There might be two ways to go about this
(1) I am going to assume that we can construct a second (reference) triangle - and you confirmed that it is ok to use trigonometry on that, and then we use the relationship between areas of similar triangles to get what we want. I choose a triangle DEF with same angles, 15, 75, and 90 degrees, and the hypotenuse DE a of length 1 (that is a triangle similar to ABC). I use sin/cos to determine the side lengths: sin(15)=EF and cos(15)=DF and then compute the area(DEF) =EF*DF/2. This turns out to be 1/8 = 0.125.
Now one can use the area formula for similar triangles to figure out the area of ABC - this without trigonometry now: area(ABC)/area(DEF)=(12/1)^2
so area(ABC)=144*area(DEF)=144*0.125=18
(2) Construct the triangle ABC geometrically using compass, protractor, and a ruler. Draw a line segment AB of length 12. Using the compass draw a (Thales') semi-circle centered at the midpoint of AB with radius of 6. Then, using the protractor, draw a line at 75 degrees going from point B. The intersection with the semicircle will give you point C. Finally. draw a line from C to A, completing the triangle. Then, using ruler, measure the length BC and AC.
Calculate the area(ABC)=BC*CA/2, which should come out close to 18, if you drew precisely enough.
Answer: 18 square cm
Step-by-step explanation:
*picture very note to scale im sorry lol*
Given: △ABC, m∠C=90°, m∠B=75°, AB=12 cm
m∠A = 15° (sum of all angles in a triangle is 180 degrees and 180-90-75=15)
CM - median to hypotenuse
CL - altitude
m<CLB = m<CLM = 90 degrees (def of altitude)
CM=MA=MB=1/2 AB = 6 cm (median to hypotenuse theorem)
m<MBC=m<BCM=75 degrees (base angles theorem of iso triangle)
m<BMC = 30 degrees (sum of all angles in a triangle, 180-75-75 = 30)
m<LCM = 60 degrees (sum of all angles in a triangle of triangle LCM, 180-90-30=60)
so now we know that triangle LCM is a 30-60-90 triangle with a hypotenuse of CM (6 cm)
LC = 1/2 of MC = 3 cm (leg opposite to 30 degree <)
So now we know that the height (altitude) of the triangle is 3 cm and the length is 12 cm.
Then, we can find the area by doing the (height * length)/2 = (3*12)/2, which brings us to our answer of 18 cm.
lmk if you don't understand anything in here i'm happy to clarify!
hope this helps!
what is the equation of a line, in point-slope form, that passes through (5, -3) and has a slope of 2/3? please help me
y + 3 = [tex]\frac{2}{3}[/tex] (x - 5)
the equation of a line in point- slope form is
y - b = m ( x - a )
where m is the slope and (a, b) a point on the line
here m =[tex]\frac{2}{3}[/tex] and (a,b) = (5 , - 3 )
y + 3 = [tex]\frac{2}{3}[/tex] (x - 5 ) ← in point-slope form
The equation of the line that passes through the point (5, -3) and has a slope of 2/3 is y = 2/3x - 19/3, using the point-slope form for the equation of a line.
Explanation:
The line that you're looking for can be represented using the point-slope form of a linear equation. This form is written as y - y1 = m(x - x1), where (x1, y1) are the coordinates of a point on the line and 'm' is the slope of the line. For a line that passes through the point (5, -3) and has a slope of 2/3, you replace x1 with 5, y1 with -3, and m with 2/3. So, the equation of the line becomes y - (-3) = 2/3(x - 5), which simplifies to y + 3 = 2/3x - 10/3. Further simplifying, we get y = 2/3x - 10/3 - 3, or y = 2/3x - 19/3.
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What is the slope of the line passing through the points (2, 4) and (5, 6)?
