In an alternate version of the universe, the earth rotates around its axis at the same speed with which it revolves around the sun (ie. 365 of our days for one rotation/r). Think about what this means for the time period of day and night in "alter-Earth". What would be the approximate value of the period of the rhythm that would evolve in most species in this world?

a. 365 days
b. 182.5 days
c. 730 days
d. There will be no rhythms based on the light cycle

Answers

Answer 1

Answer:

The Correct option is A "365 days"

Explanation:

Earth pivots on its hub once every 24 hrs and species have developed to organize their exercises dependent on these day-night cycles showing endogenously rehashing circadian rhythms.  

Then again, in an adjust earth, every revolution on its hub takes 365 days. This time-span is same as the time it takes to rotate around the sun (365 days).

The time-frame of every day and night in this adjust earth will be 182.5 days. The estimated estimation of the time of the beat that would develop in many species in this modify earth will be 365 days.


Related Questions

Mr. A.H., age 44, had a generalized tonic-clonic seizure unexpectedly at work_ He had no history of seizures, trauma, infection, or other illness. Investigation revealed a tumor in the right parietal lobe. This was removed surgically, although the diffuse nature of the malignant mass prevented its complete elimination. Follow-up radiation treatment was recommended. After surgery, Mr. A.H. demonstrated considerable weakness and sensory loss on his left side. A few days after surgery, Mr. A.H. developed a bacterial infection at the operative site. The infection was eradicated quickly with treatment, but the tumor did not respond to radiation and chemotherapy. As a result, several tumors in the brain grew relatively large during the next 2 months.
Mr. A.H. developed severe headaches and diplopia and became increasingly lethargic, and his seizures increased in frequency despite anticonvulsant medication. He was given medication to reduce the frequency of vomiting.
Explain the specific rationale for each of his manifestations.

Answers

Answer:

a tumor is a growth of abnormal cells in the brain tissue, in this case they are malignant cancer cells since their growth is very fast, some are primary that start directly in the brain and other metastatic that start in another part of the body, in the case of Mister AH always had primary symptoms.

Tumors in the brain can show various symptoms. These are some of the most common:

Headaches, usually in the morning

Nausea and vomiting

Changes in the ability to speak, hear or see

Balance or walking problems

Problems with thinking or memory

Weakness or longing to sleep

Changes in mood or behavior

Seizures

tumors can destroy brain cells which can cause inflammation and damage to parts of the body depending on where in the brain this is exerted, this also aggravates the symptoms.

Radiation therapy used to treat brain cancers increases the risk of brain tumors up to 20 to 30 years later.

In this case, he was causing this same reaction to Mr. AH, which may also have another type of tumor such as

Meningiomas and schwanomas are two other types of brain tumor. These tumors:

They occur in most cases between the ages of 40 and 70.

They are not usually cancerous, but they can still cause serious complications and death due to their size or location. Some are cancerous and aggressive.

Mr. A.H.'s seizures and left-side weakness are due to a right parietal lobe tumor affecting brain function. Post-surgery infection, tumor growth, and severe headaches result from increased intracranial pressure. Lethargy and vomiting are linked to the tumor's impact and anticonvulsant medication side effects.

The specific rationale for each of Mr. A.H.'s manifestations can be explained as follows:

1. Generalized tonic-clonic seizure: This was likely caused by the presence of the tumor in the right parietal lobe. Seizures can occur as a result of abnormal electrical activity in the brain, which can be triggered by the presence of a tumor.

2. Considerable weakness and sensory loss on his left side: These symptoms are consistent with the location of the tumor in the right parietal lobe, which could have caused damage or compression of the motor and sensory areas of the brain responsible for controlling the left side of the body.

3. Bacterial infection at the operative site: This could have occurred due to the surgical procedure, as invasive procedures carry a risk of introducing bacteria into the body. The weakened state of Mr. A.H.'s immune system post-surgery may have contributed to the development of the infection.

4. Tumor growth despite radiation and chemotherapy: The malignant nature of the tumor likely contributed to its resistance to treatment. Additionally, the diffuse nature of the tumor made complete elimination difficult, allowing it to continue growing.

5. Severe headaches and diplopia (double vision): These symptoms could be attributed to the increased size of the tumors in the brain, causing pressure on surrounding structures and interfering with normal brain function. Increased intracranial pressure from the growing tumors can lead to headaches, while pressure on the nerves controlling eye movements can result in diplopia.

6. Increasing lethargy: Lethargy can result from the effects of the brain tumors on cognitive function and overall brain function. Additionally, the presence of seizures and frequent vomiting can contribute to feelings of lethargy and fatigue.

7. Frequency of vomiting: Vomiting can be a side effect of increased intracranial pressure due to the growing tumors. It can also be a side effect of anticonvulsant medication, which Mr. A.H. was likely taking to manage his seizures. Medication to reduce vomiting frequency was given to alleviate this symptom.

Which major environmental factors can affect health?

genetics and obesity
poor water quality and obesity
poor air and water quality
genetics and poor air quality

Answers

Answer:

The answer is poor air quality and water quality

Answer:

poor air and water quality

Explanation:

Tasting involves many different cell-signaling processes that ultimately generate nerve signals transduced by membrane depolarization. Sweet tastes result in PIP2 hydrolysis, while salty tastes allow sodium ions to directly alter the membrane potential. What can you deduce about the signaling mechanisms for sweet and salty?

Choose one or more:

A. Sweet ligands bind to and close sodium channels, which starts a membrane potential.
B. Sodium ions directly enter the cells, indicating the signal is transduced by an ion channel.
C. Sweet and salty signaling pathways use the same taste receptor molecule, but with different efficacy on the sweet and salty taste center in the brain.
D. Sweet utilizes the GPCR signaling pathway, activating phospholipase C.

Answers

Answer:

B.  Sodium ions directly enter the cells, indicating the signal is transduced by an ion channel.

D. Sweet utilizes the GPCR signaling pathway, activating phospholipase C.

Explanation:

The taste received by the taste buds is processed through different channels

a) The Sweet, bitter, and umami tastes  are transduced by the GPCR (G-protein-coupled receptors) signaling pathway

b) Sour taste reaches the taste bud through the acidification of acid-sensitive membrane proteins with in the taste cell

c) The epithelial sodium channels in the renal tissues directly takes up the salty taste

Hence, option B and D are correct

Omega-3 and omega-6 essential fatty acids are readily available in leafy green plants. What is one way to ensure that animals raised for commercial purposes have enough of these fatty acids in their diets such that fatty acid supplementation is not needed

Answers

Answer:

Omega-3 and omega-6 essential fatty acids are readily available in leafy green plants. One way to ensure that animals raised for commercial purposes have enough of these fatty acids in their diets such that fatty acid supplementation is not needed is to allow the livestock adequate environment for natural grazing.

Explanation:

Animals raised on pasture are generally healthier and under less stress than those raised in confinement, making them hace omega-3 and omega-6 readily available in leafy graan plants. Pasture-based livestock farming reintegrates the cycle, putting livestock on grass or in another natural environment. These types of systems are also climate friendly.

Final answer:

To ensure that animals raised for commercial purposes get enough omega-3 and omega-6 essential fatty acids, natural grazing is encouraged. This practice enables the animals to obtain these vital nutrients from their diet directly, eliminating the need for supplements. Grass-fed animals typically have higher quantities of these fatty acids.

Explanation:

One way to ensure that animals raised for commercial purposes have enough omega-3 and omega-6 fatty acids in their diets without requiring fatty acid supplementation is by facilitating natural grazing. Leafy green plants are rich sources of these essential fatty acids. If commercial animals are allowed to graze naturally, they can obtain these essential nutrients directly from their diet.

By facilitating natural grazing, animals can get a balanced amount of essential fatty acids from their diets.Grass-fed animals have generally been shown to have higher amounts of omega-3 and omega-6 fatty acids in their meat as compared to animals fed with commercially prepared feed.This approach also supports the sustainability of farming practices and respects the animals' natural dietary needs.

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Which statement below is TRUE?

A)Crossing over shuffles genes between non-homologous chromosomes.

B)During meiosis, cells arrange their alleles so that beneficial alleles are passed on together.

C)Without crossing over, offspring would be genetically identical to parents.

D)New combinations of alleles arise from the random events of crossing over, independent assortment, and mutation.

Answers

Answer:

I think it is C.

Explanation:

C)Without crossing over, offspring would be genetically identical to parents.

Without crossing over in meiosis , offspring would be genetically identical to parents.

Meiosis is a type of cell division which occurs twice and forms four unique

daughter cells which have only one copy of chromosome from the parent.

This is as a result of the crossing over of the chromosome so that the parent

and offspring can have unique genetic makeup.

Meiosis is involved in sexual reproduction during the production of sperm and egg cells.

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Explain the cellular functions that occur when antibiotics attack a bacteria cell?

Thank you!

Answers

antibiotics target the cell wall, cell membrane, and the processes of protein and nucleic acids production in bacteria to rupture the cell.
Antibiotics target the cell wall, cell membranes, and the processes of protein and nucleic aids production in bacteria to reptile the cell.....In other words antibiotics target the cell wall and form a bridge like connection to form conjugation.

Can you tell the difference between female and male bacteria?

Answers

Answer:yes and no

Explanation:with the right tests but from eye only no

Use the following information to answer the following question below. Moss invades and establishes itself on bare rock, accumulating the beginnings of soil. After several years, enough soil has become established that grasses begin to grow where there was once bare rock. Without the moss building up soil, the grasses would have had no chance. The establishment of the mosses on bare rock and eventual addition of grasses represents intermediate succession. secondary succession. a climax ecosystem. primary succession.

Answers

Answer:

Primary succession.

Explanation:

Ecological succession refers to the changes involved in the species structure of a community that is established in a particular habitat over time. The succession is of two types: the primary succession and secondary succession.

When the succession takes place on the barren land then succession is considered primary succession.

In the given question, the moss invades and colonizes the rocks and breaks them into the soil. Here the moss species is known as the pioneer species and since the moss grows on the barren rock, therefore, is considered the primary succession.

Thus, primary succession is correct.

The Z disc is the: Group of answer choices separation between sarcomeres. electrical voltage at which a muscle cell fires an action potential. area of a sarcomere where only thick myofilaments are found. point where the axon and the sarcolemma meet. place where two cardiac muscle cells meet.

Answers

Answer:

Separation between sarcomeres.

Explanation:

The structure of the muscle fibre is composed of many functional units called sarcomere which is interrupted by the discs called Z-discs.

These Z-discs are made of the alpha-actin homodimers which allow the actin filament allows to bind to it along with other proteins.  The Z-discs since present at regular intervals in a muscle appears to separate the sarcomere and defines the boundaries of the sarcomere.

Thus, the selected option is correct.

In snapdragon plants, they can be red (dominant) or white (recessive). However, when you have a heterozygous plant, the flower is actually pink (incomplete dominance).

Two pink flowers are crossed.

Genotype possibilities:

RR:
Rr:
rr:

Phenotype possibilities:

Red:
Pink:
White:

Please help

Answers

It would be easier to put an image instead of explaining it. Here you are!

R = Red

r = white

RR = 25% - 25% chance of red

Rr = 50% - 50% chance of pink

rr = 25% - 25% chance of white

Which is the answer for it? I will appreciate the help

Answers

What do U need help with

Berkowitz and LePage (1967) found that frustrated men delivered more shocks when Group of answer choices
A) they were initially depressed.
B) badminton racquets happened to be in the room.
C) they had just received a shot that lowered their serotonin levels.
D) guns happened to be in the room.

Answers

Answer: D. Guns happened to be in the room.

Explanation: In studying different concepts of aggression, Berkowitz and Lapage(1967) found out that in their experiment, frustrated men delivered more shocks to their partners when guns rather than badminton racquets happened to be in the room.

Earth's tectonic plates
A.
do not move.
B.
move only up and down.
C.
are constantly in motion.
D.
move only once.

Answers

Answer:  

The answer is C

Explanation:

Tectonic plates, the massive slabs of Earth's lithosphere that help define our continents and ocean, are constantly on the move.

Sperm tails in the fruit fly Drosophila bifurca can reach up to 6cm long, which is over 20 times the length of the organism itself. Because the tails are so long, they aren’t able to provide the swimming force that other sperm tails are used for. Please provide a hypothesis as to why the fruit fly sperm has evolved to be so long.?

Answers

Explanation:

The length of the sperm in a few species is much larger or giant than the size of the animal-like observed in the Drosophila bifurca.

In this fruit-fly, the tails of the sperm are too long which could be accounted for many reasons:

1. The sexual selection prefers the long tails over the small tail.

2. The large sperms can displace the small sperms in the female reproductive organ.

3. The female reproductive organ increases the promiscuity of the large sperms that is favour the large sperms over the small sperms.

List two reasons why food is important.

Answers

Answer:

gives you energy, and for some animals helps them survive winter (bears)

Explanation:hope this helps god bless

1. Vitality.

A healthy diet has you glowing with vitality outside and in. Healthy food leaves you feeling energetic and raring to go!

2. Preserving youthful looks.

Healthy eating keeps your skin supple and radiant, your eyes bright and your hair in good condition.

Desquamation occurs in which layer

Answers

Answer:

Desquamation occurs in the outermost layer of the skin.

Explanation:

Desquamation is also known as skin peeling and it occurs in the outermost layer or membrane of a tissue such as the skin .

You are counseling a young Greek couple because both parents and their first-born son have been tested and found to be carriers of Beta thalassemia, an autosomal recessive severe hemoglobinopathy. They wish to know whether a current pregnancy is likely affected. Explain

Answers

Answer&Explanation:An individual with an autosomal dominant disorder, has a single mutant gene unless when their both parents are affected.

A person will have an autosomal dominant disorder if only a single parent is affected and if parent have autosomal dominant disorder only there is a 50% of inheriting a mutant gene.

In autosomal recessive disorders a person will get Ill if they inherit both mutant genes from both parents who are carriers . This person will be homozygous for the gene and will be affected by the disorder and this is highly likely to happen in their baby since they are both the carriers of this disorder.

Answer:

Beta thalassemia is an autosomal recessive disorder. It is usually inherited by children if both parents are carriers. It is a blood disorder that is characterized by decreased production of hemoglobin. Hemoglobin is an important protein in red blood cells that binds oxygen to be transported to other cells in the body.

Pregnant women with beta thalassemia can develop anemia due to the stress and other underlying factors. This can increase the chances of premature delivery. She may need more frequent blood transfusions during the pregnancy period for her health and the health of the baby.

Phototaxis is movement in response to which stimulus?​

Answers

Answer:

Phototaxis is a movement in response to light

Answer:

Light

Explanation:

Phototaxis is a kind of taxis, or locomotory movement, that occurs when a whole organism moves towards or away from a stimulus of light. This is advantageous for phototrophic organisms as they can orient themselves most efficiently to receive light for photosynthesis.

The seed color of the garden pea was used to derive Mendel's two laws: segregation and independent assortment. Now, we know that the Y allele codes for the enzyme converting green to yellow chlorophyll. The mutant allele, y, is caused by a loss-of-function mutation on this gene. Let's assume that this mutation manifests its phenotype through the haploinsufficiency mode. Answer the following questions.
P YY (Yellow) x yy (Green)
F1 Yy (?) x Yy (?)
F2 1YY (?) : 2Yy (?): 1yy (?)
1. Which color would be recognized as a dominant trait, and what would be ratio of F2 between Yellow and Green seeds? (You need to explain why)
2. In this situation, which breeding scheme should be the proper testcross and what will be the outcome of this testcross? (You also need to explain why)

Answers

Answer:1.Yellow color will be dominant and the ratio is Yellow to green allele is 3:1

2.A recessive test cross should be appropriate.The result will be all yellow colored pea plants.

