In the absence of air resistance and friction, what will happen to the velocity of an object going at 20 m/s E?

Answers

Answer 1
In the absence of any other forces, the object will continue to move at 20 m/s E.

In fact, Newton's second law states that the resultant of the forces acting on an object is equal to the product between the mass and the acceleration of the object:
[tex]\sum F = ma[/tex]
therefore, if there are no forces acting on the object, the term on the left is zero, and the acceleration of the object is zero as well. This means that the object will continue its motion with constant speed, and in the same direction.

Related Questions

PLEASE PLEADE HELP!?!?

The universe could be considered an isolated system because (2 points) Select one:
a. many people think that no energy or matter exists outside the universe.

b. energy and matter are created in the universe and flow freely into and out of the universe.

c. energy is created outside the universe and matter is created within the universe.

d. energy is created in the universe and matter is transferred out of the universe.

Answers

A. since the universe has no matter or energy on the outside

Answer: a. many people think that no energy or matter exists outside the universe.

Explanation: The universe isolated because everything is within it and nothing is on the outside. There is no exchange of energy or matter between the universe and its surroundings. Thus since it is isolated, there can be no exchange of energy with anything.

Kitty Genovese was stabbed to death while neighbors looked on. Nobody went out to help and only later did someone call the police for help. This event led psychologists to create a new term called _____.

Answers

Who is Kitty Genovese?!??!??!!?!!!???!

Do u know mike genova

A charged particle is projected with its initial velocity parallel to a uniform magnetic field. what is the resulting path? 1. parabolic arc. 2. circular arc. 3. straight line parallel to the field. 4. straight line perpendicular to the field. 5. spiral.

Answers

If a charged particle is projected with its initial velocity parallel to a uniform magnetic field, then the resulting path would be a straight line parallel to the field, therefore the correct answer is option 3.

What is a magnetic field?

A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted .

As given in the problem if a  charged particle is projected with its initial velocity parallel to a uniform magnetic field then we have to find out what would be the resulting path of the particle .

Thus , the right response is option 3, as the path of a charged particle projected with its starting velocity parallel to a uniform magnetic field would be a straight line parallel to the field .

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a type of rock that forms when particles from other rocks or the remains of plants and animals are pressed and cemented together

Answers

A sedimentary rock is a type of rock that forms when particles from other rocks or the remains of plants and animals are pressed and cemented together.

Sedimentary rock is formed from the compaction and cementation of sediment originating from other rocks or organic material. This process results in various types of sedimentary rocks, like sandstone and shale.

The type of rock that forms when particles from other rocks or the remains of plants and animals are pressed and cemented together is known as sedimentary rock. These rocks are created through a multi-step process starting with the deposition of sediment that comes from the weathering and erosion of pre-existing rocks (clasts), or from the accumulation of plant and animal material. Over time, these deposited sediments may harden into rock through two main processes:

Compaction: where sediments are squeezed together under the weight of sediments above them.

Cementation: where minerals fill in the spaces between the loose sediment particles.

This process creates various types of sedimentary rocks, such as clastic rocks which are fragments compacted and cemented together, and organic sedimentary rocks which are formed from the lithification of organic material. Examples of sedimentary rocks include sandstone, formed from cemented sand; shale, formed from compressed mud and silt; and conglomerate, composed of cemented gravel and pebbles.

When touched by a plastic straw, the metal sphere will do what?

Answers

I believe that if you touch a metal sphere with a plastic straw, the straw would not have enough strength to push it. So in that case, the metal sphere will not move and will stay in one place.

Please rate a 5 star

At what rate must electrons in a wire vibrate to emit microwaves with a wavelength of 1.00 mm

Answers

The equation to use is v=fλ where v is the speed of light, f is the frequency, i.e. the rate at which they vibrate, and λ is the wavelength in meters.

Rearrange the above equation and you get f=v/λ. So the answer is f=300000000/0.001 or 300GHz.