2/3 is the slope of (2,4) and (5,6)
slope = [tex]\frac{2}{3}[/tex]
calculate the slope m using the gradient formula
m = ( y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = ( 2, 4 ) and (x₂, y₂ ) = (5, 6 )
m = [tex]\frac{6-4}{5-2}[/tex] = [tex]\frac{2}{3}[/tex]
Two perpendicular lines have opposite y-intercepts. The equation of one of these lines is y = mx + b. Express the x-coordinate of the intersection point of the lines in terms of m and b.
The x-coordinate of the intersection point of two perpendicular lines, one with equation y = mx + b and the other with equation y = -x/m - b, is given by x = 2b/(m + 1/m).
Explanation:Given two perpendicular lines, one has the equation y = mx + b. The y-intercept of this line is b, and the slope is m. The equation of the second line, which is perpendicular to the first, will have a negative reciprocal slope, -1/m, and for opposite y-intercepts, we'll assume its y-intercept to be -b. Thus the equation of the second line is y = -x/m - b.
For the intersection point, equal the y-values of the two equations: mx + b = -x/m - b. Simplify to obtain the x-coordinate of the intersection point:
mx + x/m = 2b or x(m + 1/m) = 2b. Therefore, the x-coordinate of the intersection point is x = 2b/(m + 1/m).
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To find the x-coordinate of the intersection point of two perpendicular lines with opposite y-intercepts, set the equations of the lines equal to each other and solve for x.
Explanation:To find the x-coordinate of the intersection point of two perpendicular lines with opposite y-intercepts, we need to find the equations of both lines. Let's assume the equation of one line is y = mx + b. Since the lines are perpendicular, the slope of the other line will be the negative reciprocal of m. Let's call the slope of the other line n. Therefore, the equation of the other line will be y = -nx + c, where c is the y-intercept of the second line. To find the x-coordinate of the intersection point, we can set the two equations equal to each other and solve for x:
mx + b = -nx + c
x(m + n) = c - b
x = (c - b)/(m + n)
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Find the zeros of the function f(x)=2x^2-17.5x+35.6f(x)=2x 2 −17.5x+35.6 to the nearest hundredth.
Try this option (answers: 5.53 and 3.22)
Which type of triangle is shown here?
Hi ArbogastMadyson,
Which type of triangle is shown here?
There are 6 types of triangle:
Right TriangleEquilateral TriangleIsosceles TriangleScalene TriangleObtuse TriangleAcute TriangleSince your triangle contains length in inches not degrees we will not use the 1st, 5th, and 6th clssifications.
Scalene Triangle - 3 unequal sides
Isosceles Triangle - 2 equal sides, 1 unequal,
Equilateral Triangle - 3 Equal Sides
In your image all 3 lengths are different.
Answer - Scalene Triangle
It would of been easier to search the definition of the answers up.
HELP! WILL GIVE BRAINLIEST!
Use the figure to complete the transformations.
1. Reflect the triangle across the y-axis.
2. Reflect the image across the x-axis.
The final image is the same as what single transformation?
a reflection across the y-axis
a 180° rotation about the origin
a clockwise rotation 90° about the origin
If you actually do what the problem statement tells you to do, the answer falls into your lap.
The attachment shows the triangle reflected across the y-axis (blue), then across the x-axis (red). The red triangle is clearly equivalent to the original being rotated 180° about the origin.
The appropriate choice is ...
... a 180° rotation about the origin
_____
Algebraically, reflection across the y-axis negates the x-coordinate:
... (x, y) ⇒ (-x, y)
and reflection across the x-axis negates the y-coordinate:
... (x, y) ⇒ (x, -y)
Then, reflection across first one axis then the other will result in both coordinates being negated:
... (x, y) ⇒ (-x, -y)
This is precisely what happens when a figure is rotated 180° about the origin.
Answer:
A 180 rotation about the origin
Jacksons rectangular bedroom has an area of 90 ft.². The area of his bedroom is nine times that of his rectangular closet. If the closet is 2 feet wide, what is its links?
