If the earth has a radius of 6.4 x 10^6 and it spins once per day, what is the centripetal force on a 100 kg man who is on the equator? This would make him weigh (less/more) by ____N

A particular isotope of plutonium has 94 protons, 147 neutrons, and a mass number of 241.

Explanation:

An atom is identified by two numbers:

Mathematically, this can be rewritten as

[tex]Z=p[/tex]

[tex]A=p+n[/tex]

where

p is the number of protons

n is the number of neutrons

For the isotope of plutonium in this problem, we have

[tex]Z=p=94[/tex], since it has 94 protons

[tex]A=p+n=241[/tex] (mass number)

From the second equation we get

[tex]n=241-p[/tex]

And substituting [tex]p=94[/tex], we find the number of neutrons:

[tex]n=241-94=147[/tex]

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Answer:

92, 147, 227

Explanation:

got it right on edge2022

Answer:

Velocity

Explanation:

                                   E = P.E + K.E

                                  P.E = mgh

                                  K.E = ½ mv²

A race track has 47520 inches.

Explanation:

Given that,

Length if the race track is 0.750 miles.

We know that, one mile is 5280 feet.

One feet is 12 inches.

To convert length of the track from miles to inches follow these steps:

Step 1:

Convert into feet:

Multiply 0.750 miles to 5280 feet.

Then the race track’s length is 3960 feet.

Step 2:

Convert into inch:

Multiply 3960 feet to 12 inches.

Then the race track’s length is 47520 inches.

Therefore, length of the race track in inches is 47520 inches.

Answer:

for physics the answer is 47500

The potential energy of the skater is 2352 J

Explanation:

The gravitational potential energy of a body is the energy possessed by the body due to its position in a gravitational field. Near the Earth's surface, it can be calculated as

[tex]PE=mgh[/tex]

where

m is the mass of the body

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity near the Earth's surface

h is the height of the body relative to the ground

For the skater in this problem,

m = 60 kg

h = 4 m

Substituting, we find her potential energy:

[tex]PE=(60)(9.8)(4)=2352 J[/tex]

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Explanation:

The number of images formed by a pair mirrors kept at an angle [tex]\alpha[/tex] is

[tex]n=\frac{360}{\alpha } -1[/tex]  if [tex]\frac{360}{\alpha }[/tex] comes even.

[tex]n=\frac{360}{\alpha }[/tex]      if [tex]\frac{360}{\alpha }[/tex] comes odd.

where [tex]n[/tex] is the number of images formed.

In our question,

[tex]\alpha =120^{0}[/tex]

[tex]\frac{360}{\alpha } =\frac{360}{120}=3[/tex]

It is odd,so [tex]n=\frac{360}{120}=3[/tex]

Answer:

"The Sierra Nevada mountain range of western North America, running along the eastern edge of the U.S. state of California."

Explanation:

Block Mountains:

Due, to stress created in side the crust of the earth the blocks or pieces of land or mass of land is created. In the past due to natural disaster and events that occurred in the ancient world, left us with some natural phenomenons called as block mountains. As the natural forces like seismic waves and other volcanic eruptions leads to such a disastrous amount of force that uplifts the mass of land on which it is acted upon.

Characteristics of the Block Mountains:

Types:

There are two main types of the block mountains,which are as below:

Answer:

Explanation: 0.02

Recall: μ mg = ma

μ = ?

m = 10N

g = 10m\s2

a = 0.2m\s

Substituting the values , we have

μ x 10 x 10 = 10 x 0.2

100  μ = 2

μ = 2/100

μ = 1/50

μ = 0.02

μ = 0.02

Final answer:

The coefficient of friction between the mass and the table is calculated using Newton's second law and the formula for the coefficient of friction, which results in a value of 0.08.

Explanation:

Calculation of Coefficient of Friction

To calculate the coefficient of friction, we can use Newton's second law which states that force equals mass times acceleration (F = ma). Given that a force of 10 N is applied to a 10 kg mass and the resulting acceleration is 0.2 m/s², we can deduce that there must be a frictional force opposing the applied force. The equation simplifies to F = ma + frictional force (f). Plugging in the known values, we get 10 N = (10 kg)(0.2 m/s²) + f, which results in f = 10 N - (10 kg)(0.2 m/s²) = 10 N - 2 N = 8 N.

