If the exchange rate changes from​ $1.45 = 1 euro to​ $1.37 = 1​ euro, then

Answers

Answer 1
the euro has depreciated and the dollar as appreciated

Related Questions

Aubrey has a new art box in the shape of a rectangular prism. The box is 5 inches, by 8 inches, by 2 inches. How much volume is not take-up by the eraser if the dimension of the eraser is 5.5 inches^3

Answers

I think the answer is 74.5

volume of the rectangular prism = base area * height

base area = length * breadth

volume of the rectangular prism = length * breadth * height

volume of the rectangular prism = 5*8*2 = 80 inches ^3

volume of taken up by the eraser = 5.5 inches^3

volume that is not take-up by the eraser = 80-5.5 = 74.5 inches^3

Suppose your friend’s parents invest $20,000 in an account paying 5% interest compounded annually. What will the balance be after 10yr?

Answers

Answer: $32,577.90

A = P (1+ r/n)^nt
P= 20000
R = .05
n = 1
t = 10

To find the balance after 10 years when $20,000 is invested at 5% interest compounded annually, we can use the formula for compound interest:

A = P(1+r)ⁿ

Where:

*A is the complete volume of money obtained after

*n years, including interest.

*P embodies the initial investment, or the principle amount.

*The yearly interest rate, calculated by decimal, is r.

*n is the number of periods the money has been put into investments for.

Given:

*P = $20,000

*r = 5% = 0.05

*n = 10 years

Taking appropriate values to carry out the calculation:

A = 20000(1 + 0.05)¹⁰

A = 20000(1.05)¹⁰

Now, let's calculate:

A ≈ 20000 × (1.05)¹⁰

A ≈ 20000 × 1.62889462677744

A ≈ 32577.89

So, the balance after 10 years will be approximately $32,577.89.

After 10 years, the balance of the investment can be calculated using the formula for compound interest: A = P(1+r)ⁿ

Where:

*A is the amount of money accumulated after

*n years, including interest.

*P is the principal amount (the initial investment).

*r is the annual interest rate (in decimal).

*n is the number of times the interest is compounded per year.

In this case, the principal (P) is $20,000, the annual interest rate (r) is 5%, and the investment is compounded annually. Substituting these values into the formula:

A = 20000(1.05)¹⁰

A ≈ 20000 × (1.05)¹⁰

After computation, the balance after 10 years is approximately $32,577.89. This represents the accumulated amount including the initial investment and the interest earned over the 10-year period.

Complete Question:

Suppose your friend’s parents invest $20,000 in an account paying 5% interest compounded annually. What will the balance be after 10yr?

Algebra question ( Matrices and Determinants ) 20 points

Answers

The correct answer is option A

The answer is as following 
The new matrix is 2 rows and 2 columns . i.e. it is 2*2 matrix
The element a₁₁ =5*2 + 0*2 = 10
The element a₁₂ = 5*-1 + 0*-2 = -5
The element a₂₁ = 3*2 +-5*2 = -4
The element a₂₂ = 3*-1 + -5*-2 = 7

The new matrix will be [tex] \left[\begin{array}{ccc}10&-5\\-4&7\end{array}\right] [/tex]

The window is 60 inches wide. What is the width of the window in feet.

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The width of the window in feet is 5 feet.
The Width Of The Window In Feet Is 5 Feet Because Every Foot Is 1 Inch.

60 Divided By 12 = 5

Answer: 5 Feet

Anyone know the answer?

Answers

Hi there your answer would be d
The answer is D. 77. 

Which graph shows the same end behavior as the graph of f(x) = 2x6 – 2x2 – 5?

Answers

[tex]Given \ function : \ f(x) = 2x^6-2x^2-5[/tex]

In order to find the end behavior of the graph, we need to find the degree of the given function and the leading coefficent.

Degree of the given function is the highest power of the variable.

We have variable x there.

Highest power of x is 6.

So, we can say:

Degree = 6 ( an even degree)

And leading coefficent is the coefficent of highest power term.

We have highest power term is 2x^6.

So, the leading coefficent is : 2 (Positive number)

For even degree and positive leading coefficent, end behaviour is

x --> ∞  f(x) = +∞

x-->-∞   f(x) = +∞

Answer:

The answer is A on edg

Step-by-step explanation:

just took the test

What is the place value of the digit 4 in 6,296.04

Answers

Hoi!

