Answer:
4L
Explanation:
No of mole= concentrate × volume
Volume = n/C
V= 10/2.5 = 4L
How many moles are in 6.99 x 1020 formula units of magnesium bromide (MgBr2)? Round your answer to 2 decimal places and, if needed, enter scientific notation like this 6.02e23 (would mean 6.02 x 1023.)
Answer:
1.16x10^–3 mole
Explanation:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 formula units. This implies that 1 mole of MgBr2 also contains 6.02x10^23 formula units.
Now, if 1 mole of MgBr2 contains 6.02x10^23 formula units,
Then Xmol of MgBr2 will contain 6.99x10^20 formula units i.e
Xmol of MgBr2 = 6.99x10^20/6.02x10^23
Xmol of MgBr2 = 1.16x10^–3 mole
Which of these salts is most likely to be soluble? Potassium nitrate OR Iron carbonate OR Copper oxide
Final answer:
Potassium nitrate is the most likely to be soluble among the options given because all nitrates are known to be soluble in water, while Iron carbonate and Copper oxide are typically insoluble.
Explanation:
Among the given options of salts—Potassium nitrate, Iron carbonate, and Copper oxide—the one most likely to be soluble is Potassium nitrate. This is due to the general solubility rule that all nitrates are soluble in water. Salts containing the large, singly charged NO₃⁻ ion, such as Potassium nitrate, tend to form highly soluble compounds, while carbonates (like Iron carbonate) and oxides (like Copper oxide) are often less soluble or insoluble except in the presence of certain cations like potassium, sodium, and ammonium.
Iron carbonate and Copper oxide are generally insoluble in water. For instance, iron(II) carbonate is not soluble except when combined with cations like potassium, sodium, or ammonium. Similarly, Copper oxide's solubility is very low in water. On the contrary, even though Copper sulfate is not provided as an option, it is worth mentioning that many sulfates, unlike carbonates and oxides, are generally soluble, with few exceptions.
A small, jagged particle with a density of 1.2 g/cm3 deposits on the ground before a large, round particle with a density of 0.82 g/cm3.
Which most likely influences the rate of deposition of the jagged particle?
large size
low density
high density
irregular shape
Answer:
C
Explanation:
A small, jagged particle with a density of 1.2 g/cm³ deposits on the ground before a large, round particle with a density of 0.82 g/cm³. The one that is most likely influences the rate of deposition of the jagged particle is high density and the correct option is option 3.
What is Density?Density is the degree of how closely the mass of matter is compacted. The more compacted the mass is in relation to the amount of volume the matter occupies, the higher its density will be. Conversely, matter that has a low density, has a smaller ratio of mass per amount of volume the matter occupies.
To determine the density of a solid that has regular side lengths, it is first needed to calculate the volume of the solid using the equation volume = length x width x height.
The density of a material depends on the molecular packing.
Therefore, A small, jagged particle with a density of 1.2 g/cm³ deposits on the ground before a large, round particle with a density of 0.82 g/cm³. The one that is most likely influences the rate of deposition of the jagged particle is high density and the correct option is option 3.
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Which aqueous solution will theoretically have the lowest freezing point? A) 0.001 M NaCl B) 0.001 M C6H12O6 C) 0.001 M CaCl2 D) 0.001 M AlCl3
Answer:
D) 0.001 M AlCl3
Explanation:
The solution with the lowest freezing point would be 0.001 M AlCl3 because it produces the most particles when fully ionized in water, therefore lowering the freezing point the most.
Theoretically, the aqueous solution that will have the lowest freezing point is D) 0.001 M AlCl3. This is based on the principle of colligative properties, which states that the freezing point of a solution is lowered when solutes are added. The extent of this lowering depends on the number of solute particles present. In this case, AlCl3, when fully ionized in water, produces 4 particles (1 Al3+ and 3 Cl-), contributing to the greatest decrease in freezing point.
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As relative humidity goes up, what do you predict will happen to the wet bulb/dry bulb temperatures?
Answer:
the wet bulb will get warmer because their will be a smaller difference between the the dry/wet bulb temps.
Explanation:
At any given ambient temperature, less relative humidity results in a greater difference between the dry-bulb and wet-bulb temperatures; the wet-bulb is colder.
