If venom A is four times as potent as venom B and venom C is 2.5 times as potent as venom B. How many times as potent is venom C compared to venom A?

Hi!

You know that if f(p) = 0, then (x-p) is a factor of the polynomial f(x)

Then, f(3)=0 is the case p=0, son the factor is (x-3)

Answer: Since we are told that f(3) = 0, we know that (x-3) is a factor.

Answer:

1360.78 g

Step-by-step explanation:

1 lb = 453.592 g

3 lbs = 3 * 453.592 g = 1360.78 g

Answer:

Not always we can use a calculator to determine if a number is rational or irrational.

Step-by-step explanation:

Consider the provided information.

Can you ever use a calculator to determine if a number is rational or irrational.

Irrational   number: A   number is irrational if it cannot   be   expressed by dividing two     integers. The decimal expansion of     Irrational numbers are neither terminate nor     periodic.

The calculators gives the approximate answer, whether the number is irrational or rational.

So, it would be difficult to identify whether a large number produced by the calculator is irrational or not. As we know that many rational numbers can be incredibly large.

So, we can say that not always we can use calculator to determine if a number is rational or irrational.

Thus, Not always we can use a calculator to determine if a number is rational or irrational.

Answer:

Hello my friend! The answer is 1.75X10^-15

Step-by-step explanation:

If you multiply 2.5 x7 = 17.5

When we do the product of exponential terms with the same base, we can sum de  exponents. In this case (-10) + (-6) = -16.  

However, to scientific notation, we have to use 1.75

So, the final result wich were 17.5x10-16, will be "1.75x10^-15"

Answer:

20 cm

Step-by-step explanation:

We are given a trapezoid, where the length of shorter base or on of the parllel line is 16 cm and the length of other parallel side is 24 cm.

Let the two parallel sides be x and y that is x = 16 cm and y = 24 cm.

A median of a trapezoid is a line segment that divides the non parallel sides of a trapezoid equally or a line segment that passes through the mid points of non-parallel sides of a trapezoid.

The length of median of a trapezoid = [tex]\frac{\text{Sum of parallel sides}}{2}[/tex] = [tex]\frac{16+24}{2}[/tex] = 20 cm.

Thus, the length of median of trapezoid is 20 cm.

Answer: 0.3399

Step-by-step explanation:

The binomial probability distribution formula to find the probability of getting success in x trial:-

[tex]P(x)=^nC_xp^x(1-p)^{n-x}[/tex], where n is the number of trials and p is the probability of getting success in each trial.

Given : Jorgensens received a shipment of 12 DVD Players. Shortly after arrival the  manufacturer called to say that that he had accidentally shipped  five defective units with the shipment.

i.e. The proportion of the defective units : [tex]p=\dfrac{5}{12}\approx0.417[/tex]

Also, Mr. Jorgensen pulled ten of the units and tested two of them.

For n=2, the  probability that neither of them was defective:-

[tex]P(x=0)=^{2}C_0(0.417)^0(1-0.417)^{2}\\\\=(1)(1)(0.583)^{2}\ \ \ [\text{ Since}^nC_0=1]\\\\=0.339889\approx0.3399[/tex]

Hence, the  probability that neither of them was defective = 0.3399

The digital scale should display 3.0 when weighing 3 lbs of ham. This is because 3 pounds exactly can be displayed as the decimal 3.0 after converting the number into a fraction, 3/1, and dividing the numerator by the denominator.

When Daniel wants to buy 3 lb of ham, the digital scale at the grocery store should display the decimal 3.0. This is because 3 pounds exactly translates to 3.0 in decimal terms.

The process of converting a number like 3 into a fraction would begin by writing it as 3/1 (as any number can be written over 1).

To convert that into decimal form, you would divide the top number (numerator) by the bottom number (denominator), so 3 ÷ 1 = 3.0.

Thus, the digital scale should read 3.0 when Daniel weighs out his 3 lbs of ham.

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Answer: Yes , the points (-4,-1), (2,1) and (11,4) are collinear.

Step-by-step explanation:

We know that if three points [tex](x_1,y_1),(x_2,y_2)[/tex] and [tex](x_3,y_3)[/tex] are collinear, then their area must be zero.