Answer:

f = 3×10¹¹ Hz

Explanation:

Relation ship between frequency and wavelength

"The wave speed (v) is defined as the distance traveled by a wave per unit time. If considered that the wave travels a distance of one wavelength in one period,

ν=λ/T

As we know that T = 1/f, hence we can express the above equation as,

V = f λ

The wave speed is equal to the product of its frequency and wavelength, and this implies the relationship between frequency and wavelength."

The relation between frequency and wavelength is  

λ×f = c

c = speed of light = 3×10⁸ m/s

λ = 1.00 mm = 10⁻³ m

f=c/λ

f=(3×10⁸ m/s)/   10⁻³ m

f = 3×10¹¹ Hz

where should the property "little voltage loss across long distances" be placed in a Venn Diagram?
A) direct current
B) alternating current
C) both alternating and direct current
D) neither alternating nor direct current

Answers

The correct answer for the question, "Where should the property "little voltage loss across long distances" be placed in a Venn Diagram?" is :  B) alternating current. 
A type of current that periodically reverses in direction is called alternating current. 

The answer is B i know this because i just did it on usatestprep

For a certain transverse wave, the distance between two successive crests is 1.20 m and eight additional crests pass a given point along the direction of travel every 13.00 s. calculate the wave speed.

Answers

The distance between two succesive crests of a wave corresponds to its wavelength, therefore the wavelength of this wave is
[tex]\lambda=1.20 m[/tex]

The frequency of a wave is the number of crests that passes through a given point in a certain time; therefore, for this wave it is:
[tex]f= \frac{N}{t}= \frac{8}{13.00 s}=0.62 Hz [/tex]

And now we can calculate the wave speed, which is given by the product between the wavelength and the frequency:
[tex]v= \lambda f = (1.20 m)(0.62 Hz)=0.74 m/s[/tex]

Final answer:

The wave speed is calculated using the frequency and the wavelength. With the provided distance between crests (1.20 m) and the time for crests to pass (13 s), the wave speed is found to be approximately 0.8308 m/s.

Explanation:

The distance between two successive crests of a transverse wave is equal to one wavelength. If eight additional crests pass a given point in 13 seconds, it means that nine crests in total pass that point in 13 seconds because the first crest is observed at the beginning of the timing. The speed of the wave (v) can be calculated using the formula v = frequency x wavelength. Here, the wavelength (λ) is given as 1.20 meters.

To find the frequency, we use the number of waves passing a point divided by the time taken. Therefore, the frequency (f) is 9 crests / 13 seconds = 0.6923 Hz (where Hz represents Hertz or cycles per second).

Using the wave speed formula, we obtain the speed: v = 0.6923 Hz x 1.20 m = 0.8308 m/s. Thus, the wave speed is approximately 0.8308 meters per second.

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An ice skater starts a spin with her arms stretched out to the sides. she balances on the tip of one skate to turn without friction. she then pulls her arms in so that her moment of inertia decreases by a factor of two. in the process of her doing so, what happens to her kinetic energy?

Answers

I₁ = initial moment of inertia before pulling in the arms

I₂ = final moment of inertia after pulling in the arms = I₁ /2

w₁ = initial angular velocity before pulling in the arms

w₂ = final angular velocity after pulling in the arms

using conservation of angular momentum

I₁ w₁ = I₂ w₂

I₁ w₁ = (I₁/2 ) w₂

w₂ = 2 w₁

KE₁ = initial rotational kinetic energy before pulling in the arms = (0.5) I₁ w²₁

KE₂ = final rotational kinetic energy after pulling in the arms = (0.5) I₂ w²₂

Ratio of final rotational kinetic energy to initial rotational kinetic energy is given as

KE₂ /KE₁ = (0.5) I₂ w²₂/((0.5) I₁ w²₁ )

KE₂ /KE₁ = ((I₁/2 ) (2 w₁)²)/(I₁ w²₁)

KE₂ /KE₁ = 2

KE₂ = 2 KE₁

hence the kinetic energy becomes twice

a 920-g empty iron kettle is out on a hot stove. how much heat must the kettle absorb to raise its temperature 15.0 Celsius to 93.0 celsius the especific heat capacity iron is 470 j/kg * k

Answers

Final answer:

The iron kettle must absorb 33,768 joules of heat energy to raise its temperature from 15.0 Celsius to 93.0 Celsius.