The weight of the mass can be calculated using weight = mass × gravity, which gives us a weight of (10 kg)(10 m/s²) = 100 N. The normal force on a horizontal surface is equal to the weight of the object, so it's also 100 N. The coefficient of friction (mu) is calculated using the formula mu = frictional force / normal force. Therefore, mu = 8 N / 100 N = 0.08.

The coefficient of friction between the mass and the table is 0.08.

To determine the volume displaced by the 54 g sample of brass, use the water displacement method and calculate the density by dividing the mass by the volume.

To determine the volume displaced by the 54 g sample of brass, you need to use the water displacement method. Submerge the brass sample in water and measure the volume of water displaced. The volume of water displaced will be equal to the volume of the brass sample. Then, to calculate the density of the brass sample, divide the mass of the sample (54 g) by the volume of the sample.

For example, if the volume of water displaced is 30 mL, then the volume of the brass sample is also 30 mL. The density of the brass sample would be calculated as 54 g/30 mL = 1.8 g/mL.

The velocity of the ping-pong ball must be 8109 m/s

Explanation:

The momentum of an object is given by

[tex]p=mv[/tex]

where

m is the mass of the object

v is its velocity

For the bowling ball, we have

m = 9 kg

v = 3.28 m/s

so its momentum is

[tex]p=(9)(3.28)=29.5 kg m/s[/tex]

We want the ping-pong ball to have the same momentum, so:

p' = 29.5 kg m/s

And the mass of the ping-pong ball is

m = 3.638 g = [tex]3.638\cdot 10^{-3} kg[/tex]

Therefore, its velocity must be:

[tex]v=\frac{p}{m}=\frac{29.5}{3.638\cdot 10^{-3}}=8109 m/s[/tex]

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The velocity of the Ping-Pong ball can be found by setting the momentum of the bowling ball equal to the momentum of the Ping-Pong ball and solving for its velocity. Using the given masses and velocities, we can calculate the velocity of the Ping-Pong ball in m/s.

In order for two balls to have the same momentum, the momentum of the bowling ball must be equal to the momentum of the Ping-Pong ball. The momentum of an object is calculated by multiplying its mass by its velocity. Therefore, to find the velocity of the Ping-Pong ball, we can use the equation: momentum of bowling ball = momentum of Ping-Pong ball.

Given: mass of bowling ball = 9 kg, velocity of bowling ball = 3.28 m/s, mass of Ping-Pong ball = 3.638 g = 0.003638 kg (convert g to kg)

Momentum of bowling ball = mass of bowling ball × velocity of bowling ball

Momentum of Ping-Pong ball = mass of Ping-Pong ball × velocity of Ping-Pong ball

Setting the two momentum equations equal to each other, we can solve for the velocity of the Ping-Pong ball:

(9 kg) × (3.28 m/s) = (0.003638 kg) × (velocity of Ping-Pong ball)

Dividing both sides of the equation by 0.003638 kg will give us the velocity of the Ping-Pong ball:

velocity of Ping-Pong ball = (9 kg × 3.28 m/s) / 0.003638 kg

Calculating this expression will give us the velocity of the Ping-Pong ball in m/s.

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Answer:

Total moment of inertia when arms are extended: 1.613 [tex]kg\,m^2[/tex]

Explanation:

This second part of the problem could be a pretty complex one, but if they expect you to do a simple calculation, which is what I imagine, the idea is just adding another moment of inertia to the first one due to the arms extended laterally and use the moment of inertia for such as depicted in the image I am attaching.

In that image:

L is the length from one end to the other of the extended arms (each 0.75m from the center of the body) which gives 1.5 meters.

m is the mass of both arms. That is: twice 5% of the mass of the person: which mathematically can be written as: 2 * 0.05 * 56.5 = 5.65 kg

Therefore this moment of inertia to be added can be obtained using the formula shown in the image:

[tex]I_z=\frac{1}{12} \,m\,L^2\\\\I_z=\frac{5.65\,*\,1.5^2}{12} \\I_z=1.05937\,kg\,m^2[/tex]

Now, one needs to add this to the previous moment that you calculated, resulting in:

0.554 + 1.059 = 1.613 [tex]kg\,m^2[/tex]

Answer:

The time taken to travel is, t = 12 minutes

Explanation:

Given data,

The speed of the car, v = 60 km/h

The distance of travel, d = 12 km

The time taken for the travel is t = ?

The speed is defined as the distance divided by the time taken to travel. The formula for speed is,

                                  v = d/t

∴                                  t = d/v

                                    t = 12 km / 60 km/h

                                    t = 0.2 h

                                     t = 12 minutes

Hence, the time taken to travel is, t = 12 minutes.

