In Antoine Lavoisier’s classic experiment, mercuric oxide is heated in a sealed container. The solid red powder is changed into two products: silver liquid mercury and oxygen gas. If Lavoisier heated 100 grams of powdered mercuric oxide to produce 93 grams of liquid mercury, how much oxygen would be released? A) 7 grams B) 16 grams Reactivate C) 32 grams D) 93 grams
Answers
Answer 1
Answer:
A ) 7 GRAMS
Explanation:
7 grams.
The sum of the reactants must equal the sum of the products.
Reactant = 100 grams
Products = 100 g mercuric oxide - 93 g mercury which equals 7 grams oxygen.