \rightarrow 2 \text{MgO}(s) \quad \Delta H = -1204 \text{ kJ} \][/tex]

This equation accurately represents the combustion reaction of magnesium with oxygen, both stoichiometrically and thermochemically.

An aqueous solution is made up of
A. colloids
B. pure water molecules
C. ions dissociated in solution
D. covalent molecules in a water solution.

Answers

I believe an aqueous solution is made up of ions dissociated in solution. An aqueous solution is a solution in which water acts as a solvent. For example a solution sodium chloride in water is shown as Na+(aq) + Cl-(aq). Most acids and bases exists in aqueous solution form.

what is the empirical formula for a compound that is 83.7% carbon and 16.3% hydrogen?

Answers

Hello!

We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100 g solution)

C: 83.7% = 83,7 g
H: 16.3% = 16.3 g

Let us use the above mentioned data (in g) and values will be converted to amount of substance (number of moles) by dividing by molecular mass (g / mol) each of the values, lets see:

[tex]C: \dfrac{83.7\:\diagup\!\!\!\!\!g}{12\:\diagup\!\!\!\!\!g/mol} \approx 6.975\:mol[/tex]

[tex]H: \dfrac{16.3\:\diagup\!\!\!\!\!g}{1\:\diagup\!\!\!\!\!g/mol} = 16.3\:mol[/tex]

We note that the values found above are not integers, so let's divide these values by the smallest of them, so that the proportion is not changed, let's see:

[tex]C: \dfrac{6.975}{6.975} = 1[/tex]

[tex]H: \dfrac{16.3}{6.975} \approx 2.3[/tex]

Note: So the ratio in the smallest whole numbers of carbon to hydrogen is 3:7, thus, the minimum or empirical formula found for the compound will be:

[tex]\boxed{\boxed{C_3H_7}}\end{array}}\qquad\checkmark[/tex]

I hope this helps. =)

The empirical formula should be [tex]C_3H_7[/tex]

The calculation is as follows:

C: 83.7% = 83,7 g

H: 16.3% = 16.3 g

Now

[tex]C = 83.7 \div 12 = 6.975 mol\\\\H = 16.3 \div 1 = 16.3 mol[/tex]

The above does not represent the integers

So,

[tex]C = 6.975 \div 6.975 = 1\\\\H = 16.3 \div 6.975 = 2.3[/tex]

Therefore the above empirical formula should be used.

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is h2c2o4 an Arrhenius base or arrhenius acid

Answers

Answer:
Oxalic Acid is and Arrhenius Acid.

Explanation:
According to Arrhenius Theory of acid and base, "Acid is any substance which when dissolved in water produces H⁺ Ions".

Therefore, Oxalic Acid is a diprotic substance, which is capable of donating protons in water. This acidity of oxalic acid can be dedicated to the stability of conjugate base, this stability comes from resonance of the negative charges on Oxalate ion. Below reaction shows the dissociation of Oxalic Acid into Protons and Oxalate Ion.

H₂C₂O₄, or oxalic acid, is an Arrhenius acid because it dissociates in water to produce hydrogen ions.

H₂C₂O₄, also known as oxalic acid, is an Arrhenius acid, not an Arrhenius base. An Arrhenius acid is defined as a compound which ionizes to yield hydrogen ions (H+) in aqueous solution, whereas an Arrhenius base ionizes to yield hydroxide ions (OH-). Since H₂C₂O₄ dissociates in water to produce two H+ ions and the oxalate ion (C₂O₄-), it increases the H+ ion concentration, making it an acid according to Arrhenius's definition.

For the reaction, identify the Lewis acid and the Lewis base.
AlF3 + CH3F → CH3+ + [AlF4]-

Answers

Answer:
AlF₃ is Lewis Acid

CH₃F is Lewis Base

Explanation:
According to Lewis concept ,"those compounds which donate pair of electrons are called as Lewis Base and those accepting pair of electrons are called as Lewis Acid.

In Given Reaction,
AlF₃ + CH₃F → CH₃⁺ + [AlF₄]⁻

AlF₃ is acting as acid because the octet of Al is not complete, hence it has tendency to accept electrons.

CH₃F is acting as a base because the F atom containing three lone pair of electrons can donate it to Al metal resulting in the formation of electrophile i.e. CH₃⁺.

What is the cause of farsightedness?
The cornea is irregular.
The cornea is opaque.
The eyeball is shortened.
The eyeball is elongated.

