In addition to key executives, there are other positions in a company that may be considered critical, or whose loss will be difficult for the company. What will happen if a network administrator leaves? What customers or contacts would the company lose if a sales representative leaves? What other positions can you name where a loss would have a potentially significant negative effect on the company?

Answer:

The code to this question can be given as:

Code:

//define code.

//conditional statements.

   if (Character.isLetter(passCode.charAt(0))) //if block

   {

       System.out.println("Alphabetic at 0"); //print message.

   }

   if (Character.isLetter(passCode.charAt(1))) //if block

   {

       System.out.println("Alphabetic at 1"); //print message.

   }

Explanation:

In this code, we define conditional statement and we use two if blocks. In both if blocks we use isLetter() function and charAt() function. The isLetter() function checks the inserted value is letter or not inside this function we use charAt() function that checks inserted value index 1 and 2 is the character or not.

The code segment is an illustration of conditional statements

Conditional statements are statements whose execution depends on the truth value of the condition.

The code segment in Java, where comments are used to explain each line is as follows:

//This checks if the first character is an alphabet.

if (Character.isLetter(passCode.charAt(0))){

   //If yes, this prints alphabetic at 0

   System.out.println("Alphabetic at 0");

}

//This checks if the second character is an alphabet.

if (Character.isLetter(passCode.charAt(1))){

   //If yes, this prints alphabetic at 1

   System.out.println("Alphabetic at 1");

}

Read more about similar programs at:

https://brainly.com/question/14391069

Mostly the spyware and malware protection for desktop and laptop or workstations are to protected with anti-virus regular updates. All workstation or desktop or laptops are to updated operating systems patches.

If any operating systems patched update to be schedule and checked regularly. Schedule scanning by virus scanner to be made for desktop and laptop or workstations in regular interval basis

There are third parties tools such as malware and ADWCLEANER are also available free scanner software through internet where end user can download and scanner so software will clean the malware.

Mostly end user do mistake keep the files in desktop. Most of the malware software will affect the desktop folder only.

It will also affect c:\users folder and register enter keys.

Answer:

Assembly line.

Explanation:

The interchangeable parts was a game-changing concept for the manufacturing industry during the Industrial Revolution.

It was first introduced by Eli Whitney, also the inventor of the Cotton Gin, and later was perfected by Henry Ford, who was the first to create a continuous moving assembly line. The Interchangeable parts are identical pieces created from a master model and are so similar to each other, that they can fit into any line of production of the same kind.

Thanks to these advances, the manufacturing process across all industries could be now faster, more cost-efficient, and profitable.

Answer:

The correct program to this question can be given as:

Program:

//import package.

import java.util.Scanner; //scanner package.

public class CheckingPasscodes //define class.

{

//all the code run here.

public static void main (String [] args) //define main method

{

Scanner scnr = new Scanner(System.in); //create Scanner class Object

boolean hasDigit; //define variable.

String passCode; //define variable.

hasDigit = false; //assign value.

passCode = scnr.next(); //taking user input.

int let0 = passCode.charAt(0); //assign value in integer variable

int let1 = passCode.charAt(1); //assign value in integer variable

int let2 = passCode.charAt(2); //assign value in integer variable

//conditional statement.

if ((Character.isDigit(let0)||Character.isDigit(let1)||Character.isDigit(let2))) //if block

{

hasDigit = true; //assign value.

}

if (hasDigit) //if block

{

System.out.println("Has a digit."); //message.

}

else //else block

{

System.out.println("Has no digit.");  //message.

}

}

}

Output:

AB1

Has a digit.

Explanation:

In the given question there are many mistakes so we provide the correct solution to this question that can be described as follows:

To make corrections to your code, implies that we debug the code. The following are the reasons why your code is not working

The corrections to your code are:

The complete correct code is as follows:

import java.util.Scanner;

public class CheckingPasscodes {

   public static void main (String [] args) {

       Scanner scnr = new Scanner(System.in);

       boolean hasDigit;

       String passCode;

       hasDigit = false;

       passCode = scnr.next();

       char let0 = passCode.charAt(0);

       char let1 = passCode.charAt(1);

       char let2 = passCode.charAt(2);

       if (Character.isDigit(let0) || Character.isDigit(let1) || Character.isDigit(let2)){

           hasDigit = true;}

       if (hasDigit) {

           System.out.println("Has a digit.");}

       else {System.out.println("Has no digit.");}

   }

}

Read more about debugging at:

https://brainly.com/question/23527739

Answer:

easy. i've done this with my family before. take a bike or skateboard to the park with your family. maybe invite some friends over, or just spend the day at their house. this is obviously a good time to finish any home-work if you have any left. you can make a few extra bucks by doing some extra chores done (just make sure to tell your parents about it first;)). i hate not having technology, but i mean it's not the end of the world.

