If this atom has a balanced charged, how many protons would you expect to find in this atom?
A) 4
B) 0
C) 6
D) 2
Answers
There are 6 - electrons so there would be 6 + protons.
Answer is C.
If this atom has a balanced charged, 6 protons will be expected to be present in the atom.
WHAT IS A BALANCED CHARGE?A balanced charge in an atom refers to an even or same amount of the positive and negative subatomic particles in the atom.
This further means that the number of protons (+) and electrons (-) in the atom will be equal for there to be a balanced charge.
Based on the image provided in this question, there are 6 electrons (-) in the atom, hence, 6 protons must be present to have a balanced charge in the atom.
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Related Questions
Match the following vocabulary words with their definitions:
Question 1 options:
rate of change in velocity, which is the change in velocity divided by the change in time
the rate at which an object changes position when traveling in a certain direction
force of attraction between all masses in the universe
an object´s resistance to a change in motion
force of resistance acting between objects in contact and tending to dampen their motion
the rate at which an object changes position
1.
acceleration
2.
speed
3.
friction
4.
gravity
5.
inertia
6.
velocity
Save
Answers
Correct matching:
1 acceleration --> rate of change in velocity, which is the change in velocity divided by the change in time
2. speed --> the rate at which an object changes position when traveling in a certain direction
4. gravity --> force of attraction between all masses in the universe
5. Inertia --> an object´s resistance to a change in motion
3. friction --> force of resistance acting between objects in contact and tending to dampen their motion
6. velocity --> the rate at which an object changes position
Astronauts in orbit are not truly weightless. Please select the best answer from the choices provided T F
Answers
Answer:
true
Explanation:
true
if a cannon is fired from the front of a boat, the boat will drift backward. which on of Newton's laws best describes this motion?
Newton's second law of motion: force is equal to mass time acceleration
Newton's third law of motion: for every action, there is a equal and opposite reaction
Newton's first law of motion: an object in motion stays in motion unless acted on by another force
Answers
The cannon jumps back which pushes the boat backwards.
Lana does her homework as soon as she can after class, but she still doesn't undertand everything she suppose to learn. what could Lana do to get more out of her hhomework
Answers
Answer:
D. Ask her instructor questions about it the next day
Explanation:
We are given that Lana doesn't understand everything she's supposed to learn from the homework.
Let's check the options:
1- start working on it eve earlier
We know that she works on the homework as soon as she can. Working on it even earlier will not help her understand the difficult parts
2- put it off until she's ready to work on it
This is not the best option as it wont help her understand difficult parts. On the contrary, she might lose the time she has to practice the parts she understands and gain as much knowledge as possible
3- Only work on it directly before going to class.
this is the same as option 2. She might not even be able to finish it before the class
4- Ask her instructor questions about it the next day
This is the best solution as it will help her recap what she needs to learn and understand any difficult concepts as soon as possible which will help optimize her benefits
Hope this helps :)
Explanation:
Since Lana is unable to understand everything while doing her homework it means that she has doubts about some of the topics given in her homework.
Therefore, in that case she should take the help of her teacher or instructor the very next day because her doubts are new and she should consult about then as soon as possible.
Thus, by doing so she can clear her doubts on time.
Using a simple machine, a student is able to lift a 500N weight by applying only 100N.
What is the mechanical advantage of the simple machine?
A) 0.2
B) 1
C) 5
D) 50000
Answers
[tex] a \ student \ is \ able \ to \ lift \ a \ 500(n) \\ weight \ by \ applying \ only \ 100(n) \\ \\ so, \ this \ info \ here, \ we \ simply \ divide \ by \\ how \ much \ this \ kid \ lifted, \ by \ the \ weight \ he/she \\ \ is \ applying. \\ \\ \left[\begin{array}{ccc}\boxed{\boxed{500(n)/100(n)}}\end{array}\right] \\ \\ and \ from \ this,\ your \ answer \ would \ \\ conclude \ to \ be \ (5) \\ \\ \boxed{5} \ would \ be \ your \ answer![/tex]
Hope this helps you!
You hop on the carousel horse. The attendant flips the switch and you move up and down, around and around. When the ride ends, the attendant again flips the switch. The up and down motion stops, as you continue to move in a circular motion, gradually slowing to a stop. Why? A) All the mechanical energy of the carousel is lost. B) All of the kinetic energy is converted to potential energy. C) The external energy source overcomes the internal energy of the carousel. D) Mechanical systems need an external energy source to maintain their
Answers
A) All the mechanical energy of the carousel is lost.