Answers

The eyeball is shortened

Answer:

The eyeball is shortened.

Explanation:

Farsightedness, popularly known as difficulty seeing closely, is a common refractive problem, where the image in the eye forms after the retina rather than exactly over the retina, which hinders the brain's ability to process the image correctly. In farsightedness there is no difficulty in seeing objects from afar, but when you get closer, it becomes very difficult to focus on them.

The eyeball works the same way as a dark box: light enters the pupil and forms the image on the retina. The shape of the eye and cornea is perfect for the image to form in the right place (the macula), and then the information is sent to the brain by the optic nerve.

When you have farsightedness, the eyeball is a little shortened or the flatter cornea, so the image ends up forming after the retina, ie the image the retina captures is not correct.

A gas occupies 2.0 m3 at 100.0k and exerts a pressure of 100.0kPa. What volume will the gas occupy if the temperature is increased to 400.0 K and the pressure is increased to 200.0kPa

Answers

According to ideal gas equation, we know for 1 mole of gas: PV=RT
where P = pressure, T = temperature, R = gas constant, V= volume
If '1' and '2' indicates initial and final experimental conditions, we have
[tex] \frac{P1V1}{P2V2} = \frac{T1}{T2} [/tex]

Given that: V1 = 100.0 kPa, T1 = 100.0 K, V1 = 2.0 m3, T2 = 400 K, P2 = 200.0 kPa

∴ on rearranging above eq., we get V2 = [tex] \frac{P1V1T2}{T1} = \frac{100 X 2 X 400}{200X100} [/tex]
∴ V2 = 4 m3

The ideal equation relates the temperature with the pressure and the volume of the gas. When the temperature is increased then the volume will be 4 cubic meters.

What is an ideal gas equation?

An ideal gas equation depicts the relation between the temperature to that of the volume and the pressure of the gas.

The formula is given as,

[tex]\rm \dfrac{P_{1}V_{1}}{P_{2}V_{2}} = \rm \dfrac{T_{1}}{T_{2}}[/tex]

Given,

Initial pressure = 100 kPa

Initial volume = 2 cubic meter

Initial temperature = 100 K

Final pressure = 200 kPa

Final volume = ?

Final temperature = 400 K

The final volume is calculated as:

[tex]\begin{aligned} \rm V_{2} &= \rm \dfrac{P_{1}V_{1}T_{2}}{T_{1}}\\\\&= \dfrac{100\times 2 \times 400}{200 \times 100}\\\\&= 4 \;\rm m^{3}\end{aligned}[/tex]

Therefore, 4 cubic meters is the volume of the final gas.

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Electromagnetic waves, such as visible light, travel in a multitude of orientations. A substance that filters the light so that it only passes through in one plane works somewhat like a fence that allows only some light to pass through. This is the principle of -
A. refraction.
B. diffraction.
C. polarization.
D. interference.

Answers

I believe this is the principle of polarization.
It is the property of electromagnetic waves such as light waves, in which the direction and magnitude of the vibrating electric field are related in a specific way. Electromagnetic waves are the types of waves that do not require a material medium for transmission and travels with the speed of light.

A gas sample occupies 3.50 liters of volume at 20.°c. what volume will this gas occupy at 100°c (reported to three significant figures)?

Answers

Based on Charle's Law, we have
[tex] \frac{V1}{V2} = \frac{T1}{T2} [/tex]
where, V and T are volume and temperature respectively.

Now, given that, V1 = 3.5 L, T1 = [tex] 20 ^{0}C[/tex] = 293 K and T2 = [tex] 100^{0}C[/tex] = 373 K

∴ V2 = [tex] \frac{(T2)X(V1)}{T1} = \frac{373 X 3.5}{293} = 4.556l [/tex]

Determine the molarity of a solution made by dissolving 11.7 g of NaNO3 in water where the final volume of the solution is 250.0 mL.

Answers

Molarity is defined as the number of moles of solute in 1 L solution.
we have been given the mass of NaNO₃ dissolved in 250.0 mL
number of moles of NaNO₃ - 11.7 g / 85 g/mol = 0.138 mol
number of NaNO₃ moles in 250.0 mL - 0.138 mol
since molarity is the number of moles in 1 L
number of NaNO₃ moles in 1000 mL - 0.138 mol / 250.0 mL x 1000mL/L = 0.552 mol
molarity of NaNO₃ is 0.552 M

Answer:

[tex]0.552~M[/tex]

Explanation:

For the calculation of molarity "M" we have start with the molarity equation:

[tex]M=\frac{mol}{L}[/tex]

So, we have to calculate the moles of [tex]NaNO_3[/tex] and the L of [tex]NaNO_3[/tex].

