Physics College

How many new elements (fission fragments, or daughter nuclei) are typically presented as a result of fission?

1

3

2

5

Answers

Answer 1
The correct option is 2.
Nuclear fission refer to a nuclear reaction in which the nucleus of a single radioactive element is split into two different smaller nuclei, which are different from the parent element accompany with the release of energy. Nuclear fission is typically used to produce energy. The two smaller nuclei are called fission products.

Related Questions

When ultraviolet light with a wavelength of 400 nm falls on a certain metal surface, the maximum kinetic energy of the emitted photoelectrons is measured to be 1.10 ev . part a what is the maximum kinetic energy of the photoelectrons when light of wavelength 295 nm falls on the same surface? emax =?

Answers

A general relationship between Kinetic Energy (KE) and wavelength (y) is that KE is inversely proportional to square of y. That is,

KE α 1/y^2 => KE = k/y^2 where k is a constant of proportionality.

For KE = 1.10 ev, and y = 400 nm;

k = KE*y^2 = 1.10*400 = 176,000 ev.nm^2

For y = 295 nm,

KE = k/y^2 = 176,000/295^2 = 2.02 ev.

Therefore, e max = 2.02 ev

A cello string 0.75 m long has a 220 hz fundamental frequency. find the wave speed along the vibrating string. answer in units of m/s.

Answers

For fundamental frequency of a string to occur, the length of the string has to be half the wavelength. That is,

1/2y = L, where L = length of the string, y = wavelength.

Therefore,
y = 2L = 2*0.75 =1.5 m

Additionally,
y = v/f Where v = wave speed, and f = ferquncy

Then,
v = y*f = 1.5*220 = 330 m/s

Light of wavelength 600 nm illuminates a diffraction grating. the second-order maximum is at angle 39.5 ∘. part a how many lines per millimeter does this grating have?

Answers

Diffraction equation applies in this case:

d*Sin x = m*wavelength, where d = spacing of lines, x = angle = 39.5°, m = order of maximum = 2

Substituting;
d* Sin 39.5 = 2*600*10^-9
d = (2*600*10^-9)/Sin 39.5 = 1.88656*10^-6 m

In 1 mm (or 0.001 m), the number of lines is given as;
Number of lines = 0.001/d = 0.001/(1.88656*10^-6) = 530.065 ≈ 530 lines

The number of lines per millimeter that the grating has is : ≈ 530 lines

Given data :

light wavelength = 600 nm

second order maximum angle ( x ) = 39.5°

order of maximum = 2

Determine the number of lines the grating will have

We will apply diffraction equation

[tex]d*sinx = m*wavelength[/tex] --- ( 1 )

where : d = spacing of lines, x =  39.5°, m = 2

Insert values into equation ( 1 ) above

d * Sin ( 39.5 ) = 2 * 600 * 10⁻⁹

therefore ; d = 1.88656 * 10⁻⁶ m

Final step : determine the number of lines per mm

Number of lines per mm

= 0.001 / d

= 0.001 / (1.88656 * 10⁻⁶ )  ≈ 530 lines

Hence we can conclude that The number of lines per millimeter that the grating has is ≈ 530 lines

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What is the approximate wavelength of a light whose first-order bright band forms a diffraction angle of 45.0° when it passes

Answers

** Missing info: Lines per mm = 500 **

Ans: The wavelength is =  λ = 1414.21 nm

Explanation:
The formula for diffraction grading is:

dsinθ = mλ --- (1)

Where
d = 1/lines-per-meter = (1/500)*10^-3 = 2 * 10^-6
m = order = 1
λ = wavelength
θ = 45°

Plug in the values in (1):
(1) => 2*10^-6*sin(45°) = (1)λ
=> λ = 1414.21 nm

Organ pipe a, with both ends open, has a fundamental frequency of 340 hz. the third harmonic of organ pipe b, with one end open, has the same frequency as the second harmonic of pipe
a. how long are (a) pipe a and (b) pipe b? (take the speed of sound to be 343 m/s.)

Answers

The fundamental frequency of the open pipe A
Length 'L₀' is, f₀ = U/2L₀ = 340 H₂
the speed of sound in air V=  343m/s
∴343/2L₀ = 340 → length L₀ = 343/2 ×340 = 0.5044 = 50.44
The third harmonic of closed pipe 'B' is 
F3₀ = 3V/4LC
The second harmonic of open pipe 'A'  is
f2₀ = 2V/2L₀
∴ 3V/4LC = 2V/2L →L₀ = 3L₀/4
⇒ The length of closed pipe B is 
Lc = 37.83cm

What real-world examples show no work begin done? Can you think of examples other than resisting the force of gravity?