Explanation:

Nowadays, we rely on technology heavily. Because of this, it can be difficult to imagine what we would do without it. However, avoiding technology for a few days can be an enriching experience.

There are many things that you can do with your family without the use of technology. For example, if you are at a different location and there is nature around, you can go camping. You can make a fire to cook, swim, look at the stars and hike. If you are in the city, you can go to a park and read, or play a sport. You can also take advantage of this experience to talk more to your family and get to know them better.

Answer:

Following are the program in the Python Programming Language:

1.)

l=['Ruby','Dale','Kate']

n=input('Enter the name: ')

if(n in l):

   print('Hello {}'.format(n))

else:

   print('No {}'.format(n))

Output:

Enter the name: Dale

Hello Dale

2.)

file=open("text1.txt", "r+") #open file

str=file.read()  #read file

txt=str.replace('\n', ' ') #replace spaces

word=txt.split(' ') #split words in ' '

for words in word: #set for loop

   word2=' '

   for i in range(len(words)):  #set for loop

       if(words[i].isalpha()):  #set if statement

           word2 += words[i].lower()

   word[word.index(words)]=word2

while(' ' in word):  #set while loop

   word.remove(' ')  #remove spaces

st=set(word)

print('The ', len(st),' unique words which appears in document are ' \

     '(in no particular order): ')

for words in st:  #set for loop

   print('-', word)

file.close()  #close file

3.)

file=open("text1.txt", "r+") #open file

str=file.read()  #read file

txt=str.replace('\n', ' ') #replace spaces

word=txt.split(' ') #split words in ' '

for words in word: #set for loop

   word2=' '

   for i in range(len(words)):  #set for loop

       if(words[i].isalpha()):  #set if statement

           word2 += words[i].lower()

   word[word.index(words)]=word2

while(' ' in word):  #set while loop

   word.remove(' ')  #remove spaces

dic={}  #set dictionary

for words in word:  #set for loop

   if(words not in dic):  #set if statement

       dic[words]=1

   else:

       dic[words] +=1

print('\033[4m' + 'word   frequency' + '\033[0m')

for words in dic:

   print(format(words, '15s'), format(dic[words], '5d'))

file.close() #close file

Explanation:

1.) Here, we define the list data type variable 'l' then, set the variable 'n' and assign value by get input from the user,

2.) Here, we define the variable "file" in which we open file and save that file in it.

Then, we set variable st which read the file then we set the variable in which we apply the replace().

Then. we set variable in which we split the by suing split()

2.) Here, we define the variable "file" in which we open file and save that file in it.

Then, we set variable st which read the file then we set the variable in which we apply the replace().

Then. we set variable in which we split the by suing split()

Then, we apply all that given in the question.

Answer:

Answer:

'''

This is script makes use of dictionaries to get all the words in a file and the

number of times they occur.

'''

#section 1

import string

dic = {}

textFile=open("Text.txt","r")

# Iterate over each line in the file

for line in textFile.readlines():

   tex = line

   tex = tex.lower()

   tex=tex.translate(str.maketrans('', '', string.punctuation))#removes every punctuation  

#section 2

   new = tex.split()

   for word in new:

           if word not in dic.keys():

               dic[word] = 1

           else:

               dic[word] = dic[word] + 1

for word in sorted(dic):

   print(word, dic[word], '\n')

textFile.close()

Explanation:

The programming language used is python.

#section 1

The string module is imported because of the string operations that need o be performed. Also, an empty list is created to hold the words and the number of times that they occur and the file is opened in the read mode, because no new content is going to be added to the file.

A FOR loop is used to iterate through every line in the file and assigns each line to a variable one at a time, and each line is converted to lowercase and  punctuation is stripped off every word in each line.

