Use the Newton-Raphson method to determine the solution of the simultaneous nonlinear equations: y=−x2+x+0.75 y+5xy=x2 Use the initial guesses of x = y = 1.2, and iterate until the 4th iteration. (Round the final answers to five decimal places.) The values of x and y are as follows: iterationxy01.21.21 0.0290321.39412 3 0.239294
Answer:
Step-by-step explanation:
Let's solve for y.
−x2+x+0.75y+5xy=x2
Step 1: Add x^2 to both sides.
−x2+5xy+x+0.75y+x2=x2+x2
5xy+x+0.75y=2x2
Step 2: Add -x to both sides.
5xy+x+0.75y+−x=2x2+−x
5xy+0.75y=2x2−x
Step 3: Factor out variable y.
y(5x+0.75)=2x2−x
Step 4: Divide both sides by 5x+0.75.
y(5x+0.75)
5x+0.75
=
2x2−x
5x+0.75
y=
2x2−x
5x+0.75
Answer:
y=
2x2−x
5x+0.75
The Newton-Raphson method is a numerical technique used to find roots of nonlinear equations. Through iterations, the method identifies a value that satisfies the equations provided. Doing this for four iterations, we find that x=0.239294 and y=1.39412.
Explanation:The Newton-Raphson method uses iterations to find the solution of nonlinear equations. Given the equations y = -x^2+x+0.75 and y+5xy=x^2 and the initial guesses x=y=1.2, we'll use the Newton-Raphson method to find the roots.
We can represent these equations as f(x,y) = -x^2+x+0.75 - y and g(x,y) = x^2 - y - 5xy = 0. The Newton-Raphson method works by using the Jacobian matrix, comprised of the partial derivatives of the equations with respect to x and y, to estimate new values for x and y with each iteration. Starting with our initial values of x and y, we then repeatedly apply the formula to calculate new values of x and y until we've reached the desired number of iterations.
Using this method, you end up with the following values: x=0.239294 and y=1.39412 for iteration 4. Remember, this method uses an iterative approach, and different starting values might yield slightly different results.
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Let f : A --> B where (8 points) f = {(a, 1), (b, 3), (c, 5), (d, 2)) a. What is the co-domain of f 3. Let A= {a, b,c,d) and B= {1, 2, 3, 4, 5, 6). b. What is the range of f? c. Is f-1 a function Explain . d. Can there exist a bijection between A and B? Explain
Answer with Step-by-step explanation:
Let A= {a, b,c,d} and B= {1, 2, 3, 4, 5, 6}
Define f:A→B
where f = {(a, 1), (b, 3), (c, 5), (d, 2)}
a. What is the co-domain of f
The co-domain or target set of a function is the set into which all of the output of the function is constrained to fall.
Here, all the values are constrained to fall on the set B
Hence, co-domain={1, 2, 3, 4, 5, 6}
b. What is the range of f?
The set of all output values of a function is called range.
Here, on putting the values of set A we get the output values as:1,2,3 and 5
Hence, Range={1,2,3,5}
c. Is f 1-1 function Explain.
A function for which every element of the range of the function corresponds to exactly one element of the domain.
Yes, f is 1-1
(Since, every element of range i.e. 1,2,3 and 5 corresponds to only one element of set A)
d. Can there exist a bijection between A and B? Explain.
No, there cannot exist bijection from A to B
because if a bijection exist between two sets then there cardinalities are same but A and B have different cardinalities
A has cardinality 4 and B has cardinality 6
A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t) = 52t - 16t^2 . What is the maximum height that the ball will reach?
Do not round your answe
Answer:
42.25 feet
Step-by-step explanation:
The height function is a parabola. The maximum value of a negative parabola is at the vertex, which can be found with:
x = -b/2a
where a and b are the coefficients in y = ax² + bx + c.
Here, we have y = -16t² + 52t. So a = -16 and b = 52. The vertex is at:
t = -52 / (2×-16)
t = 13/8
Evaluating the function:
h(13/8) = -16(13/8)² + 52(13/8)
h(13/8) = -169/4 + 169/2
h(13/8) = 169/4
h(13/8) = 42.25
Answer:
42.25 feet.
Step-by-step explanation:
The maximum height can be found by converting to vertex form:
h(t) = 52t - 16t^2
h(t) = -16 ( t^2 - 3.25t)
h(t) = -16 [ (t - 1.625)^2 - 2.640625 ]
= -16(t - 1.625 ^2) + 42.25
Maximum height = 42.25 feet.
Another method of solving this is by using Calculus:
h(t) = 52t - 16t^2
Finding the derivative:
h'(t) = 52 - 32t
This = zero for a maximum/minimum value.
52 - 32t = 0
t = 1.625 seconds at maximum height.
It is a maximum because the path is a parabola which opens downwards. we know this because of the negative coefficient of x^2.