In fact, all the mechanical energy of the carousel is lost because of the friction between the carousel and the ground. The carousel loses its energy little by little because of the friction, and it gradually slows down until it stops: all the initial energy of the carousel has been dissipated into thermal energy due to the friction between the carousel surface and the ground.
Answer:
D) Mechanical systems need an external energy source to maintain their
Explanation:
Mechanical systems need an external energy source to maintain their motion.
In this case, electrical energy is transformed to mechanical energy. Without electrical energy, the carousel slows due to friction and eventually stops.
How many liters of air are in a room that measures 10.0 ft à 11.0 ft and has an 8.00 ft ceiling? 1 in. = 2.54 cm (exactly); 331l=10cm?
Answers
Final answer:
To find the liters of air in a room measured at 10.0 ft by 11.0 ft with an 8.00 ft ceiling, the volume in cubic feet (880.0) is converted to liters, resulting in approximately 24,918.96 liters of air.
Explanation:
The question asks how many liters of air are in a room given its dimensions in feet, using conversion factors to relate to liters. To determine the volume in liters of a room measuring 10.0 ft × 11.0 ft with an 8.00 ft ceiling, we first calculate the volume in cubic feet and then convert this volume to liters.
First, calculate the volume in cubic feet: 10.0 ft × 11.0 ft × 8.00 ft = 880.0 cubic feet.
Next, convert cubic feet to liters using the conversion factor, where 1 cubic foot equals approximately 28.317 liters. Thus, 880.0 cubic feet × 28.317 liters/cubic foot = 24,918.96 liters of air in the room.
A dry cleaner throws a 20 kg bag of laundry onto a stationary 8.3 kg cart. the cart and laundry bag begin moving at 2.6 m/s to the right. find the velocity of the laundry bag before the collision. answer in units of m/s. answer
Answers
- Let's start from the end: at this point, both cart and laundry bag are moving together, with a total mass of (m1+m2) and velocity 2.6 m/s. Therefore, the total momentum is
[tex]p_f = (m_1+m_2) v_f =(20 kg+8.3 kg)(2.6 m/s)=73.6 kg \cdot m/s[/tex]
- The momentum must be conserved, so the initial momentum must be equal to this value:
[tex]p_i = p_f = 73.6 kg \cdot m/s[/tex]
- At the beginning, the cart is stationary, so its momentum is zero. There is only one momentum, the one of the bag, which has a mass of 20 kg and unknwon velocity vi:
[tex]p_i = m_1 v_i[/tex]
- So, using the conservation of momentum we find
[tex]m_1 v_i = 73.6 kg \cdot m/s[/tex]
and from this, the initial velocity of the laundry bag:
[tex]v_i = \frac{p_f}{m_1}= \frac{73.6 kg \cdot m/s}{20 kg}=3.7 m/s [/tex]
Final answer:
Using the conservation of momentum, the velocity of the 20 kg laundry bag before the collision is calculated to be approximately 3.689 m/s to the right.
Explanation:
To find the velocity of the laundry bag before the collision, we can use the conservation of momentum, which states that the total momentum before an event is equal to the total momentum after the event, provided no external forces act on the system. Since the cart is initially stationary, its initial momentum is 0. After the bag is thrown onto the cart, both move together with a certain velocity, so the final momentum is the combined mass times the final velocity. We can set up the equation as follows:
Momentum before collision (p₁) = Momentum after collision (p₂)
Since the cart is stationary before the collision, this simplifies to:
Velocity of the bag before collision (v) × Mass of the bag [tex](m_{bag)[/tex] = (Mass of the bag [tex](m_{bag)[/tex] + Mass of the cart [tex](m_{cart)[/tex]) × Final velocity [tex](v_f)[/tex]
Inserting the given values, we get:
v × 20 kg = (20 kg + 8.3 kg) × 2.6 m/s
Now we solve for the velocity (v):
v = (28.3 kg × 2.6 m/s) / 20 kg
v = 3.689 m/s
Therefore, the velocity of the laundry bag before the collision was approximately 3.689 m/s to the right.
