In a class hierarchy A. The more general classes are toward the bottom of the tree and the more specialized are toward the top B. The more general classes are toward the top of the tree and the more specialized are toward the bottom C. The more general classes are toward the left of the tree and the more specialized are toward the right D. The more general classes are toward the right of the tree and the more specialized are toward the left

First language : JAVA

Second Language : C++

Major Difference :

1. Platform Dependency :

Java is platform independent which means that its code can be run on any machine. It uses JVM ( Java virtual machine ) which converts the code in byte form and then run it which makes it flexible enough to be used on any system. So .exe file can run on any OS.

C++ is not platform independent and thus its .exe file  cannot be run on different OS.

2. Objects

In JAVA everything is reference typed and is inherited from the class objects that are predefined in it.

In C++ not everything is class or reference typed.

3. Garbage Collector

Java has built in garbage collector when we use classes in java.

C++ make developer to collect garbage when he uses reference types like pointers.

Why choose Java and C++ ?

People are very confused about the platform in-dependency of JAVA, so i decided to choose Java and compared that concept with c++ which is mother of all languages.

// reading the value in response variable

cout<<"Enter the value :";

cin>>response;

// checking the value and printing the results

if(response == 'y' || response == 'Y')

{

yesCount+=1;

cout<<"YES WAS RECORDED";

}else if(response == 'n' || response == 'N')

{

noCount+=1;

cout<<"NO WAS RECORDED";

}else

cout<<INVALID";

Final answer:

To record yes or no responses, the code reads a char input, then increments corresponding counters based on the input value, and prints out a message. The counters maintain a count and total of the responses.

Explanation:

To handle the described scenario in a programming task, we would need to write a code block that checks the value of the char variable named response and, based on its value, increments either yesCount or noCount. Let's assume we're working with a language like Java, the following code snippet would achieve the desired functionality:

Scanner scanner = new Scanner(System.in);
char response = scanner.next().charAt(0);
if (response == 'y' || response == 'Y') {
   yesCount++;
   System.out.println("YES WAS RECORDED");
} else if (response == 'n' || response == 'N') {
   noCount++;
   System.out.println("NO WAS RECORDED");
} else {
   System.out.println("INVALID");
}

The code starts by waiting for the user to input a character. If the character is 'y' or 'Y', yesCount is incremented and a message is printed out. Similarly, if the character is 'n' or 'N', noCount is incremented and a corresponding message is issued. If the input is neither of these, the input is deemed invalid and an "INVALID" message is printed. This process helps in maintaining a count and total of the 'yes' and 'no' responses.

// Variable to keep track of array size

int length = 0;

// Array itself

int array[] = {};

// while loop will take input in the array until a negative number is entered

while(input>=0){

stdin = new Scanner(System.in);

array[length] = stdin;

length +=1;

}

// int variable to terminate while loop

int i =0;

// keep track of index of output array

int y =0;

while(arr[i] != length){

// making output array

int output[]={}; bool flag;

// put the element in out put array considering if it the desired one

output[y] = array [i];

// Now check if it was the desired?

for(int z=1;z<=length;z++){

if(array[i+z]!=output[y]){

 flag = true;

}

else

{

 output[y]=0;

 y+=1;

}

if(array[i+z+1]=output[y] && flag == true){

output[y] = array[i];

y+=1;

}

}

//output the array

for(int o=0;o<y;o++)

System.out.println(output[o];

To solve this problem, use a loop to read the sequence of non-negative integers terminated by a negative number. Compare each number with the previous number and increment a counter if they are the same. Print the value of the counter representing the number of consecutive duplicates encountered.

To solve this problem, we can use a loop to read the sequence of non-negative integers terminated by a negative number. We can keep track of the consecutive duplicates encountered by comparing each number with the previous number. If they are the same, we increment a counter. If they are different, we continue with the next number. Finally, we print the value of the counter, which represents the number of consecutive duplicates encountered.

Answer:

Scanner stdlin = new Scanner(System.in);

line1 = stdlin.readline();

Explanation:

1.stdlin is the referenced input variable made by using built in Scanner class of Java language.