The closet area is 1/9 of the bedroom area, so is (1/9)·(90 ft²) = 10 ft².
The width of the closet multiplied by the length is the area.
... length×(2 ft) = 10 ft²
... length = (10 ft²)/(2 ft) = 5 ft
The length of Jackson's closet is 5 ft.
What is the median of the box-and-whisker plot?
A) 36
B) 38
C) 42
D) 43
The median on any box plot is the little dot in the middle of the box so the answer is C)42. So where the line is in the middle of the box it is always going to be the median. The median is in the middle. You can also remember it like this Hey Diddle diddle the medians the middle you add and divide for the mean and the mode is the most.
Answer:
B) 38
Step-by-step explanation:
38 is the first (lower) quartile of the box-and-whisker plot.
Given any linear equation, explain how to find the slope for a line that is perpendicular to the given equation. please help i suck in math :(
given a linear equation in slope- intercept form y = mx + c
where m is the slope and c the y -intercept
the slope of a line perpendicular to it is - [tex]\frac{1}{m}[/tex]
If equation is y = 2x + 3 ( with slope m = 2 )
then the perpendicular slope = - [tex]\frac{1}{2}[/tex]
If VUW is equiangular, find k and t.
A.
k = 62, t = 74
B.
k = 64, t = 52
C.
k = 68, t = 52
D.
k = 72, t = 64
Answer:
C. k=68, t=52
Step-by-step explanation:
Let u, v, y represent the measures of the unmarked angles at the respective vertices. The angles of the equiangular triangle are all 180°/3 = 60°, so we have the relations ...
y=vy+v+k = 180v+64+60 = 180u=64u+64+t = 180From these relations, we know that
... v = 180 -124 = 56 . . . . . 3rd equation above
... 56 +56 +k = 180 . . . . . . 2nd equation above, with y=v=56
... k = 180 -112 = 68 . . . . . above with 112 subtracted
... t = 180 -128 = 52 . . . . . 5th equation above with u=64 and 128 subtracted
The vertices A(–2, –1), B(–3, 2), C(–1, 3), and D(0, 0) form a parallelogram. The vertices A’(–1, –2), B’(2, –3), C’(3, –1), and D’(0, 0) are the image of the parallelogram after a sequence of transformations. Which sequence of transformations could produce the image from the pre-image?
a reflection over the x-axis and then a reflection over the y-axis
a reflection over the y-axis and then a 90 degree clockwise rotation about the origin
a 90 degree clockwise rotation about the origin and then a reflection over the y-axis
a 90 degree counterclockwise rotation about the origin and then a reflection over the x-axis
In the attachment, the original parallelogram is shown in red. Its image is shown in blue. The purple parallelogram is the original reflected across the y-axis. You can see that it becomes the blue parallelogram if rotated 90° clockwise around the origin.
The appropriate choice is ...
... a reflection over the y-axis and then a 90 degree clockwise rotation about the origin
Answer:
B. a reflection over the y-axis and then a 90degree clockwise rotation about the origin
Step-by-step explanation:
I just did it, and all was well! :) :) :)
Jake and erica were solving a system of equations. They both noticed that the two lines had the same slope. Jake said that because each line in the system had the same slope, the two lines had to be the same, which meant there were infinitely as many solutions to the solutions to the system. Erica disagreed, and said they ahould also look at the y-intercepts before determining how many solutions there were. Who is correct?
Answer:
Erica
Step-by-step explanation:
Two lines with the same (defined) slope will only have infinite solutions if their y-intercepts are the same. Otherwise, the number of solutions (points on both lines) is zero.
Since the 2 lines have the same slope, then the lines are parallel and never intersect. Thus there is no solution to the system of equations
Neither Jake nor Erica are correct.