) with the box still on the truck, the truck attains its maximum velocity. as the truck comes to a stop at the next stop light, what is the magnitude of the maximum deceleration the truck can have without the box sliding?
Answers
If the trucks declaration is we have the following force acting on the box:
[tex]F=ma[/tex]
This force has to be smaller than static friction force:
[tex]F_f=mg\mu[/tex]
Where [tex]\mu[/tex] is static friction coefficient.
Now we can find an answer:
[tex]ma\leq mg\mu\\ a\leq g\mu[/tex]
Final answer:
The magnitude of the maximum deceleration to keep the box from sliding is determined by the coefficient of static friction and gravity; it can be calculated as 2.352 m/s² for a coefficient of 0.24.
Explanation:
The question deals with the concept of friction and deceleration in the context of a box placed on a truck that is coming to a halt. To prevent the box from sliding, the maximum deceleration is dictated by the coefficient of static friction.
This coefficient, multiplied by the acceleration due to gravity, gives us the maximum deceleration the truck can have without the box beginning to slide.
To calculate this, we can use the formula maximum deceleration (a_max) = coefficient of static friction (μ_s) × acceleration due to gravity (g), where μ_s is 0.24 and g is approximately 9.8 m/s².
Thus, a_max = 0.24 × 9.8 m/s², which results in a maximum deceleration of 2.352 m/s² without causing the box to slide.
One student did an experiment with two unknown minerals, Mineral 1 and Mineral 2. The hardness scale shown below was used for the experiment.
Mineral Talc Gypsum Calcite Fluorite Apatite Orthoclase
Hardness 1 2 3 4 5 6
Any mineral on the hardness scale would scratch minerals below it on the scale. The student tested Mineral 1 and observed that it could scratch only two other minerals on the hardness scale. It was observed that Mineral 2 could scratch only four other minerals on the hardness scale. Which of these is a correct conclusion the student can make about Mineral 1 and Mineral 2?
A) Mineral 1 can be used to scratch talc and Mineral 2 can be used to scratch orthoclase.
B) Mineral 1 can be used to scratch orthoclase and Mineral 2 can be used to scratch talc.
C) Mineral 1 can be used to scratch calcite and Mineral 2 can be used to scratch gypsum.
D) Mineral 1 can be used to scratch gypsum and Mineral 2 can be used to scratch calcite.
Answers
1=Talc 2=Gypsum 3=Calcite 4=Fluorite 5=Apatite 6=Orthoclase
Mineral #1 can only scratch two other minerals therefore it must have a hardness level of 2+1=3 which is Calcite. (scratches talc, gypsum)
Mineral #2 can scratch four other minerals therefore it must have a hardness level of 4+1=5 which is Apatite. (scratches all but Apatite, Orthoclase)
Looking through the possible conclusions.. It looks like answer is D.
Mineral 1 has a hardness equivalent to calcite, and Mineral 2 has a hardness equivalent to apatite. Therefore, Mineral 1 can scratch calcite and Mineral 2 can scratch gypsum.
Explanation:The hardness scale in the question list minerals according to their hardness. Mineral 1 could only scratch two other minerals, which means that it should rank third on the scale, since it can only scratch minerals 1 and 2. The hardness of Mineral 1 is, therefore, equivalent to that of calcite. Similarly, Mineral 2 could scratch four other minerals, and thus should rank fifth on the scale, after minerals 1, 2, 3, and 4. This means that the hardness of Mineral 2 is equivalent to that of apatite. Therefore, the correct answer is option C) Mineral 1 can be used to scratch calcite and Mineral 2 can be used to scratch gypsum.
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As the wave interacts with a wall, which kind of wave interaction is shown?
absorption
diffraction
refraction
reflection
Answers
reflection thats the answer bois
(this question is just for fun)(at least try to answer it) If I was driving 272mph in a koenigsegg one:1 And I was traveling 50 miles across the country how long will it take me to arrive without no obstacles
Answers
Speed = distance/time
Time = distance/speed = 50miles/272miles per hour = 0.1838 hours
Time = 0.1838 hours = 11.028 minutes = 661.68 seconds
USE THE AGERA RS, also it would run out of gas:) Im a car enthusiast
Compare rhyolite to basalt (answer in one word only):
a. which has a lower density?
b. which has a lighter color?
c. which has a more mafic composition?
d. which has a greater percentage of biotite in it?
e. which contains quartz? 13. name a felsic, intrusive rock. 14. name a light-colored, plutonic igneous rock.
