Identifying and Balancing Chemical Equations
Name:
Balance these equations (even if the value is one put it in the blank) :
the type of reaction. (Synthesis, Decomposition, Single Replacement, Double !
Combustion)
Type
1. _HgO + _Hg + _02

Answer:

[tex]\boxed{\text{0.17 mol}}[/tex]

Explanation:

[tex]\text{M$_{r}$ of Na} = 22.99\\\text{Moles} = \text{3.9 g } \times \dfrac{\text{1 mol}}{\text{22.99 g}} = \text{0.17 mol}\\\\\text{ The sample contains $\boxed{\textbf{0.17 mol}}$ of Na}[/tex]

Answer:

Explanation:

Polyatomic ions are ions which consist of more than one atom. For example, nitrate ion, NO3-, contains one nitrogen atom and three oxygen atoms. The atoms in a polyatomic ion are usually covalently bonded to one another, and therefore stay together as a single, charged unit.

To write the formula for a compound with a polyatomic ion, consider that the compound should be electrically neutral. Balance the charges from different ions, treating polyatomic ions as discrete units. For instance, calcium phosphate (Ca3(PO4)2) illustrates this with three calcium ions and two phosphate ions.

When writing the formula for a compound containing a polyatomic ion, you must consider that the compound has to be electrically neutral overall. This often involves balancing the number of positive and negative charges coming from different ions. The polyatomic ions are usually treated as discrete units in the formula.

For example, consider calcium phosphate, which has the formula Ca3(PO4)2. Here, there are three calcium ions (Ca²+), and two phosphate groups (PO4³-). Each PO4³- group comprises one phosphorus atom and four oxygen atoms. The overall compound is electrically neutral because the positive charges from the three calcium ions balance out the negative charges from the two phosphate ions.

Another example can be seen in the ionic compound sodium oxalate, which has the formula Na₂C₂O₄. Here, the polyatomic ion is C₂O₄²-, and the compound has two sodium ions (Na⁺) for each oxalate ion. The formula of this compound is not empirical because it represents the number of atoms in the discrete unit of the oxalate ion.

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Answer:

Concentration = 0.14 M

Explanation:

Given data:

Volume of base = 19.62 mL

Molarity of base = 0.341 M

Volume of acid = 25.00 mL

Molarity of acids = ?

Solution:

Number of moles of base = Molarity × volume in litter

Number of moles = 0.341 mol/L × 0.02 L

Number of moles =  0.007 mol

Concentration of acid:

Concentration = 1/2 (0.007 mol) / 25 mL × 10⁻³ L/mL

Concentration = 0.0035 mol / 25 × 10⁻³ L

Concentration = 1.4  × 10⁻¹ M

Concentration = 0.14 M

Answer:

[tex]\large \boxed{\text{7.94 g/mol}}[/tex]

Explanation:

We can use the Ideal Gas Law to solve this problem

pV = nRT

Data:

p = 0.998 atm

V = 0.153 L

T = 26 °C

m = 0.0494 g

1.  Convert temperature to kelvins

T = (26 + 273.15) K =  299.15 K

2. Calculate the number of moles

[tex]\text{0.998 atm} \times\text{0.153 L} = n \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1}\times \text{299.15 K}\\\\0.1527 = n \times \text{24.55 mol}^{-1}\\\\n = \dfrac{0.1527}{\text{24.55 mol}^{-1}} = 6.220 \times 10^{-3} \text{ mol}[/tex]

3. Calculate the molar mass

[tex]\text{Molar mass} = \dfrac{\text{mass}}{\text{moles}}\\\\M = \dfrac{m}{n}\\\\M = \dfrac{\text{0.0494 g}}{6.220 \times 10^{-3} \text{ mol}}\\\\M = \textbf{7.94 g/mol}\\\text{The molar mass of the gas is } \large \boxed{\textbf{7.94 g/mol}}[/tex]

Answer:

As Bob add more solute to dissolves, the rate of solution will be decreases

Explanation:

At certain temperature the maximum amount of solute dissolve in the specific amount of solution or solvent.

There are many factors that affect solubility of the solute in solvent. Nature of the solute also affects the rate of solubility.

Temperature also affects the rate of solubility. Solubility increase when the temperature increases.

Pressure: Change in pressure have no effect on the rate of solubility

The rate of solution:  is a measure that how fast a substance dissolves in solvent.

Amount of solute already dissolved affect the rate of solution. If a solvent have little amount of solute in the solution it dissolve quickly. But when you have more solute in the solution the process was slower.