2.Than in line1 the next line from the console will be assigned by using readline function.

Answer: autocomplete

Explanation:

autocomplete is a feature of the search engine whereby it it able to complete sentences we type based on our browsing or surfing experiences. It has a database that store all related words and phrases people use and when we type any words it provides us hints in respect of what we type next.

Option C is not correct because in file system there is problem of using same data at different place with old and new updated versions and thus change in the data on one file is not reflected on the other related files implicitly rather we will have to change the data in each file manually which is indeed not easy task. In fact that is one of the biggest drawback of file system.

Option A is correct because the files of different data has separate definitions of the topics they are about.

Option B is correct because has no reversibility and thus same data can be present on different files.

Option D is correct because because of no reversibility the files can have same records with new or old versions

Answer:

Basic

Explanation:

The 3rd generation programming language that most students learned when most computers used MS DOS was basic. It remains a safe programming language for using 3rd party code and provides a coding standard that integrates easily with other programming languages.

The 3rd generation programming language widely learned during the dominance of MS-DOS was C. It remains a popular language due to its safety in using third-party code and its compatibility with other languages.

The 3rd generation programming language that most students learned when most computers used MS-DOS was C. C language remains a safe programming language for using third-party code and provides a coding standard that integrates easily with other programming languages. This language is widely recognized for its efficiency and control. It's also notable for its capability to produce programs that are more compact and run faster than those written in other languages.

Learn more about Programming Languages here:

https://brainly.com/question/32924876

#SPJ2

Answer: Router

Explanation:

Explanation & answer:

We do not know which language you are using, so a pseudocode will be given, it will be similar to java or C/C++.  For other languages, you can adapt to the syntax of the target language.

int n=5;

//

total = 0  // initialize  variable to store total value, already declaired.

// k will be used as a dummy variable, already declared

for (k=1; k<=n; k++){

   total+=k*k*k;  // k*k*k works for almost all languages.  adapt as needed

   }

print(n, total)

Answer:

A: Competent Person

Explanation:

An OSHA “competent person”, by way of training and/or experience, has knowledge of applicable standards and authority to stop work deemed hazardous or that may cause harm to an employee. He/she has the authority, given from above, to correct workplace hazards. Such authority sets OSHA’S competent person apart from OSHA’S qualified person.

// i am writing c++ code for the given problem...

// taking input

cout<< " Enter the name : ;

cin>>name;

// printing the message

cout << " Greetings, " << name << endl;

Final answer:

Pete should set the quality parameter of the video to 'high' in Adobe Flash Player to prioritize display quality over playback speed.

Explanation:

Pete is designing a web page and wants to use Adobe Flash Player to play videos with a focus on display quality over playback speed. To achieve this, Pete should set the quality parameter of the video to 'high'. When the quality parameter is set to high, it ensures that the video will be displayed with the best quality possible, even if this means that the video might buffer or play back with less speed on slower internet connections or less capable devices. This setting prioritizes the visual experience for users who want to see the clothing lines with the highest image clarity and detail.

Answer: audience relevance

Explanation:

Most importantly when stating a thesis we should show and present how the work in the thesis is relevant to the audience. In this way we would be able to connect our research work more to the people and the audience. We should be able to state how our work is going to benefit them, what the people should do in this regard and all the dos and don't must be mentioned clearly while stating our thesis.

//Making a variable bool to save answer

bool recalled = false;

//Making the modelyear variable

int modelYear = 0;

//taking input from user

Scanner input = new Scanner(System.in);

modelYear = input.nextInt();

//check statement to see if the input is in range

if((modelYear >=1995 && modelYear <=1998) || (modelYear <=2004 && modelYear <=2006 )

{

recalled = true;

}else{

recalled = false ;

}

Answer:

Explanation:

data is a statement like

data 10,20, 30 , 40 , 50, 60 , 70, 80

\\the numbers represent ages.

For x := 1 to end of data do a[x]:=read(data)

\\ This is a comment. You could do this much easier if you just use three if statements rather than the if then else.

minor:=0;adult:=0;senior:=0;

while a[x] <> 0 do begin

age:= a[x]

if age < 19 then minor:=minor + 1;

If age > 18 then if age < 65 the adult:=adult + 1;

if age > 64 then senior := senior + 1;

end;

I have not declared the variables anywhere. That depends on what language you are using. The key step you  want are the three if statements. How you find out what's in them is another matter.

Answer:

Enables the users to get details ,and details if details ,of information.

Explanation:

Drill - Down Capability is the capability that lets user to see more information by pointing and clicking on the specific element.For example - a report that displays literacy rate by state can allow the user to select a state and by clicking on it and user can see the literacy rate by county or city within that state.

Hence we conclude that option d is the correct answer that is  

Answer:

You

Tube is the most popular.

Answer: This Information Security Handbook assist and guide managers to establish and implement an information security program.

Explanation:

The handbook looks to implement adequate security programs and also to demonstrate their effectiveness.

a) True, The NIST SP 800-100 Information Security Handbook provides technical guidance for the establishment and implementation of an information security program.

This handbook is published by the National Institute of Standards and Technology (NIST). Offers comprehensive advice and strategies on:

Provides detailed recommendations on:

The NIST SP 800-100 Information Security Handbook provides technical guidance for the establishment and implementation of an information security program.

a) True

b) False

Answer:

Option A

Explanation:

Option B is rejected because it is used to get the startup network settings, processes extra features used by the network.

Option C is rejected because it is used to check the stats like ping,fps of the network by using a loop back.

Option A is selected because PING command is used to check the data packets transfer rate between two ends using ICMP protocol. Local host means that you are specifying the one end as your side. If the packets are there then it is working else the IP service is down.

I'm going to assume this is Java, because you said "method" meaning it will be some sort of object oriented language, and Java's really common. Here would be the full program, but you can just take the method out isolated if you need it.

package lastname;

public class LastName {

   public static void main(String[] args) {

       // Example usage:

       String name = LastName.lastName("Garrett Acord");

       System.out.println(name);

       // Output: Acord G.

   }

   public static String lastName(String fullName)

   {

       String[] splitName = fullName.split(" ");

       return String.format("%s %s.", splitName[1], splitName[0].substring(0,1) );

   }

}

Final answer:

The method 'lastFirst' takes a full name as input and returns a string with the last name, followed by the first initial and a period. This can be implemented in a programming language like Java, and calling 'lastFirst("Marla Singer")' will return 'Singer, M.'.

Explanation:

The method lastFirst is designed to take a string input representing a person's first and last name, and return a formatted string with the last name followed by a comma, a space, the first initial of the first name, and a period. Here is how you could implement the method in Java:

public String lastFirst(String fullName) {
   int spaceIndex = fullName.indexOf(" ");
   String firstName = fullName.substring(0, spaceIndex);
   String lastName = fullName.substring(spaceIndex + 1);
   return lastName + ", " + firstName.charAt(0) + ".";
}

For example, when you call lastFirst("Marla Singer"), the method will return "Singer, M."

Answer:

C. Office Clipboard

Explanation:

An Office Clipboard is a type of slide show that is a dynamic and eye-catching way to familiarize potential customers with what your company has to offer.

Answer:

A:Photo album

Explanation:

Organizing photos into a slide show is an effective technique for a business to showcase its products and services. Rather than a static brochure, a slide show is a dynamic and eye-catching way to familiarize potential customers with what your company has to offer. Photo album slide shows can be presented at a conference booth, online, or distributed through email.

Answer:

The loop for the given scenario is shown.

while( num >= 0 )

   {

          if( num%2 == 0 )

       {

           sum_even = sum_even + num;

           count_even = count_even + 1;

       }

       else

       {

           sum_odd = sum_odd + num;

           count_odd = count_odd + 1;

       }

      cout << "Enter a positive number." << endl;

       cin >> num;

   }

Explanation:

The program uses three variables to hold the user input, sum and count of even numbers and odd numbers.

int sum_even, sum_odd, count_even, count_odd, num;

The sum variables are initialized.

   sum_even = 0;

   sum_odd = 0;

   count_even = 0;

   count_odd = 0;

Only positive input from the user needs to be considered as per the question, hence, while loop is used.

This loop will execute only if the user inputs valid number. Upon entering the negative number which is less than 0, the loop terminates.

Following this, the sum and count of even numbers is displayed followed by the sum of negative numbers.

cout << sum_even << " " << sum_odd << " " << count_even << " " << count_odd << endl;

The c++ program for the given problem statement is as follows.

#include <iostream>

using namespace std;    

int main()  

{      

   // variables declared for sum and input

   int sum_even, sum_odd, count_even, count_odd, num;    

   // sum initialized to 0

   sum_even = 0;

   sum_odd = 0;

   count_even = 0;

   count_odd = 0;

   cout << "This program calculates the sum and count of even and odd numbers which are positive. This program will end on invalid input." << endl;

   cout << "Enter a positive number." << endl;

   cin >> num;    

   // loop will terminate if the user inputs negative number

   while( num >= 0 )

   {

       // for even numbers, input is added to sum_even else sum_odd

       if( num%2 == 0 )

       {

           sum_even = sum_even + num;

           count_even = count_even + 1;

       }

       else

       {

           sum_odd = sum_odd + num;

           count_odd = count_odd + 1;

       }            

       cout << "Enter a positive number." << endl;

       cin >> num;

   }    

   cout << sum_even << " " << sum_odd << " " << count_even << " " << count_odd << endl;    

   return 0;    

}

OUTPUT

This program calculates the sum of even and odd numbers which are positive. This program will end on invalid input.            

Enter a positive number.                                                                                                        

23                                                                                                                              

Enter a positive number.                                                                                                        

56                                                                                                                              

Enter a positive number.                                                                                                        

78                                                                                                                              

Enter a positive number.                                                                                                        

91                                                                                                                              

Enter a positive number.                                                                                                        

-4                                                                                                                              

134 114 2 2

To accomplish the student's task, we can use a while loop to continuously read integers and accumulate sums/counters for even and odd numbers, terminating the loop when a non-positive integer is encountered. The resulting sums and counts are then printed out.

To write a loop that reads positive integers from standard input and terminates when a non-positive integer is read, we can use a while loop in a programming language such as Python. Below is an example of how this could be achieved:

sum_even = 0
sum_odd = 0
count_even = 0
count_odd = 0

while True:
   number = int(input("Enter a positive integer (or a non-positive integer to quit): "))
   if number \<= 0:
       break
   if number % 2 == 0:
       sum_even += number
count_even += 1
   else:
       sum_odd += number
count_odd += 1

print(sum_even, sum_odd, count_even, count_odd)

In this code, we initialize the variables sum_even and sum_odd to keep track of the total sum of even and odd numbers respectively. Similarly, count_even and count_odd are used to keep a count of even and odd numbers. The while loop continues to prompt the user for a number and checks if it is even or odd, updating the sums and counts accordingly. The loop breaks when a non-positive number is entered, after which it prints the sum of even numbers, the sum of odd numbers, the count of even numbers, and the count of odd numbers, all separated by spaces.

// Here is the required switch statement on response character

switch(response){

case 'y': // case to check if the response is y

cout<<" Your request is being processed ";

case 'n': // case to check for n

cout<<" Than you, anyway for your consideration";

case 'h': // case to check for h

cout<<"Sorry \, no help is currently available.";

default : // default case

cout<< Invalid entry: please try again.";

}

Answer:

1.Communication Management

2.Information Management

Explanation:

NIMS has introduced COMMUNICATION management system that determines if the decision makers has the ways to communicate decisions. It has standards that defines the ways that can be used by the personnel to communicate the decisions in a better and efficient manner.

NIMS has also a system which is primarily introduced to check the the personnel has the information to make and communicate decisions called Information management. Again, it also has the templates that defines that how information should be spread considering the confidentiality of the information.

Communications and Information Management is the major NIMS (National Incident Management System) Component that describes systems and methods ensuring that incident personnel and other decision-makers have the means.

Who: Incident personnel and decision-makers involved in managing an emergency or disaster situation.

What: Communications and Information Management deals with the systems, tools, and methodologies used to gather, organize, manage, and disseminate information effectively. This ensures that all participants have access to the accurate and timely information required to make informed decisions and coordinate efforts.

When: Effective communication and information management need to be in place at every stage of an incident, from the initial response through to recovery. This helps in maintaining a coordinated and efficient response effort throughout the incident.

Where: These systems and methods are applied wherever an incident or emergency situation occurs. This can include local, state, and national levels, and sometimes even international scenarios, depending on the nature and scope of the incident.

Why: The primary purpose of this component is to ensure seamless information flow among incident personnel, helping to support decision-making processes and enhance overall incident management. This ultimately leads to a more efficient and effective response and recovery effort.

How: Communications and Information Management involves using various tools and technologies, such as incident command systems, public information systems, alert and warning systems, and interoperable communication systems. These tools help ensure that critical information is shared accurately and timely among all relevant stakeholders.

Answer:

American engineer Elijah McCoy was born in Canada but became US citizen very young, and and made vital contributions in the United States after the Civil War such as in the progress of locomotives design and railroads in America, the automatic lubrication systems for steem engines and many other inventions among his 57 U.S. patents that made train travel more efficient.

Explanation:

Answer:

The c++ program using for loop is given below.

#include <iostream>

using namespace std;

int main() {

   int sq, i;    

   cout<<"Integer"<<"\t"<<"Square"<<endl;    

   for(i=200;i>=50;i=i-10)

   {

       cout<<i<<"\t"<<"\t";

       sq=i*i;

       cout<<sq<<endl;

   }

   return 0;    

}

The c++ program using do-while loop is given below.

#include <iostream>

using namespace std;

int main() {

   int sq, i=200;    

   cout<<"Integer"<<"\t"<<"Square"<<endl;    

   do

   {

       cout<<i<<"\t"<<"\t";

       sq=i*i;

       cout<<sq<<endl;

       i=i-10;

   }while(i>=50);    

   return 0;

}

The c++ program using while loop is given below.

#include <iostream>

using namespace std;

int main() {

   int sq, i=200;    

   cout<<"Integer"<<"\t"<<"Square"<<endl;    

   while(i>=50)

   {

       cout<<i<<"\t"<<"\t";

       sq=i*i;

       cout<<sq<<endl;

       i=i-10;

   }    

   return 0;

}

OUTPUT

Integer  Square

200  40000

190  36100

180  32400

170  28900

160  25600

150  22500

140  19600

130  16900

120  14400

110  12100

100  10000

90  8100

80  6400

70  4900

60  3600

50  2500

Explanation:

The integer variables sq and i are declared to hold the square and the integer respectively. The square of an integer is also a square hence, it is also declared as integer and not float.

The variable i is initialized to 200 as required by the question. All the three loops continue till value of i reaches 50. Once, the value goes below 50, loop is discontinued.

In for loop initialization, condition and decrement, all are done simultaneously.

for(i=200;i>=50;i=i-10)

In do-while and while loops, variable declaration and initialization are done simultaneously. The condition and decrement logic is contained within the loop.

This loop executes once irrespective whether the condition is satisfied or not. From the second execution onwards, the condition is taken into account.

   do

   {

       cout<<i<<"\t"<<"\t";

       sq=i*i;

       cout<<sq<<endl;

       i=i-10;

   }while(i>=50);    

The while loop is similar to do-while loop except that the while loop executes only if the condition is satisfied.

The output for all the three loops is the same hence, output is shown only once.

Answer:

C. External Data

Explanation:

On the External Data tab, you can find import and export commands located in Access.

Option A because the environment should be selected for which the changes are to be applied. In a time Force IDE has many project environments for example maybe a java project and C++ project would be there on sandbox, so the environment selection is important.

Option B because the related changed sets should be specified so that other developers that have access to the project can see the changes being made.

Option D The data fields that are needed to be deployed should also be provided so that the updated version can be seen by other developers.

Rejected Options :

Option C user name and password has nothing to do with the production environment because if the user has it only then it can come and make changes.

Answer:

Router device

Explanation:

whenever there is need to connect two networks with different IP addresses over the internet, they are connected by routers which has the ability to define these networks uniquely over the internet.

What are the following advertising methods?