Your answer would be the; NET force on the object. Refer to Newton's Laws of Forces and Motion.
Hope that helps!!!!!!!!!!!!!!!! : )
Answer:
Net force
Explanation:
When a number of forces acting on a body, and then a non zero value of force is there. It is called net force acting on a body.
There are two types of forces.
1. Balanced forces
2. Unbalanced forces
When a number of forces acting on a body and then net force is zero, Then the forces are called balanced forces.
When a number of forces acting on a body and net force is non zero . Such forces are called unbalanced forces.
sara and tory are out fishing on the lake on a hot summer day when they both decide to go for a swim. sara dives off the front of the boat with a force of 45° N, while Tory dives off the back of the boat with a force of 60° N. Draw a vector diagram of the situation. Find the resultant force on the boat.
Here it is an application of Newton's III law
as we know by Newton's III law that every action has equal and opposite reaction
So here as we know that two boys jumps off the boat with different forces
from front side of the boat the boy jumps off with force 45 N which means as per Newton's III law if boy has a force of 45 N in forward direction then he must apply a reaction force on the boat in reverse direction of same magnitude
So boat must have an opposite force on front end with magnitude 45 N
Now similar way we can say
from back side of the boat the boy jumps off with force 60 N which means as per Newton's III law if boy has a force of 60 N in backward direction then he must apply a reaction force on the boat in reverse direction of same magnitude
So boat must have an opposite force on front end with magnitude 60 N
So here net force due to both jump on the boat is given by
[tex]F_{net} = F_1 - F_2[/tex]
[tex]F_{net} = 60 - 45[/tex]
[tex]F_{net} = 15 N[/tex]
so boat will have net force F = 15 N in forward direction due to both jumps
State the difference between sensible heat and latent heat
Latent heat is related to changes in phase between liquids ,gases and solids.
Sensible heat is related to changes in temperature of a gas or object with no change in phase.
Estimate the monthly cost of using a 700-W refrigerator that runs for 10 h a day if the cost per kWh is $0.20.
Answer:
Energy in KWH = Power in KW * Time in hours
Cost is # of KWH * the cost per KWH
350 kwh
Explanation:
The monthly cost of using a 700-W refrigerator that runs for 10 h a day if the cost per kWh is $0.20 is $42.
What is cost price per watt?The cost price per watt is the amount of money required to use one watt or kilo watt electricity,
To find the total cost of electricity used, multiply the cost price of electricity per watt to total watts of electricity used.
Given information-
The power used by the refrigerator is 700- W per hour.
Total run time of the refrigerator is 10 hours per day.
The cost of the electricity is $0.20 kWh.
As, the power used by the refrigerator is 700- W per hour and total run time of the refrigerator is 10 hours per day. The power used by the refrigerator per day is,
[tex]P=700\times10\\P=7000\rm Wh\\P=7\rm kWh[/tex]
There is total 30 days in a month. Thus the total power used by the refrigerator per month is,
[tex]P=7\times30\\P=210\rm kWh[/tex]
As the cost of the electricity is $0.20 kWh. Thus the cost of 210 kWh electricity is,
[tex]C=0.2\times210\\C=42[/tex]
Thus the monthly cost of using a 700-W refrigerator that runs for 10 h a day if the cost per kWh is $0.20 is $42.
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an archer shoots an arrow horizontally that hits a target 100m away. A bystander times the flight of the arrow at 2.2s. a) what was the initial velocity of the arrow? b) How far did the arrow drop in the vertical direction?
The archer is fired horizontally.
It hits the target which is at 100 m distance.
The horizontal velocity of the archer is always constant for a projectile in this situation.
The total time of flight is given as 2.2 s
Let the initial velocity is u .
Hence the target distance = ut
⇒ 100 m = u×2.2 s
⇒u = 100÷2.2 m/s
=45.45 m/s
We are asked to calculate the vertical distance travelled.
The vertical distance travelled is calculated as-
[tex]s= ut +\frac{1}{2} at^2[/tex] [ s is the distance and a is the acceleration]
[tex]s = 0*2.2 -\frac{1}{2} g[2.2]^2[/tex] [g is te acceleration due to gravity]
[tex]s=\frac{1}{2} 9.8*[2.2]^2[/tex] [here we have taken only magnitude]
=23.716 m [ans]
An 80.0-kg object is falling and experiences a drag force due to air resistance. The magnitude of this drag force depends on its speed, v, and obeys the equation Fdrag=(12.0N⋅s/m)v+(4.00N⋅s2/m2)v2. What is the terminal speed of this object?