For the calculations of moles we have to use the molar mass of [tex]NaNO_3[/tex].

Na=23 g/mol

N=14 g/mol

O= 16 g/mol

[tex]molar~mass~=~(23*1)+(14*1)+(16*3)=85~g/mol[/tex]

[tex]1~mol~NaNO_3=85~g~NaNO_3[/tex]

Now, we can find the moles of [tex]NaNO_3[/tex]:

[tex]11.7~g~NaNO_3*\frac{1~mol~NaNO_3}{85~g~NaNO_3} =0.138~mol~NaNO_3[/tex]

The next step would be the converstion from mL to L:

[tex]250.0~mL~*\frac{1~L}{1000~mL} =~0.25~L\\[/tex]

Finally, we have to plug both values in the molarity equation:

[tex]M=\frac{0.138~mol}{0.25~L}=~0.552~M[/tex]

What is a disproportionation reaction?

Answers

what is a disproportionation reaction.

What is the oxidation state of an individual phosphorus atom in P O 3 3−?

Answers

-3 - 3(-2) = +3
___________________

A fruit and oatmeal bar contains 142 nutritional calories. Convert this energy to calories

Answers

Answer is: a fruit and oatmeal bar contains 142000 calories.
A nutritional calorie, or kilocalorie, is equal to 1000 calories.
E = 142 kcal · 1000 cal/kcal.
E = 142 000 cal.
Calorie (cal), or small calorie, is the amount of energy needed to heat one gram of water by one degree Celsius.
One small calorie is approximately 4.2 joules.
A calorie is a unit of energy.

Final answer:

142 nutritional calories (Cal) are equal to 142,000 calories (cal) since one nutritional Calorie is equivalent to 1000 scientific calories (cal).

Explanation:

To convert 142 nutritional calories to calories, you need to understand the relationship between the two units. In nutrition, when we say 'calories', we actually mean 'kilocalories' (kcal). One nutritional calorie (with an uppercase C) is equal to one kilocalorie (kcal), and one kilocalorie is equivalent to 1000 calories (with lowercase c).

Therefore, 142 nutritional calories (Cal) are equivalent to 142,000 calories (cal).

The conversion formula is as follows:
142 Cal * 1000 = 142,000 cal

what is the predicted change in the boiling point of water when 4.00 g of barium chloride is dissolved in 2.00 kg of water

Answers

Answer: The predicted change in the boiling point of water is Δt = 0.0148 °C
Solution:
We will use the equation for boiling point elevation Δt
Δt = i Kb m
where the van't Hoff Factor i is equal to 3 since one molecule of barium chloride in aqueous solution will produce one Ba2+ ion and two Cl- ions. The molality m of the solution of 4.00 g of barium chloride dissolved in 2.00 kg of water can be calculated using the molar mass of barium chloride:
m = [4.00g BaCl2 * (1 mol BaCl2 / 208.233g BaCl2)] / 2.00kg H2O
= 0.009605 mol/kg

Therefore, the amount Δt the boiling point increases is
Δt = i Kb m
= (3) (0.512 °C·kg/mol) (0.009605 mol/kg)
= 0.0148 °C
We can also find the new boiling point T for the solution since we know that pure water boils at 100 °C:
Δt = T - 100°C T = Δt + 100°C = 0.0148 °C + 100°C = 100.0148°C

Answer:

0.015 for APEX

Explanation:

A gas expands from a volume of 2.00L at 36.0oC to a volume of 2.50 L, what is the final temperature, if the pressure is constant?

Answers

We shall consider V, the volume and T, the temperature.
According to Boyle's Laws:
[tex] \frac{V1}{T1} = \frac{V2}{T2} [/tex]
In our case:
[tex] \frac{2.00}{36.0} = \frac{2.50}{T2} =\ \textgreater \ T2= \frac{2.50*36.00}{2.00} = 45 [/tex]

The final temperature is 45.45 Celcius

Explanation:

The Combined Gas Law:

The combined gas law allows to derive relationships between the variable that undergoes like pressure, temperature and volume.