Answers
The density of Basalt is higher than that of Rhyolite. Rhyolite has a density that ranges between 2.4-2.6 g/cm^3, while that of Basalt ranges from 2.9-3.1 g/cm^3.
b) Rhyolite is a Grey, white, light black rock, while Basalt is Black, Brown, Light to Dark Grey. Rhyolite appears to be banded while the apperance of Basalt is Dull and soft.
c) Basalt is more mafic; most mafic minerals are dark in color, and common rock-forming mafic minerals include olivine, Pyroxene, amphibole, and biotite. Common mafic rocks include basalt, diabase and gabbro. Mafic rocks often also contain calcium-rich varieties of plagioclase feldspar.
d) Rhyolite has a higher percentage of biotite. Rholite contains a higher percentange of sodium and potassium oxides which can reach up to 5%. Quartz, feldspar and biotite are the most common minerals found in rhyolite. In some cases , thick rhyolitic lavas will cool as glassy obsidian flows.
e) Rhyolite contains quartz. The chemical composition of rhyolite is similar to that of granite. The phenocrysts or rhyolite may include quartz, alkali feldspar, oligoclase feldspar, biotite, amphibole, or pyroxene.
13. I think it is plutonic rocks. Intrusive rocks that were formed deep in the earth's crust are called plutonic rocks and are generally coarse gained (minerals grains greater than 1 millimeter in diameter), large, and often associated with mountain building. Mafic felsic, and intermediate intrusive rocks.
14. Anorthosite. It is the light-colored plutonic rock composed mostly of feldspar, labradorite, with very little pyroxene. The felsic plutonic rocks usually have quartz, large proportions of potassium feldspar, and lesser amounts of plagioclase and mafic minerals. On the other hand, intermediate and mafic rocks have increasingly larger proportions of dark iron-rich minerals.
Rhyolite has a lower density
Average density of Rhyolite is 2.5 g/cm³ whereas the average density of basalt is 3 g/cm³ So we can say that Rhyolite is less denser.
Answer B:
Rhoylite is more lighter
Rhyolite is either pink or grey whereas basalt is usually grey or black so we can say that Rhyolite has lighter color
Answer C:Basalt is more melfic
Rhyolite is usually considered as felsic, while basalt is mafic. Generally felsic rocks make the bulk of the continental plates, while mafic basalt forms the seafloor.
Answer D:Basalt has more amount of biotite
Basalt has 5% biotite in it whereas Thyloite has very rare amount of biotite in it so we can say that greater amount of biotite is present in Basalt
Answer E:Quartz in Rhyolite may be present in amounts of 25% to 30%. whereas basalt has 20% - 60% quartz amount in it.
Answer 13:Granodiorite is an example of felsic intrusive rock.
Answer 14:Name of a very hard plutonic, igneous rock is Granite.
Term Definition
Match the correct term to the right definition
Elliptical galaxy A) Forms a perfect sphere or an ellipse and is flattened to some degree
Irregular galaxy B) Has a large flattened core
Lens galaxy C) Does not have a distinct regular shape
Spiral galaxy D) Has a central core from which curved arms spiral outward
Answers
Answer,
Elliptical Galaxy/ Forms a perfect sphere or an ellipse and is flattened to some degree
Irregular galaxy/Does not have a distinct regular shape
Lens galaxy/ Has a large flattened core
Spiral galaxy/ Has a central core from which curved arms spiral outward
I'm %500 sure this is correct :-)
When the IMA is compared to AMA in the real world, _____.
(A)the value of the IMA is always larger than the AMA
(B)the value of the AMA is always larger than the IMA
(C)the value of the AMA is larger than the IMA when there is no resistance
(D)the value of the IMA is larger than the AMA when there is no resistance
Answers
I believe the answer is A.) the value of the IMA is always larger than the AMA
(Not 100% on this, not my strongest topic, so I would double check)
Apply Newton's three laws of motion to everyday situations.
Answers
We'll start with the first law, the law of inertia, which states:
"an object in motion will stay in motion moving at the same speed in the same direction unless acted on by an outside force".