Substituting in the original formula:h(t) = 52(1.625)- 16(1.625)^2
= 42.25 feet.
A researcher is interested in estimating the mean weight of a semi trailer truck to determine the potential load capacity. She takes a random sample of 17 trucks and computes a sample mean of 20,000 pounds with sample standard deviation of 1,500. The 95% confidence interval for the population mean weight of a semi trailer truck is ______________.
Answer: 95% confidence interval = 20,000 ± 2.12[tex]\times[/tex][tex]\frac{1500}{\sqrt{17} }[/tex]
( 19228.736 , 20771.263 ) OR ( 19229 , 20771 )
Step-by-step explanation:
Given :
Sample size(n) = 17
Sample mean = 20000
Sample standard deviation = 1,500
5% confidence
∴ [tex]\frac{\alpha}{2}[/tex] = 0.025
Degree of freedom ([tex]d_{f}[/tex]) = n-1 = 16
∵ Critical value at ( 0.025 , 16 ) = 2.12
∴ 95% confidence interval = mean ± [tex]Z_{c}[/tex][tex]\times[/tex][tex]\frac{\sigma}{\sqrt{n} }[/tex]
Critical value at 95% confidence interval = 20,000 ± 2.12[tex]\times[/tex][tex]\frac{1500}{\sqrt{17} }[/tex]
( 19228.736 , 20771.263 ) OR ( 19229 , 20771 )
our friend purchases a $185,000 house. He is able to make a 15% down payment. The bank will give him a 30-year loan with a 3.5% APR.
How much money will he borrow for his mortgage?
$ (round to the nearest dollar)
What would his monthly payment be?
$ (round to the nearest cent)
How much interest will your friend pay over 30 years of his loan?
$ (round to the nearest cent)
Answer:
Given,
The value of the house = $ 185,000,
Percentage of down payment = 15%,
(i) So, the borrowed amount = 185,000 - 15% of 185,000
[tex]=185000-\frac{15\times 185000}{100}[/tex]
[tex]=185000-\frac{2775000}{100}[/tex]
[tex]=185000-27750[/tex]
[tex]=\$157250[/tex]
(ii) Since, the monthly payment formula of a loan is,
[tex]P=\frac{PV\times r}{1-(1+r)^{-n}}[/tex]
Where,
PV = present value of the loan ( or borrowed amount )
r = rate per month,
n = number of months,
Here, PV = $ 157250,
APR = 3.5% = 0.035 ⇒ r = [tex]\frac{0.035}{12}[/tex] ( 1 year = 12 months )
Time = 30 years, ⇒ n = 360 months,
Hence, the monthly payment would be,
[tex]P=\frac{157250\times \frac{0.035}{12}}{1-(1+\frac{0.035}{12})^{-360}}[/tex]
[tex]=706.122771579[/tex] ( by graphing calculator ),
[tex]\approx \$ 706.12[/tex]
(iii) Interest = Total amount paid - borrowed amount
= 706.122771579 × 360 - 157250
= 96954.1977684
≈ $ 96954. 20
The friend will borrow $157,250 for the mortgage, with a monthly payment of $704.30. They will pay $101,548 in interest over 30 years.
Explanation:To calculate the amount of money borrowed for the mortgage, we need to subtract the down payment from the total cost of the house. The down payment is 15% of the house cost, which is $185,000 x 0.15 = $27,750. So, the borrowed amount is $185,000 - $27,750 = $157,250.
To calculate the monthly payment, we can use the formula for a fixed-rate mortgage: M = P [ i(1 + i)^n ] / [ (1 + i)^n - 1 ]. Here, P is the borrowed amount ($157,250), i is the monthly interest rate (3.5% / 12 = 0.002916), and n is the total number of monthly payments (30 x 12 = 360). Plugging in these values, we get M = $157,250 [ 0.002916(1 + 0.002916)^360 ] / [ (1 + 0.002916)^360 - 1 ]. Using a calculator, the monthly payment comes out to be approximately $704.30.
To calculate the total interest paid over 30 years, we can multiply the monthly payment by the total number of payments and subtract the borrowed amount. The total interest paid = ($704.30 x 360) - $157,250. Using a calculator, the total interest paid comes out to be approximately $101,548. So, your friend will pay approximately $157,250 for the mortgage, with a monthly payment of approximately $704.30, and will pay approximately $101,548 in interest over 30 years.
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Twenty percent (20%) of 90 equals
A. 12
B. 15
C. 18
D. 21
Answer:
20 percent *90. =
(20:100)*90. =
(20*90.):100 =
1800:100 = 18
The correct answer is C.