Answers

Oh my gosh !  Resisting the force of gravity always DOES involve doing work.
If no work is being done, then you're NOT resisting the force of gravity.

Example:

-- ball rolling on the floor . . . no work
-- ball rolling up a ramp . . . work being done
-- ball rolling down a ramp . . . work being done, BY gravity

Answer:

Explanation:

The work done is defined as the product of force in the direction of displacement and the displacement.

Work done = force x displacement x Cos Ф

Where, Ф be the angle between force and the displacement vectors.

Work may be positive, negative or zero depending on the values of angle Ф.

The work done is zero when force is zero or displacement is zero or angle Ф is 90 degree.

So, when we apply a force on a body and body does not displace, then the work done is zero.

What happens when a person’s immune system is very weak?

a) The patient’s blood is unable to clot so he or she must take medication.

b) The patient is able to fight off more infections than normal.

c) The patient is unable to fight the infections a healthy person could resist.

d) The patient is unable to take antibiotics and must get a flu shot.

Answers

the correct answer is C) becuse without certain medicine they will dieeeee
Final answer:

When a person's immune system is very weak, their body may be unable to fight off pathogens and diseases that a healthy immune system can resist. This can lead to increased risk of illness and vulnerability to infection.

(Option C)

Explanation:

Immunodeficiency occurs when the immune system is not working properly, generally because one or more of its components are inactive. As a result, the immune system may be unable to fight off pathogens or cancers that a normal immune system would be able to resist. Immunodeficiency may occur for a variety of reasons.

The body's immune system would not be able to fight off pathogens like bacteria with fewer white blood cells. This can increase the risk of illness in HIV patients.

The person's immune system would not be able to distinguish self and non-self. This would make the person very vulnerable to infection.

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Which lists the amplitudes of sound waves from these sources in order from greatest to least?

busy roadway, kids whispering, average home

chainsaw, diesel truck, rustling leaves

kids whispering, vacuum cleaner, jet airplane

library, conversational speech, music from speaker

Answers

Answer:

The correct answer is option B which is a chainsaw, diesel truck, rustling leaves.

Explanation:The amplitude of the sound wave is the maximum displacement of the particles from their resting position.Higher the amplitude means high sound.So the sound of a chainsaw is high, so its amplitude will be great and after that the amplitude of diesel truck is high and rustling leaves have the lowest amplitude.

Answer:

B

Explanation:

Edge :)

What's the pressure and temp of 6694 meters high

Answers

Applying rule of thumb: For every 1000 m, temperature drops by 2 °C. If the ground temperature is room temperature at 20 °C, then:

At 6694 m, temperature = 20 - (6694/1000*2) = 6.6°C
Now,
H= (30t+8000)*ln (C/P), where H = Altitude, t = temperature, C = ground atmospheric pressure, say 101325 Pa, P is the pressure at the altitude.

Therefore,
6694 =(30*6.6+8000) ln (C/P) => 0.8165 = ln (1013255/P) => e^0.8165 = 101325/P => 2.2627 = 101325/P => P = 101325/2.2627 = 44781.39 Pa

A certain part of the electromagnetic spectrum ranges from 200 nm to 400 nm. what is the highest frequency associated with this portion of the spectrum? (c = 3.00 × 108 m/s)

Answers

The lowest and highest wavelengths of this part of the electromagnetic spectrum are:
[tex]\lambda_1 = 200 nm=200 \cdot 10^{-9} m[/tex]
[tex]\lambda_2 = 400 nm=400 \cdot 10^{-9} m[/tex]

The frequency and the wavelenght of an electromagnetic wave are related by
[tex]f= \frac{c}{\lambda} [/tex]
where c is the speed of light and f the frequency. By using this equation, we can find the frequencies that corresponds to the lowest and highest wavelengths of this part of the spectrum:
[tex]f_1 = \frac{c}{\lambda_1}= \frac{3 \cdot 10^8 m/s}{200 \cdot 10^{-9} m}=1.5 \cdot 10^{15}Hz [/tex]
[tex]f_2 = \frac{c}{\lambda_2}= \frac{3 \cdot 10^8 m/s}{400 \cdot 10^{-9} m}=7.5 \cdot 10^{14}Hz [/tex]

So, the highest frequency associated with this part of the spectrum is the one corresponding to the lowest wavelength:
[tex]f_1 = 1.5 \cdot 10^{15}Hz[/tex]
Final answer:

The highest frequency associated with the portion of the electromagnetic spectrum ranging from 200 nm to 400 nm is 7.50 × 10^14 Hz.