6th Grade Line Graph-will give brainliest
Select all that apply. A point located at (1, 6) undergoes a transformation. Its image is at (1, -6). What was the transformation? The point was reflected over the y-axis. The point was translated down 12 units. The point was reflected over the x-axis. The point was translated up 12 units.
the point was reflected over the x- axis
note that for reflection in the x- axis
a point (x, y ) → (x, - y )
the x-coordinate remains unchanged while the y- coordinate of the image is the negative of the original y- coordinate
Answer:
Option B and C are correct.
Step-by-step explanation:
It is given that A point located at (1, 6) undergoes a transformation. Its image is at (1, -6).
[tex]P(1,6)\rightarrow P'(1,-6)[/tex]
If the point was reflected over the y-axis, then
[tex]P(x,y)\rightarrow P'(-x,y)[/tex]
[tex]P(1,6)\rightarrow P'(-1,6)\neq P'(1,-6)[/tex]
If the point was translated down 12 units, then
[tex]P(x,y)\rightarrow P'(x,y-12)[/tex]
[tex]P(1,6)\rightarrow P'(1,6-12)=P'(1,-6)[/tex]
If he point was reflected over the x-axis, then
[tex]P(x,y)\rightarrow P'(x,-y)[/tex]
[tex]P(1,6)\rightarrow P'(1,-6)[/tex]
If he point was translated up 12 units, then
[tex]P(x,y)\rightarrow P'(x,y-+12)[/tex]
[tex]P(1,6)\rightarrow P'(1,6+12)=P'(1,18)\neq P'(1,-6)[/tex]
Hence, the correct options are B and C.
In number theory, two integers a and b are said to be relatively prime, mutually prime, or coprime if the only positive integer that divides both of them is _____. That is, the only common positive factor of the two numbers is _____. This is equivalent to their greatest common divisor being _____. What number fills in the blanks?
ANSWER
The number that fills in the blanks is 1
EXPLANATION
Two numbers are relatively prime if they have no common factor greater than 1.
For exam 12 and 17 have no common factor greater than 1.
This is equivalent to saying that the greatest common divisor (GCD) of the two numbers is 1.
[tex]gcd(12,17)=1[/tex]
This means that [tex]12[/tex] and [tex]17[/tex] are relatively prime.
But
[tex]gcd(12,16)=4[/tex]. This means 12 and 16 are not relatively prime or coprime
Graph f(x)=12x+2. Use the line tool and select two points to graph the line.
we have
[tex]f(x)=\frac{1}{2}x+2[/tex]
To graph the line find the x and y intercepts
we know that
The x-intercept is the value of x when the value of y is equal to zero
The y-intercept is the value of y when the value of x is equal to zero
so
Find the y-intercept
For [tex]x=0[/tex]
[tex]f(0)=\frac{1}{2}*0+2=2[/tex]
the y-intercept is the point [tex](0,2)[/tex]
Find the x-intercept
For [tex]y=0[/tex]
[tex]0=\frac{1}{2}x+2\\x=-4[/tex]
the y-intercept is the point [tex](-4,0)[/tex]
Using a graphing tool
Plot the points to graph the line
therefore
the answer in the attached figure
The graph of the linear function f(x) = 12x + 2 is attached below
What is the graph of a linear equation?The graph of a linear equation is a straight line when plotted on a coordinate plane. A linear equation can be written in the form:
y = mx + b
Where:
"y" represents the dependent variable (usually plotted on the vertical axis).
"x" represents the independent variable (usually plotted on the horizontal axis).
"m" is the slope of the line, which determines its steepness.
"b" is the y-intercept, which is the point where the line crosses the y-axis.
The graph of the linear equation f(x) = 12x + 2 is attached below;
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I need help with this problem, please help!!!
Answer:
Yes. (See below for explanation.)
Step-by-step explanation:
The number of servings is found by dividing the quantity available by the size of a serving. The quantity of punch is the sum of the quantities of the juices that go into the punch. The serving size of 3/4 cup is the same as 6 ounces, since a cup is 8 ounces. (3/4 × 8 oz = 6 oz)
The quantity available is (64 oz + 28 oz + 76 oz). The serving size is 6 oz. Since the units of numerator and denominator are the same, they cancel, leaving ...
