The distance MN is 9/(9+1) = 9/10 of the distance MP, so is
... MN = (9/10)×MP = (9/10)×2 = 9/5
The distance MK is 1/4 that, so is ...
... MK = (1/4)×(9/5) = 9/20 . . . . . matches selection (C)
Answer:
C
Step-by-step explanation:
the answer is C. give the person the brainly :) ignore this answer
what is the solution of the linear-quadratic system of equations?
will give brainliest and extra points!!!!!
Answer:
d. (1, 3) and (-3, -1)
Step-by-step explanation:
Equating the expressions for y, we have ...
... x² +3x -1 = y = x +2
Subtracting x+2 gives ...
... x² +2x -3 = 0
... (x +3)(x -1) = 0 . . . . . factored form
... x = -3, 1 . . . . . . . . . . .values that make the factors zero
The second equation tells us, y = x+2, so
... For x = -3, y = -3 +2 = -1. The solution is (-3, -1)
... For x = 1, y = 1 +2 = 3. The solution is (1, 3)
(- 3, - 1 ) or (1, 3 )
Since both equations express y in terms of x, equate both sides
x² + 3x - 1 = x + 2 ( subtract x + 2 from both sides )
x² + 2x - 3 = 0
(x + 3 )(x - 1 ) = 0
equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
x - 1 = 0 ⇒ x = 1
Substitute these values into either of the 2 equations for y
y = - 3 : y = - 3 + 2 = - 1 ( using y = x + 2 )
x = 1 : y = 1 + 2 = 3
solutions are (- 3, - 1 ) or (1, 3 )
Graph ΔRST with vertices R(6, 6), S(3, –6), and T(0, 3) and its image after a reflection over the y-axis.
under a reflection in the y-axis
a point (x, y ) → (- x, y ), thus
R(6, 6 ) → R' (- 6, 6 )
S(3, - 6 ) → S'(- 3, - 6 )
T(0, 3 ) → T'(0, 3 )
Plot the sets of points and graph them
Answer: The graph is attached below.
Step-by-step explanation: Given that the co-ordinates of the vertices of ΔRST are R(6, 6), S(3, –6), and T(0, 3).
We are given to graph ΔRST and its image after a reflection over the Y-axis.
After reflection across Y-axis, the co-ordinates of the vertices of ΔRST will follow the following transformation :
(x, y) ⇒ (-x, y), because the sign before the x-coordinates of the vertices will get reversed.
Therefore, the co-ordinates of the vertices of the image of ΔRST will be
R'(-6, 6), S'(-3, -6) and T'(0, 3).
The graphs of both the triangles, ΔRST and its image after reflection R'S'T' is drawn in the attached figure.
We see that the vertices T and T' coincide with each other.
Thus, the graph is shown below.
the number 3456 is divisible by wich single-digit number?
I'm assuming what you mean is what can you divide 3456 by to get a natural number.
First of all every number is divisible by 1.
Every even number is divisible by 2, so since 3456 is an even number, it can be divided by 2. That would equal 1728.
2456 can also be divided by 3, to get 1782.
You can also divide it by 4, to get 865.
Divided by 6, it's 576.
Divided by 8, it's 432.
And lastly, 3456 divided by 9 is 384.
So, there isn't just one single-digit number you can divide 3456 by to get a natural number. You can divide it by 1,2,3,4,6,8, and 9.
Hope that helps!
Find the value of x and y so that both proportions will be correct:
x:1 2 /3=y:3 1/3 and y:1.5=0.2:0.75
Note that a:b = c:d is the same as a/b = c/d
y:1.5=0.2:0.75 same as y/1.5 = 0.2/0.75
y = 0.4
x: 1 2/3=y:3 1/3 same as x/1 2/3 = y / 3 1/3
x = y/2 = 0.2
y:1.5=0.2:0.75
so y=1.5*0.2/0.75=0.4
x:1 2 /3=y:3 1/3
so x=1 2/3*0.4/3 1/3=0.2
Find the quotient of 6/8 ÷ 3/-4
Step-by-step explanation:
6/8 / 3/4 = 1
How do u Graph Y<-1/4x-1
When you replace the comparison symbol (<) with an equal sign (=), you get the equation of a line in slope-intercept form:
... y = mx + b
where m is the slope, and b is the y-intercept.