Explanation:

The highest frequency associated with the portion of the electromagnetic spectrum ranging from 200 nm to 400 nm can be determined using the formula c = fλ, where c is the speed of light. In this case, the wavelength is given as 200 nm to 400 nm. Converting the wavelength to meters, we find that it corresponds to 2.00 × 10-7 m to 4.00 × 10-7 m. Using the formula, we can rearrange it to solve for the frequency, f = c/λ. Plugging in the values, we get the highest frequency as 7.50 × 1014 Hz.

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which formula represents Snell's law


Answers

Its B. n1sin01=n2sin02

Snell's law is used for refraction of light

it is used to find the relation between refractive index of two medium and angle of incidence and angle of refraction.

As per this formula

[tex]n_1 sin\theta_i = n_2 sin\theta_r[/tex]

here [tex]n_1[/tex] = refractive index of first medium

[tex]n_2[/tex] = refractive index of second medium where light go after refraction

[tex]\theta_i[/tex] = angle of incidence

[tex]\theta_r[/tex] = angle of refraction


Bats can detect small objects such as insects that are of a size on the order of a wavelength. if bats emit a chirp at a frequency of 69.3 khz and the speed of sound waves in air is 330 m/s, what is the smallest size insect they can detect? give your answer in mm (millimeters)

Answers

The smallest size of the insect that the bats can detect corresponds to the wavelength of the chirp they emit.

Their chirp has a frequency of
[tex]f=69.3 kHz=69.3 \cdot 10^3 Hz[/tex]
and the speed of the chirp is equal to the speed of sound in air:
[tex]v=330 m/s[/tex]
Therefore the wavelength of the chirp is
[tex]\lambda= \frac{v}{f}= \frac{330 m/s}{69.3 \cdot 10^3 Hz}=4.76 \cdot 10^{-3} m [/tex]
which corresponds to a size of 4.76 mm.

Many __________ cause poor pupil function more quickly than alcohol does.


A. Pain relievers

B. Antihistamines

C. Tranquilizers

D. Benzodiazepines

Answers

The answer is A. Pain Relievers

Answer:

B. Antihistamines

Explanation:

Whenever you have an allergy, your body creates a chemical called histamines. For a short term treatment against there allergies, you can take antihistamines. However, among the side effects of this treatment is poor pupil function.

So the correct answer is:

B. Antihistamines

At what speed does the classical momentum, p=mv, give an error, when compared with the relativistic momentum, of 1.35 % ?

Answers

The classical momentum is given by:
[tex]p_c=mv[/tex]
where m is the particle mass and v its velocity, while the relativistic momentum is given by:
[tex]p_r=\gamma mv[/tex]
where 
[tex]\gamma = \frac{1}{ \sqrt{1- \frac{v^2}{c^2} } } [/tex]  (1)
is the relativistic factor, with c being the speed of light.

The condition given by the problem (error of 1.35%) can be rewritten as
[tex] \frac{p_r - p_c}{p_r} = 0.0135 [/tex]
which means
[tex]p_r = \frac{p_c}{0.9865} [/tex]
and since [tex]p_r = \gamma p_c[/tex], this also means that
[tex]\gamma = \frac{1}{0.9865}=1.0137 [/tex]

Now let's re-arrange eq.(1), and we get
[tex]v=c \sqrt{1- \frac{1}{\gamma^2} } [/tex]
and if we use [tex]\gamma=1.0137[/tex] as we found before, and [tex]c=3 \cdot 10^8 m/s[/tex], we find the corresponding velocity:
[tex]v=(3 \cdot 10^8 m/s) \sqrt{1- \frac{1}{(1.0137)^2} } = 4.9 \cdot 10^7 m/s[/tex]

Final answer:

To calculate the speed at which the classical momentum gives an error compared to the relativistic momentum, we need to find the ratio of the two different momenta. This can be done by solving for the velocity using the given equations and approximations.