This processing is needed in order for the program o accurately deliver the number of occurrences for each individual word in the text.

#section 2

Each line is converted to a list using the split function, this is done so that a FOR loop can iterate over each word. The FOR loop, iterates over each word in the list and the IF statement checks if the word is already in the dictionary, if the word id in the dictionary, it increases the number of occurrences, if it is not in the dictionary, it adds it to the dictionary and assigns the number 1 to it.

The words are then sorted just to make it look more organised and the words and the number of times that they occur is printed to the screen.

Here's a Python program that reads the contents of a text file, creates a dictionary with word frequencies, and then displays the frequency of each word:

```python

def count_word_frequency(file_path):

   word_frequency = {}

   # Open the file for reading

   with open(file_path, 'r') as file:

       # Iterate through each line in the file

       for line in file:

           # Split the line into words

           words = line.split()

           # Iterate through each word

           for word in words:

               # Remove any punctuation characters

               word = word.strip('.,!?;:"()[]{}')

               # Convert the word to lowercase

               word = word.lower()

               # Increment the count for this word in the dictionary

               word_frequency[word] = word_frequency.get(word, 0) + 1

   return word_frequency

def display_word_frequency(word_frequency):

   # Iterate through the dictionary and print each word and its frequency

   for word, frequency in word_frequency.items():

       print(f"{word}: {frequency}")

def main():

   file_path = input("Enter the path to the text file: ")

   word_frequency = count_word_frequency(file_path)

   display_word_frequency(word_frequency)

if __name__ == "__main__":

   main()

```

To use this program:

1. Save the code into a Python file (e.g., `word_frequency.py`).

2. Run the program.

3. Enter the path to the text file you want to analyze.

This program will read the text file, count the frequency of each word, and then display the frequency of each word in the console.

1. `count_word_frequency(file_path)` function:

  - This function takes a file path as input.

  - It initializes an empty dictionary called `word_frequency` to store word frequencies.

  - It opens the file specified by the file path in read mode using a `with` statement, ensuring that the file is properly closed after reading.

  - It iterates through each line in the file.

  - For each line, it splits the line into individual words using the `split()` method.

  - It then iterates through each word, strips any punctuation characters from the word, converts it to lowercase, and updates the count for that word in the `word_frequency` dictionary.

  - If the word is not already in the dictionary, it initializes its count to 1; otherwise, it increments its count by 1.

  - After processing all lines in the file, it returns the `word_frequency` dictionary containing the word frequencies.

2. `display_word_frequency(word_frequency)` function:

  - This function takes the `word_frequency` dictionary as input.

  - It iterates through the dictionary and prints each word along with its frequency.

3. `main()` function:

  - This function serves as the entry point of the program.

  - It prompts the user to enter the path to the text file they want to analyze.

  - It calls the `count_word_frequency()` function with the provided file path to calculate word frequencies.

  - It then calls the `display_word_frequency()` function to display the word frequencies to the user.

4. `if __name__ == "__main__":` block:

  - This block ensures that the `main()` function is only executed when the script is run directly, not when it's imported as a module in another script.

Overall, this program reads a text file, counts the frequency of each word, and displays the frequency of each word to the user.

Answer:

Following are the program in c++ language

#include<iostream> // header file

using namespace std; // using namespace

void swapvalues(int&  userVal1, int& userVal2);// fucnction declaration

int main() // main method

{

   int x,y; // variable declaration

   cout<<"Enter the two value before swapping:\n";

   cin>>x>>y; // read the two input

  cout<<"before swapping:";

  cout<<x<<y; // display the value before swapping

   swapvalues(x, y);

   cout << "\nAfter swapping:";

   cout<<x<<y; // display the value after swapping

   return 0;

}

void swapvalues(int&  userVal1, int& userVal2) // function definition

{

   int t; // variable declaration

   t = userVal1; // assign the value userval1 to variable t

   userVal1 = userVal2; // assign the value userval2 to userval1

   userVal2 = t; // assign the value of variable t to userval2

}

Output:

Enter the two value before swapping:

3

8

before swapping:3 8

After swapping   :8 3

Explanation:

Following are the description of the program

Following are C++ programs on Swapping values:

#include <iostream>//header file

using namespace std;

void SwapValues(int& userVal1, int& userVal2)//defining the method SwapValues that takes two integer variable

{

   int t;//defining integer variable t

   //performing the swapping

   t=userVal1;//using t variable that holds userVal1 value

   userVal1=userVal2;//using userVal1 variable that holds userVal2 value

   userVal2=t;//holding the t value in userVal2

   cout<<"After swapping value: "<<userVal1<<" "<<userVal2;//printing the swapped value

}

int main()//defining the main method

{

   int x,y;//defining integer variable that inputs value

   cout<<"Input first number: ";//print message

   cin>>x;//input value

   cout<<"Input second number: ";//print message

   cin>>y;//input value

   cout<<"Before swapping value: "<<x<<" "<<y<<endl;//printing value

   SwapValues(x,y);//calling method SwapValues

   return 0;

}

Program Explanation:

Output:

Please find the attached file.

Find out more information about the swapping here:

brainly.com/question/19665043

Answer:

CPU need 50% much faster

disk need 100% much faster

Explanation:

given data

workload spend time CPU  = 60%

workload spend time I/O = 40%

achieve overall system speedup = 25%

to find out

How much faster does CPU need and How much faster does the disk need

solution

we apply here Amdahl’s law for the overall speed of a computer that is express as

S = [tex]\frac{1}{(1-f)+ \frac{f}{k} }[/tex]      .............................1

here f is fraction of work i.e 0.6 and S is overall speed  i.e 100% + 25% = 125 % and k is speed up of component

so put all value in equation 1 we get

S = [tex]\frac{1}{(1-f)+ \frac{f}{k} }[/tex]  

1.25 = [tex]\frac{1}{(1-0.6)+ \frac{0.6}{k} }[/tex]  

solve we get

k = 1.5

so we can say  CPU need 50% much faster

and

when f = 0.4 and S = 125 %

put the value in equation 1

S = [tex]\frac{1}{(1-f)+ \frac{f}{k} }[/tex]  

1.25 = [tex]\frac{1}{(1-0.4)+ \frac{0.4}{k} }[/tex]  

solve we get

k = 2

so here disk need 100% much faster

Final answer:

To achieve a 25% speedup in overall system performance, we use Amdahl's Law. The CPU must become 50% faster, while the disk must become 100% faster.

Explanation:

To achieve an overall system speedup of 25%, we can use the principle known as Amdahl's Law, which provides a way to calculate the improvement to overall system performance when only part of the system is improved. Given that processes spend 60% of their time on the CPU and 40% on I/O, we can define these as fractions of the total execution time (0.60 and 0.40 respectively).

To solve these related questions, we first need to turn the desired speedup into its equivalent 'slowness' fraction. If we want a speedup of 25%, the new execution time should be 1 / (1 + speedup), which is 1 / 1.25 or 0.80 of the original execution time. This is the target 'slowness' of the improved system.

For the CPU, which currently accounts for 60% of the execution time, its improved slowness should be S_CPU * 0.60 + 0.40 (unchanged I/O slowness) = 0.80. Solving for S_CPU, we get S_CPU = (0.80 - 0.40) / 0.60 = 2/3. Therefore, to achieve the overall improvement, the CPU needs to become 1/(2/3) = 1.5 times faster.

For the disk I/O, which accounts for 40% of the execution time, its improved slowness should be 0.60 (unchanged CPU slowness) + S_IO * 0.40 = 0.80. Solving for S_IO, we get S_IO = (0.80 - 0.60) / 0.40 = 1/2. Hence, to achieve the desired system speedup, the disk needs to be 1/(1/2) = 2 times faster.

In summary:

Answer:

A friend asks you for help writing a computer program to calculate the square yards of carpet needed for a dorm room. The statement "the living room floor is rectangular" is an example of a(n) assumption . The length and width of the room are examples of known information, which you can obtain as input from the user.

Explanation:

The given question is a Problem statement.

Problem statement can be defined as the brief description of an issue that needs to be focused in order to reach the require goal.

So the parts that a problem statement may have include:

So the attributes to be filled into blanks of given statement are assumption, known, input.

i hope it will help you!

Answer:

The correct option to the following question is an option (D).

