If 0.0262 mol of cacl2 is dissolved in water to make a 0.520 m solution, what is the volume of the solution?

Answers

Answer 1
Cacl2  dissolve   in  water   according  to the  following  equation

Cacl2 + H2O  =  Ca(OH) + Hcl
Volume=  moles/molarity
  The  reacting  ratio    between CaCl2  to  Ca(OH)  is   1:1
therefore  moles  of  solution   is  also  0.0262  moles hence  volume   is  =
0.0262mol/  0.52mol/l =  0.0504L  or50.4ml

Related Questions


1. At approximately 50°C and 0.5 kPa, what phase of matter is water in? *


A. Solid

B. liquid

C. vapor

D. both liquid and vapor


2. A sample of neon occupies a volume of 375 mL at STP. What will be the volume of the neon if the pressure is reduced to 90.0 kPa? *


A.422 mL

B.422 L

C. 333 mL

D. 333 L


3. A gas at 155 kPa and standard temperature has an initial volume of 1.00 L. The pressure of the gas rises to 500 kPa as the temperature also rises to 135°C. What is the new volume? *


A. 2.16 L

B. 0.463 L

C. 0.207 L

D. 4.82 L


4. What pressure will be exerted by 0.650 mol of a gas at 30.0°C if it is contained in a 0.700 L vessel? *


A. 2340 kPa

B. 2340 atm

C. 231 kPa

D. 231 atm


5. The vapor pressure of water is *


a. high due to very weak intermolecular attractions

b. high due to water's polarity

c. low due to water's high specific heat

d. low due to relatively strong intermolecular attractions


6. Which mixture contains the largest particles? *


a. solution

b. suspension

c. colloid

d. emulsion


7. How does evaporation of a liquid differ from boiling a liquid?


8. Describe the Tyndall Effect and how it could affect my drive home on a foggy night.

Answers

The answer would have to be the letter a for question 1

which rock future is the line running between points A and B most likely to be?
A)
rock
B)
strata still
C)
dice
D)
fault

Answers

I think is D. Fault is the best answer.

Answer:

On plato this would be D a fault line

Explanation:

When shopping for major appliances, people should look for high energy-rating numbers because those items _____.

Answers

The answer would be :Use less energy

Answer:

Use less energy.

Explanation:

Hello,

High energy consumption implies higher costs during the usage of a product, nevertheless, by avoiding this factor, money could be saved in addition of the environmental damage that is prevented in the light of the lower energy use.

Best regards.

An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d = 1.114 g/ml; = 62.07 g/mol) and water (d = 1.00 g/ml) at 20°c. the density of the mixture is 1.070 g/ml. express the concentration of ethylene glycol as:

Answers

a) Volume percent

Formula: % v/v = [volume solute / volume solution] * 100

Just to make it easy take a base of 50 volume parts of ethylen glycol and 50 volume parts of water to make 100 volumes of mixture (this assumpion will be valid for all the questions):

% v/v =[ 50 ml ethyleneglycol] / [100 ml mixture] * 100 = 50%

Answer: 50% v/v

b) Mass percent

% m/m = [mass ethylene glycol / mass solution] * 100

mass ethylene glycol = 50 ml * 1.114 g/ ml = 55.7 g

mass of mixture = 100 ml * 1.07 g/ml = 107 g

% m/m = [55.7 / 107 g] * 100 = 52.06 %

Answer: 52.06%

c) Molarity

M = number of moles of solute / liters of solution

number of moles of solute = mass in grams / molar mass

number of moles of ehtylene glycol = 55.7 g / 62.07 g/mol = 0.8974 mol

liters of solution = 0.1 liter

M = 0.8974 mol / 0.1 liter = 8.974 M

Answer: 8.974 M

d) Molality

m = number of moles of solute / kg of solvent

number of moles of ethylen glycol = 0.8974 mol

mass of water = 50 ml * 1 g/ml = 50 g = 0.05 kg

m = 0.8974 mol / 0.05 kg = 17.95 m

Answer: 17.95 m

e) mole fraction

mole fraction = [number of moles of solute] / [number of moles of mixture] * 100

number of moles of ethylen glycol = 0.8974 mol

number of moles of water = 50 g / 18.01 g /mol = 2.776 mol

mole fraction = 0.8974 mol / [0.8974 mol + 2.776 mol] = 0.244

Answer: 0.244
Final answer:

The concentration of ethylene glycol in the antifreeze mixture can be calculated by determining the mole fraction. First, find the moles of ethylene glycol and water, then use the mole fraction to find the concentration. The final concentration of ethylene glycol is 0.0179 mol/kg.

Explanation:

To calculate the concentration of ethylene glycol in the antifreeze mixture, we'll first need to find the mole fraction, which involves calculating the molar amounts of both ethylene glycol and water.

Since 1ml of each liquid is used, we have 1.114g of ethylene glycol and 1.00g of water. The molar mass of ethylene glycol is 62.07 g/mol, so 1.114g / 62.07 g/mol = 0.0179 moles of ethylene glycol. The molar mass of water is 18.02 g/mol, so 1.00g / 18.02 g/mol = 0.0555 moles of water.

The mole fraction (X) of a substance is the number of moles of that substance divided by the total number of moles of all substances in the solution. So, X_ethylene glycol = 0.0179 / (0.0179 + 0.0555) = 0.244.

Finally, to express concentration of ethylene glycol as molality, we use the formula molality = moles of solute/kg of solvent. Hence, molality = 0.0179 moles/1g = 0.0179 mol/kg.

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He main reasons why ch4 has a higher vapor pressure at a given temperature when compared to ch3cl is that

Answers

Final answer:

CH4 exhibits weaker London dispersion forces while CH3Cl has stronger dipole-dipole interactions due to its polar C-Cl bond, resulting in CH4 having a higher vapor pressure at the same temperature than CH3Cl.

Explanation:

The main reason why CH4 has a higher vapor pressure at a given temperature when compared to CH3Cl is primarily due to the differences in the types and strengths of their intermolecular forces (IMFs). Methane (CH4) only exhibits London dispersion forces, which are the weakest type of IMFs because it is a non-polar molecule.

On the other hand, chloromethane (CH3Cl) exhibits both London dispersion forces and dipole-dipole interactions due to the presence of a polar C-Cl bond. This dipole-dipole interaction in CH3Cl is stronger than the dispersion forces in CH4, leading to stronger intermolecular attractions in CH3Cl and, consequently, a lower vapor pressure at the same temperature.

What does it mean for a solution to be saturated

A. No more solute can be dissolved
B. The Concentration can be increased
C. No more solvent can be dissolved
D. The Solution can dissolve more substances

Answers

Answer:
A. No more solute can be dissolved 

Explanation:
A solute is defined as a substance that is dissolved
A solvent is the substance in which the solute is dissolved

When the maximum concentration of solute is dissolved in a solvent, the solution is said to be saturated.
This means that the any more solute added to the solution will not dissolve.

Hope this helps :)

how many molecules of h2o are equal to 97.2 g h2o

Answers

m(H₂O) = 97,2 g.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 97,2 g ÷ 18 g/mol.
n(H₂O) = 5,4 mol.
N(H₂O) = n(H₂O) · Na.
N(H₂O) = 5,4 mol · 6,023·10²³ 1/mol.
N(H₂O) = 3,25·10²⁴ molecules of water.
n - amount of substance.
Na - Avogadro number.

Answer:

3.25*10^24

Explanation:

Write a balanced chemical equation for the reaction of acetone (c3h6o) with oxygen (o2) to form carbon dioxide (co2) and water (h2o). select one:
a. c3h6o + 4 o2 ® 3 co2 + 3 h2o.
b. 3 co2 + 3 h2o ® c3h6o + 4 o2.
c. 6 c3h6o + 8 o2 ® 6 co2 + 6 h2o.
d. c3h6o + o2 ® co2 + h2o.

Answers

the balanced equation for this reaction is  
C3H6O + 4 O4 → 3CO2 + 3H2O
but you should how to balance the original equation:
the original equation was C3H6O + O4 → CO2 + H2O
to be the equation balanced we have to make each number of the atom is equal on each side of the equation.
1) first, we start with C atom in the original equation it was 3 atom in the right side and 1 atom in the left side so we put 3CO2 instead of CO2 in the right side to make the C atoms number is equal in both sides.
the equation becomes C3H6O + O2 → 3CO2 + H2O
2) second, the H atom, it was 6 atom in the left side and only 2 in the right side so we put 3H2O instead of H2O to make it equals each other in both sides.
the equation becomes C3H6O + O2 → 3 CO2 + 3H2O
3) finally, the O atom, it was 4 atom in the right side and 9 atoms in the left side so we put 4 O2 instead of O2 to make it equals each other in both sides

so we get the final balanced equation is
C3H6O + 4O2 → 3CO2 +3H2O


The balanced chemical equation for the reaction of acetone (C3H6O) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is C3H6O + 4 O2 → 3 CO2 + 3 H2O (option a). It preserves mass and element conservation.

The balanced chemical equation for the reaction of acetone (C3H6O) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is:

a. C3H6O + 4 O2 → 3 CO2 + 3 H2O.

In this balanced equation, the number of carbon atoms, hydrogen atoms, and oxygen atoms on both sides is the same, ensuring that mass and element conservation are maintained.

Explanation:

- On the left side (reactants), there is one molecule of acetone (C3H6O) and four molecules of oxygen (O2).

- On the right side (products), there are three molecules of carbon dioxide (3 CO2) and three molecules of water (3 H2O).

This equation satisfies the law of conservation of mass and the law of conservation of elements because the number of each type of atom (carbon, hydrogen, and oxygen) remains the same on both sides of the equation. Option (a) is the correct balanced chemical equation for this reaction.

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if the theoretical yield of RX is 56.0 g , what is it’s percent yield ?b

Answers

the theoretical yield which is the expected yield and the actual yield obtained are not always the same. therefore percent yield is calculated which shows how much of the percentage of the theoretical yield is actually obtained.
the theoretical yield = 56.0 g 
actual yield = 47.0 g 
percent yield = actual yield / theoretical yield x 100 %
percent yield = 47.0 / 56.0 x 100% = 83.9 %
percent yield = 83.9 %
the complete question in attached figure

Let 
x------------------- >  actual yield
y------------------- > theoretical yield 
z------------------- > percent yield
we have that
z=x/y
we know
x=47 g
y=56 g
therefore
z=47/56=0.839 ---------------- > 83.9\%

the answer is the option C 83.9\%

In which circumstance is the transition state more similar to the products of the reaction?

Answers

the answer is endergonic reaction

hoped it helped !!

A certain gas is present in a 12.0 L cylinder at 4.0 atm pressure. If the pressure is increased to 8.0 atm the volume of the gas decreases to 6.0 L . Find the two constants ki, the initial value of k, and kf, the final value of k, to verify whether the gas obeys Boyle’s law by entering the numerical values for ki and kf in the space provided.

Answers

There are 3 parts in this question:
1) To find the initial Boyle's constant [tex]k_{i}[/tex]
2) To find the final Boyle's constant [tex]k_{f}[/tex]
3) To verify whether gas is obeying Boyle's law or not

Given data:
The initial volume of the cylinder(in litres) = [tex]V_{i}[/tex] = 12.0 L
The initial pressure(in atmospheric pressure) = [tex]P_{i}[/tex] = 4.0 atm

The final pressure(in atmospheric pressure) = [tex]P_{f}[/tex] = 8.0 atm
The final volume of the cylinder(in litres) = [tex]V_{f}[/tex] = 6.0 L

First you need to know what Boyle's law is:
Boyle's law states that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature.

The Mathematical form of Boyle's law is:
[tex]P = \frac{k}{V} [/tex]

Where,
P = Pressure
V = Volume of the gas
k = Boyle's constant

Now let's solve aforementioned parts one by one:
1. 
The initial volume of the cylinder(in litres) = [tex]V_{i}[/tex] = 12.0 L
The initial pressure(in atmospheric pressure) = [tex]P_{i}[/tex] = 4.0 atm
The Boyle's constant = [tex]k_{i}[/tex] = ?

According to the Boyle's law,

[tex]P_{i} = \frac{k_{i}}{V_{i}} [/tex]

=> [tex]k_{i}[/tex] =  [tex]P_{i}V_{i}[/tex]
Plug-in the values in the above equation, you would get:
[tex]k_{i}[/tex] = 4.0 * 12.0 = 48

Ans-1) [tex]k_{i}[/tex] = 48

2.
The final pressure(in atmospheric pressure) = [tex]P_{f}[/tex] = 8.0 atm
The final volume of the cylinder(in litres) = [tex]V_{f}[/tex] = 6.0 L
The Boyle's constant = [tex]k_{f}[/tex] = ?

According to the Boyle's law,

[tex]P_{f} = \frac{k_{f}}{V_{f}} [/tex]

=> [tex]k_{f}[/tex] =  [tex]P_{f}V_{f}[/tex]
Plug-in the values in the above equation, you would get:
[tex]k_{f}[/tex] = 8.0 * 6.0 = 48

Ans-2) [tex]k_{f}[/tex] = 48

3.
In order to verify Boyle's law, the initial Boyle's constant should be EQUAL to the final Boyle's constant, meaning:

[tex]k_{i}[/tex] = [tex]k_{f}[/tex]

Since,
[tex]k_{i}[/tex] = 48
[tex]k_{f}[/tex] = 48

Therefore,
48=48.

Ans-3) Hence proved: The gas IS obeying the Boyle's law.

-i

The initial value of constant [tex]{{\text{k}}_1}[/tex] is 48.0 atmL and the final value of constant [tex]{{\text{k}}_2}[/tex]  is 48.0 atmL. This proves that Boyle's lawis obeyed by gas.

Further explanation:

Boyle’s law:

It is an experimental gas law that describes the relationship between pressure and volume of the gas. According to Boyle's law, the volume of the gas is inversely proportional to the pressure of the system, provided that the temperature and the number of moles of gas remain constant.

If the temperature and number of moles of gas are constant then the equation (1) will become as follows:

[tex]{\text{PV}} = {\text{k}}[/tex]                 ……(2)

Here, k is a constant.

Or it can also be expressed as follows:

[tex]{{\text{P}}_1}{{\text{V}}_1} = {{\text{P}}_2}{{\text{V}}_2}[/tex]    ……(3)

Here,

[tex]{{\text{P}}_1}[/tex] is the initial pressure.

[tex]{{\text{P}}_2}[/tex] is the final pressure.

[tex]{{\text{V}}_1}[/tex] is the initial volume.

[tex]{{\text{V}}_2}[/tex] is the final volume.

Boyle'slaw for the initial condition of gas can be written as,

[tex]{{\text{P}}_1}{{\text{V}}_1}={{\text{k}}_1}[/tex]                                   …… (4)

Substitute 4.0 atm for [tex]{{\text{P}}_1}[/tex]  and 12.0 L for [tex]{{\text{V}}_1}[/tex]  in equation (4).

[tex]\begin{aligned}\left( {4.0{\text{ atm}}}\right)\left({12.0{\text{ L}}}\right)&= {{\text{k}}_1}\hfill\\48.0{\text{ atm}}\cdot{\text{L}}&= {{\text{k}}_1}\hfill\\\end{aligned}[/tex]

Boyle's law for the final condition of gas can be written as,

[tex]{{\text{P}}_2}{{\text{V}}_2} = {{\text{k}}_2}[/tex]                                   …… (5)

Substitute 8.0 atm for [tex]{{\text{P}}_2}[/tex]  and 6.0 L for [tex]{{\text{V}}_2}[/tex]  in equation (5).

[tex]\begin{aligned}\left( {8.0{\text{ atm}}}\right)\left({6.0{\text{ L}}}\right)&={{\text{k}}_2}\hfill\\48.0{\text{ atm}}\cdot{\text{L}}&={{\text{k}}_2}\hfill\\ \end{aligned}[/tex]

Since the value of [tex]{{\text{k}}_1}[/tex] and [tex]{{\text{k}}_2}[/tex]  is equal in both cases thus this gives,

 [tex]{{\text{P}}_1}{{\text{V}}_1} = {{\text{P}}_2}{{\text{V}}_2}[/tex]

Hence, it is proved that Boyle's law is obeyed by the given gas.