The area of triangle passes through points[tex](x_1,y_1),(x_2,y_2)[/tex] and [tex](x_3,y_3)[/tex] is given by :-

[tex]\text{Area}=\dfrac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|[/tex]

Given points : (-4,-1), (2,1) and (11,4)

Then, the area of ΔABC will be :-

[tex]\text{Area}=\dfrac{1}{2}|-4(1-4)+(2)(4-(-1))+(11)(-1-1)|\\\\\Rightarrow\text{Area}=\dfrac{1}{2}|-4(-3)+(2)(5)+(11)(-2)||\\\\\Rightarrow\text{Area}=\dfrac{1}{2}|12+10-22|\\\\\Rightarrow\text{Area}=\dfrac{1}{2}|0|=0 [/tex]

Hence, the points (-4,-1), (2,1) and (11,4) are collinear.

Answer:  a.    320 books

Step-by-step explanation:

Given : The total number of books  were placed on the discount shelf for 70% off the regular price = 960

The fraction of books sold = [tex]\dfrac{2}{3}[/tex]

Then, the number of books sold = [tex]\dfrac{2}{3}\times960=640[/tex]

Now, the number of books remain on the discount shelf = [tex]960-640=320[/tex]

Hence, the number of books remain on the discount shelf =320

Answer: c.  $4668.30

Explanation:

Given:

Sales = $513000

Sales made by an individual = 14% of $513000

Sales made by an individual = [tex]\frac{14}{100}\times 513000[/tex]

Sales made by an individual = $71280

Commission made on this sales = 6.5% of  $71280

Commission made on this sales = [tex]\frac{6.5}{100}\times 71280[/tex]

Commission made on this sales = $4668.30

Answer:

$2191.12

Step-by-step explanation:

We are asked to find the value of a bond after 10 years, if you invest $1000 in a savings bond that pays 4% interest, compounded semi-annually.

[tex]FV=C_0\times (1+r)^n[/tex], where,

[tex]C_0=\text{Initial amount}[/tex],

r = Rate of return in decimal form.

n = Number of periods.

Since interest is compounded semi-annually, so 'n' will be 2 times 10 that is 20.

[tex]4\%=\frac{4}{100}=0.04[/tex]

[tex]FV=\$1,000\times (1+0.04)^{20}[/tex]

[tex]FV=\$1,000\times (1.04)^{20}[/tex]

[tex]FV=\$1,000\times 2.1911231430334194[/tex]

[tex]FV=\$2191.1231430334194[/tex]

[tex]FV\approx \$2191.12[/tex]

Therefore, the bond would be $2191.12 worth in 10 years.

Answer: 0.03

Step-by-step explanation:

Total number of napkins: 5 x 525 = 2,625

75/2626 = 0.02857, which rounds to 0.03

The cost per individual napkin, when rounded to the nearest hundredth, is $0.03.

To begin finding the cost per napkin, we first need to find out how many napkins are purchased every 3 months. Since each box contains 525 napkins and you purchase 5 boxes every 3 months, that would be 525 * 5 = 2625 napkins. The cost of these napkins is $75.00.

So, to find the cost per individual napkin, you would divide the total cost by the total number of napkins. That would be 75 / 2625 = $0.028571... When rounded to the nearest hundredth, this becomes $0.03. So, each individual napkin costs $0.03. Therefore, the correct answer is (C) 0.03.

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Answer:

The integer representing the change of altitude to avoid the storm is 8,000

The integer representing the altitude after passing the storm is 30,000

Explanation:

The diagram of this question is shown in the attached image

We are given that the initial altitude of the plane was 30,000 ft

1- During the storm:

The plane flew at at altitude of 38,000 feet

To get the change in the altitude, we will subtract the final altitude from the initial one

change of altitude = final altitude - initial altitude

change of altitude = 38,000 - 30,000 = 8,000 ft

Therefore, the integer representing the change of altitude to avoid the storm is 8,000

2- After the storm:

We know that, after the storm, the plane returned to its initial altitude

Given that the initial altitude is 30,000 ft, this would mean that the integer representing the altitude after passing the storm is 30,000

Hope this helps :)

Final answer:

The integer representing the change in altitude when the airplane avoided the storm and then returned to its original altitude is zero. The altitude after passing the storm is 30,000 feet, the same as its original altitude before the ascent.

Explanation:

The integer representing the airplane's change in altitude to avoid the storm is zero because it returned to its original altitude after passing the storm. During the avoidance maneuver, the airplane would have increased in altitude (a positive change) and then decreased the same amount to return to its original altitude (a negative change). The sum of this positive and negative change is zero.

The integer representing the altitude after passing the storm is 30,000 feet, which is the same as the original altitude since the airplane returned to this altitude after avoiding the storm.