Explanation:

To calculate the amount of heat the iron kettle must absorb, we can use the formula:

q = mcΔT

where:

q is the heat absorbed (in joules)m is the mass of the iron kettle (in grams)c is the specific heat capacity (in J/g°C)ΔT is the change in temperature (in Celsius)

Plugging in the given values:

q = (920g) x (0.470 J/g°C) x (93.0°C - 15.0°C)

q = (920g) x (0.470 J/g°C) x (78.0°C)

q = (920g) x (36.66 J/°C)

q = 33768 J

Therefore, the iron kettle must absorb 33,768 joules of heat energy to raise its temperature from 15.0 Celsius to 93.0 Celsius.

PLEASE HELP WILL MARK THE BRAINELIST!!!!!!
1.) The fight or flight response (2 points)
a. results from chronic stress
b. has little impact on the body
c. prepares an organism to respond to stress
d. impacts only mental processes

2.) Which of the following is a true statement about stress? (2 points)
a. Both distress and eustress are harmful
b. The fight or flight response only occurs in wild animals
c. Stress is a psychophysiological response
d. Stress hormones increase the functions of all body systems

3.) According to the American Psychological Association, what is the most significant source of stress for Americans? (2 points)
a. Health
b. Education
c. Work
d. Money

4.) Which of the following is a common source of stress for both teens and adults? (2 points)
a. Child-rearing
b. Relationships
c. Economy
d. Education

5.) How can stress be beneficial? (2 points)
a. Decreasing heart rate
b. Increasing digestion
c. Increasing immune response
d. Increasing energy

6.) Chronic stress can result in all of the following except (2 points)
a. heart disease
b. weight gain
c. depression
d. improved concentration

7.) People who experience chronic stress are more vulnerable to (2 points)
a. illness
b. economic trouble
c. therapy
d. genetic disorders

8.) Type A personality has been linked to (2 points)
a. higher rates of heart disease
b. lower levels of time urgency
c. lower levels of stress hormone
d. higher rates of job satisfaction

9.) Which of the following is characteristic of Type B personality? (2 points)
a. Tendency to multitask and rush
b. Mental and physical alertness
c. Low sense of time urgency
d. Intense drive to achieve

10.) What did Friedman and Rosenman conclude from their study? (2 points)
a. Type B personality increases vulnerability to time urgency, which decreases stress response.
b. Type A personality increases vulnerability to time urgency, which decreases stress response.
c. Type B personality increases a person's levels of stress, which in turn increases vulnerability to CHD.
d. Type A personality increases a person's levels of stress, which in turn increases vulnerability to CHD.

Answers

1 is c

2 is c

3 is d

4 is b

5 is d

6 is d

7 is a

8 is a

9 is c

10 is d

i hope my answers help you

Final answer:

Stress responses, including the fight or flight response, are psychophysiological reactions that can prepare an organism for stressful situations. Chronic stress can lead to negative health effects, including illness and increased vulnerability to heart disease, particularly in individuals with a Type A personality. These concepts can help to understand the effects of stress on health.

Explanation:

The fight or flight response (c) prepares an organism to respond to stress. Stress (c) is a psychophysiological response. According to the American Psychological Association, the most significant source of stress for Americans is (d) Money. A common source of stress for both teens and adults is (b) Relationships. Stress can be beneficial by (d) Increasing energy. Chronic stress can result in all of the following except (d) improved concentration. People who experience chronic stress are more vulnerable to (a) illness. A Type A personality has been linked to (a) higher rates of heart disease. Characteristics of a Type B personality include (c) a low sense of time urgency. Friedman and Rosenman concluded from their study that (d) a Type A personality increases a person's levels of stress, which in turn increases vulnerability to CHD.

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If the potential across two parallel plates, separated by 3 cm, is 12 volts, what is the electric field strength in volts per meter? E = _____ volts/m

Answers

there are 100cm in 1m, divide 100 by 3 and you get 33, multiply that by 12 and you get  396 volts/m.

Hope this is correct and helps.

Answer:

E = 400 V/m

Explanation:

It is given that, for a parallel plates :

Potential difference, V = 12 volts

Separation between the plates, d = 3 cm = 0.03 m

The relation between the electric field and the electric potential is given as :

[tex]E=\dfrac{V}{d}[/tex]

[tex]E=\dfrac{12\ V}{0.03\ m}[/tex]

E = 400 volts/m

So, the strength of the electric field is 400 V/m.                

What is the electric potential energy of a charge that experiences a force of 3.6 x 10^-4N when it is 9.8 x 10^-5 from the source of the electric field

Answers

The electric potential energy of the charge is equal to the potential at the location of the charge, V, times the charge, q:
[tex]U=qV[/tex]
The potential is given by the magnitude of the electric field, E, times the distance, d:
[tex]V=Ed[/tex]
So we have
[tex]U=qEd[/tex] (1)
However, the electric field is equal to the electrical force F divided by the charge q:
[tex]E= \frac{F}{q} [/tex]
Therefore (1) becomes
[tex]U=Fd[/tex]
And if we use the data of the problem, we can calculate the electrical potential energy of the charge:
[tex]U=Fd=(3.6 \cdot 10^{-4}N)(9.8 \cdot 10^{-5} m)=3.53 \cdot 10^{-8} J[/tex]

What is the frequency of a pressure wave of wavelength 2.5 m that is traveling at 1400 m/s?

Answers

The relationship between the speed, the frequency and the wavelength of a wave is given by:
[tex]f= \frac{v}{\lambda} [/tex]
where
f is the frequency
v is the speed of the wave
[tex]\lambda[/tex] is its wavelength

for the pressure wave in this problem, [tex]\lambda=2.5 m[/tex] and v=1400 m/s, therefore its frequency is
[tex]f= \frac{v}{\lambda}= \frac{1400 m/s}{2.5 m}=560 Hz [/tex]

A 4.0 ω resistor, an 8.0 ω resistor, and a 13.0 ω resistor are connected in parallel across a 24.0 v battery. what is the equivalent resistance of the circuit? answer in units of ω.

Answers

104/47 ω
____________

Microwave ovens emit microwave energy with a wavelength of 13.0 cm. what is the energy of exactly one photon of this microwave radiation?

Answers

First, let's calculate the frequency of this radiation, which is given by:
[tex]f= \frac{c}{\lambda} [/tex]
where c is the speed of light and [tex]\lambda[/tex] is the photon wavelength. For this radiation, photons have wavelength of
[tex]\lambda=13.0 cm=0.13 m[/tex]
Therefore their frequency is
[tex]f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{0.13 m}=2.3\cdot 10^9 Hz [/tex]

The energy of a photon with frequency f is given by
[tex]E=hf[/tex]
where h is the Planck constant. By using the frequency we found before, we find the energy of a single photon of this radiation:
[tex]E=hf=(6.6 \cdot 10^{-34} Js)(2.3 \cdot 10^9 Hz)=1.52 \cdot 10^{-24} J[/tex]

The energy of exactly one photon of this microwave radiation is 1.53 × 10⁻²⁴Joule

Further explanation

The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is:

[tex]\large {\boxed {E = h \times f}}[/tex]

E = Energi of A Photon ( Joule )

h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )

f = Frequency of Eletromagnetic Wave ( Hz )

The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.

[tex]\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}[/tex]

[tex]\large {\boxed {E = qV + \Phi}}[/tex]

E = Energi of A Photon ( Joule )

m = Mass of an Electron ( kg )

v = Electron Release Speed ( m/s )

Ф = Work Function of Metal ( Joule )

q = Charge of an Electron ( Coulomb )

V = Stopping Potential ( Volt )

Let us now tackle the problem!

Given:

λ = 13.0 cm = 13.0 × 10⁻² m

Unknown:

E = ?

Solution:

[tex]E = h f[/tex]

[tex]E = h \frac{c}{\lambda}[/tex]

[tex]E = 6.63 \times 10^{-34} \frac{3 \times 10^8}{13.0 \times 10^{-2}}[/tex]

[tex]\large {\boxed {E = 1.53 \times 10^{-24} ~ Joule } }[/tex]

Learn morePhotoelectric Effect : https://brainly.com/question/1408276Statements about the Photoelectric Effect : https://brainly.com/question/9260704Rutherford model and Photoelecric Effect : https://brainly.com/question/1458544Photoelectric Threshold Wavelength : https://brainly.com/question/10015690

Answer details

Grade: High School

Subject: Physics

Chapter: Quantum Physics

Keywords: Quantum , Photoelectric , Effect , Threshold , Frequency , Electronvolt

In this layer of Earth's atmosphere, hydrogen and helium are the prime gases and are only present at extremely low densities. What is this layer of the atmosphere called?
A) exosphere
B) ionosphere.
C) mesosphere
D) thermosphere

Answers

The answer would be the EXOSPHERE. The exosphere is the highest layer of the atmosphere. This layer merges with space and the air is extremely thin. Molecules of air here always escape from the from the exosphere to space. This is also the layer where satellites orbit the Earth. 

The answer a. 

A flashlight operates on a 9.00 v battery and has a resistance of 45. At what rate does the flashlight use electric energy

Answers

What is required is calculation of power. Power is the rate of use of energy in J/s (W).

P = VI, but V =IR => I = V/R

Then,
P = V^2/R

Where
P = Power in J/s or W
V = Voltage, in volts
R = Resistance in ohms

Substituting;
P = 9^2/45 = 1.8 W

When a baseball player catches a baseball, the glove "gives" or moves backward. How does this movement affect the change in momentum of the baseball?


A The change in momentum increases because the impact time increases.

B The change in momentum stays the same because the ball still comes to a stop.

Answers


B The change in momentum stays the same because the ball still comes to a stop.

Answer:

The change in momentum increases because the impact time increases.

Explanation:

When a baseball player catches a baseball, the glove "gives" or moves backward. Momentum of a body is equal to the product of mass and velocity. Also, the change of momentum of an object when it is acted by a force is called impulse. It is represented by J. Mathematically, it can be written as :

[tex]J=F.\Delta t=m\Delta v[/tex]

F is applied force

[tex]\Delta t[/tex] is the time taken by an object to change its momentum

The momentum depends on the force and the time of impact. In this case, as the a baseball player catches a baseball, the gloves move in backward direction. By doing so, the ball comes to rest in larger time.

So, the change in momentum increases because the impact time increases.

sound

· parallel

· mechanical

· not a vacuum

· needs a medium

· compressions and rarefaction

What type of wave is being described?

A) compaction

B) electromagnetic

C) longitudinal

D) transverse

Answers

It is a longitudinal wave. In a longitudinal wave the particles of the medium vibrate in a direction parallel to the direction of energy transport. Sound waves are mechanical waves as well as longitudinal waves that require a medium. They do not travel through a vacuum.

What is radioactive decay

Answers

radio active decay is the process by which an unstable atomic nucleus looses energy by emitting radiation

Answer :

Radioactive decay : It the process in which an unstable atomic nucleus loses energy by emitting the radiations like, alpha particles, beta particles, or gamma rays.

Alpha particle : It is also known as alpha radiation or alpha ray that consists of 2 protons and 2 neutrons that are bound together into a particle that is identical to the helium nucleus. It is produced in the process of alpha decay.Beta particle : It is also known as beta radiation or beta ray. During the beta decay process, a high energy and speed electron or positron are emitted by the radioactive decay of atomic nucleus.Gamma particle : It is also a gamma radiation or gamma ray that is arising from the radioactive decay of atomic nuclei. It has shortest wavelength waves and imparts high photon energy can pass through most forms of matters because they have no mass.

What is the wavelength corresponding to the most intense light emitted by a giant star of surface temperature 4400 k?