1 g of lead dissolves in 100 g of water at room temperature.  Similarly 5 mg of sodium hydroxide pellet dissolve in 100ml of water at room temperature.

So if Bob add 1 mg more of NaOH in the same 100ml of water the rate of the solubility decreases.

As there are some factors that decrease the solubility rate of NaOH pellet as follow:

• large size of the solute dissolve slowly as the solubility process take on      the surface of the solute particles, powders dissolve fast.

• less amount of solvent with ratio to solute

• saturated solution

So due to all above reasons the rate of the solubility decreases upon adding a little more amount of NaOH pellet.

Answer:

a

Explanation:

:)

Answer:

Explanation:

It could make burrows and homes in the dirt. It could hide food and itself in the soil. The Soil will grow food.

In an ecosystem , a mouse would make burrows in soil and soil would provide nutrients to the mouse.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.

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Answer:

activation activation energy is defined as the minimum amount of energy needed to start a reaction.

Answer:

Stored Energy(☞ﾟヮﾟ)☞☜(ﾟヮﾟ☜)¯\_(ツ)_/¯

Explanation:

Answer:

The elements in the periodic table are arranged in order of increasing atomic number.

Explanation:

The elements are arranged based on their atomic numbers in a periodic table, not based on their atomic masses.  

• The chemical elements in the periodic table are demonstrated in order of their atomic number.  

• In the modern periodic table, the arrangement of elements is done based on their atomic number, not their relative atomic masses.  

• In the periodic table, the horizontal rows, known as periods, show the arrangement of elements in order of increasing atomic number.  

Thus, based on atomic numbers, elements are arranged in a periodic table.

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Answer:

Mass = 1.76 g

Explanation:

Given data:

Volume of solution = 25 mL

Molarity = 0.45 M

Amount of CuSO₄.5H₂O = ?

Solution:

Molarity = number of moles / volume in litter

Number of moles = Molarity × Volume in L

Number of moles = 0.45 M  × 0.025 L

Number of moles = 0.011 mol

Mass of f CuSO₄.5H₂O:

Mass = Number of moles ×  molar mass

Mass = 0.011 mol × 159.6 g/mol

Mass = 1.76 g

Answer:

Option D

Explanation:

In Sulphur dioxide molecule both sulphur and oxygen have 6 valence electrons

The oxidation state of Sulphur in Sulphur dioxide molecule is +4 and the oxidation state of oxygen in Sulphur dioxide molecule is -2

Both sulphur and oxygen in this molecule are non-metals and therefore there will be no ionic bond present between them

So bond formation in this molecule takes through sharing of electrons between sulphur and oxygen and due to the sharing of electrons, covalent bond formation takes place between them

As there are only covalent bonds involved, this molecule is a covalent molecule

∴ Sulphur dioxide molecule is covalent and formed by the sharing of electrons

Final answer:

Sulfur and oxygen, both in group 16, have six valence electrons. Sulfur dioxide (SO2) is formed by the sharing of electrons, creating a covalent bond with a sulfur oxidation state of 4+.

Explanation:

From their location on the periodic table, both sulfur and oxygen are in group 16 and have six valence electrons. The typical oxidation state for oxygen is 2-, and sulfur can also have an oxidation state of 2-. However, sulfur is known to exhibit a range of oxidation states, including positive ones in certain compounds.

Regarding reactivity, oxygen is highly reactive and forms oxides with most elements. Sulfur also reacts with many elements, including metals, forming sulfides, and multiple oxidation states when reacting with nonmetals. The reaction between sulfur and oxygen results in the formation of sulfur dioxide, SO2, which is a compound where sulfur has a 4+ oxidation state.

The correct statement that most accurately describes the compound formed by sulfur and oxygen is D) Sulfur dioxide, SO2, is covalent, formed by the sharing of electrons.

Answer:

12.04 × 10²³ atoms

Explanation:

Given data:

Mass of cobalt = 117.86 g

Number of atoms = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

Number of moles of cobalt = 117.86 g/ 58.9 g/mol

Number of moles of cobalt = 2 mol

one moles of cobalt =  6.022 × 10²³ atoms of cobalt

2 moles × 6.022 × 10²³ atoms / 1 mol

12.04 × 10²³ atoms

Answer:

71 grams of chlorine gas.

Explanation:

2Na + Cl2 = 2NaCl.

From the molar masses:

2(23+35.45) g of NaCl are made from  2*35.45 g Cl2 gas.

So  117 g are made from  (2*35.45  * 117)  / 2(23+35.45)

= 71 g.