Let's imagine you're playing soccer with your friends. You kick the ball at them really hard, and they're the goalie. It goes in the same direction in a straight line, and then they catch it - the unbalanced force. There's a change in motion there, and that change in motion depends on the inertia of an object- it's tendency to resist change in motion. Inertia even applies to planets. Wonder why out Earth's orbit is an ellipse? By natural standards of physics, the Earth goes straight when it's not pulled into orbit when here it is. It still has that tendency to go straight, but the Sun pulls it towards itself, creating a motion in which the Earth is trying to go straight, but the Sun's more powerful.
The second law is pretty much summarized by the famous equation f = ma. The law, summed up, states,
"The net force of an object is equal to the mass of the object times its acceleration."
If you tried to give a push to a small box with efficient wheels, it'd go pretty far. This is because it has not a lot of mass, and the force required isn't a lot. However, if we had a large box on the ground, the force required to move it would be larger, as it's more massive and doesn't have any acceleration. Imagine a shopping cart filled to the ceiling with cereal. It would require a lot of force, wouldn't it? Be sure to think about that.
Last one. Newton's third law is perhaps the most famous. It states,
"For every action, there is an equal and opposite reaction".
This is probably the hardest one to understand. Let's try an example. Have you ever accidentally not tightened your balloon, and it started to fly up? That's an application of Newton's third law. The air comes out from the bottom, and the balloon flies up - that's an opposite reaction; up and down. It's the same thing with a rocket. The same force to propel it up is exerted on the ground - an equal reaction.
Hope this helps! Be sure to let me know if you have any questions :)
what is a gravitational field and how its strength be measured
Answers
[tex]F= \frac{GM}{r^2} m[/tex]
where [tex]G=6.67 \cdot 10^{-11} m^3 Kg^{-1} s^{-2}[/tex] is the gravitational constant, M is the mass of the source of the field (e.g. the mass of a planet), and r is the distance between the object and the source of the field. The force is always attractive.
A possible way to measure the intensity of a gravitational field is by measuring the acceleration a of the object immersed in this field. In fact, for Newton's second law we have:
[tex]F=ma[/tex]
but since
[tex]F= \frac{GM}{r^2} m[/tex]
we can write
[tex]a = \frac{GM}{r^2}[/tex]
Therefore, by measuring the acceleration of the object, we also measure the intensity of the field.
Select the volume units that are greater than one liter.
a.) kiloliter
b.) milliliter
c.) megaliter
d.) centiliter
e.) deciliter
f.) nanoliter
Answers
c.) megaliter. 1 megaliter = 1,000,000 liters
hope this helps
Answer: The correct answers are option (a)and(c).
Explanation:
1) In ,1 kilo Liter = 1,000 Liter
1 liter = 0.001 kilo Liter
2) In ,1 Mega Liter = 1,000,000
1 Liter = [tex]10^{-6}[/tex] Mega Liter
Where as milliliter, centiliter, deciliter and nano liters are smaller units that 1 liter
1 Liter = 1000 milliliter
1 Liter = 100 centiliter
1 Liter = 10 deciliter
1 Liter = [tex]10^9[/tex] nano liter
Hence, the correct answers are option (a)and(c).
what information does a free-body diagram show?
Answers
Answer:
All of the force vector acting on an object
Explanation:
That's what a free-body diagram does, and ayepecks
An oil storage tank ruptures at time t = 0 and oil leaks from the tank at a rate of r(t) = 105e−0.04t liters per minute. how much oil leaks out during the first hour? (round your answer to the nearest liter.)
Answers
65 liters of oil leaks out during the first hour.
What is Oil leaks?When the oil filter gradually becomes looser or the oil gasket is improperly tightened, car or engine oil leaks happen.
These are also known as oil filter leaks, and generally speaking, the filter gasket should be tightened in accordance with the manufacturer's instructions.
Sometimes, a gasket and bolts are used to secure an external oil pump to the engine block. These parts are prone to wear and leakage. Lack of oil in the oil pump can result in severe damage, including early wear of the pump and oil starvation of the engine.
Therefore, 65 liters of oil leaks out during the first hour.
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A bird is flying with a speed of 18.0 m/s over water when it accidentally drops a 2.00 kg fish. If the altitude of the bird is 5.40 m and friction is disregarded, what is the mechanical energy of the system, and what is the speed of the fish when it hits the water?
Answers
(here I assume that "system" refers to the fish, because we don't know the mass of the bird).