Explanation:

Because RPO(Recovery point objective) is the objective in which we getting the greatest level of the privacy. confidence and the important thing is security for our resources.

The best thing is that the center of activity of the RPO in on the data and the overall elasticity of the loss of your company.

Answer:

1. A

2. B

Explanation:

1. For an AND truth table to output true, all it input must be true. If one or any of the input is false, the output will be false. The truth table for AND is written below:

INPUT      INPUT      OUTPUT

FALSE      FALSE      FALSE

FALSE      TRUE        FALSE

TRUE        FALSE      FALSE

TRUE        TRUE        TRUE

2. The Internal Revenue Service web site is a good search tool when looking for income tax information. The federal government main web site might look like a correct option but one must understand that the federal government will only make the policy while the Internal Revenue Service will implement the policy.

Answer: SQL Injection

Explanation:

The SQL injection is one of the type of attack which is used in the database management system for sending the commands by adding the structured query (SQL) language statement in the form of input data.

Therefore, The SQL injection is the correct option.

Final answer:

The safeOpen() function in Python is used to open a file while handling exceptions. It returns the file object on success, or None if an error occurs, thus ensuring that the program can continue to run without crashing.

Explanation:

The function safeOpen() is designed to handle file operations within a Python program safely by attempting to open a file and returning a file object if successful, or None if an exception occurs. This function makes use of Python's built-in exception handling mechanisms to provide a secure way of accessing files. Here's an example of how you can define the safeOpen() function:
def safeOpen(filename):
   try:
       file = open(filename, 'r')
       return file
   except Exception as e:
       print("An error occurred: ", e)
       return None
In this code snippet, the try block attempts to open the specified file in read mode. If the file is opened successfully, the file object is returned. If any exception, such as FileNotFoundError or PermissionError, is raised during the attempt, the except block is executed, printing out the error message and returning None.

Answer:

A) expert user

Explanation:

An expert user is an experienced user who has spent considerable time using specific application programs and, therefore, it is fair to assume that this user is likely to become comfortable and familiar with the terminal's operation.

A casual user is a less experienced computer user who will generally use a computer less frequently and thus is not likely to become comfortable and familiar with the terminal's operation.

System owners and system builders are not technically users.

Therefore, the answer is A) expert user

Answer:

The following are the program in the C++ Programming Language:

#include <iostream> //header file

#include <string>  //header file

#include <vector>  //header file

//name space

using namespace std;

//main function

int main() {

  vector<string> word; //set variable

  vector<int> c;  //set variable

  int s, counts = 0; //set variable

  string strng;  //set variable

  cout<<"Enter the size of string: "; //print message

  cin >> s; //get input

  cout<<"Enter the string: "; //print message

  for(int i = 0; i < s; ++i) {  //set for loop

     cin >> strng; //get input

     word.push_back(strng);

  }

  for(int i = 0; i < s; ++i) { //set for loop

         counts = 0;

         for(int j = 0;j<word.size();j++){ //set for loop

       if(word[j] == word[i]){ //set if statement

          counts++; //increament in counts

       }        

     }

      c.push_back(counts);

  }

  for(int i = 0; i < s; ++i) {

      cout << word[i] << " " << c[i] << endl;//print result

  }

  return 0;

}

Output:

Enter the size of string: 2

Enter the string: hello  sir

hello 1

sir 1

Explanation:

Here, we define three header files <iostream>, <String>, <vector> and namespace "std" after that we define main() method inside it.

In this exercise we have to write a C++ code requested in the statement, like this:

find the code in the attached image

We can write the code in a simple way like this below:

#include <iostream>

#include <string>

#include <vector>

using namespace std;

//main function

int main() {

 vector<string> word; //set variable

 vector<int> c;  //set variable

 int s, counts = 0; //set variable

 string strng;  //set variable

 cout<<"Enter the size of string: "; //print message

 cin >> s; //get input

 cout<<"Enter the string: "; //print message

 for(int i = 0; i < s; ++i) {  //set for loop

    cin >> strng; //get input

    word.push_back(strng);

 }

 for(int i = 0; i < s; ++i) { //set for loop

        counts = 0;

        for(int j = 0;j<word.size();j++){ //set for loop

      if(word[j] == word[i]){ //set if statement

         counts++; //increament in counts

      }        

    }

     c.push_back(counts);