To make 117 grams of sodium chloride, you would need 121 grams of chlorine gas.

To calculate the amount of chlorine gas needed to make 117 grams of sodium chloride, we need to use stoichiometry.

Step 1: Convert the mass of sodium chloride to moles using the molar mass of NaCl which is 58.4 g/mol.

Step 2: Use the balanced equation to determine the mole ratio between chlorine gas and sodium chloride. From the equation 2Na + Cl2 -> 2NaCl, we can see that 1 mole of Cl2 reacts with 2 moles of NaCl.

Step 3: Convert moles of Cl2 to grams using the molar mass of Cl2 which is 70.9 g/mol.

Therefore, to make 117 grams of sodium chloride, we need (117 g NaCl) * (1 mol NaCl / 58.4 g NaCl) * (1 mol Cl2 / 2 mol NaCl) * (70.9 g Cl2 / 1 mol Cl2) = 121 grams of chlorine gas.

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Answer:

option b : O₉S₁₀

Explanation:

There are some points to name a covalent compound, according to that

number of atoms numbered as

**mono for one, di - for two tri for three and so on.

the name of the atom as

**carbon as carbide, sulfur as sulfide, oxygen as oxide, foulrine as flouro etc.

So,

Formula of Nonoxide decasulfide

Now Naming of the Chemical compound

Following are the explanations of  terms

So keeping the above points in mind

The right answer is

Option b : O₉S₁₀

Answer:

1 grams Strontium Fluoride to mol = 0.00796 mol

10 grams Strontium Fluoride to mol = 0.07961 mol

50 grams Strontium Fluoride to mol = 0.39804 mol

100 grams Strontium Fluoride to mol = 0.79607 mol

200 grams Strontium Fluoride to mol = 1.59214 mol

500 grams Strontium Fluoride to mol = 3.98036 mol

1000 grams Strontium Fluoride to mol = 7.96072 mol

- Hopefully this helps a bit :)

Answer:

70g

Explanation:

Rate = 35g of NaCl can dissolve in 100g of H2O

Use proportions for 200g of H2O:

[tex]\frac{35}{100} = \frac{x}{200}[/tex]

Since 200 is double of 100, x needs to be double of 35.

[tex]\frac{35}{100} = \frac{70}{200}[/tex]

Therefore the maximum amount of NaCl that can dissolve in 200g of water is 70g.

1.88 g

We are given;

We are required to determine the amount of uranium left after 2 days

N = N₀ × 0.5^n

Where, N is the remaining mass, N₀ is the original mass and n is the number of half lives.

n = (2 × 24) ÷ 12 hours

  = 4

Therefore;

Remaining mass, N = 30.0 g × 0.5^4

                                = 1.875 g

                                = 1.88 g

Therefore, the mass of the remaining sample after decay is 1.88 g

Answer:

option D is correct that is  8.2 g

Explanation:

Data Given:

mole of NaCl = 0.14 mol

Volume of water = 1 L

Weight of Nacl = ?

Solution:

In this we know the amount of NaCl and to find weight of NaCl to form a solution.

So,

Formula Used

    no. of moles = weight in g / Molar mass . . . . . . . . . . (1)

Molar mass of NaCl = 23 + 35.5

Molar mass of NaCl = 58.5 g/mol

Rearrange equation (1)

        no. of moles = weight in g / Molar mass . . . . . . . . . . (1)

        weight of Nacl =  no. of moles x Molar mass . . . . . . . . . . (2)

Put values in the Equation 2

             weight of Nacl = 0.14 mol x 58.5 g/mol

              weight of Nacl = 8.2 g

weight of Nacl = 8.2 g

So option D is correct that is  8.2 g

Answer: They ionize by the gain of one electron

Explanation:

Group 7 elements have seven electrons on their outermost shell, in order to have a complete octet structure, the go into bonding with other elements by gaining one more electron to have eight complete outermost shell electron (valence electron). They thereby ionize by gain one electron forming X[tex]X^{-1}[/tex]

Answer:

250000000000 ml of apple juice

Answer:

speed of plane in still air  =  252 mph

speed of wind  = 42 mph.

Explanation:

Given:

Distance travelled by the small plane = 245  

Time taken to fly 245 miles =  1 hour and 10 minutes.

Time taken for return trip = 50 minutes.

To Find:

speed of the wind=?

