Answer:
A negative charge
Explanation:
If there is an excess of electrons in a substance, this will have a negative net charge. This is because electrons have negative charge
q = -1.67*10^{-19}
each electron will contribute with this charge to the total negative net charge of the substance.
hence, the answer is "A negative charge"
A substance with an excess number of electrons on its surface has a negative charge due to the negatively charged nature of electrons.
If a substance has an excess number of electrons on its surface, it will have a negative charge. This is because electrons have a negative charge, and having more electrons than protons results in a net negative charge for the substance. By contrast, if a substance had more protons than electrons, it would have a positive charge. Substances are typically electrically neutral when the number of electrons equals the number of protons, and this balance means there is no net electric charge.
An atom that gains one or more electrons will exhibit a negative charge and is called an anion. Conversely, when an atom loses one or more electrons, it becomes a positively charged atom, also known as a cation. For instance, when a neutral sodium atom loses one electron, it becomes a sodium cation with a 1+ charge. Conversely, an oxygen atom that gains two electrons becomes an anion with a 2- charge.
a force sets an object in motion. when the force is multiplied by the time of its application we call the quantity impulse which changes the momentum of that object. what do we call the quantity force x (times) distance, and what quantity can this change?
Answer:
Work done
Explanation:
Impulse of an object is given by the product of force and time. It is also equal to the change on momentum of an object. The quantity that is given by the product of force and distance is called work done by an object.Work done also depends on the angle between force and displacement.The work done on an object is given as the product of force and distance traveled by the object.
What is impulse?Impulse is the force applied to an object for a certain period of time
J = Ft (Ns)
The change in the momentum of an object is equal to the impulse experienced by the object.
The work done on an object is given as the product of force and distance traveled by the object.
W = Fd (J)
The work done on an object causes change in the position of the object.
Learn more about work done here: https://brainly.com/question/8119756
Soccer ball is heading east positive direction with momentum of 2kgm/s. It is kicked backwards and a fraction of a second later is moving west negative direction withmomentum of -2.3. What impulse did the kicker put on the ball on kgm/s?
Answer:
-4.3 kgm/s
Explanation:
Impulse which the soccer ball experiences is equal to the change in momentum of a body.
It is given mathematically as:
Impulse = m*Δv = [tex]mv - mu[/tex]
Initial momentum of soccer ball = 2 kgm/s
Final momentum of the soccer ball = -2.3 kgm/s
Therefore, Impulse will be:
Impulse = [tex]-2.3 - 2[/tex]
Impulse = [tex]-4.3 kgm/s[/tex]
The impulse put on the soccer ball by the kicker is -4.3 kgm/s.
The highest waterfall in the world is the Salto Angel in Venezuela. Its longest single falls has a height of 807 m. If water at the top of the falls is at 14.2°C, what is the maximum temperature of the water at the bottom of the falls? Assume all the kinetic energy of the water as it reaches the bottom goes into raising its temperature.
Answer:
Maximum temperature of the water at the bottom of the fall, θ₂ = 16.09°C
Explanation:
The height of the waterfall, H = 807 m
At the top of the fall, [tex]\theta_{1} = 14.2^{0} C[/tex]
For water, the specific heat capacity, C = 4200 J/kg/°C
Potential energy at the top of the waterfall, PE = mgH
According to the principle of conservation of energy,
Kinetic energy at the bottom of the waterfall = Potential energy at the top
Therefore, KE = mgh
Applying the conservation of energy again,
KE at the bottom = Heat Energy due to raise in temperature
Heat energy due to raise in temperature = MCΔθ
MCΔθ = MgH
CΔθ = gH
Δθ = gH/C
Δθ = (9.81*807)/4200
Δθ = 1.89°C
[tex]\triangle \theta = \theta_{2} - \theta_{1}[/tex]
1.89 = θ₂ - 14.2
θ₂ = 14.2 + 1.89
θ₂ = 16.09°C
Label the parts that make up the human heart. Drag the items on the left to the correct location on the right.
A firefighter who weighs 192 lb slides down an infinitely long fire pole that exerts a friction resistive force with magnitude proportional to his speed, with k D 2:5 lb-s/ft. Assuming that he starts from rest, find his velocity as a function of time and find his terminal velocity
Answer:
Explanation:
check the pictures attached to further understand and i hope it works
Answer:
[tex]v = \frac{-384}{5} (1 - \frac{12}{5} e^{ -5t/12})[/tex]
Explanation:
Weight of the firefighter, W = 192 lb
W = mg
g = 32 ft/s²
Mass of the firefighter, m = W/g
m = 192/32
m = 6 slugs
k = 2.5 lb-s/ft
The force, F = ma = kv
2.5v = 6a
a = 2.5v/6
a = 5v/12
The fundamental dynamic equation;
dv/dt + drag + gravity = 0
dv/dt = -g-a
dv/dt = -32-5v/12..............(a)
The motion will attain terminal velocity when dv/dt = 0
-32 - 5v/12 = 0
-32 = 5v/12
-384 = 5v
v₀ = -384/5
v₀ = -384/5
dv/dt = -32 - 5v/12
[tex]\frac{dv}{-32 -5v/12} = dt[/tex]
[tex]-12/5 ln(32 + 5v/12) = t + c\\ln(32 + 5v/12) = -5t/12 + lnc\\ln(32 + 5v/12) - ln c = -5t/12\\ln\frac{32 + 5v/12}{c} = -5t/12[/tex]
Take exponential of both sides
[tex]\frac{32 + 5v/12}{c} =e^{ -5t/12}\\32 + 5v/12 = ce^{ -5t/12}\\5v/12 = -32 + ce^{ -5t/12}\\v = 12/5 (-32 + ce^{ -5t/12})\\[/tex]
c = v₀ = -384/5
[tex]v = 12/5 (-32 - \frac{384}{5} e^{ -5t/12})\\v = \frac{-384}{5} (1 - \frac{12}{5} e^{ -5t/12})[/tex]
A solution that contains the maximum amount of solute for a given amount of solvent at a particular temperature is called
Answer:
saturated solution is the correct answer.
Explanation:
A saturated solution is a chemical solution, comprised of solute and solvent and in which no more further solute can dissolve in the solvent.A saturated solution contains the highest concentration of solute dissolved in a solvent.factors affecting the saturation solution are: the solution's temperature and pressure and also chemical composition of the substance addAn example of a saturated solution is carbonated water.What must be included when describing the displacement of an object?
Answer:
Measurement and Direction
Explanation:
Displacement is a vector quantity because it has magnitude (the measure o displacement)
Answer:
Measurement and direction.
Explanation:
Technician A says that with a properly operating air-conditioning system, the inlet to the compressor should be cold and the outlet from the compressor hot. Technician B says that the condenser should be hot and the evaporator cold. Which technician is correct?
Answer:
Only technician A is correct
Explanation:
Analysis of technician A's statements
The refrigeration cycle contains four major components: the compressor, condenser, expansion device, and evaporator. Refrigerant remains piped between these four components and is contained in the refrigerant loop.
The refrigerant begins as a cool vapor and heads to the first component:
1. the compressor
It forces the refrigerant through the system. In the process of being compressed the cool, gaseous refrigerant is turned to a very hot and high-pressure vapor.
Analysis of technician B's statement
The condenser’s job is to cool the refrigerant so that it turns from a gas into a liquid, or condenses. This happens when warm outdoor air is blown across the condenser coil that is filled with hot, gaseous refrigerant.
The evaporator is responsible for cooling the air going to the space by boiling (evaporating) the refrigerant flowing through it. This happens when warm air is blown across the evaporator as cold refrigerant moves through the evaporator coil. Heat transfers from the air to the refrigerant, which cools the air directly before it is vented to the space.
A wire runs left to right and carries a current in the direction shown.
A horizontal line representing a wire. There is a vector right labeled I. There is a point labeled Z below the line.
What is the direction of the magnetic field at point Z?
Answer (C)
Explanation:HOPE THIS HELPS
The direction of the magnetic field at point Z is into the page.
What is magnetic field?The magnetic field is the region of space where a charged object experiences magnetic force when it is moving.
When a charged particle such as an electron or proton moves inside a conductor, magnetic lines of force rotate around the particle. Since, this relative motion caused the magnetic field to generate.
A wire runs left to right and carries a current in the direction shown (attached diagram).
A horizontal line representing a wire. There is a vector right labeled I. There is a point labeled Z below the line.
According to the Fleming's right hand rule, the direction of magnetic field is into the page.
Thus, the direction of the magnetic field at point Z is into the page.
Learn more about magnetic field.
https://brainly.com/question/14848188
#SPJ5
Which of the following situations would produce an average velocity of zero?
A) a round-trip to school and back
B) a horse galloping in a field
C) the criss-crossing path of a flying bug
D) a trip, first to the moon, then onto Mars
A long string carries a wave; a 7.00-m segment of the string contains five complete wavelengths and has a mass of 180 g. The string vibrates sinusoidally with a frequency of 55.0 Hz and a peak-to-valley displacement of 20.0 cm. (The "peak-to-valley" distance is the vertical distance from the farthest positive position to the farthest negative position.)(a) Write the function that describes this wave traveling in the positive x direction. (Use the following as necessary: x and t. x is in meters and t is in seconds.)y =
Answer:
y = 0.1sin(4.5x - 345.6t)
Explanation:
Parameters given:
Length of 5 wavelengths = 7 m
Length of one wavelength, λ = 7/5 = 1.4 m
Frequency of wave, f = 55 Hz
Peak to Valley displacement = 20 cm = 0.2 m
Amplitude is half of the Peak to Valley displacement = 0.1 m
The wave function of a wave traveling in the positive x direction is given generally as:
y = Asin(kx - wt)
Where A = amplitude
k = Wave factor = 2π/λ
x = displacement on the x axis
w = angular frequency = 2πf
t = time taken
=> Wave factor, k = 2π/λ = 2π/(1.4) = 4.5 m^(-1)
=> Angular frequency, w = 2πf = 2π * 55 = 345.6 Hz
Therefore, inserting all the necessary parameters, we get that the wave function is:
y = 0.1sin(4.5x - 345.6t)
A 65kg teacher (including the parachute) is skydiving! As the parachute opens, the system experiences a 1200N drag.
How many forces are acting on the system?
What is the magnitude of the net force on the system?
What is the magnitude of the system's acceleration?
Describe the system's speed:
1) 2 Forces
2) 563 N, upward
3) [tex]8.66 m/s^2[/tex], upward
4) Speed is decreasing
Explanation:
1)
There are two forces acting on teacher during his skydiving:
- The force of gravity (also known as weight), acting downward (towards the Earth's centre), of magnitude
[tex]W=mg[/tex]
where
m is the mass of the teacher
g is the acceleration due to gravity
- The air resistance, of magnitude R = 1200 N, acting upward (air resistance always acts in the direction opposite to the direction of motion)
There are no other forces, therefore the correct answer is:
2 Forces
2)
The net force on the system is given by the vector resultant of the two forces described in part 1). Since the two forces act along the same line but in opposite directions, the net force will be equal to the difference between the two forces, so:
[tex]F_{net}=W-R=mg-R[/tex]
where we have chosen downward as positive direction, and where
m = 65 kg is the mass of the teacher
[tex]g=9.8 m/s^2[/tex] is the acceleration due to gravity
R = 1200 N is the air drag
Therefore, the net force on the teacher is
[tex]F_{net}=(65)(9.8)-1200=-563 N[/tex]
And the negative sign means that the direction of the net force is upward.
3)
The acceleration of the system can be found by using Newton's second law of motion, which can be written as
[tex]a=\frac{F_{net}}{m}[/tex]
where
a is the acceleration
[tex]F_{net}[/tex] is the net force
m is the mass of the teacher
Here we have
[tex]F_{net}=-563 N[/tex]
m = 65 kg
Therefore, the acceleration is
[tex]a=\frac{-563}{65}=-8.66 m/s^2[/tex]
And the negative sign indicates that the direction of the acceleration is opposite to the motion (so, upward).
4)
From part 3), we observed that:
- The motion of the teacher is downward (he is moving downward)
- However, the direction of his acceleration is upward
This means that the velocity and the acceleration of the system have opposite directions.
As we know, the velocity of an accelerating system can be written as
[tex]v=u+at[/tex]
where
v is the velocity after time t
u is the initial velocity
a is the acceleration
Since a is negative, we see that [tex]at<0[/tex], so [tex]v<u[/tex]: this means that the velocity of the teacher is decreasing with time, so, the teacher is slowing down, and therefore his speed is decreasing.
(a) Two forces are acting on the system.
(b) The magnitude of net force on the system is 592.4 N.
(c) The magnitude of the acceleration is 9.11 m/s².
(d) The speed of the system decreases with time
The given parameters;
mass of the teacher, m = 65 kgdrag force on the teacher, [tex]F_f[/tex] = 1200 NThe forces acting on the teacher are downward force due to the teachers weight and drag force acting upward opposing the downward motion.
The magnitude of net force on the system is calculated as follows;
[tex]F_{net}= W - F_f\\\\F_{net}= (65 \times 9.8) - (1200)\\\\F_{net} = -592.4 \ N[/tex]
The magnitude of the acceleration is calculated as follows;
[tex]a = \frac{-592.4}{65} \\\\a = -9.11 \ m/s^2\\\\|a| = 9.11 \ m/s^2[/tex]
The speed of the system is calculated as follows;
[tex]v= u + at\\\\v= 0 + (-9.11)t\\\\v = -9.11t[/tex]
The speed of the system decreases with time.
Learn more here:https://brainly.com/question/20357188
Two objects collide and bounce apart. Assuming no outside forces act on the system, which best describes the total momentum after the collision?
It is always greater than it was before the collision.
It is often greater than it was before the collision.
It is always the same as it was before the collision.
It is often the same as it was before the collision.
Answer:
It is always the same as it was before the collision.
Answer:
The answer is C on Edge
Explanation:
According to the diagram, which pair could both be north poles?
The given diagram of the magnet shows attraction which occurs between opposite poles therefore, A and C could both be the north poles. Thus, the correct option is C.
What is a magnet?A magnet is a material or an object which produces a magnetic field around itself. The magnetic field of this magnet is invisible however it is responsible for the most notable property of a magnet which is a force that is responsible for pulling on other ferromagnetic materials, such as iron, steel, nickel, cobalt, etc. towards it and attracts or repels other magnets as well.
Some important properties of magnet include a magnet has two poles which are north pole and south pole, magnets attract ferromagnetic materials, the similar poles of two magnets repel each other, whereas the opposite poles of two magnets attract each other. A magnet hung up in the air always comes to rest facing the north-south direction. The poles of a magnet are arranged in pairs.
Therefore, the correct option is C.
Learn more about Magnet here:
https://brainly.com/question/2841288
#SPJ2
Three fire hoses are connected to a fire hydrant. Each hose has a radius of 0.017 m. Water enters the hydrant through an underground pipe of radius 0.088 m. In this pipe the water has a speed of 2.7 m/s. (a) How many kilograms of water are poured onto a fire in one hour by all three hoses
Answer:
2.36 x 10^5 kg
Explanation:
radius of hose, r = 0.017 m
radius of underground pipe, R = 0.088 m
number of hoses, n = 3
velocity of water in underground pipe, V = 2.7 m/s
Let v is the velocity of water in each hose.
According to the equation of continuity
A x V = n x a x v
π R² x V = n x π x r² x v
0.088 x 0.088 x 2.7 = 3 x 0.017 x 0.017 x v
v = 24.12 m/s
(a) Amount of water poured onto a fire in one hour by all the three hoses
= n x a x v x density of water x time
= 3 x 3.14 x 0.017 x 0.017 x 24.12 x 1000 x 3600
= 2.36 x 10^5 kg
Thus, the amount of water poured onto the fire in one hour is 2.36 x 10^5 kg.
a) Using the principles of fluid dynamics, specifically the continuity equation, we found that the velocity of water in the hoses is 2.02 m/s. The volume flow rate in the hoses is 0.0055 m³/s. Therefore, the mass of water poured onto a fire in one hour by all three hoses is 19800000 kg.
Explanation:a) To answer this question, we need to apply the principles of fluid dynamics, specifically the concept of continuity equation which states that the mass flow rate (the mass of water passing through a given spot per unit time) through a pipe system is constant.
First, let's calculate the cross sectional area of the hydrant pipe (A1) which is πr² = π(0.088m)² ≈ 0.0243 m².
Then, calculate the area of one fire hose (A2) which is π(0.017m)² ≈ 0.000907 m².
Since there are three hoses, the total area for the three hoses (A3) is 3 * A2 ≈ 0.00272 m².
Then, we apply the continuity equation, which is
A1v1=A3v3. We can solve for v3 (the velocity of the water in the hoses), v3 = A1v1/A3 ≈ 2.02 m/s.
To find the mass of water delivered in one hour, we first find the volume flow rate in the hoses,
Q= A3v3 = 0.00272 m² * 2.02 m/s ≈ 0.0055 m³/s.
The volume of water in one hour is Q * 3600s = 19800 m³.
Then, since water has a density (ρ) of 1000 kg/m³, the mass (m) of the water is ρ*volume which equals
19800 * 1000 kg = 19800000 kg.
Learn more about Fluid Dynamics here:
https://brainly.com/question/34422717
#SPJ3
In the electron dot symbol shown, what kind of bond connects the two nitrogen atoms in this molecule?
ionic bond
covalent bond
double covalent bond
triple covalent bond
Answer:
triple covalent bond
Explanation:
A triple covalent bond is formed when three pairs of electrons (six electrons) are shared between the two combining atoms. A triple bond is shown by marking three short lines between the two symbols of the atoms. It requires three more electrons to attain the stable octet.
- Hope this helps! If you need a further explanation please let me know.
Final answer:
A triple covalent bond connects the two nitrogen atoms in this molecule N2.
Explanation:
A triple covalent bond connects the two nitrogen atoms in this molecule. Nitrogen atoms have 5 valence electrons and need to share 3 pairs of electrons to achieve a valence octet. The triple bond between the nitrogen atoms allows them to share 3 pairs of electrons and form a stable diatomic molecule, N2.
A spring is compressed by 50 cm from it's equilibrium length by an unattached block of mass 5.0 kg (the spring constant is 400 N/m). The box is released from rest, slides along a friction-less surface for a time, and then ascends a ramp of length 10 m, which is inclined at an angle of 20 degrees above the horizontal. What is the maximum distance that the box travels up the ramp?
Answer:
L = 2.98 m
Explanation:
In this exercise we are told that there is no friction, so we can use energy conservation
Starting point. Compressed spring
Em₀ = Ke = ½ k x²
Final point. At the highest point of the ramp
[tex]Em_{f}[/tex] = U = mg h
As there is no friction the energy is conserved
Emo = Em_{f}
½ k x² = mg h
h = ½ k x² / mg
h = ½ 400 0.50² / (5.0 9.8)
h = 1.02 m
This is the height that the body reaches, to calculate the distance traveled on the ramp let's use trigonometry
sin θ = h / L
L = h / sin θ
L = 1.02 / sin 20
L = 2.98 m
a man lift a load of 20kg through a height of 4m in 10sec . calculate the workdone
Answer:
The answer to your question is Work = 784.8 Joules
Explanation:
Data
mass = 20 kg
height = 4 m
time = 10 s
Mechanic work is defined as the force applied to a body so it moves a distance.
Formula
Work = force x distance
Process
1.- Calculate the force
Force = mass x gravity
-Substitution
Force = 20 x 9.81
-Result
Force = 196.2 N
2.- Calculate the Work
Work = 196.2 x 4
-Result
Work = 784.8 Joules
Consider heat transfer between two identical hot solid bodies and the air surrounding them. The first solid is being cooled by a fan while the second one is allowed to cool naturally. For which solid is the lumped system analysis more likely to be applicable? Why?
Answer:
The solution to the question above is explained below:
Explanation:
For which solid is the lumped system analysis more likely to be applicable?
Answer
The lumped system analysis is more likely to be applicable for the body cooled naturally.
Question :Why?
Answer
Biot number is proportional to the convection heat transfer coefficient, and it is proportional to the air velocity. When Biot no is less than 0.1 in the case of natural convection, then lumped analysis can be applied.
Further explanations:
Heat is a form of energy.
Heat transfer describes the flow of heat across the boundary of a system due to temperature differences and the subsequent temperature distribution and changes. There are three different ways the heat can transfer: conduction, convection, or radiation.
Heat transfer analysis which utilizes this idealization is known as the lumped system analysis.
The Biot number is a criterion dimensionless quantity used in heat transfer calculations which gives a direct indication of the relative importance of conduction and convection in determining the temperature history of a body being heated or cooled by convection at its surface. In heat transfer analysis, some bodies are observed to behave like a "lump" whose entire body temperature remains essentially uniform at all times during a heat transfer process.
Conduction is the transfer of energy in the form of heat or electricity from one atom to another within an object and conduction of heat occurs when molecules increase in temperature.
Convection is a transfer of heat by the movement of a fluid. Convection occurs within liquids and gases between areas of different temperature.
Final answer:
The lumped system analysis is more applicable to the solid cooled naturally because natural convection is slower, allowing the solid's temperature to equalize, which suits the assumptions of lumped system analysis better than the enhanced convection caused by a fan.
Explanation:
The lumped system analysis is more likely to be applicable to the solid that is being cooled naturally rather than the one with a fan. The reason for this is that the use of a fan increases the flow of air over the surface, enhancing convection and therefore increasing the rate of heat transfer. This forced convection reduces the likelihood that the temperature gradient within the solid will remain uniform, which is a key assumption of lumped system analysis – that the object's temperature is spatially uniform and can be modeled as a lumped capacitance.
In contrast, when cooling occurs naturally, the heat transfer is driven by natural convection, which tends to be slower as it relies on the thermal expansion of the fluid around the solid due to the heat transfer from the solid. The slower rate of heat transfer allows the temperature within the solid to equalize more readily, making lumped system analysis a more appropriate simplification for predicting the thermal response of the solid.
A cylindrical fishing reel has a mass of 0.7 kg and a radius of 5.24 cm. A friction clutch in the reel exerts a restraining torque of 1.88 N · m if a fish pulls on the line. The fisherman gets a bite, and the reel begins to spin with an angular acceleration of 65.7 rad/s 2 . What force does the fish exert on the line? Answer in units of N.
Final answer:
The force exerted by the fish on the line is 35.87 N.
Explanation:
The force exerted by the fish on the line can be calculated using the equation:
Torque = Moment of Inertia x Angular Acceleration
In this case, the moment of inertia of the fishing reel can be calculated using the formula:
Moment of Inertia = [tex]0.5 x Mass x Radius^2[/tex]
Substituting the given values, we can calculate the moment of inertia and then solve for the force exerted by the fish:
Moment of Inertia =[tex]0.5 x 0.7 kg x (5.24 cm)^2[/tex]
Angular Acceleration = [tex]65.7 rad/s^2[/tex]
Using the equation Torque = Moment of Inertia x Angular Acceleration, we can rearrange the equation to solve for the force:
Torque = Force x Radius
Solving for the force:
Force = Torque / Radius
Substituting the given values, we can calculate the force exerted by the fish:
Force = 1.88 N.m / (5.24 cm)
Converting the radius to meters:
Force = 1.88 N.m / (0.0524 m) = 35.87 N
The force exerted by the fish on the line is calculated using the reel's moment of inertia, angular acceleration, and the restraining torque applied by the clutch. The resulting force is found to be 37.08 N.
To find the force that the fish exerts on the line, we need to consider the torque and angular acceleration.
First, let's find the moment of inertia (I) for the cylindrical reel. The moment of inertia for a cylinder rotating around its central axis is given by:I = 0.5 * m * r²
m = 0.7 kg (mass of the reel)
r = 0.0524 m (radius of the reel, converted from cm to meters)
Therefore:
I = 0.5 * 0.7 kg * (0.0524 m)² = 9.62 * 10⁻⁴ kg·m²
We are given the angular acceleration (α) as:α = 65.7 rad/s²
Using Newton's second law for rotation, we find the net torque (τ_net) on the reel:
τ_net = I * α
τ_net = 9.62 * 10⁻⁴ kg·m² * 65.7 rad/s² = 0.0632 N·m
The friction clutch exerts a restraining torque (τ_friction) of 1.88 N·m. The total torque exerted by the fish includes overcoming this friction:τ_fish = τ_net + τ_friction
τ_fish = 0.0632 N·m + 1.88 N·m = 1.9432 N·m
The force (F) exerted by the fish on the line can be related to the torque using:τ_fish = F * r
Therefore:F = τ_fish / r
F = 1.9432 N·m / 0.0524 m = 37.08 N
Thus, the force exerted by the fish on the line is 37.08 N.
Complete Question: A cylindrical fishing reel has a mass of 0.7 kg and a radius of 5.24 cm. A friction clutch in the reel exerts a restraining torque of 1.88 N · m if a fish pulls on the line. The fisherman gets a bite, and the reel begins to spin with an angular acceleration of 65.7 rad/s 2 . What force does the fish exert on the line? Answer in units of N.
A radio wave of frequency on the order of 105 Hz is used to carry a sound wave with a frequency on the order of 103 Hz. Is the wavelength of this radio wave on the order of (a) kilometers, (b) meters, (c) centimeters, (d) micrometers
Given that,
Frequency of radio wave is from f = 10⁵ Hz and f' = 10³ Hz
We need to find the wavelength of radio wave. The speed of a wave is given by formula as follows :
If f = 10⁵ Hz
[tex]v=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{10^5}\\\\\lambda=3000\ m[/tex]
or
[tex]\lambda=3\ km[/tex]
If f' = 10³ Hz
[tex]v=f\lambda\\\\\lambda'=\dfrac{c}{f'}\\\\\lambda'=\dfrac{3\times 10^8}{10^3}\\\\\lambda'=300000\ m[/tex]
or
[tex]\lambda'=300\ km[/tex]
So, the wavelength of this radio wave on the order of kilometres.
The wavelength of this radio wave is on the order of meters.
Explanation:The wavelength of a radio wave can be calculated using the formula: wavelength = speed of light / frequency. In this case, the given frequency of the radio wave is on the order of 10^5 Hz. To compare it with the lowest audible sound waves with a frequency of 20 Hz, we can use the formula again. Taking the speed of sound in air at 20 °C as 343 m/s, we can calculate the wavelength of the lowest audible sound waves. By comparing the wavelengths of the two waves, we can determine the order of magnitude of the wavelength of the radio wave.
Let's calculate the wavelengths:
Wavelength of radio wave = speed of light / frequency = (3 x 10^8 m/s) / (10^5 Hz) = 3000 m
Wavelength of lowest audible sound wave = speed of sound / frequency = (343 m/s) / (20 Hz) = 17.15 m
Comparing the two wavelengths, we can see that the wavelength of the radio wave is on the order of meters.
Learn more about wavelength of radio waves here:https://brainly.com/question/28874040
#SPJ3
Which example illustrates an engineering improvement that has led to greater knowledge about
space?
analyzing rock samples from the moon to determine the composition of the moon
science experiments on the International Space Station that study how crystals grow in
space
development of the space shuttle to allow humans to explore the moon
Answer:
D.
Explanation:
development of the space shuttle to allow humans to explore the moon
10 points
True or False? Charging by friction happens when you rub two objects
together and PROTONS move from one object to the other.
Answer:
true
Explanation:
yes because I said so
How much charge can be added to each of the plates before a spark jumps between the two plates? For such flat electrodes
Answer:
7.54 x[tex]10^{-7}[/tex] C
Explanation:
The complete question is:
Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular aluminum plates, each 19 cm in diameter, separated by 1.0 cm.How much charge can be added to each of the plates before a spark jumps between the two plates? For such flat electrodes, assume that value of 3×106N/C of the field causes a spark.
SOLUTION:
As you know that, parallel plate capacitance can be defined as
C=εo A/d
Where,
εo is the permittivity of free space constant, A is area of the capacitor plates, and d is the distance between them
Also, C= Q/V
where,
'Q' defines charge stored on the capacitor and 'V' express the potential difference between the plates.
Equating the equations.
εo A/d = Q/V
Q= (εo A V)/d
for a uniform electric field (such as the one between the plates of a parallel-plate capacitor)
V= Ed ->where 'E' defines magnitude of the electric field.
Therefore,
Q= (εo A E d)/d =>εo A E ->eq(1)
The area of the plates is given by
A= πr² => π(d/2)² =>π(0.19/2)
A=0.0284m²
Given: E= 3 x [tex]10^{6}[/tex] N/C
Substituting all the required values in eq(1)
(1)=> Q= (8.85x[tex]10^{-12}[/tex]) (-.0284)(3 x [tex]10^{6}[/tex] )
Q= 7.54 x[tex]10^{-7}[/tex] C
Therefore,7.54 x[tex]10^{-7}[/tex] C can be added to each of the plates before a spark jumps between the two plates
A sphere of radius R has total charge Q. The volume charge density (C/m3) within the sphere is rho(r)=C/r2, where C is a constant to be determined. Part A The charge within a small volume dV is dq=rhodV. The integral of rhodV over the entire volume of the sphere is the total charge Q. Use this fact to determine the constant C in terms of Q and R. Hint: Let dV be a spherical shell of radius r and thickness dr. What is the volume of such a shell? Express your answer in terms of the variables Q and R.
Answer: C = Q/4πR
Explanation:
Volume(V) of a sphere = 4πr^3
Charge within a small volume 'dV' is given by:
dq = ρ(r)dV
ρ(r) = C/r^2
Volume(V) of a sphere = 4/3(πr^3)
dV/dr = (4/3)×3πr^2
dV = 4πr^2dr
Therefore,
dq = ρ(r)dV ; dq =ρ(r)4πr^2dr
dq = C/r^2[4πr^2dr]
dq = 4Cπdr
FOR TOTAL CHANGE 'Q', we integrate dq
∫dq = ∫4Cπdr at r = R and r = 0
∫4Cπdr = 4Cπr
Q = 4Cπ(R - 0)
Q = 4CπR - 0
Q = 4CπR
C = Q/4πR
The value of C in terms of Q and R is [Q/4πR]
Putting a marshmallow directly in the fire
A. Conduction
B. Convention
C. Radiation
Answer:
A conduction is the answer
Explanation:
Answer: Radiation
Explanation:
Conduction involves thermal energy between a conductor/insulator, convection is when warm fluids rise and cool fluids sink due to a distinction in the density of their particles. None of these match a marshmallow over fire. Radiation is the correct answer.
A horizontal 826 N merry-go-round of radius 1.17 m is started from rest by a constant horizontal force of 57.8 N applied tangentially to the merry-go-round. Find the kinetic energy of the merry-goround after 3.47 s. The acceleration of gravity is 9.8 m/s 2 . Assume the merry-go-round is a solid cylinder. Answer in units of J. 028 10.0
Answer:
The kinetic energy of the merry-go-round is [tex]\bf{475.47~J}[/tex].
Explanation:
Given:
Weight of the merry-go-round, [tex]W_{g} = 826~N[/tex]
Radius of the merry-go-round, [tex]r = 1.17~m[/tex]
the force on the merry-go-round, [tex]F = 57.8~N[/tex]
Acceleration due to gravity, [tex]g= 9.8~m.s^{-2}[/tex]
Time given, [tex]t=3.47~s[/tex]
Mass of the merry-go-round is given by
[tex]m &=& \dfrac{W_{g}}{g}\\~~~~&=& \dfrac{826~N}{9.8~m.s^{-2}}\\~~~~&=& 84.29~Kg[/tex]
Moment of inertial of the merry-go-round is given by
[tex]I &=& \dfrac{1}{2}mr^{2}\\~~~&=& \dfrac{1}{2}(84.29~Kg)(1.17~m)^{2}\\~~~&=& 57.69~Kg.m^{2}[/tex]
Torque on the merry-go-round is given by
[tex]\tau &=& F.r\\~~~&=& (57.8~N)(1.17~m)\\~~~&=& 67.63~N.m[/tex]
The angular acceleration is given by
[tex]\alpha &=& \dfrac{\tau}{I}\\~~~&=& \dfrac{67.63~N.m}{57.69~Kg.m^{2}}\\~~~&=& 1.17~rad.s^{-2}[/tex]
The angular velocity is given by
[tex]\omega &=& \alpha.t\\~~~&=& (1.17~rad.s^{-2})(3.47~s)\\~~~&=& 4.06~rad.s^{-1}[/tex]
The kinetic energy of the merry-go-round is given by
[tex]E &=& \dfrac{1}{2}I\omega^{2}\\~~~&=&\dfrac{1}{2}(57.69~Kg.m^{2})(4.06~rad.s^{-1})^{2}\\~~~&=& 475.47~J[/tex]
A thin film of alcohol (n = 1.36) lies on a flat glass plate (n = 1.51). When monochromatic light, whose wavelength λ can be changed, is incident normally, the reflected light is minimum for wavelength λ = 512 nm and a maximum for wavelength = 640 nm. What is the minimum thickness of the film?
To find the minimum thickness of the film, one should understand thin film interference. For minimum reflection, this corresponds to the condition of destructive interference. Using this knowledge, the minimum thickness can be calculated using the provided values.
Explanation:One needs to understand thin film interference to solve this problem. This concept involves understanding how light waves interact when they hit a thin film, and this interaction depends on the film's thickness, the light's wavelength, and the medium's indices of refraction.
Given that minimum reflection is obtained for a wavelength of 512 nm, we know that this condition corresponds to destructive interference. For destructive interference in a thin film like the one we're discussing, the additional distance traveled by the second ray of the light (which reflects off the lower surface of the film) must be odd multiples of λ/2, where λ is the wavelength of the light in the medium of the film.
In this case, we know that the film is made of alcohol and the light in this medium has a different wavelength than in vacuum, given by λ' = λ/n. Here, n is the refractive index of alcohol, so λ' = 512 nm/1.36.
For minimum thickness, and therefore first-order destructive interference, we have that 2t = λ'/2, or t = λ'/4, where t is the thickness of the film, the thing we're looking to find. Substituting in our value for λ', we can calculate that the minimum thickness of the film would be 512 nm/(1.36 x 4).
Learn more about thin film interference here:https://brainly.com/question/33710977
#SPJ11
The minimum thickness of the film is approximately 470.6 nm.
To find the minimum thickness of the film, we need to consider the conditions for constructive and destructive interference for normally incident light on a thin film.
For destructive interference (minimum reflected light), the optical path difference between the reflected rays from the top and bottom surfaces of the film must be an odd multiple of half the wavelength of the light in the medium of the film. This can be expressed as:
[tex]2n_f_t = (2m + 1)\frac{\lambda_d}{2}[/tex]
where [tex]\( n_f \)[/tex] is the refractive index of the film, (t) is the thickness of the film, [tex]\( \lambda_d \)[/tex] is the wavelength of the light in air for which destructive interference occurs, and (m) is an integer.
For constructive interference (maximum reflected light), the optical path difference must be an even multiple of half the wavelength of the light in the medium of the film. This can be expressed as:
[tex]2n_f_t = m\lambda_c[/tex]
where [tex]\( \lambda_c \)[/tex] is the wavelength of the light in air for which constructive interference occurs.
Given that the destructive interference occurs at [tex]\( \lambda_d = 512 \)[/tex] nm and the constructive interference occurs at [tex]\( \lambda_c = 640 \)[/tex] nm, we can set up two equations using the above conditions:
For destructive interference:
[tex]2 \times 1.36 \times t = (2m + 1)\frac{512}{2}[/tex]
For constructive interference:
2 x 1.36 x t = m x 640
We can solve these two equations simultaneously to find the minimum thickness (t). Let's first express (m) in terms of (t) from both equations:
From destructive interference:
2 x 1.36 x t = (2m + 1) x 256
[tex]t = \frac{(2m + 1) \times 256}{2 \times 1.36}[/tex]
From constructive interference:
2 x 1.36 x t = m x 640
[tex]t = \frac{m \times 640}{2 \times 1.36}[/tex]
Since the thickness (t) must be the same for both conditions, we can equate the two expressions for (t):
[tex]\frac{(2m + 1) \times 256}{2 \times 1.36} = \frac{m \times 640}{2 \times 1.36}[/tex]
2m + 1 x 256 = m x 640
512m + 256 = 640m
256 = 640m - 512m
256 = 128m
m = 2
Now that we have the value of (m), we can substitute it back into either equation to find (t). Using the destructive interference equation:
[tex]t = \frac{(2 \times 2 + 1) \times 256}{2 \times 1.36}[/tex]
[tex]t = \frac{5 \times 256}{2.72}[/tex]
[tex]t = \frac{1280}{2.72}[/tex]
t = 470.6 nm
A thermometer reading 10 degrees C is brought into a room with a constant temperature of 38 degrees Upper C. (a) If the thermometer reads 14 degrees C after 4 minutes, what will it read after being in the room for 6 minutes?
Answer:
Explanation:
We shall apply Newton's laws of cooling .
dT / dt = k ( T₁ - T₂ )
dT is change in temperature in time dt , k is constant , T₁ and T₂ are temperature of cold object and hot surrounding respectively.
For the first case of 4 minutes
(14 - 10)/ 4 = k [(14+10) /2 - 38 ] , T₁ = (14+10) /2 , the average temperature
1 = - 26 k
Using the formula for next two minutes
T-14 / 2 = k [(14+T) /2 - 38 ]
T-14 / 2 = 1/26[ 38 - (14+T) /2 ]
T / 2 - 7 = 1.46 - .27 - T / 52
T/2 + T/52 = 7 + 1.46 - .27
= .52 T = 8.19
T = 15.75 degree
A rifle fires a 1.06 x 10-2-kg pellet straight upward, because the pellet rests on a compressed spring that is released when the trigger is pulled. The spring has a negligible mass and is compressed by 6.61 x 10-2 m from its unstrained length. The pellet rises to a maximum height of 6.26 m above its position on the compressed spring. Ignoring air resistance, determine the spring constant.
Answer:
k = 2.65 10² N / m
Explanation:
As the pellets shoot up we can use energy conservation
Starting point. Compressed spring rifle
Em₀ = Ke = ½ k x²
Final point. Highest point of the path
[tex]Em_{f}[/tex] = U = m g y
Energy is conserved
Em₀ = Em_{f}
½ k x² = m g y
k = 2 m g y / x²
Let's calculate
k = 2 1.06 10⁻² 9.8 6.26 / (6.61 10⁻²)²
k = 2.65 10² N / m