Identify the three ingredients used in a blast furnace to make pig iron.

No K₂Cr₂O₇ will crystallize out of the solution during cooling.

Crystallization is a separation technique used to purify a solid substance by selectively dissolving it in a suitable solvent at a high temperature and then cooling the solution to obtain pure crystals of the solute.

Given:

The solubility of K₂Cr₂O₇ in water at 60°C is 127 g/100 mL, and at 20°C is 13.9 g/100 mL.

Dissolved 100 g of  K₂Cr₂O₇ in 200 g of water, which is 200 mL of water.

At 60°C, the solution can dissolve 127 g/100 mL × 2 L

= 254 g of  K₂Cr₂O₇.

100 g of  K₂Cr₂O₇, the solution is saturated and no more of the salt can dissolve.

When the solution is cooled to 20°C, the solubility of K₂Cr₂O₇ is only 13.9 g/100 mL.

The amount of water in the solution at 20°C is 200 mL. The maximum amount of K₂Cr₂O₇ that can remain in solution at this temperature is:

13.9 g/100 mL × 2 L = 278 g

Dissolved 100 g of K₂Cr₂O₇ in the solution, the amount that will crystallize out is:

100 g - 278 g = -178 g

This result is negative, indicating that all the K₂Cr₂O₇ will remain in solution at 20°C.

Therefore, no K₂Cr₂O₇ will crystallize out of the solution during cooling.

To learn more about the crystallization, follow the link:

https://brainly.com/question/13008800

#SPJ2

Answer:

D.Conducting electricity and heat

Explanation:

Metal : It is defined as that substance which is good conductor of electricity and heat. Metal have  ductile and malleable property.In metal, atoms are held together by metallic bonds .The valence electrons from s and p orbital are delocalised and they form sea of electrons that surround the positively charged nuclei of the interacting metal ion.Then , the electrons are freely move throughout the space between atomic nuclei.

Due to availability of free  electrons, metal conduct electricity and heat.

Therefore, the electron sea is responsible for conducting electricity and heat .

To determine the molar solubility of chromium(III) fluoride, we need to use the solubility product constant (Ksp) of 6.6 × 10⁻¹¹. The molar solubility of chromium(III) fluoride is 8.184 × 10⁻⁴M.

To determine the molar solubility of chromium(III) fluoride, we need to use the solubility product constant (Ksp) of 6.6 × 10⁻¹¹ for chromium(III) fluoride. The Ksp expression is Ksp = [Cr³⁺][F⁻]³.

Let's assume the molar solubility of chromium(III) fluoride is x M. Since the stoichiometry of the balanced equation for its dissolution is 1:3 (one chromium ion per three fluoride ions), the equilibrium expression becomes Ksp = x(3x)³.

Now, we can set up the expression and calculate the molar solubility by solving the equation: Ksp = 108x⁴ = 6.6 × 10⁻¹¹. Solving for x gives x = 8.184 × 10⁻⁴ M. Therefore, the molar solubility of chromium(III) fluoride is 8.184 × 10⁻⁴ M.

The standard Gibbs free energy of formation of NH3(g) at 298 K is approximately -16.5 kJ/mol.

The standard Gibbs free energy of formation (ΔG°f) for ammonia (NH3(g)) at 298 K is approximately -16.5 kJ/mol. The standard Gibbs free energy of formation for a substance is the change in Gibbs free energy when one mole of the substance is formed from its elements in their standard states. The standard state for nitrogen gas (N2) is N2(g) at 1 bar pressure, and for hydrogen gas (H2) it is H2(g) at 1 bar pressure.

please note that the given value of -16.5 kJ/mol is an approximation, and it is recommended to refer to the latest thermodynamic data sources for the most accurate and up-to-date information.

Answer: The energy drawn by electric hair dryer is 2,98,800 J

Explanation:

To calculate the power of the electric hair dryer, we use the equation:

[tex]P=I\times V[/tex]

where,

P = power of electric hair dryer

I = Current of electric hair dryer = 8.3 A

V = voltage of electric hair dryer = 120 V

Putting values in above equation, we get:

[tex]P=8.3\times 120=996W[/tex]

To calculate the energy of electric hair dryer, we use the equation:

[tex]E=P\times t[/tex]

where,

E = energy of electric hair dryer = ?