When considering aircraft performance, it's vital to take into account the rate of climb and descent, potential energy swaps from kinetic energy, and altitude effects on aircraft performance. However, in this instance, the specific figure for altitude change during the storm avoidance is not given, but the concept of returning to starting altitude implies no net change.

Answer: A programmer is the person who is responsible for making  computer programs.He/she makes sure that the program is created according to the requirement and  accurate performing operations .The goals of the programmer are as follows:-

Programmer is indulged in these goals because there are always upcoming new technologies in the field of programming so, to keep theirselves updates and maintain their skill they improve theirselves time to time. Also it can affect the job of the programmer if they are not aware about programming skills quite well or might end up losing the job.

Answer:

D

Step-by-step explanation:

Because ordering in ratios is important, so it must stay constant like 6,15.

Answer:

The answer is: D) 15/6

Step-by-step explanation:

The ratio of two given numbers such as X and Y is expressed by the symbol ':' Therefore, the ratio of X and Y or X:Y can be referred to as X is to Y and can also be expressed as a fraction X/Y or X÷Y.

Therefore, the ratio can be expressed in a number of ways, 6:15 = 6 to 15 = 6/15

Whereas, 15/6 = 15:6 ≠ 6:15

Answer:

a) -2 from (-2,0) b) 6 from (6,0) c) y-intercept: 12 from (0,12)

Step-by-step explanation:

The X intercepts in a quadratic function are the points of the x-axis crossed by the parabola. One quadratic equation may have up to two points on the X-axis. This or these points in the X-axis, the Zeros of this function,  will be crossed by the parabola.

The Y-intercept is the point of the y-axis crossed by the parabola.

Solving the equation:

[tex]-x^{2} +4x+12=0\\ x'=\frac{-4+\sqrt{64}}{-2} \\ x"=\frac{-4-\sqrt{64}}{-2} \\ x'=-2\\ x"=6\\[/tex]

S={-2, 6} These values, or zeros of this quadratic function are the X, intercepts.

c) The indepent term, or c, in f(x)= ax²+bx+c in this case is 12, also is the Y coordinate for the Parabola Vertex. This point is our intercept for y.

Answer:

Yolanda had the same number of penalties in both games.

Step-by-step explanation:

Both of these penalties can be modeled by a first order equation.

Game of Meteor-Mania:

In a game of Meteor-Mania, each penalty is -5 seconds. So the expression for the total of penalties is:

Tp(n) = -5*n, where n is the number of penalties.

In the game of Meteor-Mania, Yolanda had penalties totaling -25 seconds. So

-25 = -5*n *(-1)

5n = 25

n = 25/5

n = 5

Yolanda had 5 penalties in the game of Meteor-Mania

Game of Cosmic Calamity

In a game of Meteor-Mania, each penalty is -7 seconds. So the expression for the total of penalties is:

Tp(n) = -7*n, where n is the number of penalties.

In the game of Cosmic Calamity, Yolanda had penalties totaling -35 seconds. So

-35 = -7n *(-1)

7n = 35

n = 35/7

n = 5

Yolanda had 5 penalties in the game of Cosmic Calamity

Yolanda had the same number of penalties in both games.

The 99% confidence interval estimate for the genuine proportion of families who own at least one DVD player is:

Lower bound: 0.287.

Upper bound: 0.563.

To find the 99% confidence interval estimate of the true proportion of families who own at least one DVD player, follow these steps:

Step 1. Determine the sample proportion [tex](\( \hat{p} \))[/tex]:

Number of families surveyed ( n ) = 85

Number of families owning at least one DVD player ( x ) = 36

Sample proportion [tex](\( \hat{p} \)) = \( \frac{x}{n} = \frac{36}{85} = 0.4247 \)[/tex]

Step 2. Find the standard error (SE) of the sample proportion:

Standard error formula: [tex]\( SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \)[/tex]

Plug in the values: [tex]\( SE = \sqrt{\frac{0.4247 \times (1 - 0.4247)}{85}} = \sqrt{\frac{0.4247 \times 0.5753}{85}} = \sqrt{\frac{0.2443}{85}} = \sqrt{0.002875} = 0.0536 \)[/tex]

Step 3. Determine the z-value for a 99% confidence interval:

The z-value for a 99% confidence interval is approximately 2.576.

Step 4. Calculate the margin of error (ME):

Margin of error formula: [tex]\( ME = z \times SE \)[/tex]

Plug in the values: [tex]\( ME = 2.576 \times 0.0536 = 0.1381 \)[/tex]

Step 5. Determine the confidence interval

Lower limit: [tex]\( \hat{p} - ME = 0.4247 - 0.1381 = 0.2866 \)[/tex]

Upper limit: [tex]\( \hat{p} + ME = 0.4247 + 0.1381 = 0.5628 \)[/tex]

Therefore, the 99% confidence interval estimate of the true proportion of families who own at least one DVD player is:

Lower limit: 0.287

Upper limit: 0.563

Complete Question:

A survey of 85 families showed that 36 owned at least one DVD player. Find the 99 \% confidence interval estimate of the true proportion of families who own at least on DVD player. Place your limits, rounded to 3 decimal places, in the blanks. Do not use any labels or symbols other than the decimal point. Simply provide the numerical values. For example, 0.123 would be a legitimate entry.

Lower limit (first blank) [tex]$=$ $\qquad$[/tex] ______ , Upper limit (second blank) = _______

[tex]2xyy'+y^2-4x^3=0[/tex]

Let [tex]z(x)=y(x)^2[/tex], so that [tex]z'(x)=2y(x)y'(x)[/tex] (which appears in the first term on the left side):

[tex]xz'+z=4x^3[/tex]

This ODE is linear in [tex]z[/tex], and we don't have to find any integrating factor because the left side is already the derivative of a product:

[tex](xz)'=4x^3\implies xz=x^4+C\implies z=\dfrac{x^4+C}x[/tex]

[tex]\implies y(x)=\sqrt{\dfrac{x^4+C}x}[/tex]

With [tex]y(1)=2[/tex], we get

[tex]2=\sqrt{1+C}\implies C=3[/tex]

so the solution is as given in your post.

Answer:    a) 45    b) 60

Step-by-step explanation:

Given : A small restaurant has a menu with 2 appetizers, 5 main courses, and 3 desserts.

a) Number of meals includes an main course , a dessert and a appetizer, :-

[tex]2\times5\times3=30[/tex]

Number of meals includes an main course and a dessert and but not appetizer , then total possible meals:-

[tex]5\times3=15[/tex]

Then, the number of meals are possible if each includes an main course and a dessert, but may or may not include an appetizer= 30+15=45

b) Number of meals includes an main course and appetizer but not dessert:

[tex]5\times2=10[/tex]

Number of meals includes only main course =5

Now, the number of meals if dessert is also not required= 45+5+10=60

Answer: a) 15:26, and b) 15:11.

Step-by-step explanation:

Since we have given that

Number of graded tests = 15

Number of total tests = 26

Number of ungraded tests is given by

[tex]26-15\\\\=11[/tex]

a) Proportion of all exams has Dr. Fitxgerald graded is given by

15:26.

b) Ratio of graded to ungraded tests is given by 15:11

Hence, a) 15:26, and b) 15:11.

(a) The proportion of all exams graded by Dr. Fitzgerald is [tex]\(\frac{15}{26}\)[/tex].

(b) The ratio of graded to ungraded tests is [tex]\(\frac{15}{26 - 15}\) or \(\frac{15}{11}\)[/tex].

(a) To find the proportion of exams graded by Dr. Fitzgerald, we divide the number of exams graded by the total number of exams. This gives us the fraction:

[tex]\[ \text{Proportion graded} = \frac{\text{Number of exams graded}}{\text{Total number of exams}} = \frac{15}{26} \][/tex]

This fraction represents the part of the whole set of exams that has been graded.

(b) To find the ratio of graded to ungraded tests, we take the number of exams that have been graded and divide it by the number of exams that have not been graded. The number of ungraded exams is the total number of exams minus the number of graded exams:

[tex]\[ \text{Number of ungraded exams} = \text{Total number of exams} - \text{Number of exams graded} = 26 - 15 = 11 \][/tex]

Now, we can find the ratio:

[tex]\[ \text{Ratio of graded to ungraded tests} = \frac{\text{Number of exams graded}}{\text{Number of exams ungraded}} = \frac{15}{11} \][/tex]

This ratio tells us how many times greater the number of graded exams is compared to the number of ungraded exams.

Final answer:

To solve the system of inequalities, first, solve each inequality separately. Then, combine the solutions to find the common range of values for x that satisfy all the inequalities.