Answer:
Terminal velocity of object = 12.58 m/s
Explanation:
We know that the terminal velocity is attained when drag force and gravitational force are of the same magnitude.
Gravitational force = mg = 80 * 9.8 = 784 N
Drag force = [tex]12.0v+4.00v^2[/tex]
Equating both, we have
[tex]784=12.0v+4.00v^2\\ \\ v^2+3v-196=0\\ \\ (v-12.58)(v+15.58)=0[/tex]
So v = 12.58 m/s or v = -15.58 m/s ( not possible)
So terminal velocity of object = 12.58 m/s
The terminal speed of the object is approximately [tex]\( 12.59 \, \text{m/s} \).[/tex]
To find the terminal speed of the object, we need to set the drag force equal to the gravitational force acting on the object. At terminal speed, the net force on the object is zero, meaning the drag force and the gravitational force are balanced.
The gravitational force [tex]\( F_g \)[/tex] acting on the object is given by the mass of the object m times the acceleration due to gravity g , which is approximately[tex]\( 9.81 \, \text{m/s}^2 \):[/tex]
[tex]\[ F_g = m \cdot g = 80.0 \, \text{kg} \times 9.81 \, \text{m/s}^2 \][/tex]
[tex]\[ F_g = 784.8 \, \text{N} \][/tex]
The drag force [tex]\( F_{\text{drag}} \)[/tex] is given by the equation:
[tex]\[ F_{\text{drag}} = (12.0 \, \text{N} \cdot \text{s/m})v + (4.00 \, \text{N} \cdot \text{s}^2/\text{m}^2)v^2 \][/tex]
At terminal speed,[tex]\( F_{\text{drag}} = F_g \)[/tex], so we have:
[tex]\[ (12.0 \, \text{N} \cdot \text{s/m})v_{\text{terminal}} + (4.00 \, \text{N} \cdot \text{s}^2/\text{m}^2)v_{\text{terminal}}^2 = 784.8 \, \text{N} \][/tex]
Now, we can use the quadratic formula to solve for [tex]\( v_{\text{terminal}} \):[/tex]
[tex]\[ v_{\text{terminal}} = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \][/tex]
where [tex]\( a = 4.00 \, \text{N} \cdot \text{s}^2/\text{m}^2 \), \( b = 12.0 \, \text{N} \cdot \text{s/m} \)[/tex], and [tex]\( c = -784.8 \, \text{N} \).[/tex]
Plugging in the values:
[tex]\[ v_{\text{terminal}} = \frac{-12.0 \pm \sqrt{(12.0)^2 - 4 \cdot 4.00 \cdot (-784.8)}}{2 \cdot 4.00} \][/tex]
[tex]\[ v_{\text{terminal}} = \frac{-12.0 \pm \sqrt{144 + 12556.8}}{8} \][/tex]
[tex]\[ v_{\text{terminal}} = \frac{-12.0 \pm \sqrt{12700.8}}{8} \][/tex]
[tex]\[ v_{\text{terminal}} = \frac{-12.0 \pm 112.7}{8} \][/tex]
Since speed cannot be negative, we take the positive root:
[tex]\[ v_{\text{terminal}} = \frac{-12.0 + 112.7}{8} \][/tex]
[tex]\[ v_{\text{terminal}} = \frac{100.7}{8} \][/tex]
[tex]\[ v_{\text{terminal}} = 12.5875 \, \text{m/s} \][/tex]
Help Please!! An object is dropped from a height h meters. From the time the object is h/2 meters above the ground, it takes 1 second until the object strikes the ground. From what height was the object dropped?
