Answer:22
Step-by-step explanation:
diameter=d
Area=121π
area of circle=π x (d/2)^2
121π=π x d^2/4
121π=πd^2/4
Cross multiplying we get
121π x4=πd^2
484π=πd^2
Divide both sides by π
484π/π=πd^2/π
d^2=484
Taking the square roots of both sides we get
d=√(484)
d=22 diameter=22
Suppose that .06 of each of two populations possess a given characteristic. Samples of size 400 are randomly drawn from each population. The probability that the difference between the first sample proportion which possess the given characteristic and the second sample proportion which possess the given characteristic being more than .03 is _______.
Answer:
The correct answer to the following question will be "0.0367".
Step-by-step explanation:
The given values are:
[tex]p1=p2=0.06[/tex]
[tex]q1=q2=1-p1=0.94[/tex]
[tex]n1=n2=400[/tex]
As we know,
[tex]E(p1-p2)=p1-p2=0\\[/tex]
[tex]SE(p1-p2)=\sqrt{\frac{p1q1}{n1}+\frac{p2q2}{n2}}[/tex]
On putting the given values in the above expression, we get
[tex]= \sqrt{p1q1(\frac{1}{400}+\frac{1}{400})}[/tex]
[tex]=0.0168[/tex]
Now, consider
[tex]P(p1-p2>0.03)=P[\frac{(p1-p2)-E(p1-p2)}{SE(p1-p2)}>\frac{0.03-0}{0.0168}][/tex]
[tex]=P(Z>1.7857)[/tex]
[tex]=P(Z>1-79)[/tex]
[tex]=0.036727[/tex]
Therefore, "0.0367" is the right answer.
Calculating the probability of the difference between two sample proportions being more than 0.03 involves executing a hypothesis test via a z-test due to our large sample size. We formulate and employ a formula to get the z-score and then determine the associated p-value using a statistical tool.
Explanation:This question falls within the area of statistics, particularly dealing with hypothesis testing and comparison of two independent population proportions. Given that 0.06 of each population possess a certain characteristic and samples of size 400 are drawn from each, we are required to calculate the probability that the difference between the sample proportions exceeds 0.03.
First, we establish the null hypothesis (H0) and alternative hypothesis (Ha) for the test. H0: P1 = P2 and Ha: P1 ≠ P2. Here, P1 and P2 represent the populations respectively. Given a sufficiently large sample size (n > 30), we use a z-test for comparing the proportions.
In computing the z-score, we use the following formula: z = (P1 - P2) / √ ((P*(1 - P*) / n1) + (P*(1 - P*) / n2)). Here, P* = (x1 + x2) / (n1 + n2), where x is the number of successes in each sample (0.06*400 = 24 per population logistically).
The p-value associated with the calculated z-score, which represents the probability that the difference between the first sample proportion and the second sample proportion being more than 0.03, can be found using a statistical calculator or statistical software. The precise numerical value for p will depend on the computed z-score.
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A normal deck of cards has 52 cards, consisting of 13 each of four suits: spades, hearts, diamonds, and clubs. Hearts and diamonds are red, while spades and clubs are black. Each suit has an ace, nine cards numbered 2 through 10, and three face cards. The face cards are a jack, a queen, and a king. Answer the following questions for a single card drawn at random from a well-shuffled deck of cards.
What is the probability of drawing a king of any suit?
What is the probability of drawing a face card that is also a spade?
Answer:
a) 1/3
Step-by-step explanation:
a) Probability of drawing a king of any suit
Number of kings = 4
P(king) = 4/52
= 1/13
b) Probability of drawing a face card that is also a spade
Number of face =3
P(king) = 3/ 52
if h(x)=1-2/3x, find h(-6).
Answer:
5
Step-by-step explanation:
Put -6 where x is and do the arithmetic.
[tex]h(x)=1-\dfrac{2}{3}x\\\\h(-6)=1-\dfrac{2}{3}(-6)=1-\dfrac{-12}{3}=1-(-4)=1+4\\\\\boxed{h(-6)=5}[/tex]
A bag contains eleven equally sized marbles, which are numbered. Two marbles are chosen at random and replaced after each selection.
Eleven numbered marbles are shown. Marbles 2, 5, 6, 7, 8, 10, 11 are white. Marbles 1, 3, 4, 9 are purple.