Explanation:

The classical momentum, p=mv, gives an error when compared with the relativistic momentum. The error can be calculated by finding the ratio of the relativistic momentum to the classical momentum. In this case, the error is 1.35%. To find the velocity at which this error occurs, we need to solve for the velocity using the given equations and approximations.

(a) Find the momentum of a 1.00 × 10⁹ kg asteroid heading towards the Earth at 30.0 km/s.

(b) Find the ratio of this momentum to the classical momentum. (Hint: Use the approximation that y = 1+(1/2)v²/c² at low velocities.)

An automotive research facility is testing a new design on bumpers to determine the force at which it will break. The formula for Force is F = 1 2 m v 2 Where m is the mass (weight) and v is the velocity (speed)What is the effect on the force if the velocity changes from 5 miles per hour to 10 miles per hour?

What is the effect on the force if the velocity changes from 5 miles per hour to 10 miles per hour?

Same
Twice as much
Four times as much
Five times as much

Answers

Let's call (F1) the force produced with a speed of 5 miles per hour.
 Call (F2) the force produced with a speed of 10 miles per hour.
 To know what the effect on force is, change the speed from 5 miles per hour to 10 miles per hour, divide F2 / F1 to find the relation.
 So:
 F2 / F1 = (12m * 10²) / (12m * 5²)
 F2 / F1 = 4.
 Therefore, the answer is option 3.
 Strength increases 4 times more

How does natural selection result in adaptations in a species

Answers

An organism's "fitness" is measured by its ability to live long enough to reproduce and pass down traits to their offspring. In sexually reproducing organisms, those who are most fit are most likely to survive often have a specialized trait that gave them the advantage in doing so. The organism with the traits that allowed them to survive and reproduce passes the trait to it's offspring. Assuming that the environment doesn't overly change, those offspring have a greater chance to survive and reproduce themselves. Thus, this trait becomes a specialized adaption for the environment and allows the species as a whole to survive longer.

When a rocket is traveling toward a mountain at 100 m/s, the sound waves from this rocket's engine approach the mountain at speed v. if the rocket doubles its speed to 200 m/s, the sound waves from the engine will now approach the mountain at speed?

Answers

The sound will approach the mountain at the same speed, v, irrespective of the speed of the rocket. This is because sound will always travel at the same speed as long as properties of air remain the same.
Therefore, sound will approach the mountain at velocity v in both 100 m/s and 200 m/s of the rocket.

Answer:

The sound waves from the engine will approach the mountains at the same speed, no matter if the speed of the rocket is 100m/s or 200 m/s.

Explanation:

The sound wave is a property of the air, which means that the speed of the object producing sound does not matter to the sound of the waves, that is, they are always going to be the same.

So the sound waves from the engine will approach the mountains at the same speed, no matter if the speed of the rocket is 100m/s or 200 m/s.

Assume that you have two objects, one with a mass of 10 kg and the other with a mass of 18 kg, each with a charge of −0.027 c and separated by a distance of 9 m. what is the electric force that these objects exert on one another? answer in units of n.

Answers

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Final answer:

Using Coulomb's law, the electric force between two objects with charges of – 0.027 C each and separated by 9 m is 81 N. The force is repulsive since the charges are alike.

Explanation:

To calculate the electric force between two objects using Coulomb's law, one needs to know the charges on the objects and the distance separating them. Coulomb's law is represented by the formula F = k * |q1 * q2| / r2, where F is the force between the charges, k is Coulomb's constant (9.0 × 109 N·m2/C2), q1 and q2 are the amounts of the charges, and r is the distance between them.

In this case, with both objects having a charge of – 0.027 C and separated by a distance of 9 m, the electric force F is calculated as follows:

F = (9.0 × 109 N·m2/C2) * |(– 0.027 C) * (– 0.027 C)| / (9 m)2

Since the charges are like charges, the force will be repulsive and we can ignore the negative sign for the purposes of calculating magnitude:

F = (9.0 × 109 N·m2/C2) * (0.027 C * 0.027 C) / (81 m2) = 9.0 × 109 * 0.000729 / 81 = 8.1 × 101 N

Thus, the electric force between the two objects is 81 N acting to push them apart.

¿Cuál es la velocidad promedio de un hombre que camina 70m con una rapidez de 1m/s y luego corre 70m con una rapidez de 3m/s?

Answers

Hola!

Respuesta:

[tex]1,5 \frac{m}{s} [/tex]

Explicación:

Para calcular la velocidad promedio, necesitamos conocer dos cosas:

1: Distancia total recorrida
2: Tiempo total del recorrido

Del enunciado tenemos los siguientes datos:

Primer tramo:

Distancia recorrida : 70 m
Velocidad: [tex] \frac{1m}{s} [/tex]

Segundo tramo:

Distancia recorrida:70 m
Velocidad: [tex]\frac{3m}{s}[/tex]

Utilizando la siguiente formula:

[tex]X=Xo + V.t[/tex]

Donde:

X: Distancia final
Xo: Distancia inicial
V: Velocidad
T: Tiempo

Para este ejercicio, nos es dada la distancia recorrida, es decir  la diferencia entre la distancia final (X) y la distancia inicial (Xo), teniendo que:

[tex]X-Xo= V. t[/tex]

Sustituyendo los valores del primer tramo, tenemos:

[tex]70m= \frac{1m}{s} .t \\ t= \frac{70m}{ \frac{1m}{s \\ } } \\ t= 70s [/tex]

Sustutuyendo los valores del segundo tramo, tenemos:

[tex]70m= \frac{3m}{s} .t \\ t= \frac{70m}{ \frac{3m}{s \\ } } \\ t= 23,33 s[/tex]

Calculando ambos tiempos, tenemos un tiempo de recorrido total de:

[tex]Ttotal= [/tex] Tiempo en el tramo 1 + Tiempo en el tramo 2 [tex]= 93,33 s[/tex]

Para calcular la velocidad promedio, dividimos la distancia total del recorrido por el tiempo total recorrido. Esta viene dada por la siguiente formula:

[tex]Vprom= \frac{Distancia Total}{Tiempo Total} = \frac{140 m}{93,33s} = \frac{1,5m}{s} [/tex]

Que tengas un buen día!


What are three benefits of being assertive and what are three tips to help you develop an assertive style of communication? (Site 1)

                 

Answers

1. The benefits of been assertive include the following:
a. It improve one self image: When you choose to be assertive, you adopt  a self realistic image.
b. It enhance how we understand others: Been assertive helps you to see others in a more realistic context.
c. Promote self awareness and self confidence: Been assertive helps you to develop a greater respect for your own points of view when dealing with issues. 
d. Been assertive is a less stressful way of communicating.

2. The three steps needed to develop assertive communication, include:
a. Learn to 'no' more often: refuse to please everyone and do not behave according to people expectations of you. Be yourself.
b. Your tone must be properly turned when talking: Do not raise your voice or rush a communication. Be calm and cool when talking.
c. Be open to communication: Be willing to discuss issues until a suitable solution is found.
d. Pay attention to non-verbal communication of others: Keep eye contact when communicating and pay attention to other body gestures. 

Which statement is true of equinoxes? They occur in June and December. Days and nights are equal in length everywhere. The length of daylight in the Arctic and Antarctic circles is 24 hours. The sun’s vertical rays are striking either 23.5°S or 23.5°N.

Answers

Days and nights are equal in length everywhere.(gradpoint)

Answer: Days and nights are equal in length everywhere.

Explanation:

Equinox means equal night. There are two equinox - vernal equinox and autumnal equinox. When the sun crosses celestial equator, the sun rays fall directly over equator at noon. Thus, there is equal length of day and night in the two hemisphere. It occurs around March 22 and September 22.

What is the resistance of a resistor if the potential differences across the resistor is 4v when a cirrent of 10 a flow through the resistor?

Answers

R=V/I = 4v / 10A = 0.4 ohms

The most common natural fiber found at a crime scene, and thus forensically insignificant (unless it is of a unique color)

Answers

i believe the answer is cotton
The answer is cotton.

Two small objects each with a net charge of +q exert a force of magnitude f on each other: we replace one of the objects with another whose net charge is +4q: the original magnitude of the force on the +q charge was f; what is the magnitude of the force on the +q charge now?

Answers

The force between 2 charged objects is given by, F = kq1q2/d².
where k ⇒ constant
          d ⇒ distant between the 2 objects.
 
In this case, k and d are constants.
So, let k/d² = x
since q1=q2,
F = xq²
x = F/q²
After replacing q1  with 4q, the new force on +q will be:

F = xq.4q
    = Fq4q/q²
    = 4F

The new charge on +q is 4F.  

which step makes proteins by binding amino acids together

Answers

Translation is when proteins are produced from amino acids carried by tRNA. If you need a thorough explanation, you can message me.

