I WILL MARK BRAINLIEST How could this sentence be re-written to convey the active voice?
The landscape was carefully painted by the artist.
A) The landscape was painted.
B) The landscape was painted by the artist.
C) The artist carefully painted the landscape.
D) The beautiful landscape was carefully painted by the talented artist.

The answers a (apex)

The volume of the 3.00 M KI stock solution needed to prepare 0.195 L of a 1.25 M KI solution is 81.25 mL.

The student is asking how to calculate the volume of a stock solution needed to make a diluted solution of a different concentration. The problem can be solved using the dilution equation C1V1 = C2V2, where C1 and V1 are the concentration and volume of the stock solution, respectively, and C2 and V2 are the concentration and volume of the diluted solution, respectively. For this particular question:

C1 = 3.00 M (stock solution concentration)

V2 = 0.195 L (volume of the desired diluted solution)

C2 = 1.25 M (desired concentration of the diluted solution)

To find V1, the volume of the stock solution, we rearrange the equation to:

V1 = (C2 * V2) / C1

V1 = (1.25 M * 0.195 L) / 3.00 M

V1 = (0.24375) / 3.00

V1 = 0.08125 L or 81.25 mL

Answer:

_+_

Explanation:

Answer:C

Explanation:

The solution follows as;

Given:

CuSO4 – 9.70 (weight)

Water / H2O – 12.98 – 9.70 = 3.28 (weight)

Molecular weight of CuSO4 – 160

Molecular weight of H2O – 18

To solve;

= weight of CuSO4 x MW of CuSO4

= 970 / 160

= 328/x*18

= 6x = 18

= x – 3

= CuSO4*3H2O

Charcoal is black because it absorbs all the wavelengths of light, not reflecting any back to the eye. This is due to its porous structure and numerous carbon atoms.

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This means that you need to add 1 gallon of water to 1 gallon of pure antifreeze to obtain a solution that is 75% antifreeze. To obtain a solution that is 75% antifreeze, you need to add 1 gallon of water to 1 gallon of pure antifreeze.

To obtain a solution that is 75% antifreeze, you need to determine how much water should be added to 1 gallon of pure antifreeze.

Let's assume that the final volume of the solution, after adding water, remains at 1 gallon.

The amount of antifreeze in the solution can be calculated using the equation:

Amount of antifreeze = Volume of antifreeze / Total volume of solution

Since the volume of the antifreeze is 1 gallon (given) and the total volume of the solution is also 1 gallon (assuming), we can calculate:

Amount of antifreeze = 1 gallon / 1 gallon = 1

This means that you need to add 1 gallon of water to 1 gallon of pure antifreeze to obtain a solution that is 75% antifreeze.

Answer:

Na+

Explanation:

Atoms may loose or gain electrons in order to attain octate.

Chemical species obtained after loosing or gaining electrons are called ions.

When an element losses electrons, positively charged ion is formed.

When an element gains electrons, negatively charged ion is formed.

Among the given, only Na+ carry a positive charge, rest are neutral.

Therefore, Na+ is an ion.

Final answer:

The net ionic equation for the reaction between solid chromium(III) hydroxide and nitrous acid is Cr(OH)3(s) + 3 H+(aq) → Cr3+(aq) + 3 H2O(l), after removing the spectator nitrate ions.

Explanation:

The question involves writing a net ionic equation for the reaction between solid chromium(III) hydroxide and nitrous acid. To start, write down the full balanced molecular equation:

Cr(OH)3(s) + 3 HNO2(aq) → Cr(NO3)3(aq) + 3 H2O(l)

Now write the full ionic equation:

Cr(OH)3(s) + 3 H+(aq) + 3 NO2⁻(aq) → Cr3+(aq) + 3 NO2⁻(aq) + 3 H2O(l)

Notice that the nitrate ions (NO2⁻) are present on both sides of the equation and thus are spectator ions. Removing the spectator ions gives us the net ionic equation:

Cr(OH)3(s) + 3 H+ (aq) → Cr3+ (aq) + 3 H2O(l)

It's important to verify that both sides of the equation are balanced with respect to both charge and mass. The equation above satisfies this requirement, with three positive charges on both sides and the same number of each type of atom on each side.

Final answer:

The net ionic equation for the reaction of solid chromium (iii) hydroxide with nitrous acid is Cr(OH)₃(s) + 3 HNO₂(aq) → Cr₃+(aq) + 3 NO₂−(aq) + 3 H₂O(l).

Explanation:

The net ionic equation for the reaction of solid chromium (iii) hydroxide with nitrous acid is:

Cr(OH)₃(s) + 3 HNO₂(aq) → Cr₃+(aq) + 3 NO₂−(aq) + 3 H₂O(l)

First, solid chromium (iii) hydroxide reacts with nitrous acid to form chromium ions, nitrite ions, and water.