For your problem, this is opposite, therefore it will get warmer.
Most first aid "cold packs" are based on the dissociation of ammonium nitrate (NH4NO3) in water. When the cold pack is activated, the ammonium nitrate (NH4NO3) dissolves in water, producing ammonium (NH4+) and nitrate (NO3-) ions. The "cold pack" then feels cold to touch. What conclusion can be drawn about the bond energy of products and reactants?
A) More energy was absorbed in the formation of chemical bonds than released in the breaking of chemical bonds.
B) Less energy was absorbed in the breaking of chemical bonds than released in the formation of chemical bonds.
C) More energy was absorbed in the breaking of chemical bonds than released in the formation of chemical bonds.
D) Less energy was absorbed in the formation of chemical bonds than released in the breaking of chemical bonds.
Answer:C) More energy was absorbed in the breaking of chemical bonds than released in the formation of chemical bonds.
Explanation:
When the pressure of a gas doubt, does the volume:
A. Doubles
B.triples
C. Halves
D. Quarters
E. Remains constant
Answer:
it will halves
Explanation:
if the volume is doubled then the pressure is halves.
Determine the solution of the following system of equations: *
Captionless Image
No solution
(3, 1)
( 1 , -3 )
Infinite Solutions
Answer: N/A
Explanation: You have to write down the equation otherwise we are unable to help you.
this is 6th grade question 25 POINTS PLEASE HELP A waste company has been dumping untreated sewage into the river next to the house. They have recently been found guilty because of the effect the pollution has had on the plants and animals living there. What effect has the raw sewage had on the animals that live in the river?
A) Animals blend in better in the darker water.
B) More animals now live in the river than ever before.
C) Many animals have become sick or have been found dead.
D) Animals that have lived in the water now live on land.
Final answer:
Untreated sewage dumped into a river causes significant harm to aquatic life, leading to sickness and fatalities among animals, degradation of water quality, and the creation of dead zones. These pollutants also pose a risk to human health as they can travel up the food chain.
Explanation:
The effect of untreated sewage being dumped into a river on the animals living therein is typically devastating. The correct answer to the question, 'What effect has the raw sewage had on the animals that live in the river?' is C) Many animals have become sick or have been found dead.
Water pollution from untreated sewage includes harmful bacteria and chemicals that can cause disease and death in river ecosystems. Pollutants like nitrogen and phosphorus can lead to eutrophication, which depletes the oxygen in the water, creating dead zones where fish and other aquatic life cannot survive. Additionally, contaminated water can carry diseases and toxins up the food chain, posing health risks to animals and humans alike.
Industrial waste and agricultural runoff also contribute to the degradation of water quality, affecting not only the immediate area but also environments downstream. This contamination has a cascading effect on ecosystems, harming countless plants, animals, and humans who depend on these water sources.
Which organism is a tertiary consumer?
clownfish
brittle star
killer whale
octopus
Answer:
killer whale
Explanation:
Answer:
c
Explanation:
im taking the test right now
Find Number 6. After Titration, Calculate and Enter Molarity of Base
To calculate the molarity of your base, you will first need to write out the balanced equation for the reaction between your acid and base . You will then use the Molarity of Acid , Volume of Acid, and Volume of Base Used to determine the Molarity of the Base. Your sig figs should match with the sig figs used in the Molarity of the Acid.
I’ll give Brainliest
Answer:
where in the book is it
Explanation:
You want to create 14.0 g of copper to meld into a piece of jewelry. You
know that when copper (II) chloride reacts with aluminum, copper is a
product. How much aluminum would you need to start your reaction with
to get 14.0 g of copper? *
2Al + 3CuCl2 + 2AlCl3 + 3Cu
Answer:
3.4g of Al
Explanation:
you would need to start with 3.4 g of Al
Cloudy nights can be warmer than clear nights because clouds trap heat
Answer:
Cloudy nights can be warmer than clear nights because clouds trap heat absorbed by Earth during daylight hours.
Cloudy nights can be warmer than clear nights because clouds trap heat absorbed by Earth during daylight hours.
