In the equation y=x/3 , what is the unit rate?

Answers

Answer 1
[tex]\bf y=\cfrac{x}{3}\implies y=\stackrel{rate}{\cfrac{1}{3}}x[/tex]

Related Questions

If all terms of a series are​ positive, the series sums to a positive number?

A.
The statement is false because the series could converge to a negative number.
B.
The statement is true because the series will converge to a positive number because the series contains no negative terms.
C.
The statement is true because the series cannot diverge since all the terms are positive.
D.
The statement is false because the series could diverge.

Answers

It is B. There are no counterexamples of it being wrong.

A geometric series is the sum of an unlimited number of terms with a fixed ratio between them. The correct option is B.

What is geometrical series?

A geometric series is the sum of an unlimited number of terms with a fixed ratio between them.

The given statement "If all terms of a series are​ positive, then the series sums to a positive number" is true because the series will converge to a positive number because the series contains no negative terms.

Hence, the correct option is B.

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Jim and his dad are building a rectangular flower bed. They have a total of 35 feet of landscaping timber to use, and they want to use all of it. However, they are not sure what width and length they want the flower bed to be. In this activity, you will write a function in which the width of the flower bed, w, is the input, and the length, l, is the output. The perimeter of a rectangle is given by the equation 2l + 2w = p. Part A Jim and his dad want to find the length of the garden once they decide its width. Use function notation to write a function that represents its length in terms of the width.

Answers

The perimeter is 35 hope it helps

The perimeter of a rectangle is 35.

So the function that represents the length of the flower bed in terms of its width is:

l(w) = (35 - 2w) / 2.

What is a rectangular perimeter?

The whole distance that a rectangle's borders, or its sides, cover is known as its perimeter. Given that a rectangle has four sides, the perimeter of the rectangle will be equal to the total of its four sides.

To write a function that represents the length of the flower bed in terms of its width, we can use the equation for the perimeter of a rectangle:

2l + 2w = p

where l is the length, w is the width, and p is the perimeter. We know that the perimeter is 35 feet, so we can substitute that into the equation:

2l + 2w = 35

We want to solve this equation for l, so we can isolate the variable on one side of the equation:

2l = 35 - 2w

Dividing both sides by 2 gives:

l = (35 - 2w) / 2

So the function that represents the length of the flower bed in terms of its width is:

l(w) = (35 - 2w) / 2

where l(w) is the length of the flower bed for a given width w.

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Jan and Jo live 1,170 miles apart. At the same time, they start driving toward each other on the same road. Jo’s constant rate is 60 mph. Jan’s is 70 mph. How long will it take them to meet?

Answers

Answer:

the answer is 9 hours

Step-by-step explanation:

I got it right on the test

The time taken by Jan and Jo with constant rate of 70 mph and 60 mph respectively, will meet in 9 hours while driving towards each other along a 1,170-mile road.

To find out how long it will take Jan and Jo to meet, you can use the formula:

Time = Distance / Speed

Since they are driving toward each other, their combined speed is the sum of their individual speeds:

Combined Speed = Jan's Speed + Jo's Speed

Combined Speed = 70 mph + 60 mph

Combined Speed = 130 mph

Now, you can use this combined speed to calculate the time it will take for them to meet:

Time = Distance / Combined Speed

Time = 1,170 miles / 130 mph

Time = 9 hours

Therefore, time taken by Jan and Jo is 9 hours to meet while driving toward each other on the same road.

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which of the following statements are true? Select all that apply.
a) The image of the point (-3,-5) under a reflection across the x-axis is (3,-5).
b) The image of the point (1,9) under a reflection across the y-axis is (1,-9).
c) The image of the point (8,7) under a reflection across the line y=-x is (-7,-8).
d) The image of the point (-6,-6) under a reflection across the y=x is (-6,-6).
e) The image of the point (2,4) under a reflection across the y-axis followed by a reflection across y=xis (-2,-2).
f) Point K (3,-1)is reflected across the x-axis to creak point K'.The line x+3y=6 passes through point K'.