What is the probability that the first marble chosen is shaded and the second marble chosen is labeled with an odd number?
StartFraction 10 Over 121 EndFraction
StartFraction 24 Over 121 EndFraction
StartFraction 6 Over 11 EndFraction
StartFraction 10 Over 11 EndFraction
EndFraction
StartFraction 24 Over 121 EndFraction
StartFraction 6 Over 11 EndFraction
StartFraction 10 Over 11 EndFraction
Answer:
StartFraction 24 Over 121 EndFraction
Step-by-step explanation:
Calculate the divergence of the following radial field. Express the result in terms of the position vector r and its length StartAbsoluteValue Bold r EndAbsoluteValue. FequalsStartFraction left angle x comma y comma z right angle Over x squared plus y squared plus z squared EndFraction equalsStartFraction Bold r Over StartAbsoluteValue Bold r EndAbsoluteValue squared EndFraction Choose the correct answer below. A. The divergence of F is 0. B. The divergence of F is StartFraction negative 2 Over StartAbsoluteValue Bold r EndAbsoluteValue Superscript 4 EndFraction . C. The divergence of F is StartFraction 1 Over StartAbsoluteValue Bold r EndAbsoluteValue squared EndFraction . D. The divergence of F is StartFraction negative 1 Over StartAbsoluteValue Bold r EndAbsoluteValue squared EndFraction
Answer:
C. The divergence of F is StartFraction 1 Over StartAbsoluteValue Bold r EndAbsoluteValue squared EndFraction
∇•F = 1/|r|²
Step-by-step explanation:
The position vector r = (x, y, z)
r = xi+yj+zk
|r| = √x²+y²+z²
|r|² = x²+y²+z²
Given the radial field F = r/|r|²
Divergence of the radial field is expressed as:
∇•F = {δ/δx i+ δ/δy j + δ/δy k} • {(r/|r|²)
∇•F = {δ/δx i+ δ/δy j + δ/δy k} • {xi/|r|² + yj/|r|² + zk/|r|²}
∇•F = δ/δx(x/|r|²) + δ/δy(y/|r|²)+δ/δz(z/|r|²)
Check the attachment for the complete solution.
Solve the right triangle shown in the figure. Around lengths to two decimal places and express angles to the nearest tenth of a degree.
Answer:
a = 65.37
b = 46.11
B = 35.2
Step-by-step explanation:
sin 54.8 = a / 80
a = 80 sin 54.8 = 65.3715 = 65.4
[tex]b^{2} = c^{2} - a^{2}[/tex]
b=[tex]\sqrt{80^2 - 65.3715^2}[/tex]
b=46.1147 = 46.11
B = 180 - 90 - 54.8 = 35.2
The sides and the angles as follows:
Therefore,
∠A = 54.8°
∠B = 35.2°
∠C = 90°
a ≈ 65.37
b ≈ 46.64
c = 80
The triangle is a right angle triangle. Using trigonometric ratios, let's find a.
sin 54.8 = opposite / hypotenuse
sin 54.8 = a / 80
a = 80 sin 54.8
a = 65.3715918668
a ≈ 65.37
let's use Pythagoras theorem to find b.
c² = a² + b²
b² = c² - a²
b² = 80² - 65²
b² = 6400 - 4225
b² = 2175
b = √2175
b = 46.6368952654
b ≈ 46.64
let's find ∠B
∠A + ∠B + ∠C = 180°
∠B = 180 - 54.8 - 90
∠B = 35.2°
Therefore,
∠A = 54.8°
∠B = 35.2°
∠C = 90°
The sides are as follows:
a ≈ 65.37
b ≈ 46.64
c = 80
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In cooking class, Sofia measures a stick of butter. It is 13 centimeters long, 3 centimeters
wide, and 3 centimeters tall. What is the volume of the stick of butter?
Answer: 117 centimeters
Step-by-step explanation:
Answer:
117 cm³
Step-by-step explanation:
To calculate the volume of a Rectangular Prism, we must use the formula:
l×w×h=V.
In this case, l= 13, w= 3, and h= 3.
When these values are substituted in, we get:
13×3×3= 117 cm³
Assume that when adults with smartphones are randomly selected, 58% use them in meetings or classes. If 10 adult smartphone users are randomly selected, find the probability that at least 5 of them use their smartphones in meetings or classes.
Answer:
79.85% probability that at least 5 of them use their smartphones in meetings or classes.
Step-by-step explanation:
For each adult, there are only two possible outcomes. Either they use their smartphone during meetings or classes, or they do not. The probability of an adult using their smartphone in these situations are independent of other adults. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
Assume that when adults with smartphones are randomly selected, 58% use them in meetings or classes.
This means that [tex]p = 0.58[/tex]
10 adults selected.
This means that [tex]n = 10[/tex]
Find the probability that at least 5 of them use their smartphones in meetings or classes.
[tex]P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 5) = C_{10,5}.(0.58)^{5}.(0.42)^{5} = 0.2162[/tex]
[tex]P(X = 6) = C_{10,6}.(0.58)^{6}.(0.42)^{4} = 0.2488[/tex]
[tex]P(X = 7) = C_{10,7}.(0.58)^{7}.(0.42)^{3} = 0.1963[/tex]
[tex]P(X = 8) = C_{10,8}.(0.58)^{8}.(0.42)^{2} = 0.1017[/tex]
[tex]P(X = 9) = C_{10,9}.(0.58)^{9}.(0.42)^{1} = 0.0312[/tex]
[tex]P(X = 10) = C_{10,10}.(0.58)^{10}.(0.42)^{0} = 0.0043[/tex]
[tex]P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.2162 + 0.2488 + 0.1963 + 0.1017 + 0.0312 + 0.0043 = 0.7985[/tex]
79.85% probability that at least 5 of them use their smartphones in meetings or classes.
Insert three geometric means between 2 and 81/8
Answer:
The three geometric means are 3, 9/2 and 27/4Step-by-step explanation:
The nth term of a geometric sequence is expressed as Tn = [tex]ar^{n-1}[/tex] where;
a is the first term
r is the common ratio
n is the number of terms
Since we are to insert three geometric means between 2 and 81/8, the total number of terms in the sequence will be 5 terms as shown;
2, a, b, c, 81/8
a, b, and c are the 3 geometric mean to be inserted
T1 = [tex]ar^{1-1}[/tex] = 2
T1 = a = 2....(1)
T5= [tex]ar^{5-1}[/tex]
T5 = [tex]ar^{4}[/tex] = 81/8... (2)
Dividing equation 1 by 2 we have;
[tex]\frac{ar^{4} }{a}= \frac{\frac{81}{8} }{2}[/tex]
[tex]r^{4} = \frac{81}{16}\\\\r = \sqrt[4]{\frac{81}{16} } \\r = 3/2[/tex]
Given a =2 and r = 3/2;
[tex]T2=ar\\T2 = 2*3/2\\T2 = 3\\\\T3 = ar^{2} \\T3 = 2*\frac{3}{2} ^{2} \\T3 = 2*9/4\\T3 = 9/2\\\\T4 = ar^{3}\\T4 = 2*\frac{3}{2} ^{3} \\T4 = 2*27/8\\T4 = 27/4\\[/tex]
Therefore the three geometric means are 3, 9/2 and 27/4
In a geometric sequence where three terms lie between 2 and 81/8, the three geometric terms are:
[tex]\mathbf{T_2 =3 }[/tex]
[tex]\mathbf{T_3 =\frac{9}{2} }[/tex]
[tex]\mathbf{T_4 =\frac{27}{4} }[/tex]
Recall:
nth term of a geometric sequence is given as: [tex]\mathbf{T_n = ar^{n - 1}}[/tex]a = the first term; r = the common ratio; n = the number of termsGiven a geometric sequence, 2 . . . 81/8, with three other terms in the middle, first, find the value of r.
Thus:
First Term:
a = 2Fifth Term:
[tex]T_5 = ar^{n - 1}[/tex]
a = 2
n = 5
r = ?
T5 = 81/8
Plug in the value of a, n, and T5[tex]\frac{81}{8} = 2r^{5 - 1}\\\\\frac{81}{8} = 2r^4\\\\[/tex]
Multiply both sides by 8[tex]\frac{81}{8} \times 8 = 2r^4 \times 8\\\\81 = 16r^4\\\\[/tex]
Divide both sides by 16[tex]\frac{81}{16} = \frac{16r^4}{16} \\\\\frac{81}{16} = r^4\\\\[/tex]
Take the fourth root of both sides[tex]\sqrt[4]{\frac{81}{16}} = r\\\\\frac{3}{2} = r\\\\\mathbf{r = \frac{3}{2}}[/tex]
Find the three geometric means [tex]T_2, T_3, $ and $ T_4[/tex] between 2 and 81/8.
[tex]\mathbf{T_n = ar^{n - 1}}[/tex]
a = 2
r = 3/2
Thus:[tex]T_2 = 2 \times (\frac{3}{2}) ^{2 - 1}\\\\T_2 = 2 \times (\frac{3}{2}) ^{1}\\\\\mathbf{T_2 = 3}[/tex]
[tex]T_3 = 2 \times \frac{3}{2} ^{3 - 1}\\\\T_3 = 2 \times (\frac{3}{2}) ^{2}\\\\T_3 = 2 \times \frac{9}{4}\\\\\mathbf{T_3 =\frac{9}{2} }[/tex]
[tex]T_4 = 2 \times \frac{3}{2} ^{4 - 1}\\\\T_4 = 2 \times (\frac{3}{2}) ^{3}\\\\T_4 = 2 \times \frac{27}{8}\\\\\mathbf{T_4 =\frac{27}{4} }[/tex]
Therefore, in a geometric sequence where three terms lie between 2 and 81/8, the three geometric terms are:
[tex]\mathbf{T_2 =3 }[/tex]
[tex]\mathbf{T_3 =\frac{9}{2} }[/tex]
[tex]\mathbf{T_4 =\frac{27}{4} }[/tex]
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2 ( n-1 ) + 4n= 2( 3n-1 )
Answer:
infinite solutions
Step-by-step explanation:
2 ( n-1 ) + 4n= 2( 3n-1 )
Distribute
2n -2 +4n = 6n -2
Combine like terms
6n -2 = 6n -2
Subtract 6n from each side
6n-2-6n = 6n-2-6n
-2 = -2
This is always true so there are infinite solutions
A recipe for a loaf of bread calls for of a cup of flour. If Milo used 12 cups of flour, how many loaves of bread did he prepare?
A.
18
B.
16
C.
15
D.
12
E.
8
Answer: The answer is D 12 i am pretty sure.
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
Which triangle can be solved using the law of sines?
Answer:
for AAS triangles or SSA
Step-by-step explanation:
Answer:
ny triangle whose two sides and 1 angle is known or 2 angles are known and 1 side is known
Step-by-step explanation:
brainliest.
The set {5, 6, 8, 9, 10} is part of a solution set for which inequality?
A. c+14<24
B. c+18≥24
C. c+18>24
D. c+14≤24
please help
Answer:
D. c+14≤24
Step-by-step explanation:
A. c+14<24 is c<10 (subtract 14)
B. c+18≥24 is c≥6 (subtract 18)
C. c+18>24 is c>6 (subtract 18)
D. c+14≤24 is c≤10 (subtract 14)
The set is {5, 6, 8, 9, 10}, so it should include each one of those numbers. C and A don't include 6 and 10 respectively, so they can't be the answer. B contains all numbers 6 and above, which doesn't include 5. The remaining letter is D, so that's the final answer.
How can you use a rational exponent to
represent a power involving a radical?
Answer:
[tex]\sqrt[n]{x^m}=x^{\frac{m}{n}}[/tex]
Step-by-step explanation:
A radical represents a fractional power. For example, ...
[tex]\sqrt{x}=x^{\frac{1}{2}}[/tex]
This makes sense in view of the rules of exponents for multiplication.
[tex]a^ba^c=a^{b+c}\\\\a^{\frac{1}{2}}a^{\frac{1}{2}}=a^{\frac{1}{2}+\frac{1}{2}}=a\\\\(\sqrt{a})(\sqrt{a})=a[/tex]
So, a root other than a square root can be similarly represented by a fractional exponent.
____
The power of a radical and the radical of a power are the same thing. That is, it doesn't matter whether the power is outside or inside the radical.
[tex]\sqrt[n]{x^m}=x^{\frac{m}{n}}=(\sqrt[n]{x})^m[/tex]
I need help ASAP what do I put for what I already know
Please help!! MATH! WILL MARK BRAINLIEST!!
Answer:
Step-by-step explanation:
10 POINTS ! PLZ HURRY AND ANSWER (:
Answer:
The top question = 189.25 rounded = 189.3 sq in
explanation: area= radius square x pi so radious is 5..sq will 25 then 25xpi(3.14)=78.50 78.50/2= 39.25 + 150 (area of rect) =189.25 rounded to 189.3
for the bottom question = 488 square cm
Step-by-step explanation:
17x22= 374
22-10=12
12x19=228 / 2 = 114
114 + 374 = 488 sq cm
A sphere has a diameter of 30 meters. What is the volume of the sphere.
Answer:
V≈14,137.17m³ or 4500π
Step-by-step explanation:
Formula: V=(1 /6)πd³
V=(1/6)π(30³)= 14137.16694115406957308189522475776297888726229718797619438.....
Answer:
14137.17 meters cubed
Step-by-step explanation:
volume = 14137.17 meters cubed
The pita‑franchise owner has observed in the past that waiting times tend to have a long tail to the right, with most customers served relatively quickly and a few rare customers required to wait a very long time.Is a two‑sample t ‑test appropriate in this setting?The two‑sample t ‑test is appropriate because this is a comparison of the means of two continuous, random variables.The two‑sample t ‑test is not appropriate because the two samples do not have the same size.The two‑sample t ‑test is not appropriate because the sample standard deviations are not equal.The two‑sample t ‑test is not appropriate because the distributions are not normal and the sample sizes are too small.The two‑sample t ‑test is appropriate because the samples are random and contain no outliers, and the populations are normal.
Answer:
The two‑sample t ‑test is not appropriate because the distributions are not normal and the sample sizes are too small.
Step-by-step explanation:
The complete question is:
The owner of a pita franchise with two locations is interested in the average time that customers spend waiting for service at each store. She believes that the average waiting time at the original location is higher than the average waiting time at the new location.
The pita‑franchise owner has observed in the past that waiting times tend to have a long tail to the right, with most customers served relatively quickly and a few rare customers required to wait a very long time.Is a two‑sample t ‑test appropriate in this setting?The two‑sample t ‑test is appropriate because this is a comparison of the means of two continuous, random variables.The two‑sample t ‑test is not appropriate because the two samples do not have the same size.The two‑sample t ‑test is not appropriate because the sample standard deviations are not equal.The two‑sample t ‑test is not appropriate because the distributions are not normal and the sample sizes are too small.The two‑sample t ‑test is appropriate because the samples are random and contain no outliers, and the populations are normal.
For two sample t-test the distributions must be normal. Here the data, as mentioned in the questions is skewed to the right with long waiting times in the past.
Final answer:
The two-sample t-test is not appropriate for the pita-franchise owner's observations because the waiting times are not normally distributed and the sample sizes are small. A test that does not assume normality, like the Mann-Whitney U test, would be more suitable in this situation.
Explanation:
The two-sample t-test is a statistical method used to determine if the means of two groups are significantly different. One key assumption for a two-sample t-test, however, is that the data should come from populations that are approximately normally distributed, especially if the sample sizes are not large. If the assumption of normality is violated and the sample size is small, as indicated by a distribution with a long tail to the right, the two-sample t-test may not be appropriate. To make an informed decision, it would also be necessary to consider the equality of variances, sample sizes, and independence of the samples.
In the context of a pita-franchise with long-tailed waiting times, the distribution is not normal, indicating that the normality assumption is not met. Consequently, using the two-sample t-test might lead to inaccurate results, especially if the sample sizes are too small to compensate for the lack of normality. In such cases, a different test like the Mann-Whitney U test, which does not assume normality, might be a better choice.
There is a spinner with 14 equal areas, numbered 1 through 14. If the spinner is spun one time, what is the probability that the result is a multiple of 3 or a multiple of 2?
Answer:
There is a 11/14 chance that the result is a multiple of 3 or a multiple of 2.
Step-by-step explanation:
Since the spinner is from 1 to 14, find all of the multiples of 3 and multiples of 2.
There are 4/14 multiples of 3 and 7/14 multiples of 2.
Add both of these numbers together 4/14 + 7/14 = 11/14
If this answer is correct, please make me Brainliest!
The probability of landing on a multiple of 2 or 3 when spinning a spinner numbered 1 through 14 is 4/7.
The student asked about the probability of getting a multiple of 3 or a multiple of 2 when spinning a spinner numbered 1 through 14. To determine this, we first list the multiples of 3 and 2 within the range of numbers on the spinner.
Multiples of 3: 3, 6, 9, 12
Multiples of 2: 2, 4, 6, 8, 10, 12, 14
Note that 6 and 12 are multiples of both 2 and 3, so we should not count them twice.
The total number of distinct multiples of 2 or 3 is 3 (multiples of 3) + 7 (multiples of 2) - 2 (common multiples) = 8 unique numbers. Since there are 14 possible outcomes on the spinner, the probability of landing on a multiple of 3 or 2 is 8 (favorable outcomes) divided by 14 (total possible outcomes).
The probability calculation is: 8/14, which simplifies to 4/7.
Find the Surface Area.
18m2
20m2
16m2
15m2
Answer:
20 meters square
Step-by-step explanation:
Surface Area of this square based pyramid = A = base area + 4* (face area)
A = (2 *2) + 4* ( (1/2)*2 * 4) )
A = 4 + 4*(4)
A = 4 + 16 = 20
A = 20 square meters
Consider the quadratic equation x2 = 4x - 5. How many solutions does the equation have?
Answer:
no real solutions2 complex solutionsStep-by-step explanation:
The equation can be rearranged to vertex form:
x^2 -4x = -5 . . . . . . . . . subtract 4x
x^2 -4x +4 = -5 +4 . . . . add 4
(x -2)^2 = -1 . . . . . . . . . show the left side as a square
x -2 = ±√-1 = ±i . . . . . . take the square root; the right side is imaginary
x = 2 ± i . . . . . . . . . . . . . add 2. These are the complex solutions.
_____
Comment on the question
Every 2nd degree polynomial equation has two solutions. They may be real, complex, or (real and) identical. That is, there may be 0, 1, or 2 real solutions. This equation has 0 real solutions, because they are both complex.
Mary lives on a corner lot. The neighborhood children have been cutting diagonally across her lawn instead of walking around the yard. If the diagonal distance across the lawn is 50 ft and the longer part of the sidewalk is twice the shorter length, how many feet are the children saving by cutting the lawn? round to the nearest foot if necessary.
Answer:
17 feet
Step-by-step explanation:
Length of the diagonal=50 feet
Let the shorter part of the sidewalk =x
Since the longer part of the sidewalk is twice the shorter length,
Length of the longer part of the sidewalk =2x
First, we determine the value of x.
Using Pythagoras Theorem and noting that the diagonal is the hypotenuse.
[tex]50^2=(2x)^2+x^2\\5x^2=2500\\$Divide both sides by 5\\x^2=500\\x=\sqrt{500}=10\sqrt{5} \:ft[/tex]
The length of the shorter side =[tex]10\sqrt{5} \:ft[/tex]
The length of the longer side =[tex]20\sqrt{5} \:ft[/tex]
Total Distance =[tex]10\sqrt{5}+ 20\sqrt{5}=67 \:feet[/tex]
Difference in Distance
67-50=17 feet
The children are saving 17 feet by cutting the lawn diagonally.
Click the prime number cards to build composite numbers to 50. Click the blank card to add a new prime number
Answer:
See Explanation
Step-by-step explanation:
A prime number is a number that is only divisible by by 1 and itself.Composite numbers on the other hand is any number which is not prime.To determine the number of prime cards needed to build a composite number, we simply express the number as a product of its prime factors.
These are:
4=2X2
6=2X3
8=2X2X2
9=3X3
10=2X5
12=2X2X3
14=2X7
15=3X5
16=2X2X2X2
18=2X3X3
20=2X2X5
21=3X7
22=2X11
24=2X2X2X3
26=2X13
27=3X3X3
28=2X2X7
30=2X3X5
32=2X2X2X2X2
33=3X11
34=2X17
35=5X7
36=2X2X3X3
38=2X19
39=3X13
40=2X2X2X5
42=2X3X7
44=2X2X11
45=3X3X5
46=2X2X13
48=2X2X2X2X3
49=7X7
50=2X5X5
Therefore for each of the numbers, those are the prime number cards to be used.
Increasing numbers of businesses are offering child-care benefits for their workers. However, one union claims that more than 85% of firms in the manufacturing sector still do not offer any child-care benefits to their workers. random sample of 330 manufacturing firms is selected and asked if they offer child-care benefits. Suppose the P-value for this test was reported to be p = 0.1071. State the conclusion of interest to the union. Use alpha=0.05 .
Final answer:
With a p-value of 0.1071 exceeding the significance level of 0.05, we do not reject the null hypothesis and conclude there is insufficient evidence to support the union's claim about child-care benefits in manufacturing firms.
Explanation:
The reported p-value of 0.1071 is greater than the significance level alpha (0.05). Based on this result, the appropriate statistical decision would be to do not reject the null hypothesis.
Therefore, at the 5 percent significance level, there is insufficient evidence to support the claim made by the union that more than 85% of firms in the manufacturing sector do not offer child-care benefits to their workers.
The higher p-value suggests that the data collected from the random sample of 330 manufacturing firms does not provide strong enough evidence to refute the possibility that the percentage of firms not offering child-care benefits is at or below 85%.
What is the volume of the triangular prism? A) 15 cm3 B) 18 cm3 C) 21 cm3 D) 24 cm3
Answer:
See Explanation Below
Step-by-step explanation:
The image of the trianglular prism is missing.
However, I'll answer your question using the attachment below.
The volume of a triangular prism is calculated as follows.
V = ½lbh
Where l = length of the prism
b = base of the prism
h = height of the prism
V = volume of the prism.
From the attachment,
Length, l = 6 cm
Base, b = 3 cm
And Height, h = 4 cm
By substituting each of these values in the formula given above
V = ½lbh becomes
V = ½ * 6 * 3 * 4
V = 3 * 3 * 4
V = 36 cm³
If you follow these steps you'll get the volume of the trianglular prism as it is in your question.
Answer:
its 15
Step-by-step explanation:
ik its 15 because when i put in 24 it was wrong and gave me the awnser which was 15
Valerie is taking a road trip over spring break. At 4:30 p.m. she looks down at her speedometer and notices that she is going 45 mph. Ten minutes later she looks down at the speedometer again and notices that she is going 55 mph. When was she moving exactly 50 mph?Select one:a. 4:30 p.m.b. 4:35 p.m.c. 4:40 p.m.d. Cannot be determined
Answer:
b. 4:35 p.m
Step-by-step explanation:
Her speed in t minutes after 4:30 p.m. is modeled by the following equation:
[tex]v(t) = v(0) + at[/tex]
In which v(0) is her speed at 4:30 pm and a is the acceleration.
At 4:30 p.m. she looks down at her speedometer and notices that she is going 45 mph.
This means that [tex]v(0) = 45[/tex]
Ten minutes later she looks down at the speedometer again and notices that she is going 55 mph.
This means that [tex]v(10) = 55[/tex]
So
[tex]v(t) = v(0) + at[/tex]
[tex]55 = 45 + 10a[/tex]
[tex]10a = 10[/tex]
[tex]a = 1[/tex]
So
[tex]v(t) = 45 + t[/tex]
When was she moving exactly 50 mph?
This is t minutes after 4:30 p.m.
t is found when v(t) = 50. So
[tex]v(t) = 45 + t[/tex]
[tex]50 = 45 + t[/tex]
[tex]t = 5[/tex]
5 minutes after 4:30 p.m. is 4:35 p.m.
So the correct answer is:
b. 4:35 p.m
Find the missing side of the triangle. Leave your answer in simplest radical
form.
Answer:
that answer is D
Step-by-step explanation:
I used pythagreum theurum a^2+b^2=c^2
then i divided square root 260 by 4 the largest perfect square factor which gives us 2 square root 65 because 4 is a perfect square that equal 2
Does anybody know how to do #11, I figured out #10
Answer:
no
Step-by-step explanation:
PLEASE- The label of a certain cheese states that it weighs 8 ounces. The actual weight of the product sold is allowed to be 0.2 ounces above or below that. Write a compound inequality that represents this situation.
Answer:
7.8《 X《 8.2
Step-by-step explanation:
Let X be the weight of the product
8 - 0.2《 X《 8 + 0.2
7.8《 X《 8.2
Answer:
7.8《 X《 8.2
Step-by-step explanation:
Let X be the weight of the product
8 - 0.2《 X《 8 + 0.2
7.8《 X《 8.2p