Answers

This can be calculated by applying Wein displacement law which is stated as follows;

Maximum wavelength (m)*Temperature (K) = 2.90 *10^-3  m.K

Therefore, substituting for the values given;
Wavelength = (2.90*10^-3)/T = (2.90*10^-3)/4400 = 6.59*10^-7 m ≈ 659 nm

Final answer:

The wavelength corresponding to the most intense light emitted by a giant star with a surface temperature of 4400 K is approximately 681.8 nm.

Explanation:

According to Wien's law, the wavelength at which the most intense light is emitted by a giant star can be determined using the formula:
wavelength = 3 x 10^6 / temperature

In this case, the surface temperature of the giant star is 4400 K. Plugging in this value into the formula, we get:
wavelength = 3 x 10^6 / 4400 = 681.8 nm

Therefore, the wavelength corresponding to the most intense light emitted by the giant star is approximately 681.8 nm.

A ball is kicked with an initial velocity of 22 m/s in the horizontal direction and 13 m/s in the vertical direction. (assume the ball is kicked from the ground.) (a) at what speed (in m/s) does the ball hit the ground? m/s (b) for how long (in s) does the ball remain in the air? s (c) what maximum height (in m) is attained by the ball? m

Answers

(a) The motion on the vertical axis is an uniformly accelerated motion, with acceleration [tex]g=9.81 m/s^2[/tex] and initial vertical velocity [tex]v_y = 13 m/s[/tex], so the vertical position of the ball at time t is:
[tex]y(t) = v_y t - \frac{1}{2}gt^2 [/tex]
where we put a minus sign in front of g because the gravitational acceleration points toward the ground. The time when the ball hits the ground is the time t at which the vertical position is zero:
[tex]y(t) = v_y t - \frac{1}{2}gt^2 =0 [/tex]
which gives two solutions:
[tex]t=0 s[/tex], the initial moment when the ball is thrown,
[tex]t= \frac{2v_y}{g}= \frac{2 \cdot 13 m/s}{9.81 m/s^2}=2.65 s [/tex], the moment when the ball hits the ground.

The vertical velocity at time t is given by
[tex]v_y(t) = v_y - gt[/tex]
and by substituting [tex]t=2.65 s[/tex], we find the vertical velocity of the ball when it hits the ground
[tex]v_y(2.65 s) = 13 m/s - (9.81 m/s^2)(2.65 s)=-13.00 s[/tex]
So, it is equal to the initial vertical velocity, but in the opposite direction (toward the ground, due to the negative sign).

To find the speed of the ball when it hits the ground, we should find the resultant of the horizontal velocity (which has not changed, because the motion on the horizontal axis is a uniform motion) and of the vertical velocity:
[tex]v= \sqrt{v_x^2 + v_y^2}= \sqrt{(22 m/s)^2+(-13 m/s)^2} =25.6 m/s [/tex]
and this is the speed of the ball when it hits the ground.

(b) we already found the answer at point (a): the time it takes the ball to reach the ground is 2.65 s, so this is the time the ball remains in the air.

(c) The maximum height reached by the ball is the vertical position y(t) at which the vertical velocity is zero:
[tex]v_y (t) = 0[/tex]
Therefore,
[tex]v_y - gt = 0[/tex]
[tex]t= \frac{v_y}{g}= \frac{13 m/s}{9.81 m/s^2}=1.33 s [/tex]
this is the time at which the ball reaches the maximum height, and if we use this value in the formula of y(t), we find the value of the maximum height:
[tex]h=y(1.33 s)=v_y t - \frac{1}{2}gt^2=(13 m/s)(1.33 s)- \frac{1}{2}(9.81 m/s^2)(1.33s)^2 =8.6 m [/tex]
Final answer:

The speed at which the ball hits the ground, the time it remains in the air, and the maximum height it attains can be calculated using the initial vertical and horizontal velocities and the acceleration due to gravity.

Explanation:

Given the ball is launched with an initial horizontal velocity (Vx) of 22 m/s and a vertical velocity (Vy) of 13 m/s. The acceleration due to gravity (g) is -9.81 m/s2.

(a) Speed when the ball hits the ground:

Using the kinematic equation, we have Vy_final = Vy - g*t, where t is the time. The total final velocity as the ball hits the ground is given by V_final = sqrt(Vx2 + Vy_final2).