The digit 4 is in the hundredths place, since it's behind a decimal.

Place value in front of a decimal goes as:

Ones, tens, hundreds, thousands, etc

Place value behind a decimal goes as:

Tenths, Hundredths, Thousandths, etc

The digit 4 in 6,296.04 is in the hundredths place, representing four hundredths or 4/100. This can also be expressed in scientific notation as 4 x 10⁻².

The place value of the digit 4 in 6,296.04 is in the hundredths position. This is because the digit 4 is two places to the right of the decimal point. In a decimal number, the first place to the right of the decimal point is the tenths place, the second is the hundredths place, and it continues with thousandths, ten-thousandths, and so on. Therefore, in the number 6,296.04, the 4 represents four hundredths, or 4/100, which can also be written in scientific notation as 4 × 10⁻².

HELP PLEASE Simplify the rational expression. State any excluded values. x^2-12x+35/x^2-3x-10

Answers


[tex]\frac{{x}^{2} - 12x + 35 }{ {x}^{2} - 3x - 10 } [/tex]
Factorise both the term by splitting the mid term and you'll get


[tex] \frac{ {x}^{2} - 5x - 7x + 35}{ {x}^{2} - 5x + 2x - 10 } \\ = \frac{x(x - 5) - 7(x - 5)}{x(x - 5) + 2(x - 5)} \\ = \frac{(x - 7)(x - 5)}{(x + 2)(x - 5)} \\ = \frac{x - 7}{x + 2} [/tex]

A ball is kicked into the air and follows the path described by h(t)= -4.9t^2+6t+0.6. where t is the time in seconds and h is the height in meters above the ground. Find the maximum height of the ball. What value would you have to change in the equation if the maximum height of the ball is more than 2.4 meters?

FIND THE VETEX!!!!

Answers

For this case we have the following equation:
 h (t) = -4.9t ^ 2 + 6t + 0.6
 Deriving we have:
 h '(t) = -9.8t + 6
 We equal zero and clear t:
 -9.8t + 6 = 0
 9.8t = 6
 t = 6 / 9.8
 t = 0.61
 We substitute the value of time in the equation of the height:
 h (0.61) = -4.9 * (0.61) ^ 2 + 6 * (0.61) +0.6
 h (0.61) = 2.44m
 For the height to be higher than 2.44m, two values can be changed:
 Initial speed: 6
 Initial height: 0.6
 Answer:
 
The maximum height of the ball is:
 
h (0.61) = 2.44m
 
You would have to change in the equation if the maximum height of the ball is more than 2.4 meters:
 
Initial speed: 6
 or
 
Initial height: 0.6

Which kind of function best models the data in the table? Use differences or ratios.


A. linear
B. quadratic
C. exponential
D. none of the above

Answers

The data in the table represents a C. exponential function. In an exponential function, as x-values increase, y-values get greater and greater. The y-values increase more rapidly as x-values increase linearly.
The answer would be B. Hope this helps :)

Find the slope of the line graphed below

Answers

4/6, but the simplified form of it is 2.3

The slope of the line is 2/3

To find the slope of the line, first choose two points that are on the line. For this example we'll use (0, -4) and (6, 0). Now use the slope formula with these two points to find the slope.

m(slope) = (y2 - y1)/(x2 - x1)

m = (0 - -4)/(6 - 0)

m = (0 + 4)/(6 - 0)

m = 4/6

m = 2/3

help plzzzzzzzzz????? asapp

Answers

The two angles are a linear pair.
(Explanations down below!)

Linear pair angles must add up to 180 degrees. You can tell that the two angles add up to 180 degrees because they form a straight line (which is 180 degrees).

Complementary angles add up to 90 degrees. The two angles are not complementary because they do not form a 90 degree angle (right triangle, square in corner, like a L shape).

Vertical angles are opposite each other and are equal to one another. These angles are adjacent to each other and do not look similar.

Identify the values that create ordered pairs that are solutions to the equation 3x - 5y = 20.

(5,y) (x,2)

Answers

X=10 Y=1

thats your answer hope it helps ;P
3x - 5y = 20

(5; y)  -  put x = 5 to the equation

3 · 5 - 5y = 20
15 - 5y = 20  |-15
-5y = 5  |:(-5)
y = -1

Answer: (5; -1)

(x; 2)  -  put y = 2 to the equation

3x - 5 · 2 = 20
3x - 10 = 20    |+10
3x = 30    |:3
x = 10

Answer: (10; 2)

You flipped a coin 70 times and recorded 23 heads. What is the experimental probability of flipping tails?