Here object is dropped from height "h"
so we can say its initial speed is zero
and it will accelerate downwards due to gravity
now we can say it will take time T to hit the ground
now we can use
[tex]h = v_i*t + \frac{1}{2}gt^2[/tex]
[tex]h = 0 + \frac{1}{2}*gT^2[/tex]
now it is given that it will take 1 second to drop h/2 height to strike the ground
so here we have can say that in "T - 1" s it will cover the h/2 distance from start
[tex]h/2 = 0 + \frac{1}{2}g(T-1)^2[/tex]
now we can say
[tex]h = g(T-1)^2[/tex]
from above two equations we have
[tex]\frac{1}{2}gT^2 = g(T-1)^2[/tex]
[tex]T^2 = 2(T^2 + 1 -2T)[/tex]
[tex]T^2 - 4T + 2 = 0[/tex]
[tex]T = 3.41 s[/tex]
now we can find total height of the drop by first equation
[tex]h = \frac{1}{2}gT^2[/tex]
[tex]h = \frac{1}{2}*9.81*3.41^2[/tex]
[tex]h = 57.2 m[/tex]
Explain the versatility of epithelial tissue
Answer:
Explanation:
The epithelial tissues cover the body surfaces, forms a lining over the body cavities and hollow organs. These tissues also forms a protective barrier between the external environment and the body.
The epithelial tissues are the tissues which performs various functions. These tissues are composed of cells that are laid close to each other with the cells that lies in the close association with each other. The structure and function of the epithelial cells vary from both upper and lower surfaces. Due to variety in the functions of the epithelial tissues like protection, secretion, cellular transportation, filtration, selective absorption and sensing, these are called as the versatile tissues.
What is the magnitude of force required to accelerate a car of mass
1.7 × 103 kilograms by 4.75 meters/second2?
Solution is attached.
Answer:
C. 8.1 × 103 newtons
Explanation:
if 2 objects have the same momentum which statement is true
A.mass and velocity are the same for both
B.they both have the same mass
C.the product of mass x velocity is the same for both
D.they both have the same velocity
C is the correct option
As momentum = (mass) (velocity)
P=mv
So the object having greater mass has less velocity and the object having smaller mass will move faster. But product of mass and velocity is same to each other.
___Fe + ___O2 →___Fe2O3
Your old bike left out in the rain starts to rust. What coefficients fill in the blanks to balance the equation?
A) 1,2,3
B) 2,3,1
C) 2,3,2
D) 4,3,2
The answer is D) 4,3,2
Just had this question
What makes some chemical bonds more stable than others
it occurs when the energy of the combination has lower energy than the separated atoms
These three members of the Noble gas family all have one property in common because they are gases at room temperature. That is they A) are combustible. B) are compressible. C) are relatively dense. D) have no definite shape but a definite volume.
B) are compressible.
gasses are compressible
Answer: Option (B) is the correct answer.
Explanation:
Noble gases group 18 elements. Members of this group are He, Ne, Ar, Kr, Xe, and Rn.
All these elements have completely filled sub-shells and hence they are stable in nature. All the elements of group 18 are gases, this means that their particles are loosely held due to weak intermolecular interaction.
As a result, their particles can move freely from one place to another. These gases can be compressed in order to bring their particles together. It is also known that all gases are compressible in nature.
Thus, we can conclude that noble gases have one property in common is that they are compressible.
What modifications did Kepler make to Copernicus model
Planets move in elliptical orbits and this theory was formulated by Johannes Kepler. Kepler's laws of planetary motion defined a set of rules followed by the planets while revolve around the sun and determines their orbits.
This modified the earlier theory of circular orbits from Nicholas Copernicus.
Kepler made two key modifications to Copernicus's model:
1. Kepler modified the circular orbits of planets proposed by Copernicus into elliptical orbits.
2. Kepler introduced the concept of varying planetary speeds along their orbits, rather than assuming constant speeds as Copernicus did.
To calculate the modifications Kepler made:
1. Elliptical Orbits:
- Kepler's first law states that planets move in elliptical orbits with the Sun at one of the foci. The formula for an ellipse is [tex]\( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \)[/tex], where [tex]\( a \)[/tex] is the semi-major axis and [tex]\( b \)[/tex] is the semi-minor axis.
- In contrast, Copernicus's model assumed perfect circular orbits with the Sun at the center.
2. Varying Planetary Speeds:
- Kepler's second law states that a line segment joining a planet and the Sun sweeps out equal areas during equal intervals of time. Mathematically, this is expressed as [tex]\( \frac{dA}{dt} = \text{constant} \),[/tex]where [tex]\( A \)[/tex] is the area swept and [tex]\( t \)[/tex] is time.
