Ethylene gas and steam at 320°c and atmospheric pressure are fed to a reaction process as an equimolar mixture. the process produces ethanol by the reaction: c2h4(g) + h2o(g) → c2h5oh(l)c2h4(g) + h2o(g) → c2h5oh(l) the liquid ethanol exits the process at 25°c. what is the heat transfer associated with this overall process per mole of ethanol produced?
Without specific enthalpy change (ΔH) values for the reactions in question, we cannot accurately calculate the heat transfer per mole of ethanol produced. However, if these values were provided, the general formula qp = ΔH(T2-T1)/T1*T2 could be used to determine this, where qp represents heat transfer at constant pressure, T1 and T2 are the initial and final temperatures respectively.
Explanation:This question pertains to the field of thermochemistry and the role of heat transfer in chemical reactions. The process in question involves the transformation of ethylene gas and steam into ethanol, or C2H5OH. We would need the specific heat, or enthalpy change (ΔH), values for these reactions to calculate the heat transfer per mole of ethanol produced. Since these values haven't been provided, we can't provide a definite answer.
Generally, in such questions, when ΔH values and temperatures are given, one formula that can be applied is q_p = ΔH(T2-T1)/T1*T2 where T1 is initial temperature, T2 is final temperature and qp represents heat transfer at constant pressure.
This formula can be used to estimate the heat transfer associated with the process per mole of ethanol produced, once the ΔH value is known. It's also important to remember that if the reaction is exothermic (releases heat), the ΔH value would be negative, and if it's endothermic (absorbs heat), the ΔH value would be positive.
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A compound is found to contain 58.80 % xenon, 7.166 % oxygen, and 34.04 % fluorine by mass. what is the empirical formula for this compound?
What is the name of the species formed when a sodium atom loses an electron?
When a sodium atom loses an electron, it becomes a sodium ion (Na+).
Explanation:When a sodium atom loses an electron, it becomes a sodium ion (Na+).
For example, a sodium atom has 11 protons and 10 electrons. By losing one electron, it now has an overall charge of +1. This positive charge is denoted by the superscripted plus sign (Na+).
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Hydrogen peroxide, h2o2(aq), decomposes into water and oxygen. adding a small amount of fecl3(aq) increases the rate of gas evolution in this reaction. what is the best description of the role of fecl3?
Answer:
fecl₃ acting as catalyst-iron (III) chloride is acts as the catalyst for the reaction which takes place in the transformation of hydrogen peroxide, H₂O₂(aq) into the two main products mainly water,H₂O and oxygen,O₂.
The reaction is as follow:H₂O₂(aq)⇒ H₂O + O₂.Explanation:
Catalysts-A catalyst provide the best route or the easy path to start or initiate the reaction or the chemical transformation which leads to the speeding up the reactions.
Kemmi pipets 25.00 ml of pure 1-propanol (c3h7oh, a liquid organic alcohol) into a 100.0 ml volumetric flask. she dilutes it with di water. help her calculate the strength of her diluted solution. volumes: 25.00 ml volumetric pipet, 100.00 ml volumetric flask. molar mass of pure 1-propanol: 60.09 g/mol. density of pure 1-propanol: 0.803 g/ml calculate the number of moles in exactly 25.00 ml of 1-propanol. (3 significant digits; units of mol) [x] calculate the molarity of the diluted solution. (3 significant digits; units of m or mol/l) [y]
The number of moles of 1-propanol in 25.00 mL is 0.334 (to three significant digits). The molarity of the diluted 1-propanol solution in a 100.0 mL flask is 3.34 M (to three significant digits).
To calculate the number of moles of 1-propanol in 25.00 mL, we use the density of 1-propanol (0.803 g/mL) to find the mass:
Mass = Volume × Density = 25.00 mL 0.803 g/mL = 20.075 g
Next, we convert this mass to moles using the molar mass of 1-propanol (60.09 g/mol):
Moles of 1-propanol = Mass / Molar Mass = 20.075 g / 60.09 g/mol
This calculation yields 0.334 moles of 1-propanol (to three significant digits).
For the molarity of the diluted solution, we take into account that the total volume is now 100.0 mL. Since molarity is moles per liter (mol/L), we must first convert the volume from mL to L:
Volume in L = 100.0 mL (1 L / 1000 mL) = 0.100 L
Molarity = Moles of 1-propanol / Volume in L = 0.334 mol / 0.100 L
The molarity of the solution is 3.34 M (to three significant digits).
100 POINTS Which energy source produces electricity at a hydroelectric dam? A. solar panels B. wind turning turbines C. falling water D. pressure from water on the dam
100 POINTS
The answer is C falling water hope this helps
Electricity at a hydroelectric dam is produced by falling water, which turns turbines to generate electricity. The ultimate source of this energy is solar energy that drives the hydrological cycle.
The energy source that produces electricity at a hydroelectric dam is C. falling water. This process involves the conversion of potential energy stored in the water behind the dam into kinetic energy as the water flows down. The kinetic energy turns the blades of turbines, which then drive a generator to produce electricity. The ultimate source of the electrical energy produced by a hydroelectric plant is solar energy, which drives the hydrological cycle that lifts water to high elevations through evaporation and precipitation.
What is the ph of a 0.015 m aqueous solution of hydrazoic acid (hn3) (ka = 1.9 x 10–5) at 25°c?
how can an atom that has seven valence electrons complete its outermost level
Answer: The element needs to react with other element by gaining an electron to complete its valence electron.
Explanation: The element which exhibit 7 valence electrons are halogens. They readily react with other element, for example: Hydrogen and Sodium, in order to gain an electron to complete their outermost shell.
Be sure to answer all parts. identify and label the species in each reaction. (a) nh4+(aq) + h2o(l) ⇌ nh3(aq) + h3o+(aq) acid base acid base conjugate acid conjugate base conjugate acid conjugate base (b) cn−(aq) + h2o(l) ⇌ hcn(aq) + oh−(aq) acid base acid base conjugate acid conjugate base conjugate acid conjugate base
In the given reaction, label the species as acid, base, conjugate acid, and conjugate base. (a) Acid: NH4+, Base: H2O, Conjugate Acid: H3O+, Conjugate Base: NH3. (b) Acid: CN-, Base: H2O, Conjugate Acid: HCN, Conjugate Base: OH-
Explanation:(a) In the reaction: NH4+(aq) + H2O(l) ⇌ NH3(aq) + H3O+(aq), we have NH4+ as the acid and H2O as the base. After the reaction, NH3 becomes the conjugate base and H3O+ becomes the conjugate acid.
(b) In the reaction: CN-(aq) + H2O(l) ⇌ HCN(aq) + OH-(aq), we have CN- as the acid and H2O as the base. After the reaction, HCN becomes the conjugate acid and OH- becomes the conjugate base.
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If the first half-life of a zero-order reaction is 200s, what will be the duration of the next half-life?
A 42 kg sample of water absorbs 347 kJ of heat. If the water was initially at 23.2 ∘C, what is its final temperature?
Determine the melting point of an aqueous solution containing 101 mg of saccharin (c7h5o3ns) added to 1.00 ml of water (density of water = 1.00 g/ml, kf = 1.86°c/m).
The freezing point of the solution is - 0.74 °c.
First, we have to determine the mass of the water as follows;
Density of water = mass/ volume
Mass = Density of water × volume
Mass = 1.00 g/ml × 1.00 ml = 1.00 g or 0.001 Kg
Number of moles of solute = 101 × 10^-3 g/183 g/mol = 0.0004 moles
Molality = 0.0004 moles/0.001 Kg = 0.4 m
ΔT = K m i
K = freezing constant
m = molality
i = Van't Hoff factor
ΔT = 1.86°c/m × 0.4 m × 1 = 0.74 °c
Freezing point = 0 °c - 0.74 °c = - 0.74 °c
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A ball-and-stick model of a molecule provides much the same information as a
Both the ball-and-stick and space-filling models are 3D molecular representations, with the former displaying the bonds and the latter showing the relative atom sizes and general shape.
A ball-and-stick model of a molecule provides much the same information as a space-filling model. Both are used to represent the three-dimensional structure of a molecule in different ways. The ball-and-stick model shows atoms as spheres and bonds as sticks, highlighting the bond angles and lengths between atoms.
In contrast, the space-filling model represents atoms by spheres that are sized proportionally to the atoms' radii, depicting the actual volume occupied by the atoms without showing the bonds explicitly.
While the ball-and-stick model may exaggerate the space between the atoms, it is beneficial for understanding the geometry of the chemical bonds. The space-filling model, however, allows for visualization of the molecule's general shape and the relative sizes of the atoms. Both models are simplifications and do not fully capture subtle variations in bond lengths and angles.
A nuclide of 64/29 Cu absorbs a position. Which is the resulting atom?
A) 65/29 Cu
B) 63/29 Cu
C) 64/28 Ni
D) 64/30 Zn
When a nuclide of 64/29 Cu absorbs a positron, it undergoes a process called positron emission and the resulting atom is 63/29 Cu.
Explanation:When a nuclide of 64/29 Cu absorbs a positron, it undergoes a process called positron emission. During this process, one of the protons in the nucleus is transformed into a neutron, resulting in a new atom. The resulting atom will have the same number of protons as the original atom, but one less proton. Therefore, the resulting atom will be 63/29 Cu, which is option B.
which molecular formula is also an empirical formula?
1)C6h6
2)h2o2
3) n2h4
4) n2o5
The molecular formula which is also an empirical formula is Choice 4: N2O5
The molecular formula of a compound is always a multiple of the empirical formula.
The choices are analysed as follows;
For Choice 1;
The subscripts can further be divided. As such, C6H6 is a molecular formula but not an empirical formula.For Choice 2;
The subscripts can further be divided. As such, H2O2 is a molecular formula but not an empirical formula.
For Choice 3;
The subscripts can further be divided. As such, N2H4 is a molecular formula but not an empirical formula
However; For Choice 3;
The subscripts can not be further divided. As such, N2O5 is a molecular formula and also an empirical formula.
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What do you need to know describe the velocity of an object
Answer:
You need to know the speed, direction (displacement) and time to describe the velocity of an object.
If the calcium oxide were to be obtained by the heating of calcium hydroxide, how much hydroxide would be needed to obtain the 15.0 g?
Major groups of minerals include _____. oxides and carbonates ions and isotopes inorganics and halides silicates and magnetics
oxides and carbonates, grad point..
how many grams of NaCl will be needed to form 600 ml of a saturated solution at 100 degrees celsius ?
Think about a carbon atom that is released into the atmosphere from the burning of wood in a campfire. If it were to go through the whole carbon cycle,
Step 1 A caterpillar gets the carbon by eating the tree's leaves.
Step 2 The bird decomposes and the carbon is added to the atmosphere.
Step 3 A bird gets the carbon by eating the caterpillar.
Step 4 The bird flies into a building and dies instantly. It falls to the ground
Step 5 A tree absorbs the carbon from the atmosphere into its leaves for photosynthesis.
plz help me by telling me what order this go's in?
Answer: the actual answer is
step 1: A tree absorbs the carbon from the atmosphere into its leaves for photosynthesis
step 2: A caterpillar gets the carbon by eating the tree's leaves
step 3: A bird gets the carbon by eating the caterpillar
step 4: The bird flies into a building and dies instantly. It falls to the ground
step 5: The bird decomposes and the carbon is added to the atmosphere
Explanation:
Which metal(s) can be oxidized with a sn2+ solution but not with an fe2+ solution? (hint: the reactions are occurring under standard conditions.)?
For this we have to consider the reactive series of metals in which metals are arranged according to their reactivity order.
Oxidation of a metal can be defined as ability to lose electrons to become positively charged metal and a metal will lose its electrons by reacting with a metal that is having low chemical reactivity as a higher reactive metal can lose its electrons to a low reactive metal. So here a metal should be one that is more reactive than tin so that it can lose its electrons to tin to become positively charged and less reactive than iron so that it will not give its electrons to iron to become positively charged. If we look into reactive series of metal than we will find that nickel is the example of a metal that is more reactive than tin and less reactive than iron.
Nickel and cadmium is the metal that can be oxidized with a sn2+ solution, but not with a fe2+ solution.
What is metal oxidization?An ionic chemical reaction occurs on the surface of metal in the presence of oxygen.
Metals that can be oxidized in solution must have a weaker oxidizing agent or be less reactive than tin.
With solution, the same metals cannot be oxidized.
Thus, the correct option is Nickel and cadmium.
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What is the molecular formula of the molecule that has an empirical formula of C2H2O and a molar mass of 252.22 g/mol?
Empirical formula is the simplest whole number ratio of elements in a compound. Molecular formula is n times the empirical formula, where n is integers 1,2,... Therefore, the molecular formula of the compound C[tex]_{10}[/tex]H[tex]_{10}[/tex]O[tex]_5[/tex].
What is empirical formula?
Empirical formula gives the proportion of the element that is present in a compound. It does not give information about the actual number or the arrangements of the atoms.
n= molecular formula÷ empirical formula
Molar masses of C[tex]_2[/tex]H[tex]_2[/tex]O
C = 12.0107
H = 2.016
O = 15.999
Molar masses of C[tex]_2[/tex]H[tex]_2[/tex]O =2(12.0107)+2(2.016)+15.999
=24.0214+4.032+15.999
= 44.0524
252.22/44.0524 = 5
C[tex]_2[/tex]H[tex]_2[/tex]O ×5=C[tex]_{10}[/tex]H[tex]_{10}[/tex]O[tex]_5[/tex]
The molecular formula is C[tex]_{10}[/tex]H[tex]_{10}[/tex]O[tex]_5[/tex]
Therefore, the molecular formula of the compound C[tex]_{10}[/tex]H[tex]_{10}[/tex]O[tex]_5[/tex].
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2C6H5COOH + 15O2 → 14CO2 + 6H2O which of the following options gives the correct product:product ratio? CO2:H2O = 14:6 CO2:H2O = 6:14 CO2:H2O = 1:1 O2:H2O = 15:6
Answer:
The Answer is a) CO2:H2O = 14:6
Explanation:
Identify element 3. EXPLAIN YOUR REASONING
A 6 l volume of ideal neon gas (monatomic) is at a pressure of 3.2 atmospheres and a temperature of 310 k. the atomic mass of neon is 20.2 g/mol. in this situation, the temperature of the gas is increased to 410 and the volume is increased to 8.0 l. the final pressure of the gas, in atmospheres, is closest to:
Answer is: the final pressure of the gas is closest to 3,17 atm.
p₁ =
3,2 atm.
T₁ =
310 K.
V₁ =
6 L.
p₂ = ?
T₂ =
410K.
V₂ = 8,0 L.
Use combined gas law - the volume of amount of gas is proportional to the ratio of
its Kelvin temperature and its pressure.
p₁V₁/T₁ =
p₂V₂/T₂.
3,2 atm · 6,0 L ÷ 310 K = p₂ · 8,0 L ÷ 410 K.
0,0619 = 0,0195p₂.
p₂ =
3,17 atm.
Provide the structure of the major product which results from 1,4-addition of br2 to the diene shown below.
Sodium chloride comprises 97%-99% of table salt. Given their location on the periodic table, identify the ionic charge for each element and predict the chemical formula of the compound formed. A) Sodium, Na, is an alkali metal and is in Group IA with an ionic charge of +1. While chlorine, Cl, is a halogen and is in Group VIIA with a charge of -1. These will form NaCl(s). B) Sodium, Na, is an alkaline earth metal and is in Group IA with an ionic charge of +2. While chlorine, Cl, is a halogen and is in Group VIIA with a charge of -1. These will form NaCl2(s). C) Sodium, Na, is an alkali earth metal and is in Group IA with an ionic charge of +2. While chlorine, Cl, is a noble gas and is in Group VIA with a charge of -2. These will form Na2Cl2(s). D) Sodium, Na, is an alkali earth metal and is in Group IA with an ionic charge of +1. While chlorine, Cl, is a diatomic gas and is in Group VIA with a charge of -2. These will form Na2Cl(s).
Answer is: A) Sodium, Na, is an alkali metal and is in Group IA with an ionic charge of +1. While chlorine, Cl, is a halogen and is in Group VIIA with a charge of -1. These will form NaCl(s).
Table salt is sodium chloride mixed with small amount of potassium iodide (KI), sodium iodide (NaI) or sodium iodate (NaIO₃).
Atomic level - sodium chloride (NaCl) has crystal cubic structure (lattice-type arrangement) with ionic bonds. Sodium is cation with charge 1+ and chlorine is an anion with charge 1-.
Macroscopic level - table salt is colorless crystal, soluble in water with high melting and boiling temperature.
Ionic compounds are good good electricity and heat conductors, because ionic compounds have mobile ions (cations and anions) that are able to transfer electrical charge.
Compare the viscosity of n-hexane, ch3ch2ch2ch2ch2ch3, to the viscosity of n-heptane, ch3ch2ch2ch2ch2ch2ch3.
Final answer:
n-Heptane has a higher viscosity than n-hexane due to its longer carbon chain and greater molecular weight, which leads to stronger dispersion forces and hence more resistance to flow.
Explanation:
The viscosity of a liquid is a measure of its resistance to deformation or flow. In comparing the viscosities of n-hexane (CH₃(CH₂)₄CH₃) and n-heptane (CH₃(CH₂)₅CH₃), we must consider their molecular weights and the strength of their intermolecular forces. Because n-heptane has a longer carbon chain and greater molecular weight than n-hexane, it also has stronger dispersion forces. These dispersion forces increase with the molecular surface area, so the larger n-heptane molecules experience more significant intermolecular attractions. As a result, n-heptane has a higher viscosity compared to n-hexane.
A 13.0 kg iron weightlifting plate has a volume of 1650 cm3 . What is the density of the iron plate in g/cm3?
Explanation:
It is known that density is the amount of mass divided by volume.
Mathematically, Density = [tex]\frac{mass}{volume}[/tex]
It is given that mass is 13.0 kg or 13000 g (as 1 kg = 1000 g). And, volume is 1650 [tex]cm^{3}[/tex].
Therefore, calculate the density as follows.
Density = [tex]\frac{mass}{volume}[/tex]
= [tex]\frac{13000 g}{1650 cm^{3}}[/tex]
= [tex]7.87 g/cm^{3}[/tex]
Thus, we can conclude that density of the given iron plate is [tex]7.87 g/cm^{3}[/tex].
A gas sample has a volume of 178 mL at 0.00oC.The temperature is raised at constant pressure until the volume reaches 211 mL. What is the temperature of that gas sample at this volume?
The temperature of the gas will be 324K or [tex]\rm \bold{51^\cdot C}[/tex] when volume reaches 211 mL.
Charle's law stated that the volume occupied by fixed amount of gas is directly proportional to the temperature,while pressure is constant.
[tex]\rm \bold{\frac{V_1}{T_1} =\frac{V_2}{T_2}}[/tex]
Where,
[tex]\rm \bold V_1[/tex] is initial volume = 178mL
[tex]\rm \bold {V_2}[/tex] is final volume = 211mL
[tex]\rm \bold{ T_1}[/tex] is initial temperature = [tex]\rm \bold{0.00^\cdot C}[/tex] = 273K
[tex]\rm \bold {T_2}[/tex] is final temperature = ?
Put the values,
[tex]\rm \bold{\frac{178}{273} =\frac{211}{T_2}}\\\\\rm \bold{T_2=324 K}[/tex]
Hence, we can conclude that the temperature of the gas will be 324K or [tex]\rm \bold{51^\cdot C}[/tex] when volume reaches 211 mL.
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