 }

 for(int i = 0; i < s; ++i) {

     cout << word[i] << " " << c[i] << endl;//print result

 }

 return 0;

}

See more about C++ at brainly.com/question/19705654

Answer:

import re

#section 1

while True:

   try:

       major=input('Enter Major: ')

       if re.search(r'^\d{1,4}$',major):

           minor=input('Enter minor: ')

       else:

           raise

       try:

           if re.search(r'^\d{1,4}$',minor):

               sub1=input('Enter sub1: ')

           else:

               raise

           try:

               if re.search(r'^\d{1,4}$',sub1):

                   sub2=input('Enter sub2: ')

               else:

                   raise

               try:

                   if re.search(r'^\d{1,4}$',sub2):

                       break

                   else:

                       raise

               except:

                   print('enter a correct sub 2')

           except:

               print('enter a correct sub1')        

       except:

           print('Enter a correct minor ')            

   except:

        print('enter a correct Major')

#section 2

sub1= f"{int(sub1):04d}"

sub2= f"{int(sub2):04d}"

major= f"{int(major):04d}"

minor= f"{int(minor):04d}"

if major == '0000' and minor == '0000' and sub1=='0000' and sub2=='0000':

   print('INVALID!!! Acount Number')

else:

   print('-----------------------')

   print('Your Account Number is')

   print(major, minor, sub1, sub2)

   print('-----------------------')

Explanation:

The programming language used is python 3

The Regular  Expression Module was imported to allow us perform special operations on string variables.

This is the pattern that was used to check if an input was valid or invalid re.search(r'^\d{1,4}$',string)

what this pattern does is that it ensures that:

we also made use of fstrings

sub1= f"{int(sub1):04d}"

the above line of code takes 'sub1' in this case, and converts it temporarily to an integer and ensures it has a length of 4 by adding 0's in front of it to convert it to a four digit number.

These are the major though areas, but i'll explain the sections too.

#section 1

In this section the WHILE loop is used in conjunction with the TRY and EXCEPT block and the IF statement to ensure that the correct input is given.

The while loop will keep looping until the correct input is inserted  before it breaks and each input is tested in the try and except block using the if statement and the regular expression pattern I explained, as a result, you cannot input a letter, a blank space, a punctuation or numbers with length greater than 4, it has to be numbers within the range of 1-4.

#section 2

The second section converts each entry to a four digit number and checks with an if statement if the entry is all zeros (0000 0000 0000 0000) and prints invalid.

Otherwise, it prints the account number.

check the attachment to see how the script runs.

Answer:

See the code snippet in the explanation section

Explanation:

import java.util.Scanner;

public class Question {

 public static void main(String[] args) {

   Scanner scan = new Scanner(System.in);

   System.out.println("Enter temperature in Fahrenheit: ");

   int inputTemperature = scan.nextInt();

   fahrenheitTemperatureToCelsius(inputTemperature);

 }

public static void fahrenheitTemperatureToCelsius(int fahrenheitTemperature){

   int celsiusTemperature = ((fahrenheitTemperature - 32)*5)/9;

   System.out.println("Temperature in Celsius = " + temperature);

}

}

Final answer:

To find all .conf files in the /etc directory, use the find command and redirect the output to a file. Knowledge of navigating directories and handling file permissions is also applicable.

Explanation:

The student has asked for assistance in searching for configuration files in the directory /etc, including all of its subdirectories, that end with the .conf extension. To accomplish this task, one can use the find command in a Unix-based system. Here's an example of how this command can be structured:

find /etc -type f -name "*.conf" > s9

This command will search for all files (-type f) within the /etc directory and its subdirectories that match the name pattern (-name "*.conf") and redirect the output to a file named s9. The student is also advised on how to navigate directories using both absolute and relative paths and how to handle any 'Permission Denied' errors that may occur during the execution of the find command.

Furthermore, it is important to note that file permissions, as per Unix file system conventions, may prevent certain directories from being accessible to non-root users.

Answer:

The correct option to the following question is option:

(C).

29. (A).

Explanation:

Cloud firms or companies are those that provides us the facilities to store our important data and kept it in safety, they also provides more facilities such as storage, networking, intelligence, database, etc.