The speed of the plane in still air=?​

Solution:

We Know that

[tex]speed = \frac{distance}{time}[/tex]  

=>[tex]\frac{245}{ \frac{70}{60}} hours[/tex]

=>[tex]\frac{245}{ \frac{7}{6}} hours[/tex]

=>[tex]245 \times { \frac{6}{7}[/tex]

=>210  mph against wind

on way back

=>[tex]\frac{245}{ \frac{50}{60}} hours[/tex]

=>[tex]\frac{245}{ \frac{5}{6}} hours[/tex]

=>[tex]245 \times { \frac{6}{5}[/tex]

=> 294

Now

294 = plane +wind------------------------(1)

210 =plane - wind-------------------------(2)

Solving (1) and (2)

2 plane = 504

plane = 252

plane = [tex]\frac{504}{2}[/tex]

So  substituting plane value in eq(2) we get,

210 =252 - wind

wind = 42 mph

The speed of the wind is 35.6 miles per hour in the opposite direction of the plane's movement, and the speed of the plane in still air is 209.4 miles per hour.

To solve this problem, we can use the formula:

Plane speed in still air = (total distance) / (total time)

Given that the plane flew 245 miles in 1 hour and 10 minutes against the wind, and the return trip took 50 minutes, we can calculate the speed of the wind and the speed of the plane in still air as follows:

Step 1: Convert the time to hours:
1 hour and 10 minutes = 1.17 hours
50 minutes = 0.83 hours

Step 2: Calculate the speed of the plane in still air using the formula:
Speed of the plane in still air = (total distance) / (total time)
Speed of the plane in still air = 245 / 1.17 = 209.4 miles per hour

Step 3: Calculate the speed of the wind by finding the difference between the speed of the plane in still air and the actual speed of the plane against the wind:
Speed of the wind = Speed of the plane in still air - Speed of the plane against the wind
Speed of the wind = 209.4 - 245 = -35.6 miles per hour

Therefore, the speed of the wind is 35.6 miles per hour in the opposite direction of the plane's movement, and the speed of the plane in still air is 209.4 miles per hour.

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Answer:

Volume percent of a solution that has 10.0 g of ethanol= 12.37%

Volume percent of a solution that has 90.0 g of water = 87.69%

Explanation:

Volume Percent:

The volume percent helps us  to indicate the concentration of the solution when the volume of the solute and volume of the solution is given by

[tex]Volume Percent=\frac{\text{Volume of the Solute}}{\text{Volume of Solution}}\times100%[/tex]

With respect to density 1mL of ethanol

=> 0.7893g or 10g of methanol contains

=> [tex]\frac{1}{0.7893}\times10[/tex]

=> 12.67mL

And for water = [tex]\frac{1}{0.9987} \times 90.0[/tex]

=> 90.12mL

Now total volume = 90.12+ 12.67 = 102.79mL

%(v/v) for water = [tex]\frac{90.12}{102.79}\times 100[/tex]

 = 87.69%

%(v/v) for ethanol = [tex]\frac{12.67}{102.79}\times 100[/tex]

 = 12.37%

The volume percent of ethanol in the solution is 12.3%, and the volume percent of water is 87.7%. This is calculated by determining the volume of each substance using their respective densities and the mass provided and then finding the percentage of each substance's volume in the total solution volume.

To find the volume percent of a solution that has 10.0 g of ethanol with a density (D) of 0.7893 g/mL, and 90.0 g of water with a density (D) of 0.9987 g/mL, we first calculate the volumes of each component. For ethanol, divide 10.0 g by 0.7893 g/mL to get the volume in milliliters. For water, divide 90.0 g by 0.9987 g/mL to get the volume in milliliters.

To calculate the volume of ethanol: 10.0 g / 0.7893 g/mL = 12.7 mL
To calculate the volume of water: 90.0 g / 0.9987 g/mL = 90.2 mL
Assuming volumes are additive: Total volume of the solution = 12.7 mL (ethanol) + 90.2 mL (water) = 102.9 mL

Now, we can find the volume percent of ethanol: (volume of ethanol / total volume of solution) × 100% = (12.7 mL / 102.9 mL) × 100% = 12.3%

The volume percent of water is similarly calculated: (volume of water / total volume of solution) × 100% = (90.2 mL / 102.9 mL) × 100% = 87.7%

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Answer:

negatively-charged particles.(ELECTRON) B

Explanation:

Electrons are the negatively charged particles of atom. Together, all of the electrons of an atom create a negative charge that balances the positive charge of the protons in the atomic nucleus

The reaction that can extract silver metal from a silver nitrate solution is Equation 1, where zinc metal reacts with silver nitrate, displacing the silver and allowing it to precipitate.