Explanation:

Since Yy x Yy produces

1YY,2Yy and 1yy then it shows that YY and Yy are 3 yellow pea plants and 1yy green pea plant.

A recessive test cross should be used because a recessive genotype being homozygous can be noticed by its physical appearance

The forward and reverse PCR primers used for the amplification of a VNTR locus on chromosome number 4 are 20 bases and 21 bases long, respectively. The 3’ base of the forward primer is 53 bases away from the first repeat. The 3’ base of the reverse primer is 28 bases away from the first repeat in that direction. Each repeat unit is 60 bases in length. A person has, on one of their number 4 chromosomes, 6 repeats. How long (in bp) should its PCR product be?

Answers

The repeats which occur together on a chromosome are referred to as VNTR. The length of each repeat is 60bp.

The first primer is 20bp and is 53 bp away from 1st repeat. Therefore, the total length of sequence amplified by the first primer till 1st repeat = 20+53 = 73bp. Beyond this point 6 repeats on 60 bp are present, hence, the length becomes = 73 + (60X6) = 433bp.

Now the reverse primer which is 21bp in length is located 28bp from the repeat on its side. Reverse primer comes from the opposite direction, so it must be present after the 6 repeats.

The total length of the amplified region = 433 + 28 + 21 = 482 bp.

Final answer:

The PCR product for the given VNTR locus on chromosome number 4 should be 482 base pairs long.

Explanation:

The PCR product length can be calculated by adding the lengths of the forward primer, the reverse primer, and the number of repeat units, including the sequences between them. The forward primer is 20 bases long, and its 3' base is 53 bases away from the first repeat. Therefore, the forward primer covers 20 + 53 = 73 bases. Similarly, the reverse primer is 21 bases long and its 3' base is 28 bases away from the first repeat. Hence, the reverse primer covers 21 + 28 = 49 bases.

Each repeat unit is 60 bases long, and the person has 6 repeats. So, the length of the repeat units is 60 * 6 = 360 bases.

To calculate the PCR product length, add the lengths of the forward primer, the reverse primer, and the repeat units: 73 + 49 + 360 = 482 bases. Therefore, the PCR product should be 482 base pairs long.

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a. Bacteriophage MS2 carries its genetic information in RNA. Its chromosome is analogous to a polygenic molecule of mRNA in organisms that store their genetic information in DNA. The MS2 mini-chromosome encodes four polypeptides (i.e., it has four genes). One of these four genes encodes the MS2 coat protein, a polypeptide 129 amino acids long. The entire nucleotide sequence in the RNA of MS2 is known. Codon 112 of the coat protein gene is CUA, which specifies the amino acid leucine. If you were to treat a replicating population of bacteriophage MS2 with the mutagen 5-bromouracil, what amino acid substitutions would you expect to be induced at position 112 of the MS2 coat protein (i.e., Leu —> other amino acid)? (Note: Bacteriophage MS2 RNA replicates using a complementary strand of RNA and base-pairing like DNA.)

b.Would such mutations occur if a non-replicating suspension of MS2 phage was treated with 5-bromouracil?

Answers

Final answer:

Amino acid substitutions at codon 112 in MS2 phage could occur due to mispairing caused by the mutagen 5-bromouracil during replication, potentially resulting in a different amino acid being coded. However, mutations would not occur in a non-replicating suspension of MS2 since 5-bromouracil incorporation requires active replication.

Explanation:

If you were to treat a replicating population of bacteriophage MS2 with the mutagen 5-bromouracil, you might expect amino acid substitutions at codon 112 of the MS2 coat protein, which commonly specifies the amino acid leucine (Leu). Given that 5-bromouracil can substitute for thymine in DNA replication, and considering RNA's analogous base uracil, during RNA replication, this mutagen could potentially cause uracil to mispair, leading to a substitution mutation. Specifically for codon 112 (CUA), a possible mutation could turn it into UUA which would likely also code for leucine, or into CUG, which also encodes for leucine due to the degeneracy of the genetic code. A more significant change, such as substituting cytosine with uracil, creating UUA or UUG, could result in a phenylalanine being placed instead of leucine, since these codons specify phenylalanine.