(b) Time the ball remains in the air:

The ball reaches its maximum height when Vy_final=0. So, 0=Vy-g*t => t=Vy/g. As the motion is symmetrical, the total time in air would be 2*t.

(c) Maximum height attained:

Using the formula for maximum height H = Vy2/2g.

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Select all that apply.

Images produced by a flat mirror are _____.

inverted (upside down)
left-right reversed
upright
diminished in size
enlarged
real
virtual

Answers

The correct options are:

- upright (the image of a flat mirror always appear in the same vertical-orientation of the object)
- left-right reversed (the image of a flat mirror always appear inverted in the horizontal direction)
- virtual (the image appears in fact behind the plane of the mirror)

Answer:

-left-right reversed

-upright

-virtual

I just did this in my lesson.

If an object starts at rest and moves 60 meters north along a straight line in 2 seconds, what is the average velocity?

Answers

Velocity: 30 m/s north

Answer:

The average velocity, expressed as a vector, is v=30 m/s with direction north.

Explanation:

In this case, we will obtain a vector velocity, and the correct answer will be expressed as a vector. But as the movement happens only along a straight line (with direction to the north from the point of rest), we can do the math calculation as a one-dimensional problem. Then the final velocity will be a vector with the calculated magnitude, pointing to the north, as we already know.

The question is simple, as we were given the distance in meters that the object moved in a straight line, and the time in seconds that took the object to move that distance, we have the correct units and we can write the average velocity as

[tex]v=\frac{d}{t}[/tex]

where d is the distance, and t is the time. Therefore

[tex]v=\frac{60m}{2s}=30\frac{m}{s}[/tex]

which is the magnitude of the velocity we wanted to know, then we express it as vector saying its direction (north, for our system of reference).

Given an electron beam whose electrons have kinetic energy of 5.00 kev , what is the minimum wavelength λmin of light radiated by such beam directed head-on into a lead wall?

Answers

Wavelength and frequency are inversely proportional, therefore the minimum wavelength occurs when the emitted radiation has maximum frequency. 
The energy of the emitted photons is
[tex]E=hf[/tex] (1)
where h is the Planck constant and f is the frequency. The maximum energy that can be given to the emitted photons corresponds to the kinetic energy of the electrons (in fact, if they are completely stopped, they give all their kinetic energy to the photons). Converting the energy in Joules:
[tex]E=5.00 keV= 5000 eV =8.01 \cdot 10^{-16}J[/tex]
from eq.(1) we find the corresponding frequency of the photons:
[tex]f= \frac{E}{h}= \frac{8.01 \cdot 10^{-16} J}{6.6 \cdot 10^{-34} Js}=1.21 \cdot 10^{18}Hz [/tex]

This is the maximum frequency the emitted photons can have, and by using the basic relationship between frequency, wavelength and speed of light c, we can find the corresponding wavelength:
[tex]\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{1.21 \cdot 10^{18} Hz}=2.48 \cdot 10^{-10} m [/tex]
And this is the minimum wavelength of the radiation emitted by this electron beam.

To answer the problem we would be using this formula which is E = hc/L where E is the energy, h is Planck's constant, c is the speed of light and L is the wavelength

L = hc/E = 4.136×10⁻¹⁵ eV·s (2.998x10⁸ m/s)/10⁴ eV

= 1.240x10⁻¹⁰ m

= 1.240x10⁻¹ nm

Why does the amount of water that flows in a river change during the year?