P = Power of electric hair dryer = 996 W

t = time taken = 5.0 min = 300 s     (Conversion factor:  1 min = 60 sec)

Putting values in above equation, we get:

[tex]E=996\times 300=2,98,800J[/tex]

Hence, the energy drawn by electric hair dryer is 2,98,800 J

To calculate the standard electrode potential (E°) for a cell composed of Sr/Sr²⁺ and Mg/Mg²⁺ half-cells, use the Nernst equation with the given equilibrium constant value. The resulting E° is approximately 1.038 V.

To find the standard electrode potential (E°) for the cell, we can use the Nernst equation and the relationship between the equilibrium constant (Keq) and the standard electrode potential:

Nernst equation:

E° = (RT / nF) * ln(Keq)

Where:

Plugging in the values, we get:

E° = (8.314 * 298 / (2 * 96485)) * ln(3.69 × 1017)

Simplify the constants:

E° = (0.0257 V) * ln(3.69 × 1017)

Evaluating the natural logarithm:

E° = 0.0257 * 40.38

E° ≈ 1.038 V

Therefore, the standard electrode potential (E°) for the cell is approximately 1.038 V.

Answer : The freezing point of a solution is, [tex]0.32^oC[/tex]

Explanation :

First we have to calculate the Van't Hoff factor (i) for [tex]NaNO_3[/tex].

The dissociation of [tex]NaNO_3[/tex] will be,

[tex]NaNO_3\rightarrow Na^++NO_3^-[/tex]

So, Van't Hoff factor = Number of solute particles = [tex]Na^++NO_3^-[/tex] = 1 + 1 = 2

Now we have to calculate the freezing point of a solution.

Formula used for lowering in freezing point :

[tex]\Delta T_f=i\times k_f\times m[/tex]

or,

[tex]T_f^o-T_f=i\times k_f\times m[/tex]

where,

[tex]\Delta T_f[/tex] = change in freezing point

[tex]T_f[/tex] = temperature of solution = ?

[tex]T^o_f[/tex] = temperature of pure water = [tex]0^oC[/tex]

[tex]k_f[/tex] = freezing point constant  = [tex]1.86^oC/m[/tex]

m = molality  = 0.08500 m

i = Van't Hoff factor = 2

Now put all the given values in this formula, we get the freezing point of a solution.

[tex]0^oC-T_f=2\times (1.86^oC/m)\times 0.08500m[/tex]

[tex]T_f=0.32^oC[/tex]

Therefore, the freezing point of a solution is, [tex]0.32^oC[/tex]

The ground-state electron configuration for cobalt (Z = 27) is [Ar] 3d7 4s2.

The ground-state electron configuration for the element cobalt (Co), which has an atomic number (Z) of 27, is as follows:

Co: [Ar] 3d74s2

This configuration indicates that cobalt has 2 electrons in the outermost 4s subshell and 7 electrons in the 3d subshell after the [Ar] noble gas core.

The ground-state electron configuration for the element cobalt (Z = 27) is 1s²2s²2p⁶3s²3p⁶4s²3d⁷. Co has 27 protons, 27 electrons, and 33 neutrons. The electron configuration represents the distribution of electrons in the energy levels and orbitals of an atom.

Answer : The correct answer for amount of radioisotope remain in 2030 is 0.619 g .

Radioactive Decay is emission of radiations ( in form of alpha , beta particle etc ) by unstable atom .

Radioactive decay is FIRST ORDER reaction . So , the equation of first order can be used to find decay constant , amount of radioisotopes or half life .

The equation for radioactive decay is given as :

[tex] ln (\frac{N}{N_0}) = -k * t [/tex]

Where : N = amount of radioisotope at time t

N₀ = amount of radioisotope initially present

k = decay constant t = time

Half life :

It is time when amount of radioisotope decrease to 50 % of its original amount . Half life [tex] (T_\frac{1}{2} ) [/tex] and decay constant can be related :

[tex] T_\frac{1}{2} = \frac{ln 2 }{k} = \frac{0.693}{k} [/tex]

Following are the steps can be used to determine amount of radioisotope (N) :

1) To find decay constant :

Given : [tex] (T_\frac{1}{2} ) [/tex] = 28 yrs

Decay constant can be calculated using half life by plugging value in half life formula :

[tex] 28 yrs = \frac{0.693}{k} [/tex]

On multiplying both side by k

[tex] 28 yrs * k= \frac{0.693}{k} *k [/tex]

On dividing both side by 28 yrs

[tex] \frac{28 yrs * k}{28 yrs} = \frac{0.693}{28 yrs} [/tex]

k = 0.02475 yrs⁻¹

2) To find amount of radioisotope (N):

Given : Amount of radioisotope originally present = 3.5 g

Time = 2030 - 1960 = 70 yrs

decay constant = 0.02475 yrs⁻¹

Amount of radioisotope (N) = ?