To extract silver metal from silver nitrate solution, one would look for a chemical reaction where a more reactive metal displaces silver from its compound. In Equation 1, we have AgNO3 reacting with Zn, which is a more reactive metal known to displace other metals in a single displacement reaction. The reaction between zinc and silver nitrate can be represented as follows: Zn(s) + 2AgNO3(aq)
ightarrow Zn(NO3)2(aq) + 2Ag(s). This results in the precipitation of silver metal (Ag). References to similar reactions such as the reaction between copper and silver nitrate, where silver is also displaced and precipitated, support this concept.

On the other hand, Equation 2, which involves MgCl2 reacting with AgNO3, does not lead to a displacement reaction to extract silver because chlorides are usually spectators in such reactions unless conditions like oxidation or other complex reactions are involved. Additionally, MgCl2 itself as a compound does not have a free metal to displace silver from silver nitrate.

Therefore, the reaction that can be used to extract silver metal from a silver nitrate solution is Equation 1, where zinc metal is reacting with silver nitrate.

Answer:

A) 1.5 moles  B) 1.5 moles  C) 3.5 moles  D) 2/3 moles

Explanation:

A) 1 mole of CO₂ gives 1 mole of CH₄ and 2 moles of H₂O, i.e, 3 moles of products. So 0.5 moles of CO₂ gives 3 x 0.5 = 1.5 moles of products.

B) 1 mole of BaCl₂ gives 2 moles of AgCl and 1 mole of Ba(NO₃)₂, i.e, 3 moles of products. So 0.5 moles of BaCl₂ gives 3 x 0.5 = 1.5 moles of products.

C) 1 mole of C₃H₈ gives 4 moles of H₂O and 3 moles of CO₂, i.e, 7 moles of products. So 0.5 moles of C₃H₈ gives 7 x 0.5 = 3.5 moles of products.

D) 3 moles of H₂SO₄ gives 1 mole of Fe₂(SO₄)₃ and 3 moles of H₂, i.e, 4 moles of products. So 0.5 moles of H₂SO₄ gives 4/3 x 0.5 = 2/3 moles of products.

To calculate the number of moles of product produced when a given amount of reactant is completely reacted, use the stoichiometric coefficients of the balanced chemical equation.

To calculate the number of moles of product produced when a given amount of reactant is completely reacted, we need to use the stoichiometric coefficients of the balanced chemical equation. Each coefficient represents the ratio of moles between reactants and products.

For example, in the first equation, CO2 (g) + 4H2 (g) → CH4 (g) + 2H2O (l), the coefficient of CO2 is 1 and the coefficient of CH4 is also 1. This means that for every 1 mole of CO2 that reacts, 1 mole of CH4 is produced.

Therefore, if 0.500 mole of CO2 were to react completely, 0.500 mole of CH4 would be produced.

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Answer:

C) 14.1 moles

Explanation:

1 mole = 6.02 *10^ 23

8.50 * 10^24 molecules *(1 mole/6.02*10^23 molecules) ≈ 14.1 moles

The number of moles there are in 8.50 X [tex]10^{24}[/tex] molecules of sodium sulfate is 14.1 moles (option C).

The number of moles in a molecule of a substance can be calculated by dividing the number of molecules by Avogadro's number as follows:

no of moles = no of molecules ÷ 6.02 × [tex]10^{23}[/tex] molecules

According to this question, there are in 8.50 X [tex]10^{24}[/tex] molecules of sodium sulfate in a substance. The number of moles in this substance can be calculated as follows:

no of moles = 8.50 X [tex]10^{24}[/tex] ÷ 6.02 × [tex]10^{23}[/tex]

no of moles = 14.1 moles

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Answer:

a. chromium (III) chloride

Explanation:

Chromium chloride is also binary ionic compound composed of only two element chromium and chlorine.

When naming these compounds the name of metal or cation is written first and anion is written after the cation. The anions are non meals.

The anion name is end with suffix " ide".

such as chromium chloride.

The (III) shows the oxidation number of metal. In given compound the oxidation state of chromium is +3 while chlorine chow the oxidation state of -1 that's why three chlorine atoms are attached with one chromium atom.

Final answer:

The ionic compound CrCl3 is correctly named chromium(III) chloride, identifying the trivalent state of chromium in the compound.