Answers

hey 

in the summer it is because of the meting  of snow 
in the spring it is rain

hope l helped

The small currents in axons corresponding to nerve impulses produce measurable magnetic fields. a typical axon carries a peak current of 0.040 μa. part a what is the strength of the field at a distance of 1.2 mm

Answers

We can see the axon as a current-carrying wire. The magnetic field produced by a current-carrying wire is given by
[tex]B(r) = \frac{\mu_0 I}{2 \pi r} [/tex]
where
[tex]\mu_0 = 4 \pi \cdot 10^{-7} Tm/A[/tex] is the vacuum permeability
I is the current in the wire
r is the radial distance from the wire at which the field is calculated

The current in the axon is 
[tex]I=0.040 \mu A=0.040 \cdot 10^{-6} A[/tex], 
therefore the magnetic field strength at distance
[tex]r=1.2 mm=1.2 \cdot 10^{-3}m[/tex] 
from the axon is
[tex]B= \frac{\mu_0 I}{2 \pi r}= \frac{(4 \pi \cdot 10^{-7} Tm/A)(0.040 \cdot 10^{-6} A)}{2 \pi (1.2 \cdot 10^{-3} m)}=6.67 \cdot 10^{-6} T = 6.67 \mu T [/tex]

The strength of the magnetic field at a distance of 1.2 mm from a typical axon carrying a peak current of 0.040 μA is 0.667 nanotesla (nT).

To determine the strength of the magnetic field at a distance of 1.2 mm from a current-carrying axon, we can use the formula for the magnetic field around a long straight wire: B = (μ₀ * I) / (2π * r), where B is the magnetic field, μ₀ is the permeability of free space (4π × 10⁻⁷ T*m/A), I is the current, and r is the distance from the wire.

Calculating the Magnetic Field:

Convert the given current (0.040 μA) to amperes: 0.040 μA = 0.040 × 10⁻⁶ AUse the given distance (1.2 mm) in meters: 1.2 mm = 1.2 × 10⁻³ mSubstitute the values into the magnetic field formula: B = (4π × 10⁻⁷ T*m/A * 0.040 × 10⁻⁶ A) / (2π * 1.2 × 10⁻³ m)Simplify the expression to find the magnetic field: B = (1.6 × 10⁻¹² T*m)/ (2.4 × 10⁻³ m) = 0.667 × 10⁻⁹ T = 0.667 nT

Therefore, the strength of the magnetic field at a distance of 1.2 mm from a typical axon carrying a peak current of 0.040 μA is 0.667 nanotesla (nT).

As a rough approximation, the human body may be considered to be a cylinder of length l=2.0m and circumference c=0.8m . (to simplify things, ignore the circular top and bottom of the cylinder, and just consider the cylindrical sides.) if the emissivity of skin is taken to be e=0.6 , and the surface temperature is taken to be t= 30 ∘ c , how much thermal power p does the human body radiate?

Answers

e= 0.6
Constant sigma is 5.6704004× 10∧ (-8)
The area is LC = 2× .8 = 1.6m∧2
to convert degrees celcious to Kelvin =303K
The equation is 
P = e ? AT∧4.
Then the answer is 460 watts.

Answer:

458.826 watts

Explanation:

According to Stefan-Boltzmann's Law, thermal energy emitted by a black body per second per unit area is directly proportional to the fourth power of the absolute temperature and is given by;

[tex]\frac{P}{A}[/tex] = σ[tex]eT^{4}[/tex]

P = ?

A = l x c = 2 x 0.8 = [tex]1.6m^{2}[/tex]

(Please ignore Armstrong symbol, I don't know how it appeared using the equation tool)

σ = [tex]5.6703 X 10^{-8}  watt/m^{2} K^{4}[/tex]

e = 0.6

T = [tex]30^{o} C[/tex] = 303 K

P = σeTA

P = [tex]5.6703 X 10^{-8}[/tex] x 0.6 x [tex]303^{4}[/tex] x 1.6

P = 458.826 watts

Tony made 14 liters of lemonade for a party. His guests drank 9500 mL of the lemonade. After the party Tony had mL of lemonade left over.

Answers

There are 1000 milliliters (mL) in a liter (L). Remember that the prefix milli- means one thousandth. 

Since Tony made 14 liters, that means he made:
[tex]14 \: L \times \frac{1000\: mL}{L} = 14000 \: mL \: total[/tex]

His guests drank 9500 mL, so subtract from the total amount of lemonade made to get the amount left over:
[tex]14000 \: mL - 9500 \:mL = 4500\: mL[/tex]

------

Answer: 4500 mL

Answer:

4500

Explanation:

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