What is heat?In thermodynamics, heat is defined as the form of energy crossing the boundary of a thermodynamic system by virtue of a temperature difference across the boundary.[1] A thermodynamic system does not contain heat. Nevertheless, the term is also often used to refer to the thermal energy contained in a system as a component of its internal energy and that is reflected in the temperature of the system. For both uses of the term, heat is a form of energy.
Another example of informal usage is the term heat content, used despite the fact that physics defines heat as energy transfer. More accurately, it is thermal energy that is contained in the system or body, as it is stored in the microscopic degrees of freedom of the modes of vibration.
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Sodium Sulfide chemical formula
Answer:
Na2S
Explanation:Just took the test
The chemical formula for the compound formed between sodium and sulfide is Na2S. Sodium has a positive charge and sulfide has a negative charge, which balance when combined in the proportions indicated by the formula.
Explanation:The chemical formula for the ionic compound formed between the sodium cation, Na+, and the sulfide anion, S²-, is Na2S. This is derived from the fact that sodium (Na) has a positive charge and sulfide (S) has a negative charge.
To balance these charges and form a neutral compound, you need two sodium ions for every sulfide ion. Hence the '2' in Na2S.
This indicates there are two sodium ions in the compound.
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Sr(OH)2 will dissociate into what ions with what charge
Answer : [tex]Sn(OH)_2[/tex] will dissociate into strontium ion, [tex]Sr^{2+}[/tex] with a (+2) charge and hydroxide ion, [tex]OH^-[/tex] with a (-1) charge.
Explanation :
As we know that when strontium hydroxide, [tex]Sn(OH)_2[/tex] dissociates then it gives strontium ion, [tex]Sr^{2+}[/tex] and hydroxide ion, [tex]OH^-[/tex].
The dissociation reaction will be:
[tex]Sr(OH)_2\rightarrow Sr^{2+}+2OH^-[/tex]
[tex]Sn(OH)_2[/tex] will dissociate into strontium ion, [tex]Sr^{2+}[/tex] with a (+2) charge and hydroxide ion, [tex]OH^-[/tex] with a (-1) charge.
Strontium hydroxide, Sr(OH)2, dissociates into one Sr2+ ion and two OH- ions when it dissolves in water.
Explanation:When Sr(OH)2 (strontium hydroxide) dissociates in water, it separates into ions with specific charges. The chemical equation representing this dissociation is:
Sr(OH)₂ → Sr²⁺ (aq) + 2OH⁻(aq)
This means that one molecule of strontium hydroxide will produce one Sr²⁺ ion and two OH⁻ ions. The Sr²⁺ ion has a plus two charge and each of the OH⁻ ions has a negative one charge.
Given the reaction at equilibrium:N2(g) + 3H2(g) 2NH3(g) + 91.8kJWhat occurs when the concentration of H2(g) is increased?A)The rate of the forward reaction increases and the concentration of N2(g) decreases.B)The rate of the forward reaction decreases and the concentration of N2(g) increases.C)The rate of the forward reaction and the concentration of N2(g) both increase.D)The rate of the forward reaction and the concentration of N2(g) both decrease.
Answer:
A
Explanation:
N2(g) + 3H2(g) -> 2NH3(g)
According to Le Chatelier's principle, and since H2(g) is on the left side and a reactant, if it's concentration is increased, the equilibrium shifts to the right and the forward reaction is favoured, leading to the production of more NH3(g). The rate of the forward reaction increases.
As the concentration of H2(g) is increased, the concentration of the other reactant, N2(g) decreases as more of it is used up to react with the excess H2(g)
The forward reaction would increase to start reducing the concentration of N2.
Explanation:
In which compound have electrons been transferred to an oxygen atom
a NO2
b N2O
c Na2O
d CO2
Answer:
Na2O
Explanation:
This is because a bond between a metal and a non-metal has occured.
Final answer:
In Na₂O, two sodium atoms transfer one electron each to the oxygen atom, forming a neutral ionic compound with a ratio of two sodium ions to one oxide ion.
Explanation:
Among the options given, the compound in which electrons have been transferred to an oxygen atom is Na₂O. In Na₂O, two sodium (Na) atoms each donate one electron to the oxygen (O) atom. This transfer of electrons is what forms the ionic bond in Na₂O. Each sodium atom becomes positively charged (Na+), and the oxygen atom gains two electrons to become negatively charged (O₂-). This results in the formation of a neutral ionic compound with a ratio of two sodium ions to one oxide ion.