... number of servings = (quantity available)/(serving size)
... = (64 +28 +76)/6 . . . . as shown in the problem statement
_____
It might not be obvious that the above ratio gives the number of servings. However, if you look at the real units, you see how it happens.
[tex]\dfrac{oz}{(\frac{oz}{serving})}= oz\dfrac{serving}{oz}=\dfrac{oz}{oz}serving=serving[/tex]
The table below shows two equations:
Equation 1 |4x − 3|− 5 = 4
Equation 2 |2x + 3| + 8 = 3
Which statement is true about the solution to the two equations?
Equation 1 and equation 2 have no solutions.
Equation 1 has no solution, and equation 2 has solutions x = −4, 1.
The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution.
The solutions to equation 1 are x = 3, −1.5, and equation 2 has solutions x = −4, 1.
Answer:
The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution.
Step-by-step explanation:
Rearranging the two equations, you get ...
|4x -3| = 9 . . . . . has two solutions|2x +3| = -5 . . . . has no solutions (an absolute value cannot be negative)The above-listed answer is the only one that matches these solution counts.
_____
Testing the above values of x reveals they are, indeed, solutions to Equation 1.
(1) has solutions x = 3, x= - 1.5 and (2) has no solution
solving each equation
(1)
add 5 to both sides
|4x - 3 | = 9 ( remove bars from absolute value )
4x - 3 = 9 or 4x - 3 = - 9 ( by definition )
4x = 9 + 3 = 12 or 4x = - 9 + 3 = - 6
x = 3 or x = - 1.5
(2)
subtract 8 from both sides
|2x + 3 | = - 5
the absolute value cannot be equal to a negative quantity
thus |2x + 3 | = - 5 has no solution
A selection of staff wages is collected and shown below. £254 £254 £310 £276 £116 £90 £312 £180 £180 £536 £350 £243 £221 £165 £239 £700 What is the mode of staff wages? £ and £
the mode is the amount/s which occurs most frequently.
In this data set there are 2 values which occur twice
the mode is £254 and £180
The mode of staff wages is:
£ 180 and £ 254
Step-by-step explanation:The mode of a data set is a data value that exist or occur in the set most frequently (i.e. most of the times)
We are given data points as:
£254 £254 £310 £276 £116 £90 £312 £180 £180 £536 £350 £243 £221 £165 £239 £700
On arranging these data points along with their frequency we get:
Data point Frequency
£90 1
£116 1
£165 1
£180 2
£221 1
£239 1
£243 1
£254 2
£276 1
£310 1
£312 1
£350 1
£536 1
£700 1
Two data points has highest frequency
£180 and £254
( since both have frequency 2)
What is the median of this set of values? 6, 8, 10, 8, 4, 2, 12
The median is the middle number in order of the set of values:
2, 4, 8, 10, 12
8 is the median in the set of values!
Answer:
its 8
Step-by-step explanation:
No
Lines k and n are perpendicular. If the slope of line k is -6, what is the slope of line n?
A. -6
B.-1/6
C.6
D.1/6
Lines k and n are perpendicular
The slope of line k is -6
Fact: The product of slopes of two perpendicular lines = -1
So the slope of line n = -1 ÷ -6 = 1/6
The correct choice is 'D.'
If lines k and n are Slopes of Perpendicular Lines k is -6, then the slope of the perpendicular line n is 1/6.
In the study of Mathematics, especially when dealing with Geometry and Algebra, understanding the relationship between lines can be critical.
This particular question asks about perpendicular lines and their slopes. If lines k and n are perpendicular, knowing the slope of one can help deduce the slope of the other.
As per the properties of perpendicular lines, the product of their slopes is -1.
In the case where the slope of line k is -6, the slope of the perpendicular line n would be the Positive reciprocal, which is simply flipping the fraction and changing the sign.
Hence, the slope of line n would be 1/6.
So, ultimately the answer is Option d: 1/6, which is the slope of line n that is perpendicular to line k with a slope of -6.
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Describe the end behavior of the following function:
Answer:
The correct answer is that the function starts high and ends low.
Step-by-step explanation:
First we need to check for the highest power in a term. Since it is 5, which is an odd number, we know that they start and end in different places.
Next, we determine where it finishes based on the coefficient of that term, which is -1. Since it is negative, we know it finishes down. Since they are different, this means it starts up
Answer:
A ) The graph of the function start high and ends low .
Step-by-step explanation:
Given : f(x) = [tex]-x^{5} +x^{2} -x[/tex].
To find : Describe the end behavior of the following function.
Solution : We have given function
f(x) = [tex]-x^{5} +x^{2} -x[/tex].
We can see the Degree = 5 ( Odd) , Leading coefficient = negative .
By the End Behavior Rule : If the degree odd and leading coefficient is negative then the left side of graph would be up and right would be down.
Therefore, A ) The graph of the function start high and ends low .
on an incoming field trip, 60 sixth graders and 48 seventh graders, will be traveling by vans to the museum. Each van will be carry the same number of students and carry only sixth graders on only seventh graders. If vans are to carry the greatest possible number of students, how many vans will be needed?
The greatest common factor of 60 and 48 is 12. If 12-student vans are used for transport, then (60+48)/12 = 9 vans will be needed.
_____
5 vans are needed for the 6th graders; 4 vans are needed for the 7th graders.
Stanley wants to know how many students in his school enjoy watching talk shows on TV. He asks this question to all 24 students in his history class and finds that 55% of his classmates enjoy watching talk shows on TV. He claims that 55% of the school's student population would be expected to enjoy watching talk shows on TV. Is Stanley making a valid inference about his population? No, it is not a valid inference because he asked all 24 students in his history class instead of taking a sample from his math class No, it is not a valid inference because his classmates do not make up a random sample of the students in the school Yes, it is a valid inference because his classmates make up a random sample of the students in the school Yes, it is a valid inference because he asked all 24 students in his history class
Answer:
The Answer is;
No, it is not a valid inference because his classmates do not make up a random sample of the students in the school.
Step-by-step explanation:
You cannot make a valid inference of the preference of watching TV talk shows by only considering students in one class. You have to randomly select people from the whole population (i.e the total number of students in the school) and then make an inference.
Answer:
No, it is not a valid inference because his classmates do not make up a random sample of the students in the school.
Suppose that you are asked if there would be a strong or weak correlation between the number of people shopping in malls and the approach of the Holiday Season. Explain whether there would be a strong or weak correlation and the difference between the two.
There could be a strong correlation between the proximity of the holiday season and the number of people who buy in the shopping centers.
It is known that when there are vacations people tend to frequent shopping centers more often than when they are busy with work or school.
Therefore, the proximity in the holiday season is related to the increase in the number of people who buy in the shopping centers.
This means that there is a strong correlation between both variables, since when one increases the other also does. This type of correlation is called positive. When, on the contrary, the increase of one variable causes the decrease of another variable, it is said that there is a negative correlation.
There are several coefficients that measure the degree of correlation (strong or weak), adapted to the nature of the data. The best known is the 'r' coefficient of Pearson correlation
A correlation is strong when the change in a variable x produces a significant change in a variable 'y'. In this case, the correlation coefficient r approaches | 1 |.
When the correlation between two variables is weak, the change of one causes a very slight and difficult to perceive change in the other variable. In this case, the correlation coefficient approaches zero
Most likely, there would be a strong correlation between the two.
A correlation is a measurement of the relationship between two variables. When two variables are strongly correlated, this means that a change in one variable has a strong impact on the other one. On the other hand, when the correlation between variables is weak, this means that the two variables are not strongly connected. In this example, the two situations are likely to be strongly correlated because the number of people is very likely to go up as the holiday season approaches.