Answers

Answer: The answer in order are false, false, true, true, false and (3,1)

Step-by-step explanation:

We know that image of a point (x,y) under the y-axis

is (-x,y) i.e. the sign of x coordinate changes

Similarly in case of x-axis sign of y coordinate changes

i.e (x,y) is reflected to (x,-y)

Also the reflection of (x,y) under the line y=x is (y,x)

and the reflection of (x,y) under the line y=-x is(-y,-x)

So  

a) Given image of (-3,-5) under x-axis is (3,-5).

Hence statement is false

b) Given image of (1,9) under y-axis is (1,-9)

Hence the statement is false

c) Given image of (8,7) under y=-x is (-7,-8)

i.e. the statement is true

d) Given image of (-6,-6) under y=x is (-6,-6)

i.e the statement is true

e) Given image of (2,4) under y axis followed by x-axis is (-2,-2)

Hence the statement is false

f) (3,-1) is reflected in x-axis to (3,1)

Hence the point k is (3,1)

Answer:

a

b

e

g

Step-by-step explanation:

I just did the assignment lol-

S22 for 161+147+133+119+...

Answers

The arithmetic sequence of 161,147,133,119
Compute the general progression formula of 161,147,133,119 d=-14, a↓n+175
Compute ᵃ₂₂ = -133
Final answer:

The 22nd term of the arithmetic progression in the series 161, 147, 133, 119.... is -133.

Explanation:

This question involves finding the 22nd term in a series of numbers where each term is 14 less than the preceding term. This is an arithmetic progression where the first term, 'a' is 161 and the common difference, 'd' is -14.

The formula for the nth term in an arithmetic progression is: a + (n - 1)*d.

Substituting the given values into the formula, we get:

'a' + (22 - 1)*'d' = 161 + (21)*(-14) = 161 - 294 = -133

So, S22 for 161+147+133+119+... = -133.

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Five coins are tossed. let x be the number of heads and y be the number of tails. find the expectation

Answers

out of one hundred 50 percent x and 50 percent

For what value of a does the equation ax^2−3x−5=0 have 1 as one of its roots?

Answers

First, rearrange the equation so you have just ax² on one side. This can be done by adding -3x and -5 on both sides of the equation:
ax²=3x+5
Now, substitute x for 1 and simplify:
a(1²)=(3×1)+5
1a=3+5
a=8
You can double check this by substituting a for 8 back into the original equation:
(8×1²)-(3×1)-5=0
8-3-5=0

To determine the value of ↑ which the equation ax²-3x-5=0 has 1 as a root, we substitute x=1 into the equation and solve for a, yielding the result that a=8.

To find the value of a for which the equation ax² - 3x-5=0 has 1 as one of its roots, we can substitute x=1 into the equation and solve for a. When x=1, the equation simplifies to:

a(1)² - 3(1) - 5 = 0

a - 3 - 5 = 0

a - 8 = 0

Therefore, a = 8.

This means that the value of a is 8 for the equation to have 1 as one of its roots. This is a direct application of the fact that if a polynomial has a certain number as a root, then by substituting that number in place of the variable, the equation should result in zero.

Rita rode her bicycle out into the country at a speed of 20 miles per hour and returned along the same route at 15 miles per hour. If the round trip took 5 hours and 50 minutes, how far out did she ride?

Answers

x/20+x/15=5 5/6

(15x+20x)/20*15 = 35/6

35x/300= 35/6 CROSS MULTIPLY.

6*35x= 35*300

210x = 10,500

x= 10,500/210

X=50

I am trying to graduate HS please help me out!!!

Answers

1. To solve this exercise, you must apply the formula for calculate the area of a trapezoid, which is shown below:
 
 A=(b1+b2/2)h
 
 A is the area of the trapezoid.
 b1 is the larger base of the trapezoid (b1=16-4=12 ft).
 b2 is the smaller base of the trapezoid (b2=10-4=6 ft).
 h is the height of the trapezoid (h=12-4=8 ft)
 