Cloud computing are the facility in which we keep our data safe and confidential by saving our data in drives.

Operating System are software which manages the software as well as hardware also, that's why this option is correct

Answer:

def gradeAverage():

   grades = []

   i = 0

   while i < 5:

       a = int(input('enter score ' + str(i + 1) + ': '))

       grades.append(a)

       i = i+1

   #print(grades)

   average = sum(grades)/len(grades)

   #print(average)

   return average

def lettergrade(a):

   letter = 'A'

   if a < 60:

       letter = 'F'

   elif 59 < a < 63:

       letter = 'D-'

   elif 62 < a < 67:

       letter = 'D'

   elif 66 < a < 70:

       letter = 'D+'

   elif 69 < a < 73:

       letter = 'C-'

   elif 72 < a < 77:

       letter = 'C'

   elif 76 < a < 80:

       letter = 'C+'

   elif 79 < a < 83:

       letter = 'B-'

   elif 82 < a < 87:

       letter = 'B'

   elif 86 < a < 90:

       letter = 'B+'

   elif 89 < a < 94:

       letter = 'A-'

   elif 93 < a < 101:

       letter = 'A'

   return letter

numOfStudents = int(input('How many students: '))

names = []

aver = []

grade =[]

while numOfStudents > 0:

   studentName = input('Enter students name: ')

   names.append(studentName)

   a = gradeAverage()

   aver.append(a)

   grade.append(lettergrade(a))

   numOfStudents = numOfStudents - 1

for name in names:

       for score in aver:

           for letter in grade:

               if names.index(name) == aver.index(score) == grade.index(letter):

                   print('%s : Average =  %d  Letter Grade:  %s \n' %(name, score, letter))

                   break

Explanation:

The programming language used is python.

Two functions were created, the first function gradeAverage() was used to calculate the average values of the scores.

The second function lettergrade(a) was used to get the letter grade i.e(A, A-, C, D, e.t.c.) and it takes its argument from the average.

The main block of code asks for how many students are there and prompts the user to input their names and scores for all the students.

It takes that data calculates the average and the letter grade and prints out the names of the students, their average and their letter grade.

Here's a C++ program that reads two rectangles' lengths and widths as integer values and tests if they are similar:

#include <iostream>

#include <cmath>

using namespace std;

bool areSimilar(int length1, int width1, int length2, int width2) {

   float lengthRatio = static_cast<float>(length1) / static_cast<float>(length2);

   float widthRatio = static_cast<float>(width1) / static_cast<float>(width2);

   return lengthRatio == widthRatio;

}

int main() {

   int length1, width1, length2, width2;

   cout << "Enter the length and width of the first rectangle: ";

   cin >> length1 >> width1;

   cout << "Enter the length and width of the second rectangle: ";

   cin >> length2 >> width2;

   if (areSimilar(length1, width1, length2, width2)) {

       cout << "The two rectangles are similar." << endl;

   } else {

       cout << "The two rectangles are not similar." << endl;

   }

   return 0;

}

This program defines a function areSimilar that takes the lengths and widths of two rectangles as input and returns a boolean value indicating whether the rectangles are similar. The function calculates the ratios of the lengths and widths and checks if they are equal. If the ratios are equal, the rectangles are considered similar, and the function returns true. Otherwise, the rectangles are not similar, and the function returns false.

Answer:

The output of the given code is "AB-2".

Explanation:

The description of the java program can be given as:

That's why the output of this program is "AB-2".

Answer:

fav_number=26

guess=0

while 0==0:

   try:

       guess=int(input('Enter your guess: '))

   except:

       print ('You have entered an invalid value.')

   else:

       if guess == fav_number:

           break

       elif guess>fav_number:

            print ('Try a smaller number.')

       elif guess<fav_number:

           print ('Try a larger number')

Explanation:

define a variable fav_number and set it to number. write an infinite while loop to read input from user. In try block get input from user, if user enters invalid input code in except block will be executed. For valid input

Loop-tee-loop LOL

...

Not funneh...