The mechanical energy of the fish is conserved during the entire free fall, because there are no friction acting on it, therefore we can calculate it at the beginning of its free fall, when it is dropped by the bird. At this instant, the velocity of the fish is equal to the speed of the bird [tex](v_i=18 m/s)[/tex], and the distance from the ground is h=5.40 m. The mechanical energy is the sum of its kinetic energy and its potential energy:
[tex]E=K+U= \frac{1}{2}mv_i^2+mgh=[/tex]
[tex]= \frac{1}{2}(2 kg)(18 m/s)^2 +(2kg)(9.81 m/s^2)(5.40m)=430 J[/tex]
2) When the fish hits the water, its potential energy has become zero, because the height from the water is now zero: h=0. This means that the mechanical energy E (which is conserved) is now only kinetic energy. Therefore we can write:
[tex]E=K_f = \frac{1}{2}mv_f^2 [/tex]
And we can find the final speed:
[tex]v_f = \sqrt{ \frac{2E}{m} }= \sqrt{\frac{2\cdot 430 J}{2 kg}} = 20.7 m/s[/tex]
(a) The mechanical energy of the system is 429.84 J.
(b) The speed of the fish when it hits the water is 20.73 m/s.
Given data:
The speed of flying bird is, v = 18.0 m/s.
The mass of fish is, m = 2.00 kg.
The altitude of bird is, h = 5.40 m.
(a)
Since the fish is carried by the bird initially. So, considering them as a part of single system. The mechanical energy (ME) of system is given as,
[tex]\rm ME = \rm kinetic\;\rm energy + \rm potential \;\rm energy\\ME = \dfrac{1}{2}mv^{2} + mgh\\\\ME = \dfrac{1}{2} \times 2.00 \times 18.0^{2} + (2.00 \times 9.8 \times 54.0)\\\\ME= 429.84 \;\rm J[/tex]
Thus, the mechanical energy of the system is 429.84 J.
(b)
When the fish is dropped to water at ground, then entire mechanical energy is converted into the kinetic energy (or potential energy becomes zero). So,
mechanical energy = kinetic energy
[tex]ME = \dfrac{1}{2}mv^{2}[/tex]
Here, v is the speed of fish, with which it hits the water.
Solving as,
[tex]429.84 = \dfrac{1}{2} \times 2.00\times v^{2}\\v=\sqrt{429.84} \\v = 20.73 \;\rm m/s[/tex]
Thus, the speed of the fish when it hits the water is 20.73 m/s.
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19. Water that flows downhill along Earth's surface is called A. beach hydraulics. B. cycles. C. runoff. D. rain.
Answers
A shot hitting the birdie high and deep to the backcourt is called what
Answers
Final answer:
In badminton, a shot that sends the birdie high and deep to the backcourt is called a clear. It's a defensive move to create more playing space and opportunities.
Explanation:
A shot in badminton that is hit high and deep into the opponent’s backcourt is known as a clear. This type of shot is a defensive move, intended to give the player hitting the clear more time to return to a ready position and to push the opponent to the rear of their court, potentially creating opportunities for future aggressive plays. The clear can be performed as either a forehand or backhand stroke depending on the player's position and the shuttlecock's trajectory.
Two mechanical waves intersect and produce the straight line seen here. What is the result of this intersection called?
A) summative interference
B) destructive interference
C) subtractive interference
D) constructive interference
Answers
Answer: The correct option is B.
Explanation:
In the given problem, two mechanical waves intersect and produce the straight line seen here. It means that the new wave having zero amplitude is formed.
Destructive interference is the interference of the wave in which the new wave will form with lower amplitude.
Constructive interference is the interference of the wave in which the new wave will form with lower amplitude.
Therefore, the correct answer is B.
The weight of an ice sheet can cause continental lithosphere to sink into the underlying asthenosphere due to ____.
Answers
Answer: Isostatic rebound
The weight of an ice sheet imposed on lithosphere in the continental block will cause the continent to sink in the asthenosphere due to isostatic rebound. The thickness of the ice sheet change with time as the sea level rise and the sinking of the lithosphere will continue until isostatic equilibrium is reached.