The intensity of the sun's radiation incident upon the earth is about i=1.4kw/m2. suppose this is the value for the intensity of sunlight incident upon the satellite's solar panels. what is the total solar power p absorbed by the panels?

Answers

Intensity = power/ Area
⇒ Power absorbed = 1× A ⇒ 1.4 × 10∧3 ×(10)
= 14000 Watt = 14 kWatt
time - averaged intensity divided by speed of light in free space is the radiation pressure
P = (1.4 × 1000)/c
Force = pressure × area ⇒ ((1.4× 1000)/(10∧8)) × 10
= 0.00004666666N
0.000047N

An elephant can hear sound with a frequency of 15 hz. what is the wavelength of this wave if the speed of sound in air is 343 m/s?

Answers

Final answer:

The wavelength of a sound wave with a frequency of 15 Hz and a speed of sound in air of 343 m/s is approximately 22.87 meters.

Explanation:

To calculate the wavelength of the sound wave, we can use the formula:

Speed of sound (v) = wavelength (λ) x frequency (f)

Given that the frequency of the sound wave is 15 Hz and the speed of sound in air is 343 m/s, we can substitute these values into the formula to solve for the wavelength:

343 m/s = λ x 15 Hz

Dividing both sides of the equation by 15 Hz, we get:

λ = 343 m/s / 15 Hz = 22.87 meters (rounded to two decimal places)

Therefore, the wavelength of the sound wave is approximately 22.87 meters.

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1. Which of the following statements about mechanical waves is true?
a. mechanical waves require a medium to travel through
b. mechanical waves do not have amplitude and wavelength
c. mechanical waves do not have frequency
d. mechanical waves can travel through blank space

2. Which waves have the shortest wavelength and highest energy on electromagnetic spectrum?
a. microwaves
b. x-rays
c. infrared
c. gamma rays

3. What is true about infrared and X-Rays?
a. X-Rays have greater longer wavelength than infrared
b. Infrared have shorter wavelength than x-rays
c. x-rays have lower energy than infrared
d. Infrared have lower frequency than x-rays

4. In a longitudinal wave (compression wave_ the particles of a matter move ______
a. perpendicular (at right angles)
b. in a circular direction
c. backwards
d. parallel

5. In regard to spend of sound, sound travels slowest in ____
a. solids
b.liquids
c. gases

Answers

1) a. mechanical waves require a medium to travel through
In fact, mechanical waves cannot travel trough empty space, but they always require a medium for their propagation. (on the contrary, electromagnetic waves can also travel through empty space)

2) d. gamma rays
In fact, gamma rays are the radiations with shortest wavelength on the electromagnetic spectrum (range in the picometer). Correspondingly, this is the radiation with highest energy, because the energy of the radiation is inversely proportional to its wavelength, according to:
[tex]E=h \frac{c}{\lambda} [/tex]
where h is the planck constant, c the speed of light and [tex]\lambda[/tex] the wavelength.

3) d. Infrared have lower frequency than x-rays
In fact, infrared radiation has frequency in the range of the THz (terahertz, [tex]10^{12} Hz[/tex]), while x-rays have frequency in the range of hundreds of PHz (Petahertz, [tex]10^{15}Hz[/tex]).

4) d. parallel
In longitudinal waves, the oscillations of the wave (such as the motion of the particles in a compression wave) occur in the direction parallel to the direction of propagation of the wave itself.

5) c. gases
Sound travels slowest in gases. In fact, the speed of sound is proportional to the density of the medium: the more dense the medium is, the faster is the sound in that medium, and vice-versa. Since gases are less dense than liquids and solids, sound travels slowest in gases. The reason is that sounds propagates through the oscillations of the molecules of the medium; if the medium is less dense (such as in gases), it takes more time to transmit the sound through the medium itself.
Final answer:

Mechanical waves require a medium to travel, gamma rays have the highest energy and shortest wavelength on the electromagnetic spectrum, x-rays have higher frequency than infrared, particles in a longitudinal wave move in parallel, and sound travels slowest in gases.

Explanation:

1. The correct statement about mechanical waves is 'a. mechanical waves require a medium to travel through'. Unlike electromagnetic waves, mechanical waves, such as sound or seismic waves, need a medium like air, water, or solids to propagate or move.

2. The waves with the shortest wavelength and highest energy on the electromagnetic spectrum are 'c. gamma rays'.

3. The true statement about infrared and X-Rays is 'd. Infrared has lower frequency than x-rays'. X-rays have a higher frequency and shorter wavelength compared to infrared waves, which directly impacts their energy levels, with X-rays having higher energy.

4. In a longitudinal wave (compression wave), the particles of matter move 'd. parallel' to the direction of the wave's propagation. This is different from transverse waves where particles move perpendicular to the wave direction.

5. Sound travels slowest in 'c. gases'. Sound waves travel the fastest through solids, slower through liquids, and slowest through gases.

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Two long parallel wires carry currents of 20 a and 5.0 a in opposite directions. the wires are separated by 0.20 m. what is the magnitude of the magnetic field midway between the two wires?

Answers

Final answer:

The magnitude of the magnetic field midway between two long parallel wires carrying currents of 20 A and 5.0 A in opposite directions and separated by 0.20 m is 4.5 x 10⁻⁵ T.

Explanation:

To find the magnitude of the magnetic field midway between the two long parallel wires carrying currents of 20 A and 5.0 A in opposite directions and separated by 0.20 m, we can use the formula for the magnetic field due to a long straight wire. The magnitude of the magnetic field at a distance r from the wire is given by: B = (μ₀ * I) / (2π * r). Since we are looking for the magnetic field midway between the wires, the distance from each wire to the point is half of the total separation, which is 0.10 m. Plugging in the values, we get: B = (4π * 10⁻⁷ T·m/A * (20 A + 5.0 A)) / (2π * 0.10 m) = 4.5 x 10⁻⁵ T.

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Final answer:

The magnitude of the magnetic field midway between two parallel wires carrying currents of 20 A and 5 A in opposite directions and separated by 0.20 m is 3 * 10^-6 T.

Explanation:

To find the magnitude of the magnetic field midway between the two wires, we can use the formula for the magnetic field produced by a long straight wire:

B = (μ0 * I) / (2πr)

where B is the magnetic field, μ0 is the permeability of free space, I is the current, and r is the distance from the wire. In this case, we have two wires with currents of 20 A and 5 A, and they are separated by 0.20 m. Since we are interested in the magnetic field midway between the wires, the distance r will be half of the separation between the wires, which is 0.20 m / 2 = 0.10 m.

Plugging in the values, we get:

B = (4π * 10-7 T·m/A * (20 A - 5 A)) / (2π * 0.10 m) = (4 * 10-7 T·m/A * 15 A) / (0.20 m) = 3 * 10-6 T

So, the magnitude of the magnetic field midway between the two wires is 3 * 10-6 T.

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How many photons per second are emitted by the antenna of a microwave oven if its power output is 1.00 kw at a frequency of 2515 mhz?

Answers

Final answer:

To determine the number of photons emitted per second by the antenna of a microwave oven, we need to use the formulas for energy per photon and number of photons.

Explanation:

The number of photons emitted by the antenna of a microwave oven can be calculated using the formula:

Number of photons = (Power output / Energy per photon) x frequency

To find the energy per photon, we can use the formula:

Energy per photon = Planck's constant x frequency

Given that the power output is 1.00 kW and the frequency is 2560 MHz, we can convert these values to SI units and calculate the number of photons emitted per second.

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Approximately 6.01 x 10²⁶ photons per second are emitted by the antenna of the microwave oven.

To determine the number of photons emitted per second by a microwave oven, we can use the formula:

Number of Photons per Second (N) = Power Output (P) / Energy per Photon (E)

Given:

Power Output (P) = 1.00 kW (or 1000 W)Frequency (f) = 2515 MHz (or 2.515 x 10⁹ Hz)

First, find the energy per photon (E) using the equation:

E = h * f

where h is Planck's constant (6.626 x 10⁻³⁴ Js) and f is the frequency.

Substitute the values:

E = 6.626 x 10⁻³⁴ Js * 2.515 x 10⁹ Hz

E = 1.665 x 10⁻²⁴ J

Next, calculate the number of photons per second:

N = P / E

N = 1000 W / 1.665 x 10⁻²⁴ J

N ≈ 6.01 x 10²⁶ photons per second

Therefore, the antenna of the microwave oven emits approximately 6.01 x 10²⁶ photons per second.

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