Plugging these values in the formula as:

[tex] ln (\frac{N}{3.5 } ) = - 0.02475 yrs^-^1 * 70 yrs [/tex]

[tex] ln (\frac{N}{3.5 } ) = - 1.7325 [/tex]

[tex] ln\frac{N}{No} [/tex] can be converted using the formula ( [tex] ln (\frac{a}{b} ) = ln a - ln b [/tex] )

ln N - ln (3.5 ) = - 1.7325

(ln 3.5 = 1.253 )

ln N -1.253 = -1.7325

Adding both side 1.253

ln N -1.253 + 1.253 = -1.7325 + 1.253

ln N = -0.4795

Taking anti ln of -0.4795

N = 0.619 g

Hence amount of radioisotope remained in 2030 is 0.619 g

A sound is first produced by making something vibrates and then the sound travels through a medium and reach our ears.

The ear is responsible for hearing sounds as well as for balance in the human body. The ear has three parts i.e. the outer, middle and inner ears. We hear the sound when the body starts vibration.

So we can conclude that a sound is first produced by making something vibrates and then the sound travels through a medium and reach our ears.

Learn more about sound here: https://brainly.com/question/1199084

the number of atoms bonded to the central atom is 4

Explanation:

Answer:

150.0 is the final volume

next question is a

and the next is 0.125 M

Explanation:

got it right in edge in 2020

To calculate the new concentration of NaCl solution after dilution, the final volume of the solution is determined to be 150.0 mL by adding the initial volume and the volume of water added. Using the molarity equation, the new concentration is found to be 0.125 M.

To find the new concentration of the NaCl solution after dilution, we use the concept of molarity and the principle of conservation of mass. The amount of solute (NaCl in this case) stays the same, but the volume increases when more solvent (water) is added.

The initial molarity (Mi) of the NaCl solution is 0.150 M and the initial volume (Vi) is 125.0 mL. The volume of water added is 25.0 mL.

The final volume (Vf) is the sum of the initial volume and the volume of water added:

Vf = Vi + volume of water added

Vf = 125.0 mL + 25.0 mL

Vf = 150.0 mL

The new concentration Cf can be calculated using the formula:

Ci × Vi = Cf × Vf

(0.150 M) × (125.0 mL) = Cf × (150.0 mL)

Cf = (0.150 M × 125.0 mL) / 150.0 mL

Cf = 0.125 M

The final volume of the solution is 150.0 mL.

Answer:

The molecules get closer together and move more slowly.

Explanation:

from a gas to a liquid, the atoms or molecules of the substance do not change. Instead, the motion of the atoms or molecules in the substance determines its state of matter.

gas condenses to form a liquid, the molecules get closer together and move more slowly. If the molecules continue to slow down until they move so slowly that they can only vibrate against one another, then the substance becomes a solid.

The average translational kinetic energy of helium s equal to that of oxygen at [tex]\boxed{300\;{\text{K}}}[/tex] .

Further Explanation:

One of the states of matter is gas. In gases, the atoms and molecules have space between them and can easily move over each other hence gases are compressible. Gases neither have fixed shape nor volume. It occupies the shape and volume of the container. The examples of matter that are gases are nitrogen and carbon dioxide.

The kinetic theory is based on the following postulates:

1. Gas molecules have a large collection of individual particles with empty space between them and the volume of each particle is very small as compared to the volume of the whole gas.

2. The gas particles are in straight-line motion or random motion until they are not collided with the wall of the container or with each other.

3. The collision between the gas particles and the wall of the containers are an elastic collision that means molecules exchange energy but they don’t lose any energy during the collision. So the total kinetic energy is constant.

The formula to calculate the average translational kinetic energy of helium is as follows:

[tex]{{\text{E}}_{{\text{He}}}} = \frac{3}{2}{\text{k}}{{\text{T}}_{{\text{He}}}}[/tex]           …… (1)

Here,

[tex]{{\text{E}}_{{\text{He}}}}[/tex] is the average translational kinetic energy of helium gas.

k is the Boltzmann constant.

[tex]{{\text{T}}_{{\text{He}}}}[/tex]  is the absolute temperature of helium gas.

The formula to calculate the average translational kinetic energy of oxygen is as follows:

[tex]{{\text{E}}_{{{\text{O}}_{\text{2}}}}} = \frac{3}{2}{\text{k}}{{\text{T}}_{{{\text{O}}_{\text{2}}}}}[/tex]                                                                                                …… (2)

Here,

[tex]{{\text{E}}_{{{\text{O}}_{\text{2}}}}}[/tex] is average translational kinetic energy of oxygen gas.

k is the Boltzmann constant.

[tex]{{\text{T}}_{{{\text{O}}_{\text{2}}}}}[/tex]  is absolute temperature of oxygen gas.

Since both gases have same average translational energy. So left-hand side of equation (1) and (2) becomes equal, and therefore right-hand side of both equations can be compared as follows:

[tex]\frac{3}{2}{\text{k}}{{\text{T}}_{{{\text{O}}_2}}} = \frac{3}{2}{\text{k}}{{\text{T}}_{{\text{He}}}}[/tex]                                                                                                       …… (3)

Rearrange equation (3) to calculate  [tex]{{\text{T}}_{{{\text{O}}_{\text{2}}}}}[/tex]  

[tex]{{\text{T}}_{{{\text{O}}_2}}} = {{\text{T}}_{{\text{He}}}}[/tex]                                                        …… (4)

The value of [tex]{{\text{T}}_{{\text{He}}}}[/tex] is 300 K. So according to equation (4),  [tex]{{\text{T}}_{{{\text{O}}_{\text{2}}}}}[/tex] also becomes 300 K.

Learn more:

1. What is the kinetic energy of electrons? https://brainly.com/question/5031462

2. Calculate the frequency of yellow light: https://brainly.com/question/5882803

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: 300 K, helium, oxygen, average translational kinetic energy, k, Boltzmann constant, absolute temperature, gas, kinetic theory, 3/2 kT, same, equal.

When butanal is heated with excess benzaldehyde and sodium hydroxide, the crossed-aldol product formed is 4-phenyl-2-butanol, which is obtained through the aldol condensation reaction.

Crossed-aldol product formation occurs when two different carbonyl compounds, such as aldehydes or ketones, react in an aldol condensation. The products are a mixture of different aldol adducts, resulting from the nucleophilic addition of one carbonyl compound to the other. This reaction allows for the creation of complex molecules with varied functionalities.

When butanal is heated in the presence of excess benzaldehyde and sodium hydroxide, the crossed-aldol product formed is 4-phenyl-2-butanol. The product is obtained by the aldol condensation reaction between butanal and benzaldehyde. In this reaction, a molecule of water is eliminated, and the resulting product contains both the aldehyde and the alcohol functional groups.

https://brainly.com/question/32134011

#SPJ12

Answer:

d

Explanation:

Final answer:

Benzene has six carbon-carbon sigma bonds because each carbon atom forms two sigma bonds with its adjacent carbon atoms. Cyclobutane has four carbon-carbon sigma bonds since it is a four-membered ring with each carbon bonded to two other carbons.

Explanation:

The question asks about the number of carbon-carbon sigma bonds in benzene and cyclobutane. Let's examine each molecule separately.

Benzene (C₆H₆)

In benzene, the carbons form a hexagonal ring and each carbon atom is bonded to two other carbon atoms. The structure of benzene is often depicted with alternating single and double bonds. However, due to resonance, the electrons are delocalized and each carbon-carbon bond is equivalent, resembling a structure with one-and-a-half bonds. Despite the presence of alternating double bonds, each carbon is involved in two sigma bonds with adjacent carbons and one sigma bond with a hydrogen atom, making a total of six carbon-carbon sigma bonds in benzene.

Cyclobutane (C₄H₈)

Cyclobutane is a four-membered ring where each carbon atom is bonded to two other carbons forming single bonds. Thus, for cyclobutane, there are four carbon-carbon sigma bonds, one between each pair of adjacent carbon atoms.

Answer:

Correct answer is X = ΔH

Explanation: