Answer:
=C₄H₄O₂
Explanation:
Given the empirical formula of a molecule, the he the quotient of the molecular mas and and the empirical mass=constant.
84.0 g/mol/mass of(C₂H₂O)=constant
=84/(12×2+1×2×16)
=84/42
=2
Therefore, the molecular formula is (C₂H₂O)₂=C₄H₄O₂
Answer:
[tex]C_2 H_2 O \times 2=C_4 H_4 O_2[/tex] is the molecular formula
Explanation:
Empirical formula is the simplest form of a Molecular formula.
For example
Molecular formula of glucose is [tex]C_6 H_{12} O_6[/tex]
Its empirical formula is [tex]C_1 H_2 O_1[/tex]
The subscript numbers of the molecular formula is divided by a common number n=6 here.
Another example:
Molecular formula of Octane is [tex]C_8 H_{18}[/tex] and Its empirical formula will be [tex]C_4 H_9[/tex]
Subscripts divided by n=2.
To find n we make use of the formula
[tex]\frac {(molecular mass )}{(empirical formula mass)}=n[/tex]
[tex]= \frac {84.0g}{(C_2H_2O mass)}\\\\=\frac {84.0g}{(24+2+16)g}=\frac {84.0g}{42g}=2[/tex]
So, we see n=2 here
Empirical formula × n = molecular formula
[tex]C_2 H_2 O \times 2=C_4 H_4 O_2[/tex] is the molecular formula
(Answer)
Please note:
Molar mass is the mass of 1 mole of the substance and its unit is g/mol .
n is the number of moles by which the empirical formula is multiplied to get the molecular formula of the compound.
Can you describe the situations when Greek prefixes are used?
Answer:
Here's what I get
Explanation:
At the introductory level of chemistry, I can think of only two situations when you use Greek prefixes.
They indicate the number of atoms or groups in a molecule when you are naming a compound.
1. Binary covalent compounds
For example, P₂S₅ is diphosphorus pentasulfide.
2. Hydrates
For example, Na₂SO₄·10H₂O is sodium sulfate decahydrate.
The Greek prefixes are used in naming different compounds such as binary compounds, complexes, hydrates of inorganic molecules, organic molecules, etc.
Explanation:
The Greek prefixes are used in naming different compounds. They are used to convey the number of atoms of elements present in the compound's molecule.For example: mono-(1), di-(2), tri-(3), tetra-(4), etcIn naming hydrates of ionic compounds.In naming binary compounds In the naming of organic molecules to convey the number of carbon atoms in the molecules.In the naming of complexes formed by the transition elementsLearn more about the use of greek prefixes in the naming of compounds here:
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If you have a 92.0 gram sample of water, then what mass of hydrogen and what mass of oxygen are in the sample? Make sure you answer in “grams” of Hydrogen and “grams” of Oxygen.
Answer:
[tex]\boxed{\text{10.29 g H and 81.71 g O}}[/tex]
Explanation:
The formula of water is H₂O.
1. Calculate the molar mass of water
2 H = 2 × 1.008 = 2.016 u
1 O = 1 × 16.00 = 16.00 u
MM = 18.02 u
2. Mass of hydrogen
\text{Mass of H} = \text{92.0 g water} \times \dfrac{\text{2.016 g H}}{\text{18.02 g water }} = \textbf{10.29 g[tex]\text{Mass of H} = \text{92.0 g water} \times \dfrac{\text{2.016 g H}}{\text{18.02 g water }} = \textbf{10.29 g H}[/tex] H}
3. Mass of 0xygen
[tex]\text{Mass of O} = \text{92.0 g water} \times \dfrac{\text{16.00 g H}}{\text{18.02 g water }} = \textbf{81.71 g O}\\\\\text{The masses are } \boxed{\textbf{10.29 g H and 81.71 g O}}[/tex]
A 92 gram sample of water will consist of approximately 10.22 grams of hydrogen and 81.78 grams of oxygen.
Explanation:Water
consists of two hydrogen atoms and one oxygen atom. Therefore, it has a
molecular formula of H2O
. To find the mass of each element in a 92 gram sample, we need to know the molar mass of the elements and the compound. The molar mass of hydrogen (H) is about 1 gram per mole, and oxygen (O) has a molar mass of 16 grams per mole. So, the molar mass of water (H2O) is approximately 18 grams per mole (2*1 + 16). This means that in one mole of water, 2 grams are hydrogen and 16 grams are oxygen. If we scale this up to 92 grams, we find that there are approximately 10.22 grams of hydrogen and 81.78 grams of oxygen.
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How would the number of moles (n) of O2 change if the atmospheric pressure doubled but all variables stayed the same?
Answer:
The no. of moles will be doubled as the pressure is doubled.
Explanation:
We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
If V and T are constant, and have different values of P and n:(P₁n₂) = (P₂n₁).
P₂ = 2P₁,
∴ n₂ = (P₂n₁)/(P₁) = (2P₁n₁)/(P₁) = 2n₁.
So, the no. of moles will be doubled as the pressure is doubled.
The number of moles (n) of O2 would remain unchanged if the atmospheric pressure doubled but all other variables, such as temperature, volume, and the amount of gas, stayed the same.
According to the Ideal Gas Law, the relationship between pressure (P), volume (V), number of moles (n), and temperature (T) is given by:
[tex]\[ PV = nRT \][/tex]
where R is the ideal gas constant.
If the atmospheric pressure doubles, we can denote the new pressure as [tex]\( 2P \)[/tex]. Assuming that the volume (V), temperature (T), and the amount of gas (n) remain constant, the Ideal Gas Law for the new conditions would be:
[tex]\[ (2P)V = nRT \][/tex]
Since the volume (V), temperature (T), and the gas constant (R) are unchanged, the equation simplifies to:
[tex]\[ 2PV = nRT \][/tex]
Comparing this to the original Ideal Gas Law [tex]\( PV = nRT \),[/tex] we can see that the number of moles (n) does not change. The pressure and volume are directly proportional to each other according to Boyle's Law, which is a special case of the Ideal Gas Law when temperature and number of moles are constant. Therefore, if the volume were to decrease by half to maintain the relationship [tex]\( PV = nRT \)[/tex], the number of moles would remain the same. However, if the volume is not changed and only the pressure is doubled, the equation does not hold true unless the number of moles is also doubled. But in the context of the atmosphere, the volume would naturally decrease as the pressure increases (assuming a closed system), and thus the number of moles of O2 would not change.
A container of carbon dioxide (CO2) has an initial temperature of 170 K with a pressure of 50 kPa. When the container is heated the pressure is measured at 283 kPa. The volume is constant at 12 L throughout. What is the final temperature of the carbon dioxide (CO2)?
A. 391.0 K
B. 1179.16 K
C. 6.94 K
D. 962.2 K
Answer:
[tex]\boxed{\text{D. 962 K}}[/tex]
Explanation:
The volume and number of moles are constant, so we can use Gay-Lussac’s Law:
At constant volume, the pressure exerted by a gas is directly proportional to its temperature.
[tex]\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}[/tex]
Data:
p₁ = 50 KPa; T₁ = 170 K
p₂ = 283 KPa; T₂ = ?
Calculations:
[tex]\begin{array}{rcl}\dfrac{50}{170} & = & \dfrac{283}{T_{2}}\\\\0.294 & = & \dfrac{283}{T_{2}}\\\\0.294T_{2} & = & 283\\\\T_{2} & = &\dfrac{283}{0.294}\\\\ & = &\textbf{962 K}\\\end{array}\\\text{The final temperature of the carbon dioxide is }\boxed{\textbf{962 K}}[/tex]
Examine the chemical formula.
CS2
Which answer choice lists this compound's chemical name?
carbon disulfate
carbon bisulfate
carbon disulfide
carbon bisulfide
Answer:
Carbon disulfide
Explanation:
Carbon disulfide is the chemical name of the compound, CS2.
Carbon disulfide is a clear or colorless liquid that is often used in organic chemistry.
The bonds in the reactants of a chemical reaction store 710 kj of potential energy.The bonds in the products of the reaction store 641 kj of potential energy. Is the reaction endothermic or exothermic? explain please
Answer:
Exothermic
Explanation:
Well as we can, see the energy decreases when it changes from reactant to product.
Endothermic reactions involve the absorption of energy from the surroundings (meaning there would be in an increase in energy)
Exothermic reactions involve the energy being released into the surroundings (meaning there would be a lost in energy)
Therefore, the reaction is exothermic.
Velocity is the slope of the acceleration vs. time graph.
O
A. True
False
Answer:
False
Explanation:
The slope of a velocity-time graph gives acceleration. Acceleration can be defined as the change in velocity with time.
A slope denotes the gradient of line. It takes into consideration the changes on both y and x axis. The ratio of the changes gives the slope.
On a velocity-time graph, the y-axis is the velocity and the x-axis is time. The change in velocity with time gives acceleration.
The slope of an acceleration
-time graph is not velocity.
Force 1: The squeezing force applied to remove water from a wet cloth Force 2: The gravitational force exerted by Earth on the moon Which statement is true about the forces? (3 points) Question 5 options: 1) Both are contact forces. 2) Both are non-contact forces. 3) Force 1 is a contact force and Force 2 is a non-contact force. 4) Force 1 is a non-contact force and Force 2 is a contact force.
Answer:
3) Force 1 is a contact force and Force 2 is a non-contact force.
Explanation:
Force is a phenomenon that causes a change in phsical quantity. It is expressed as the product of mass and acceleration.
Contact force is a type force that involves physical contact between two bodies or more. An example is the pulling of a cart. Also, when the wet clothe is being squeeze, a physical contact is established.
Non-contact force occurs between bodies in which there is no physical contact. An example is gravitational force of attraction between two bodies.
How many molecules of sodium oxide will be created if 275 grams of sodium reacts with excess oxygen?
Given the equation: 4Na + O2 -> 2Na2O
Given 275 grams of sodium, approximately 3.6 x 10^24 molecules of sodium oxide are created when this reacts with excess oxygen, as per the provided balanced chemical equation.
Explanation:To find out how many molecules of sodium oxide will be created, we need to first calculate the number of moles of sodium being reacted. Given that the molar mass of sodium is about 23g/mol, if we have 275 grams of sodium, that would translate to about 275/23 = 11.96 moles of sodium.
Using the molar ratio in the balanced chemical equation, 4 moles of sodium produce 2 moles of sodium oxide. So, 11.96 moles of sodium would produce 11.96/4 * 2 = 5.98 moles of sodium oxide.
Avogadro's number tells us that one mole of any substance contains 6.022 x 1023 molecules. Therefore, 5.98 moles of sodium oxide would contain 5.98 * 6.022 x 1023 = 3.6 x 1024 molecules of sodium oxide.
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When 275 grams of sodium reacts with excess oxygen, approximately 3.6 x 10^24 molecules of sodium oxide will be created.
Explanation:To determine the number of molecules of sodium oxide produced, we need to use the given equation balanced equation 4Na + O2 -> 2Na2O. The molar mass of sodium (Na) is 22.99 g/mol and the molar mass of sodium oxide (Na2O) is 61.98 g/mol. We can use these molar masses and the given mass of sodium to calculate the number of moles of sodium, and then use the stoichiometric coefficients in the balanced equation to find the number of moles of sodium oxide produced. Finally, we can convert the number of moles to molecules using Avogadro's number (6.022 x 10^23).
First, we calculate the number of moles of sodium using the formula:
Moles = Mass / Molar mass
Moles of sodium = 275 g / 22.99 g/mol = 11.97 mol (approximately)
According to the balanced equation, 4 moles of sodium react to form 2 moles of sodium oxide. So, using the molar ratio, we can determine the number of moles of sodium oxide produced:
Moles of sodium oxide = 2/4 * 11.97 mol = 5.98 mol (approximately)
Finally, we can convert the number of moles of sodium oxide to molecules using Avogadro's number:
Number of molecules of sodium oxide = Moles of sodium oxide * Avogadro's number
Number of molecules of sodium oxide = 5.98 mol * 6.022 x 10^23 molecules/mol = 3.6 x 10^24 molecules
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Which statement best describes the role of plants in the water and carbon cycles?
Plants release oxygen when they decompose take in oxygen for photosynthesis.
Plants take in carbon dioxide during photosynthesis and absorb water through their leaves and roots.
Plants take in oxygen during photosynthesis and absorb carbon dioxide through their leaves and roots.
Plants use oxygen to perform photosynthesis and release carbon dioxide as a by-product.
Answer: Option B
Explanation:
The plants uses sunlight to convert carbon dioxide and water into more complex carbohydrate known as glucose.
Plants utilize carbon dioxide during photosynthesis. Plants absorb water through roots and leaves.
Plants release oxygen as a by-product which is used by animals and other organism.
The carbohydrates inside the plants is broken down into simpler form and the energy released is used by plants for its cellular processes. This is known as cellular respiration.
Answer:
Plants take in carbon dioxide during photosynthesis and absorb water through their leaves and roots.
Which equation using element symbols correctly describes the reaction: "One molecule of methane plus two molecules of diatomic oxygen react to form two molecules of water and one molecule of carbon dioxide?"
A. CH4+2O2+2H2O→CO2
B. 2H2O+CO2→CH4+2O2
C. CH4+2O2→2H2O+CO2
D. CO2+2O2→2H2O+CO2
Answer:
C. CH₄+2O₂ →2H₂O+CO₂
Explanation:
This is a popular combustion reaction.
C. CH₄+2O₂ →2H₂O+CO₂
In combustion, hydrocarbons burn in the presence of oxygen gas and they produce water and carbon dioxide only. The process is accompanied with the release of energy.
We simply say for the above reaction that:
One molecule of methane(CH₄) reacts with two molecules of oxygen gas(O₂) to produce two molecules of water(H₂O) and one molecule of carbon dioxide only
Answer:
the answer is C
Explanation:
because I just took the a quiz with this same question and it was right.
Write the complete, balanced equation for the reaction between iron (III) oxide and carbon monoxide.
Answer:
Fe(iii)2O3 + 3CO ===> 2Fe + 3CO2
Explanation:
Fe(iii)2O3 + CO ===> Fe + CO2
The best thing to do is start with the Oxygens. They are the most complicated.
Fe(iii)2O3 + 3 CO ===> Fe + 3 CO2
Unfortunately this equation is a bit of by guess and by gosh. You need to balance the oxygens so that the total is an even number. That's because the right hand side is always going to be even. [The 2 on CO2 will make anything in front of it even).
So there are 6 oxygens on the left and 6 on the right. The carbons by accident are balanced with this maneuver. So all that is left is the irons.
Fe(iii)2O3 + 3CO ===> 2Fe + 3CO2
This equation is a bit nasty, but in higher chemistry courses, you will learn how to make it a whole lot simpler. For now you are just going to have to put up with the nastiness of the question and guess.
Which of the following is a base?
O
A. HNO3 (nitric acid)
O
B. HI (hydroiodic acid)
O
C. H2CO3 (carbonic acid)
O
D. Ca(OH)2 (calcium hydroxide)
Answer:
Ca (oh)2 (calcium hydroxide)
Explanation:
a.p.e.x
Ca(OH)2 (calcium hydroxide) is a base.
Is Ca acidic or basic?
Calcium, strontium, barium, and radium are always considered to be alkaline earth metals; the lighter beryllium and magnesium, also in group 2 of the periodic table, are often included as well.
Is calcium hydroxide a strong or weak base?Calcium hydroxide is a strong base. Since it produces OH- ions on electrolyte dissociation.
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A __________ is a natural or human-made body of water surrounded by land.
dune
glacier
hill
lake
Answer:
Lake
Explanation:
Yeah...not much else to say honestly
Answer:
Lake is the answer :))
what is silicon used for?
-matches
-gunpowder
-glass
-steel can coating
Answer:
Silicon can be used to make glass. So your 3rd option.
Explanation:
Sue used the following method to convert 5 g/gal to oz/m^3.
((5 g) / (1 gal)) x ((1 gal/ (0.00378541 m^3)) x ((1 m^3) / (28.3495 g)) = 45.59 oz/m^3
(1 gal = 0.00378541 m^3 and 1 oz = 28.3495 g)
What is the error in Sue’s conversion method?
A. 0.00378541 m^3 should be written as 0.00378541 gal.
B. 28.3495 g should be written as 28.3495 oz.
C. 5 g should be written as 5 oz.
D. 1 m^3 should be written as 1 oz.
Answer:
The correct answer is option D.
Explanation:
5 g/gal to [tex]oz/m^3[/tex]
[tex]1 gal = 0.00378541 m^3[/tex]
[tex]1 oz = 28.3495 g[/tex]
[tex]\frac{5g}{1 gal}\times \frac{1 gal}{0.00378541 m^3}\times \frac{1 m^3}{28.3495 g}=45.59 [/tex] unitless (not possible)
Common unit present in denominator and numerator will get cancelled.
[tex]\frac{5g}{1 gal}\times \frac{1 gal}{0.00378541 m^3}\times \frac{1 oz}{28.3495 g}=46.59 oz/m^3[/tex]
The error in the conversion was instead of [tex]1 m^3[/tex] 1 oz should be written.
The correct answer is D.
The conversion of 5 g/gal to oz/m^3 is as follows:-
Given:-1 gal = 0.00378541 m^3
1 oz = 28.3495 g
Accoring to sue:-
[tex]\frac{5\ g}{1\ gal} \times\frac{1\ gal}{0.00378541\ m^{3} }\times\frac{1\ m^{3}}{28.3495\ g} \\=45.59[/tex]
Common units present in numerator and denominator will get canceled.
The correct conversion is as follows:-
[tex]\frac{5\ g}{1\ gal} \times\frac{1\ gal}{0.00378541\ m^{3} }\times\frac{1\ oz}{28.3495\ g} \\=45.59\ oz/m^{3}[/tex]
The error in the conversion was instead of [tex]1\ m^{3}[/tex], 1 oz should be written.
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2. How many nanometers are in 5.6 x 10-4 meters?
Answer:
[tex]\boxed{5.6 \times 10^{5}\text{ nm}}[/tex]
Explanation:
1 nm = 10⁻⁹ m
[tex]5.6 \times 10^{-4}\text{ m} \times \dfrac{\text{1 nm}}{10^{-9}\text{ m}} = \mathbf{5.6 \times 10^{5}}\textbf{ nm}\\\\\text{There are } \boxed{\mathbf{5.6 \times 10^{5}}\textbf{ nm}} \text{ in 5.6 $\times 10^{-4}$ m}[/tex]
5.4 × [tex]10^{5}[/tex] nanometers are in 5.6 x [tex]10^{-4}[/tex] meters
Calculation,
Since, 1 nanometer = [tex]10^{-9}[/tex] meter.
1 meter = [tex]10^{9}[/tex] nanometer
5.6 x [tex]10^{-4}[/tex] meters = 5.6 x [tex]10^{-4}[/tex] × [tex]10^{9}[/tex] nanometer = 5.4 × [tex]10^{5}[/tex] nanometer
What is unit of length or distance?The distance or length can be measured by many units like,
Picometer, Nanometer, micrometer, milimeter, centimeter, meter and kilometer.The largest unit is kilometer.The standard unit of length is meter.learn about nanometer,
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Try try try please for me please
Answer:
a.) It is a chemical reaction because a new substance was formed and a colour change occurred in the reaction.
b.) Iron- Metallic element
sulpher- Non-Metalic element
Iron Sulphide- Compound
HOPE IT HELPS....
An acid without
oxygen EXCEPT HCI
HF hydrofluoric acid
HBr hydrobromic acid
HI hydroiodic acid
H₂S hydrogen sulfide
Which physical method can be used for obtaining a sample of salt from a small beaker of salt water?
boiling
freezing
chromatography
sorting
Answer:
Boiling.
Explanation:
Solution is a uniform composition and can be separated by physical methods.Boiling is the process of fast evaporation of water, that a liquid is boiled to its boiling point.Boiling point is the temperature at which the condensation pressure of the liquid is equal to the force used on the liquid by the nearby environment.Boil the water till complete water evaporation, water evaporates and salt remain in the beaker.So, the right choice is: Boiling.
Answer:
A. Boiling
Explanation:
Just tested
What is the name of solution who’s classification of salute is equal to the maximum concentration
Answer:
Saturated solution.
Hope this helps!
Answer:
saturated
Explanation:
oh i love xxxtentacion
What is the empirical formula of C6H12O6?
Answer:
C6H12O6 is the molecular formula, which can either be equivalent to the empirical formula or an integer n multiple of the empirical formula. In this case, n is equal to 6. The empirical formula of glucose C6H12O6 is CH2O . It indicates that the ratio of C,HandO atoms in a molecule of glucose is 1:2:1.
Explanation:
The empirical formula of C₆H₁₂O₆ is CH₂O.
The empirical formula represents the simplest whole-number ratio of atoms in a compound.
To determine the empirical formula of C₆H₁₂O₆, find the lowest whole number ratio of carbon (C), hydrogen (H), and oxygen (O) atoms.
To simplify the ratio, divide each subscript by the greatest common divisor (GCD) of all the subscripts.
The GCD of 6, 12, and 6 is 6. Dividing each subscript by 6, we get:
C₆H₁₂O₆ ⇒ (6/6)C (12/6)H (6/6)O ⇒ C₁H₂O₁
Therefore, the empirical formula of C₆H₁₂O₆ is CH₂O.
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Are elements with similar chemical properties found in the same period or group on the periodic table?
A.
period
B.
group
The elements with similar chemical properties are found in the same group of the periodic table. Thus, the correct option is B.
What are chemical properties?Chemical properties may be defined as those properties of matter or substances that can be observed in a chemical reaction. Some of them are flammability, toxicity, the heat of combustion, pH value, rate of radioactive decay, chemical stability, etc.
The groups are arranged vertically in a periodic table that shares identical chemical properties of the elements. There are 18 groups present in the modern periodic table.
Each group of the periodic table illustrates its own unique properties in terms of valance shell, electron, identity, and reactivity. For example, group 17 is known as halogen.
Therefore, the elements with similar chemical properties are found in the same group of the periodic table. Thus, the correct option is B.
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What information does the activity series of metals give?
A. It predicts if one metal will replace another metal in a compound.
B. It identifies which metals have the highest electronegativities.
C. It gives the ionic charges of most metals on the periodic table.
D. It tells which metals will react with nonmetals to form compounds.
Answer:
The answer is A.It predicts if one metal will replace another metal in a compound.
Explanation:
I did quiz.
The activity series of metals predicts if one metal will replace another metal in a compound.
Hence, Option (A) is correct answer.
What is Metal ?Metals are good conductor of heat. It have high density. Metals are ductile. Metals are malleable.
What is Reactivity series of metal ?Reactivity series of metals is also called the activity series of metals. Reactivity series of metal includes oxidation reaction of each metal to the metal ion. It gives the information about the reaction of metals with water and acids. Reactivity series can be used to predict whether the metal will replace another metal in the compound.
Thus from the above conclusion we can say that The activity series of metals predicts if one metal will replace another metal in a compound.
Hence, Option (A) is correct answer.
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A penny has a total mass of 3.1 grams. Zinc makes up 2.9 g of the penny. What is the percentage of zinc in the penny?
Answer: 93.54%
Explanation: Divide the mass of the zinc by the total mass of the penny.
2.9/3.1=0.9354
To get to a percent, multiply by 100.
0.9354 x 100 = 93.54
The mass of the zinc in the penny is 93.54%.
93.54% of zinc in the penny when a penny has a total mass of 3.1 grams and zinc makes up 2.9 g of the penny.
What is mass?Mass is simply the measure of the amount of matter in a body.
Divide the mass of the zinc by the total mass of the penny.
[tex]\frac{Mass \;of \;zinc}{Total \;mass}[/tex]
[tex]\frac{2.9}{3.1}[/tex]
=0.9354
To get to a percent, multiply by 100.
0.9354 x 100 = 93.54
Thus, the mass of the zinc in the penny is 93.54%.
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What is the percent composition of NaHCO3?
23.20% Na, 4.26% H, 18.41% C, and 54.13% O
24.21% Na, 4.35% H, 12.26% C, and 59.18% O
27.36% Na, 1.20% H, 14.30% C, and 57.14% O
30.44% Na, 2.12% H, 10.25% C, and 60.19% O
Answer:
Option-C (27.36% Na, 1.20% H, 14.30% C, and 57.14% O)
Explanation:
Percent Composition is defined as the %age by mass of each element present in a compound. Therefore, it is a relative amount of each element present in a compound.
Calculating Percent Composition of NaHCO₃:
1: Calculating Molar Masses of all elements present in NaHCO₃:
a) Na = 22.99 g/mol
b) H = 1.01 g/mol
c) C = 12.01 g/mol
d) O₃ = 16.0 × 3 = 48 g/mol
2: Calculating Molecular Mass of NaHCO₃:
Na = 22.99 g/mol
H = 1.01 g/mol
C = 12.01 g/mol
O₃ = 48 g/mol
----------------------------------
Total 84.01 g/mol
3: Divide each element's molar mass by molar mass of NaHCO₃ and multiply it by 100:
For Na:
= 22.99 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100
= 27.36 %
For H:
= 1.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100
= 1.20 %
For C:
= 12.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100
= 14.29 % ≈ 14.30 %
For O:
= 48.0 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100
= 57.13 % ≈ 57.14 %
Answer:
Great Explanation and Answer Above, Just confirming its the correct answer.
Hope This Helps!
C: 27.36% Na, 1.20% H, 14.30% C, and 57.14% O
Explanation:
Four (4.0) liters of helium gas are stored at 125 atm pressure. If the temperature and number of particles do not change, what will be the new volume when the pressure is decreased to 50 atm? Show your work.
Please answer ASAP!!
Answer:
10 L
Explanation:
The only variables are pressure and volume, so we can use Boyle's Law:
p1V1 = p2V2
Data:
p1 = 125 atm; V1 = 4.0 L
p2 = 50 atm; V2 = ?
Calculation:
125 × 4.0 = 50V2
500 = 50 V2
V2 = 500/50 = 10 L
The new volume will be 10 L.
The levels of nitrogen and _______ in the atmosphere remain fairly constant, but the levels of the other gases may vary. _______, such as carbon dioxide and water vapor, are known to trap heat in Earth's atmosphere. Particles of solids and liquids floating in the atmosphere are known as _______. The upper boundary of the troposphere is called the _______. Ozone gas heats the stratosphere by absorbing _______ rays from the Sun. The International Space Station (ISS) orbits Earth in the _______. In the atmosphere, the _______ has no upper boundary and just fades into space. When you place your hand near a candle flame, your hand will get warm due to _______. If you place one end of a metal rod in a fire, the other end will eventually get hot due to _______. Boiling water on the stove is an example of the transfer of thermal energy via _______.
Answer:
oxygen
Greenhouse gases
aerosols
tropopause
ultraviolet
thermosphere
exosphere
radiation
conduction
convection
Answer:
oxygen
Greenhouse gases
aerosols
tropopause
ultraviolet
thermosphere
exosphere
radiation
conduction
convection
Explanation:
According to the kinetic-molecular theory, the average kinetic energy of gas
s depends on which factor?
volume
pressure
temperature
number of particles
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Answer:
The average kinetic energy of a gas depends only on its temperature.
Explanation:
The average kinetic energy of particles in a gas can be found using the equation
[tex]\displaystyle \text{Average K.E.} = \frac{3}{2}k\cdot T[/tex],
where
[tex]k[/tex] is the Stefan-Boltzmann constant, and[tex]T[/tex] is the absolute temperature of this gas (the one in degree Kelvins.)As seen in this equation, the average kinetic energy of particles in a gas depends only on the temperature of the gas. Also, since the question is asking for the average not the total kinetic energy, the number of particles in this gas doesn't matter, either.
Answer:
The answer is temperature. Edge 2020
Explanation:
Consider the following equation.
Fe2O3(s) + 3H2(g) → 2Fe(s) + 3H2O(g)
H = 98.8 kJ, and S = 141.5 J/K. Is this reaction spontaneous or nonspontaneous at high and low temperatures?
A. spontaneous at high temperatures, non-spontaneous at low temperatures
B. Non-spontaneous at high and low temperatures
C. Spontaneous at low temperatures, non-spontaneous at high temperatures
D. Spontaneous at high and low temperatures
Answer:
This reaction is A. Spontaneous at high temperatures, and non-spontaneous at low temperatures.
Explanation:
Both the enthalpy change [tex]\Delta H[/tex] and the entropy change [tex]\Delta S[/tex] due to this reaction are positive. A chemical reaction will be spontaneous only if the change in its Gibbs Free Energy [tex]\Delta G = \Delta H - T \cdot \Delta S[/tex] is negative. [tex]T[/tex] is the absolute temperature in degrees Kelvins.
Assume that both [tex]\Delta H[/tex] and [tex]\Delta S[/tex] doesn't change much as [tex]T[/tex] increases. The value of [tex]\Delta G[/tex] will initially be close to [tex]\Delta H[/tex] when [tex]T[/tex] is small. The sign of [tex]\Delta G[/tex] will depends on that of [tex]\Delta H[/tex]. However, [tex]\Delta H[/tex] is positive, so at low temperatures [tex]\Delta G[/tex] will be positive and the reaction will be non-spontaneous.
However, as [tex]T[/tex] increases, the role of entropy change becomes more significant. The sign of [tex]\Delta G[/tex] will eventually be the opposite of [tex]\Delta S[/tex]. The value of [tex]\Delta G[/tex] will eventually drop below zero after the value of [tex]T[/tex] rises above [tex]\Delta H / \Delta S[/tex]. The reaction will eventually become spontaneous.
Answer:
A.) spontaneous at high temperatures, non-spontaneous at low temperatures
Explanation:
Edge2021