 2. When you substitute these values into the formula A=(b1+b2/2)h, you obtain:
 
 A=(b1+b2/2)h
 A=(12 ft+6 ft/2)(8 ft)
 A=9 ftx8ft
 A=72 ft² 
 
 The length of fencing is:
 
 a²=b²+c²
 a=√b²+c²
 a=√(8 ft)²+(6 ft)²
 a=10 ft
 
 Perimeter (Length of fencing)=12 ft+8 ft+6 ft+10 ft=36 ft


Solve the inequality and graph on a number line. 7x + 4 ≤ x – 2

Answers

we have that
7x + 4 ≤ x – 2------------> (7x-x ) ≤ -2-4------> 6x ≤ -6---------> x ≤ -1

the solution is the interval (-∞, -1]

using a graph tool
see the attached figure

the floor plan of a kitchen is shown at the right. if the entire floor is to be tiled, how many square feet of tile are needed

Answers

Did you try adding all the sides like this: 6+2+6+12+16+6+12=?



Corey drew a sketch of a paper hat as shown below.
If a = 4 in and b = 3 in, what is the area of the sketch?

A.84 in squared
B.60 in squared
C.30.5 in squared
D.40 in squared

Answers

4(3) = 12 x 3 = 36

2(4) = 8 +4 = 12/2 = 6*4 = 24

36 +24 = 60

 Answer is B


Do the rectangle first.
Area = L * W
L = 4b
W = b
Area = 4b * b
Area = 4 *3 * 3
Area = 36 square inches.

Do the trapezoid next
b1 = a
b2 = 2a
h = a
Formula
Area = (b1 + b2) * h / 2
Area = (a + 2a) * a / 2
Area = (3a) * a / 2
a = 4
Area = (3*4) * 4 / 2
Area = 12 * 4/2
Area = 48 /2
Area = 24

Total Area
Area = 24 + 36
Area = 60 in^2

B <<<< answer

when derek planted a tree it was 36 inches tall. the tree grew 1 1/4 inches per year the tree is now 44 3/4 inches tall. how many years ago did derek lant the tree?

Answers

7 1/2 years ago to be precise

If correct brainley please

Thank you


Choose the correct simplification of the expression g5h4/g2h3

Answers

the answer is
[tex]g ^{3} h [/tex]
because you subtract exponents

Work out: 2/3 x 2 =

Answers

2/3 * 2 = 4/3, or 1 1/3.

Hope this helps! Have a good day :)

Find y'' by implicit differentiation. 5x2 + y2 = 3

Answers

Final answer:

To find y'' by implicit differentiation, differentiate the equation 5x^2 + y^2 = 3 twice with respect to x. Simplify and isolate y'' to find the second derivative of y.

Explanation:

To find y'' by implicit differentiation, we differentiate the equation 5x^2 + y^2 = 3 with respect to x twice.

Step 1: Differentiate both sides of the equation with respect to x using the chain rule.

Step 2: Simplify the equation and isolate y'' to find the second derivative of y.

Step 3: Rewrite the equation with the second derivative of y isolated on one side.

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As part of their senior project Janus nd Arya collected a total of $306 for the construction of a storage shed at a homeless shelter. Janus collected $88 less than Arya collected. How much money did each collect?

Answers

Given that the total money they collected is $306 and Janus collected $88 less than Arya, we can assume the equation:
306=X+Y
Where:
X=Janus collected
Y=Arya collected
But:
X=Y-88
Substitute to the equation :
306=(Y-88)+Y
306=2Y-88
2Y=306+88
Y=(306+88)/2
Y=197
Therefore:
X=197-88
X=109

Janus collected $109 while Arya collected $197.

A single card is drawn from a deck. find the probability of selecting a heart or a 8.

Answers

n(E) = 16
n(S) = 52

P(E)=n(E)/n(S)
=16/52
=4/13

Answer with Step-by-step explanation:

Let

A:selecting a heart

Total cards=52

number of hearts=13

P(A)=13/52

B:selecting a 8

number of 8=4

P(B)=4/52

A∩B:selecting a heart with 8 on it

number of hearts with 8 on it=1

P(A∩B)=1/52

A∪B:selecting a heart or a 8

We have to find P(A∪B)

P(A∪B)=P(A)+P(B)-P(A∩B)

          = [tex]\dfrac{13}{52}+\dfrac{4}{52}-\dfrac{1}{52}[/tex]

          =[tex]\dfrac{13+4-1}{52}[/tex]

          = 16/52

          = 4/13

Hence, the probability of selecting a heart or a 8 is:

4/13

A parabola has a vertex at (0,0). The focus of the parabola is located on the positive x-axis. Which part of the graph will the directrix pass through? the origin the negative part of the x-axis the positive part of the x-axis the negative part of the y-axis

Answers

 the negative part of the x-axis

Answer with explanation:

→→Information given about Parabola

Vertex of the Parabola = (0,0)

Focus is located on the positive x- axis.

Definition of Parabola: A parabola is locus of all the points such that distance from a fixed point known as focus to distance from a fixed line called, Directrix  is always constant.

Let focus of the parabola be (k,0), where , k>0.

Distance between vertex (0,0) and focus(k,0) = Distance between vertex (0,0) and point on negative x-axis (-k,0).

Directrix will pass through point (-k,0).

So, equation of Directrix will be, x= -k

Directrix will pass through

Option B: The Negative part of the x -axis.

a local post office sells stamps in packs of 4, 6 and 7. andy bought several packs of 4. erin bought several packs of 6. jarred bought several packs of 7. each of the three friends ended up with the same number of stamps that each person could have purchased?

Answers

The number of stamps each could have purchased is 84

How to determine the number of stamps each purchased

From the question, we have the following parameters that can be used in our computation:

Andy = packs of 4

Erin = packs of 6

Jarred = packs of 7

Expand 4, 6 and 7

So, we have

4 = 2 * 2

6 = 2 * 3

7 = 7

The LCM of 4, 6 and 7 is then calculated as

LCM = 2 * 2 * 3 * 7

Evaluate

LCM = 84

Hence, the number of stamps each could have purchased is 84

The box plots display the same data for the number of crackers in each snack bag, but one includes the outlier in the data and the other excludes it. 4, 14, 15, 15, 16, 16, 18, 19, 20, 20, 21 Number of Crackers in Each Bag, with Outlier Number of Crackers in Each Bag, without Outlier Which statement comparing the box plots is true? Both the median and the range changed. Both the range and the lower quartile changed. Both the median and the interquartile range changed. Both the interquartile range and the lower quartile changed.

Answers

Answer:

Both the median and the range changed.

Step-by-step explanation:

We first ensure this data set is from least to greatest.  This one is.

Next we find the median.  This is the middle value; in this set, it is 16.

Next we find Q1, the lower quartile.  This is the middle of the lower set of data (once the data is "split" by the median).  This is 15.

Next we find Q3, the upper quartile.  This is the middle of the upper set of data (once the data is "split" by the median).  This is 20.

The IQR is Q3-Q1, or 20-15 = 5.

The range is the max subtracted by the min, or 21-4 = 17.

Any outlier will be 1.5 times the IQR below Q1 or 1.5 times the IQR above Q3.

1.5(5) = 7.5; 15-7.5 = 7.5.  Any lower outlier would be below this value; this makes 4 an outlier.

20+7.5 = 27.5.  Any upper outlier would be above this value; this means there are no outliers on the upper end.

Taking the data value 4 out, the median is now 17.  Q1 would still be 15 and Q3 would still be 20; this means the IQR would still be 5.

The range would now be 21-14 = 7.

This means the median and the range have changed.

The true statement comparing the box plots is that Both the median and the range changed.

What are quartiles?

When we get data that can be compared relatively with each other, for finding quartiles, we arrange them in ascending or descending order.

Quartiles are then selected as 3 points such that they create four groups in the data, each group approximately possessing 25% of the data.

The box plots display the same data for the number of crackers in each snack bag, but one includes the outlier in the data and the other excludes it.

4, 14, 15, 15, 16, 16, 18, 19, 20, 20, 21 Number of Crackers in Each Bag, with Outlier Number of Crackers in Each Bag, without Outlier

The median in this set is 16.

Q1, the lower quartile. This is the middle of the lower set of data.

This is 15.

Q3, the upper quartile. This is the middle of the upper set of data. This is 20.

The IQR is Q3-Q1

20-15 = 5.

The range will be

21-4 = 17.

Any outlier will be 1.5 times the IQR below Q1 or 1.5 times the IQR above Q3.

1.5(5) = 7.5

15-7.5 = 7.5.  