Explanation:

To solve the system of inequalities:

2x - 1 < x + 3

5x - 1 > 6 - 2x

x - 5 < 0

So, the solution to the system of inequalities is: x < 4, x > 1, x < 5

Answer:

  see below

Step-by-step explanation:

The "roster method" means you simply list them all:

  {John Boozman, Doug Jones, Martha McSally, Lisa Murkowski, Tom Cotton, Richard C. Shelby, Kyrsten Sinema, Dan Sullivan}

_____

There are no senators from these states with the same name, so repeated elements is not an issue here.

The set S includes the Senators John Boozman, Tom Cotton from Arkansas, Richard C. Shelby, Doug Jones from Alabama, and Lisa Murkowski, Dan Sullivan from Alaska. Each state has two unique senators, thus there are no repeated elements in the set.

The set S of current U.S. Senators from states that begin with 'A' using the roster method can be written as follows:

John Boozman (Arkansas)

Tom Cotton (Arkansas)

Richard C. Shelby (Alabama)

Doug Jones (Alabama)

Lisa Murkowski (Alaska)

Dan Sullivan (Alaska)

Each state beginning with 'A' (Alabama, Alaska, and Arkansas) contributes two senators to the set. S, as defined, would not have repeated elements since senators are unique to each state they represent, and no senator represents more than one state.

Answer:   29

Step-by-step explanation:

Let S denotes the total number of people surveyed, A denotes the event of having dog , B denotes the event of having cats and C denotes the event of having fish.

Given :     n(S)=50  ;n(A)=11  ;  n(B) =13  and  n(C)=6

Also, n(A∩B)=5 ;  n(A∩C) = 2 and n(B∩C)=3 and n(A∩B∩C)=1

We know that,

[tex]n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A \cap B)-n(A \cap C)-n(B \cap C)-n(A \cap B\cap C)\\\\=11+13+6-5-2-3+1=21[/tex]

Now, the number of people owned none of these pets :-

[tex]n(S)-n(A\cup B\cup C)\\\\=50-21=29[/tex]

Hence, the number of people owned none of these pets =29

Answer:

p = 5/7

Step-by-step explanation:

The given function is:

[tex]g(x) = -3x^{2} - 2x + 8[/tex] for -4 ≦ x < 1

[tex]g(x) = -2x + 7p[/tex] for 1 ≦ x ≦ 5

Part a)

A continuous function has no breaks, jumps or holes in it. So, in order for g(x) to be continuous, the point where g(x) stops during the first interval -4 ≦ x < 1 must be equal to the point where g(x) starts in the second interval 1 ≦ x ≦ 5

The point where, g(x) stops during the first interval is at x = 1, which will be:

[tex]-3(1)^{2}-2(1)+8=3[/tex]

The point where g(x) starts during the second interval is:

[tex]-2(1)+7(p) = 7p - 2[/tex]

For the function to be continuous, these two points must be equal. Setting them equal, we get:

3 = 7p - 2

3 + 2 = 7p

p = [tex]\frac{5}{7}[/tex]

Thus the value of p for which g(x) will be continuous is [tex]\frac{5}{7}[/tex].

Part b)

We have to find p by setting the two pieces equal to each other. So, we get the equation as:

[tex]-3x^{2}-2x+8=-2x+7p\\\\ -3x^{2}+8=7p[/tex]

Substituting the point identified in part (a) i.e. x=1, we get:

[tex]-3(1)^{2}+8=7p\\\\ 5=7p\\\\ p=\frac{5}{7}[/tex]

This value agrees with the answer found in previous part.

Answer:

If [tex]P_0 (x_0,y_0,z_0)[/tex] is a point on the surface, then the cartesian equation of the  tangent plane at [tex]P_0 (x_0,y_0,z_0)[/tex] is

[tex](\ast)z = z_0 + \frac{\partial z}{ \partial x}(x_0,y_0)\cdot (x -x_0) + \frac{\partial z}{\partial y} (x_0, y_0) (y -y_0)[/tex],

where [tex]z_0 = x_0 f \left ( \frac{y_0}{x_0}\right )[/tex].

Given that

[tex]\frac{\partial z}{\partial x} (x_0 , y_0) = f \left( \frac{y_0}{x_0}\right ) - \frac{y_0}{x_0} \cdot \frac{\partial f}{\partial x}(x_0,y_0) \ , \ \frac{\partial z}{\partial y} (x_0 , y_0)=\frac{\partial f}{\partial y} (x_0,y_0)[/tex], then

[tex](\ast)[/tex] becomes

[tex](\ast \ast) z=x_0 f \left ( \frac{y_0}{x_0}\right ) + f \left( \frac{y_0}{x_0}\right ) - \frac{y_0}{x_0}\cdot \frac{\partial f}{\partial x} (x_0,y_0)\cdot (x -x_0)+\frac{\partial f}{\partial y} (x_0,y_0)\cdot (y -y_0)[/tex].