In this reaction, the hydroxide ions combine with the hydrogen ions from the acid to produce water, and chromium (iii) hydroxide dissolves to leave behind chromium ions in solution.

Since chromium (iii) hydroxide is a weak base and does not dissociate into ions in its solid state, it is included as a whole compound in the net ionic equation. The nitrite ions and chromium ions remain in solution, indicating a chemical change has occurred.

Answer: C) 154 g

I did the assignment already, it's correct.

Answer:

Metals are malleable due to the layers of atoms which can move over each other. Ionic crystals are made of rigid lattice structures

Explanation:

The molecular structure of metals consists of metallic ions in a sea of de-localized electrons. The ions are closely packed in a regular arrangement. The layers of ions are held together due to the electrostatic forces between the ions and electrons. The layers of ions are not bonded to each other directly, which allows them to move when force is applied. This is why metals are malleable

Ionic crystals are strongly bonded lattice structures with oppositely charged ions strongly attracted to each other. As the ions are bonded directly to each other, the application of a force has the potential to break existing bonds, making the structure brittle.

Yes, you can dissolve 0.35 moles of Potassium Permanganate (KMnO4) into 500 mL of water.

To answer whether you can dissolve 0.35 moles of Potassium Permanganate (KMnO4) into 500 mL of water, we need to consider the solubility of the compound. Potassium Permanganate is highly soluble in water, with a solubility of about 7 g per 100 mL of water at room temperature. The molar mass of KMnO4 is 158.034 g/mol, so 0.35 moles would weigh 55.3119 g. Since you have 500 mL of water, which is about 500 g, you can dissolve 55.3119 g of KMnO4 into it.

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The number of atoms of any element in the given chemical formula is the number that is written on the food of the symbol of that element. The total number of atoms of oxygen in given molecule is 9.033  ×10²³.

Atom is the smallest particle of any matter. Atom combines to form element and element combine to form molecule or compound. Atom can be further divided into electron, protons and neutrons.

1 molecule of given molecule contain 5 atoms of oxygen

Molar mass of N₂O₅= 108.01 g/mol

given mass of  N₂O₅=32.4 g

Number of moles of N₂O₅= given mass÷molar mass =0.3mol

Number of atoms= 0.3 ×6.022×10²³

Number of atoms=1.8066 ×10²³

total number of atoms=5×1.8066 ×10²³

                                    =9.033  ×10²³atoms of oxygen

Thus the total number of atoms of oxygen in given molecule is 9.033  ×10²³.

Learn more about atoms, here:

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Final answer:

approximately 9.033 x 10^23 oxygen atoms.

Explanation:

Calculating the Number of Oxygen Atoms in 32.4 g of N2O5

To determine the number of oxygen atoms in 32.4 g of N2O5, we first need to understand the concept of moles and how it relates to the mass of a substance. N2O5 has a molecular mass of 108.02 amu. This means one mole of N2O5 weighs 108.02 grams and contains Avogadro's number of molecules. Using the equation for calculating moles, where n is the number of moles, m is the mass of the substance in grams, and M is the molar mass of the substance in g/mol, the formula is:

n = m / M

Substituting the given values:

n = 32.4 g / 108.02 g/mol ≈ 0.3 moles of N2O5

Since each molecule of N2O5 contains 5 oxygen atoms, we multiply the number of moles of N2O5 by 5 and then by Avogadro's number (6.022 x 1023) to get the total number of oxygen atoms:

Total oxygen atoms = 0.3 moles x 5 x 6.022 x 1023 ≈ 9.033 x 1023 oxygen atoms

Final answer:

To calculate the number of moles of a gas sample in a 5.0 L container at 373 K and 203 kPa, one uses the Ideal Gas Law. By substituting the appropriate values into the equation and solving for 'n', the calculation yields approximately 0.328 moles of the gas under the specified conditions.

Explanation:

The question asks how many moles of a gas sample are in a 5.0 L container at 373 K and 203 kPa. To find the number of moles of gas, we use the Ideal Gas Law, which is PV = nRT. In this formula, P is the pressure (in kPa), V is the volume (in liters), n is the number of moles, R is the ideal gas constant (8.314 J/(mol·K) or 8.314 L·kPa/(mol·K)), and T is the temperature (in Kelvin).

First, we convert the pressure into kPa since R is given in L·kPa/(mol·K). The pressure is already in kPa. Then, we solve for 'n' (number of moles):

P = 203 kPa

V = 5.0 L

R = 8.314 L·kPa/(mol·K)

T = 373 K

Using the Ideal Gas Law:

n = PV / RT = (203 kPa × 5.0 L) / (8.314 L·kPa/(mol·K) × 373 K)

n = ​1015 / ​3093.402 = ​0.328 mol

Thus, under the given conditions, the 5.0 L container holds approximately 0.328 moles of the gas sample.