[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]

It is given thatpressure is constant so,

[tex]P_1=P_2[/tex]

Hence combined gas law becomes,

[tex]\frac{ V_1}{T_1}=\frac{V_2}{T_2}[/tex]

Substituting the values given in the question,

[tex]\frac{2.00}{36}=\frac{2.50}{T_2}[/tex]

[tex]0.055=\frac{2.50}{T_2}[/tex]

[tex]T_2=\frac{2.50}{0.055}[/tex]

[tex]T_2[/tex]=45.45 C

what is the key difference between a liquid and a gas?

Answers

Answer :

The key differences between a liquid and the a gas is,

Shape and volume :

A liquid has no fixed shape but it has a volume.

A gas has neither a fixed shape nor a volume.

Inter-molecular space :

A liquid has more inter-molecular space between the molecules.

A gas has larger inter-molecular space between the molecules as compared to the liquids.

Inter-molecular attraction :

A liquid has some Inter-molecular attraction between the molecules because of the low Inter-molecular spacing between the molecules.

A gas has very low or minimum Inter-molecular attraction between the molecules because of the larger Inter-molecular spacing between the molecules.

Fluidity :

A liquid flow from the higher to the lower region but a gas flow in all the direction.

Liquids and gases differ from each other in the following ways:

1. Intermolecular forces

2. Motion of particles

3. Direction of flow

4. Compressibility

Further Explanation:

Matter can mainly exist in three physical states. These are solid, liquid and gas.

Solid

It is that state of matter that has a definite shape and volume. These have a regular arrangement of its constituent particles. These have the strongest intermolecular forces between their constituent particles and therefore the motion of particles in solid is almost negligible. Table salt, wood, and diamond are some examples of solids.

Liquid

The state of matter with a definite volume but no particular shape is called liquid. The intermolecular forces in the liquids are weaker than that in solids and therefore the motion of particles in liquids is more as compared to that in solids. Milk, water, and bromine are some examples of liquids.

Gas

This state of matter has neither a definite shape nor a definite volume. These have a disordered arrangement of its constituent particles. These have the weakest intermolecular forces between their constituent particles and therefore the motion of particles in a gas is the highest among all states of matter. Nitrogen, hydrogen and carbon dioxide are some examples of gases.

Liquids have a definite volume but gases occupy the volume of the container in which these are kept.

Liquids have stronger intermolecular forces as compared to that of gases so the motion of gas particles is more than that of liquid particles.

Liquids are incompressible whereas gases are highly compressible in nature.

The flow of liquid takes place from higher to lower level while gases can move randomly in all directions.

Learn more:

1. Which sample is a pure substance? https://brainly.com/question/2227438

2. Which is a characteristic of a mixture? https://brainly.com/question/1917079

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Matter in our surroundings

Keywords: liquid, gas, solid, states of matter, intermolecular forces, shape, volume, matter, strong, weakest, motion of particles.

Which class of compounds is responsible for the scents and flavors of many fruits? amides amines ethers esters

Answers

Esters are responsible for the scents and flavors of many fruits.

Answer: Esters for Plato

Explanation:

if 24500 J is applied to 125g of water at 35 C, what will the final temperature of the water be?

Answers

The final temperature of water is calculated using the below equation

Q= MC delta T
Q= heat energy (24500 j)
m= mass( 125 g)
c= specific heat capacity ( 4.18 j/g/c)
delta T = change in temperature ( final temperature -initial temperature)=(T-35)

final temperature is therefore=24500 j =125 g x 4.18 g/j/c x (T- 35)
24500 j=522.5 (T-35 c)
24500 j = 522.5T -18287.5

like terms together 24500 + 18287.5 =522.5 T
42787.5j =522.5 T
divide both side by 522.5 T

T=81.9 c

Which halocarbon has the highest boiling point? 2-dichloropropane 2-chloropropane 1-chloropropane 1,2,3-trichloropropane?

Answers

1,2,3-trichloropropane

Answer:1,2,3-trichloropropane

Explanation:

A chemical supply company sells a concentrated solution of aqueous h2so4 (molar mass 98 g mol−1 ) that is 50. percent h2so4 by mass. at 25°c, the density of the solution is 1.4 g ml−1 . what is the molarity of the h2so4 solution at 25°c?

Answers

Answer is: the molarity of the sulfuric acid is 7.14 M.
ω(H₂SO₄) = 50% ÷ 100% = 0.5.
d(H₂SO₄) = 1.4 g/mL.
V(H₂SO₄) = 100 mL ÷ 1000 mL/L = 0.1 L..
mr(H₂SO₄) = d(H₂SO₄) · V(H₂SO₄).
mr(H₂SO₄) = 1.4 g/mL · 100 mL.
mr(H₂SO₄) = 140 g.
m(H₂SO₄) = ω(H₂SO₄) · mr(H₂SO₄).
m(H₂SO₄) = 0.5 · 140 g.
m(H₂SO₄) = 70 g.
n(H₂SO₄) = m(H₂SO₄) ÷ M(H₂SO₄).
n(H₂SO₄) = 70 g ÷ 98 g/mol.
n(H₂SO₄) = 0.714 mol.
c(H₂SO₄) = n(H₂SO₄) ÷ V(H₂SO₄).
c(H₂SO₄) = 0.714 mol ÷ 0.1 L.
C(H₂SO₄) = 7.14 M.

How many grams of barium sulfate, baso4, are produced if 25.34 ml of 0.113 m bacl2 completely react given the reaction: bacl2 + na2so4 → baso4 + 2 nacl?

Answers

Answer is: mass of barium sulfate is 0.668 grams.
Chemical reaction: BaCl₂ + Na₂SO₄ → BaSO₄ + 2NaCl.
V(BaCl₂) = 25.34 mL ÷ 1000 mL/L = 0.02534 L.
c(BaCl₂) = 0.113 mol/L.
n(BaCl₂) = V(BaCl₂) · c(BaCl₂).
n(BaCl₂) = 0.02534 L · 0.113 mol/L.
n(BaCl₂) = 0.00286 mol.
From chemical reaction: n(BaCl₂) : n(BaSO₄) = 1 : 1.
n(BaSO₄) = 0.00286 mol.
m(BaSO₄) = n(BaSO₄) · M(BaSO₄).
m(BaSO₄) = 0.00286 mol · 233.4 g/mol.
m(BaSO₄) = 0.668 g.

Answer:

0.668 g of barium sulfate

Explanation:

Given,

Balanced chemical equation: BaCl₂ + Na₂SO₄ → BaSO₄ + 2NaCl.

Volume of BaCl₂ = 25.34 mL x [tex]\frac{1L}{1000 ml }[/tex]= 0.02534 L.

Molarity of BaCl₂ = 0.113 M

Molarilty = [tex]\frac{moles of solute}{L of the solution }[/tex]

Moles of solute = Molarilty x L of the solution

Moles of BaCl₂ = 0.113 M x 0.02534 L = 0.00286 mol.

From the balanced chemical equation there is a 1:1 molar ratio between BaCl₂ and BaSO₄

Therefore, moles of BaCl₂ = moles of BaSO₄

Moles of BaSO₄ = 0.00286 mol.

Mass of BaSO₄ = moles of BaSO₄ x Molar mass of BaSO₄

Mass of BaSO₄ = 0.00286 mol x 233.4 g/mol.

Mass of BaSO₄ = 0.668 g.

Both protons and neutrons (and their anti-particles) froze out:

Answers

I think Both protons and neutrons (and their anti-particles) froze out at 1013 K, about 0.0001 seconds after the Big Bang. Protons and neutrons are sub atomic particles of an atom that are found in the nucleus of an atom. Proton is the positively charge particle while the neutron has no charge. The proton positive charge accounts for the positive nuclear charge.

What conditions favor the formation of ionic compounds from elements? both atoms must be non metals. you must have a metal and a nonmetal. both atoms must be metals. you must have a metal atom and a halogen?

Answers

You must have a metal and a non-metal

Final answer:

The formation of ionic compounds is favored when a metal, which loses electrons, combines with a nonmetal, which gains electrons. This process results in an ionic compound stabilized by ionic bonds between ions of opposite charges, a well-known example being sodium chloride (NaCl). It's also possible for an ionic compound to form between a metal atom and a halogen.

Explanation:

The conditions favoring the formation of ionic compounds typically involve a metal and a nonmetal. This is because metals, which have low ionization potential, tend to readily lose electrons and nonmetals, with high electron affinities, tend to gain electrons. In this process, such as the formation of sodium chloride (NaCl), the metal (sodium) loses an electron to form a cation (Na+), and the nonmetal (chlorine) gains an electron to form an anion (Cl-), resulting in an ionic compound. The compound is stabilized by ionic bonds, which are electrostatic attractions between ions of opposite charges.