A solution has a pH of 11.8. What is the pOH?
Answer:
pOH is 2.2
Explanation:
The pH scale goes from 0 to 14. As such, the pH and the pOH add up to 14. Subtract your pH from 14 to get your answer.
14 - 11.8 = 2.2
One liter of 1 M NaOH will completely neutralize one liter of
a
1.0 M H2SO4
b
2.0 M H2SO4
c
1.5 M H2SO4
d
0.50 M H2SO4
Final answer:
One liter of 1 M NaOH can completely neutralize one liter of 0.50 M H2SO4 because 1 mole of NaOH is needed to neutralize 0.5 mole of H2SO4, according to the stoichiometric relationship in the balanced chemical equation. So the correct option is d.
Explanation:
To determine which molarity of H2SO4 will be completely neutralized by one liter of 1 M NaOH, we need to look at the stoichiometry of the reaction. Sulfuric acid is a diprotic acid, meaning it can donate two protons (H+). The balanced chemical equation for its reaction with sodium hydroxide (NaOH), which is a monoprotic base, is:
H2SO4(aq) + 2NaOH(aq) → Na2SO4(aq) + 2H2O(l)
From this equation, we can see that it takes two moles of NaOH to neutralize one mole of H2SO4. Therefore, one liter of 1 M NaOH contains one mole of NaOH, and it can completely neutralize 0.5 mol of H2SO4. If we have one liter of H2SO4, the molarity that would supply 0.5 mol would be 0.50 M, because 0.50 mol/L × 1 L = 0.5 mol. The correct answer is option d - 0.50 M H2SO4.
Match each type of asexual reproduction with its description.
Budding
A new organism grows from the body of the
parent
Fragmentation
The parent cell divides to produce a
genetically identical cell
Binary fission
The parent breaks into parts that may
regenerate into offspring
Answer:
Budding- A new organism growing from the body of the parent
Fragmentation- The parent breaks into parts that may regenerate into offspring
Binary Fission- The parent cell divides to produce a genetically identical cell
Answer: A new organism growing from the body of the parent
Fragmentation- The parent breaks into parts that may regenerate into offspring
Binary Fission- The parent cell divides to produce a genetically identical cell
Give the characteristic of a second order reaction having only one reactant. Group of answer choices The rate of the reaction is proportional to the natural logarithm of the concentration of the reactant. The rate of the reaction is not proportional to the concentration of the reactant. The rate of the reaction is proportional to the square of the concentration of the reactant. The rate of the reaction is proportional to the square root of the concentration of the reactant. The rate of the reaction is directly proportional to the concentration of the reactant.
Answer:
The rate of the reaction is proportional to the square of the concentration of the reactant.
Explanation:
Let us assume a hypothetical reaction in which the rate determining step is the elementary reaction;
2A------> A2
The rate of reaction will be given by:
Rate= k[A]^2
Hence for a second order reaction having only one reactant, the rate of reaction is proportional to the square of the concentration of the reactant. The proportionality constant k, is known as the rate constant of the reaction.
Glucose (C6H12O6)(C6H12O6) can be fermented to yield ethanol (CH3CH2OH)(CH3CH2OH) and carbon dioxide (CO2).
C6H12O6⟶2CH3CH2OH+2CO2
The molar mass of glucose is 180.15 g/mol,180.15 g/mol, the molar mass of ethanol is 46.08 g/mol,46.08 g/mol, and the molar mass of carbon dioxide is 44.01 g/mol.
a) What is the theoretical yield (in grams) of ethanol from the fermentation of 97.5 g of glucose?
b) If the reaction produced 23.4 g of ethanol, what was the percent yield?