Your equation has m = -1/4 and b = -1. To graph this line, find the point (0, -1) on the y-axis. To find another point on the line, you can use the slope value (rise/run = -1/4), which tells you the line "rises" -1 for each "run" of +4. That is, another point on the line will be 4 units to the right and 1 unit down, at (4, -2). Working in the other direction (to the left, instead of to the right), the -1/4 slope tells you the point 4 units left and 1 unit up (-4, 0) will also be on the line. Draw a dashed line through these points,
The dashed line you just drew is the boundary of the solution region. It is dashed because the line itself is not part of the solution. (Those points do not meet the requirement for "less than.")
Appropriate values of y are ones that are less than those on the line, so the solution region is indicated as being the half-plane below the line. You indicate this by shading the solution region. (See the attachment for an example of the way this can be graphed.)
_____
If the comparison is ≤ instead of <, then the line is solid (not dashed), indicating it is part of the solution region. If the comparison is > or ≥, then the shaded region is above the line, where y-values are greater than those on the line.
Can someone please help with number 3 and 4 thank you
Answer:
Step-by-step explanation:
3) Purchase price of the home is $585000
Cash down payment is $ 175000
Amount to taken for loan
[tex] = 585000-175000 = $410000[/tex]
Therefore, loan to value ratio will be
[tex]= \frac{loan amount}{value}[/tex]
[tex] =\frac{410000}{585000}[/tex]
On solving
[tex]=\frac{410}{585}[/tex]
On simplifying
[tex] =\frac{82}{117}[/tex]
The loan to value ratio will be [tex]82:117[/tex]
4) it is given that
Fixed monthly expences i.e. debt [tex]=$1836[/tex]
Total income per month [tex] =$4934[/tex]
Therefore debt to income ratio will be
[tex]= \frac{debt}{income}[/tex]
[tex]= \frac{1836}{4934}[/tex]
On simplifying we get
[tex]=\frac{918}{2467}[/tex]
Therefore debt to income ratio will be
[tex]918:2467[/tex]
im quite confused, please help :((
You need to pick from each column depending on what makes sense - they are mixed (some numbers are roots, some cubes, in the same column).
On the order:
3 - 27
4 - 64
5 - 125
512 - 8
8 - 2
729 - 9
216 - 6
1 - 1
Answer:
as>JDKFas;lkdjfsa;lkdfjas;kldfjlakdjfalsdkfjakdkdkdlddd
Step-by-step explanation:
what's the difference between 1968 and 3000
Hey mate!!
Answer⤵
The difference between 1,968 and 3,000 is 1,032.
3,000-1,968=1,032.
Answer confirmed= 1,032
Hope it helps you! ヅ
To find the difference between 1968 and 3000, you need to subtract the smaller number from the larger one.
Step 1: Identify the larger number. In this case, 3000 is larger than 1968.
Step 2: Subtract the smaller number from the larger number.
3000 - 1968 = 1032
So, the difference between 1968 and 3000 is 1032.
In △ABC, point M is the midpoint of AC , point D∈ BM so that MD:DB=1:4. If ACMD=7 ft2, find ABDC, AAMB, and AABC.
Note that
[tex]A_{CMD}=\dfrac{1}{2}\cdot MC\cdot h=7\ sq. ft.[/tex]
Let H be the height of triangle ABC. Since [tex]\dfrac{MD}{DB}=\dfrac{1}{2},[/tex] then
[tex]\dfrac{H}{h}=\dfrac{5}{1}, \\ \\H=5h.[/tex]
1.
[tex]A_{BDC}=A_{MBC}-A_{CMD}=\dfrac{1}{2}\cdot MC\cdot H-\dfrac{1}{2}\cdot MC\cdot h=\dfrac{1}{2}\cdot MC\cdot (5h-h)=\\ \\=4\cdot \dfrac{1}{2}\cdot MC\cdot h=4\cdot 7=28 sq. ft.[/tex]
2. M is midpoint of AC, then AM=MC.
[tex]A_{AMB}=\dfrac{1}{2}\cdot AM\cdot H=\dfrac{1}{2}\cdot MC\cdot 5h=5\cdot \dfrac{1}{2}\cdot MC\cdot h=5\cdot 7=35\ sq. ft.[/tex]
3.
[tex]A_{ABC}=\dfrac{1}{2}\cdot AC\cdot H=\dfrac{1}{2}\cdot 2MC\cdot 5h=10\cdot \dfrac{1}{2}\cdot MC\cdot h=10\cdot 7=70\ sq. ft.[/tex]
Answer:
[tex]A_{BDC}=28\ sq. ft,\ A_{AMB}=35\ sq. ft,\ A_{ABC}=70\ sq. ft.[/tex]
Answer:
28,35,70
Step-by-step explanation:
Use the given conditions to write an equation for the line in point-slope form and in slope-intercept form. Passing through (minus−44,minus−88) and parallel to the line whose equation is y equals negative 3 x plus 3y=−3x+3 Write an equation for the line in point-slope form.