ANY HELP IS APPRECIATED!
Please show work

Answers

The experimental probabilities relies on the fact of actual occurrence of the experiment and events. It is the ratio of the number of times an event is occurring to the total number of times that activity has been repeated for.
thus:
experimental probability of our case will be:
P(H)=(# of times of occurrence of the event)/(# of trials)
=23/70
So the probability of getting a head in the experiment is 23/70=0.33

10 POINTS!!! FULL ANSWER IN STEP BY STEP FORMAT!! ALL PARTS A, B, C, D, E

Answers

The first thing to do is to get the graph. That's below. That is a very wicked looking graph. I'm not sure what happens at 0. I'm not sure it is continuous at 0. That's something to make a fuss over because x = 0  is one of the x intercepts.

y = - x^(2/5)(x(5/5) + 7).
y = - x^(2/5)(x + 7)
So one of the x intercepts is 0 and the other one is -7.

The reasons are known because the factors can be equated to 0. It does not look to me like there is exact symmetry. There is a local minimum however at what the graph says is (-2,-6.5 or so)
You could differentiate that to find the exact point, but you are not asked for that.

So the domain is from -∞ to zero and 0 to plus ∞ I think you have to exclude 0 even though it is an x intercept. 

The graph decreases from -∞ < x < -2
It increases from -2 < x < 0
It decreases form 0< x < ∞

What constant term should be used to complete the square? x 2 - 5x + _____ = 7

Answers

For this case we have an expression of the form:
 x ^ 2 - 5x + _____ = 7
 To complete the square, we must add to both sides of the equation a constant of the form:
 (b / 2) ^ 2
 We have then:
 x ^ 2 - 5x + (-5/2) ^ 2 = 7 + (-5/2) ^ 2
 Rewriting we have:
 x ^ 2 - 5x + 6.25 = 7 + 6.25
 x ^ 2 - 5x + 6.25 = 13.25
 Answer:
 
The constant term that should be used to complete the square is:
 
6.25
the correct answer is 25/4 so  choose letter  as you answer have beautiful day.

Isabel is purshing a 5 pound bag of dog food.how many 8- ounce servings can she feed her dog (1lb=16oz

Answers

1 pound = 16 ounces
16 ounces / 8 ounces = 2 servings per pound

5 pound bag x 2 servings per pound = 10 total servings

Simplify: x+2/x2-6x-16 ÷ 1/9x

Answers

[tex]\dfrac{x+2}{x^2-6x-16}:\dfrac{1}{9x}=\dfrac{x+2}{x^2-8x+2x-16}\cdot9x=\dfrac{x+2}{x(x-8)+2(x-8)}\cdot9x\\\\=\dfrac{x+2}{(x-8)(x+2)}\cdot9x=\dfrac{1}{x-8}\cdot9x=\dfrac{9x}{x-8} [/tex]

When i am divided into 22, the remained is one. when i am added to 5, the answer is an even number. what number am i? * 5 7 9 10 4 2/5?

Answers

Working with the given answers we can find the correct answer. Indeed, it is a comfortable and cozy way to solve this problem. We have given 5, 7, 9, 10, 4 and 0.4. Among these numbers, if we take 7 we can see that when 22 is divided into that, 1 is remaining and when we sum up 7 and 5, the result is 12, which is an even number. The correct answer is 7

Answer:

Number is 23.

Step-by-step explanation:

We have been given the information when a number is divided by 22 the remainder is 1.

And when it is added to 5  it will give us an even number.

So, the number 23 if we take when divided by 22 it will give the remainder 1.

And when added to 5 it will give 23+5=28 which is an even number.

So, the number is 23.

What is EC if AC = 12, BC = 5, and DC = 4?

A. 30
B. 9
C. 15
D. 7

Answers

we need to find ED first

the formula for this would be (AB +BC)*BC = (ED+DC)*DC

lets replace the letters with the given numbers:

If AC = 12 and BC = 5 then AB = 12-5 = 7

so we get:
(7+5) *5 = (ED+4)*4

12*5 = (ED+4)*4

60 = (ED+4)*4

60/4 = (ED+4)

15 = ED +4

ED = 15-4 = 11

now add ED + DC to get EC

11+4 = 15
 The answer is C. 15

Help me please and I will return the favor !