Answer: a) 49.8 gram
b) 47.0 %
Explanation:
First we have to calculate the moles of glucose
[tex]\text{Moles of glucose}=\frac{\text{Mass of glucose}}{\text{Molar mass of glucose}}=\frac{97.5g}{180.15g/mole}=0.54moles[/tex]
The balanced chemical reaction will be,
[tex]C_6H_{12}O_6\rightarrow 2CH_3CH_2OH+2CO_2[/tex]
From the balanced reaction, we conclude that
As,1 mole of glucose produce = 2 moles of ethanol
So, 0.54 moles of glucose will produce = [tex]\frac{2}{1}\times 0.54=1.08[/tex] mole of ethanol
Now we have to calculate the mass of ethanol produced
[tex]\text{Mass of ethanol}=\text{Moles of ethanol}\times \text{Molar mass of ethanol}[/tex]
[tex]\text{Mass of ethanol}=(1.08mole)\times (46.08g/mole)=49.8g[/tex]
Now we have to calculate the percent yield of ethanol
[tex]\%\text{ yield of ethanol}=\frac{\text{Actual yield}}{\text{Theoretical yield }}\times 100=\frac{23.4g}{49.8g}\times 100=47.0\%[/tex]
Therefore, the percent yield is 47.0 %
Final answer:
The theoretical yield of ethanol from the fermentation of 97.5 g of glucose is 49.3 g. The percent yield is 47.4% if the actual yield of ethanol is 23.4 g.
Explanation:
To determine the theoretical yield of ethanol, we need to calculate the molar ratio between glucose and ethanol. According to the balanced equation, for every mole of glucose, two moles of ethanol are produced. Therefore, we can set up a proportion and solve for the theoretical yield:
(97.5 g glucose / 180.15 g/mol) x (2 mol ethanol / 1 mol glucose) x (46.08 g/mol) = 49.3 g ethanol
For the percent yield, we can divide the actual yield (23.4 g) by the theoretical yield (49.3 g) and multiply by 100:
(23.4 g / 49.3 g) x 100 = 47.4%
What volume is occupied by 21.0 g of methane (CH4) at 27 degrees Celsius and 1 atm?
Answer:
The volume is occupies by 21,0g of methane is 32, 3 L.
Explanation:
We use the formula PV=nRT. We convert the unit temperature Celsiud into Kelvin: 0°C=273 K---> 27°C= 27+273= 300K. We calculate the weight of 1 mol of CH4:
Weight 1 mol CH4= Weight C+ (Weight H)x4= 12 g+ 1g x4= 16 g
16 g---1 mol CH4
21g---x= (21g x 1 mol CH4)/16g= 1, 31 mol CH4
PV=nRT ----> V= (nRT)/P
V= (1, 31 mol x 0,082 l atm/K mol x 300 K)/ 1 atm
V= 32, 3875 L
The volume occupied by 21.0 g of methane (CH4) at 27 degree celsius and 1 atm is 32.3L
IDEAL GAS LAW:The volume occupied by a gas can be calculated by using the ideal gas law equation as follows:PV = nRT
Where;
P = pressure (atm)V = volume (L)n = number of moles (mol)R = gas law constant (0.0821 Latm/molK)According to this question;n = 21g ÷ 16g/mol = 1.3125molV = ?P = 1 atmT = 27°C + 273 = 300K1 × V = 1.3125 × 0.0821 × 300V = 32.32LTherefore, volume occupied by 21.0 g of methane (CH4) at 27 degree celsius and 1 atm is 32.3L.Learn more about ideal gas law at: https://brainly.com/question/4147359?referrer=searchResults
Lithium has two stable isotopes with masses of 6.01512 amu and 7.01600 amu. The average molar mass of Li is 6.941 amu. What is the percent abundance of each isotope? Show all calculations and report to the correct number of sig figs.
Answer : The percent abundance of Li isotope-1 and Li isotope-2 is, 6.94 % and 93.1 % respectively.
Explanation :
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
[tex]\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i[/tex] .....(1)
Let the fractional abundance of Li isotope-1 be 'x' and the fractional abundance of Li isotope-2 will be '100-x'
For Li isotope-1 :
Mass of Li isotope-1 = 6.01512 amu
Fractional abundance of Li isotope-1 = x
For Li isotope-2 :
Mass of Li isotope-2 = 7.01600 amu
Fractional abundance of Li isotope-2 = 100-x
Average atomic mass of Li = 6.941 amu
Putting values in equation 1, we get:
[tex]6.941=[(6.01512\times x)+(7.01600\times (100-x))][/tex]
By solving the term 'x', we get:
[tex]x=694.048[/tex]
Percent abundance of Li isotope-1 = [tex]\frac{694.048}{100}=6.94\%[/tex]
Percent abundance of Li isotope-2 = 100 - x = 100-6.94 = 93.1 %
The relative abundance of the isotopes are 7.5% and 92.5%.