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Ideal gas of equation

Keywords: Boyle's law, volume, temperature, pressure, volume pressure relationship, constant temperature, relationship, V inversely proportional to P, ideal gas, ideal gas equation number of mole and moles.

Draw the major product(s) of electrophilic chlorination of p-cyanobenzoic acid.

Answers

p-cyanobenzoic acid is a nitrile group in the 1-position and a carboxylic acid group in the 4-position, these groups are para-substituted. However, both nitrile and carboxylic acid groups are electron-withdrawing, which means that they are both meta-directing groups when undergoing electrophilic substitution. At the same time, both groups are deactivating groups. Since they are both deactivating, it is possible that no further substitution will even occur.

For the sake of the question, we will assume that the reaction is allowed to take place. Therefore, each group will be trying to direct the to different meta-positions. The nitrile group is a much stronger withdrawing group, therefore, it will be the major directing group and the chloro will substitute in the position that is meta- to the nitrile, and ortho- to the carboxylic acid. The minor product would be the meta-position relative to the carboxylic acid. The reaction scheme provided shows the potential products of this reaction.

if the theoretical yield of RX is 56.0 g , what is the percent yield ?

Answers

the complete question in attached figure

Let 
x------------------- >  actual yield
y------------------- > theoretical yield 
z------------------- > percent yield
we have that
z=x/y

we know
x=47 g
y=56 g

therefore

z=47/56=0.839 ---------------- > 83.9%

the answer is the option C 83.9%

select the one that most likely has the highest rate of effusion Oxygen (O2) or hydrogen (H2):

Answers

The answer is hydrogen (H2) because i just answered this question from Edgenuit.

HELP!!!! 15 pts !!! Which chemical equation below does not illustrate the Law of Conservation of Mass? Al4C3 + 3H2O yields CH4 + 4Al(OH)3 2 NaCl + CaO yields Na2O + CaCl2 3 LiOH + Fe(NO3)3 yields 3LiNO3 + Fe(OH)3 Zn + 2HCl yields ZnCl2 + H2

Answers

The last chemical equation doesn't follow the law of conservation because there isn't an equal number of zinc

What is the main reason for processing coal ore?

A) To increase heating value
B) To remove inorganic material
C) To eliminate pollution of groundwater
D) To recover other valuable minerals from the ore

Answers

It is A because to increase heating value removing other materials from coal increases its effectiveness as an energy source, making the coal more valuable. It also reduces transportation costs.

Helium has the lowest boiling point of any substance, at 4.2 k. part a what is this temperature in âc?

Answers

Answer is: temperature of helium is -296,95°C.
The temperature T in degrees Celsius (°C) is equal to the temperature T in Kelvin (K) minus 273,15: T(°C) = T(K) - 273.15.
T(He) = 4,2 K.
T(He) = 4,2 K - 273,15.
T(He) = -268,95°C.
The Celsius scale was based on 0°C for the freezing point of water and 100°C for the boiling point of water at 1 atm pressure.

The temperatur e of Helium in °C =  -268.8 °

Further explanation

Temperature is one of the principal quantities that shows the degree of heat or cold from an object / space

Temperature is used as a guide to the level of heat energy from objects

Temperature measures thermal energy

The temperature of an object also depends on the kinetic energy of the object's molecules

Temperature cannot be measured by the surface of the hand because it is not accurate but can be measured by a thermometer. Temperature units include Celsius, Fahrenheit, Reamur or Kelvin

Boiling point and freezing point of Temperature units;

1. Celsius

Boiling point : 100 °C

Freezing point: 0 °C

2. Reamur

Boiling point : 80 °R

Freezing point: 0 °R

3. Fahrenheit

Boiling point : 212 °F

Freezing point: 32 °F

4. Kelvin

Boiling point : 373 °K

Freezing point: 273 °K

Whereas the temperature conversion is

°F = (9/5) °C + 32

°R = (4/5) °C

°K = °C + 273

°C = 5/9 (°F-32)