Which statement is true regarding the graphed functions?
f(-2)=g(-2)
Think of the number in parentheses as your x value. f(x)=y. In this case the line hit at (-2,4) so when f(x) = 4, g(x)= 4 and 4=4 so you then have to find the x which in this case is -2. I’m pretty bad at explaining but there’s your answer
Answer:
f(-2)=g(-2)
Think of the number in parentheses as your x value. f(x)=y. In this case the line hit at (-2,4) so when f(x) = 4, g(x)= 4 and 4=4 so you then have to find the x which in this case is -2. I’m pretty bad at explaining but there’s your answer
Step-by-step explanation:
If f(x) = 3x – 15, then f-'(x) =D
Answer:
[tex]f^{-1}(x)=\frac{x+15}{3}[/tex]
or
[tex]f^{-1}(x)=\frac{x}{3}+5[/tex]
Step-by-step explanation:
That means we want to find the inverse function of f(x)=3x-15.
The inverse function is just the swapping of x and y really. We tend to remake the y the subject afterwards.
So we are given:
y=3x-15
First step: Swap x and y
x=3y-15
Now it's time to solve for y.
Second step: Add 15 on both sides:
x+15=3y
Third step: Divide both sides by 3:
(x+15)/3=y
The inverse function is:
[tex]f^{-1}(x)=\frac{x+15}{3}[/tex]
You can also split up the fraction like so:
[tex]f^{-1}(x)=\frac{x}{3}+\frac{15}{3}[/tex]
The last fraction there can be reduced:
[tex]f^{-1}(x)=\frac{x}{3}+5[/tex]
Since 2007, a particular fund returned 13.3% compounded monthly. How much would a $4000 investment in this fund have been worth after 2 years? (Round your answer to the nearest cent.)
Answer:
$5,211.30
Step-by-step explanation:
We have to calculate compound interest with the formula [tex]A=P(1+\frac{r}{n})^{nt}[/tex]
Where A = Amount after maturity
P = Principal amount ( $4,000)
r = Rate of interest 13.3% in decimal ( 0.133)
n = number of compounding period, monthly ( 12 )
t = Time in years ( 2 )
Now we put the values in the formula
[tex]A=4,000(1+\frac{0.133}{12})^{(12\times 2)}[/tex]
[tex]A=4,000(1+0.0110833)^{(24)}[/tex]
[tex]A=4,000\times 1.0110833^{24}[/tex]
[tex]A=4,000\times 1.3028262297[/tex]
A = $5,211.30
After 2 years investment would be $5,211.30.
The ratio of my money to Natalie's was 7 to 4. After I gave Natalie $15, I now have 20 % more than her. How much money do we each have now? Solve with a strip diagram and explain.
Answer:
my money= $192.5
Natalie's money= $110
Step-by-step explanation:
let my and Natalie's money be 7x and 4x respectively.
Now i gave $15 dollar to Natalie so now
my and Natalie's money will be (7x-15) and (4x+15) respectively.
now my money is 20% more than Natalie
therefore,
[tex]\frac{7x-15}{4x+15} =\frac{6}{5}[/tex]
now calculating for x we get
x= 27.5
since, my and Natalie's money be 7x and 4x respectively
putting x=27.5
my money= $192.5
Natalie's money= $110
Solve for n
–6(n – 8) = 4(12 – 5n) + 14n
show work please!
Step-by-step explanation:
-6(n-8)=4(12-5n)+14n
-6n+48=48-20n+14n
20n-6n-14n=48-48
-6n+6n=0
-6n=-6n
The statement is true for any value of n, because both sides are identical.
n€ R.
...
wait ... is this a graphical question ?!?!?!
The answer is:
The solution is all the values that belong to the real numbers, and any value of "n" that we can substitute, will lead us to a satisfied equation.
Why?We are given the following expression:
[tex]-6(n-8)=4(12-5n)+14n[/tex]
So, we need to perform the expressed operations using the distributive property, and then, add/subtract the like terms.
Now, solving we have:
[tex]-6(n-8)=4(12-5n)+14n[/tex]
[tex]-6*n+(-6*-8)=4*12+(4*-5n)+14n[/tex]
[tex]-6n+48=48-20n+14n[/tex]
[tex]-6n+48=48-6n[/tex]
[tex]0=0[/tex]
Hence, we can se that 0 is equal to 0, it means that the solution is all the values that belong to the real numbers, and any value of "n" that we can substitute, will lead us to a satisfied equation.
Have a nice day!
My Notes OAsk Your Tea The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.3 hours. If 1 gram of this isotope is present initially, how long will it take for 85% of the lead to decay? (Round your answel to two decimal places.) hr
Answer:
10.96 hours will take for 85% of the lead to decay.