The equation of the line through the given point parallel to the given line ...
in point-slope formin slope-intercept formSolutionThe given line's equation is is slope-intercept form. The slope is -3, the coefficient of x.
In point-slope form, the equation of a line with slope m through point (h, k) is ...
... y -k = m(x -h)
For slope m=-3 and point (h, k) = (-4, -8) the equation of the line is ...
... y +8 = -3(x +4) . . . . equation in point-slope form
We can eliminate parentheses and add -8 to put this equation in slope-intercept form.
... y +8 = -3x -12
... y = -3x -20 . . . . equation in slope-intercept form
Answer:
Step-by-step explanation:
The answer is B
y=2x+11
Q # 2 i need help please
Answer: First option. The slope is -4 and the y-intercept is 2.
Solution:
y=-4x+2
When the equation is in the form:
y=mx+b (y isolated)
The coefficient of the variable "x" is the slope "m" of the right line. In this case the coefficient of "x" is -4, then the slope "m" is -4.
The indeoendent term is the y-intercept "b". In this case the independent term is +2, then the y-intercept "b" is 2.
Solution:
Given equation of line [tex]y=-4x+2[/tex].
The given equation is in the form of y=mx+b, y is isolated. So the coefficient of x is the slope of the line.
The slope of the line y=-4x+2 is -4
To find the y-intercept of the equation, substitute [tex]x=0[/tex] in the equation,
[tex]\Rightarrow y=-4(0)+2\\\Rightarrow y=2[/tex]
So, y-intercept of the equation is [tex](0,2)[/tex].
Hence, the slope is -4 and y intercept is 2. (first option)
For what value(s) of k will the relation not be a function?
A = {(3k−4, 16), (4k, 32)}
We won't have a function if for same value of x in (x,y) we get different values y.
So first step: figure out k so that the first coordinate (x) is the same:
3k-4=4k | solve for k
k = -4
no check the values y for the elements of the relation
x = 3k-4 = -12-4=-16
so at -16 we get (-16,16) and (-16, 32), which mean for k=-4 the relation is not a function.
Let me know if you have any questions.
Answer:
K= -4
Step-by-step explanation:
Since it isn't possible that (3k-4, 16) is going to be equal to (4k, 32) in terms of positive numbers, you will have to go to the negative side of the number line.
K has to equal 4 because 3 · -4 = -12, and -12 minus 4 is equal to -16.
And since 4 · -4 = -16, K has to equal - 4.
write a point-slope equation for the line that passes through the point (6,8) and is parallel to the line given by y=-5x+4
Answer:
y -8 = -5(x -6)
Step-by-step explanation:
The point-slope form of the equation for a line is generally written ...
y -k = m(x -h)
for slope m and point (h, k).
The slope of your parallel line is the same as the slope of the reference line, -5. So your equation is ...
y -8 = -5(x -6)
On spring break, Mirna went to Florida. She collected 6 seashells. The following set of data shows the weight of each seashell in ounces. 16, 17, 13, 12, 18, 20 What is the mode of this set of data?
The set of seashell weights that Mirna collected (12, 13, 16, 17, 18, 20) does not have a mode because all values appear only once.
The mode of a set of data refers to the number that appears most frequently. In the case of the weights of the seashells Mirna collected in Florida, the data set is: 12, 13, 16, 17, 18, 20. To find the mode, we look for the value that occurs the most:
12 ounces - occurs once13 ounces - occurs once16 ounces - occurs once17 ounces - occurs once18 ounces - occurs once20 ounces - occurs onceSince all numbers occur only once, there is no number that appears more frequently than the others. Therefore, this set of data does not have a mode.
Wich product is equivalent to 25x2 -16
25x²-16 is the difference of two squares, so can be written as the product ...
... (5x -4)(5x +4)
or
... (5x +4)(5x -4)
Answer:
[tex](5x+4)(5x-4)[/tex]
Step-by-step explanation:
25x^2- 16
To find out the product that is equivalent to the given expression we need to factor the given expression
we write the numbers in square form
25 = 5*5 = 5^2
16 = 4*4 = 4^2
5^2x^2 - 4^2
[tex](5x)^2- 4^2[/tex]
we apply difference in square formula
a^2 - b^2 = (a+b)(a-b)
[tex](5x)^2- 4^2=(5x+4)(5x-4)[/tex]
How would you solve 3x=18
Hi!
[tex]3x=18[/tex]
[tex]\frac{3x}{3}=\frac{18}{3}[/tex]
[tex]x=6[/tex]
Explanation: This question is super easy on this question. First you had to divide by 3 from both sides. And simplify, it gave us the answer is x=6 is the right answer. Hope this helps! And thank you for posting your question at here on Brainly. And have a great day. -Charlie
How do you graph these?
Answer:
See the attached.
Step-by-step explanation:
A graph of f' is a graph of the slope of the function. Your function f(x) is piecewise linear, so different sections of its graph have different constant values of slope.
In the intervals (-5, -2) and (0, 2), the slope is -1. (The graph has a "rise" of -1 for each "run" of 1.) So, in those intervals, the graph of f' looks like a graph of y=-1.
In the interval (-2, 0), the rise is 2 for a run of 2, so the slope is 2/2 = 1. The graph of f' in that interval will look like a graph of y=1.
In the interval (2, 5), the rise of f(x) is 1 for a run of 3, so the slope in that interval is 1/3. There, the graph of f' will look like a graph of y=1/3.
If you want to get technical about it, the slope is undefined at x=-2, x=0, and x=2. Therefore, the line segments that make up the graph of f' ought to have open circles at those points, indicating that f' is not defined.
The circle below is centered at the point (4, -3) and has a radius of length 3. What is its equation?
Answer:
(x-4)² + (y+3)² = 9
Step-by-step explanation:
The equation of a circle of radius r centered at (h, k) is ...
... (x-h)² + (y-k)² = r²
Subsituting your given values gives ...
... (x -4)² +(y -(-3))² = 3²
... (x -4)² +(y +3)² = 9
If f(x) = -4x^2 - 6x - 1 and g(x) = -x^2 - 5x + 3, find (f + g)(x).
B
note that (f + g)(x) = f(x) + g(x)
f(x) + g(x) = -4x² - 6x - 1 - x² - 5x + 3 ( collect like terms )
= - 5x² - 11x + 2
Answer:
The correct option is B.
Step-by-step explanation:
The given functions are
[tex]f(x)=-4x^2-6x-1[/tex]
[tex]g(x)=-x^2-5x+3[/tex]
Using the p addition property of functions (f + g)(x) can be written as
[tex](f+g)(x)=f(x)+g(x)[/tex]
Substitute the values of each function in the above equation.
[tex](f+g)(x)=-4x^2-6x-1-x^2-5x+3[/tex]
Combine like terms.
[tex](f+g)(x)=(-4x^2-x^2)+(-6x-5x)+(-1+2)[/tex]
[tex](f+g)(x)=-5x^2-11x+2[/tex]
Therefore the correct option is B.
Graph f(x)=−23x−3 .
Lol plx i need help
Answer:
Points (0,-3) and (-3,-1) work, I got a 100% on the test.
given the function f(x)=3x -2 and g(x)= x+2/3 complete parts A and B.
A. Find f(g(x)) and g(f(x)). Include your work in your final answer.
B. Use complete sentence's to explain the relationship that exists between the composition of the functions. F(g(x)) and g(f(x)).
First, I should point out that g(x) should be written as g(x)=(x+2)/3, otherwise the problem is confusing.
[tex]f(x)=3x-2 \enspace g(x)=\frac{x+2}{3}[/tex]
(A) [tex]f(g(x))=3(\frac{x+2}{3})-2=x\\g(f(x))=\frac{3x-2+2}{3}=x[/tex]
(B) Since [tex]f(g(x))=x[/tex] and [tex]g(f(x))=x[/tex], it holds that
[tex]f(g(x))=g(f(x))[/tex] for all x. This means the composed functions are *identical*
A
f(g(x)) = f([tex]\frac{x+2}{3}[/tex]) = 3([tex]\frac{x+2}{3}[/tex]) - 2 = x + 2 - 2 = x
g(f(x)) = g(3x - 2) = [tex]\frac{3x-2+2}{3}[/tex] = [tex]\frac{3x}{3}[/tex] = x
B
Since both composite functions f(g(x)) and g(f(x)) equal x
This indicates that the functions f(x) and g(x) are inverse functions
If s = 1/4 unit and A = 80s^2, what is the value of A, in square units? ____ square unit(s). (Input whole number only.)
If s = 1/4 unit and A = 80s^2
A = 80 (1/4)^2
A = 80 (1/16)
A = 5
Answer
5 square units
5 square units
substitute s = [tex]\frac{1}{4}[/tex] into the equation
A= 80 × ([tex]\frac{1}{4}[/tex])² = 80 × [tex]\frac{1}{16}[/tex] = [tex]\frac{80}{16}[/tex]= 5 square units
Plz hurry A board 12 3/4 feet long is cut so that 9 7/8 feet are left. What length of the board was cut off? A) 21 2 ft B) 27 8 ft C) 31 2 ft D) 37 8 ft
2 7/8 ft
Explanation:We presume no length was lost in the cut, so that ...