Calculate the water pressure in the pipes at the bottom of a high-rise building that is fed by reservoir 60 m above the roof top. Please help and explain
Answers
[tex]p=\rho g h[/tex]
In our problem, the fluid is water, so its density is [tex]\rho = 1000 Kg/m^3[/tex]. The height of the column of water is h=60 m, and [tex]g=9.81 m/s^2[/tex], therefore
[tex]p=(1000 Kg/m^3)(9.81 m/s^2)(60 m)=5.89 \cdot 10^5 Pa[/tex]
Match up the following set of words with their definitions:
Question 2 options:
mass
magnitude
weight
net force
vector
force
1.
a measure of the force of gravity on an object, expressed as mass of the object times acceleration due to gravity
2.
the amount of matter an object is made up of measured in grams
3.
a push or pull
4.
a numerical quantity, expressed by standard unit/s of measurement
5.
a number (rate) with a direction; a quantity that has both magnitude (measurable amount) and direction
6.
refers to the application of more than one force on an object and, therefore, the combined effect (sum of forces)
Answers
The match of the following set of words with their definitions is given as follows,
Mass ⇒ 2, Magnitude ⇒ 4, Weight ⇒ 1, Net force ⇒ 6
Vector ⇒5, Force ⇒ 3
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
Mass ⇒ the amount of matter an object is made up of measured in grams.
Magnitude ⇒ a numerical quantity, expressed by standard unit/s of measurement.
Weight ⇒ a measure of the force of gravity on an object expressed as the mass of the object times acceleration due to gravity.
Net force ⇒ refers to the application of more than one force on an object and, therefore, the combined effect (sum of forces).
Vector ⇒ a number (rate) with a direction; a quantity that has both magnitude (measurable amount) and direction.
Force ⇒ a push or pull
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An antique carousel that’s powered by a large electric motor undergoes constant angular acceleration from rest to full rotational speed in 5.00 seconds. When the ride ends, a brake causes it to decelerate steadily from full rotational speed to rest in 11.0 seconds. Compare the torque that starts the carousel to the torque that stops it. τstart/τstop = the tolerance is +/-2%
Answers
[tex]\tau = I \alpha[/tex]
where [tex]\tau[/tex] is the torque applied to the object, I is the moment of inertia and [tex]\alpha [/tex] is the angular acceleration.
2) We can write the ratio between the starting torque and the stopping torque as:
[tex] \frac{\tau _{start}}{\tau _{stop}} = \frac{I \alpha _{start}}{I \alpha _{stop}} = \frac{ \alpha _{start}}{\alpha _{stop}} [/tex]
3) Then, we can rewrite the two angular accelerations. The general formula is
[tex]\alpha = \frac{\omega _f - \omega _i}{t} [/tex]
where [tex]\omega _f [/tex] and [tex]\omega _i[/tex] are the final and initial angular velocities, while t is the time.
4) Let's start by calculating the starting acceleration. In this case, the initial velocity is zero, while the final velocity is the full rotational speed (let's call it [tex]\omega _{max}[/tex], and the time is t=5.0 s:
[tex]\alpha _{start} = \frac{\omega_{max}-0}{5 s}= \frac{\omega_{max}}{5 s}=[/tex]
When the carousel stops, instead, the initial velocity is [tex]\omega _{max}[/tex] while the final velocity is 0, and the time is t=11.0 s:
[tex]\alpha _{stop} = \frac{0-\omega _{max}}{11 s}= \frac{-\omega _{max}}{11 s} [/tex]
Therefore, if we replace the two angular accelerations that we found into the formula of the torque ration written at step 2), we find:
[tex] \frac{\tau _{start}}{\tau _{stop}} = - \frac{11}{5} [/tex]
where the negative sign simply means that the two torques have opposite direction. Therefore, the ratio between starting and stopping torque is 11:5.
can someone help me with the physics problem?:
if you do 144 J of work to elevate a bucket of water, what is it’s final gravitational potential energy relative to its starting position?
Answers
If a steel, thin-shelled wheel of radius r and mass M is moving along the road at 2 m/s, what is the total kinetic energy?
1) 2M
2) 3M
3) 1M
4) 5M
5) 4M
Answers
I = Mr²
The linear velocity is v = 2 m/s. The rotational velocity is
ω = 2/r
The total KE (kinetic energy) is
KE = (1/2)Mv² + (1/2) I ω²
= (1/2)(M)(4) + (1/2)(Mr²)(4/r²)
= 2M + 2M
= 4M
Answer: 4M