°R = 4/9 (°F-32)

°K = 5/9 (°F-32) + 273

°C = °K - 273

°R = 4/5 (°K-273)

°F = 9/5 (°K-273) + 32

°C = (5/4) °R

°F = (9/4) °R + 32

°K = °C + 273

°K = (5/4) °R + 273

Helium at 4.2 K, then the temperature in C  :

C = K - 273

C = 4.2 - 273

C = -268.8 C

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PLEASE HELP ME BABES AND ASAP PLEASE!!

What special structures are needed for green plants?


A.chloroplasts and chlorophyll
B. stems and roots
C. cotyledon and embryo
D. flowers and spores

What happens during the light reaction of photosynthesis?


A.Water molecules combine to make food.
B.Air and water create energy for a plant.
C.Carbon dioxide is combined with glucose.
D. Water molecules split apart.

Answers

What special structures are needed for green plants?
A.chloroplasts and chlorophyll


What happens during the light reaction of photosynthesis?
D. Water molecules split apart. (Not 100%)
a for the first on and d for the second one ☺

Which of the following correctly describes voltage difference?

Answers

voltage difference is the push that causes charges to flow from high to low areas.

The best description of voltage is:  Difference in potential energy per unit charge when measured between two points.

The correct answer is option C.

Voltage, often referred to as electric potential difference or electric potential, is a fundamental concept in electricity and represents the electric potential energy per unit charge between two points in an electric field. It is typically measured in volts (V).

Here's an explanation of why the other options are not accurate:

a. Amount of charge stored by a battery: Voltage is related to the potential energy difference, not the amount of charge stored.

b. Amount of power stored by a battery: Voltage is not a measure of power; it's a measure of electric potential.

d. Amount of potential energy at a given location: This option is somewhat close but lacks the specific reference to the difference in potential energy between two points, which is essential for voltage.

e. Difference in charge between two points: Voltage is not a measure of the difference in charge but rather the difference in potential energy per unit charge.

In summary, voltage is a measure of the potential energy difference per unit charge between two points in an electric field. It is crucial for understanding how electrical circuits work and plays a fundamental role in electricity and electronics  making option C the correct answer.

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The question probable may be:

Which of the following best describes voltage?

a. Amount of charge stored by a battery

b. Amount of power stored by a battery

c. Difference in potential energy per unit charge when measured between two points

d. Amount of potential energy at a given location

e. Difference in charge between two points

Differentiated animal cells and tissues include _____.

cuboidal cells
columnar cells
bone cells
fat cells
neurons
all of the above

Answers

The correct option is ALL OF THE ABOVE.
Differentiation of cell is said to occur when cells changes into another type of cells or cells. The process occurs during cell growth in multi cellular organisms. When a cell is fully differentiated it becomes specialized. All of the cells mentioned in the options above are differentiated cells. 

Answer as many as you can please, 40 POINTS
(Only right answers please don't guess)

1. At approximately 50°C and 0.5 kPa, what phase of matter is water in? *

A. Solid
B. liquid
C. vapor
D. both liquid and vapor

2. A sample of neon occupies a volume of 375 mL at STP. What will be the volume of the neon if the pressure is reduced to 90.0 kPa? *

A.422 mL
B.422 L
C. 333 mL
D. 333 L

3. A gas at 155 kPa and standard temperature has an initial volume of 1.00 L. The pressure of the gas rises to 500 kPa as the temperature also rises to 135°C. What is the new volume? *

A. 2.16 L
B. 0.463 L
C. 0.207 L
D. 4.82 L

4. What pressure will be exerted by 0.650 mol of a gas at 30.0°C if it is contained in a 0.700 L vessel? *

A. 2340 kPa
B. 2340 atm
C. 231 kPa
D. 231 atm

5. The vapor pressure of water is *

a. high due to very weak intermolecular attractions
b. high due to water's polarity
c. low due to water's high specific heat
d. low due to relatively strong intermolecular attractions

6. Which mixture contains the largest particles? *

a. solution
b. suspension
c. colloid
d. emulsion

7. How does evaporation of a liquid differ from boiling a liquid?

8. Describe the Tyndall Effect and how it could affect my drive home on a foggy night.







Answers

it would be to see your awnsers

A first-order reaction has a half-life of 29.2 s . how long does it take for the concentration of the reactant in the reaction to fall to one-sixteenth of its initial value?

Answers

Answer is: it takes 116,8 seconds to fall to one-sixteenth of its initial value

The half-life for the chemical reaction is 29,2 s and is independent of initial concentration.
c₀ - initial concentration the reactant.

c - concentration of the reactant remaining at time.

t = 29,2 s.
First calculate the rate constant k:
k = 0,693 ÷ t = 0,693 ÷ 29,2 s = 0,0237 1/s.
ln(c/c₀) = -k·t₁.
ln(1/16 ÷ 1) = -0,0237 1/s · t₁.

t₁ = 116,8 s.

Given that the molar mass of NaCl is 58.44 g/mol, what is the molarity of a solution that contains 87.75 g of NaCl in 500. mL of solution?
Use mc006-1.jpg.
0.333 M
0.751 M
1.50 M
3.00 M

Answers

hi friend,

[tex]the \: answer \: is \: 3 \: molar[/tex]
the solution is as follows

[tex]moles \: of \: NaCl \: in \: the \: solution[/tex]

=
[tex]give \: mass \: of \: sodium \: chloride \\ - - - - - - - - - - - - - - - - \\ molecular \: mass \: of \: sodium \: chloride \: [/tex]

=
[tex] \: \: 87.75 \\ - - - - \\ \: \: 58.44[/tex]
[tex] = \: 1.501 \: moles[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: moles \: of \: solute \\ Molarity \: = \: \: \: \: \: - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: volume \: of \: solution(litrs)[/tex]
[tex]applying \: the \: formulae \: [/tex]
converting ml to litres

1.501/(500/1000)

1.501 X 2

3 M



Hope it helps


Answer: D on Edge :)

Explanation:

What is the maximum mass of sugar that could be dissolved in 1.3 l of water?

Answers

Answer is: the maximum mass of sugar that could be dissolved in 1.3 l of water in room temperature is 2652 grams.
The solubility of sugar in water in room temperature is 204 g/100 ml.
Make proportion, if 204 grams of sugar dissolve in 100 ml of water, than how much dissolve in 1300 ml of water:
204 g : 100 ml = m(sugar) : 1300 ml.
m(sugar) = 204 g · 1300 ml ÷ 100 ml.
m(sugar) = 2652 g ÷ 1000 g/kg = 2,652 kg.

Which of the following is an example of how science can solve social problems? It can stop excessive rain from occurring. It can identify the sources of polluted water. It can control the time and day when cyclones happen. It can reduce the frequency of severe weather conditions.

Answers

Answer: It can identify the sources of polluted water.

Scientific innovations and researches have been proved to be beneficial in solving the day to day social problems such as household practices such as cooking, washing of cloth, industrialization and conservation of the environment.

It can identify the sources of polluted water is the correct example of how science can solve social problems. The source of pollution can be identified by tracing back it's origin and application of filters and purifiers can help in controlling the pollution.

An example of how science can solve social problems is : ( B ) It can Identify the sources of polluted water

Scientific innovations

Several scientific innovations have made the identification and resolution of certain problems easier and one of such is the ability to Identify the dangers and sources of pollution.

Certain natural conditions such as excessive rain, cyclones and severe weather conditions can be identified but not stopped because they occur naturally.

Hence an example of how science can solve social problems is It can identify the sources of polluted water.

Learn more about Polluted water : https://brainly.com/question/1235358

Why is butyl iodide preferred over butyl chloride in a williamson ether synthesis?

Answers

In Williamson ether synthesis, the reaction begins when the hydrogen from the alcohol's hydroxyl group contacts the halogen ion. Since the iodide ion is larger than the chloride ion, there is a larger chance of collision between it and the hydrogen atom, so butyl iodide is preferred over butyl chloride.

Also, Williamson synthesis is carried out at relatively high temperatures, around 50ºC-100º C. Ethyl iodide has a boiling point of 72.2ºC, so it will be in the liquid phase. Ethyl chloride has a boiling point of 12.3ºC so it will be in the gaseous phase, which is undesirable for this.

Final answer:

Butyl iodide is used in Williamson ether synthesis due to iodide ion being a better leaving group than chloride, facilitating the formation of ethers more selectively and efficiently.

Explanation:

Butyl iodide is preferred over butyl chloride in a Williamson ether synthesis because of its ease in undergoing nucleophilic substitution due to the Iodide ion (I-) being a better leaving group than the Chloride ion (Cl-).

The Iodide ion is larger and more polarizable compared to chloride, which means the carbon-iodine bond can be more easily broken during the reaction, facilitating the formation of the ether product.

Additionally, iodide is a weaker base than chloride, which reduces the chance of side reactions such as elimination, leading to a more selective and efficient ether synthesis.

In which range of time do earthquakes occur? A. seconds B. days C. months D. millions of years

Answers

A) Seconds
Earthquakes are very frequent around the world

is the correct.......................

What bonds to cytosine (C) in DNA.

Answers

guanine is what bonds to it

The R-COOH compound behaves as an _____. acid base alcohol ester

Answers

the correct answer is base 

Answer: Option (a) is the correct answer.

Explanation:

An organic compound that contains "-COOH" as the function group is known as carboxylic compound.

A carboxylic compound is an acid as it dissociates to give hydrogen ion.

          [tex]R-COOH \rightarrow R-COO^{-} + H^{+}[/tex]

Whereas a compound with functional group "-OH" is known as alcohol.

And, a compound with general formula RCOOR' is known as an ester.

Thus, we can conclude that the R-COOH compound behaves as an acid.

Part a draw the major organic product formed when the compound shown below undergoes a reaction with an excess of etoh under acidic conditions.

Answers

Propanal undergoes nucleophilic addition with excess ethanol under acidic conditions, forming ethyl propanoate (ethyl propionate) and water through esterification.

Let's go into more detail about the reaction between propanal [tex](\(CH_3CH_2CHO\))[/tex] and ethanol [tex](\(EtOH\))[/tex] under acidic conditions.

1.  Nucleophilic Addition of Ethanol:

  - In the presence of an acid catalyst, such as sulfuric acid [tex](\(H_2SO_4\))[/tex], the carbonyl group of propanal undergoes nucleophilic addition with ethanol.

  - The oxygen in the carbonyl group acts as a nucleophile attacking the partially positive carbon of the carbonyl carbon.

 [tex]\[ \ce{CH3CH2CHO + EtOH} \xrightarrow{acid} \ce{CH3CH2COOCH2CH3} \][/tex]

2. Formation of Hemiacetal:

  - Initially, a hemiacetal is formed, which involves the addition of one molecule of ethanol to the carbonyl group.

[tex]\[ \ce{CH3CH2CHO + EtOH} \xrightarrow{acid} \ce{CH3CH(OH)CH2COOCH2CH3} \][/tex]

3. Formation of Acetal (Ester):

  - The hemiacetal formed can undergo another nucleophilic addition with a second molecule of ethanol, leading to the formation of the acetal (ester) and regeneration of the acid catalyst.

 [tex]\[ \ce{CH3CH(OH)CH2COOCH2CH3} \xrightarrow{acid} \ce{CH3CH2COOCH2CH3 + H2O} \][/tex]

4. Overall Reaction:

  - The overall reaction involves the addition of two molecules of ethanol to propanal, resulting in the formation of ethyl propanoate (ethyl propionate) and water.

[tex]\[ \ce{CH3CH2CHO + 2 EtOH} \xrightarrow{acid} \ce{CH3CH2COOCH2CH3 + H2O} \][/tex]

The ethyl propanoate formed is an ester, and this reaction is an example of an esterification reaction under acidic conditions. It's important to note that excess ethanol is used to drive the reaction to completion, and the acidic conditions help in the protonation and activation of the carbonyl group for nucleophilic attack by ethanol.

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