Finally, replacing [tex] (x,y,z)=(0,0,0)[/tex] in [tex](\ast \ast)[/tex] you have that the equality is true for all [tex]P_0[/tex]. This means that [tex]O(0,0,0)[/tex]

belongs to all tangent planes and therefore, the result follows.      

Answer:

The set of solutions is [tex]\{\left[\begin{array}{c}a\\b\\x\\y\\z\end{array}\right] = \left[\begin{array}{c}-26+503y+543z\\-37+655y+724z\\-4+80y+90z\\y\\z\end{array}\right] : \text{y, z are real numbers}\}[/tex]

Step-by-step explanation:

The matrix associated to the problem is [tex]A=\left[\begin{array}{ccccc}1&-1&2&-8&1\\2&-1&-4&1&-2\\-4&1&4&-3&-1\end{array}\right][/tex] and the vector of independent terms is (3,1,-1)^t. Then the matrix equation form of the system is Ax=b.

The vector equation form is [tex]a\left[\begin{array}{c}1\\2\\-4\end{array}\right]+b\left[\begin{array}{c}-1\\-1\\1\end{array}\right] + x\left[\begin{array}{c}2\\-4\\4\end{array}\right]+y\left[\begin{array}{c}-8\\1\\-3\end{array}\right] + z\left[\begin{array}{c}1\\-2\\-1\end{array}\right]=\left[\begin{array}{c}3\\1\\-1\end{array}\right][/tex].

Now we solve the system.

The aumented matrix of the system is [tex]\left[\begin{array}{cccccc}1&-1&2&-8&1&3\\2&-1&-4&1&-2&1\\-4&1&4&-3&-1&-1\end{array}\right][/tex].

Applying rows operations we obtain a echelon form of the matrix, that is [tex]\left[\begin{array}{cccccc}1&-1&2&-8&1&3\\0&1&-8&-15&-4&-5\\0&0&1&-80&-9&-4\end{array}\right][/tex]

Now we solve for the unknown variables:

Since the system has two free variables then has infinite solutions.

The set of solutions is [tex]\{\left[\begin{array}{c}a\\b\\x\\y\\z\end{array}\right] = \left[\begin{array}{c}-26+503y+543z\\-37+655y+724z\\-4+80y+90z\\y\\z\end{array}\right] : \text{y, z are real numbers}\}[/tex]

Answer:

$767.49

Step-by-step explanation:

given,

Amount of money = $16,500

quarterly rate = 3.6/4 = 0.9 %

times = 6 × 4 = 24 quarters.                            

[tex]A =\dfrac{P(r(1+r)^n)}{(1+r)^n-1}\\\\A =\dfrac{16500\times(0.009(1+0.009)^{24})}{(1+0.009)^{24}-1}\\A = \$ 767.49[/tex]          

hence, the payment to amortize the dept  will be equal to $767.49  .

Answer:

3.055 m

Step-by-step explanation:

In this solution we will use next notation:

[tex]t_1[/tex]=  time elapsed since oco serves the ball until it reaches its opponent.

[tex]t_2[/tex]=  time elapsed since the opponent returns the ball until it reaches oco.

d= Total distance traveled by Oco since serving the ball until  meeting the return.

We know that oco serves at vs = 50 m/s and her opponent is x=25 m away. Then, t_1 is given by

[tex]t_1=\frac{25m}{50m/s}=0.5s[/tex]

To compute t_2 observe that the return speed is 12.5 m/s and the distance that the ball will travel is [tex]25-(10t_1+10t_2)[/tex]. Then,

[tex]t_2=\frac{25-10t_1-10t_2}{12.5}=\frac{20-10t_2}{12.5}\implies t_2=\frac{20}{22.5}=\frac{8}{9}s[/tex].

Therefore,

[tex]d=10(t_1+t_2)=10(0.5+\frac{8}{9})=10(\frac{17}{18})=\frac{85}{9}m[/tex]

Finally, as Oco started 12.5m away from the net, when she meets the return she will be

[tex]12.5-\frac{85}{9}=\frac{55}{18}=3.055m[/tex]

away from the net.