PLZZZZZZZZZZZZZZZZ HELP IM IN A RUSH
The average temperature of Kopikoville was reported to be - 19° last year. This year, the average temperature of Kopikoville rose by 5°. Which of the following is true about this year's average temperature of Kopikoville?
A. This year's average temperature of Kopikoville is 24°.
B. This year's average temperature of Kopikoville is - 14°.
C. This year's average temperature of Kopikoville is 14°.
D. This year's average temperature of Kopikoville is - 24°.
B
the average temperature rose by + 5°
this years average = - 19 + 5 = - 14°
Write the function rule for the function shown below reflected in the given axis. f(x)=5x;x-axis
Hello!
Given the function, f(x) = 5x, find the equation where the function f, is reflected over the x-axis.
There are two types of reflections. One reflection is over the x-axis (the most common) and over the y-axis.
Say for example, we are given the point (x, y), and we want to reflect it over the x-axis. If the point (x, y) is reflected over the x-axis, then the point is (x, -y). Why? It's because y-values above the x-axis are POSITIVE while x-values below are NEGATIVE.
So, an equation to show this is: y = -f(x).
To find it, we multiply the entire function, which is f(x), by a negative. Since f(x) = 5x, the transformed function is f(x) = -5x.
Therefore, the function rule for the function shown is -f(x).
The function rule for the function f(x) = 5x reflected over the x-axis is -f(x) = -5x. This is due to the reversal of the y-values when reflecting a function over the x-axis.
Explanation:In Mathematics, when we reflect a function over the x-axis, it simply means reversing the signs of the y-values. For this given function f(x) = 5x, its reflection would get the y-values inverted, which would convert the positive to negative (or vice versa). Taking this into account, the function reflecting in the x-axis would be -f(x) = -5x.
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Find a gradient of a line that is parallel and perpendicular to this line with this gradient of -2
a gradient of a line that is parallel and perpendicular to this line with this gradient of -2
Gradient is the slope
So slope of the line =-2
Slope of parallel line is equal to the slope of the line
So slope of parallel line = -2
Slope of perpendicular line is equal to negative reciprocal of slope of the line
We know slope of line = -2
Negative reciprocal = [tex]\frac{1}{2}[/tex]
So , Slope of perpendicular line= [tex]\frac{1}{2}[/tex]
Help please! 17 points!
Which expression shows the distance on the number line between −12 and 8?
A. | − 12 − 8 |
B. | 8 − 12 |
C. | − 12 + 8 |
D. | − 12 − (−8) |
The answer would be A because the distance from 8 to 0 is 8 and the distance from 0 to -12 is 12 so 8+12 is 20
In City A, the temperature rises 4
degrees
°F from 8 A.M. to 9 A.M. Then the temperature drops 7
degrees
°F from 9 A.M. to 10 A.M. In City B, the temperature drops 6
degrees
°F from 8 A.M. to 9 A.M. Then the temperature drops 2
degrees
°F from 9 A.M. to 10 A.M. Write an expression that represents the change in temperature from 8 A.M. to 10 A.M. for each city. Simplify and interpret each sum.
Use pencil and paper. Which city has the greater change in temperature?
The general expression for the change in temperature between 8am and 10am
[tex]\delta_{8-10}= \delta_{8-9} + \delta_{9-10}[/tex] where [tex]\delta[/tex] stands for change in the subscripted time interval.
For city A:
[tex]\delta_{8-10} = 4 - 7 = -3\enspace ^\circ F[/tex]
For city B:
[tex]\delta_{8-10} = -6 - 2 = -8\enspace ^\circ F[/tex]
In city A, there is an overall drop of 3 degrees (negative value). In city B, the temp drops 8 degrees.
Among A and B, city B has a greater change in temperature (8 vs. 3)