The formation of ionic compounds ensures that both the metal and nonmetal achieve a stable electron configuration, often referred to as an octet. Additionally, ionic compounds can also form between a metal atom and a halogen as halogens are a group of nonmetals that are extremely electron-affinitive.

Lastly, it's important to note that not all combinations of metals and nonmetals produce ionic compounds. For instance, compounds that do not contain ions but consist of atoms bonded tightly together in molecules, usually form from two nonmetals and are called covalent compounds.

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What do we call the mass of an element in a compond compared to the entire mass of the compound?

Answers

molar mass is the mass of a given substance divided by the amount of that substance, measured in g/mol.

What is the molality of a solution made by dissolving 14.7 g of c6h12o6 into 150.0 ml of water? assume the density of water is 1.00 g/ml?

Answers

Hello!

We have the following data:

W (molality) = ? (in Molal)
m1 (mass of the solute) = 14.7 g
m2 (mass of the solvent) =? (in Kg)
d (solvent density) = 1,00 g/mL
V (volume of the solvent) = 150 mL

The mass of the solvent will be found by the following formula

[tex]d = \dfrac{m_2}{V} [/tex]

[tex]1 = \dfrac{m_2}{150} [/tex]

[tex]m_2 = 1*150 [/tex]

[tex]m_2 = 150\:g\to \boxed{m_2 = 0,15\:Kg}[/tex]

M1 (Molar mass of solute - C6H12O6) = ?
C = 6*12 = 72 u
H = 12*81 = 12 u
O = 6*16 = 96 u
------------------------
M1 (Molar mass of solute - C6H12O6) = 72+12+96 = 180 g/mol

Now, let's find Molality, applying the above data to the formula, let's see:

[tex]\omega = \dfrac{m_1}{M_1*m_2} [/tex]

[tex]\omega = \dfrac{14,7}{180*0,15}[/tex]

[tex]\omega = \dfrac{14,7}{27}[/tex]

[tex]\boxed{\boxed{\omega \approx 0,54\:Molal}}\end{array}}\qquad\checkmark[/tex]

I hope this helps. =)

Final answer:

The molality of the solution is calculated by dividing the number of moles of glucose by the mass of water in kilograms, resulting in a solution with a molality of 0.544 m.

Explanation:

The question is asking to calculate the molality of a glucose solution. To find the molality, we need to know the mass of the solute (glucose) and the mass of the solvent (water) in kilograms.

Steps to Calculate Molality

First, calculate the number of moles of glucose (C6H12O6). Its molar mass is 180.16 g/mol.

Next, convert the mass of water from milliliters to kilograms. Since the density of water is 1.00 g/mL, we simply convert 150.0 mL to grams and then to kilograms.

Finally, use the equation for molality: molality (m) = moles of solute (mol) / mass of solvent (kg).

Let's perform the calculations:

Moles of glucose = 14.7 g / 180.16 g/mol = 0.0816 mol

Mass of water = 150.0 mL * 1.00 g/mL = 150.0 g = 0.150 kg

Molality of the solution = 0.0816 mol / 0.150 kg = 0.544 m

If the temperature of a 5 L sample of gas is lowered from 400k to 200k, what will the resulting volume of the gas be?

Question 4 options:

10 L

50 L

2.5 mL

2.5 L

Answers

The answer would be 2.5ML

How many atoms are in a sulfur molecule that has the elemental formula s8?

Answers

[tex]S_{8} 8 atoms of S in the molecule S_{8} Subscript shows number of atoms in the molecule. For example, O_{3} - 3 atoms of oxygen in the molecule of ozone.[/tex]

What volume will 50.2 grams of co2 (g) occupy at stp?

Answers

Final answer:

The volume at STP that 50.2 grams of CO2 will occupy is found by converting the mass to moles and then multiplying by the molar volume of a gas at STP, which is 22.4 liters per mole.

Explanation:

To find the volume at STP that 50.2 grams of CO2 (g) will occupy, we first need to convert the mass of CO2 to moles using the molar mass of CO2, which is approximately 44.01 g/mol. Next, we apply the concept that one mole of any gas at STP will occupy 22.4 liters. The calculation involves dividing the mass of CO2 by its molar mass to get the moles, and then multiplying the number of moles by 22.4 L/mol to find the volume.The steps are as follows:Calculate the number of moles: number of moles = mass (g) / molar mass (g/mol)

Calculate the volume at STP: volume (L) = number of moles x 22.4 L/mol

By following these steps, we can determine the volume of CO2 gas at STP conditions.

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