... (remaining length) + (cut off length) = (original length)
Then ...
... (cut off length) = (original length) - (remaining length)
... = 12 3/4 - 9 7/8
... = (12 - 9) + (3/4 - 7/8)
... = 3 + (6/8 -7/8)
... = 3 - 1/8
... = 2 7/8
The cut off length was 2 7/8 feet.
Is it possible to find an edge length that would be perfect for a cube with a volume of 30 cubic units? Explain!
Yes ,
side ×side×side= side^3 =volume of cube
=>side^3=30
=>side = 30^1/3-answer
I need to prove that A’B’= A’D’ but i keep going in circles.
You have the figure in the picture, the hypothesis are:
AA’= (1/2)AB
BB’=(1/2)BC
CC’=(1/2)CD
DD’=(1/2)DA
These are all vectors!
It can't be proven because it isn't so.
You can show that A'B' = C'D' because each is half of AC (from the midsegment theorem).
A worm travels 1250 mm how many meters did the worm
Help ASAP plsssssssssss
answer:
1. 24
2. -6
work:
1.
[tex]5n + 3n[/tex]
[tex]5 (3) + 3 (3)[/tex]
[tex]15 + 9[/tex]
24
2.
[tex]9 (x -7) - y[/tex]
[tex]9 ( (11) -7) - 19[/tex]
[tex]9 + 4 - 19[/tex]
[tex]13 - 19[/tex]
[tex]-6[/tex]
hope this helps! ❤ from peachimin
1. How to get answer:
5(3)+3(3) (now you don't have to use parenthesis but you need to multiply these two because the n represents the times.The answer for number one would be 15 + 9 equals 24.Answer is 242. How to get answer:
9(x-7)-y (you can use the distributive property for the first one but you figured out one of two of the variables so it should look like this 9(11-7)-19=9(11-7)-19 now you can use distributive property multiply 9 times 11 which equals 99 and then multiply 9 times 7 which equals 63.Now that you have the 9 out of the way it should look like this (99-63)-19 now we can use the order of operations 99-63 equals 36.The last step should be 36 - 19 = 17.The answer is 17.Flannery used 30 lilies and 78 roses to create six identical flower arrangements. Write an equation to describe the relationship between l, the number of lilies, and r, the number of roses.
The equation to describe the relationship between the number of lilies and roses is l/30 = r/78. This equation represents the proportion between the number of lilies and roses used in each arrangement.
Explanation:The relationship between the number of lilies (l) and the number of roses (r) can be described by the equation l/30 = r/78. This equation represents the proportion between the number of lilies and roses used in each arrangement. By setting up this proportion, we can determine the ratio of lilies to roses in each arrangement.
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PLEASEE HELPPP!!!!
What is the equation of a line that passes through the point (5, −4) and is parallel to the line whose equation is 2x + 5y = 10?
Enter your answer in the box
y = - [tex]\frac{2}{5}[/tex] x - 2
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
rearrange 2x + 5y = 10 into this form
subtract 2x from both sides
5y = - 2x + 10 ( divide all terms by 5 )
y = - [tex]\frac{2}{5}[/tex] x + 2 ← point- slope form with slope m = - [tex]\frac{2}{5}[/tex]
Parallel lines have equal slopes hence
y = - [tex]\frac{2}{5}[/tex] x + c is the partial equation of the parallel line
to find c, substitute ( 5, - 4 ) into the partial equation
- 4 = - 2 + c ⇒ c = - 4 + 2 = - 2
y = - [tex]\frac{2}{5}[/tex] x - 2 ← equation of parallel line
The equation of the line that is parallel to 2x + 5y = 10 and passes through the point (5, -4) is y + 4 = (-2/5)x + 2.
Explanation:To find the equation of a line that is parallel to another line, we need to use the fact that parallel lines have the same slope. First, let's write the given equation in slope-intercept form (y = mx + b), where m represents the slope:
2x + 5y = 10
5y = -2x + 10
y = (-2/5)x + 2
Since the given line has a slope of -2/5, the parallel line will also have a slope of -2/5. Now, we can use the point-slope form of a line (y - y1 = m(x - x1)) to find the equation. Plugging in the coordinates of the point (5, -4):
y - (-4) = (-2/5)(x - 5)
y + 4 = (-2/5)(x - 5)
y + 4 = (-2/5)x + 2
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