I need help on This question please read it and give Me The answer

Answer:

32

Step-by-step explanation:

1 = 2

2 = 4

3 = 8

4 = 16

5 = 32

Answer:

4 to the fifth power

Step-by-step explanation:

I think u just to find what is the same as 2 and or equivalent to 2 to the fifth power

The entire interval over which the function, f(x), is positive is from (-2, 1), according to the provided table of function values.

You are asking for the interval over which the function f(x) is positive based on the provided table of values.

A function is positive when its value, represented as f(x), is greater than 0. Looking at the table, f(x) is positive when x is in between -2 and 1. Therefore, the interval over which the function, f(x), is positive is from (-2, 1).

This can be confirmed visually if you were to plot the x-values with their corresponding f(x) values and look for the section of the graph where the curve is above the x-axis (y>0).

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x<-4

x≥-7

-4≤5

i dont think the last one is right

Answer:

1,600,000

Step-by-step explanation:

120,000,000 divided by 75 is 1,600,000

Answer:

did the math its 90,000,000

thats how much 75% is

Step-by-step explanation:

Answer: $49.5

Step-by-step explanation: If each song costs 0.99 cents then you multiply the number of songs you are buying by the cost. So that would be 0.99×50=49.5

Answer:

A ≈ 69.5°

Step-by-step explanation:

Given the triangle is right use the cosine ratio to find A

cosA = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{2.7}{7.7}[/tex], thus

A = [tex]cos^{-1}[/tex] ( [tex]\frac{2.7}{7.7}[/tex] ) ≈ 69.5° ( to 1 dec. place )

Answer:

0; 10; 20

Step-by-step explanation:

x is the independent variable

y is the dependent variable

y is dependent on x

a) For what value of the independent variable will the value of the function be equal to −6

y=0.3x−6

-6 = 0.3x-6

0=0.3x

x = 0

Therefore, if the independent variable is 0, the value of the function will be -6.

b) For what value of the independent variable will the value of the function be equal to −3

y=0.3x−6

-3 = 0.3x-6

0.3x = -3+6

0.3x = 3

x = 3/0.3

x = 10

Therefore, if the independent variable is 10, the value of the function will be -3.

c) For what value of the independent variable will the value of the function be equal to 0.

y=0.3x−6

0=0.3x-6

6 = 0.3x

x = 6/0.3

x = 20

Therefore, if the independent variable is 20, the value of the function will be 0.

Answer:

b=3in

Step-by-step explanation:

SO first of all, the formula for area is lxw (length x width)

And our question tells us that

l x w=24in^2

4 x w = 24 (question tells us that length is 4 inches as listed on side)

4 x (b+3) = 24 (b+3 is the total width of the postcard)

4b + 12 =24 (multiply by 4 inside the bracket)

4b=12 (subtract 12 from both sides)

b=3 (solve for b by dividing by 4)

Answer: 8.5 (rounded)

Step-by-step explanation:

a squared + b squared = c squared

3 squared= 9

8 squared= 64

64+9=73

the square root of 73 is 8.5 (rounded)

Answer:

[tex]37[/tex]  [tex]crackers[/tex]

Step-by-step explanation:

Tins (or Tina)  ate 8 crackers for a snack  each day on school , then on Friday, she drops three and only eats 5.

Meaning that for 4 days, she ate 8 crackers not including Friday.

So meaning we have to multiply how many crackers she ate for those 4 days in total:

[tex]8 * 4[/tex]

[tex]==> 32[/tex]

Then on Friday, she only ate 5, so we add 5 for how many crackers she ate into how many we have right now:

[tex]32 + 5[/tex]

[tex]==> 37[/tex]

To find out how many crackers Tins ate on Friday, you can subtract the number of dropped crackers from the total number she normally eats.

In this question, the subject is mathematics and the grade level is middle school. The question asks about a student named Tins who eats 8 crackers for a snack each day at school. On Friday, she drops 3 crackers and only eats 5. To find out how many crackers she ate on Friday, we can subtract the number of dropped crackers from the total number she normally eats.

Number of crackers normally eaten: 8

Number of crackers dropped on Friday: 3

Number of crackers eaten on Friday: 8 - 3 = 5 crackers

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Answer:

6 x 5 - 25 = 30 - 25 = 5

Answer : 5

Step-by-step explanation:

5² = 5 x 5 = 25

Answer:

When both integers have the same value, the difference is zero. The difference between a positive and a negative integer can be positive or negative. When you subtract a negative integer from a positive integer, the difference is always positive this might help

Step-by-step explanation:

Write a subtraction problem involving two positive integers with a negative difference.

1) When you subtract a positive integer from a negative integer, the difference is always negative.

For example : [tex]-7 - 3 = -10[/tex]

2) When you subtract a larger positive integer from a smaller integer, the difference is always negative.

For example : [tex]5-7=-2[/tex]

3) When you subtract two negative integers and the first integer (or minuend) is smaller than the second integer (or subtrahend), the difference is negative.

For example : [tex]-8 - (-2) = -6[/tex]

4: Geraldine wanted custom keychains. The store she went to has a service fee of 5 dollars, then 8 dollars per key chain. Geraldine payed 37 dollars. How many key chains did she buy?

(She bought 4 keychains)

As for b, I need to see question 3 in order to answer

are they asking to graph or just answer it?

Answer:

you can't get an answer from that question unless they are asking you to graph it or something else

Answer: 1 1/3

Step-by-step explanation:

-4 + 5 = 1

-1/3 + 2/3 = 1/3

OR

Turn them both into mixed numbers: -13/3 + 17/3

-13/3 + 17/3 = 4/3 = 1 1/3

well, let's say the original price is "x", and thus is also the 100% price of the item, however the item is discounted by 16.5%, well 100% - 16.5% = 83.5%, so then the discounted price is really the 83.5% of the item, and we know that is $1135.60.

now, if 1135.60 is 83.5%, what is the 100% or namely "x"?

[tex]\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 1135.60&83.5\\ x&100 \end{array}\implies \cfrac{1135.60}{x}=\cfrac{83.5}{100}\implies 113560 = 83.5x \\\\\\ \cfrac{113560}{83.5}=x\implies 1360 = x[/tex]

The original price of the swimming  pool $1,360.

Original pool price=x

Percent discount=16.5% or 0.165

Sale price=$1135.60

Hence:

x-0.165(x)=$1135.60

x(1-0.165)=$1135.60

0.835x=$1135.60

Divide both side by 0.835x

x=$1135.60/0.835

x=$1,360

Inconclusion the original price of the swimming  pool $1,360.

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Answer: 751.62

Step-by-step explanation: 3 is lower than 5 so you have to round it to zero

751.623 rounded to the nearest hundredth is 751.62

To round the number 751.623 to the nearest hundredth, follow these steps:

Therefore, 751.623 rounded to the nearest hundredth is 751.62

Answer:

C. 3; rotation about the origin, translation, dilation

Step-by-step explanation:

The first obvious step is to rotate it 270° counterclockwise [90° clockwise], next you translate it, then you dilate [long and wide].

I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.

C

Step-by-step explanation:

Hey!

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Straight-Time Pay - someone works the minimum and gets paid for working those hours. This person doesn't work any overtime hours.

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Solution:

8.75 * 20 = 175

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Answer:

Jason's straight-time pay for the week is $175!

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Hope This Helped! Good Luck!

Answer:

Jason’s straight-time pay for the week is $175.

Step-by-step explanation:

Given : Jason Ayers works as a lifeguard earning $8.75 an hour for 20 hours per week.

To find : What is Jason’s straight-time pay for the week?

Solution :

Jason Ayers works as a lifeguard earning in an hour = $8.75

In a week Jason Ayers works for 20 hours.

i.e. Jason Ayers works as a lifeguard earning in 20 hour =[tex]\$8.75\times 20[/tex]

Jason Ayers works as a lifeguard earning in 20 hour = $175

Therefore, Jason’s straight-time pay for the week is $175.

Answer:

low interest rate on a car loan

Answer:

B. low interest rate on a car loan

Answer:

The sum of 3 + (-2) = 1 because it's just like 3 - 2

The sum of -6 + 3 = - 3 because the negative number is greater than positive number it's a negative.

For B you fill in Six negative, -6; three positive, 3. And you are left with three negative counters.

For A you are left with one positve counters.

Answer:

[tex]\frac{3}{5}[/tex] + [tex]\frac{4}{5}[/tex] = [tex]\frac{7}{5}[/tex]

Step-by-step explanation:

Since 3/5 & 4/5 are both over 5 we can add the numbers on the top (numerators) normally while keeping the bottom number (denominator) the same.

[tex]\frac{3}{5}[/tex] + [tex]\frac{4}{5}[/tex] = [tex]\frac{7}{5}[/tex]

[tex]Hey~freckledspots!\\----------------------[/tex]

[tex]We~will~solve~for~i^{425}![/tex]

[tex]Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\[/tex]

[tex]Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------[/tex]

[tex]Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------[/tex]

[tex]Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------[/tex]

[tex]Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------[/tex]

[tex]Answer:\\\large\boxed{-1+i}\\----------------------[/tex]

[tex]Hope~This~Helped!~Good~Luck![/tex]

Answer:

[tex]i - 1[/tex]

Step-by-step explanation:

Complex Number System Rules

[tex]\sqrt{-1} = i \\ -1 = {i}^{2} \\ -i = {i}^{3} \\ 1 = {i}^{4} [Every \: multiple \: of \: four][/tex]

The Divisibilty Rule of 4 states that the last two digits of a number must be a multiple of four, so you will have this:

[tex]{i}^{425} + {i}^{14} + {i}^{-14} + {i}^{44} \\ \\ i - 1 - 1 + 1 = i - 1[/tex]

I am joyous to assist you anytime.

Answer:

p=2

Step-by-step explanation:

−4p=11−19

−4p=−8

then you divide both sides by -4 and two negatives make a positive.

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Answer:

850 for student and 850 for students

Step-by-step explanation:

Let student tickets sold be=x

and adult tickets sold=y

They sold 5 times as many student tickets as adult tickets.

i.e. x=5y

The student tickets cost $2.00 each and

the adult tickets cost $4 each.

They made $140.

i.e. 2x + 4y = 140

Dividing both sides by 6, we get

x + 2y = 70

or 5y + 2y= 70

i.e. 7y=70

i.e. y=10

x= 5y

⇒ x = 50

Hence, Student tickets sold= 50

and Adult tickets sold= 10

Answer:

[tex]\overline{QP} = \overline{SR}[/tex]

Step-by-step explanation:

Given: ∠PTQ ≅ ∠STR and TP, TQ, TR and TS are radii of the circle.

If  two angle are equal, then they are equal in size and their measurements are equal.

IF ∠PTQ ≅ ∠STR then they are also equal in their measurements.

Now, In ΔPTQ and ΔSTR

∠PTQ ≅ ∠STR  (vertically opposite angle)

[tex]\overline{TQ} \cong \overline{ST}[/tex]  (Radius of the circle are equal and congruent in length)

[tex]\overline{PT} \cong \overline{TR}[/tex]  (Radius of the circle)

∴ ΔPTQ ≅ ΔSTR (SAS postulate)

∴ [tex]\overline{QP}\cong \overline{SR}[/tex] (corresponding sides of congruent triangle are equal  and congruent).

You can use the fact that a closed figure made by connecting the adjacent end points of two equal and intersecting line segment is a rectangle.

Option A:  [tex]\overline{QP} \: \rm and \: \overline{SR}\\[/tex]correct choice since the line segment QP is and line segment SR are congruent.

Given that:

Since angle  PTQ and angle STR are congruent, thus we have:

PR and SQ as straight intersecting lines.

Due to angle PTS and angle QTR are opposite angles made by intersecting lines, we have them as congruent or say of equal measurement.

[tex]\angle PTS \cong \angle QTR[/tex]

Since [tex]\overline{TP} = \overline{TQ} = \overline{TR} = \overline{TS}[/tex], thus we have got:

[tex]\overline{PR} = \overline{SQ}[/tex] in measurement ( as PR is sum of PT and TR and same for SQ)

"A closed figure made by connecting the adjacent end points of two equal and intersecting line segment is a rectangle", we have PQRS as a rectangle.

As a rectangle have opposite sides parallel and equal, we have got:

[tex]\overline{PQ} \cong \overline{SR}[/tex]

Thus, Option A: [tex]\overline{QP} \: \rm and \: \overline{SR}\\[/tex] is the correct choice since the line segment QP is and line segment SR are congruent.

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Answer: this is for the whole gizmo

1. C

2. B

3. D

4. A

5. D

Step-by-step explanation:I hope this can help everybody.

Answer:

2* (4x + 1)

Step-by-step explanation:

8x = 2 * 2 *2 * x

2 = 2* 1

GCF = 2

8x+2  =  2*2*2*x + 2*1 = 2* (4x + 1)