For the second part of the question, mutations from 5-bromouracil would not occur in a non-replicating suspension of MS2 phage since mutations require nucleic acid replication for incorporation into the genetic material, and 5-bromouracil would not be incorporated without active replication.

An organism in which a parasite or virus lives is called a

Answers

Answer:

the answer is a parasite

Answer:

A Host

Explanation:

If a parasite is living, its not going to live on something it can't benefit from, this is called a host.

Think of a cat with fleas, would a flea (the parasite) live on another parasite? NO

THEY WOULD LIVE ON A HOST

true or false: natural resources can be man made

Answers

Answer:

False

Explanation:

Natural resources are made by nature

Answer:

False

Explanation:

Natural resources are resources that aren't made with any human action. If a resource is made by man, they would be called man-made resources of human-made resources.

The citric acid cycle is a stage of catabolism that oxidizes acetate into carbon dioxide and generates energy. There are eight enzymes involved in the citric acid cycle.

Which enzymes have an α‑keto acid substrate?

A. fumarase
B. α‑ketoglutarate dehydrogenase
C. malate dehydrogenase
D. citrate synthase

Answers

Answer:D

Explanation:

The loss of an organism at the bottom of a food chain negatively impacts all organisms in the chain.
Please select the best answer from the choices provided
От
OF

Answers

Answer:

True

Explanation:

It would break the natural order each row dying or having to adjust messing up another food chain

Muscle is an example of which level of organization?
A plant cell is an example of which level of organization?
Our skeleton is an example of which level of organization?

Answers

Explanation:

muscle is an example ofthe tissue level of organization

a plant cell is an example of the cell level of organization

our skeleton is an example of the system level of organization☺


In which of these ways might an ectotherm respond to changes in environmental temperature?
fight or flight​

Answers

Answer: move elsewhere  b

Explanation:

Answer:  b

Explanation:

How does carbon become locked inside the earth?

A) tree roots expel carbon into the soil as they grow

B) humans use machines to pump carbon into large underground tanks

C) rocks become richer in carbon as time goes on

D) the carbon-rich bodies of plants and animals decay into the earth after they die

Answers

Answer:

a) tree roots expel carbon into the soil as they grow.

Explanation:

Roots offer physical anchoring to the soil of the tree, with water uptake and inorganic nutrition as its principal activity.

The absorption and the transfer of ions and the growth and maintenance of the roots themselves require energy, therefore releasing CO2 into the ground and into the air.

A diverse ground microbiota exists underneath the earth in addition to the plant roots. Their work results in carbon dioxide being released into the soil, which flows into the air. This soil microbiota is responsible for decomposing the litter and, in general, any dead organic matter in the soil. It may breathe more than half of the total soil respiration. Soil temperature and humidity strongly affect root and microbial activity. In warm and moderately moist soils, soil breathing is highest.

Final answer:

The correct answer to how carbon becomes locked inside the Earth is option D: the carbon-rich bodies of plants and animals decay into the earth after they die.

Explanation:

This natural process is part of the carbon cycle, where carbon is stored in soil as organic carbon due to the decomposition of living organisms by decomposers or from the weathering of terrestrial rock and minerals. Over long periods, this material might be buried and converted into fossil fuels, which are a type of non-renewable resource because they are regenerated very slowly, if at all. These fuels include coal, oil, and natural gas, which are the anaerobic remains of plants and algae that lived millions of years ago.

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During which stage of mitosis do the chromosomes attach to the spindle fibers and line up in the center of the cell
Anaphase
Interphase

Metaphase

Telophase

Answers

Answer:

The answer is

Explanation:

Metaphase

Answer:

the answer is c!!!! i took the test so i know its c

Explanation:

Which symbolizes a molecule of a compound
He
Be
N2
NaCl

Answers

Answer:

NaCl

Explanation:

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