Explanation:

The correct name for the ionic compound with the formula CrCl3 is chromium(III) chloride. This name indicates that the chromium ion in the compound has a valency of three, which is communicated by the Roman numeral III. Ionic compounds such as this are named by stating the metal ion followed by the non-metal ion with an -ide ending, and when the metal can form ions with different charges, the specific charge is included in parentheses in Roman numerals immediately after the name of the metal.

Some similar examples include iron(II) chloride (FeCl2) and iron(III) chloride (FeCl3), where the Roman numerals II and III denote the valency of the iron ion in each compound, respectively.

Final answer:

Physical weathering refers to the process of breaking down rocks without changing their chemical composition. Examples include grinding away of rock, flaking due to pressure release, and water freezing and thawing.

Explanation:

Physical weathering refers to the process of breaking down rocks into smaller pieces without changing their chemical composition. Examples of physical weathering include the grinding away of a rock surface, the top layers of rock flaking off due to the release of pressure, and the freezing and thawing of water, which causes it to expand and contract and break the rock apart.

Other examples include tree roots growing in the cracks of rocks and animals digging burrows. On the other hand, rust forming due to oxidation and acid rain weathering a statue are examples of chemical weathering.

Final answer:

Physical weathering includes processes like abrasion, exfoliation, temperature fluctuations, freeze-thaw cycles, animal activities, and root wedging, all of which disintegrate rock mechanically.

Explanation:

The examples of physical weathering are those processes that result in the breakdown of rock without altering its chemical composition. Here are the examples that correctly apply to the concepts of physical weathering:

On the other hand, the following are not examples of physical weathering because they involve chemical changes to the rock: water dissolving soft rock, rust forming due to oxidation, and acid rain weathering a statue.

Answer:

[tex]\large \boxed{\text{460 dg}}[/tex]

Explanation:

1. Convert decagrams to grams

[tex]\text{Mass} =  \text{4.6 dag} \times\dfrac{\text{10 g}}{\text{1 dag}} = \text{46 g}[/tex]

2. Convert grams to decigrams

\[tex]\text{Mass} =  \text{46 g} \times\dfrac{\text{10 g}}{\text{1 dg}} = \text{460 dg}\\\\\large \boxed{\textbf{4.6 dag = 460 dg}}[/tex]

To find the pressure of CH4 gas in a flask, one must convert the mass of methane to moles, plug it into the Ideal Gas Law equation (PV = nRT), and solve for pressure. After calculation, the pressure of the methane gas at 25°C in a 1.75 L flask is approximately 0.33 atm.

To calculate the pressure of CH4 gas in a flask using the Ideal Gas Law, you need to use the amount of substance (in moles), the volume of the container, the temperature, and the ideal gas constant in appropriate units. First, convert the mass of CH4 to moles by dividing by the molar mass of methane (16.04 g/mol). Then, use the Ideal Gas Law formula PV = nRT to solve for pressure (P).

Moles of CH4 = 0.357 g / 16.04 g/mol = 0.02226 mol

Given: V = 1.75 L, T = 25°C (which is 298.15 K when converted to Kelvin), R = 0.08206 L atm/mol K

Now, substitute the values into the Ideal Gas Law equation:

P = (nRT) / V

P = (0.02226 mol * 0.08206 L atm/mol K * 298.15 K) / 1.75 L

P = 0.3298 atm

Therefore, the pressure of CH4 gas in the flask at 25°C is approximately 0.33 atm.

Answer:

Ionic compounds are electrically neutral because the positive ions and the negative ions in the compound cancel each other.

Explanation:

Ion- It is an atom or a molecule that has an equal number of protons (subatomic particles with positive electric charge) and electrons (subatomic particles with negative electric charge).

Positive ion- This is also called a "cation." It consists of more protons than electrons.

Negative ion- This is also called an "anion." It consists of more electrons than protons.

Ionic compounds are electrically neutral because they consist of anions and cations. This neutralizes the compounds. A common example of ionic compound is the NaCl (Sodium Chloride). The Na (Sodium) atom loses an electron in order to become Na+ while the Cl (Chlorine) atom gains an electron in order to become Cl-. This interaction balances them together.  

Ionic compounds are electrically neutral overall because the total number of positive charges of the cations equals the total number of negative charges of the anions. This allows ionic compounds to maintain overall neutrality despite the presence of positive and negative ions.

In every ionic compound, the total number of positive charges of the cations equals the total number of negative charges of the anions. Thus, ionic compounds are electrically neutral overall, even though they contain positive and negative ions. We can use this observation to help us write the formula of an ionic compound. The formula of an ionic compound must have a ratio of ions such that the numbers of positive and negative charges are equal.