Answers

The answer is c) Step 3
The explanation is self explanatory
i think the answer would be c

Write the expression in complete factored form 5(y-7)+b(y-7)

Answers

the answer is (y-7)(5+b)

I would appreciate it if someone could please check my work on this calculus problem! My steps/answers are in green.

Answers

A. Correct.
B. Some error in evaluation. The result should be near 2.10592505299.
C. Your final answer should have ln(2) in the denominator. The evaluation should be near 1.354326176.
D. Need ln(4) in the denominator everywhere. The evaluation should be near 79.408765453.

"the placement test for a college has scores that are normally distributed with a mean of 600 and a standard deviation of 60.if the college accepts only the top 1​% of​ examinees, what is the cutoff score on the test for​ admission?"

Answers

Given that only the top 1% are admitted, the cutoff will be as follows:
the z-score is given  by:
z=(x-μ)/σ
where:
μ-mean
σ-standard deviation
P(x>X)=1-P(z<Z)=0.01
⇒P(z<Z)=1-0.01=0.99
thus:
the value of z that corresponds to 0.99 is 2.33
thus:
2.33=(x-600)/60
solving for x we get:
139.8=x-600
x=739.8
thus the cutoff was 739.8


Will give brainliest!  pts to the correct answer! Are quadratic equations already in rectangular form? I'm asked to eliminate the parameter t from these two questions to get it into the rectangular equation with x and y. Is it possible?
x(t) = 0.5t^2+0.4t-87.30
y(t)= 0.4t^2+0.1t +29.44

Answers

[tex]\bf x(t)=0.5t^2+0.4t-87.30\implies x(t)=\cfrac{1}{2}t^2+\cfrac{2}{5}t-\cfrac{873}{10} \\\\\\ x=\cfrac{1}{2}\left( t^2+\cfrac{4}{5}t+\boxed{?}^2 \right)-\cfrac{873}{10}[/tex]

so, as you already know, we'll borrow from our good friend Mr Zero, 0, to get that missing value for the perfect square trinomial,

[tex]\bf x=\cfrac{1}{2}\left[ t^2+\cfrac{4}{5}t+\left( \cfrac{2}{5} \right)^2-\left( \cfrac{2}{5} \right)^2 \right]-\cfrac{873}{10} \\\\\\ x=\cfrac{1}{2}\left[t^2+\cfrac{4}{5}t+\cfrac{4}{25}-\cfrac{4}{25} \right]-\cfrac{873}{10} \\\\\\ x=\cfrac{1}{2}\left[t^2+\cfrac{4}{5}t+\left( \cfrac{2}{5} \right)^2\right]-\cfrac{2}{25}-\cfrac{873}{10} \\\\\\ x=\cfrac{1}{2}\left[t^2+\cfrac{4}{5}t+\left( \cfrac{2}{5} \right)^2\right]-\cfrac{4369}{50}[/tex]

[tex]\bf x=\cfrac{1}{2}\left( t+\frac{2}{5} \right)^2-\cfrac{4369}{50}\implies x+\cfrac{4369}{50}=\cfrac{1}{2}\left( t+\frac{2}{5} \right)^2 \\\\\\ 2x+\cfrac{4369}{25}=\left( t+\frac{2}{5} \right)^2\implies \sqrt{2x+\cfrac{4369}{25}}=t+\cfrac{2}{5} \\\\\\ \sqrt{2x+\cfrac{4369}{25}}-\cfrac{2}{5}=t[/tex]

[tex]\bf -------------------------------\\\\ y(t)=0.4t^2+0.1t+29.44\implies y=\cfrac{2}{5}t^2+\cfrac{1}{10}t+\cfrac{736}{25} \\\\\\ y=\cfrac{2}{5}\left( \sqrt{2x+\cfrac{4369}{25}}-\cfrac{2}{5} \right)^2+\cfrac{1}{10}\left( \sqrt{2x+\cfrac{4369}{25}}-\cfrac{2}{5} \right)+\cfrac{736}{25}[/tex]

In a large population, 61 % of the people have been vaccinated. if 4 people are randomly selected, what is the probability that at least one of them has been vaccinated?

Answers

Final Answer:

The probability that at least one of the four randomly selected people has been vaccinated is approximately 0.9606.

Explanation:

To find the probability that at least one of the four randomly selected people has been vaccinated, we can use the complement rule. The complement of "at least one person vaccinated" is "none of the people vaccinated." Then, we subtract the probability of none of them being vaccinated from 1.

Given that 61% of the population has been vaccinated, the probability that a randomly selected person has been vaccinated is [tex](P(\text{vaccinated}) = 0.61\)[/tex].

So, the probability that a randomly selected person has not been vaccinated is [tex]\(P(\text{not vaccinated}) = 1 - P(\text{vaccinated}) = 1 - 0.61 = 0.39\).[/tex]

Now, we can find the probability that none of the four randomly selected people has been vaccinated:

[tex]\[P(\text{none vaccinated}) = (0.39)^4\][/tex]

And the probability that at least one of them has been vaccinated is the complement of this:

[tex]\[P(\text{at least one vaccinated}) = 1 - P(\text{none vaccinated}) = 1 - (0.39)^4\][/tex]

Let's calculate it:

[tex]\[P(\text{at least one vaccinated}) = 1 - (0.39)^4\][/tex]

[tex]\[P(\text{at least one vaccinated}) \approx 1 - 0.0394179 \][/tex]

[tex]\[P(\text{at least one vaccinated}) \approx 0.9605821\][/tex]

So, the probability that at least one of the four randomly selected people has been vaccinated is approximately 0.9606.

The probability that at least one of the 4 randomly selected people has been vaccinated is calculated using the complement rule and is found to be 0.9769.

To determine the probability that at least one of the 4 randomly selected people has been vaccinated, we can use the complement rule. The probability of an individual not being vaccinated is 1 - 0.61 = 0.39.

We need to calculate the probability that none of the 4 selected people are vaccinated and subtract this from 1:

Probability that a single person is not vaccinated: 0.39Probability that all 4 people are not vaccinated: 0.39⁴0.39⁴ = 0.0231

Thus, the probability that at least one of them is vaccinated is:

1 - 0.0231 = 0.9769

Therefore, the probability that at least one of the 4 randomly selected people has been vaccinated is 0.9769.

A toy company produces two kites whose shapes are geomaetrically similar. Find the length of the missing size of similar kite.

Answers

your answer is x=17.5

A number cube is rolled 120 times. The number 4 comes up 47 times. What is the experimental probability of rolling a 4? What is the theoretical probability of rolling a 4?

A. 47/120; 1/30
B. 47/120; 1/6 ******
C. 4/47; 1/6
D. 1/6; 47/120

Am I Correct? 

Answers

Yes you are.
(Your answer is B, right?)

A number cube is rolled 120 times. The number 4 comes up 47 times.

We have to determine the experimental probability of rolling a 4.

The formula to evaluate probability of an event is given by:

Probability  = [tex] \frac{Favourable outcomes}{Total outcomes} [/tex]

So, Probability of rolling a 4 = [tex] \frac{ Total number of times when 4 appears}{Total number of times number cube rolled} [/tex]

= [tex] \frac{47}{120} [/tex]

Now, we have to find the theoretical probability of rolling a 4.

Total number of outcomes of number cube = {1,2,3,4,5,6}

Probability of rolling a 4 = [tex] \frac{1}{6} [/tex]

So, Option B is the correct answer.

What do the graphs of sine and cosine have in common with the swinging you see?
Which reasons did you think of?

Answer:

The high and low points repeat in a pattern.
The cycle repeats at equal time intervals.
The swinging motion is smooth, unabrupt.

Answers

Final answer:

The graphs of sine and cosine functions have similarities with the swinging motion such as repeating patterns at equal time intervals and smoothness.

Explanation:

The graphs of sine and cosine functions have several similarities with the swinging motion you observe:

Both the high and low points in the graphs of sine and cosine functions repeat in a pattern, just like the motion of a swing repeating from its highest to lowest points.The cycle of both graphs repeats at equal time intervals, just like the swinging motion of a swing that takes the same amount of time to swing back and forth.The swinging motion of a swing is smooth and uninterrupted, just like the graphs of sine and cosine functions.

These similarities are because simple harmonic motion, which includes swinging, is closely related to sine and cosine waves.

Learn more about The Link between Simple Harmonic Motion and Waves here:

https://brainly.com/question/37843140

#SPJ11

Need help please asap.

Answers

quadrilateral
trapezoid
isosceles trapezoid
parallelogram
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