To calculate the number of moles of H2O formed, determine the moles of CH3OH involved in the reaction, convert the volume of CH3OH to mass using its density, convert the mass of CH3OH to moles using its molar mass, and use the balanced chemical equation to determine the stoichiometry between CH3OH and H2O.

To calculate the number of moles of H2O formed, we first need to determine the number of moles of CH3OH and O2 involved in the reaction.

1. Convert the volume of CH3OH to mass using its density:

Mass of CH3OH = Volume of CH3OH x Density = 50.0 mL x 0.850 g/mL = 42.5 g

2. Convert the mass of CH3OH to moles using its molar mass:

Moles of CH3OH = Mass of CH3OH / Molar mass of CH3OH = 42.5 g / 32.04 g/mol = 1.327 mol

3. Use the balanced chemical equation to determine the stoichiometry between CH3OH and H2O:

1 mol of CH3OH produces 2 mol of H2O

Therefore, 1.327 mol of CH3OH will produce 2 x 1.327 = 2.654 mol of H2O

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Answer: Potential energy of products is less than the potential energy of the reactants.

Explanation:

Exothermic reactions are defined as the reactions which releases heat. The release in heat is due to the difference in the potential energy of the reactants and the products.

For these reactions, the potential energy of the products is less than the potential energy of the reactants. Total enthalpy change of the reaction is given by the equation:

[tex]\Delta H_{rxn}=\sum H_{products}-\sum H_{reactants}[/tex]

For exothermic reaction, [tex]\Delta H_{rxn}[/tex] is negative.

For the reaction of baking soda and vinegar, the equation follows:

[tex]NaHCO_3+CH_3COOH\rightarrow CH_3COONa+CO_2+H_2O+\text{ energy}[/tex]

As, the energy is written at the product side, this means that the reaction between baking soda an=d vinegar is an exothermic reaction.

The radon is the decay byproduct of radium which emits alpha rays to convert into the lead or polonium. The alpha particles have less penetration inside the cell than the beta particle or gamma rays and have the more dangerous effect than these other days. In the environment, the high presence of radon enters into the lungs through breathing and start to decay. In their decay, it emits alpha rays, which acts as the carcinogenic agent in the body.

Answer : The molarity of the solution is, 0.4028 mole/L

Explanation : Given,

Mass of [tex]Ca(OH)_2[/tex] = 31.3 g

Molar mass of [tex]Ca(OH)_2[/tex] = 74 g/mole

Volume of solution = 1050 ml

Molarity : It is defined as the moles of solute present in one liter of solution.

Formula used :

[tex]Molarity=\frac{\text{Mass of }Ca(OH)_2\times 1000}{\text{Molar mass of }Ca(OH)_2\times \text{volume of solution in ml}}[/tex]

Now put all the given values in this formula, we get:

[tex]Molarity=\frac{31.3g\times 1000}{74g/mole\times 1050ml}=0.4028mole/L[/tex]

Therefore, the molarity of the solution is, 0.4028 mole/L

To calculate the initial velocity of a rock thrown 1.8 meters in the air, we use the vertical motion equation, resulting in an initial velocity of approximately 5.94 m/s.

To find out how fast a rock was thrown 1.8 meters in the air, we can use the physics of projectile motion and the equations of motion under the influence of gravity. Given that the height reached by the rock is 1.8 meters, we can use the equation for vertical motion:

h = vi2 / (2g),

where h is the maximum height (1.8 meters), vi is the initial velocity we want to calculate, and g is the acceleration due to gravity (9.8 m/s2). Rearranging the formula to solve for the initial velocity gives us:

vi = sqrt(2gh).

Plugging in the values, we get:

vi = sqrt(2 * 9.8 m/s2 * 1.8 m) = sqrt(35.28) ≈ 5.94 m/s.

Thus, the rock was thrown upwards with an initial velocity of approximately 5.94 m/s.

Using the kinematic equation v^2 = u^2 + 2as, the initial velocity (u) at which the rock was thrown into the air is found to be approximately 5.94 m/s.

To calculate the initial velocity at which a rock is thrown into the air, we can use the kinematic equations for projectile motion. Since air resistance is negligible, we'll apply the equation for an object under uniform acceleration due to gravity.

The equation we use is v^2 = u^2 + 2as, where:

Rearranging the equation to solve for the initial velocity (u), we get:

u = √(v^2 - 2as)

Plugging in the known values:

u = √(0^2 - 2*(-9.8 m/s^2)*(1.8 m))

u = √(0 + 35.28)

u = √35.28

u = 5.94 m/s

The rock was thrown with an initial velocity of approximately 5.94 m/s.