- Copernicus's model assumed uniform orbital speeds for planets.
Kepler's modifications were revolutionary as they better explained observations such as varying planetary brightness and retrograde motion. These changes laid the foundation for modern celestial mechanics and our understanding of planetary motion.
Complete Question:
What modifications did Kepler make to Copernicus model?
What best describes the difference between the second sound wave and the first
Second sound is a quantum mechanical phenomenon in which heat transfer occurs by wave-like motion, rather than by the more usual mechanism of diffusion. This leads to a very high thermal conductivity. It is known as "second sound" because the wave motion of heat is similar to the propagation of pressure waves in air (sound).
Normal sound waves are fluctuations in the density of molecules in a substance; second sound waves are fluctuations in the density of particle-like thermal excitations (rotons and phonons[1]). Second sound can be observed in any system in which most phonon-phonon collisions conserve momentum. This occurs in superfluids,[2] and also in some dielectric crystals[3][4][5] when Umklapp scattering is small. (Umklapp phonon-phonon scattering exchanges momentum with the crystal lattice, so phonon momentum is not conserved.)
wikipedia sourced to
Answer:
Its a
Explanation:
to improve the acoustics in an auditorium, a sound reflector with a mass of 170kg is suspended by a chain from the ceiling. what is the tension in the chain? assume that the mass of the chain itself is 8.0kg.
Mass of the sound reflector is given as
[tex]m_1 = 170 kg[/tex]
mass of the chain itself is
[tex]m_2 = 8 kg[/tex]
now here since this system is suspended at rest and no acceleration is given for the system so in order to find the tension in the chain we will just use force balance equation
As per force balance we can say that weight of the chain and reflector downwards will be counter balanced by tension in the string
Now here we will have
[tex]T = m_1g + m_2g[/tex]
since chain is given with some mass so tension at the top end of the chain will be
[tex]T = 170* 9.8 + 8 * 9.8[/tex]
[tex]T = 1744.4 N[/tex]
So here tension in the chain will be 1744.4 N at the top end and this tension will decrease as we move down along the length of the chain.
In the past, it was common for waste rocks from mines to be dumped in piles, known as tailings piles. These piles were sometimes located near bodies of moving water. how likely are tailings piles affect the water's natural processes?
A.
It increased erosion upstream.
B.
It increased erosion downstream.
C.
It decreased deposition upstream.
D.
It increased deposition downstream.
D.
It increased deposition downstream.
Answer:
D. It increased deposition downstream.
Explanation:
Tailing is the material leftover after separation of valuable material from ore. Tailing ponds are made near moving water are not good for water as they increase water pollution. In case of waste rocks from mine dumped near water body such as river, may reduce the depth of river bed and increase chances of flood. These deposits also increase deposition downstream and form big deltas.
Select the statement that is true regarding scientific theories.
A. Scientific theories are what laws are called before they are proven.
B. Scientific theories attempt to explain why natural events occur.
C. Scientific theories are based on true facts.
D. Scientific theories describe natural events.
B. Scientific theories attempt to explain why natural events occur.
Answer: B. Scientific theories attempt to explain why natural events occur.
Explanation:
The scientific theories are the detailed explanations which gives reasons for the cause of natural events, processes and phenomena that occur in the natural world. These are supported by the evidences and observations that are obtained through experimental trials. These theories can be changed due to the changing of facts due to further experimental studies conducted by new generation scientists.
The use of force to move an object is "_____".
The use of force to move an object is defined as 'work' in physics. Work is done when a force moves an object. The amount of work is measured as force multiplied by distance.
Explanation:The use of force to move an object is called work. This is a fundamental concept in Physics, specifically in the field of mechanics. According to this principle, work is done when a force that is applied to an object moves that object. For instance, when you push a box and it moves, you're doing work on the box. The amount of work done is calculated by multiplying the force by the distance over which it is applied (Work = Force x Distance). If there is no movement despite the force applied, no work is done according to physics.
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Bethany had a beaker with a small amount of baking soda. She added a few drops of pickle juice to the baking soda and observed fizzing and bubbling. Based on her observation, which of these can Bethany determine about the new substance formed by mixing the baking soda and pickle juice?
A chemical reaction produced a gas.
A chemical reaction produced a solid.
No chemical reaction took place.
Only a physical change happened.
A chemical reaction produced a gas. This was the observation done for the experiment performed by Bethany.
Answer: A
Explanation
Baking soda which is chemically known as sodium bicarbonate reacts with acidic agents like lemon juice or vinegar forming a bubbling like thing.
The sodium bicarbonate undergoes a chemical reaction with the acidic solution and the product of this reaction is the formation of carbon di oxide gas as bubbles and fizzing.
In this case, the pickle solution contains acidic substance like vinegar and lemon juice extract so when it reacts with sodium bicarbonate or baking soda, the carbon-di-oxide present in the sodium bicarbonate (NaHCo3) will be released as gas in the form of bubbles and fizzes on the surface of the solution.
Amy uses 20n of force to push a lawn mower 10 meters. How much work does she do
An object is moving at constant speed in a straight line. Which of the following would cause it to move differently? A. It is acted on by balanced forces. B. It is acted on by unbalanced forces. C. It is pushed by two new, exactly opposing forces. D. It ceases to be subject to any force.
An object moving at constant speed in a straight line would move differently if acted on by unbalanced forces, as indicated by Newton's first and second laws. Unbalanced forces would cause changes in the object's velocity, either in speed, direction, or both.
Explanation:An object moving at constant speed in a straight line would move differently if it was acted on by unbalanced forces. According to Newton's first law, an object will continue in its state of motion at constant speed in a straight line unless it is compelled to change by an external force. This principle refers to the inertia of the object.
For instance, the answer option 'B. It is acted on by unbalanced forces.' would make the object move differently. Unbalanced forces will cause the object to either speed up, slow down, or change its direction of motion. If there are exactly opposing forces (option 'C'), assuming they are equal in magnitude, they would balance each other out and the object will continue to move at the same speed in the same direction.
Newton's second law further explains that the rate of change of momentum of an object is directly proportional to the unbalanced force acting on it and takes place in the direction in which the force acts. As such, any presence of unbalanced forces will result in a change in the object's velocity - either speed, direction, or both - meaning the object's motion would be different.
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At take off, a plane flies 100 km north before turning to fly 200 km east. How far is its destination from where the plane took off?
Question 3 options:
173 km
300 km
224 km
200 km
Save
Question 4 (1 point)
A runner traveled 15 kilometers north then backtracked 11 kilometers south before stopping. His resultant displacement was
Question 4 options:
26 km south
4 km south
26 km north
4 km north
Answer
224 Km
4 Km
Explanation
Part 1
The plane flies 100 Km north and then 200 Km east. This makes a 90° turn. To get the distance taken by the plane we get the hypotenuse.
c² = a² + b²
c² = 100² + 200²
= 50,000
c = √50,000
= 223.606 Km
The answer to the nearest whole number is 224 Km
Part 2
If the runner run 15 Km north then 11 Km south, the resultant distance would be,
15 - 11 = 4 Km
Please select the word from the list that best fits the definition Used to compare two specific variables
A. line graph B. circle graph C. bar graph
please help.
i would say line graph
Answer: a. line graph
Explanation: A line graph is formed by joining the points given by the data with straight lines.
A line graph is usually used to show the change of information over a period of time using two variables . This means that the horizontal axis is usually a time scale, for example minutes, days, months or years; and the vertical axis shows the value of the information that varies in time.
As a country advances from an undeveloped nation to a modern industrialized nation, it changes in many significant ways.
How ever, some parallels will remain. For example ______ was used as an energy source by ancient civilization, and is still being used to produce energy today.
A.) wind
B.) fusión
C.) eléctricity
D.) volcanic ash
I’m not sure but I’m guessing wind.
Answer:
wind
Explanation:
From powering ships and windmills to wind-farms that generate electricity, wind has proven to be somewhat useful.
I’m gym class you run 22m horizontal then climb a rope vertically for 4.8m. What is the direction angle of your total displacement, as measured from the horizontal?
The answer is: 12.30 degrees.