Given that the average speed of the car is 60 km/hr and it needs to travel a distance of 12 km, it will take the car around 0.2 hours, which is equivalent to 12 minutes, to travel this distance.

This problem is related to the concept of speed, which in physics, is the distance covered per unit time. Here, we are asked to find the time so, we will use the formula for calculating time which is Time = Distance / Speed.

Given:

So, time needed can be calculated as:

Time = Distance / Speed

Time = 12 km / 60 km/hr

This gives Time = 0.2 hr.

But as we generally count time in minutes, we can convert hours into minutes. Since 1 hour = 60 minutes, therefore, 0.2 hr = 0.2 x 60 = 12 minutes.

So, it takes 12 minutes to travel 12 kilometers with an average speed of 60 kilometers per hour.

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Answer:

The bomb will remain in air for 17.5 s before hitting the ground.

Explanation:

Given:

Initial vertical height is, [tex]y_0=1500\ m[/tex]

Initial horizontal velocity is, [tex]u_x=688\ m/s[/tex]

Initial vertical velocity is, [tex]u_y=0(\textrm{Horizontal velocity only initially)}[/tex]

Let the time taken by the bomb to reach the ground be 't'.

So, consider the equation of motion of the bomb in the vertical direction.

The displacement of the bomb vertically is [tex]S=y-y_0=0-1500=-1500\ m[/tex]

Acceleration in the vertical direction is due to gravity, [tex]g=-9.8\ m/s^2[/tex]

Therefore, the displacement of the bomb is given as:

[tex]S=u_yt+\frac{1}{2}gt^2\\-1500=0-\frac{1}{2}(9.8)(t^2)\\1500=4.9t^2\\t^2=\frac{1500}{4.9}\\t=\sqrt{\frac{1500}{4.9}}=17.5\ s[/tex]

So, the bomb will remain in air for 17.5 s before hitting the ground.

Answer:

The horizontal velocities of the projectile for both cases are going to remain the same.

Explanation:

Taking the horizontal direction as x-axis and the vertical component as y-axis.

Let V be the object's velocity and θ be the angle formed with the horizontal.

Therefore,  

The horizontal component of velocity is,

                      [tex]V_{x}=V Cos\theta[/tex]

                      [tex]V_{y}=V Sin\theta[/tex]

Due to the force of gravity the vertical component of velocity changes. But there is no influence of force in the horizontal component other than the air resistance.

Hence, the horizontal component of the velocities of the projectile remains the same.

Answer:

3.2 m

Explanation:

we know

Hmax = V²/2g

= 8² / 2*10 = 3.2

Answer:

The ball will get upto the height of 3.26 meters.

Explanation:

Initial velocity of the ball = u = 8 m/s

final velocity of the ball = v = 0 m/s ( upward)

Acceleration due to gravity ,a= -g =[tex]-9.8 m/s^2[/tex]

Height of the ball when kicked = s

Using third equation of motion :

[tex]v^2-u^2=2as[/tex]

[tex](0 m/s)^2-(8 m/s)^2=2\times (-g)\times s[/tex]

[tex](0 m/s)^2-(8 m/s)^2=2\times (-9.8)\times s[/tex]

[tex]s=\frac{(-8 m/s)^2}{2\times -9.8 m/s^2}=3.26 m[/tex]

The ball will get upto the height of 3.26 meters.

Answer:

Thunder and lightning may become connected in the mind because they often occur together. This is an example of (A) law of similarity

Explanation:

"Gestalt law of similarity" states that objects or things that shares visual characteristics like shape, size, color, texture, value and orientation can be perceived as a unified group.

Thus thunder and lightning can be placed in the same group as lightning causes thunder. When passing from the clouds to that of the surface, a lightning strike pops open up a little void in the atmosphere, called a channel. After the lightning has disappeared, the atmosphere falls back in and produces a sound wave we perceive as a thunder.

Answer:

d. continuity

Explanation:

The law of continuity says that two events can become connected to each other if they happen close together. For example, thunder and lightning may become connected in the mind because they often occur together.

Answer:

The 'b x h' side of the brick exerts more pressure on the ground, P =  1428.57 N/m²    

Explanation:

Given data,

The dimension of the brick, l = 10 cm = 0.1 m

                                              b = 7 cm = 0.07 m

                                              h = 5 cm = 0.05 m

The force exerted by the brick on ground, F = 5 N

The brick has three 2 x 3 sides, b x h, l x h, and l x b

The area of the side, A₁ = b x h

                                        = 0.07 x 0.05

                                         = 0.0035 m²

The area of the side, A₂ = l x h

                                         = 0.1 x 0.05

                                          = 0.005 m²

The area of the side, A₃   = 0.1 x 0.07

                                          = 0.007 m²

The pressure exerted by the surface A₁ on the ground, P₁ = F/A₁

                                                                                                 = 5 / 0.0035

                                                                                                  = 1428.57 N/m²

The pressure exerted by the surface A₁ on the ground, P₂ = F/A₂

                                                                                                  = 5 / 0.005

                                                                                                  = 1000 N/m²  

The pressure exerted by the surface A₁ on the ground, P₃ = F/A₃

                                                                                                 = 5 / 0.007

                                                                                                  = 714.29 N/m²  

Hence, the 'b x h' side of the brick exerts more pressure on the ground, P =  1428.57 N/m²                                                

The forces that act upon a baseball player diving head-first into second base and sliding on the infield dirt are the Normal Force, Gravity Force, and Friction Force.

When a baseball player dives head-first into second base and slows down while sliding on the infield dirt, several forces act upon the player. These forces include:

Therefore, the correct answers would be a. Normal Force, b. Gravity Force, d. Friction Force.

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Answer:

The second option: 11 kg * m/s

Explanation:

Recall that linear momentum is defined as the product of the mass times its velocity, therefore in this case, the mass is 0.45 kg , and the speed is 25 m/s, therefore the linear momentum is:

P = m * v = 0.45 Kg * 25 m/s = 11.25 kg * m/s

So roundng the answer to the nearest whole number, you get 11 kg * m/s, which is the second option they give you.

Answer:

11 kg • meters per second

Explanation:

Answer:

x-axis

Explanation:

when it is at rest, horizontal, on a graph it is the x-axis.

Hope this helped!

Answer:

it is A aluminum

Explanation:

Answer:

Aluminium has best conductivity

So option (a) will be correct answer

Explanation:

We have given material resistance of of different material

Aluminium = 0.0000000282 ohm

Carbon = 0.000035

Germanium = 0.46 ohm

And silicon = 640 ohm

We know that resistance is the opposition in flow of current and conductivity of the material is inversely proportional to the resistance

So the material which has less Resistance will have high conductivity

As aluminium has less resistance so it will have high conductivity

So option (a) will be correct answer

Answer:

26

Explanation:

Answer:

An unbalanced force.

Explanation:

Teacher: "An object in motion will stay in motion unless..."

Auggie : "Acted on by an unbalanced force."

Teacher: "Very good."

The current in the circuit is 5 A

Explanation:

The intensity of current is given by the equation:

[tex]I=\frac{q}{t}[/tex]

where

I is the current

q is the amount of charge passing through a given point of the circuit in a time interval of t

For the cell in this problem, we have

q = 150 C is the charge

t = 30 s is the time interval

Substituting into the equation, we f ind

[tex]I=\frac{150}{30}=5 A[/tex]

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The amount of energy transferred is 4320 J

Explanation:

Power is defined as the amount of energy transferred per unit of time:

[tex]P=\frac{E}{t}[/tex]

where

P is the power

E is the amount of energy transferred

t is the time

In this problem, we have:

P = 720 W is the power

t = 6 s is the time elapsed

Solving for E, we find the energy transferred needed to push the box:

[tex]E=Pt=(720)(6)=4320 J[/tex]

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Answer:

Elements in a period share the highest unexcited electron energy level. There are more elements in some periods than others because the number of elements is determined by the number of electrons allowed in each energy sub-level.

Explanation:

Answer:

flexibility

Explanation:

Answer:

Sulfate

The sulfate or sulphate (see spelling differences) ion is a polyatomic anion with the empirical formula SO2−4. Sulfate is the spelling recommended by IUPAC, but sulphate is used in British English. Salts, acid derivatives, and peroxides of sulfate are widely used in industry. Sulfates occur widely in everyday life. Sulfates are salts of sulfuric acid and many are prepared from that acid.

Sulfide

Sulfide (systematically named sulfanediide, and sulfide(2−)) (British English sulphide) is an inorganic anion of sulfur with the chemical formula S2− or a compound containing one or more S2− ions. It contributes no color to sulfide salts. As it is classified as a strong base, even dilute solutions of salts such as sodium sulfide (Na2S) are corrosive and can attack the skin. Sulfide is the simplest sulfur anion.

Answer:

If Galileo's experiment did not measure the speed of light, it measures man's reaction time.

Option B

Explanation:

Answer:

Galileo's experiment measured mans reaction time.

Explanation:

Explanation:

The given problem should be solved using basic sedimentary laws proposed by Nicolas Steno and other group of geologists.

Some of the laws that would find application in this problem are:

Based on this premise, we can derive the geologic column for the area:

                       Chart A                                               Chart B

                        Erosion                                              Erosion

1                             C                                                          a

2                             E                                                         e

3                             H                                                         h

3                         Erosion                                                   m

4                           A                                                         Erosion

5                            B                                                              c

6                            F                                                               j

7                            D                                                              l

8                            L                                                              g

9                            G                                                              k

10                           J                                                              f

11                            i                                                                i

12                                                                                          d

13                                                                                           b

The above was derived using the sedimentary laws for relative dating.

Observations 1

In Record A unconformity will occur between layers H and A

    Record B unconformity will occur between layers c and m

An unconformity is a huge break in the stratigraphic record. It is usually a time gap as a result of non-deposition of sediments, erosion of a rock layers amidst other factors.

The type of unconformity here is called an angular unconformity.

In this kind of unconformity, parallel beds are deposited on the tilted or folded layer below resulting in an angular discordance of some sort.

The surface between H and A is an erosional surface of the tilted beds in record A. This was followed by the deposition of new beds that are parallel to the tilted ones below.

In record be, a folded and eroded surface separate c and m.

Analysis 2

In record A, the rock layer K is older than F but younger than D. This rock layer has been tilted. This interpretation is based on the law of superposition of strata. If the sequences are reconstructed without the tilt, layer K will be on top of D and F will be on top of K.

Analysis 3

Layer c is younger than j but older than the parallel lying m on top of it. This geologic structure is called a synform. In synform, the rock strata has a concave shape. Usually, we can assume that this is a synformal syncline in which the youngest bed is at the core of the fold. This pits layer c as the youngest in the folded beds. The age increases outward in a synform.

Analysis 4

Layers C and E in record A are both eroded beds. Layer C has been eroded to the level of layer E.

We can establish that when layer C was exposed and eroded, the overburden on the earth was relieved and part of bed E re-adjusted up to the level of E.

Analysis 5

Reconstructing the geologic history of A

To form a sedimentary rock sequence, a basin must be available. Sedimentary basins are natural depressions on the earth crust in which sediments collects and are deposited.

Sediments i - A were deposited layer by layer into the basin. They became compacted and lithified to form sedimentary rocks.

With the passage of time, these layers became tilted by natural forces. This could be an earthquake, stress e.t.c

After the tilting, a period of non-deposition occurred in which the forces of denudation prevailed to cause the erosion of the bed when it was uplifted and exposed.

After this period, layers H-C was then deposited, compacted and lithified. The whole rock sequence was then uplifted exposing some rock layers. Erosion washed parts of layers C and E to what we can see in the present day.

Analysis 6

In record B, sequences b-c were laid in the basin of deposition where they were transformed into sedimentary rocks.

The rocks were then subjected to a compressive stress regime. The layers buckled and a synformal sycline fold formed.

After this period, the rock was uplifted and exposed. Erosion caused the washing away of parts of the top layer.

A period of deposition shortly followed and parallel layers m-a were deposited. This layer was then transformed into sedimentary rocks.

After this the layer became exposed and part of a was eroded to its present day level.

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Due to missing visuals, it's impossible to provide factual answers. Remember, rock layers are in order of their age, youngest at top, oldest at bottom, taking into account any geological disruptions. This concept should help in interpreting the charts and layers.

Apologies, but it's impossible to assist effectively as we cannot view your Page 1 or the Rock Records you're referring to. However, I can guide you on how to interpret rock layers. Always remember that the youngest layer of rock is located at the top, and the oldest at the bottom, unless disturbed by a geological event like a tilting, erosion or folding. Look for signs of these disturbances - tilting might have shifted the layers from their horizontal plane, erosion can create gaps in the sequence, and folding could have distorted the layers. If a layer cuts across another (like an intruding magma chamber or a fault), it is younger. This should assist you in interpreting both Chart A and Chart B. Consider these tips while studying the age of a certain layer (e.g., layer K or C) and while making conclusions on how the group of rock layers formed.

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