Step-by-step explanation:
Suppose A represents the amount of Pb-209 at time t,
According to the question,
[tex]\frac{dA}{dt}\propto A[/tex]
[tex]\implies \frac{dA}{dt}=kA[/tex]
[tex]\int \frac{dA}{A}=\int kdt[/tex]
[tex]ln|A|=kt+C_1[/tex]
[tex]A=e^{kt+C_1}[/tex]
[tex]A=e^{C_1} e^{kt}[/tex]
[tex]\implies A=C e^{kt}[/tex]
Let [tex]A_0[/tex] be the initial amount,
[tex]A_0=C e^{0} = C[/tex]
[tex]\implies A=A_0 e^{kt}[/tex]
Since, the half-life of 3.3 hours.
[tex]\implies \frac{A_0}{2}=A_0 e^{3.3k}\implies e^{3.3k}=0.5\implies k=-0.21004[/tex]
[tex]\implies A=A_0 e^{-0.21004t}[/tex]
Here, [tex]A_0=1\text{ gram}[/tex]
[tex]A=(100-85)\% \text{ of }A_0=15\%\text{ of }A_0=0.15A_0[/tex]
By substituting the values,
[tex]0.15A_0=A_0 e^{-0.21004t}[/tex]
[tex]0.15=e^{-0.21004t}[/tex]
[tex]\implies t\approx 10.96\text{ hour}[/tex]
Last year, a person wrote 128 checks. Let the random variable x represent the number of checks he wrote in one day, and assume that it has a Poisson distribution. What is the mean number of checks written per day? What is the standard deviation? What is the variance?
Answer: The mean number of checks written per day = [tex]\lambda=0.3507[/tex]
[tex]\text{Variance}(\sigma^2)=\lambda=0.3507[/tex]
[tex]\text{Standard deviation}=0.5922[/tex]
Step-by-step explanation:
Given : A person wrote 128 checks in last year.
Consider , the last year is a no-leap year.
The number of days in ;last year = 365 days
Let X be the number of checks in one day.
Then , [tex]X=\dfrac{128}{365}=0.350684931507\approx0.3507[/tex]
The mean number of checks written per day = [tex]\lambda=0.3507[/tex]
Now X follows Poisson distribution with parameter [tex]\lambda=0.3507[/tex].
Then , [tex]\text{Variance}(\sigma^2)=\lambda=0.3507[/tex]
[tex]\Rightarrow\sigma=\sqrt{\lambda}=\sqrt{0.3507}=0.59219929078\approx0.5922[/tex]
. Joyce Meadow pays her three workers $160, $470, and $800, respectively, per week. Calculate what Joyce will pay at the end of the first quarter for (A) state unemployment and (B) federal unemployment. Assume a state rate of 5.6% and a federal rate of .6%. Base is $7,000. A. $950.64; $67.14 B. $655.64; $97.14 C. $755.64; $81.14 D. $850.64; $91.14
Answer:
Option D. $850.64; $91.14
Step-by-step explanation:
Joyce Meadow pays her three workers per week $160, $470 and $800 respectively.
A year has 52 weeks, Therefore quarter has [tex]\frac{52}{4}[/tex] = 13 weeks.
So for a quarter she pays = 160 × 13 = $2,080, 470 × 13 = $6,110, 800 × 13 = $10,400
State rate is 5.6%
Federal rate is 0.6%
Base is $7,000
It means the unemployment needs to be paid on the first $7000 only
So the state unemployment = (0.056 × 2,080) + (0.056 × 6,110) + (0.056 × 7,000)
= 116.48 + 342.16 + 392 = $850.64
Federal unemployment = (0.006 × 2,080) + (0.006 × 6,110) + (0.006 × 7,000)
= 12.48 + 36.66 + 42 = $91.14
Option D. is the correct answer.
In a certain country, the average age is 31 years old and the standard deviation is 4 years. If we select a simple random sample of 100 people from this country, what is the probability that the average age of our sample is at least 32?
Answer: 0.0062
Step-by-step explanation:
Given : Mean : [tex]\mu=\ 31[/tex]
Standard deviation :[tex]\sigma= 4[/tex]
Sample size : [tex]n=100[/tex]
Assume that age of people in the country is normally distributed.
The formula to calculate the z-score :-
[tex]z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]
For x = 32
[tex]z=\dfrac{32-31}{\dfrac{4}{\sqrt{100}}}=5[/tex]
The p-value = [tex]P(x\geq32)=P(z\geq5)[/tex]
[tex]=1-P(z<5)=1- 0.9937903\approx0.0062[/tex]
Hence, the the probability that the average age of our sample is at least =0.0062
The probability that the average age of the sample is at least 32 is approximately 0.62%.
Explanation:To find the probability that the average age of our sample is at least 32, we can use the normal distribution. The average age of the population is 31 years old and the standard deviation is 4 years. Since we have a large sample size (100), we can use the central limit theorem to assume that the sample mean will follow a normal distribution.
To calculate the probability, we need to find the z-score for the value 32. The z-score formula is z = (x - μ) / (σ / √n), where x is the desired value, μ is the population mean, σ is the population standard deviation, and n is the sample size. Plugging in the values, we get z = (32 - 31) / (4 / √100) = 1 / (4 / 10) = 2.5.
Using a z-table or a calculator, we can find that the probability of a z-score of 2.5 or more is approximately 0.0062, or 0.62%.
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Find the selling price for a case of Newman's Own® special blend coffee that costs the retailer $35.87 if the markup is 22% of the selling price.
Answer:
The selling price is $46 approx.
Step-by-step explanation:
The cost price is = $35.87
Markup is 22% of selling price.
Let the selling price be = 100%
So, 100%-22%=78% = 0.78
So, solution is = [tex]35.87/0.78=45.98[/tex] ≈ $46.
Hence, the selling price is $46 approx.
17. Prove the following statement: Let n e Z. If n is odd, then n2 is odd. Proof 6 pts. 2 VÎ±Î¶Ï there fore, n and n Please See tue classnotes
Answer with explanation:
It is given that , n is Odd integer.
If , n is odd, then it can be Written as with the help of Euclid division lemma
→ n= 2 p +1, as 2 p is even , and adding 1 to it converts it into Odd.
As Euclid lemma states that for any three integers, a ,b and c ,when a is divided by b, gives quotient c and remainder r , then it can be written as:
a= b c+r, →→0≤r<b
Now, n² will be of the form
(2 p +1)²=(2 p)²+2 × 2 p×1+ (1)²
=4 p²+4 p +1
⇒Multiplying any positive or negative Integer by 4, gives Even integer and sum or Difference of two even integer is always even.
So, 4 p²+4 p, will be an even term.But Adding , 1 to it converts it into Odd Integer.
Hence, if n is an Odd number then , n² will be also odd.
Solve the system of equations. x+y=4 y=x^2 - 8x + 16 a) {(-3,7).(-4, 8)} b) [(4,0)} c) {(3,1),(4,0) d) {(3,7). (4.0)} e) none
Answer: The required solution of the given system is
(x, y) = (3, 1) and (4, 0).
Step-by-step explanation: We are given to solve the following system of equations :
[tex]x+y=4~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\y=x^2-8x+16~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)[/tex]
From equation (i), we have
[tex]x+y=4\\\\\Rightarrow y=4-x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)[/tex]
Substituting the value of y from equation (iii) in equation (ii), we get
[tex]y=x^2-8x+16\\\\\Rightarrow 4-x=x^2-8x+16\\\\\Rightarrow x^2-8x+16-4+x=0\\\\\Rightarrow x^2-7x+12=0\\\\\Rightarrow x^2-4x-3x+12=0\\\\\Rightarrow x(x-4)-3(x-4)=0\\\\\Rightarrow (x-3)(x-4)=0\\\\\Rightarrow x-3=0,~~~~~~~x-4=0\\\\\Rightarrow x=3,~4.[/tex]
When, x = 3, then from (iii), we get
[tex]y=4-3=1.[/tex]
And, when x = 4, then from (iii), we get
[tex]y=4-4=0.[/tex]
Thus, the required solution of the given system is
(x, y) = (3, 1) and (4, 0).
please help
An aircraft factory manufactures airplane engines. The unit cost C (the cost in dollars to make each airplane engine) depends on the number of engines made. If x engines are made, then the unit cost is given by the function C(x) = 1.1x^2 - 638x + 111,541 . What is the minimum unit cost?
Do not round your answer.
The minimum unit cost is approximately $42,330.09.
Explanation:To find the minimum unit cost, we need to find the vertex of the quadratic function C(x) = 1.1x^2 - 638x + 111,541. The x-coordinate of the vertex can be found using the formula x = -b / 2a, where a = 1.1 and b = -638. Plugging in these values, we get:
x = -(-638) / (2 * 1.1) = 290.9090909
So the minimum unit cost occurs when approximately 291 engines are made. To find the minimum unit cost, we substitute this value back into the C(x) function:
C(291) = 1.1(291)^2 - 638(291) + 111,541 = 42330.090909
Therefore, the minimum unit cost is approximately $42,330.09.
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if 1.04 = 2 to the power of 1/j, how do I calcate j ? i know the answer should be 17.7
Answer:
Step-by-step explanation:
Follow these steps. First let's look at the problem:
[tex]1.04=2^{\frac{1}{j}}[/tex]
Multiply each side by j/1:
[tex]1.04^{\frac{j}{1}} =2^{\frac{1}{j} *\frac{j}{1}}[/tex]
which simplifies to
[tex]1.04^j=2[/tex]
Now take the natural log of both sides:
[tex]ln(1.04)^j=ln(2)[/tex]
The power rule says that we can bring the exponent down in front of the natural log:
(j) ln(1.04) = ln(2) and then divide both sides by ln(1.04)
Do the division on your calculator to get that j = 17.7
A fleet of refrigerated delivery trucks is acquired on January 5, 2017, at a cost of $830,000 with an estimated useful life of eight years and an estimated salvage value of $75,000. Compute the depreciation expense for the first three years using the double-declining-balance method
Answer:
1st year: $ 622,500
2nd year: $415,000
3rd year: $207,500
Step-by-step explanation:
Step 1: Write the beginning book value of the asset
$830,000
Step 2: Determine the asset's estimated useful life
8 years
Step 3: Determine the asset's salvage value
$75,000
Step 4: Subtract the salvage value from the beginning value to get the total depreciation amount for the asset's total life.
830,000 - 75,000 = $755,000
Step 5: Calculate the annual depreciation rate
Depreciation rate = 100%/8 years = 12.5%
Step 6: Multiply the beginning value by twice the annual depreciation rate to find the depreciation expense
Depreciation expense = 830,000 x 25% = $207,500
Step 7: Subtract the depreciation expense from the beginning value to find the ending period value
Ending period value for 1st year: Beginning value - depreciation expense
830,000 - 207,500 = $ 622,500
Ending period value for 2nd year: 622,500 - 207,500 = $ 415,000
Ending period value for 3rd year: 415,000 - 207,500 = $ 207,500
!!
Does the mean of a normal distribution is always positive? How about the standard deviation?
Answer:
Mean of a Normal Distribution:
The mean of normal distribution is not always positive, it is equally distributed around mean,mode and median and can be any value from ranging from negative to positive to infinity.
Standard Deviation:
For the standard deviation, it can not be negative. It can only be equal to any positive values i.e., values [tex]\geq 0[/tex].
Express the situation as a system of two equations in two variables. Be sure to state clearly the meaning of your x- and y-variables. Solve the system by row-reducing the corresponding augmented matrix. State your final answer in terms of the original question.
For the final days before the election, the campaign manager has a total of $37,000 to spend on TV and radio campaign advertisements. Each TV ad costs $3000 and is seen by 10,000 voters, while each radio ad costs $500 and is heard by 2000 voters. Ignoring repeated exposures to the same voter, how many TV and radio ads will contact 130,000voters using the allocated funds?
x = TV ads
y = radio ads
Answer:
9 TV ads and 20 radio ads
Step-by-step explanation:
He has $37,000 to spend. He has to sum that amount of money between the TV and radio ads. Each TV ad costs $3000 while each radio ad costs $500, so the equation that represents that is 37000 = 3000x + 500y
The same happens with the amount of voters he needs to reach, the equation is 130000 = 10000x + 2000y
The system that represents this is
[tex]\left \{ {{3000x+500y=37000} \atop {10000x+2000y=130000}} \right.[/tex]
And the augmented matrix is
[tex]\left[\begin{array}{cc|c}3000&500&37000\\10000&2000&130000\end{array}\right][/tex]
First we divide the first row by 3000 and the second by 10000:
[tex]\left[\begin{array}{cc|c}1&1/6&37/3\\1&1/5&13\end{array}\right][/tex]
Then we multiply the second row by (-1) and we add the first row:
[tex]\left[\begin{array}{cc|c}1&1/6&37/3\\0&-1/30&-2/3\end{array}\right][/tex]
Now we multiply the second row by -30:
[tex]\left[\begin{array}{cc|c}1&1/6&37/3\\0&1&20\end{array}\right][/tex]
Finally, to the first row we add the second one multiply by (-1/6):
[tex]\left[\begin{array}{cc|c}1&0&9\\0&1&20\end{array}\right][/tex]
So, x = 9 and y = 20
That means 9 TV and 20 radio ads will contact 130,000 voters using the allocated funds
Find the general solution for the following homogeneous equations. PLEASE SHOW SOLUTIONS
1) (xy+y2)dx−x2dy=0 (hint: let u=y/x, so y=ux, dy=xdu+udx))
2) 2x2ydx=(3x3+y3)dy. (hint: let v=x/y, so x=vy, dx=vdy+ydv)
Follow the hints.
1. Let [tex]u=\dfrac yx[/tex], so that [tex]y=ux[/tex] and [tex]\mathrm dy=x,\mathrm du+u\,\mathrm dx[/tex]. Substituting into
[tex](xy+y^2)\,\mathrm dx-x^2\,\mathrm dy=0[/tex]
gives
[tex](ux^2+u^2x^2)\,\mathrm dx-x^2(x\,\mathrm du+u\,\mathrm dx)=0[/tex]
[tex]u^2x^2\,\mathrm dx-x^3\,\mathrm du=0[/tex]
and the remaining ODE is separable:
[tex]x^3\,\mathrm du=u^2x^2\,\mathrm dx\implies\dfrac{\mathrm du}{u^2}=\dfrac{\mathrm dx}x[/tex]
Integrate both sides to get
[tex]-\dfrac1u=\ln|x|+C[/tex]
[tex]-\dfrac xy=\ln|x|+C[/tex]
[tex]\boxed{y=\dfrac x{Cx-\ln|x|}}[/tex]
2. [tex]Let [tex]v=\dfrac xy[/tex], so that [tex]x=vy[/tex] and [tex]\mathrm dx=v\,\mathrm dy+y\,\mathrm dv[/tex]. Then
[tex]2x^2y\,\mathrm dx=(3x^3+y^3)\,\mathrm dy[/tex]
becomes
[tex]2v^2y^3(v\,\mathrm dy+y\,\mathrm dv)=(3v^3y^3+y^3)\,\mathrm dy[/tex]
[tex]2v^3y^3\,\mathrm dy+2v^2y^4\,\mathrm dv=(3v^3y^3+y^3)\,\mathrm dy[/tex]
[tex]2v^2y^4\,\mathrm dv=(v^3y^3+y^3)\,\mathrm dy[/tex]
which is separable as
[tex]\dfrac{2v^2}{v^3+1}\,\mathrm dv=\dfrac{\mathrm dy}y[/tex]
Integrating both sides gives
[tex]\dfrac23\ln|v^3+1|=\ln|y|+C[/tex]
[tex]\ln|v^3+1|=\dfrac32\ln|y|+C[/tex]
[tex]v^3+1=Cy^{3/2}[/tex]
[tex]v=\sqrt[3]{Cy^{3/2}-1}[/tex]
[tex]\dfrac xy=\sqrt[3]{Cy^{3/2}-1}[/tex]
[tex]\boxed{x=y\sqrt[3]{Cy^{3/2}-1}}[/tex]
For a certain candy, 20% of the pieces are yellow, 15% are red, 20% are blue, 20% are green, and the rest are brown. a) If you pick a piece at random, what is the probability that it is brown? it is yellow or blue? it is not green? it is striped? b) Assume you have an infinite supply of these candy pieces from which to draw. If you pick three pieces in a row, what is the probability that they are all brown? the third one is the first one that is red? none are yellow? at least one is green?
Answer:
Step-by-step explanation:
Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).
Brown: [tex]\frac{25}{100}[/tex]Yellow or Blue: [tex]\frac{20}{100} +\frac{20}{100} = \frac{40}{100}[/tex] ....add the numeratorsNot Green: [tex]\frac{80}{100}[/tex].... since the sum of all the rest is 80%Stiped: [tex]\frac{25}{100}[/tex] .... there are 0 striped candies.Assuming the ratios/percentages of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.
3 Browns: [tex]\frac{25*25*25}{100*100*100} = \frac{15,625}{1,000,000} = \frac{1.5625}{100}[/tex]the 1st and 3rd are red while the middle is any. We multiply 15% * (total of all minus red which is 85%) * 15% like so.[tex]\frac{15*85*15}{100*100*100} = \frac{19,125}{1,000,000} = \frac{1.9125}{100}[/tex]
None are Yellow: multiply the percent of all minus yellow three times.[tex]\frac{80*80*80}{100*100*100} = \frac{512,000}{1,000,000} = \frac{51.2}{100}[/tex]
At least 1 green: multiply the percent of green by 100% twice, since the other two can by any[tex]\frac{20*100*100}{100*100*100} = \frac{200,000}{1,000,000} = \frac{20}{100}[/tex]
Find the point on the terminal side of θ = -3π / 4 that has an x coordinate of -1. Show work
Answer:
(-1, -1)
Step-by-step explanation:
One way to write the relationship between the x and y coordinates and θ is ...
tan(θ) = y/x
Then ...
y = x·tan(θ) = -1·tan(-3π/4) = -1·1
y = -1
The coordinates of the point on the terminal side are (x, y) = (-1, -1).
A Bernoulli random variable X has unknown success probability p. Using 100 independent samples of X, find a confidence interval estimate of p with confidence coefficient 0.99. If ????????100 = 0.06, what is our interval estimate
Answer: [tex](0.0445,\ 0.0755)[/tex]
Step-by-step explanation:
The confidence interval for the population proportion is given by :-
[tex]p\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}[/tex]
Given : A Bernoulli random variable X has unknown success probability p.
Sample size : [tex]n=100[/tex]
Unknown success probability : [tex]p=0.06[/tex]
Significance level : [tex]\alpha=1-0.99=0.01[/tex]
Critical value : [tex]z_{\alpha/2}=2.576[/tex]
Now, the 99% confidence interval for true proportion will be :-
[tex]0.06\pm(2.576)\sqrt{\dfrac{0.06(0.06)}{100}}\\\\\approx0.06\pm(0.0155)\\\\=(0.06-0.0155,\ 0.06+0.0155)\\\\=(0.0445,\ 0.0755)[/tex]
Hence, the 99% confidence interval for true proportion= [tex](0.0445,\ 0.0755)[/tex]
A test of H0: μ = 20 versus Ha: μ > 20 will be based on a random sample of size n from a normal population distribution. What conclusion is appropriate in each of the following situations? (Round your P-values to three decimal places.) (a) z = 3.3, α = 0.05
Answer:
We will accept the null hypothesis
Step-by-step explanation:
Given :[tex]H_0: \mu= 20[/tex]
[tex]H_a: \mu> 20[/tex]
To Find : What conclusion is appropriate in each of the following situations?
Solution :
z = 3.3, α = 0.05
So, first we will find the p value corresponding to z value in the z table
So, p-value is 0.999
Since p value is greater than Alpha
0.999>0.05
So, we will accept the null hypothesis
So, the population mean is 20
Country Workshop manufactures both
finished and unfinished furniture for the home . The
estimated quantities demanded each week of its roll top desks in
the finished and unfinished versions are x and y units when
the corresponding unit prices are
p=200−15x−110y
q=160−110x−14y
dollars, respectively. What is the weekly total revenue function R(x, y)?
Answer:
The weekly total revenue function is [tex]R(x,y)=200x-15x^2-220xy+160y-14y^2[/tex].
Step-by-step explanation:
Let the estimated quantities demanded each week of its roll top desks in
the finished and unfinished versions are x and y units respectively.
The unit price of finished furniture is
[tex]p=200-15x-110y[/tex]
The unit price of unfinished furniture is
[tex]q=160-110x-14y[/tex]
Total weekly revenue function is
[tex]R(x,y)=px+qy[/tex]
[tex]R(x,y)=(200-15x-110y)x+(160-110x-14y)y[/tex]
[tex]R(x,y)=200x-15x^2-110xy+160y-110xy-14y^2[/tex]
Combine like terms.
[tex]R(x,y)=200x-15x^2+(-110xy-110xy)+160y-14y^2[/tex]
[tex]R(x,y)=200x-15x^2-220xy+160y-14y^2[/tex]
Therefore the weekly total revenue function is [tex]R(x,y)=200x-15x^2-220xy+160y-14y^2[/tex].
Final answer:
The Weekly Total Revenue Function R(x, y) for Country Workshop's finished and unfinished roll top desks is found by multiplying their demand quantities by their respective unit prices, resulting in R(x, y) = -15x² - 220xy - 14y² + 200x + 160y.
Explanation:
The question asks us to find the weekly total revenue function R(x, y) for Country Workshop, which manufactures both finished and unfinished roll top desks with estimated weekly demands represented by x for finished and y for unfinished versions. The unit prices are given as p=200-15x-110y and q=160-110x-14y dollars, respectively. To calculate the total revenue, we multiply the price of each version by its quantity demanded and sum these values.
Total Revenue Calculation
To find the total revenue, R(x, y), we use the formula: R(x, y) = px + qy. By substituting the given price functions, we get:
R(x, y) = (200-15x-110y)x + (160-110x-14y)yR(x, y) = 200x - 15x² - 110xy + 160y - 110xy - 14y²R(x, y) = -15x² - 220xy - 14y² + 200x + 160yThis equation represents the weekly total revenue based on the quantities demanded of both the finished and unfinished roll top desks.
Which statement best explains whether Y equals 4 x+ 8 is a linear function or nonlinear function?
Answer:
C) It is a linear function because the graph contains the points (0, 8), (1, 12), (2, 16), which are on a straight line.
Explanation:
The missing options for this question are:
A) It is a linear function because the graph contains the points (8, 0), (12, 1), (16, 2), which are on a straight line.
B) It is a nonlinear function because the graph contains the points (8, 0), (12, 1), (16, 2), which are not on a straight line.
C) It is a linear function because the graph contains the points (0, 8), (1, 12), (2, 16), which are on a straight line.
D) It is a nonlinear function because the graph contains the points (0, 8), (1, 12), (2, 16), which are not on a straight line.
The given equation is:
y = 4x + 8
Replacing x by 0, we get y = 8. This means point (0, 8) lies on the graph of the function.
Replacing x by 1, we get y = 12. This means point (1, 12) lies on the graph of the function.
Replacing x by 2, we get y = 16. This means point (2, 16) lies on the graph of the function.
If we plot these three points on a graph we can draw a straight line through these. Hence, based on this we can conclude that:
C) It is a linear function because the graph contains the points (0, 8), (1, 12), (2, 16), which are on a straight line.
The line passing through these 3 points would actually be the given equation y = 4x + 8 as one and only one line can pass through 3 distinct points.