To solve this problem you must apply the proccedure shown below:
1. You run 22 meters horizontally and then you climb a rope vertically for 4.8 meters.
2. So. let's call the angle [tex]\alpha[/tex], therefore, you must find it using [tex]tan^{-1}[/tex], as following:
[tex]tan^{-1}(\alpha)=\frac{opposite}{adjacent} \\opposite=4.8\\adjacent=22[/tex]
3. Substitute values and solve for the angle:
[tex]tan^{-1}(\alpha)=\frac{4.8}{22}\\\alpha=12.30degrees[/tex]
a ball was kicked horizontally off a clif at 15m/s, how high was the cliff if the ball landed 83 m from base of the cliff
The ball's horizontal position [tex]x[/tex] at time [tex]t[/tex] is
[tex]x=v_{0x}t[/tex]
The ball has initial velocity in the horizontal direction only, so [tex]v_{0x}=15\,\frac{\mathrm m}{\mathrm s}[/tex]. Then the time it takes for the ball to travel 83 m horizontally [tex]t[/tex] is given by
[tex]83\,\mathrm m=\left(15\,\dfrac{\mathrm m}{\mathrm s}\right)t\implies t=5.5\,\mathrm s[/tex]
Meanwhile, the ball's vertical position [tex]y[/tex] at time [tex]t[/tex], starting at the height of the cliff [tex]h[/tex], is given by
[tex]y=h-\dfrac12gt^2[/tex]
where [tex]g=9.8\,\frac{\mathrm m}{\mathrm s^2}[/tex] is the acceleration due to gravity. After 5.5 seconds, the ball hits the ground, so that [tex]y=0[/tex] when [tex]t=5.5\,\mathrm s[/tex], and we use this to solve for [tex]h[/tex]:
[tex]0=h-\dfrac12g(5.5\,\mathrm s)^2\implies h\approx150\,\mathrm m[/tex]
Across what potential difference does an electron have to be accelerated in order to reach the speed v=3e7 m/s?
When an electron is accelerated through potential difference then the speed that it attain will be explained by energy conservation
here by energy conservation we can say that
change in kinetic energy of electron = electrostatic potential energy gained through given potential difference
kinetic energy is given as
[tex]KE = \frac{1}{2}mv^2[/tex]
electrostatic potential energy is given as
[tex]PE = qV[/tex]
now by energy conservation
[tex]qV = \frac{1}{2}mv^2[/tex]
given that for electron
[tex]m = 9.1 * 10^{-31} kg[/tex]
[tex]v = 3 * 10^7 m/s[/tex]
[tex]q = 1.6 * 10^{-19} C[/tex]
now by plug in values
[tex]1.6 * 10^{-19} * V = \frac{1}{2}*9.1* 10^{-31} *(3*10^7)^2[/tex]
[tex]V = \frac{4.095 * 10^{-16}}{1.6 * 10^{-19}}[/tex]
[tex]V = 2559.4 Volts[/tex]
So here it is accelerated through potential difference of 2559.4 Volts
The electric potential is 4100 V or 4.1kV.
We know that the kinetic energy of the moving electron is equal to the 1/2mv^2. On this basis, we can write;
1/2mv^2 = eV
Where;
m = mass of the electron
v = speed of the electron
V = potential of the electron
e = charge on the electron.
Hence;
V = 1/2mv^2 /e
V = 0.5 × 9.11 × 10^-31 × (3 × 10^7)^2/1.6 ×10^-19
V = 4100 V or 4.1kV
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Please answer this! Answer #14
I would say B because not wearing a seatbelt is an example of risky behavior, which they’re were trying to prevent
What is the most important concern when trying to prevent frostbite?
A. Drinking enough fluids
B.wearing cotton next to your skin
C. Dressing to protect hands
D.wearing sunscreen
answer is C. dressing to protect hands
The most reactive metals are located at the of the periodic table.
Answer:
the elements towards the bottom left corner
Explanation:
Metals are the substances which tend to lose their valence electrons in order to attain stability.
For example, metals of group 1 are lithium, sodium, potassium, rubidium and cesium.
And, each of these elements have only 1 valence electron present. So, it is much easier to lose just one electron rather than losing 2 or 3 valence electrons.
Hence, alkali metals are the most reactive substances of the periodic table and they are present at extreme left side of periodic table.
Therefore, we can conclude that the most reactive metals are located at the extreme left of the periodic table.