If matrix A has dimensions 3 x 2 and matrix B has dimensions 3 x 2, can matrix A and matrix B be multiplied?

Answer:

25,35

Step-by-step explanation:

Part A: There are five buttons in all in all in the given item. The item above can be answered through the fundamental principles of counting.  

There are 5 items to choose from during the first pick. Because the shape can be returned and picked again, there are also 5 items to choose from in the second pick. Multiplying them,

                              n = 5 x 5 = 25

Therefore, the sample size for the compound event is equal to 25.

Part B: The same concept can be used in this part of the item; however, instead of 5 there are 6 buttons to choose from.

                             n = 6 x 6 = 36

Hence, the sample size of this picking process is 36.

Answer x= 32

Imagine math

The coordinates of point P that partitions the segment AB in the ratio 1:1 are (4, -1). The calculation is done using the segment partition formula.

To solve this problem, we use the formula for finding the point that divides a line segment into a given ratio. The formula is P(x, y) = ((x1*m2 + x2*m1)/(m1+m2), (y1*m2 + y2*m1)/(m1+m2)). Here, points A and B are (13,1) and (-5,-3) respectively, and the ratio m1:m2 is 1:1.

So applying the formula, we have P(x, y) = ((13*1 + -5*1) / (1+1), (1*1 + -3*1) / (1+1)) = (8/2, -2/2) = (4, -1).

So, the coordinates of point P that partitions the segment AB in the ratio 1:1 are (4, -1).

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To find the coordinates of point P that bisects the segment AB in the ratio 1:1, we use the midpoint formula. Substituting the values of points A(13,1) and B(-5,-3) into the formula gives us P(4,-1).

The student wants to find the coordinates of point P that would bisect the line segment AB in a 1:1 ratio. Since the ratio is 1:1, point P is the midpoint of the segment. To find the coordinates of the midpoint P, we need to calculate the average of the x-coordinates and the y-coordinates of points A and B.

Using the formula of a midpoint, M(x, y) = [ (x1+x2)/2 , (y1+y2)/2 ], let's substitute the coordinates of points A(13,1) and B(-5,-3).

P(x, y) = [ (13-5)/2 , (1-3)/2 ]

Therefore, the coordinates of point P that partitions the segment AB in the ratio 1:1 is P(4, -1).

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To find the total number of photographs, we use the fact that 30% were perfect, meaning 70% were not perfect. By setting up the equation 0.70x = 210, we can solve for x, finding that there were 300 photographs in total.

If 30% of John's photographs were perfect and 210 were not perfect, determining the total number of photographs involves understanding percentages and basic algebra. Here's the step-by-step breakdown of solving the problem:

Therefore, there were 300 photographs in total.

The total number of photographs is 300.

If 30% of John's photographs were perfect, it means that 70% were not perfect. Since 210 photographs were not perfect, we can set up an equation to find the total number of photographs. Let x represent the total number of photographs. We know that 70% of x equals 210:

[tex]\[ 0.70x = 210 \][/tex]

Solving this equation, we find that

[tex]\( x = \frac{210}{0.70} = 300 \)[/tex]

Therefore, there were 300 photographs in total. This calculation assumes that all photographs are either perfect or imperfect, with no other categories.

Answer:  [tex]1667978979\pi[/tex] cubic miles

Step-by-step explanation:

We know that the shape of moon is sphere.

The volume of sphere is given by :-

[tex]\text{V}=\dfrac{4}{3}\pi r^3[/tex], where r is the radius of sphere.

Given : The diameter of moon = 2155 miles

Then the radius of moon=[tex]\dfrac{2155}{2}[/tex]

Then , the volume of moon is given by :-

[tex]\text{V}=\dfrac{4}{3}\pi (\dfrac{2155}{2})^3=1667978979.2\pi\approx1667978979\pi \text{ cubic miles}[/tex]

10% of 100 < 20% of 200.

10% of 1000 > 20% of 100.

Percentage is the fraction out of an amount that is usually expressed as a number out of hundred. Percentages are a measure of frequency. The sign used to represent percentages is %.

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Answer:

Algebraic expression that best describes the sequence is:

[tex]2^{n}[/tex]

Step-by-step explanation:

We have the sequence 2, 4, 8, 16, 32,...?

With the Algebraic expression:

[tex]2^{n}[/tex] (1)

n is the number into the sequence that you want to find, we can prove it if we replace in the equation (1)

For example in the first term, n=1

[tex]2^{1}=2[/tex]

in the second term, n=2, and so on

[tex]2^{2}=4\\2^{3}=8\\2^{4}=16\\2^{5}=32\\2^{6}=64\\[/tex]

Answer:

D infinitely many  

Step-by-step explanation:

They lines never cross

Answer:

the answer is 10 m2

Step-by-step explanation:

Answer:

11/20

Step-by-step explanation:

The answer to your question is the third option:

1/2(n+4) = 5/n - 3

Answer:

x² + (-6x) = -13

ALSO the second answer,
x² + (-6x) __ = -13 +  __
Both blanks are 9
Third answer, factor the trinomial and simplify:

(x + -3 )²= -4

Use the square root property of equality to solve

(x  – 3)2 = –4.

The solutions are

The correct option is   C.   3 ± 2i.

:D

The equation 8x² - 48x = -104 can be rewritten with 'a' = 1 by dividing all terms by 8 and rearranging to the form ax² + bx + c = 0, yielding x² - 6x + 13 = 0.

To rewrite the equation so that 'a' = 1, it would be useful to adjust the coefficients in your equation first. Starting with the given equation: 8x² - 48x = -104. We can divide all terms by 8 to normalize the 'a' coefficient.

Doing that gives us: x² - 6x = -13. Now, to write the equation in the form ax² + bx + c = 0, we can add 13 to both sides which results in: x² - 6x + 13 = 0. Now your equation is in the standard quadratic form with 'a' = 1.

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radius = square root (( x2-x1)^2 +(y2-y1)^2)

 = sqrt(1-(-3)^2+(5-2)^2

= sqrt(16+9)

=sqrt(25)

= 5

radius is 5

The radius of the circle is [tex]\boxed{5{\text{ units}}}.[/tex]

Further explanation:

The standard equationof the circle with center [tex]\left( {h,k}\right)[/tex] and radius r can be expressed as,

[tex]{\left( {x - h}\right)^2} + {\left({y - k} \right)^2}= {r^2}.[/tex]

Given:

A circle with center at [tex]\left({ - 3,2} \right).[/tex]

The passing through point is [tex]\left( {1,5} \right).[/tex]

Explanation:

The center is at [tex]\left( { - 3,2} \right).[/tex]

The passing through point is [tex]\left( {1,5} \right)[/tex]. Therefore, the point satisfies the equation of circle.

Substitute 1 for x, 5 for y, -3 for h and 2 for k in general equation of the circle to obtain the radius of circle.

[tex]\begin{aligned}{\left( {x - h}\right)^2}+{\left({y - k}\right)^2}&={r^2}\\{\left( {1 + 3} \right)^2} + {\left( {5 - 2}\right)^2}&= {r^2}\\16 + 9&= {r^2}\\\sqrt{25}&= r\\5&= r\\\end{aligned}[/tex]

The radius of the circle is [tex]\boxed{5{\text{ units}}}.[/tex]

The radius of the circle is [tex]\boxed{5{\text{ units}}}.[/tex]

Learn more:

1. Learn more about equation of circle brainly.com/question/1506955.

2. Learn more about domain of the function https://brainly.com/question/3852778.

3. Learn more about coplanar https://brainly.com/question/4165000.

Answer details:

Grade: Middle School

Subject: Mathematics

Chapter: Circle

Keywords: Circle, centered point, (-3,2), passes point (1,5), standard form of the circle, equation of the circle, center, diameter of circle, radius of the circle,center-radius form, general equation of circle, tangent, area of circle.

Answer: Its the 3rd choice.

No, as long as you remember that distance is awlays zero or positive.

Final answer:

The height of the plane above the ground after traveling 3,000 meters at a 15° angle of elevation is approximately 776.4 meters. This is calculated using the sine function: height = 3,000 m × sin(15°).

Explanation:

To find the height of the plane above the ground after taking off at an angle of elevation of 15° and traveling for 3,000 meters, we can use trigonometric functions. Specifically, the sine function relates the opposite side of a right-angled triangle (in this case, the height above ground) to the hypotenuse (the distance traveled by the plane).

The sine of an angle in a right triangle is equal to the length of the opposite side divided by the length of the hypotenuse. The formula is:

height = hypotenuse × sin(angle)

Here, the hypotenuse is the distance traveled by the plane (3,000 m), and the angle is 15°. Thus, the calculation would be:

height = 3,000 m × sin(15°)

We can calculate the sine of 15° using a calculator.

height = 3,000 m × 0.2588 (approximately)

height = 776.4 m (approximately)

Therefore, the plane is approximately 776.4 meters above the ground.

9 / 5/8 =

9/1 / 5/8 =

9/1 * 8/5 = 72/5 = 14 2/5