Any lower outlier would be below this value, this makes 4 an outlier.

20+7.5 = 27.5.  

Any upper outlier would be above this value, this means there are no outliers on the upper end.

Taking the data value 4 out, the median is now 17.  

Q1 would still be 15 and Q3 would still be 20; this means the IQR would still be 5.

The range would now be 21-14 = 7.

Thus, This means the median and the range have changed.

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name AND define the two ways to classify polynomials

Answers

the 2 ways a polynomial can be classified is by its degree or by its number of terms.
Number of terms is each amount of individual term. A term is just a number and a variable (possibly to a power/degree). Terms are also separated using a function such as multiplication, addition, and subtraction.

The degree of a polynomial is just the greatest variable's power so if x^5 is the greatest power in that function, than that is the degree of the polynomial 

What is the perimeter of this shape? A. 26 cm B. 24 cm C. 22 cm D. 18 cm PLEASE HELP

Answers

perimeter is adding all dimensions:
11 + 2 + 8 + 5 = 26 cm
 Answer is A
the perimeter would be 26

12÷0.5 explain the division expression in terms of bags of almonds

Answers

You have a total of $12. Each bag of almonds cost $0.50, how many bags of almonds can you buy with your $12?

Convert 5x + 6y = -5 to slope-intercept form. Simplify your answer

Answers

Slope intercept form is y=mx+b. In this case, I believe it's y= -5/6x -5/6.

In the neighborhood park there is a circular grassy picnic area, but half of the grass has died. The city wants to replant the grads, but needs to know the square footage of the damaged area. If the circular picnic are is 150 feet across what is the square footage of the damaged area

Answers

The area of the circle 150 ft in diameter is
.. A = π*(75 ft)^2 ≈ 17,671.459 ft^2

The damaged area is half that, about 8836 ft^2.

Answer: The damaged area is equal to 8831.25ft^2

Step-by-step explanation:

We know that we have a circular area, where half of the grass has died. We know that the circular picnic is "150 feet across" I guess this means that if you walk in a straight line from the edge of the circular area, through the middle, and to the next edge, the distance is 150ft.

This would mean that the diameter is equal to 150ft.

With this we can calculate the total area of the circle; this is:

A = pi*r^2

where r is the radius, that is half the diameter, so we have r = 150ft/2 = 75ft

and pi = 3.14

so we have:

A = 3.14*(75ft^)^2 = 17662.5ft^2

And we know that half of that area has the grass damaged, so the amount of square feet of grass needed is equal to A/2 = (17662.5ft^2)/2 = 8831.25ft^2

Jamie is making treat bags with 1/3 cups of M&M's in each bag how many cups of M&M's will she need to make 20 bags

Answers

Hello,

Here is your answer:

The proper answer for this question is "20/3".

1*20=20
3*1=3

Your answer is 20/3!

If you need anymore help feel free to ask me!

Hope this helps!

An athlete runs around a circular track. The track has a diameter of 200 feet. How many laps does she need to take to run a mile?

Answers

First you have to figure out the length of the track:

[tex] 2 * \pi * r [/tex]

r is the half of the diameter:
200ft : 2 = 100ft

[tex] 2* \pi *100ft [/tex] = 200[tex] \pi [/tex]≈ 628,31

The athlete has to run ca. 5280ft for one mile:

5280 : 628,31≈8,4

The athlete has to run 8,4 laps

find the product of 3 and 3/4 and 1 1/10 how do you find the product and how did you come up with it could you show your work

Answers

To find the product, first, we need to turn the two fractions into improper fractions.

3 3/4 = (3 × 4 + 3) / 4 = 15/4

1 1/10 = (1 × 10 + 1) / 10 = 11/10

Now, we find the receprical of the second fraction and multiply.

11/10 receprical = 10/11

10/11 × 15/4 = 150/44

Now, we simplify.

150/44 = 75/22 = 3 11/22 = 3 1/2

Your answer is 3 1/2.

Hope this helps!

Let y=3t+6 be a linear function representing the distance from home for an ant t minutes after starting out from a location near its home. What does the number 3 represent in this function?

Answers

The direction from home to the ants current location.
The answer is the ant is crawling at 3 feet per minute
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