The relative atomic mass of an atom is the sum of the products of the relative atomic masses of its isotopes and their respective percentage abundance. We have been told in the question that the relative atomic mass of Li is 6.941 amu. Let the percentage abundance be x and 1-x
6.941 = 6.01512x + 7.01600(1 - x)
6.941 = 6.01512x + 7.01600 - 7.01600x
6.941 - 7.01600 = -1.00088x
-0.075 = -1.00088x
x = -0.075/-1.00088
x = 0.075
Hence, the other isotope is 1 - 0.075 = 0.925
Therefore, the relative abundance of the isotopes is 7.5% and 92.5%
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Organisms can reproduce asexually or sexually. All BUT ONE of the steps below is involved in sexual reproduction. Which step
describes asexual rather than sexual reproduction?
The sperm fertilizes the egg to produce a zygote.
Egg and sperm receive chromosomes from each parent.
In some organisms, a piece of the parent may bud off to produce offspring.
The zygote undergoes cell division and cell differentiation to become a
new and different organism from the parents.
The step which best describes asexual rather than sexual reproduction is that "in some organisms, a piece of the parent may bud off to produce offspring." Thus, the correct option for this question is C.
What is Asexual reproduction?Asexual reproduction may be defined as a mode of reproduction in which a new offspring is significantly produced or constructed by a single parent itself. This mode of reproduction does not involve the fusion of gametes or a change in the number of chromosomes.
The new individuals produced through asexual reproduction are genetically and physically identical to each other along with their parents, i.e., they are the clones of their parents. This type of reproduction is mediated via mitosis.
Therefore, the correct option for this question is C.
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There are three groups that contain carbon but are not organic compounds:
•carbon chlorides
•carbon oxides
•carbon iodides
•carbides
•carbonates
Answer:
Carbonates, Carbides, Carbon oxides
Explanation: Its the answer I promise!!
5. A gas occupies 2000. L at 100.0 K and exerts a pressure of 100.0 kPa. What volume will the gas occupy if the temperature is increased to 400. K and the pressure is increased to 200. kPa?
Answer:
The gas will occupy a volume of 4000L
Explanation:
V1 = 2000L
T1 = 100K
P1 = 100kPa = 100*10³Pa
T2 = 400k
P2 = 200kPa = 200*10³kPa
V2 = ?
To solve this question, we need to use combined gas equation
[(P₁ * V₁) / T₁] = [(P₂ * V₂) / T₂]
V₂ = (P₁ * V₁ * T₂) / (P₂ * T₁)
V₂ = (100*10³ * 2000 * 400) / (200*10³ * 100)
V₂ = 8.0*10¹⁰ / 2.0*10⁷
V₂ = 4000L
The new volume of the gas is 4000L
Answer:
The volume that the gas will occupy when the temperature is increased to 400.0 K and the pressure is increased to 200. kPa is 4000. L
Explanation:
Here we are required to utilize the combined gas equation as follows;
[tex]\frac{P_{1}\times V_{1}}{T_{1}} = \frac{P_{2}\times V_{2}}{T_{2}}[/tex]
Where:
P₁ = Initial pressure of the gas = 100.0 kPa
V₁ = Initial volume of the gas = 2000. L
T₁ = Initial temperature of the gas = 100.0 K
P₂ = Final pressure of the gas = 200.0 kPa
V₂ = Final volume of the gas = Required
T₂ = Final temperature of the gas = 400.0 K
Making V₂ the formula subject of the combined gas equation, we have;
[tex]V_{2}}{} = \frac{P_{1}\times V_{1}\times T_{2} }{T_{1}\times P_{2}}[/tex]
Therefore, by plugging the values, we have;
[tex]V_{2}}{} = \frac{100.0\times 2000\times 400.0 }{100.0 \times 200.0 } = 4000. \, L[/tex]
The volume that the gas will occupy when the temperature is increased to 400.0 K and the pressure is increased to 200. kPa = 4000. L.