Answer:  Database Architect

Explanation:

Answer:

def nounToplural(tex):

   import re

   text = tex.split()

   new = []

   for word in text:

       if re.findall(r"y\b", word):

           word = re.sub(r"y\b", 'ies' ,word)

           new.append(word)

       elif re.findall(r"ch\b", word):

           word = re.sub(r"ch\b", 'ches' ,word)

           new.append(word)

       elif re.findall(r"sh\b", word):

           word = re.sub(r"sh\b", 'shes' ,word)

           new.append(word)

       elif re.findall(r"s\b", word):

           word = re.sub(r"s\b", 'ses' ,word)

           new.append(word)

       else:

           word = word + 's'

           new.append(word)

   result = []

   for i in text:

       for j in new:

           if new.index(j) == text.index(i):

               result.append( (i,j) )

   print(result)

str = "chair dairy boss circuis fly dog church clue dish"

nounToplural(str)

Explanation:

We made use or Regular Expressions which is simply a special sequence of characters that helps you match or find other strings or sets of strings, by using a specialized syntax held in a pattern.

Firstly, define the function and import the regular expression module, split the text into a list and create an empty list to hold the plural list.

For every word in the list  we check with IF statements and regular expressions to find out what they end with.

 if re.findall(r"y\b", word):

           word = re.sub(r"y\b", 'ies' ,word)

           new.append(word)

The above IF block checks if a noun ends with 'y', if it does it replaces the 'y' with 'ies' and ads it to the new list.

If it does not, ot moves to the next IF/ELIF block.

In the ELIF blocks carry out a  a similar operation for "s", "ch", or "sh", in order to add "es".

Finally, 's' is added to all other cases using the ELSE block which traps any noun that did not fall under the IF or any of the ELIF blocks.

This last part of the code prints both list side by side and passes them to a new list result which is printed to the screen

result = []

   for i in text:

       for j in new:

           if new.index(j) == text.index(i):

               result.append( (i,j) )

   print(result)

I called the function and passed the string you provided in your question and attached the result of the code.

Answer:AEIOU

Explanation:

Answer:

1. INTERSECT

Explanation:

Intersection is the set operator that gives us the information which is common to both tables. In this case the query will be:

SELECT firstname, lastname, phone FROM Customers

INTERSECT

SELECT firstname, lastname, phone FROM Employees;

Answer:

#include <iostream>

#include <string>

using namespace std;

int

stringLength (string str)

{

 int i = 0;

 int count = 0;

 while (0 == 0)

   {

     if (str[i])

{

  i++;

  count++;

}

     else

{

  break;

}

   }

 return count;

}

int

main ()

{

 string userinput;

 cout << "Enter string ";

 getline (cin, userinput);

 int string_length = stringLength (userinput);

 int vowels=0;int numeric=0;int consonants=0;int special = 0;

 for (int i = 0; i < string_length; i++)

   {

     if (userinput[i] == 'a' ||

  userinput[i] == 'e' ||

  userinput[i] == 'i' ||

  userinput[i] == 'o' ||

  userinput[i] == 'u' ||

  userinput[i] == 'y' ||

  userinput[i] == 'A' ||

  userinput[i] == 'E' ||

  userinput[i] == 'I' ||

  userinput[i] == 'O' || userinput[i] == 'U' || userinput[i] == 'Y')

{

  vowels++;

}

    else if (userinput[i] - 48 > 0 && userinput[i] - 48 <= 9)

{

  numeric++;

}

     else if (userinput[i] == '~' ||

  userinput[i] == '!' ||

  userinput[i] == '@' ||

  userinput[i] == '#' ||

  userinput[i] == '$' ||

  userinput[i] == '%' ||

  userinput[i] == '^' ||

  userinput[i] == '&' ||

  userinput[i] == '*' ||

  userinput[i] == '(' ||

  userinput[i] == ')' ||

  userinput[i] == '_' ||

  userinput[i] == '+' ||

  userinput[i] == '-' ||

  userinput[i] == '+' ||

  userinput[i] == ':' ||

  userinput[i] == ':' ||

  userinput[i] == '?' ||

  userinput[i] == '/' || userinput[i] == '<' || userinput[i] == '>')

{

  special++;

}

     else

{

  consonants++;

}

}

cout << vowels << " vowels and " << consonants << " consonants and " << special

 << " special characters and " << numeric << " numbers." << endl;

return 0;

}

Explanation: