Answer:
0.01 rad
Explanation:
For a double-slit experiment, we have that dsinθ = nλ. The separation between the central maximum and an adjacent maximum is when n = 1
dsinθ = λ
The angular separation θ = sin⁻¹(λ/d)
now d = 100λ
θ = sin⁻¹(λ/100λ) = sin⁻¹(0.01) = 0.573°
θ = 0.573° × π/180 = 0.01 rad
Two balls collide with each other. Ball 1 experiences a high acceleration as a result of the collision, while Ball 2 experiences a small acceleration. What can you conclude about Ball 2?
Answer:
We conclude that ball 2 has a larger mass.
Explanation:
This is because the internal forces at collision are an action reaction pair. The force on ball 1 due to ball 2 equals the force on ball 2 due to ball 1. Since these forces are equal in magnitude, let's denote it by F. So
For each ball, F = ma and a = F/m. Since F is the same for both balls, if follows that the acceleration of each ball is inversely proportional to its mass. That is, a ∝ 1/m.
Since ball 1 has a higher acceleration, it has a lower mass. Also ball 2 has a small acceleration, so it has a higher mass.
Answer:
See explanation
Explanation:
Solution:-
- Denote the following:
mass of ball 1 = m1
initial velocity of ball 1 = vi,1
Final velocity of ball 1 = vf,1
mass of ball 2 = m2
initial velocity of ball 2 = vi,2
Final velocity of ball 2 = vf,2
- Since there are no external forces acting on the system containing the two balls then we can say that the linear momentum of the system is conserved.
- The conservation of linear momentum says that the momentum before or after the collision remains conserved:
Pi = Pf
Where, p = m*v
- The conservation of momentum for the given system:
m1*vi,1 + m2*vi,2 = m1*vi,1 + m2*vi,2
- Since no information is given about the initial conditions. We will consider the internal force (F) that acts when two balls come in contact. Then apply Newton's second law of motion on both balls individually:
F = m*a
Where, m: Mass of object
a: Acceleration of the object
- For ball 1:
F1 = m1*a1
- For ball 2:
F2 = m2*a2
Given that a1 > a2, and the the internal force that acts on both balls during collision obeys Newton's 3rd Law i.e for every action there is an equal but opposite reaction: So , F1 = F2
F = m1*a1
F = m2*a2
m1*a1 = m2*a2
- Since, a1 > a2 for above equation to hold true then m1 < m2. That is the mass of ball 1 is quite less compared to ball 2.
1. In the picture below, energy is being converted to heat water. What type of energy transformations take place in this model?
Kinetic energy is formed when water is heated.
Explanation:
Suppose in an electric kettle there is water , when water is boiled the electrical energy changes into thermal energy when heating is done.The thermal energy then gets transferred to the water . When the boiling takes place in the water the energy gets transformed into sound. Lastly at the end the gravitational potential energy finally changes to the kinetic energy.There are three types of energy transformations taking place
(i) conversion of kinetic energy to rotational energy
(ii) conversion of rotation energy to electrical energy
(iii) conversion of electrical energy to heat energy
As seen in the image attached, there is running water that is falling on the blades of a small turbine and makes it rotate. The turbine is connected to the heating system with wires.
Now, the energy transformations that take place in heating water are described as follows:
The flowing tap water is falling on the blades of the turbine which produces torque and makes the blade rotate. Hence, the kinetic energy of the tap water is converted into rotational energy.Now the turbine is connected to the heating system with wire, which means it must produce electricity. Here, The rotation energy is converted into electrical energy. Lastly, the electrical energy produced by the turbine is being converted into heat energy by the heating system to warm water.Learn more:
https://brainly.com/question/19305456?referrer=searchResults
A spring (k=15.19kN/m)is is compresses 25cm and held in place on a 36.87° incline. A block (M=10kg) is placed on the spring. When the spring is released the block slides up and off the end of the ramp. The block travels 1.12m along the ramp where the co efficient of kinetic friction is 0.300. Determine the maximum vertical displacement of the block after it becomes airborne relative to it's initial position on the spring
Answer:
The maximum vertical displacement is 2.07 meters.
Explanation:
We can solve this problem using energy. Since there is a frictional force acting on the block, we need to consider the work done by this force. So, the initial potential energy stored in the spring is transferred to the block and it starts to move upwards. Let's name the point at which the block leaves the ramp "1" and the highest point of its trajectory in the air "2". Then, we can say that:
[tex]E_0=E_1\\\\U_e_0=K_1+U_g_1+W_f_1[/tex]
Where [tex]U_e_0[/tex] is the elastic potential energy stored in the spring, [tex]K_1[/tex] is the kinetic energy of the block at point 1, [tex]U_g_1[/tex] is the gravitational potential energy of the block at point 1, and [tex]W_f_1[/tex] is the work done by friction at point 1.
Now, rearranging the equation we obtain:
[tex]\frac{1}{2}kx^{2}=\frac{1}{2}mv_1^{2}+mgh_1+\mu Ns_1[/tex]
Where [tex]k[/tex] is the spring constant, [tex]x[/tex] is the compression of the spring, [tex]m[/tex] is the mass of the block, [tex]v_1[/tex] is the speed at point 1, [tex]g[/tex] is the acceleration due to gravity, [tex]h_1[/tex] is the vertical height of the block at point 1, [tex]\mu[/tex] is the coefficient of kinetic friction, [tex]N[/tex] is the magnitude of the normal force and [tex]s_1[/tex] is the displacement of the block along the ramp to point 1.
Since the force is in an inclined plane, the normal force is equal to:
[tex]N=mg\cos\theta[/tex]
Where [tex]\theta[/tex] is the angle of the ramp.
We can find the height [tex]h_1[/tex] using trigonometry:
[tex]h_1=s_1\sin\theta[/tex]
Then, our equation becomes:
[tex]\frac{1}{2}kx^{2}=\frac{1}{2}mv_1^{2}+mgs_1\sin\theta+\mu mgs_1\cos\theta\\\\\implies v_1=\sqrt{\frac{2(\frac{1}{2}kx^{2}-mgs_1\sin\theta-\mu mgs_1\cos\theta)}{m}}=\sqrt{\frac{kx^{2}}{m}-2gs_1(\sin\theta+\mu \cos\theta)}[/tex]
Plugging in the known values, we get:
[tex]v_1=\sqrt{\frac{(15190N/m)(0.25m)^{2}}{10kg}-2(9.8m/s^{2})(1.12m)(\sin36.87\°+(0.300) \cos36.87\°)}\\\\v_1=8.75m/s[/tex]
Now, we can obtain the height from point 1 to point 2 using the kinematics equations. We care about the vertical axis, so first we calculate the vertical component of the velocity at point 1:
[tex]v_1_y=v_1\sin\theta=(8.75m/s)\sin36.87\°=5.25m/s[/tex]
Now, we have:
[tex]y=\frac{v_1_y^{2}}{2g}\\\\y=\frac{(5.25m/s)^{2}}{2(9.8m/s^{2})}\\\\y=1.40m[/tex]
Finally, the maximum vertical displacement [tex]h_2[/tex] is equal to the height [tex]h_1[/tex] plus the vertical displacement [tex]y[/tex]:
[tex]h_2=h_1+y=s_1\sin\theta +y\\\\h_2=(1.12m)\sin36.87\°+1.40m\\\\h_2=2.07m[/tex]
It means that the maximum vertical displacement of the block after it becomes airborne is 2.07 meters.
"A horizontal loop of wire has a magnetic field passing upward through the plane of the loop. If this magnetic field increases with time, is the direction of the induced current clockwise or counterclockwise (viewed from above) as predicted by Lenz's law?
Answer:
See explanation
Explanation:
If the magnetic field increases up through the loop a current will flow such that the magnetic field from this current will oppose the change in magnetic flux. (As per Lenz's Law)
The magnetic field is increasing up so the field from the current must be directed down.
From the application of right hand rule by pointing the thumb downwards and curl our fingers the current flows clockwise then the magnetic field from this current will be directed downward inside the loop of wire.
According to Lenz's law, the induced current in a horizontal loop of wire with an increasing magnetic field passing upward through it will flow clockwise when viewed from above, as it acts to oppose the change in the magnetic field.
When a horizontal loop of wire has an increasing magnetic field passing upward through it, Lenz's law helps us determine the direction of the induced current in the loop. According to Lenz's law, the induced current will flow in such a way that it creates a magnetic field that opposes the change in magnetic flux. Since the magnetic field through the loop is increasing upwards, the induced current must produce a magnetic field that points downwards.
Applying the right-hand rule, if you orient your right hand with the thumb pointing downwards (opposing the increasing magnetic field), your fingers would curl in a clockwise direction when viewed from above. Therefore, the induced current in the loop will flow in a clockwise direction, as viewed from above, when the magnetic field is increasing through the plane of the loop.
you push a 560 mm radius bicycle wheel, which is approximately hoop shaped, along a flat region until it reaches a speed of 5.01 m/s. It then goes up a smooth hill of irregular shape and height 0.6 m before falling off the vertical face on the opposite side.
What is its speed at the top of the hill?
Answer:
The speed at the top of the hill is 4.38 m/s
Explanation:
Here we have total Kinetic = KE (translational) +KE (rotational)
=0.5 m v² + 0.5m·r²v²/r² = m·v²
Therefore at height 0.6 m we have
0.6 mg = mv²
When v = 5.01 m/s maximum height is
m·g·h=m·5.01²
or h = 2.56 m
Therefore at 0.6 m we have 2.56 - 0.6 more height energy to climb
which gives
1.96·m·g = m v₂²
or v₂² = 19.22
v₂ = 4.38 m/s.
Which features do sound waves have the ocean and light waves do not
Sound waves spread out and bend around corners, while light waves behave like rays and do not bend around corners.
Explanation:The difference between sound waves and light waves when passing through an opening is that light waves behave like rays and do not bend around corners, while sound waves spread out and bend around corners due to their longer wavelengths.
Light waves have very short wavelengths, which allows them to act like rays and create sharp shadows when passing through openings. On the other hand, sound waves have longer wavelengths, on the order of the size of the opening, and can bend around corners.
For example, when light shines through an open door into a dark room, we expect to see a sharp shadow of the doorway on the floor and no light bending around corners. However, when sound passes through a door, we expect to hear it everywhere in the room, indicating that sound waves spread out and bend around corners.
A particle with mass 1.81×10−3 kgkg and a charge of 1.22×10−8 CC has, at a given instant, a velocity v⃗ =(3.00×104m/s)j^v→=(3.00×104m/s)j^. What are the magnitude and direction of the particle’s acceleration produced by a uniform magnetic field B⃗ =(1.63T)i^+(0.980T)j^B→=(1.63T)i^+(0.980T)j^?
Answer:
-(0.330m/s² ) kˆ
Explanation:
given data:
Mass of particle 'm'= 1.81 x [tex]10^{-3}[/tex] kg
Velocity 'v'= (3.00 x[tex]10^{4}[/tex] m/s)j
Charge of particle 'q'= 1.22 x [tex]10^{-8}[/tex] C
Uniform magnetic field 'B' = (1.63iˆ + 0.980jˆ )T
In order to calculate particle's acceleration, we'll use Newton's second law of motion i.e F=ma
Also,the force a magnetic field exerts on a charge q moving with velocity v is called the magnetic Lorentz force. It is given by:
F = qv × B
F= ma = qV x B
a= [tex]\frac{q(v*B)}{m}[/tex] --->eq(1)
Lets determine the value of (v x B) first
v x B= (3.00 x[tex]10^{4}[/tex] m/s)j x (1.63iˆ + 0.980jˆ )
v x B= 4.89 x [tex]10^{4}[/tex]
Plugging all the required values in eq(1)
a= [1.22 x [tex]10^{-8}[/tex] x (4.89 x [tex]10^{4}[/tex]kˆ)] / 1.81 x [tex]10^{-3}[/tex]
a= -(0.330m/s² ) kˆ
-ve sign is representing the opposite direction
Two quakes of equal measurements on all scales occur in two different areas. In earth quake 1, the damage is severe but in earthquake 2, the damage is minimal. Explain some reasons why this is possible.
Answer:
See explanation
Explanation:
Depth: Earthquakes can happen anywhere from at the surface to 700 kilometers below. In general, deeper earthquakes are less damaging because their energy dissipates before it reaches the surface. So it is highly likely that the earthquake 1 was shallower than earthquake 2.
Distance from the epicenter: The epicenter is the point at the surface right above where the earthquake originates and is usually the place where the earthquake's intensity is the greatest. Plausible that earthquake 1 might have been closer to its epicenter as compared to earthquake 2.
Local geologic conditions: The nature of the ground at the surface of an earthquake can have a profound influence on the level of damage. Loose, sandy, soggy soil, like in Mexico City, can liquefy if the shaking is strong and long enough, for example. That doesn't bode well for any structures on the surface. Plausible that the area around the earthquake 1 might have poorer geologic conditions as compared to area of earthquake 2.
When you swim, your hands apply a force backward on the water. The reaction to this force is________
Explanation:
THERE FORE THE REACTION IS FRICTION FORCE.
THIS MAY HELP YOU...
PLEASE MARK MY ANSWER AS BRAINLIEST...
PLEASE BRO PLEASE
It should be pushing because when you swim you are pushing yourself
Technician A says that in any type of fluid coupling not equipped with a mechanical lock-up some slippage exists resulting in a difference between input and output speeds. Technician B says that in torque converter coupling phase impeller and turbine rpms match. Who is correct
Final answer:
Technician A is correct, as there is slippage between input and output speeds in fluid couplings without a mechanical lock-up. Technician B is incorrect, as the impeller and turbine rpms do not match in a torque converter coupling.
Explanation:
Technician A is correct. In any type of fluid coupling without a mechanical lock-up, there is always some slippage between the input and output speeds. This means that the output speed will be less than the input speed, resulting in a difference between them.
Technician B is incorrect. In a torque converter coupling, the impeller and turbine do not have matching rpm (revolutions per minute). The impeller rpm is higher than the turbine rpm, which allows the torque converter to efficiently transfer power from the engine to the transmission.
A dumbbell-shaped object is composed by two equal masses, m, connected by a rod of negligible mass and length r. If I_1 is the moment of inertia of this object with respect to an axis passing through the center of the rod and perpendicular to it and l_2 is the moment of inertia with respect to an axis passing through one of the masses, it follows that l_1 = l_2. l_l > l_2. l_2 > l_1
Answer:[tex]I_2>I_1[/tex]
Explanation:
Given
Shape of the object is dumbbell shaped
Moment of Inertia w.r.t an axis passing through center and perpendicular to it
[tex]I_1=m(\frac{r}{2})^2+m(\frac{r}{2})^2[/tex]
[tex]I_1=\frac{mr^2}{2}[/tex]
For the axis which passes through one of the masses
[tex]I_2=mr^2[/tex]
so [tex]I_2>I_1[/tex]
The diagram shows a transformer. Based on the diagram the voltage at the second winding is ____ v
Answer:
60V
Explanation:
240V/12 loops = 20 volts per loop.
20 * 3 = 60 volts
Answer:
60V
Explanation:
A typical incandescent light bulb consumes 75 W of power and has a mass of 30 g. You want to save electrical energy by dropping the bulb from a height great enough so that the kinetic energy of the bulb when it reaches the floor will be the same as the energy it took to keep the bulb on for 1.0 hour. From what height should you drop the bulb, assuming no air resistance and constant g?
Answer:
The height will be 917431.2 m.
Explanation:
Power of bulb = 75 W
Time kept on 1 hr = 60 x 60 = 3600 sec
Energy of bulb = power x time
E = 75 x 3600 = 270000 J
From conservation of energy, kinetic energy of the bulb is equal to the potential energy of the bulb due to its height of fall.
Potential energy = m x g x h
Where g = acceleration due to gravity 9.81 m/s2
m = mass = 30 g = 0.03 kg
PE = 0.03 x 9.81 x h = 0.2943h
Equating withe the energy of bulb (still obeying energy conservation)
270000 = 0.2943h
h = 270000/0.2943 = 917431.2 m
The incandescent bulb would have to be dropped from a height of approximately 918,367.35 meters to have its kinetic energy equal to the energy consumed in one hour of use.
To determine from what height you should drop a 75-watt incandescent bulb so that upon reaching the floor, its kinetic energy will equal the energy used to power it for 1.0 hour, we use the formula for gravitational potential energy (PE) and kinetic energy (KE), where PE = mgh and KE = ½ mv². The power consumption of the bulb indicates how much energy it uses per second, so we first calculate the energy consumed in one hour (E = power × time). Since the bulb is 75 watts, and there are 3600 seconds in an hour, it uses 75 W × 3600 s = 270,000 joules in one hour. This is the energy we want the bulb to have as kinetic energy when it hits the ground. To find the height, we set this equal to the potential energy at the start (mgh) and solve for h:
E = mgh
270000 J = (0.03 kg)(9.8 m/s²)(h)
h = 270000 J / (0.03 kg × 9.8 m/s²)
h = 918367.35 m
Thus, the bulb would have to be dropped from a height of approximately 918367.35 meters to have the same energy when it impacts the ground as it uses in one hour of being lit.
what voltage would be required to run a 600-watt motor with a current of 400 amperes
Answer:
Voltage can be calculated in various ways but I am a easier solution to it:
Explanation:
V=I×R instead of this formula I use:
P=I×V
600=400×V
600=400V
Divide both sides by 400
V=3÷2
V=1.5 J/C
1volt=1coulomb or joule
Answer:1.5V
Explanation: power =IV
Where I= current
V= voltage
Therefore Voltage=power/current
V= 600/400= 1.5
What would happen if a person who is wearing a heavy winter jacket were to place a thermometer inside the jacket next to his or her skin? What would happen if we took the same jacket, after it had been hanging in a closet, and placed a thermometer inside?
Answer:
Explained.
Explanation:
Let me explain the two cases in by one.
(1) When Person wearing a jacket, heat from his or her body is going to get trapped inside his or her jacket to keep this person warm when a thermometer is placed inside, it would indicate a higher temperature on the scale.
(2) When Jacket is Hanging in a closet, its temperature would be roughly close to room temperature and when we would place a thermometer it would not indicate any change on its scale.
On classical Hall mobility: In a semiconductor sample, the Hall probe region has a dimension of 0.5 cm by 0.25 cm by 0.05 cm thick. For an applied electric field of 1.0 V/cm, 20 mA current flows (through the long side) in the circuit. When a 10 kG magnetic field is applied, a Hall voltage of 10 mV is developed. What is the Hall mobility of the sample and what is the carrier density
Answer:
hall mobility = 139.8 x 10 ∧3
carrier density = 83.1 x 10 ∧14
Explanation:
The pictures attached below shows the full explanation
A child bounces a 57 g superball on the sidewalk. The velocity change of the superball is from 24 m/s downward to 11 m/s upward. If the contact time with the sidewalk is 1 800 s, what is the magnitude of the average force exerted on the superball by the sidewalk? Answer in units of N.
Correct question:
A child bounces a 57 g superball on the sidewalk. The velocity change of the superball is from 24 m/s downward to 11 m/s upward. If the contact time with the sidewalk is 1/800 s, what is the magnitude of the average force exerted on the superball by the sidewalk? Answer in units of N.
Answer:
The magnitude of the average force exerted on the superball by the sidewalk is 592.8 N
Explanation:
Given;
mass of the superball, m = 57 g = 0.057 kg
initial velocity of the superball, u = 24 m/s
final velocity of the superball, v = 11 m/s
contact time with the sidewalk, t = 1 / 800 s
To determine the magnitude of the average force exerted on the superball by the sidewalk, we apply Newton's second law of motion;
F = ma
[tex]But, a = \frac{v-u}{t} \\\\Thus, F = m(\frac{v-u}{t} )\\\\F = 0.057(\frac{11-24}{1/800} )\\\\F = 0.057(\frac{-13}{1/800})\\\\F = -0.057(\frac{800*13}{1})\\\\ F = -592.8 \ N\\\\Magnitude \ of \ the \ force \ is \ 592.8 \ N[/tex]
Therefore, the magnitude of the average force exerted on the superball by the sidewalk is 592.8 N
What are characteristics that enable plants to protect themselves from herbivores include
Answer:
All of the above!
Explanation:
All of the answers are true! I hope I helped!
What condition is necessary for the flow of heat? What analogous condition is necessary for the flow of charge?
What is your prediction on the effects of drinking 20oz of sports drink vs. 20oz of water? What would happen to urine volume
Answer:
Drinking 20oz of sports drinks decrease the urine volume compared to 20oz of water
Explanation:
Sport drinks typically used by athletes contain water,carbs and electrolytes which helps to replenish the lost minerals from the body during exercises.
Electrolytes an important ingredients of sports drinks is typically sodium and potassium they help the body to retain water,hence less volume of urine is released from the body.
Batteries have potential energy in their
energy stores. What one word completes the sentence?
Answer:
Chemical
Explanation:
Answer:
The right answer is "chemical"
Explanation:
Batteries store energy in the chemical bonds in the metals inside them.
A policeman investigating an accident measures the skid marks left by a car on the horizontal road. He determines that the distance between the point that the driver slammed on the brakes (thereby locking the wheels) and the point where the car came to a stop was 28.0 m. From a reference manual he determines that the coefficient of kinetic friction between the tires and the road under the prevailing conditions was 0.300. How fast was the car going when the driver applied the brakes
Answer:
The car was 12.8m/s fast when the driver applied the brakes.
Explanation:
The equations of motion of the car in the horizontal and vertical axes are:
[tex]x: f_k=ma\\\\y: N-mg=0[/tex]
Since the kinetic friction is defined as [tex]f_k=\mu_kN[/tex] and [tex]N=mg[/tex] we have:
[tex]\mu_kmg=ma\\\\a=\mu_kg[/tex]
Next, from the kinematics equation of speed in terms of distance, we have:
[tex]v^2=v_0^2-2ax\\\\v^2=v_0^2-2\mu_kgx[/tex]
Since the car came to a stop, the final velocity [tex]v[/tex] is zero, and we get:
[tex]0=v_0^2-2\mu_kgx\\\\v_0=\sqrt{2\mu_kgx}[/tex]
Finally, plugging in the known values, we obtain:
[tex]v_0=\sqrt{2(0.300)(9.81m/s^2)(28.0m)}\\\\v_0=12.8m/s[/tex]
It means that the car was 12.8m/s fast when the driver applied the brakes.
The car was moving at the speed of 12.8 m/s, when the driver applied the brakes.
From kinamatic equation,
[tex]\bold {v^2 = v_0^2-2ax}\\[/tex]
Since, car stops the final veocity will be zero. and
Acceleration [tex]\bold {a = \mu_kg}[/tex]
So,
[tex]v_0 = \sqrt {2\mu k_gx}[/tex]
Where,
Vo - initial speed =?
[tex]\mu[/tex] - friction constant = 0.3
g - gravitational acceleration = 9.8 m/s²
x - distance = 25 m
Put the values,
[tex]v_0 = \sqrt {2\times 0.3 \times 9.81 \times 0.25 m}\\\\v_0 = 12.8\ m/s[/tex]
Therefore, the car was moving at the speed of 12.8 m/s, when the driver applied the brakes.
To know more about kinamatic equation,
https://brainly.com/question/5955789
Let the magnitudes of two displacement vectors be 4 m and 8 m, respectively. If the two vectors are added, the magnitude of the resultant vector. A. is exactly equal to 4 m. B. is exactly equal to 12 m. C. is greater than 12 m. D. could be as small as 4 m, and as large as 12 m
Answer:
D. Could be as small as 4 m, and as large as 12 m.
Explanation:
Since the magnitudes are vectors instead of scalars, their sum is not just the sum of their magnitudes; their directions must be taken in account. The maximum possible magnitude of the resultant occurs when both vectors have the same direction; in that case the resultant magnitude is the sum of the individual magnitudes (in this case, 12 meters). In the other hand, the minimum possible magnitude is when the vectors have opposite directions; in that case the magnitude of the resultant is the substraction of one magnitude to another (in this case, 4 meters). Finally, the right answer is D, because the possible values range from 4m to 12m.
Final answer:
The magnitude of the resultant vector when adding two displacement vectors of 4 m and 8 m can be as small as 4 m if they are in opposite directions or as large as 12 m if they are collinear and in the same direction.(Option D)
Explanation:
The question asks about the magnitude of the resultant vector when two displacement vectors are added. A displacement vector has both magnitude and direction, and when two vectors are combined, their resultant depends on both their magnitudes as well as the angle between them. When two vectors are added, the magnitude of the resulting vector can vary depending on this angle. If the vectors are collinear and in the same direction, the magnitude of the resultant will be the sum of the magnitudes of the individual vectors, which is the maximum possible magnitude.
However, vectors can also be in opposite directions, in which case the resultant magnitude will be the difference between the two, representing the minimum magnitude. Therefore, given two displacement vectors with magnitudes of 4 m and 8 m, the magnitude of the resultant vector upon addition can range from 4 m to 12 m. This occurs because if the vectors are in the same direction, their magnitudes add up (to 12 m); if they are opposite, the resultant is the difference (to 4 m). In any other scenario of different angles between the vectors, the resultant will fall somewhere between 4 m and 12 m.
what is electrical circuit
Although blood cells are contained within a special liquid called plasma, the cells themselves are___________.
Answer:
Solid
Explanation:
The plasma is the liquid part of blood, it is 90% and accounts for 55% of blood volume. It is what red blood cells, white blood cells, and platelets move around in. These cells remain solid within the plasma. I hoped this helped!
Although blood cells are contained within a special liquid called plasma, the cells themselves are suspended in plasma.
Blood is a fluid tissue that is made up of plasma, red blood cells, white blood cells, and platelets. Plasma is the liquid part of blood that makes up about 55% of blood volume.
Red blood cells make up about 45% of blood volume and are responsible for carrying oxygen to the tissues. White blood cells make up about 1% of blood volume and are responsible for fighting infection. Platelets are responsible for clotting blood.
The cells are suspended in the plasma because they are too small to sink to the bottom of the blood. The plasma also helps to transport the cells throughout the body.
Learn more about blood cells, here:
https://brainly.com/question/7812856
#SPJ3
A light bulb produces light with frequency = 4.65 x 1014 Hz. What is the wavelength of light the bulb produces?
6.45 x 10-7 meters
1.55 x 106 meters
6.45 x 1021 meters
1.395 x 1023 meters
Answer:
6.45 x 10-7 meters
Explanation:
Taking speed of light as 300000000 m/s
We know that speed of light is product of wavelength and frequency and expressed as
s=fw
Where s represent speed, f is frequency and w is wavelength
Substituting 4.65*10^14 Hz for frequency then the wavelngth will be given by
300000000=4.65*10^14 *w
w=300000000÷4.65*10^14
w=6.451612903225*10^-7 m
Rounded off, the wavelength is 6.45 x 10-7 meters
Solids,liquids,and gases are three forms of matter that?
500 kg cannon and is at rest on a horizontal, frictionless surface on a clear and sunny day. When a crazy cool 100 kg clown decided to show how the cannon works they decided to get fired horizontally from the barrel of the cannon and the cannon recoils with a speed of 5 m/s. A very inquisitive Physics student figured out how fast the clown was traveling when leaving the cannon. What value did they come up with?
Answer:
Explanation:
Given that,
Mass of cannon
M1= 500kg and initially at rest
U1 = 0m/s
Mass of clown
M2 = 100kg
so it was initial at rest before this time, therefore, U2 = 0
Recoils speed of cannon V1 =5m/s, the recoils speed is after the cannon has left the barrel.
Using construction of linear momentum
Momentum before collision is equal to momentum after collision
The initial momentum is zero since the two bodies are until at rest
And the final momentum is
M1•V1 + M2•V2
Then,
P(initial) = P(final)
0 = M1•V1 + M2•V2
0 = 500 × 5 + 100 × V2
0 = 2500 +100•V2
100•V2 = -2500
V2 = -2500/100
V2 = —25m/s
So, the final velocity of the clown is -25m/s, opposite direction of the cannon
When checking the charging system on a late-model vehicle: Technician A connects a scan tool to monitor the system voltage output. Technician B connects a scan tool to retrieve any DTCs that may be in the system. Who is correct:a.Technician Ab.Technician Bc.both 1 and 2d.neither 1 and 2
Answer:
C) Both 1 and 2
Explanation:
The scan tool may include a bi-directional control that allows the technician to control the output of the alternator for testing purposes.
The Diagnostic Trouble Codes (DTCs), are used by automobile manufacturers to diagnose problems related to the vehicle.
The scan tool can also be used to monitor the output voltage of the vehicle to verify if the correct amount of voltage is supplied by the alternator.
Both Technicians A and B are correct because the steps they both take are necessary for the diagnosis of the vehicle.
Which of the following describes wavelength?
A.
the number of waves that pass a point in a given amount of time
B.
the distance between crests of adjacent waves
C.
the distance a wave travels in a given amount of time
D.
the height of a wave
Answer:
B.
Explanation:
The distance between two crests of adjacent waves is called wavelength.
Final answer:
Wavelength is (option B) the distance between consecutive crests of adjacent waves and is parallel to the direction of wave propagation, typically represented by the Greek letter lambda (λ).
Explanation:
The correct description of wavelength in the context of waves is the distance between crests of adjacent waves. Wavelength is the distance between two consecutive points of similar position along the wave such as from one crest to the next crest, or one trough to the next trough. It's important to note that wavelength is parallel to the direction in which the wave is traveling, so it measures the length of one complete cycle of the wave.
Options such as the number of waves passing a point in a given time (frequency) and the wave's height (amplitude) are different wave properties. Thus, the correct answer is option B: the distance between crests of adjacent waves.