The pressure of 9.0 L of an ideal gas in a flexible container is decreased to one-eighth of its original pressure, and its absolute temperature is decreased to one-ninth of the original. What is the final volume of the gas
Answer:
8L will be the new volume
Explanation:
Let's use the Ideal Gases Law to determine the answer of this question:
Pressure . volume = number of moles . R . T
P . V = n . R . T
We can propose the two situation for the gas:
P₁ . V₁ = n₁ . R . T₁
P₂ . V₂ = n₁ . R . T₂
Notice that R is a constant and n₁ (moles of gas), is not modified with the changes, so we can cancel them.
For the second situation: P₂ = P₁/8 and T₂ = T₁/9
(P₁ . 9L) / T₁ = (P₁/8 . V₂) / T₁/9
(P₁ . 9L) / T₁ . T₁/9 = (P₁/8 . V₂)
P₁ . 1L = P₁/8 . V₂
P₁ . 1L . 8/P₁ = V₂ → 8L
You can also see it, if you put numbers, for example
1 mol of the gas at 1 atm, let's find out the temperature:
1 atm . 9L = 1 mol . 0.082 . T
9/ 0.082 = 110 K
Second situation: 1/8 atm . V = 1 mol . 0.082 . 110/9 K
V = (1 mol . 0.082 . 110/9 K) . 8 atm → 8.02 L ≅ 8L
WILL MARK BRAINLIEST and 30 points The table lists the number of protons, electrons, and neutrons in a certain radioactive nuclide.
Electrons 11
Protons 11
Neutrons 13
Which is the symbol of this radioactive nuclide?
Superscript 24 subscript 11 upper N a.
Superscript 22 subscript 11 upper N a.
Superscript 13 subscript 11 upper Al.
Superscript 24 subscript 13 upper A l.
Answer:
It is given that number of electrons is 11.
It is known that when an atom is neutral then the number of protons equals number of electrons. Also, atomic number means number of protons an atom holds.
Whereas mass number equals number of protons + number of neutrons. Thus, mass number of given atom is 11 + 13 = 24.
The symbol for this element will be as follows 24/11x . This atom sodium has atomic number 11 and mass number 24.
Therefore, symbol of this radioactive nuclide is as follows . A)Superscript 24 subscript 11 upper N a.
Answer:
Answer Is A
Explanation:
24/11 NA: This answer was correct
CH3 + HCl <=> CH3Cl + H2O
Kp = 4.7 x 10^3 at 400K.
CH3Cl and HCl combine in 10.00L at 400K. The pressure of CH3OH is 0.250 atm and the pressure of HCl is 0.600 atm (I might have wrote this down wrong).
Does the pressure increase, decrease, or stay the same if equilibrium approaches?
Using Kp, calculate the final partial pressure of HCl at equilibrium.
A student claims the final partial pressure is small but not zero. Justify or argue against this claim and explain why.
Answer:
The pressure of CH3OH and HCl will decrease.
The final partial pressure of HCl is 0.350038 atm
Explanation:
Step 1: Data given
Kp = 4.7 x 10^3 at 400K
Pressure of CH3OH = 0.250 atm
Pressure of HCl = 0.600 atm
Volume = 10.00 L
Step 2: The balanced equation
CH3OH(g) + HCl(g) <=> CH3Cl(g) + H2O(g)
Step 3: The initial pressure
p(CH3OH) = 0.250atm
p(HCl) = 0.600 atm
p(CH3Cl)= 0 atm
p(H2O) = 0 atm
Step 3: Calculate the pressure at the equilibrium
p(CH3OH) = 0.250 - X atm
p(HCl) = 0.600 - X atm
p(CH3Cl)= X atm
p(H2O) = X atm
Step 4: Calculate Kp
Kp = (pHO * pCH3Cl) / (pCH3* pHCl)
4.7 * 10³ = X² /(0.250-X)(0.600-X)
X = 0.249962
p(CH3OH) = 0.250 - 0.249962 = 0.000038 atm
p(HCl) = 0.600 - 0.249962 = 0.350038 atm
p(CH3Cl)= 0.249962 atm
p(H2O) = 0.249962 atm
Kp = (0.249962 * 0.249962) / (0.000038 * 0.350038)
Kp = 4.7 *10³
The pressure of CH3OH and HCl will decrease.
The final partial pressure of HCl is 0.350038 atm